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บทท่ี2 เร่ืองอนุพันธของฟงกชัน
Calculus 1Calculus 1Calculus 1Calculus 1
1
ก������� )(xfy = ��� ��ก���� ),( yxP �������� � ������� )(xfy = ��� ),( hyhxQ ++ ������������ !"��������ก�ก����� P ���$!�%"�&��'(
)'���� x ��&� )(xfy = )'���� hx + ��&� )( hxfy +=
����ก��������
1. ��%$�ก�$��'� ����� 2. ���-��.�/�� ��ก���� 3. ก�$�����-��.� ��ก����-'��12%�� ���2 �3 4. ก�$�����-��.� ��ก����-'��12%�� ���!%$ 5. ก�$�����-��.� ��ก������26� �� ���!%$ 6. ���-��.� ��ก�����$�ก�� ��ก������ �$2 � ������-��.��������!�
������ ����� ������ก ��� ����� 2
�����ก���� �����
),( yxP ∆x
y∆∆
),( hyhxQ ++
hx + x x
y
O
���ก����������� �:� ��ก����)'�/' �&��� ���2-��� ;����$�ก���< �"���%�< %�<��$����$:����3� �<ก �� ��$ ก$1=� ����' �"�
155 +− xx ���%�
บทท่ี2 เร่ืองอนุพันธของฟงกชัน
Calculus 1Calculus 1Calculus 1Calculus 1
2
�����(��"�)'���'� ���ก��� x &� ����� hx + $' ก<"� ��%$�ก�$��'� ����� /��%�<��$ x ��&�
xhxx −+=∆ )( �����)����&� )(xf ��'� �&���� )( hxf + $' ก<"� ��%$�ก�$��'� ����� /�� ��ก������&�
)()( xfhxfy −+=∆ ��%$�ก�$��'� �����/�� y )' �ก�� x �:� ��%$��"<�/���"� y )'���'� �&� %"��"� x )'���'� �
h
xfhxf
x
y
xhx
xfhxf
x
y
)()(
)(
)()(
−+=
∆∆
−+−+
=∆∆
3:�� x∆ /��ก� 0 ���"�&� $���$' ก�"��232%�'(<"� �������� ������ก���� )(xfy = ����ก�� x
�:� h
xfhxfh
)()(lim
0
−+→
�$:� x
yx ∆∆
→∆ 0lim
����� �� �� 73 2 −= xy ������%$�ก�$��'� �����/�� y )' �ก�� x �� ?�'� ���"<�3:�� x ��'� ���ก 1 &���� 4 �����!� ��ก��) ���&� 4=+ hx , 1=x ������%$�ก�$��'� �����
14
)1()4(
)(
)()(
−−
=
−+−+
=∆∆
ff
xhx
xfhxf
x
y
3
)4(413
)7)1(3()7)4(3( 22
−−=
−−−=
153
45
=
=
�����(���%$�ก�$��'� �����/�� y )' �ก�� x �� ?�'� ���"<�3:�� x ��'� ���ก 1 &���� 4 )"�ก�� 15
��%$�ก�$��'� �����/�� y )' �ก�� x �� ?�'� ���"<�3:�� x ��'� ���ก 1 &���� 4 )"�ก�� 15 ��� � "# � x�� "�$%� 1 '� ����(� y )*
�� "�$%��*"�� 15 '� ��
บทท่ี2 เร่ืองอนุพันธของฟงกชัน
Calculus 1Calculus 1Calculus 1Calculus 1
3
��������������ก����
����"����������� ก������� )(xfy = ��� ��ก������� ���-��.�/�� )(xf /' ��)��< ��A��กB1� )(xf ′ �"��<"� Cf prime xJ ;���ก�����/�(�����'(
h
xfhxf
x
yxf
hx
)()(limlim)(
00
−+=
∆∆
=′→→∆
K��232%�'(���"�&�$���ก�"�<<"� f ��� ��ก����)'������-��.�&� ���$' ก )(xf ′ <"� C���-��.�/�� ��ก���� f )'� x J K� )(xfy = ��< ���-��.�/�� ��ก���� f )'� x ��ก��ก��/' ��)��< )(xf ′ ����3�$K/' ��)���A��กB1��:��&��'ก �:�
dx
dyy ,′ �$:�
dx
xdf )(
