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7/31/2019 BT Chung Da Cau Tu_Nha

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Bi tp chng ct a cu t

SVTH: Nguyn Ngc Nha Lp 08H5A Page 1

Bi ton 1 :

xheptane 0 0.08 0.18 0.25 0.49 0.65 0.79 0.91 1.0

yhe tane 0 0.28 0.43 0.51 0.73 0.83 0.90 0.96 1.0

Hl (kJ/kmol) x 10-3

24.3 24.1 23.2 22.8 22.05 21.75 21.7 21.6 21.4

Hv (kJ/kmol) x 10-3 61.2 59.6 58.5 58.1 56.5 55.2 54.4 53.8 53.3

1. 2. 3. 4.

Bi lm

MHeptane = 100

MEthyl benzene = 106

MA = 0.42*100 + 0.58*106 = 103,42

,42 = 9.6693 kmol/hr


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Gian x-y

0

0,1

0,2

0,3

0,4

0,5

0,6

0,7

0,8

0,9

1

0 0,1 0,2 0,3 0,4 0,5 0,6 0,7 0,8 0,9 1

x

y

Gian H-x-y

-50

-40

-30

-20

-10

0

10

20

30

40

50

60

70

80

90

100

0 0,1 0,2 0,3 0,4 0,5 0,6 0,7 0,8 0,9 1

x-y

H,

kJ/kmol.10-3


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zA = 0.42

hA = 22.3*103

kJ/kmol ( -- )

xD = 0.97

hD = 21.537*103

kJ/kmol --

xR = 0.01

hR = 24.276*103

kJ/kmol --

1. E, LA, VA, PRQC

E, RQC A, VA, R E D RQC).

VA -- -y.

xA 4 A* 67 VA (0.67; 56.897*10

3)

Q'C = 98.439*103

(kJ/kmol) -x-y)

PE = -34.4537*103

(kJ/kmol) -x-y)

H1 = 53.705*103

(kJ/kmol) -x-y)

1

1

'c

D

Q HR

H h

391,1537,21705,53705,53439,98

min R

2. s


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- 7.

3. s .

5,2537,21705,53

705,53'

c

QR

Q'C = 134.12*103

(kJ/kmol)

Gian x-y

0

0,1

0,2

0,3

0,4

0,5

0,6

0,7

0,8

0,9

1

0 0,1 0,2 0,3 0,4 0,5 0,6 0,7 0,8 0,9 1

x

y


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- xy :

Gian x-y

0

0,1

0,2

0,3

0,4

0,5

0,6

0,7

0,8

0,9

1

0 0,1 0,2 0,3 0,4 0,5 0,6 0,7 0,8 0,9 1

x

y


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7

4. C A = 9.664 (kmol/hr)

:

A = D + R

A.zA = D.xD + R.xR

RDRD

.01,0.97,042,0.664,9

664,9

Suy ra :

D = 4.127 (kmol/hr)

R = 5.537 (kmol/hr)

:

A.hA = D.Q'C + R.QR

9.664.22,3.103

= 4,127.134,12.103

+ 5.537.QR

QR = -61.057*103

(kJ/kmol)

Ta c :

Q'C = hD + QC / D

QR = hRQR / R

134,12.103

= 21,537.103

+ QC / 4,1272


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QC = 496,711.103

(kJ/hr) = 137,98 (kW)

-61.057.103

= 24,27584.103QR / 5,537

QR = 472,445.103

(kJ/hr) = 131,23 (kW)

C : QC = 137,98 (kW)

C : QR = 131,23 (kW)


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Bi ton 2 C n GO c d = 0.870 v b t ASTMsau:

