Cẩm nang Cấu Kiện

7/29/2019 Cm nang Cu Kin

1/15

Cm nang Cu KinHic! Nu ko phi l n xng nh vy th mn ny ko xut hin nhiu trn din n th ny!Ni chung mn ny cn qu nhiu th bn, phn tip dnh cho cc member khc ca kho 07!Hm nay cho cc e kho di cht t tch lu c khi bo v th nghim cu kin:Mn th nghim ny lm rt l mt, c bit phn s liu.Cc u nn nh s liu phi l thc o

c, thng th n ko ging hon ton m ch gn ging vi l thuyt thui! Qua bo v th huht l b sai s liu, v d nh in p phn cc thun ca diode xp x 0,53 ch ko phi l 0.6v..v..v...trong phn mm winface c nhng kt lun m bn ko o dc nhng theo l thuyt ling th ko nn cho vo bo co.Bi v thy ch yu hi kt lun ca bi bo co thui!Cm k nhtl cu tr li l :"em o c".TR li nh vy coi nh ln bo v bn s phi o c bui mhu nh l ko qua phi bo v li.Tuy nhin nu chc chn ng th bn c tr li nh vy ri rao ng s c im cao(hi bo v ch c mt ngi lm c iu ny)Tr li nn i theo hng nguyn l hot ng(cc ch phn cc), ch c tnh vt l(s dichuyn ca cc e v l trng).Cng thm vi l thuyt gii bi tp ca thy cho v lm na l cth qua c ln 1 ri!V bo v th gm thy Bnh v 2 hay 3 thy tr khc!Nu gp thy Bnh th nh kho 07 th thycho t chn mt phn ri thy hi nhng thy hi rt k,nu qua c phn th thy hi thm

v ba cu na l qua.Cn gp cc thy khc hi ko k lm ch yu l c bn nhng li hi tonb(sc xut qua ln 1 cao hn rt nhiu m im li cao).i loi c bn l nh vy sorry ni nh vy l gn nht ri ! C g thc mc cc bn c th tra, bit s gip lin.Bun ng lm ri, ng !bYE cc u nha!

B cc ca bi bo co thng l:1. Mc ch th nghim.

- Bi th nghim gip em hiu v c tnh hay nguyn l lm vic, ... ca linh kinno? khi mch no?2. Dng c th nghim.

- VD: DMM (cc ng h o trn PTN u l DMM, k phi VOM), Oscilloscope, tnboard mch, tn khi mch, my to sng, phn mm WIN FACET, ...3. Ni dung th nghim.

a. Th nghim 1.- o trn khi mch no?- o ci g? S liu? Hnh v dng sng, p ng pha, tn s,...Nn ghi theo trnh t trong bi th nghim. VD: Cp sng vo l sng g?

(sin hay vung,...), tn s bao nhiu? o tn hiu ng ra ti u? Dng knh no caOscilloscope (CH1 or CH2), dng DMM th thang o no, o gi tr g?... Kt qu nhth no?

- Kt lun: V s liu o c, v linh kin m em th nghim. Nhn xt1 s c tnh ca chng, so snh vi l thuyt. C th tham kho cc kt lun cui bitest trong WIN FACET. Ci no hiu r th mi ghi vo kt lun, k hiu r hoc l m th

ng ghi vo.b. Th nghim 2..........................c. Th nghim n.

4. Kt lun chung: Cho c bi th nghim.

khi vo th nghim th u tin l bt ci my tnh lni th nghim ch yu l e phi hiu c mch v bit c cch o trnmultimeter, trn my hin sng, khi bo v thy thng hi cc linh kin trnmch dng lm g ri ch 1 im bt k trn mch bo em v dng sng ca

n hoc dng sng qua 1 in tr bt k trn mch dng phng php no o.