�����������ก���� f ��� x ���������ก������������������ก��� )(xfy = � ����� �! "�#����ก��
บทท่ี2 เร่ืองอนุพันธของฟงกชัน
Calculus 1Calculus 1Calculus 1Calculus 1
4
����� �� ก������� 3)( += xxf �������-��.�/�� )(xf
�����!� ��ก��) � 3)( += xxf ��&� 3)()( ++=+ hxhxf ��ก�2 �3
1
lim
33lim
)3()3)((lim
)()(lim)(
0
0
0
0
=
=
−−++=
+−++=
−+=′
→
→
→
→
h
hh
xhxh
xhxh
xfhxfxf
h
h
h
h
�����(����-��.�/�� 3)( += xxf )"�ก�� 1
ก��'������������ก�����������,-�.�(����"
����</��'($������2 �3/�����-��.�-:������<1���"����-��.������:�
h
xfhxfxf
h
)()(lim)(
0
−+=′
→
บทท่ี2 เร่ืองอนุพันธของฟงกชัน
Calculus 1Calculus 1Calculus 1Calculus 1
5
����� �� ก������� 1)( 2 −+= xxxf �������-��.�/�� )(xf
�����!� ��ก��) � 1)( 2 −+= xxxf ��&� 1)()()( 2 −+++=+ hxhxhxf
1)()2( 22 −++++= hxhxhx (�!%$ก���������3�!$1� ( ) 222 2 BABABA ++=+ )
)1()12(
122
22
−++++=
−++++=
xxhxh
hxhxhx
��ก�2 �3
[ ]
12
102
12lim
)12(lim
)1()1()12(lim
)()(lim)(
0
0
22
0
0
+=
++=
++=
++=
−+−−++++=
−+=′
→
→
→
→
x
x
hxh
hxhh
xxxxhxh
h
xfhxfxf
h
h
h
h
�����(����-��.�/�� 1)( 2 −+= xxxf )"�ก�� 12 +x
)�)<��!%$�!%$ก���������3�!$1� ( ) 222 2 BABABA ++=+ ( ) 222 2 BABABA +−=−
บทท่ี2 เร่ืองอนุพันธของฟงกชัน
Calculus 1Calculus 1Calculus 1Calculus 1
6
����� �� ก������� 2)( 3 −= xxf �������-��.�/�� )(xf
�����!� ��ก��) � 2)( 3 −= xxf ��&� 2)()( 3 −+=+ hxhxf
2)2)(( 22 −+++= hxhxhx ( )[ ]23 )BA)(BA(BA ++=+
)2()33(
233322
3223
−+++=
−+++=
xhxhxh
hxhhxx
��ก�2 �3
[ ]
2
2
22
0
22
0
3322
0
0
3
003
33lim
)33(lim
)2()2()33(lim
)()(lim)(
x
x
hxhx
h
hxhxh
h
xxhxhxh
h
xfhxfxf
h
h
h
h
=
++=
++=
++=
−−−+++=
−+=′
→
→
→
→
�����(����-��.�/�� 2)( 3 −= xxf )"�ก�� 23x
3323
223
33
)2)(()(
BABBAA
BABABABA
+++=
+++=+
บทท่ี2 เร่ืองอนุพันธของฟงกชัน
Calculus 1Calculus 1Calculus 1Calculus 1
7
����� �� ก������� 0;1
)( >= xx
xf �������-��.�/�� )(xf
�����!� ��ก��) � x
xf1
)( =
��&� hx
hxf+
=+1
)(
��ก�2 �3
xx
xxxx
xxxx
hxxhxx
hxxhxx
h
h
hxxhxx
hxx
h
hxx
hxx
hxx
hxx
h
hxx
hxx
h
xhxh
h
xfhxfxf
h
h
h
h
h
h
h
2
1
1
)0()0(
1
)()(
1lim
)()(
1lim
)()(
)(1lim
))((
1lim
)()(
1lim
111lim
)()(lim)(
0
0
0
0
0
0
0
−=
+
−=
+++
−=
+++
−=
+++
−=
+++
+−=
++
++
+
+−=
+
+−=
−
+=
−+=′
→
→
→
→
→
→
→
�����(����-��.�/�� 0;1
)( >= xx
xf )"�ก�� xx2
1−
บทท่ี2 เร่ืองอนุพันธของฟงกชัน
Calculus 1Calculus 1Calculus 1Calculus 1
8
����� �� �������-��.�/�� )(xf %"�&��'(�� ���2 �3 1. xxf 3)( = 2. 2)( 3 −= xxf 3. 123)( 2 +−= xxxf PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP
