Doan Chi Tiet May Nmc

Embed Size (px)

Citation preview

TRNG I HC PHM VN NG KHOA K THUT CNG NGH N CHI TIT MY GVHD: Minh Tin TrangSVTH: Nguyn Minh Cng1 MC LCLI NI U....................................................................................................3 NHN XT CA GIO VIN.........................................................................4 PHN I: GII THIU H THNG DN NG...........................................5 I.B TRUYN BNH RNG: ....................................................................5 1.Nguyn l lm vic:...............................................................................5 2.u nhc im ca ca b truyn bnh rng:.......................................5 II. TRUYN NG BNH AI: ...................................................................5 1.Nguyn l lm vic: ..............................................................................5 2.u nhc im: ....................................................................................6 III. HP GIM TC: ......................................................................................6 1.u im: ...............................................................................................7 2.Nhc im: .........................................................................................7 IV. VN BI TRN H THNG: ...........................................................7 1. Bi trn b phn : ...............................................................................7 2. Bi trn trt:....................................................................................7 3. Bi trn hp gim tc: ..........................................................................8 PHN II: TNH TON CC THNG S H THNG:................................9 I.CHN NG C IN: ..........................................................................9 II.PHN B T S TRUYN: ...................................................................... 10 1. T s truyn chung: ................................................................................. 10 2. S vng quay ca mi trc:..................................................................... 103. Cng sut trn cc trc: .......................................................................... 10 4. Momen xon ca ng c:...................................................................... 11 5.Momen con trn cc trc:..................................................................... 11 PHN III: THIT K CC B TRUYN:...................................................... 12 I.THIT K B TRUYN AI: .................................................................. 12 1.Chn loi ai: ........................................................................................ 12 2.nh ng knh ai nh: ...................................................................... 12 3.Tnh ng knh ai ln: ....................................................................... 12 4.Xc nh s b khong cch trc A:....................................................... 13 5.Tnh chiu di L theo khong cch trc A:............................................. 13 6.Xc nh khong cch trc A: ................................................................ 13 7.Tnh gc m: ......................................................................................... 13 8.Xc nh s dy ai cn thit: ................................................................ 13 9.nh cc kch thc ch yu ca bnh ai: ............................................ 14 10.Tnh lc tc dng:.................................................................................. 14 II.THT K B TRUYN BNH RNG TR RNG THNG CP NHANH: .................................................................................................... 15 1.Chn vt liu ch to bnh rng v cch nhit luyn: ............................ 15 2.nh ng sut cho php:........................................................................ 16 3.Tnh khong cch trc A: ...................................................................... 17 4.Tnh vn tc ca bnh rng v chn cp chnh xc bnh rng:............... 18 TRNG I HC PHM VN NG KHOA K THUT CNG NGH N CHI TIT MY GVHD: Minh Tin TrangSVTH: Nguyn Minh Cng2 5.H s ti trng k: ................................................................................... 18 6.Xc nh m un, s rng v chiu rng bnh rng: .............................. 18 7.Kim nghim bn un ca rng: ....................................................... 18 8.Kim nghim sc bn ca chn rng khi chu qu ti t ngt:.............. 19 9.Xc nh cc thng s hnh hc ca b truyn:...................................... 20 10.Lc tc dng ln trc:........................................................................... 20 III. THIT K B TRUYN BNH RNG TR RNG THNG CPCHM: ...................................................................................................... 21 1.Chn vt liu ch to bnh rng v cch nhit luyn: ............................. 21 2.nh ng sut cho php: ........................................................................ 21 3.Tnh khong cch trc A: ...................................................................... 23 4.Tnh vn tc ca bnh rng v chn cp chnh xc bnh rng:............... 23 5.H s ti trng k: ................................................................................... 23 6.Xc nh m un, s rng v chiu rng bnh rng: .............................. 24 7.Kim nghim bn un ca rng: ....................................................... 24 8.Kim nghim sc bn ca chn rng khi chu qu ti t ngt:.............. 25 9.Xc nh cc thng s hnh hc ca b truyn:...................................... 25 10.Lc tc dng ln trc: ............................................................................ 26 PHN IV: TNH LC TC DNG TRC: ..................................................... 27 I.CHN VT LIU LM TRC: ............................................................... 27 II.TNH SC BN TRC : ........................................................................... 27 1.Tnh ng knh s b ca trc:........................................................... 27 2.Tnh gn ng trc: ............................................................................... 28 3.Tnh chnh xc trc: .............................................................................. 36 PHN V: TNH THEN:...................................................................................... 43 1. Tnh then lp trn trc I: ....................................................................... 43 2. Tnh then lp trn trc II: ...................................................................... 44 3. Tnh then lp trn trc III:....................................................................46TRNG I HC PHM VN NG KHOA K THUT CNG NGH N CHI TIT MY GVHD: Minh Tin TrangSVTH: Nguyn Minh Cng3 LI NI U Thit k v pht trin nhng h thng truyn ng l vn ct li trong c kh.Mtkhc,mtnncngnghipphttrinkhngththiumtnnckh hini.Vvy,victhitkvcitinnhnghthngtruynnglcng vic rt quan trng trong cng cuc hin i ho t nc. Hiu bit, nm vng vvndngttlthuytvothitkcchthngtruynnglnhngyu cu rt cn thit i vi sinh vin. Trong cuc sng ta c th bt gp h thng truyn ng khp ni, c th ni n ng mt vai tr quan trng trong cuc sng cng nh sn xut.i vi cchthngtruynngthnggpthhpgimtclmtbphnkhng th thiu. nthitkhthngdnngbngtigiptatmhiuvthitkhp gim tc, qua ta c th cng c li cc kin thc hc trong cc mn hc nh Nguyn l my_ Chi tit my, V k thut c kh..., v gip sinh vin c ci nhn tng quan v vic thit k c kh.Hp gim tc l mt trong nhng b phn in hnh m cng vic thit k gip chng ta lm quen vi cc chi tit c bn nhbnhrng,btruynai,Thmvo,trongqutrnhthchincc sinhvincthbsungvhonthinknngvAutoCad,iurtcnthit vi mt sinh vin c kh. Em chn thnh cm n cc thy trong khoa gip em rt nhiutrong qu trnh thc hin n. Vi kin thc cn hn hp, v vy thiu st l iu khng th trnh khi, em rt mong nhn c kin t thy c v cc bn Sinh vin thc hin: Nguyn Minh Cng TRNG I HC PHM VN NG KHOA K THUT CNG NGH N CHI TIT MY GVHD: Minh Tin TrangSVTH: Nguyn Minh Cng4 NHN XT CA GIO VIN ..............................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................TRNG I HC PHM VN NG KHOA K THUT CNG NGH N CHI TIT MY GVHD: Minh Tin TrangSVTH: Nguyn Minh Cng5 PHN I: GII THIU H THNG DN NG. I.TRUYN NG BNH RNG 1. Nguyn l lm vic: Truyn ng bnh rng gm bnh rng dn, bnh rng b dn, truyn ng bnh rng l mt phng php truyn chuyn ng v cng sut nh s n khp ca cc rng trn cc bnh rng 1l bnh dn 2 l bnh b dn n1 l s vng quay ca bnh dn n2 l s vng quay ca bnh b dn d1 l ng knh bnh dn d2 l ng knh bnh b dn