ASTM PI 10% 30% 50% 70% 90% PF

T (oC) 215 225 240 265 280 295 320

1. Xy d ng cong TBP2. Xy d ng cong FC

Bi lm

1. Xy d ng cong TBP:Ta c :

T50 = 265o T50(TBP-ASTM) = 11oC 50(TBP) = 265 + 11 = 276

oC

T50-70(ASTM)= 280265 = 15 oC 50-70(TBP) = 22

oC

70(TBP) = 276 + 22 = 298oC

T70-90(ASTM)= 295280 = 15 oC70-90(TBP) = 19

oC

90(TBP) = 298 + 19 = 317oC

T90-PF(ASTM)= 320295 = 25 oC 90-PF(TBP) = 27

oC

PF(TBP) = 317 + 27 = 344oC

T30-50(ASTM)= 265240 = 25 oC 30-50(TBP) = 36

oC

30(TBP) = 276 - 36 = 240oC

T10-30(ASTM)= 240225 = 15 oC 10-30(TBP) = 27

oC

10(TBP) = 240 - 27 = 213oC


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TPI-10(ASTM)= 225215 = 10 oC PI-10(TBP) = 22

oC

PI(TBP) = 213 - 22 = 191oC

T kt qu tnh ta c bng sau :TBP PI 10% 30% 50% 70% 90% PF

oC 191 213 240 276 298 317 344

2. Xy d ng cong FC:Ta c :

T50(ASTM) = 265oC v T30T10 = 15oC 50(FC-ASTM) = 12

oC

50(FC) = 265 + 12 = 277oC

T50-70(ASTM)= 15 oC 50-70(FC-ASTM) = 7

oC

70(FC) = 277 +7 = 284oC

T70-90(ASTM)= 15 oC 70-90(FC-ASTM) = 6

oC

90(FC) = 284 + 6 = 290oC

T90-PF(ASTM)= 25 oC 90-PF(FC-ASTM) = 8

oC

PF(FC) = 290 + 8 = 298oC

T30-50(ASTM)= 25 oC 30-50(FC-ASTM) = 14oC

30(FC) = 277 - 14 = 263oC

T10-30(ASTM)= 15 oC 10-30(FC-ASTM) = 8

oC


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10(FC) = 263 - 8 = 255oC

TPI-10(ASTM)= 10 oC 0-10(FC-ASTM) = 3

oC

0(FC) = 255 - 3 = 252oC

T cc kt qu c ta c bng sau :FC PI% 10% 30% 50% 70% 90% PF%oC 252 255 263 277 284 290 298

Ta c bng tng k ng cong:PI% 10% 30% 50% 70% 90% PF%

ASTM (oC) 215 225 240 265 280 295 320

TBP (oC) 191 213 240 276 298 317 344

FC (oC) 252 255 263 277 284 290 298

Xy d th t ng cong trn:

185

205

225

245

265

285

305

325

345

0 20 40 60 80 100

T(oC

)

%V

ng cong chng ct ca GO

ASTM

TBP

FC


11/21



Bi ton 3: Ti n hn hp sau p sut 10atm

Cu t C2 C3 iC4 nC4 iC5 nC5(mol) 8 22 14 24 10 22

Bit nhi nhp liu l 65oC Yu cu v sn phm:

N propan sn ph Pentan ph c sn ph t l 99% t ng

pentan trong hn hp X nh Nmin v Rmin X nh s bc l thuyt N theo R hp l:

Bi lm

1. Chun b dkin v cc gi thit:-Chn cu t kha

+Cu t kha nh CV: C3

+Cu t kha nng CL: iC5

-Gi thit s phn b n +C2 khng c +iC4 l cu t trung gian nh, phn bnh nhi

+nC4 l cu t trung gian nng, phn bu

+C5 tng (nC5 +iC5) phn b % u cho hai cu t

bi, ta c:

99,0)(5

)(5

A

R

C

C

M 5(A) = 32 (mol)

5(R) = 31,68 (mol)Gi x l s mol C3(R).

Ta gi s: thnh phn iC4 v nC4 phn b

iC4(R) = 5(mol), iC4(D) = 9(mol)

nC4(R) = 12(mol), nC4(D) = 12(mol)


12/21



4(R) = 17 (mol)

)(492,0

01,0

)(4)(5

molxCCx

x

RR

Li c: C5 tng (nC5 +iC5) phn b % u cho hai cu t, nn thnhphn ca iC5 v nC5 c phn b

iC5(D) = nC5(D) = )(16,032.2

01,0.