บทท่ี2 เร่ืองอนุพันธของฟงกชัน
Calculus 1Calculus 1Calculus 1Calculus 1
9
PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP
บทท่ี2 เร่ืองอนุพันธของฟงกชัน
Calculus 1Calculus 1Calculus 1Calculus 1
10
ก��'������������ก�����������,-�.�(/0��
ก�$�����-��.��� ���2 �3��(����ก�$ �"� �ก���)�����' <��3�ก �����(����3'ก�$�$���!%$����$�������-��.�/�� ��ก����-'��12%/�(� �)�ก�$���2 �3 �� �� )(,)( xvxu ��� ��ก����/�� x
��� c ��� �"����-��.�/�� ��ก����/' ��)��< )(xf ′ , dx
dyy ,′
�$:� dx
xdf )(
������������ ������ �� cxf =)( ��&�
chxf =+ )(
h
xfhxfxf
h
)()(lim)(
0
−+=′
→
0
lim)(0
=
−=′
→ h
ccxf
h
�����(���&��!%$
0=dx
dc
/0��-1ก2
บทท่ี2 เร่ืองอนุพันธของฟงกชัน
Calculus 1Calculus 1Calculus 1Calculus 1
11
���������������� �� xxf =)( ��&� hxhxf +=+ )(
h
xfhxfxf
h
)()(lim)(
0
−+=′
→
1
1lim
lim
lim)(
0
0
0
=
=
=
−+=′
→
→
→
h
h
h
h
hh
xhxxf
�����(���&��!%$
1=dx
dx
��������������ก������ "�� �������0���0 �� )()( xcfxg = 3:�� c ����"���%�< ��&� )()( hxcfhxg +=+
h
xghxgxg
h
)()(lim)(
0
−+=′
→
)(
)()(lim
)]()([lim
)()(lim)(
0
0
0
xfch
xfhxfc
h
xfhxfch
xcfhxcfxg
h
h
h
′=
−+=
−+=
−+=′
→
→
→
�����(���&��!%$ 3:�� c ����"���%�<
dx
xdfc
dx
xdcf )()(=
/���"�ก
บทท่ี2 เร่ืองอนุพันธของฟงกชัน
Calculus 1Calculus 1Calculus 1Calculus 1
12
��������������ก���� nx ��* nu �� nxxf =)( 3:�� n ����/����<��$2������� 0n ≠ ��&� nhxhxf )()( +=+
h
xfhxfxf
h
)()(lim)(
0
−+=′
→
1
1
121
0
121
0
221
0
2221
0
0
0...0
...!2
)1(lim
]...!2
)1([
lim
...!2
)1(
lim
]...!2
)1([
lim
)(lim)(
−
−
−−−
→
−−−
→
−−
→
−−
→
→
=
+++=
++−
+=
++−
+=
++−
+=
−++−
++=
−+=′
n
n
nnn
h
nnn
h
nnn
h
nnnn
h
nn
h
nx
nx
hhxnn
nx
h
hhxnn
nxh
h
hhxnn
hnx
h
xhhxnn
hnxx
h
xhxxf
�����(���&��!%$ ���
1−= nn
nxdx
dx
nxxf =)( 3:�� n ����/����<��$2������� 0n ≠ -$��K� 0=n ��)���� 1)( 0 == xxf
dx
dunu
dx
du nn
1−=
บทท่ี2 เร่ืองอนุพันธของฟงกชัน
Calculus 1Calculus 1Calculus 1Calculus 1
13
�����������3���ก'�#�3�� ��������ก���� �� )()()( xvxuxf ±= �� )'� u ��� v 3'���-��.�)'� x ��&� )()()( hxvhxuxf +±+=+
h
xfhxfxf
h
)()(lim)(
0
−+=′
→
)()(
)()(lim
)()(lim
)]()([)]()([lim)(
00
0
xvxuh
xvhxv
h
xuhxuh
xvxuhxvhxuxf
hh
h
′±′=
−+±
−+=
±−+±+=′
→→
→
�����(���&��!%$
dx
dv
dx
duvu
dx
d±=± ][
����� �� �������-��.�/�� 7254)( 23 −+−= xxxxf
�����!� )7254()( 23 −+−=′ xxxdx
dxf
7254 23
dx
dx
dx
dx
dx
dx
dx
d−+−= → ][ vu
dx
d±
7254 23
dx
dx
dx
dx
dx
dx
dx
d−+−= → )(xcf
dx
d