2. u nhc im ca truyn ng bnh rng: a. u im: - m bo chnh xc truyn ng (v, i) v khng c s trt. - T s truyn c nh. -Cthsptvtrtngigiacpbnhrngnkhptheongnggc mong mun trong khng gian (song song, cho hay vung gc vi nhau). - Hiu sut cao98 , 0 96 , 0 = q , thm ch99 , 0 = q cho mt cp bnh rng.- Kch thc b truyn tng i nh gn, kh nng ti ln. - Tui th v tin cy cao. - Lm vic trong phm vi cng sut, tc v t s truyn kh rng. b.Nhc im: - Khng thc hin c truyn ng v cp.- Khng c kh nng t bo v an ton khi qu ti. - C nhiu ting n khi vn tc ln. - i hi chnh xc cao trong ch to (ch to tng i phc tp) v lp rp. - Chu va p km v cng ca b truyn kh cao. II. TRUYN NG BNH AI 1. Nguyn l lm vic: Truynngailtruynngmastgintiptruynchuynngvc nng nh ma st ca ai vi cc bnh ai. 2n1n12d21dTRNG I HC PHM VN NG KHOA K THUT CNG NGH N CHI TIT MY GVHD: Minh Tin TrangSVTH: Nguyn Minh Cng6 1 l bnh dn 2 l bnh b dn3 l dy ai n1 l s vng quay bnh dnn2 l s vng quay bnh b dn 2. u nhc im ca truyn ng bnh ai: a. u im: - C kh nng truyn chuyn ng v c nng gia cc trc kh xa nhau. - Lm vic m, khng n do vt liu ai c tnh n hi. -Gicantonchoccchititmykhckhibquti,vlcnyais trc trn ton phn trn bnh. - Kt cu n gin, gi thnh r. b.Nhc im: - Khun kh kch thc kh ln (khi cng mt iu kin lm vic, thng ring ng knh bnh ai ln hn ng knh bnh rng khong 5 ln). - T s truyn khng n nh v c trt n hi trn bnh. - Lc tc dng ln trc v ln do phi cng ai (lc tc dng trn trcv tng thm3 2 ln so vi trong truyn ng bnh rng). - Tui th thp khi lm vic vi vn tc cao.- Khi dng bnh cng ai lm tng s chu k b un ca ai, s lm tui th ca ai. III. HP GIM TC Hp gim tc l c cu truyn ng bng n khp trc tip c t s truyn khng ivcdnggimvntcvtngmmenxon.Mtloiccutngt nhngcdngtngvntcgcvgimmmenxoncgilhpgim tc. Tu theo t s truyn chung ca hp gim tc ngi ta phn ra: hp gim tc mt cp v hp gim cp nhiu cp. Tu theo loi truyn ng trong hp gim tc ta phn ra: hp gim tc bnh rng tr, hp gim tc bnh rng cn hoc cn- tr, hp gim tc trc vt, trc vt- bnh rng hoc bnh rng - trc vt; hp gim tc bnh rng hnh tinh; hp gim tc bnh rngsngvngchpgimtc.Hpgimtccsdngrngritrong cc nghnh c kh, luyn kim, ho cht, trong cng nghip ng tu Cc loi hp gim tc: 32n 1n 12d 21dTRNG I HC PHM VN NG KHOA K THUT CNG NGH N CHI TIT MY GVHD: Minh Tin TrangSVTH: Nguyn Minh Cng7 - Hp gim tc bnh rng tr. + Hp gim tc bnh rng tr cp mt.+ Hp gim tc bnh rng tr cp hai. + Hp gim tc bnh rng tr cp ba. 1. u im: Hp gim tc l mt c cu gm cc b phn truyn bnh rng hay trc vt, to thnh mt t hp bit lp gim s vng quay v truyn cng sut t ng c n my cng tc. u im l hiu sut cao, c kh nng truyn nhng cng sut khc nhau, tui th ln, lm vic chc chn v s dng n gin. Phm vi cng sut, vn tc v t s truyn kh rng. 2. Nhc im: i vi hp gim tc nhiu cp ti trng phn b khng ng iu trn cc trc nn cc