De Va Dap an KT Chuong II Dai So 11 NC

7/31/2019 De Va Dap an KT Chuong II Dai So 11 NC

1/4

www.daykemquynhon.ucoz.com Trung tm bi dng kin thc vn ha cho hc sinh cp 2 + 3

TRNG THPT S 1 TP LO CAI KIM TRA 1 TITT: TON - TIN Bi s:03 Hc k I, nm hc 2011-2012

MN : TON. LP: 11A1-11A6,11D S: 01

Cu 1(3,0im): Vi cc ch s 0,1,2,3,4,5 c th lp c bao nhiu s t nhin

a) C nm ch s khc nhau.b) C nm ch s khc nhau, trong c ch s 0.

Cu 2(2,0im):

Trong khai trin nh thc:20

32

5, 0x x

x

+

. Hy tm s hng khng cha x.

Cu 3(4,0im): Mt hp cha 6 qu cu mu v 5 qu cu mu xanh. Ly ngunhin 4 qu cu. Tnh xc sut .

a) Ly c ba qu cu mu , mt qu cu mu xanh.b) Ly c c bn qu cu cng mu.c) Ly c t nht mt qu cu xanh.

Cu 4(1,0im): Tm nghim nguyn dng ca phng trnh: 145

1 72 + = xxx PPA ---------------------- Ht -----------------------------

TRNG THPT S 1 TP LO CAI KIM TRA 1 TITT: TON - TIN

Bi s:03 Hc k I, nm hc 2011-2012MN : TON. LP: 11A1-11A6,11D S: 02

Cu 1(3,0im): Vi cc ch s 0, 1, 3, 6, 9 c th lp c bao nhiu s t nhina) C 4 ch s khc nhau.b) C 4 ch s khc nhau v l s chn.

Cu 2(2,0im):

Trong khai trin nh thc:10

32

2, 0x x

x

+

. Hy tm s hng cha x5.

Cu 3(4,0im): Mt bnh cha 7 vin bi trng, 6 vin bi en v 3 vin bi .Ly ngu nhin 3 vin bi. Tnh xc sut .

a) Ly c c ba vin bi .b) Ly c c c ba vin bi khng .c) Ly c mt vin bi trng, mt vin bi en v mt vin bi .

Cu 4(1,0im): Tm n nguyn dng bit rng 53 5720 .n n nP A P+ =

---------------------- Ht -----------------------------


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www.daykemquynhon.ucoz.com Trung tm bi dng kin thc vn ha cho hc sinh cp 2 + 3

P N I S 11NC 01

Cu p n imCu1(3,0) a) Mt s 5 ch s k hiu abcde vi

a c chn t tp { }0,1,3,4,5 c 5 cch chn.

b,c,d,e l mt b phn bit c chn t{ } { }0,1,3,4,5 \ a

C 45A cch chn

Vy s gm 5 ch s phn bit hnh thnh t tp E bng: 5. 45A = 600sb) Theo a) tp cc s gm 5 ch s phn bit 600Tp cc s gm 5 ch s phn bit hnh thnh t{ }0,1,3,4,5 trong

khng c ch s 0: 5 5! 120P = = sVy s gm 5 ch s PB, trong c ch s 0: 600- 120 = 480 s

0,5

0,50,5

1,00,5

Cu2(2,0)Ta c ( )

20 20 20203 3 60 520 202 2

0 0

5 55

kk

k k k k

k k

x C x C xx x

= =

+ = =

S hng th k + 1 khng ph thuc x tho mn: 60 5k = 0 k = 12

KL: 12 12205 C

0,50,50,5

0,5

Cu3(4,0)

Mi ln ly ngu nhin 4 qu cu trong hp cho ta mt t hp chp 4ca 11 phn t. Do , khng gian mu gm cc t hp chp 4 ca11 phn t.Vy s phn t ca khng gian mu l: 411C =330.a) Gi A l bin c Ly c ba qu cu mu , mt qu cu

mu xanh. 3 16 5.C C 3 16 5

411

.( )

C CP A

C=

b) Gi B l bin c : Ly c 4 qu cu cng mu+TH1: Ly c 4 qu cu mu : c 46C =15 (cch ly)

+TH2: Ly c 4 qu cu mu xanh: c 45C =5 (cch ly)20 2

( )330 33

P B = =

c)Gi C l bin c : Ly c t nht 1 qu cu mu xanh.C l bin c : Ly c 4 qu cu mu 46C =15

0,5

0,5

0,5

0,50,5

0,5


3/4

www.daykemquynhon.ucoz.com Trung tm bi dng kin thc vn ha cho hc sinh cp 2 + 315 1

( )330 22

P B = =

P(B)=1 )(BP =1-22

21

22

1=

0,5

0,5

Cu 4(1,0)

145

1 72 + = xxx PPA( )

( )

( ) ( )!172!4

!4

!1=

+ xx

x

x

72)1( =+ xx

x2 + x - 72 = 0

=

=

)(9

8

loaix

x

Vy phng trnh c nghim x=8

0,25

0,250,25

0,25

02Cu p n im

Cu 1(3,0) a) 45 120A = s c 4 ch s t tp cc ch s { }0,1,3,6,9 (c th bt

u vi ch s 0)34 24A = s c 4 ch s bt bu vi ch s 0

Vy c 120 24= 96 s c 4 ch s khc nhau

0,5

0,50,5

b) Gi s TN cn lp c dng abcd (vi a,b,c,d i mt khc nhauv a 0)+V s cn lp l s l nn d{1,3,9} c 3 cch chn d.+ Ch s a c 3 cch chn+ Ch s b c 3 cch chn

+ Ch s c c 2 cch chnS l c 4 ch s khc nhau3.3.3.2= 54 s lVy c 96 54 = 42 s chn

0,5

0,50,5

Cu2(2,0)Ta c ( )

10 10 10103 3 30 510 102 2

0 0

2 22

kk

k k k k

k k

x C x C xx x

= =

+ = =

S hng th k + 1 khng ph thuc x tho mn: 30 5k = 5 k = 5

KL:55

1052 xC

0,50,50,5

0,5

Cu3(4,0)a) 3

6

1 1

560C=

b)313316

143

280

C

C=

c) 316

7.6.3 9

40C=

1,5

1,5

1,0


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www.daykemquynhon.ucoz.com Trung tm bi dng kin thc vn ha cho hc sinh cp 2 + 3Cu 4(1,0)

( )( )

( ) ( ) ( )( )!

3 ! 720. 5 ! 3 2 1 720 75 !

nn n n n n n

n+ = + + + = =

Vy pt c nghim n = 7.

0,5

0,25

0,25

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De Va Dap an KT Chuong II Dai So 11 NC