0)1(2)2(5)3(4 2 −+−= xx → dx
dc
dx
dx
dx
dxn
,,
21012 2 +−= xx �����(� ���-��.�/�� 7254)( 23 −+−= xxxxf )"�ก�� 21012 2 +− xx
บทท่ี2 เร่ืองอนุพันธของฟงกชัน
Calculus 1Calculus 1Calculus 1Calculus 1
14
����� �� �������-��.�/�� 96 )35()( −= xxf
�����!� 96 )35()( −=′ xdx
dxf
)35()35(9 686 −−= xdx
dx → nu
dx
d
]35[)35(9 686
dx
dx
dx
dx −−= → ][ vu
dx
d± , )(xcf
dx
d
]0)6(5[)35(9 586 −−= xx → dx
dc
dx
dxn
,
865 )35(27 −= xx �����(� ���-��.�/�� 96 )35()( −= xxf )"�ก�� 865 )35(27 −xx
����� �� �������-��.�/�� 5
432)(
xxxxf +−=
�����!� )43
2()(5xx
xdx
dxf +−=′
52
1
2
1
432 −−+−= x
dx
dx
dx
dx
dx
d → ][ vudx
d±
52
1
2
1
432 −−+−= x
dx
dx
dx
dx
dx
d → )(xcfdx
d
)5(4)2
1(3)
2
1(2 62
3
2
1−−−
−+−−= xxx → dx
dxn
62
3
2
1
202
3 −−−−+= xxx
6
2
3
20
2
31x
xx
−+=
�����(� ���-��.�/�� 5
432)(
xxxxf +−= )"�ก��
6
2
3
20
2
31
xx
x−+
บทท่ี2 เร่ืองอนุพันธของฟงกชัน
Calculus 1Calculus 1Calculus 1Calculus 1
15
����� �� �������-��.�/��
1. 73 )43()( +−= xxxf 2. 522)( 3 ++= xxxf 3. 74
713)(
xxxxf −−=
4. 523 )943(
1)(
−−+=
xxxxf 5. 35335)( 81221 −+−−= xxxxxf
PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP
บทท่ี2 เร่ืองอนุพันธของฟงกชัน
Calculus 1Calculus 1Calculus 1Calculus 1
16
PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP
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Calculus 1Calculus 1Calculus 1Calculus 1
17
��������3��0�������ก���� �� )().()( xvxuxf = ��&� )().()( hxvhxuhxf ++=+
h
xvxuhxvhxuxf
h
)().()().(lim)(
0
−++=′
→
��� )x(v).hx(u + 3��<ก/��������ก ��&�
h
xvhxuxvhxuxvxuhxvhxuxf
h
)]().()().([)]().()().([lim)(
0
+−++−++=′
→
h
xvxuxvhxuxvhxuhxvhxuh
)]().()().([)]().()().([lim
0
−+++−++=
→
h
xuhxuxvxvhxvhxuh
)]()()[()]()()[(lim
0
−++−++=
→
h
xuhxuxv
h
xvhxvhxu
hhhh
)]()([lim).(lim
)]()([lim.)(lim
0000
−++
−++=
→→→→
)().()(.)( xudx
dxvxv
dx
dxu +=
�����(���&��!%$
dx
duv
dx
dvuvu
dx
d+=).(
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Calculus 1Calculus 1Calculus 1Calculus 1
18
��������3�'��������ก����
�� )(
)()(
xv
xuxf = ��&�
)(
)()(
hxv
hxuhxf
++
=+
)(.)(.
)(.)()(.)(lim
)(.)(
)(.)()(.)(
lim
)(
)(
)(
)(
lim)(
0
0
0
xvhxvh
xuhxvxvhxuh
xvhxv
xuhxvxvhxuh
xv
xu
hxv
hxu
xf
h
h
h
++−+
=
++−+
=
−++
=′
→
→
→
��� )().( xvxu 3��<ก/��������ก ��&�
)(.)(.
)().()().()](.)()(.)([lim)(
0 xvhxvh
xvxuxvxuxuhxvxvhxuxf
h +−++−+
=′→
)(.)(.
)]().()(.)([)](.)()(.)([lim
0 xvhxvh
xvxuxuhxvxvxuxvhxuh +
−+−−+=
→
)(.)(.