trc c chn theo phn lc ln nht, v vy kch thc v trng lng hp gim tc ln. Kh bi trn cc b truyn trong hp gim tc. IV. VN BI TRN CA H THNG 1. Bi trn b phn : Bi trn b phn nhm mc ch gim ma st gia cc chi tit ln, chng mn, to iu kin thot nhit tt, bo v b mt lm vic ca chi tit khng b hn g, gim ting n v bo v khi b bi bm. Vic chn hp l loi du v cch bi trn s lm tng tui th ca b phn . Khi chn cch bi trn cn da vo nhng iu kin sau: - Vn tc vng quay. - Ti trng tc ng.- Nhit lm vic v c im ca mi trng xung quanh. Cht bi trn thng dng l du hoc m Trong thc t khi vn tc di 4 5m/s u c th dng m hoc du bi trn b phn . Khi vn tc ln hn 5m/s ch nn dng du bi trn v khi vn tc cng ln ta chn nht cng cao.2. Bi trn trt: Bitrntttinhnhkhibphnanglmvic,ducavoch khngcplcthung,thngchottrnxunghocbncnhvo,hoc vng khe h ln nht gia ngng trc v lt . Vic a du bi trn vo ch c p lc thu ng thng lm gim kh nng ti ca . i vi ngng trc di nn lm rnh du du phn b u dc chiu di ngng trc. Du c cha cc v du ri t ng chy vo hoc dng bm du... Trong thc t thng xy ra trng hp trt lm vic ch ma st khng n nh v lm cho ngng trc dao ng. khc phc hin tng trn ngi ta lt hnh dp, dng c vng gng, hoc thay i ch cho du. TRNG I HC PHM VN NG KHOA K THUT CNG NGH N CHI TIT MY GVHD: Minh Tin TrangSVTH: Nguyn Minh Cng8 3. Bi trn hp gim tc: gimmtmtcngsutvmast,gimmimnrng,mbothot nhitttvphngccchititbhngcnphibitrnlntcccbtruyn trong hp gim tc. Vic chn hp l du, nht v h thng ( phng php ) bi trn s lm tng tui th ca cc b truyn tc l nng cao thi gian s dng my. Cc phng php bi trn hp gim tc: - Bi trn ngm du bng cch ngm bnh rng, bnh vt trc vt, hoc cc chi tit my ph ( bnh bi trn, vng vng du v.v) trong du cha hp - Bi trn lu thng dng cho cc hp gim tc c cng sut v vn tc khng lnlmnhngcutocankhngchophpthchincbitrnngmdu. Du bm t b vi p sut atm 7 , 1 5 , 0 theo cc ng ng qua cc vi phun n bi trn ch n khp. * Cc loi du thng dng bi trn hp gim tc: - Du cng nghip: Thng dng rng ri bi trn nhiu loi my khc nhau. Bi trn bng phng php lu thng nn dng du cng nghip 45 - Du tua pin: C cht lng tt nn thng dng bi trn cc b truyn bnh rng quay nhanh. - Du t my ko AK10 v AK15: Cng c dng bi trn hp gim tc. TRNG I HC PHM VN NG KHOA K THUT CNG NGH N CHI TIT MY GVHD: Minh Tin TrangSVTH: Nguyn Minh Cng9 PHN II: TNH TON CC THNG S H THNG. - Cc s liu cho trc: + Lc tc dng: P = 8400 N. + Vn tc bng ti: v = 0,77 m/s. + ng knh tang: D = 470 mm. + Thi gian: t = 5 nm. + Ca/ngy: 2 ca. + gi/ca: 6 gi. I. CHN NG C IN: -Tnh s vng quay ca trc tang: pht vngDvntg/ 3 , 31470 14 , 377 , 0 1000 60 1000 60= = =t - chn ng c in cn tnh cng sut cn thit Nu ta gi: N l cng sut trn bng ti D l ng knh tang ql hiu sut Nct l cng sut cn thitTa c: qNNct =Mt khc:5 , 6100077 , 0 84001000===v PNkw -Da vo bng| |((

