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thi mn: L THUYT TRNG IN TTn ch, 05/2007, 1
(Thi gian lm bi: 90 phtKhng s dng ti liu, np cng vi bi thi)
Bi 1:
Cho mt S gii hn bi ng knP A B C D A= nh trn hnh v vi bn knh1R =
.
Bit ( ) ( )2 2 x yx xy y xy= + + +F i i
, da
hng theo
Oz, tnh ( )S
rot d F a
i .
Bi 2:
Trong mt in trng c ( ) ( ) ( )2 2 2x y zyz zx xy= + + + + +E i i
i
. Tnh ABU cho
(3;4;5)= v (1;1;1)B = .
Bi 3:
Tnh vc-t cm ng t( )P
B
ti P (l tm ca cung trn). Bit hai on dy dn thng c
chiu di v hn, cung mt phn t ng trn ni hai dy c bn knh R, cng
dngin trong dy dn l I, dy dn trn nghing 45oso vi dy dn di.
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thi mn: L THUYT TRNG IN TTn ch, 05/2007, 3
(Thi gian lm bi: 90 phtKhng s dng ti liu, np cng vi bi thi)
Bi 1:
Cho mt S c gii hn bi ng kn P A B O A= nh trn hnh v vi bn knh 1R
= , gc 45xOA = .
Tnh ( )S
rot d F a
i bit2 5 2cosrr r = + +F i i i
.
Bi 2:
Xc nh vc- t cng in trng ( )PE
ti P (l tm
ca cung trn). Bit hai on dy dn thng c chiu div hn, cung mt na ng
trn ni hai dy c bn knhR. Cc dy dn c tch in vi mt in di .
Bi 3:
Cho mt vng hnh ch nht c t trng uB
nh hnh v. Mt in t ebay vo trong ttrng vi vn tc v(hng song song
vi trcOx). Bit khi lng ca in t l m, hy xcnh im bay ra ca in t. Ly
im bay vot trng ca in t l gc ta O(0,0).
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thi mn: L THUYT TRNG IN TTn ch, 05/2007, 4
(Thi gian lm bi: 90 phtKhng s dng ti liu, np cng vi bi thi)
Bi 1:
Cho mt cong S c gii hn bi ng knP A B C D A= nh trn hnh v vi bn
knh
5R = , chiu cao mt tr 8h = . Tnh ( )S
rot d F a
i bit
2 sin 5 2 coss zs z sz = + +F i i i
.
Bi 2:
Xc nh vc-t cng in trng ( )PE
ti P (l
tm ca cung trn). Bit hai on dy dn thng cchiu di v hn, cung mt
phn t ng trn ni haidy c bn knh R. Cc dy dn c tch in vi mt in di
.
Bi 3:
Cho mt vng hnh ch nht c t trng u B
nhhnh v. Mt khung dy hnh tam gic vung cn c cnhbn R song song vi
cc cnh gii hn ca vng c t
trng, in tr khung 0,1 , quay xung quay trc vi tns gc khng i l .
Xc nh cng ca dng incm ng.