)]()()[(])()()[(lim
0 xvhxvh
xvhxvxuxuhxuxvh +
−+−−+=
→
)(.)(
)]()([)(
])()([)(
lim0 xvhxv
h
xvhxvxu
h
xuhxuxv
h +
−+−
−+
=→
)(.)(lim
)]()([lim.)(lim
])()([lim.)(lim
0
0000
xvhxvh
xvhxvxu
h
xuhxuxv
h
hhhh
+
−+−
−+
=→
→→→→
)(.)(
)(.)(
)(.)(
xvxvdx
xdvxu
dx
xduxv −
=
�����(���&��!%$
2)(
vdx
dvu
dx
duv
v
u
dx
d−
=
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Calculus 1Calculus 1Calculus 1Calculus 1
19
�����4" .'(�#"/0��
��ก�!%$ dx
duv
dx
dvuvu
dx
d+=).( $������)"������!%$<"�
-�� ('�(�'���) = '�(�-��'��� ��ก '���-��'�(�
�"<��!%$ 2
)(v
dx
dvu
dx
duv
v
u
dx
d−
= �����)"��<"�
-�� (��'��� �� ) = � ��-���� �� ��-��� �� / ��-(��� ��ก!����/��
����� �� �������-��.�/�� )57()12( 2 +−= xxy ���� dx
dy
�����!� )57()12( 2 +−= xxdx
d
dx
dy → 57,12 2 +=−= xvxu
)12()57()57()12( 22 −+++−= xdx
dxx
dx
dx →
dx
duv
dx
dvuvu
dx
d+=).(
)4)(57()7)(12( 2 xxxx ++−= ,
xxxx 2028714 23 ++−= xxx 132814 23 ++= )132814( 2 ++= xxx �����(� ���-��.�/�� )57()12( 2 +−= xxy )"�ก�� )132814( 2 ++ xxx
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Calculus 1Calculus 1Calculus 1Calculus 1
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����� �� �������-��.�/�� )133()4( 52 −+= xxy ���� dx
dy
�����!� )133()4( 52 −+=′ xxdx
dy → )133(,)4( 52 −=+= xvxu
222
1
2
122 )4()133()133()4( +−+−+= x
dx
dxx
dx
dx →
dx
duv
dx
dvuvu
dx
d+=).(
)4()4(2)133()133()133(2
1)4( 222
1
2
122 ++−+−−+=
−x
dx
dxxxx
dx
dxx ,
)2)(4(2)133()3()133()4(2
1 22
1
2
122 xxxxx +−+−+=
−
133)4(4133
)4(
2
3 222
−++−
+= xxx
x
x
�����(� ���-��.�/�� )133()4( 52 −+= xxy )"�ก�� 133)4(4133
)4(
2
3 222
−++−
+xx
x
x
����� �� �������-��.�/�� 2
12
−−
=x
xy ����
dx
dy
�����!� )2
1(
2
−−
=′x
x
dx
dy → 2,12 −=−= xvxu
2
22
)2(
)2()1()1()2(
−
−−−−−=
x
xdx
dxx
dx
dx
→ 2
)(v
dx
dvu
dx
duv
v
u
dx
d−
=
2
2
)2(
)1)(1()2)(2(
−−−−
=x
xxx ,
2
22
)2(142
−+−−
=x
xxx
2
2
)2(14
−+−
=x
xx
�����(� ���-��.�/��212
−−
=x
xy )"�ก��
2
2
)2(14
−+−
x
xx
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Calculus 1Calculus 1Calculus 1Calculus 1
21
����� �� �������-��.�/�� 5
2 9
52
++
=x
xy ����
dx
dy
�����!� 5
2 9
52
++
=′x
x
dx
dy →
dx
du n
++
++
=9
52
9
525 2
4
2 x
x
dx
d
x
x → 9,52 2 +=+= xvxu
+
++−++
++
=22
22
42
4
)9(
)9()52()52()9(
)9(
)52(5
x
xdx
dxx
dx
dx
x
x→
2)(
vdx
dvu
dx
duv
v
u
dx
d−
= ,
++−+
++
=22
2
42
4
)9(
)2)(52()2)(9(
)9(
)52(5
x
xxx
x
x
2242
4
22
2
42
4
)9(
)2)(52(.
)9(
)52(5
)9(
)2)(9(.
)9(
)52(5
++
++
−++
++
=x
xx
x
x
x
x
x
x
62
5
52
4
)9(
)52(10
)9(
)52(10
++
−++
=x
xx
x
x
�����(� ���-��.�/��5
2 9
52
++
=x
xy )"�ก��
62
5
52
4
)9(
)52(10
)9(
)52(10
++
−++
x
xx
x
x
K�� �ก��ก"� %��)�����VWก��� ������$�� �3���VWก)�)<��< �$��
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Calculus 1Calculus 1Calculus 1Calculus 1
22
����� �� �������-��.�/��
1. 13
6)(
23
+−−
=x
xxxf 2. )343)(8522()( 424 −−+−−= xxxxxxf
3. 23
4)(
3
4
+−
−=
xx
xxf 4.