I271 2 ta xc nh c cc thng s hiu sut. 3 2o kn br q q q q q =Trong :95 , 0 =ql hiu sut b truynbnh ai98 , 0 =brql hiu sut b truyn bnh rng 1 =knq l hiu sut khp ni995 , 0 =oql hiu sut ca mt cp lnKhi :9 , 0 995 , 0 1 98 , 0 95 , 03 2= = qVy: 2 , 79 , 05 , 6= =ctNkw Nhvycnphichnngclnhncngsutcnthit.Chnngc in che kn c qut gi k hiu (A02 - 52 - 4), c cng sut ng c=cN 7.5 kw, csvngquayngcnc=1460vng/pht.Nctstruynchungcth phnphitstruynchungcthphnphitstruynhplchobtruyn trong h thng dn ng. Tra bng| |((

13222p TRNG I HC PHM VN NG KHOA K THUT CNG NGH N CHI TIT MY GVHD: Minh Tin TrangSVTH: Nguyn Minh Cng10 II. PHN PHI T S TRUYN CHUNG: 1. T s truyn chung: 7 , 463 , 311460= = =tgcchnniTrong : nc l s vng quay ca ng c ntg l s vng quay ca tang Ta c t s truyn i vi cc phn t chuyn ng: bc bn i i i i =Trong :il t s truyn ca b truyn bnh ai ibnl t s truyn ca b truyn bnh rng tr rng thng cp nhanh ibcl t s truyn ca b truyn bnh rng tr rng thng cp chm Chn trc i = 5.Tra bng| |((

I322 2 Vy: 3 , 957 , 46= = = chbc bniii i bcbnii3 , 9= to iu kin bi trn trong hp gim tc bng phng php ngm du ta chn.bc bni i = ) 3 , 1 2 , 1 (bcbcii) 3 , 1 2 , 1 (3 , 9 = ) 7 , 2 8 , 2 () 3 , 1 2 , 1 (3 , 9 =||.|

\|= bciChn ibc = 2,8. 3 , 38 , 23 , 9= =bni2. S vng quay ca mi trc: 2925146012= = = = =cIIcinnnnDDivng/pht. 5 , 883 , 3292= = =bnIIIinn vng/pht. 3 , 31 = =tg IIIn n vng/pht. 3. Cng sut trn cc trc: Trc I:8 , 6 995 , 0 95 , 0 2 , 7 = = =o ct IN N q q kw TRNG I HC PHM VN NG KHOA K THUT CNG NGH N CHI TIT MY GVHD: Minh Tin TrangSVTH: Nguyn Minh Cng11 Trc II:6 , 6 995 , 0 98 , 0 8 , 6 = = =o br I IIN N q qkw Trc III: 4 , 6 995 , 0 98 , 0 6 , 6 = = =o br II IIIN N q q kw 4. Momen xon ca ng c:(Cng thc| |((

I5553 3) mm NnNMccc/ 2 , 4905914605 , 7 10 55 , 9 10 55 , 96 6= = =5.Momen xon trn cc trc: Trc I: mm NnNMIII/ 3 , 2223972928 , 6 10 55 , 9 10 55 , 96 6= = = Trc II: mm NnNMIIIIII/ 4 , 7122035 , 886 , 6 10 55 , 9 10 55 , 96 6= = = Trc III:mm NnNMIIIIIIIII/ 7 , 19527153 , 314 , 6 10 55 , 9 10 55 , 96 6= = =Trong : Mc l momen xon ca ng c MI l momen xon ca trc I MII l momen xon ca trc II MIII l momen xon ca trc III

Trc Thng s Trc ng cIIIII Ii = 5ibn = 3,3ibc = 2,8 n (vng/pht)146029288,531,3 N (kw)7,56,86,66,4 M (N.mm)49059,2222397,3712203,41952715,7 TRNG I HC PHM VN NG KHOA K THUT CNG NGH N CHI TIT MY GVHD: Minh Tin TrangSVTH: Nguyn Minh Cng12 PHN III: THIT K CC B TRUYN. I. THIT K B TRUYN AI: + Cng sut: N1 = Nct = 7,2kw + S vng quay trc dn: n1 = 1460 vng/pht. + S vng quay trc b dn: n2 = 292 vng/pht. + B truyn lm vic mi ngy: 2 ca. 1. Chn loi ai: Gi thuyt vn tc ca ai v > 5m/s c th dng ai thang loi A tra bng | |((

I9313 5, tit din ai tra bng| |((

I9211 5 S tit din ai K hiuA ao ao (mm) h (mm) a (mm) ho (mm) F, mm (din tch) 11 8 13 2,8 81 2. ng knh bnh ai dn d1: Tra bng| |((

I9314 5, d1 = 150 mm Kim nghim vn tc ca ai: cng thc| |((

I9318 5 2 , 91000 60120 1460 14 , 31000 601= = =d nvct m/s ) 35 30 (max = < v vm/s 3. ng knh bnh ai b dn d2:6002921460120 ) 1 (1 2= = = i d dmm Chn d2 = 600 mm Kim nghim li s vng quay li s vng quay thc n2 ca bnh ai b dn: 2926001201460 ) 1 ( '211 2= = =ddn n vng/pht. a ho h TRNG I HC PHM VN NG KHOA K THUT CNG NGH N CHI TIT MY GVHD: Minh Tin TrangSVTH: Nguyn Minh Cng13 Sai s vng quay:22'2nn n % = %) 5 %( 0 %292292 292< =

Vy n2 khng chnh lch so vi n2 v th ta khng cn chn li d1 v d2 4. Xc nh s b khong cch trc A: Ta c t s truyn i = 5 tra bng| |((