2/15

V th i hi khi i th nghim , u tin phi c trc hiu cc bc tinhnh th nghim o nhanh chng, th 2 cn bt tay vo lm ,d nhiu ngicng nn tp trung quan st hiu r ng nn 1 ngi lm ht th sau nybo v ko bit nh th no.......hiu c cc ch o trn my hin sng th mi th nghim tt c nn emhy tm hiu trc cc ch o trn my hin sng, trong bi th nghim cu

kin phn 3 ch ADD-INVERT ( cng o= tn hiu i qua 1 in tr) thngxuyn c s dng.Ti liu hng dn s dng Oscilloscope bng ting Vit. My em nn c trc cho bitcc chc nng c bn ca n ri lm th nghim s d hn.

http://www1.dt vt.org/dtvt.asp?TID=15258&PID=67972

Cn phn cc bi th nghim th lm theo cc hng dn ca WIN FACET. Ln th nghimth ch lm phn procedure thi. Cc phn khc th nn xem trc nh hiu v WINoffline vn c, k c phn test. Quan trng l s liu o phi chnh xc. Ch no khngo c, hoc o khng ng th c mnh dn hi thy.

Vit bo co th c theo y nh s liu thc t mnh o c. ng xch s liu ngikhc b ba v, thy biu o li khng ng l tiu . Gluck!Bo co mu (Khuyn co khng nn lm theo nh):http://dtvt.org/dtvt.asp?TID=43&PID=22420

QUOTE _(^_^) (^_^)_ Din n sinh vin khoa in t -Vin thng - HBK Nng

m em hi ci ny hi tc ci 1 t.cc thy hi bng english hay ting vit vy a,

D nhin l thy hi bng ting Vit riDn d cn thn l ng ghi ting Anh v bo co nh. Thy biu dch m dch khngng l ri... v vit li bo co. Ch my ci c tuyn v cho ng, ng v congcong l tng ho. Nh hi mnh bo v thy hi ngay c tuyn diode v phn cho 1

cu: "Em thch ng cong lm h?"

Lm ch yu phn o c thi em, nhng phn no cn kt qu o hoc tnh ton mWINFACET offline k c thi. Ch cn cc bi test hay my cu trc nghim k cn thit,WIN offline vn c th test bnh thng. Ln bo v thy s hi s liu v em phi giithch c kt qu o ca mnh, k o m ghi by b lung tung vo bo co l tiu.

Nu o bng Oscilloscope th tt nht em nn chp li mn hnh my ci dngsng, nu k th phi v khung hnh ging nh screen ca my vy (10x8 cm), cng chnhxc cng tt. Nh ghi li chia time/DIV v V/DIV. o bng ng h th sai s ti thiuphi l 0.01 (k nn ghi s chn, d die lm). C khi o 1 ng, kt qu 1 no l chuynthng.

Kinh nghim vit bo co l em nn ghi nhng s liu m em o c, ng cghi s liu l tng. Nu c sai so vi s liu em nhp vo my th cng ng b, nn ghivo. Thy hi th ni l em o c nh vy, ch ghi by b thy bt o li k ra ng s

liu th ch c nc... .

Nu c thc mc g em c hi thy, ng s. Thy ch bo nhit tnh lm (thchnht khong ny).
http://www1.dtvt.org/dtvt.asp?TID=15258&PID=67972http://dtvt.org/dtvt.asp?TID=43&PID=22420http://dtvt.org/dtvt.asp?TID=43&PID=22420http://dtvt.org/dtvt.asp?TID=43&PID=22420http://dtvt.org/dtvt.asp?TID=43&PID=22420http://dtvt.org/dtvt.asp?TID=43&PID=22420http://www1.dtvt.org/dtvt.asp?TID=15258&PID=67972


3/15

Em m sing sing th c th c trc nh cho hiu ni dung cng c, kquan trng lm. ng qu ph thuc vo WIN FACET. Gluck!

Theo anh th ch yu l lm trn mch ch khng cn thit phi ngi m dch tng cu u.

Tng trang ni tng yu cu, mnh lm theo ri o t kt qu l c riNu ai sing th nh c hiu trn my file word y cng c. Cn phng Lab th kt qu l

ch yu .

C gng bit cch o t l sau ny thy yu cu thc hin trn mch

VGS phn cc thun khng dng cho JFET?in p st p trn in tr ngun to ra in p phn ccPhn cc ngun hay t phn cc gim tc ng ca s thay i IDSS.