5
2
5
57
52)(
−−−
=xx
xxf
5. 3263 )35()53()( +−= xxxxf PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP
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PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP
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Calculus 1Calculus 1Calculus 1Calculus 1
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)�'�� ���������������ก����� �4��%
1. 992
93)( 23 +++−= xxxxf
2. x
xxxf
474)(
3 −+=
3. 32
11)(
xxxf −=
4. 5
2
3
14 59)(
−− +−= xxxxf
5. xx
xf +=2
1)(
6. 32 )2(
1
−=
xy
7. 314 xy −= 8. 22 )3( −−= xxy 9. 52 )4( −= xxy 10. )2)(78( 2 −−= xxy 11. )5)(32( 2234 −++−= xxxxxy
12. 392
+−
=x
xy
13. 92 +
=x
xy
14. xx
xxy
5
1282
2
−+−
=
15. 10
4
7
+−
=x
xy
�����ก���
��%�.)�!��*
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Calculus 1Calculus 1Calculus 1Calculus 1
25
���ก�����-�8�� (transcendental Functions) ��ก������26� �:� ��ก����)'�&3"��" ��ก����-'��12% �"� ��ก�����'(ก����� ��ก������ก�$2)�3 ��ก����%$'�ก132%2 ��� ��ก����%$'�ก132%2[ก[�� ���%� $!����/�� ��ก������26� 1. ��ก�����'(ก����� ( The Exponential Functions) ;���� !"��$!� xay = �$:� xey = 2. ��ก������ก�$2)�3 (The Logarithmic Functions) ;���� !"��$!� xy alog= �$:� xy ln=
3. ��ก����%$'�ก132%2 (The Trigonometric Functions) ;���3' 6 ��ก���� �:�
xxecxxxx cot,sec,cos,tan,cos,sin 4. ��ก����%$'�ก132%2[ก[�� (Inverse Trigonometric Functions) ;���3' 6 ��ก���� 3'
��กB1�����'(
1. xy 1sin−= กg%"�3:�� xy =sin 3:�� -1 ≤ x ≤ 1, -2π≤ y ≤
2π
2. xy 1cos−= กg%"�3:�� xy =cos 3:�� -1 ≤ x ≤ 1, 0 ≤ y ≤ π
3. xy 1tan−= กg%"�3:�� xy =tan 3:�� - ∞ < x < ∞ , -2π
< y < 2π
4. xecy 1cos −= กg%"�3:�� xyec =cos 3:�� x ≥ 1, y ε [0 , 2π
) ∪ (0 , 2π
]
5. xy 1sec−= กg%"�3:�� xy =sec 3:�� x ≥ 1, y ε [0 , 2π
) ∪ (2π
, π]
6. xy 1cot−= กg%"�3:�� xy =cot 3:�� - ∞ < x < ∞ , 0 < y < π
ก��'������������ก�����-�8��,-�.�(/0��
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Calculus 1Calculus 1Calculus 1Calculus 1
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ก��'���������������ก������ก����$" (Differentiation of Logarithmic Function) 3'�!%$ 2 �!%$ ����'( ����� �� ���� y′ 3:�� )152ln( 2 +−= xxy
<2.')�� ��ก dx
du
uu
dx
d 1ln =
��� )152ln( 2 +−= xxy
�����(� )152ln( 2 +−=′ xxdx
dy
152
54
)152(152
1
2
22
+−−
=
+−+−
=
xx
x
xxdx
d
xx
����� �� ���� y′ 3:�� )75(log 3
3 −= xy
<2.')�� ��ก dx
due
uu
dx
daa log
1log =
��� )75(log 33 −= xy
�����(� )75(log 33 −=′ x
dx
dy
e
x
x
xdx
de
x
33
2
333
log75
15
)75(log75
1
−=
−−
=
1. dx
due
uu
dx
daa log
1log =
2. dx
du
uu
dx
d 1ln =
พิจารณาให้ดีนะครับ...ว่าควรจะใช้สูตรใดประกอบด้วย
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%�<� "�� �����"����-��.�/�� ��ก����%"�&��'(
1. 43 )12ln()( +−= xxxf 2. )92(log
142)(
5
4
+−−
=x
xxxf
3. )726ln(.)( 3 +−= xxxxf 4.
+−
=2
13log)(
2
7 x
xxf
PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP
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PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP
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Calculus 1Calculus 1Calculus 1Calculus 1
29
ก��'���������������ก������%ก!���� (Differentiation of Exponential Function) �� )(,)( xvxu ��� ��ก���� ��3'�!%$����'( ����� �� �������-��.�/�� 252 2
4)( +−= xxxf
<2.')�� ��ก dx
duaaa
dx