I9416 5ta c: 540 600 9 , 0 9 , 02= = = d Amm 5. Tnh chiu di L theo khong cch trc A: Theo cng thc:mmAd d d dA L 1 , 2317540 4) 120 600 (2) 120 600 ( 14 , 3540 24) (2) (22 21 2 1 2=++ + =++ + ~tChn L = 2360 mm tra bng| |((

I9212 5 Kim nghim s vng chy u trong 1 giy: 310 98 , 323602 , 9 = = =Lvuu nh hn10max = u 6. Xc nh chnh xc khong cch trc A: Xc nh A theo L tiu chun theo cng thc: )` ((

+ ++ =21 221 2 1 2) ( 22) (2) (41d dd dLd dL At t )` ((

+ ++ =22) 120 600 ( 22) 120 600 ( 14 , 323602) 120 600 ( 14 , 3236041 7 , 563 =mm 7. Tnh gc m1: Theo cng thc:0 0 0 0 1 2 01131 577 , 563120 600180 57 180 = = ~Ad doVy tha mn iu kin: 01120 > otheo| |((

I9421 5 Khong cch nh nht, cn thit mc ai: 3 , 528 2360 015 , 0 7 , 563 015 , 0min= = = L A Amm Khong cch ln nht, cn thit d mc ai: 5 , 634 2360 03 , 0 7 , 563 03 , 0max= + = + = L A Amm 8. Xc nh s dy ai cn thit Z: Chn ng sut cng ban u 20/ 2 , 1 mm N = o v theo tr s d1 tra bng| |((

I9517 5

TRNG I HC PHM VN NG KHOA K THUT CNG NGH N CHI TIT MY GVHD: Minh Tin TrangSVTH: Nguyn Minh Cng14 Cc h s:| | 61 , 10 =Po tra bng | |((

I9517 5 9 , 0 =tCtra bng| |((

I896 5 86 , 0 =oCtra bng| |((

I9518 5 1 =VCtra bng| |((

I9519 5 S ai tnh theo cng thc:| |75 , 781 1 86 , 0 9 , 0 61 , 1 2 , 92 , 7 1000 10000= = >F C C C vNZV t Pctoo Ly s ai Z = 8 9. nh cc kch thc ch yu ca bnh ai: Chiu rng bnh ai: Cng thc| |((

I9623 5

( ) ( ) 132 10 2 16 1 8 2 1 = + = + = s t Z Bmm ng knh ngoi cng ca bnh ai: cng thc| |((

I9624 5 Bnh dn:127 5 , 3 2 120 20 1 1= + = + = h d dn mm Bnh b dn: 607 5 , 3 2 600 20 2 2= + = + = h d dn mm Cc kch thc t, S v h0 xem bng| |((

I2573 10 10. Tnh lc cng ban u S0 cng thc v lc tc dng ln trc R cng thc: -Tnh lc cng So theo cng thc | |((

I9625 5 N F S 2 , 97 81 2 , 10 0= = = o-lc tc dng ln trc R cng thc| |((

I9626 5 N Z S Rd7 , 10632131sin 8 2 , 97 32sin 310= = =o Cc thng s b truyn: Chn loi ai hnh thang k hiu A TT THNG S K hiu Kt qu 1d1 d1(mm)120 2 1000 6014601 =dvtv(m/s)9,2 3 1 2) 1 ( d i d = d1 (mm)600 TRNG I HC PHM VN NG KHOA K THUT CNG NGH N CHI TIT MY GVHD: Minh Tin TrangSVTH: Nguyn Minh Cng15 4A(mm)540 5 Ad dd d A L4) () (2221 21 2+ + + =t L(mm)2360 6 )` ((

+ ++ =21 221 2 1 2) ( 22) (2) (41d dd dLd dL At tA(mm)563,7 7 0 1 2 0157 180 ~Ad do (o)131 8 | | F C C C vNZV t Pct >oo01000 Z(ai)8 9 ( ) S t Z B + = 2 1 B(mm)132 F S =0 0o So(N) 97,2 10 2sin 310o = Z S R R(N)1063,7 II. THIT KB TRUYN BNH RNG TR RNG THNG CPNHANH: 1. Chn vt liu ch to bnh rng v cch nhit luyn: -Do hp gim tc hai cp chu ti trng trung bnh nn chn vt liu lm bnh rng c rn b mt rng HB < 350. ng thi chng kh nng chng mn ca rng chn rn bnh rng nh ln hn bnh rng ln khong25 50 HB. HB1 = HB2 +(25 50 HB). -Bnh rng nh thp 45 thng ha.Theo bng ((

] [396 3I. Ta c cc thng s ca thp nh sau. Theo bng ((

] [408 3I+ ng knh phi (100 300) mm. + Gii hn bn ko: bk = 580 N/mm2. + Gii hn chy: ch = 290 N/mm2. + rn : 170 220 HB. Chn 200HB. -Bnh rng ln thp 35 thng ha. Theo bng ((

] [396 3I . Ta c cc thng s ca thp nh sau. Theo bng ((

] [408 3ITRNG I HC PHM VN NG KHOA K THUT CNG NGH N CHI TIT MY GVHD: Minh Tin TrangSVTH: Nguyn Minh Cng16 + ng knh phi 100 300 mm. + Gii hn bn ko: bk = 500 N/mm2. + Gii hn chy: ch = 260 N/mm2. + rn : 140 190 HB. Chn 170HB. (Vi c bnh rng nh v bnh rng ln chn phi l phi rn ). 2. nh ng sut cho php: -Theo cng thc ((