Em ko hiu my cu ni cho lm nh my bc ch dm v sao li nh th

Thank nhiu

JFet th nghim l knh N nn Vgs phi phn cc ngc mi xi c

Vg = 0 , Vs = -Rs x Id

in p st p trn in tr ngun to ra in p phn cc: v VGS=VG-VS,trng

hp t phn cc VGS=-VS nn n ph thuc vo st p trn in tr ngun to !Phn cc ngun hay t phn cc gim tc ng ca s thay i IDSS:---tc l i vi t phn cc th s thay i ca Idss t tc ng n cc gi tr tnh,do vi t

phn cc Vgs l 1 hm thay i theo Id nn dc ca ng phn cc nh hn so vi phncc c inh(Vgs khng i nn n c dng thng ng) ==>mc thay i trong cc gi trtnh cng thp.---C th v c tuyn Jfet vi 2 gi tr Idss khc nhau,sau v ng Vgs ph thuc theoId(c dng Vgs=-k*Id) v 1 dng Vgs=-L(const) s thy ng Vgs=-k*Id ct c tuyn ti2 gi tr m chnh lch gia 2 gi tr khng ln bng trng hp phn cc c nh (Vgs=-L(const) )VGS phn cc thun khng dng cho JFET? l mosfet ngho knh N cng tng t nh

jfet knh n cng hot ng khi Vgs0 cn jfet th khng (do cu to ) chnh v vy nn mi c kt lun ny nhn mnh iu

Vgs phn cc thun khng dng cho JFET l doJFET l FET c cng tip gip PNm nu Vgs phn cc thun th vng ngho cng ca tip gip PN cch ly gia cng G v

knh dn c sn s b tiu bin nh th khng cn c cch ly gia cng v knh na tcl mt bn cht JFET c cng tip gip nn VGs phn cc thun ko dng cho JFET

Thy hi nhiu vi hi su + rng na. Gi cng khng ai nh c u em.

Ch cn nh vi cu m hi thy hi:

1. c tuyn ca diode (ci ni nhiu ngi die lm n)


4/15

Lm sao em v c c tuyn ny? Ly s liu t u? V sao ng cong?...

Tr li:Tt nht l trn ci bo co phi ng , ch khng ng th c tr li kiu g cng

sai. Tht ra th khi mnh th nghim, mnh ch ly mu ti mt vi thi im thi.Nn sau khi c s liu, th xc nh c cc im v ni li bng cc ng thng(tuyn tnh), ch khng phi ng cong. ng cong ging trong sch l do ngi taly rt nhiu mu, cc mu st nhau nn v ra vy. Cn mnh l th nghim th ch ly c10 mu l nhiu ri nn n khng c cong c nh vy u.

2. in p np x trn t trong mch lc:http://dtvt.org/dtvt.asp?TID=6834&PID=38565My anh ch ui,tr li gim em cu ny vi:

V sao trong mach chnh lu c t lc,dng song ra l gnrng ca m hok phi gn cong (dng sng vo l sng

sin)Cu ni thy Bnh hi em khi bo v .Thy ni nu tr li c th 10 im.Hic,kiuni lm ren m c im y tri???Theo t: dng sng ra vn gn ch cha phi thng ro th u nhng v gn rt nh,khong cch gia 2 "im gn" l rt b nn ng cong c th xem nh l

thng.Hic, bo v hn xui thit, c ngi vo b hi c bi, o c ng ci cng vn 5 im, cngi vo ko cn hi vn... 3 im. Cn trng hp kon Huyn y ch cn tr li c 1

cu vn 10 im .

ch mi hiu sai con Huyn ri VR

thy yu cu hn gii thch ti sao ci ch mu ta khoanh trn li thng m khng

phi l ng cong
http://dtvt.org/dtvt.asp?TID=6834&PID=38565http://dtvt.org/dtvt.asp?TID=6834&PID=38565


5/15

p trn t V=(1/C)(tch phn ca Ic dt)trong khong thi gian nh , t x, xem nhng dng x khng i th Ic l constnn tch phn ra V = Ic x t / Cnn p l ng thngtm li l th ny. ban u khi m ngun bn ngoi bn k Dng th t s c np in nin p nh l nh A. khi m ngun bn ngoi gim i ( bn k m ) th t s bt u x, nhng

n s khng x hon ton c v c in tr R, 1 phn in p s gim xung n in p im Bri n C, sau khi ngun bn ngoi tng li n in p nh ( bn k Dng ) th t s clp li trng thi np v tng ln li A. lp li nh th l okie. ci ny mnh lm klm xong c hi thy:D chc khng sai:D hi vng th

Tr li: Do thi gian np x qu nhanh nn t ch mi np x n on tuyn tnh --->Kt qu: Dng sng ra c dng gn nh hnh.