d uu ln=
��� 252 2
4)( +−= xxxf �����(� 252 2
4)( +−=′ xxxf
4ln4)54(
)252(4ln4
252
2252
2
2
+−
+−
−=
+−=
xx
xx
x
xxdx
d
����� �� �������-��.�/�� 73)( −= xexf
<2.')�� ��ก dx
duee
dx
d uu =
��� 73)( −= xexf �����(� 73)( −=′ xexf
73
73
3
)73(
−
−
=
−=
x
x
e
xdx
de
����� �� �������-��.�/�� 52
)35()( +−+= xxxxf
�����!� ��ก dx
dvuu
dx
duvuu
dx
d vvv ln1 += −
��� 52
)35()( +−+= xxxxf
�����(� 52
)35()( +−+=′ xxxdx
dxf
)35ln()35)(12()35)(5(5
)5()35ln()35()35()35)(5(
542
25152
22
22
++−+++−=
+−++++++−=
+−+−
+−−+−
xxxxxx
xxdx
dxxx
dx
dxxx
xxxx
xxxx
dx
dvuu
dx
duvuu
dx
ddx
duee
dx
ddx
duaaa
dx
d
vvv
uu
uu
ln.3
.2
ln.1
1 +=
=
=
−
บทท่ี2 เร่ืองอนุพันธของฟงกชัน
Calculus 1Calculus 1Calculus 1Calculus 1
30
����� �� �������-��.�/�� 1. 3ln.)(
2
xexf x= 2. 535)( −= xxf 3. 8323 2
)23()( −−−+= xxxxxf
4. 33 )14(
)(+−
=xx
exf
x
5. xxxf ln.7)( =
PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP
บทท่ี2 เร่ืองอนุพันธของฟงกชัน
Calculus 1Calculus 1Calculus 1Calculus 1
31
PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP
บทท่ี2 เร่ืองอนุพันธของฟงกชัน
Calculus 1Calculus 1Calculus 1Calculus 1
32
ก��'���������������ก�������,ก�"��� (Differentiation of Trigonometric Function) 3'�!%$ 6 �!%$ ����'( ����� �� �������-��.�/�� )152cos()( 2 +−= xxxf
<2.')�� ��ก dx
duuu
dx
dsincos −=
��� )152cos()( 2 +−= xxxf
�����(� )152cos()( 2 +−=′ xxdx
dxf
)152sin()54(
)152()152sin(
2
22
+−−−=
+−+−−=
xxx
xxdx
dxx
����� �� �������-��.�/�� )73tan(.)(
2
−= xexf x
<2.')�� ��ก dx
duv
dx
dvuvu
dx
d+=).(
��� )73tan(.)(2
−= xexf x
�����(� 22
)73tan()73tan()( xx edx
dxx
dx
duexf −+−=′
)73tan(2)73(sec.3
).73tan()73()73(sec.
22
22
2
22
−+−=
−+−−=
xxexe
xdx
dexx
dx
dxe
xx
xx
1. dx
duuu
dx
dcossin =
2. dx
duuu
dx
dsincos −=
3. dx
duuu
dx
d 2sectan =
4. dx
duuecu
dx
d 2coscot −=
5. dx
duuuu
dx
dtan.secsec =
6. dx
duuecuecu
dx
dcot.coscos −=
บทท่ี2 เร่ืองอนุพันธของฟงกชัน
Calculus 1Calculus 1Calculus 1Calculus 1
33
����� �� �������-��.�/��
1. )(cos)( xeecxf = 2. )423cot( 4
5)( −+= xxxf 3. )8sin(
164)(
3
23
x
xxxxf
+−−=
4. xxf sec)( = 5. 32 tan.)( xxxf = PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP
บทท่ี2 เร่ืองอนุพันธของฟงกชัน
Calculus 1Calculus 1Calculus 1Calculus 1
34
PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP
บทท่ี2 เร่ืองอนุพันธของฟงกชัน
Calculus 1Calculus 1Calculus 1Calculus 1
35
ก��'���������������ก�������,ก�"���3ก3�� (Differentiation of Trigonometric Function) 3'�!%$ ����'(
����� �� 3:��ก������� y = sin-1 (3x - 4) ���� y′ PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP
����� �� 3:��ก������� y = tan-1(3x2+5)2 PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP
1. dx
d sin-1 u = dx
du
u 21
1
−
2. dx
d cos-1 u = dx
du
u21
1
−
−
3. dx
d tan-1 u = dx
du
u 21
1
+
4. dx
d csc-1 u = dx
du
uu 1
12 −
−
5. dx
d sec-1 u = dx
du
uu 1
12 −
6. dx
d cot-1 u = dx
du
u21
1
+−
บทท่ี2 เร่ืองอนุพันธของฟงกชัน
Calculus 1Calculus 1Calculus 1Calculus 1
36
ก��'���������������ก�����*ก�� ,-�.�(กP�0ก,Q ( chain rule)
กP�0ก,Q K� )(ufy = ��� )(xgu = ��� ��ก����;���3'���-��.�)'� u ��� x %�3
������ ��<��&� ��ก�����$�ก�� fog /�� x ;���ก������� ))(( xgfy = ��� ��ก����)'�3'���-��.�)'� x ���
dx
du
du
dy
dx
dy.=
��ก�!ก�;" ��&�
��ก�!%$ dx
dunuu
du
d nn 1−=
����� �� ก������� 452 2 −−= uuy ��� 22 −= xu ���� dx