] [423 3I .Nt = 60unT Trong : n s vng quay trong mt pht ca bnh rng. T tng s gi lm vic. T = 263005 = 1800 u s ln n khp ca mt bnh rng khi quay mt vng.u = 1 + S chu k lm vic ca bnh nh : Nt1 = 60un1T = 6018001292 = 31,5107

+ S chu k lm vic ca bnh ln : Nt2 = 60un2T = 601800187,43 = 9,4107

-Theo bng ((

] [439 3I ta chn chu k c s No = 107 Nt1 > No Nt2 > No Do c hai bnh rng c ' ' 'N Nk k = = 1. a. Xc nh ng sut tip xc cho php : N tx N txk' ] [ ] [0 = o oTra bng ((

] [439 3I ta cHBtx N6 , 2 ] [0= o-ng sut tip xc ca bnh nh : 520 200 6 , 2 ] [1= =txoN/mm2 -ng sut tip xc ca bnh ln : 442 170 6 , 2 ] [2= =txo N/mm2 TRNG I HC PHM VN NG KHOA K THUT CNG NGH N CHI TIT MY GVHD: Minh Tin TrangSVTH: Nguyn Minh Cng17 b. Xc nh ng sut un cho php : -V phi rn, thp thng ha nn ly h s an ton n= 1,5. H s tp trung ng sut kqt = 2 theo bng ((

] [3202IP . + Gii hn mi ca bnh rng nh l: o-1 = (0,4 0,45)obk= (0,4 0,45) 580 = (232 261) N/mm2

Chn o-1 = 246 N/mm2 + Gii hn mi ca bnh rng ln l: o-2 = (0,4 0,45)obk= (0,4 0,45) 500 = (200 225) N/mm2 Chn o-2 = 212 N/mm2 -Khi rng lm vic mt mt (rng chu ng sut thay i mch ng ) ng sut un cho php c tnh theo cng thc((

] [425 3I . [o]u1 = ooK nkN' '0=( )ooK nkN ' '16 , 1 4 , 1 . -ng sut un cho php ca bnh nh: [o]u1 =qtNK nk' '0o= ( )qtNK nk ' '16 , 1 4 , 1 o=2/ ) 2 , 131 8 , 114 (2 5 , 11 246 ) 6 , 1 4 , 1 (mm N = Chn [o]u1 = 123 N/mm2. -ng sut un cho php ca bnh ln: [o]u2 = qtNK nk' '0o=( )qtNK nk ' '16 , 1 4 , 1 o= 2/ ) 1 , 113 9 , 98 (2 5 , 11 212 ) 6 , 1 4 , 1 (mm N = Chn [o]u2 = 106 N/mm2 3. Tnh khong cch trc A: -Chn s b h s ti trng: k = (1,3 1,5).Chn ksb = 1,4 -Chn chiu rng bnh rng:4 , 0 =A . p dng cng thc ((

] [459 3I . 32632265 , 88 4 , 08 , 6 4 , 13 , 3 44210 05 , 1) 1 3 , 3 (] [10 05 , 1) 1 (||.|

\|+ =||.|

\|+ >II AIbn txbn sbnN Kii A o = 223 mm TRNG I HC PHM VN NG KHOA K THUT CNG NGH N CHI TIT MY GVHD: Minh Tin TrangSVTH: Nguyn Minh Cng18 Chn Asb = 223 mm. 4. Tnh vn tc vng ca bnh rng v chn cp chnh xc ca bnh rng: p dng cng thc ((

] [4617 3I . 58 , 1) 1 3 , 3 ( 1000 60292 223 14 , 3 2) 1 ( 1000 602=+ =+ =bnIin Avt m/s Theo bng ((

] [4611 3I . Ta chn cp chnh xc l 9 5. H s ti trng k: -V bnh rng c cng HB < 350 v ti trng khng i nn c ktt=1.Vi vn tc v = 1,4m/s v c cp chnh xc l 9 . Theo bng bng ((

] [4813 3I . Ta chn k=1,45. Do k = ktt k=11,45=1,45. -H s ti trng k =1,45 khng khc nhiu so vi kSb=1,4 nn ta khng tnh li khong cch trc A =223 mm . 6. Xc nh m un, s rng v chiu rng bnh rng: -M un: m=(0,010,02)A=(0,010,02)223 = (2,23 4,46)mm Ly m=3. theo bng ((

] [341 3I . -Tnh s rng: + S rng bnh nh:6 , 34) 1 3 , 3 ( 3223 2) 1 (21=+=+=bni mAZ . ChnZ1= 35 rng. + S rng bnh ln:5 , 115 3 , 3 351 2= = =bni Z ZChnZ2=115 rng. -Chiu rng bnh rng : b = AA= 0,4223 = 89,2 mm Ly b = 89 mm. 7. Kim nghim bn un ca rng: -Theo cng thc ((

] [5133 3I , c b n Z m yN KI tIu =2610 1 , 19o . -Trong : + k = 1,45: H s ti trng. + NI: Cng sut b truynkw. + y: H s dng rng. + n: S vng quay trong mt pht ca bnh rng ang tnh. + m: M un. + Zt : S rng tng ng trn bnh. + b, uo : B rng, ng sut ti chn rng. TRNG I HC PHM VN NG KHOA K THUT CNG NGH N CHI TIT MY GVHD: Minh Tin TrangSVTH: Nguyn Minh Cng19 -Theo bng ((