anh ch cho em hi t : trong mch khuch i bng jfet mc ngun chung, t ni song song

vi in tr ngun Rs c tc dng j, c anh hng gi ti h s khuch i p koT mc song song vi Rs c tc dng lm tng h s khuch i ca mch v Av=-gm*(Rd//Rs)m.Khi mc t th Rs=0 nn Av s tng

Xc nh chn JFET

Da vo cu to bnh trong ca JFET m suy ra cch xc nh chn ca JFET Ta t ng h VOM thang o 1k hoc100.Ta t que o vo mt chn c nh, cn que cn li o ga hai chn cn li nu kim ln u thta o hai que o vi nhau v o nh trn th kim khng ln th chn c nh l chn G. trnghp que cn li o ga hai chn cn li nu kim ln u, que chn c nh l que en th JFET

knh N, nu que chn c nh th l JFET knh P.JFET knh N: Ta t hai que o vo hai chn cn li(Khng t chn E), Dng tay kch vo chnG nu kim vt ln th que en ng vi cc D, que ng vi cc S.JFET knh P: Ta t hai que o vo hai chn cn li(Khng t chn E), Dng tay kch vo chnG nu kim vt ln th que en ng vi cc S, que ng vi cc D.

Xc nh chn ca UJT.

Da vo cu to bnh trong ca UJT m suy ra cch xc nh chn ca UJTTa t ng h VOM thang o 1k hoc100.Ta t que o vo mt chn c nh, cn que cn li o ga hai chn cn li nu kim ln u th

ta o hai que o vi nhau v o nh trn th kim khng ln th chn c nh l chn E.Ta t que o vo hai chn cn li, ta ni mt in tr t que en n chn E nu kim vt ln thchn ng vi que en l chn B2 . chn cn li l chn B1.

Cch xc nh chn ca SCR.

Vn VOM thang Rx1Ta t que o vo mt chn c nh, cn que cn li o ga hai chn cn li nu kim khng lnth ta o hai que o vi nhau v o nh trn kim khng ln th chn c nh l chn A. Ta t queen vo chn A v que vo mt trong hai chn cn li, sau ly dy ni ga chn A kch vichn cn li ( chn khng t que ). Nu kim ln v th ra kim t gi th chn l chn G.

Chn cn li l chn K.


6/15

Xc nh chn BJT.

Da vo cu to bnh trong ca BJT m suy ra cch xc nh chn ca BJTTa t ng h VOM thang o 1k hoc100.Ta t que o vo mt chn c nh, cn que cn li o ga hai chn cn li nu kim ln u thta o hai que o vi nhau v o nh trn th kim khng ln th chn c nh l chn B. trnghp que cn li o ga hai chn cn li nu kim ln u, que chn c nh l que en th BJTloi NPN, nu que chn c nh th l loi PNP.BJT(NPN): Ta t hai que o vo hai chn cn li(Khng t chn B), dng in tr(hoc ngntay) ni ga que en vi cc B nu kim ln th chn tng ng vi que en l chn c chn cnli l chn E. Khi kim khng ln thi ta o ngc que li v kim tra nh trn.BJT(PNP): Ta t hai que o vo hai chn cn li(Khng t chn B), dng in tr(hoc ngntay) ni ga que en vi cc B nu kim ln th chn tng ng vi que en l chn E chn cnli l chn C. Khi kim khng ln thi ta o ngc que li v kim tra nh trn.i vi BJT cng sut th khi ch to ngi ta c in tr lt hoc in tr v diode lt bnhtrong th khi o cn ch .

Cch xc nh chn ca TRIAC.Vn VOM thang Rx1Ta t que o vo mt chn c nh, cn que cn li o ga hai chn cn li nu kim khng lnth ta o hai que o vi nhau v o nh trn kim khng ln th chn c nh l chn T2. Ta tque en vo chn A v que vo mt trong hai chn cn li, sau ly dy ni ga chn T2 kchvi chn cn li ( chn khng t que ). Nu kim ln v th ra kim t gi th chn l chn G.Chn cn li l chn T1.

i vi Diode

thang o Rx1 ta tin hnh do hai ln c o que o.- Nu quan st thy kim ng h mt ln kim ln ht. Mt ln kim khng ln th Diode hotng tt.- Nu quan st thy kim ng h mt ln kim ln ht. Mt ln kim ln 1/3 vch th Diode br.- Nu quang st hai ln o kim u ln ht th diode b thng.- Nu quang st hai ln o kim u khng ln ht th diode b t.