2

01,0)(5 molC A

iC5(R) = 100,16 = 9,84 (mol)

nC5(R) = 220,16 = 21,84 (mol)Bng gi thit phn b n :

Cu tNguyn liu Sn ph nh Sn ph

Mol Phn mol Mol Phn mol Mol Phn mol

C2(V) 8,00 0,08 8,00 0,157 0,00 0,00

C3(CV) 22 0,22 21,51 0,423 0,492 0,01

iC4(iV) 14 0,14 9 0,177 5,00 0,102

nC4(iL) 24 0,24 12 0,236 12 0,244

iC5(CL) 10 0,1 0,16 0,003 9,84 0,2

nC5(L) 22 0,22 0,16 0,003 21,84 0,444

Tng 100 1 50,83 1 49,18 1

i

Ly gi tr trung bnh ti 3 v p liu

Ti mi v tr cn bit nhi , t hng s cn bng pha v tnh i

Ch : tnh theo cu t kha nng iC5


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T nh thp:

Nhi t nh l nhi a hn h nh

Cu tNhi gi thit l nhi oC

yi=xiD Ki xi=yi/Ki iD=Ki/KCLC2(V) 0,157 4,4 0,036 16,296

C3(CV) 0,423 1,55 0,273 5,741

iC4(iV) 0,177 0,74 0,239 2,741

nC4(iL) 0,236 0,56 0,422 2,074

iC5(CL) 0,003 0,27 0,012 1

nC5(L) 0,003 0,21 0,015 0,778

Tng 1 0,996

T :

Nhi m si ca hn h

Cu tNhi gi thit l nhi m si t=102 oC

yi=xiR Ki yi=xi.Ki iR=Ki/KCL

C2(V) 0 7,2 0 9,231

C3(CV) 0,01 3,05 0,030 3,91

iC4(iV) 0,102 1,71 0,174 2,192

nC4(iL) 0,244 1,42 0,347 1,821

iC5(CL) 0,2 0,78 0,156 1

nC5(L) 0,444 0,67 0,298 0,859

Tng 1 1,005


15/21



T p liu:

Nhi np liu theo gi thit l 65 oC

Ti nhi ny ta tnh % b cn bng pha

Cu t Zi Ki Gi s V=25% ti t=65 oc

1+Ki/3 Li=100.Zi/(1+Ki/3) Xi F

C2(V) 0,08 5,2 2,733 2,927 0,039 13,684

C3(CV) 0,22 1,95 1,65 13,333 0,178 5,132

iC4(iV) 0,14 0,93 1,31 10,687 0,143 2,447

nC4(iL) 0,24 0,76 1,253 19,149 0,256 2,00

iC5(CL) 0,1 0,38 1,127 8,876 0,118 1,00

nC5(L) 0,22 0,31 1,103 19,94 0,266 0,816

Tng 1 74,911 1

Bng tng kt s li

Cu t F iD iR i

C2(V) 13,684 16,296 9,2311 12,721

C3(CV) 5,132 5,741 3,91 4,866

iC4(iV) 2,447 2,741 2,192 2,45

nC4(iL) 2 2,074 1,821 1,962

iC5(CL) 1 1 1 1

nC5(L) 0,816 0,778 0,859 0,817

2. X nh Nmin theo cng thc Fenske:Kim tra gi thit phn b n bng cch gii h Fk t cho

tng cu t khc nhau


16/21



Gi a l s mol iC5 trong sn ph nh thp, ta c

Cu t nh

iC5(mol) a 10-a

nC5(mol) 0,32-a 21,68+a

Cng th Fk c vi di dng

min)(N

ij

iR

jR

jD

iD

x

x

x

x

Vit cng thc Fenske ln t cho cc cp cu t sau:

+C3 v iC5:

min)866,4(10

5,0

5,21 N

a

a

+C3 v nC5:

min)82,0

866,4(

32,0

68,21

5,0

5,21 N

a

a

Gii h ta c: Nmin = 4,931, a= 0,176Cu t nh

iC5(mol) 0,176 9,824

nC5(mol) 0,144 21,856

Gi b l s mol C2nh,vit cng thc Fenske cho C2 v iC5

9206,4

)721,12(176,0

824,9

8

b

b

Gi c b =7,998

Gi c l s mol iC4nh ,vit cng thc Fenske cho iC4 v iC5


17/21



9206,4)450,2(

176,0

824,9

14

c

c

Gii ra c c = 8,365

Gi d l s mol ca nC4nh,vit cng thc Fenske cho nC4 v iC5

9206,4)962,1(

176,0

824,9

24

d

d

Gi c d= 7,962

Bng phn b n c

Cu t Nguyn liu Sn ph nh Sn ph Mol Phn mol Mol Phn mol Mol Phn mol

C2(V) 8 0,08 7,998 0,173 0,002 0

C3(CV) 22 0,22 21,508 0,466 0,492 0,009

iC4(iV) 14 0,14 8,365 0,181 5,635 0,105

nC4(iL) 24 0,24 7,962 0,173 16,038 0,298

iC5(CL) 10 0,1 0,176 0,004 9,824 0,182

nC5(L) 22 0,22 0,144 0,003 21,856 0,406

Tng 100 1 46,154 1 53,846 1

S sai khc gia kt qu tnh ton vi gi thit phn b n u khngln lm trng hp ca nC4 l cu t trung gian, ta khng c yucu cht ch. Mt khc gi tr phn b n k i k nhi si ca hn hp t nh v t y cth s dng s liu phn b n v gi tr c m khng cn phitnh lp li.

3.Tnh t s h ti thiu Rmin:

S dng cng thc Maxwell tnh Rmin ng hp bin ca trng thi npli R ng vi hn hp nguyn liu

Nhp liu dng lng: cu t nh u t kha nh C2 = 8% => Nhp liu 8% 92% lng

Nhp liu d u t n u t kha nng l pha lngnC5 = 22% => Nhp liu 78% % ng


18/21



Tnh cc gi tr l:

Cu t Zi Nhp liu dng lng Nhp liu d

%b l %b l

C2(V) 0,08 12,721 8 0,063

78

0,063

C3(CV) 0,22 4,866 2,2 0,452

iC4(iV) 0,14 2,45 1,4 0,571

nC4(iL) 0,24 1,962 0,917 0,37

iC5(CL) 0,1 1

nC5(L) 0,22 0,817 1 1

X nh Rmin cho trng thi np liu dng lng:

4368,0

4368,1

)003,01

467,0(

817,0866,4

817,0

)172,0917,0

467,0(

962,1866,4

962,1

)004,0.4,1181,0(145,2

45,2

)004,0.063,0174,0(1721,12

721,12

004,02,2

467,0

1866,4

12,2.866,41

%8min

%8min

R

R

X nh Rmin cho trng thi np liu dng


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169,1

161,2

)003,01

467,0(

817,0866,4

817,0

)172,0370,0

467,0(

962,1866,4

962,1

)004,0.571,0181,0(145,2

45,2

)004,0.063,0174,0(

1721,12

721,12

004,0452,0

467,0

1866,4

1452,0.866,41

%78min

%78min

R

R

X nh Rmin cho trng thi np liu thc t vi 25% b

6153,0

)878(

)825).(4368,01717,1(4368,0

%25min

%25min

R

R

X nh s bc l thuyt N theo R hp l:

Gi sR c gi tr fR theo cng thc

1

R-R=f min

RR

T fR th ca Gilliland:


20/21



Ta c

)(1

)(

1)(

min

min

Nf

NNfN

N

NNNf

c bng s liu sau:

R R - Rmin fR f(N) f(N) + Nmin N N.(R+1)

0.8 0.187 0.104 0.5 5.431 10.862 19.55

1 0.387 0.193 0.44 5.371 9.591 19.18

1.2 0.587 0.267 0.39 5.321 8.723 19.19

1.4 0.787 0.328 0.35 5.281 8.124 19.50

1.6 0.987 0.379 0.33 5.261 7.852 20.42

1.8 1.187 0.424 0.31 5.241 7.595 21.27

2 1.387 0.462 0.25 5.181 6.908 20.72


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V th : N.(R+1) - N

D th, chn N = 9

N.(R+1) = 19,2 => R = 1,133

19.00

19.50

20.00

20.50

21.00

21.50

6.000 7.000 8.000 9.000 10.000 11.000

N.(

R+1)

N

Chn N ti u

Chn N ti u

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