] [5218 3I . + S rng tng ng ca bnh nh: Zt1 = Z1 =35 rng. H s dng rng bnh nh: y1 = 0,451 + S rng tng ng ca bnh nh: Zt2 = Z2 =115 rng. H s dng rng bnh nh: y1 = 0,517 -ng sut ti chn rng ca bnh nh l: b n Z m yN KI tIu =26110 1 , 19o226/ 01 , 5189 292 35 3 451 , 08 , 6 45 , 1 10 1 , 19mm N = = u1 < []u1 = 123 N/mm2. Tha mn -ng sut ti chn rng ca bnh ln l: . / 50 , 44517 , 0451 , 001 , 512211 2mm Nyyu u= = = o o u2 < []u2 = 106 N/mm2. Tha mn 8. Kim nghim sc bn ca chn rng khi chu qu ti t ngt: -Kim nghim ng sut tip xc cho php khi qu ti ((

] [5343 3I . | | | |Notx txqto o 5 , 2 =+ Bnh rng nh: []txqt1 = 2,5| |Notxo= 2,52,6HB = 2,52,6200 = 1300 N/mm2. + Bnh rngln: []txqt2 = 2,5| |Notxo= 2,52,6HB = 2,52,6170 = 1105 N/mm2. Theo cng thc| |((

I4513 3. II bnbntxqtn bN k ii A =3 6) 1 ( 10 05 , 1o=292 898 , 6 45 , 1 ) 1 3 , 3 (3 , 3 22310 05 , 13 6 + = 247,8 N/mm2. ng sut qu ti nh hn ng sut un cho php trn bnh nh v bnh ln: -Kim nghim ng sut cho php khi qu ti; + Bnh nh: | |ch upto o = 8 , 01= 0,8 290 = 232 (N/mm2). b Z n m yN kIIupt =26110 1 , 19o =226/ 5189 35 292 3 451 , 08 , 6 45 , 1 10 1 , 19mm N = TRNG I HC PHM VN NG KHOA K THUT CNG NGH N CHI TIT MY GVHD: Minh Tin TrangSVTH: Nguyn Minh Cng20 | |1 1 uqt uqto o No Do c hai bnh rng c ' ' 'N Nk k = = 1. a. Xc nh ng sut tip xc cho php : N tx N txk' ] [ ] [0 = o oTra bng ((

] [439 3I ta cHBtx N6 , 2 ] [0= o-ng sut tip xc ca bnh nh : 494 190 6 , 2 ] [1= =txoN/mm2 -ng sut tip xc ca bnh ln : 416 160 6 , 2 ] [2= =txo N/mm2 b. Xc nh ng sut un cho php : -V phi rn, thp thng ha nn ly h s an ton n= 1,5. H s tp trung ng sut k = 2 theo bng ((

] [3202IP. + Gii hn mi ca bnh rng nh l: o-1 = (0,4 0,45)obk= (0,4 0,45) 560 = (224 252) N/mm2

Chn o-1 = 238 N/mm2 + Gii hn mi ca bnh rng ln l: o-2 = (0,4 0,45)obk= (0,4 0,45) 480 = (192 216) N/mm2 Chn o-2 = 204 N/mm2 -Khi rng lm vic mt mt (rng chu ng sut thay i mch ng ) ng sut un cho php c tnh theo cng thc((

] [425 3I . TRNG I HC PHM VN NG KHOA K THUT CNG NGH N CHI TIT MY GVHD: Minh Tin TrangSVTH: Nguyn Minh Cng23 [o]u1 = qtNK nk' '0o=( )qtNK nk ' '16 , 1 4 , 1 o . -ng sut un cho php ca bnh nh: [o]u1=qtNK nk' '0o=( )qtNK nk ' '16 , 1 4 , 1 o=2/ ) 9 , 126 1 , 111 (2 5 , 11 238 ) 6 , 1 4 , 1 (mm N = Chn [o]u1 = 118 N/mm2 -ng sut un cho php ca bnh ln: [o]u2=qtNK nk' '0o=( )qtNK nk ' '26 , 1 4 , 1 o=2/ ) 8 , 108 2 , 95 (2 5 , 11 204 ) 6 , 1 4 , 1 (mm N = Chn [o]u2 = 102 N/mm2 3. Tnh khong cch trc A: - Chn s b h s ti trng: k = (1,3 1,5), chn ksb = 1,4. - Chn chiu rng bnh rng:4 , 0 =A . p dng cng thc ((

] [459 3I . 32632265 , 88 4 , 06 , 6 4 , 18 , 2 41610 05 , 1) 1 8 , 2 (] [10 05 , 1) 1 (||.|

\|+ =||.|

\|+ >II AIIbc txbcnN Kii A o = 226,6mm Chn Asb = 227 mm. 4. Tnh vn tc vng ca bnh rng v chn cp chnh xc ca bnh rng: p dng cng thc ((

] [4617 3I . 55 , 0) 1 8 , 2 ( 1000 605 , 88 227 14 , 3 2) 1 ( 1000 602=+ =+ =bcIIin Avt m/s Theo bng ((