V i bo v TN cu kin v nhiu ngi tm c hi qu, c nh mi i nc ngoi v

v c phng vn .

Sau y xin tr li my cu m my a hi tui (nhm 09B, bo v th 6):1. Mi bo v cha? c my im?Tr li: i bo v ri nhng cha c bo v (cha ti lt), => cha bit im.2. Bo v c my ngi ri, im cao khng?Tr li: hm m a vo bo v lu qu nn cng ch bo v c 12 hay 15 a chi thi.

im th thi ri , thng u tin 2 im, thng th 2, 3, 4 c th m


7/15

nhm .Ni chung tng kt li th: a s l 2 im, c vi a 0 im, c 1 a 3 im, 2 a 5im.

3. Ai l ngi cao im nht trong bui , bo v c lu ko?Tr li: hnh nh thng Huy 08DT1 (nick 4rm l bombom) v 1 a na ko bit tn.im cao nht bi l 5 im (c th k bo tin li lc tui m i n ti).

2 ngi c im cao nht vo bo v mt gn.... 1 ting th phi . Tr li xong

ri phi o t li, m o c nh mun u .

4. Thy c chp nhn bn in hay khng?Tr li: mt s tm gng in hnh i bo v vi tp bo v in trn tay v ra v vi

con 0 .

5. Th im thp vy ri c c bo v li ko?Tr li: im ch mi l im trong bn im tm ca thy, thy s cho bo v li.

6. Khi no th c bo v li?Tr li: ngay bt c khi no ca phng th nghm m!

Recommend: vo bui c nhm bo v th ln bo v chui , m c hi c bo

v chui hi hm, ngay c tui thuc nhm chnh bo v m cng cha c bo v ..........

Li khuyn:Nn vit tay bo co, ng tiu ting Anh trong tp bo co.Hiu phn no vit phn y, hn ch b bng, ko hiu m vit vo ri thy hi ko reply

c th hi ko kp.

Cc t tuyn trong tp bo co phi chnh xc vi bng s liu, lch xem nh toi.Chc chn thy s hi mt cu l: "em hiu phn no?", "em hiu bao nhiu %"....

Nu tr li khng hiu phn xyz no th thy s hi chnh phn , bit v saoko? V thy va hi va ging cho mnh phn lun cho mnh hiu.


8/15

ng thy ra m tr li l "tha thy, em khng hiu phn diode" nh .Cc s liu trong tp bo co phi hiu v sao m c n, nu ni l "em o c thy"th c khi thy s bt n o li (nu thy s liu c vn hoc thy mnh ngp ngng).

Quan trng nht l cc kt lun, phi hiu kt lun trong bi bo co ca mnh.

Tm li: hc cho hiu ht cun "Dng c bn dn" ri ln bo v l chc n nht .

Bi vit ca virus_lazy_(^_^) (^_^)_ QUOTE by Ent - DUT forum

4. Thy c chp nhn bn in hay khng?Tr li: mt s tm gng in hnh i bo v vi tp bo v in trn tay v ra v vi

con 0 .

Chp tay khi tn tin mt cng i in li

Nm trc in nguyn khng chnh sa my

c in i in li 3 ln trong c 1 ln chi in mu (ln th 2 )

Ni ra hiu l b i my ln riNi chung ai c sc khe th nn chp tay cho chc.

C lm phn no th chp ra ch ng c ham nhiuBa ni tri lnh ri.P/s:Bo v TN CKT mt rt nhiu thi gian nn ch l mang theo n,thc ung dng c si m.Gook luck!!!!!

B sung thm 1 na:Khi thy hi :"em hiu phn no nht ?" th ko nn tr li:"em ch hiu phn Diod".Bi v cu nythy nghe nhiu qu ri, mt s a b ui ra ngoi v cu ny v trc khi ui thy cn chi

cho 1 trn na.