dy
<2.')�� ��ก 452 2 −−= uuy
54
)452( 2
−=
−−=∴
u
uudu
d
du
dy
��ก 22 −= xu
x
xdu
d
dx
du
2
)2( 2
=
−=∴
กn�!ก�;" dx
du
du
dy
dx
dy.=
)134(2
)2).(584(
)2).(5)2(4(
)2).(54(
2
2
2
−=
−−=
−−=
−=
xx
xx
xx
xu
�����������ก�����*ก�����ก����,-��������*�����������-��/0�
บทท่ี2 เร่ืองอนุพันธของฟงกชัน
Calculus 1Calculus 1Calculus 1Calculus 1
37
����� �� 1. ก������� 231 uy −= ��� 223 +−= xxu ���� dx
dy
2. ก������� 523 23 −+−= xxuy ��� 35 += xu ���� dx
dy
PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP
บทท่ี2 เร่ืองอนุพันธของฟงกชัน
Calculus 1Calculus 1Calculus 1Calculus 1
38
����� �� ก������� 6uy = ��� xu 21+= ���� dx
dy
PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP
NOTE …………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………
บทท่ี2 เร่ืองอนุพันธของฟงกชัน
Calculus 1Calculus 1Calculus 1Calculus 1
39
ก��'���������,-������ (Implicit Differentiation) ��ก�����$2 � (Implicit Differentiation) �3� K�� ��ก����)'�ก��������� �3ก�$;��������<�3��3-��.�/�� x ��� y ;����"�/�� y &3"&�������ก3��� �������-���/�� x �$:��"�/�� x &3"&�������ก3��� �������-���/�� y ก�"�<�:� ��ก�����V�ก������� �3ก�$
0),( =yxF �"� x2 + y2 - a = 0, 3x2y - 3y2 + 2x - y2x - 5 = 0 ก�$�����-��.�/�� ��ก������ �$2 � )��&��� �����-��.�/���%"��/��/���3ก�$)' �ก�� x
�� ��K:�<"� y ��� ��ก����/�� x $' กก�$�����-��.�����'(<"� ก�$�����-��.��� �$2 �
����� �� ���� dx
dy /�� ��ก����%"�&��'( 042 22 =−++ yxyx
PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP
บทท่ี2 เร่ืองอนุพันธของฟงกชัน
Calculus 1Calculus 1Calculus 1Calculus 1
40
����� �� ���� dx
dy /�� ��ก����%"�&��'( yxyyx 8473 324 −=−
PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP
NOTE PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP.
บทท่ี2 เร่ืองอนุพันธของฟงกชัน
Calculus 1Calculus 1Calculus 1Calculus 1
41
�����������-��/0� (Higher Derivative) ก����� ��ก���� )(xfy = ��� K� )(xf ′ ������-��.�/�� )(xf $�$' ก )(xf ′ <"����-��.������������/�� )(xf )(xf ′′ ������-��.�/�� )(xf ′ $�$' ก )(xf ′′ <"����-��.����������/�� )(xf )(xf ′′′ ������-��.�/�� )(xf ′′ $�$' ก )(xf ′′′ <"����-��.���������3/�� )(xf $�����A��กB1�%"�&��'(�)����-��.��������!� K� )(xfy = ��< ��&�
yxfdx
dy ′=′= )(
yxfdx
yd
dx
dy
dx
d ′′=′′==
)(2
2
yxfdx
y
dx
yd
dx
d d ′′′=′′′==
)(
3
3
2
2
nnn
n
n
n
yxfdx
y
dx
yd
dx
d d ===
−
−
)(1
1
����� �� ก������� 9234 234 +−+−= xxxxy ���� 4,,, yyyy ′′′′′′ PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP
บทท่ี2 เร่ืองอนุพันธของฟงกชัน
Calculus 1Calculus 1Calculus 1Calculus 1
42
����� �� 1. ก������� 234)( xxf −= ���� )(xf ′′ 2. ก������� xexxf 23)( = ���� )(xf ′′′ PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP
บทท่ี2 เร่ืองอนุพันธของฟงกชัน
Calculus 1Calculus 1Calculus 1Calculus 1
43
1. ������<2.')��-:�������-��.�/�� ��ก����%"�&��'( 1.1 43)37()( xxf −= 1.2 5432)( 2468 −−−−−= xxxxxxf 1.3 )26()1()( 382 xxxg −−=
1.4 2
2
3
25)(
x
xxg
−
−=
1.5 23 ln.2)( xexf x= 1.6 )5cos(3)( 2 −−= xxf 1.7 32 3
)13()( −−−= xxxxf 1.8 )3.(sec)( xxxf = 1.9 73 )3.(sin)(
2
xexf x= 1.10 xxf 7tan5)( =
2. ก����� 43)( 2 += xxxf ���� )(xf ′ �� ���2 �3
−+=′
→ h
xfhxfxf
h
)()()( lim
0
3. ก������� 223 35,22 xuuuy −=−−= ���� dx
dy �� ��กn�!ก�;"
dx
du
du
dy.
4. ก����� 2)53ln()( −= xxf �����"� )(xf ′′
���WXก'�-