Tt nht l ni: "em hiu 1/3" thy cho 3 im i v.Kho re

------------------------------------------------------------


9/15

He he! Cu kin l mt mn kh xng c phn l thuyt ln th nghim!Ni chung ai bt u hc mn ny cng thy kh! Phn l thuyt th cc u phi cy tht nhiuvo,theo kinh nghim hc th mn ny mun thi tt ng nhin phi lm nhiu bi tp ri,tuynhin ci xng ca mn ny l thy s ko ra d nh l bi tp lm trn lp u m cn m rnghn nhiu.Ch cc dng mch ghp tng khuch i(BJT,FET).Mn ny th nn c gng lm tt

phn trc nghim, cn phn bi tp th va kh m yu cu ca thy cng cao na.Cui k phntrc nghim s tp trung ch yu vo t chng 3 tr i(nht l SCR,Thyristor,triac...).Nu hiu rc tnh lm vic ca tng loi th c th suy lun ra m tr li ng c nu ko bit th chtchc!Hm nay mun ri, phn bo v tn th s ni sau!Chc cc u thi tt!ci th 1 l do PL tnh theo dng in hiu dng (IL/CN 2)2

Bi vit ca friend_for_life_2312 _(^_^) (^_^)_ QUOTE by Ent - DUT forum

cho mnh hi ci1.Ti sao cng sut tiu tn trn ti li bng PL=IL^2.RL/2 (1/2 ny ly u ra? )2. Mnh thy trong tp bi gii c ni " mch lm vic n nh th RB=0,1..RE " bn no

bit gii thch r hn t c khng? Vii li RE l REac hay REdc vy?Cm n trc nha.Cu 2. l lut 10 : 1 m. Mt s sch c ni."Gio trnh cu kin in t" ca hcvin cng ngh bu chnh vin thng chng hn.V khng th tnh trc tip R1 v R2 nn mch hot ng n nh th ta chn R1 v R2 sao cho VB c gi tr ph hp v dngin qua R1 v R2 gn nh l bng nhau tc l 2 dng ln hn nhiu so vi Ib th yucu 10RB lc cn R1 // R2 nn Rth= R1//R2.


10/15

V li s c Vth ni tip Rth ni vo cc B ca BJT, b R1,R2, phn pha sau gi nguyn. G.luck

B tay cho ci kt ln ca bn nguyenha v bn thu thi , hm ba nhm t ol 6k v 6.5k i vi B1-B2 v B2-B1. Nhng sau nhn vo bi bo co "mu" th thy2 gi tr nh nhau nn phang vo l 6k v 6k lun.

Xem s tng ng ca hn th bik k, ng c bo l o u G v 1 u B bt k

nh

Da vo s mch tng ng, nu o u G v 1 u B th s ging 1 diode, cn o2 u B1 v B2 th chng khc g 1 in tr.

Hnh nh my em 10DT chun b thi cu kin nn mnh post cu trc thy thng ra gn y my em d n tp hn

1)phn trc nghim: gm c t (8-->10) cu hi v l thuyt + bi tp nhanh, ci ny phi c

k phn l thuyt trong sch v hiu mi lm c, nn phn ny l (5-->6 im)

2)phn t lun:2 cu, thng thy ra trong quyn bi tp, lm ht trong l ok 4-->5 imNn canh thi gian phn b hp l, ng nn bu phn trc nghim lu qu(v c nhng cu hikh vi li nhiu phng n nhiu na) lm phn t lun kim chc 4-->5

V phn l thuyt my a nh k cc c tuyn nh,cc cu hi trc nghimca thy rng lm,c gng nm k vn l ok,phn ny 5 im,kim t im :DPhn bi tp th nh bn Lc ni,hu nh l bi tp trong tp bi tp,vo thi clm phn ny trc cho chc n :DCui cng chc mi ngi thi tt nh ^^phn trc nghim c ni n chnh la(v d nh cho ci s chnh la. hi l chn la g....)phn bi tp c 2 cu. 1 l v diode 2 l v fet


11/15

mt kinh nghim xng mu khi i thi cu kin in t nn em bp ch kim i thi. ci ny th aikhng nghe hi sau s r ni trc mt hay


hc BJT nhng khng bit cui k c phn khng?

cui k thy ra 2 cu BJT v op-am,thng l 1 cu BJT 1 cu op-am, nhng cng c lc c 2 cuop-amQUOTE _(^_^) (^_^)_ Din n sinh vin khoa in t -Vin thng - HBK Nng

Phn FET c ra mch xoay chiu hay 1 chiu ra?mun phn tch ac, phi phn tch dc ci chTm li mun im cao th phi hc ht, nu BJT hok c trong t lun th cng c trong phn trcnghimSau khi TN xong 7 bui s c bo v em ,bo co vit bng ting Vit ghi li r nhng s liumnh o c cc bi,rt kinh nghim l bit ci g th vit vo ci ,ng c vit di dng

v nhng ci mnh khng bit.Chc em hc v thi tt ^^Bi vit ca ie_gt_(^_^) (^_^)_ QUOTE by Ent - DUT forum

Em c th nghim 3 ri nhng m vn thy m h. Mi ch hiu v thyristor v triac,anh ch no hng dn v bi 3 gip em vi, c th l khi vo th nghim s lm nhngg y. Em cm n nh!!!

Bi vit ca only_begin _(^_^) (^_^)_ QUOTE by Ent - DUT forum

Cho em hi dm a bn ang bo v th nghim cu kin in t:V sao khi ta o 2 que o gia B1 v B2 th in tr gia Rb1-b2 v Rb2-b1 khc nhau.

H, phi ging nhau ch, ko thy trong kt lun v UJT c cu "in tr ni xut hin

ging mt gi tr in tr"

coi , nh li thi th no:

- thi cui k cng gm` trc nghim (22 cu th phi) -6dv 2 cu bi tp -4d

1.phn trc nghim ni v kin thc chung anh nh c vi cu th ny:-Tip gip pn c bao nhiu loi in t ? -3 hay 4 chi ko nh na (in t, l trng,....)-JFET v DMOS(knh ngho) khc nhau ch no? -ci ny chn: DMoS knh c sn, cn

JFET ko-Nu cng thc tnh h s khuch i dng ca mch BJT mc B chung (cu ny khi a

ng ngi ) ?+chn cu c cng thc th ny:

CODE _(^_^) (^_^)_ Din n sinh vin khoa in t -Vin thng - HBK Nng

-Dong Ic ln nht khi no?-c tuyn sau l ca linh kin no ?



12/15

+chn p n : DMOS knh N-Ci no thuc ( ko thuc) h Thyristor trong ci lkin sau ? Cu ny thuc chg 5 + thm 2 cu

na(kh hn)-Mt bi tp nh ve JFET phn p cho y thng s cn thit yu cu tm R1 v R2. (ci ny 2-3

cu trc nghim)Ngoi ra cn c 1 s cu thuoc phn dit cc bn v xem li my bi tp trong sch trc nghim l

lm c thi..............

........... [cn na nhng nh hok ni ]

2.Phn bi tp: phn ny bit lm th mi lm c khng loto nh phn trn u nha-cu u th nhiu dng ->> hn xui, nh c 2 dng nh th ny:+ Kdai vi sai, tm Vb,Vc,Ve ca cc BJT , tm h s khuch i in p ca u ra n & h s

khuch i vi sai ca mch:CODE _(^_^) (^_^)_ Din n sinh vin khoa in t -Vin thng - HBK Nng

+Ghp tng - dng mch gn ging th ny:CODE _(^_^) (^_^)_ Din n sinh vin khoa in t -Vin thng - HBK Nng

Cc bn nn tm hiu thm cc truong hp khng c t lin lc; BJT 1 npn,BJT 2 pnp ;v trng hp BJT 2 mcnguc (cc E ni ln trn cn cc C mc xuong duoi).

- Cau 2 th thuc dang bi tp chg 6: -ci ny 2 im-Dng ging nh th ny:*** H TTL : phn tch mch , lp bng logic cho u vo,cc cng v u ra.



13/15

*** H CMOS: Ch lp bng logic cho u vo,cc cng v u ra.

Dng th ny :



Bng logic:


Tm li thi c chng y,ko cn lm nhiu m ch cn hiu nguyn l ca n l ok ri.Chc cc bn thi tt !

Bi vit ca FotD _(^_^) (^_^)_ QUOTE by Ent - DUT forum

Cho mnh hi trong my bi thit k mch khuych i bng JFET, p s nhiu bi c Rsacv Rsdc, nh vy ngha l sao, trong ti liu ch no c nh mi ngi ch dm

Mn ni l mn mnh hc ngu nht trong tt c cc mn tri qua BKN

Ci Rs trong iu kin bnh thng s khng c r mch do t.Trong bi thit k thng thng cho my ci thng s by by VD: Vgsoff th tm ra c Vgs.--> tm c Rs. Rs l Rsdc.Tm c Rs--> Rc.....Khi trong bi thit k m c cho Av th khi thay v cng thc. Nu nh thay gi tr Rs trn mkhng m bo Av theo yu cu th mnh phi thay i gi tr Rs. Nu khng sai th Rs mi c gitr nh hn Rs u. Gi gi tr mi l Rs1. Th phn bt i l Rs2.C ngha l chia Rs thnh 2 phn l Rs1 v Rs2. Rs=Rs1+Rs2phn Rs2 dng t ngn mch xung t. phn l Rsac.

Nu nh khng nhm l nh ra


14/15

Goodluck.

Bi vit ca phuongtuan18 _(^_^) (^_^)_ QUOTE by Ent - DUT forum

Cho em hi thm 1 cht, lm sao xc nh c im lm vic tnh Q , bi hn ch choVgsoff v Idss.

Em chn cng cng Idsq=Idss/2, Vds=Vdd/2 ra m c my bi ng mi cht ch(my bi c p s)

th chn th ch sao na ch Tunim tnh Q thng chn gia ca ng ti mlc Idsq=Idss/2, Vds=Vdd/2thng l chn nh thchn nh th nhng lc tnh nu kt qu ph hp th cnu m khng ph hp phi chn im tnh Q khcCn ci Rsac v Rsdc th nh anh Hng ni tgi s thit k mch phn cc phn p JFET knh Nban u mnh chn im tnh Q ri sau tnh ra c Rd + Rs=??p dng n thay vo Av tnh c Rdsau suy ra Rsthay Rs vo tnh VG=Vgsq+Id.Rs

nu VG m dng th khng c Rsac tc khng c t r mt thnh phn ca Rsnu m VG m :th do cc cng c cp ngun VDD nn VG>=0 nn ta phi thit k li mch tc lchuyn sang mch t phn cc VG=0thay vo li phng trnh VG=Vgsq+Id.Rs ta tnh c Rs chnh l Rsdc ri thay voRd+ Rs=?tnh c Rd

ri thay Rd vo cng thc tnh Av=-Gm.RdsongsongRL/1+Gm.Rsacta tnh c Rsac tc thnh phn ny chnh l thnh phn Rs ko b t r mchtham kho nh!!

c sa bi loi09dt1 - 13/10/2010 lc 19:46Bi vit ca phuongtuan18 _(^_^) (^_^)_ QUOTE by Ent - DUT forum

Mnh c mt thc mc nho nh, cc bc gii thch gim cht: Ti sao xi Transistor phi ni

t , v trong bng mch "t" l ch m! Kin thc cn nng mong c tn tnh ch

gio...

Thc ra ni t (Ground) l c th xem nh im c in p =0V. Trong thc t

chng ai em bng mch ca mnh ni t c , ko l xi ci di ng, i u cng c 1

dy ni xung t . Trong mch thng c nhiu im ni t, l cc imchung hay cn gi l Mass (Mass l cc im chung), thng th n s ni vi cc m cangun.Bi vit ca phuongtuan18 _(^_^) (^_^)_ QUOTE by Ent - DUT forum

Mnh c mt thc mc nho nh, cc bc gii thch gim cht: Ti sao xi Transistor phi ni

t , v trong bng mch "t" l ch m! Kin thc cn nng mong c tn tnh ch

gio...


15/15

transistor c cu trc nh t in c in dung nh d b tch in tnh khi chm vo chn ca

transistor n s b nh thng nn cn phi ni t hoc ni cc cc ca n vi nhau

bc virus lm chi ci gh th

tham kho!!hot thy thi thng c 2 phn, 1 l trc nghim, 2 l bi tp. Bi tp th r rng l phn tchmch, m mun phn tch mch th c nm r nguyn l hot ng th phn tch dc thi. Nhng btth ngoi nm l thuyt cn phi lm nhiu, cc dng th chc l lp thy c cho bi tp tngchng ri, xo i xo li cng s lm dc bi cui k thi. Cn trc nghim th v l dng trcnghim nn khi hc t, tng detail trong ti liu or bi ging ca thy nn nm k. Gud luk!

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