] [4611 3I . Ta chn cp chnh xc l 9. 5. H s ti trng k: -V bnh rng c cng HB < 350 v ti trng khng i nn c ktt=1.Vi vn tc v = 0,55 m/s v cp chnh xc l 9.Theo bng ((

] [4813 3I . Ta chn k=1,1. Do k = ktt k=11,1=1,1. -H s ti trng k =1,1 hc nhiu so vi kSb=1,4 nn ta tnh li khong cch trc A . TRNG I HC PHM VN NG KHOA K THUT CNG NGH N CHI TIT MY GVHD: Minh Tin TrangSVTH: Nguyn Minh Cng24 5 , 2094 , 11 , 1227 3 3 = = =sbsbkkA Amm Chn A = 210 mm 6. Xc nh m un, s rng v chiu rng bnh rng: -M un: m=(0,010,02)A=(0,01 0,02)210 = (2,1 4,2)mm Ly m = 4. theo bng ((

] [341 3I . -Tnh s rng: + S rng bnh nh:6 , 27) 1 8 , 2 ( 4210 2) 1 (21=+ =+=bci mAZ . ChnZ1= 28 rng. + S rng bnh ln:4 , 78 8 , 2 281 2= = =bci Z ZChnZ1= 78 rng. -Chiu rng bnh rng : b = AA= 0,4210 = 84 mm Ly b = 84 mm. 7. Kim nghim bn un ca rng: -Theo cng thc ((

] [5133 3I , c b n Z m yN KII tIIu =2610 1 , 19o . -Trong : + k = 1,1: H s ti trng. + NII: Cng sut b truynkw. + y: H s dng rng. + n: S vng quay trong mt pht ca bnh rng ang tnh. + m: M un. + Zt : S rng tng ng trn bnh. + b, uo : B rng, ng sut ti chn rng. -Theo bng ((

] [5218 3I . + S rng tng ng ca bnh nh: Zt1 = Z1 =28 rng. H s dng rng bnh nh: y1 = 0,451 + S rng tng ng ca bnh nh: Zt2 = Z2 =78 rng. H s dng rng bnh nh: y1 = 0,511 -ng sut ti chn rng ca bnh nh l: b n Z m yN KII tIIu =26110 1 , 19o = 226/ 3 . 9284 5 , 88 28 4 451 , 06 , 6 1 , 1 10 1 , 19mm N = u1 < []u1 = 118 N/mm2. Tha mn -ng sut ti chn rng ca bnh ln l: TRNG I HC PHM VN NG KHOA K THUT CNG NGH N CHI TIT MY GVHD: Minh Tin TrangSVTH: Nguyn Minh Cng25 . / 5 , 81511 , 0451 , 03 , 922211 2mm Nyyu u= = = o o u2 < []u2 = 102 N/mm2. Tha mn 8. Kim nghim sc bn ca chn rng khi chu qu ti t ngt: -Kim nghim ng sut tip xc cho php khi qu ti ((

] [5343 3I . | | | |Notx txqto o 5 , 2 =+ Bnh rng nh: []txqt1 = 2,5| |Notxo= 2,52,6HB = 2,52,6190 = 1235 N/mm2. + Bnh rngln: []txqt2 = 2,5| |Notxo= 2,52,6HB = 2,52,6160 = 1040 N/mm2. Theo cng thc| |((

14513 3. IIII bcbctxqtn bN k ii A =3 6) 1 ( 10 05 , 1o =5 , 88 846 , 6 1 , 1 ) 1 8 , 2 (8 , 2 21010 05 , 13 6 + = 413,4 N/mm2. ng sut qu ti nh hn ng sut cho php trn bnh nh v bnh ln: -Kim nghim ng sut cho php khi qu ti: + Bnh nh: | |ch upto o = 8 , 01= 0,8 280 = 224 (N/mm2). b Z n m yN kt IIIIupt =26110 1 , 19o =226/ 3 , 9284 28 5 , 88 4 451 , 06 , 6 1 , 1 10 1 , 19mm N = | |1 1 uqt uqto o D1,28,85 = 10,62 mm, ta ly D = 12 mm) + Chiu cao ca Bulng ghp np v chiu dy np :16 mm + Khe h gia mt bn bnh ai v u Bulng : 15 mm + Chiu rng bnh ai: 148 mm + Chiu rng bnh rng cp nhanh :89 mm + Chiu rng bnh rng cp chm : 84 mm -Tng hp cc kch thc trn ta c:+mm a 5 , 7728412 10227= + + + =+mm b 92 10284280= + + =+ mm c 8028912 10227= + + + =+mm l 5 , 128214810 16 15227= + + + + =a. S phn tch lc trn trc I: -Cc thng s ch yu + l = 128,5 mm, a + b = 169,5 mm. + c = 80 mm -Cc lc tc dng ln trc I bao gm : + Lc tc dng ln ai: Pd= 1063,7 N + Lc hng tm : Pr1= 1541,6 N + Lc vng : P1= 4236,1 N -Tnh phn lc ti gi : Chiu ln mt phng yOz. + Tnh phn lc ti gi A: RBy

0 ) ( = + + + =c b a R c P l P mBy r dy Ay c b ac P l PRr dyBy+ + + = ) ( ) ( N 104280 5 , 169). 80 6 , 1541 ( ) 5 , 128 7 , 1063 (=+ + =TRNG I HC PHM VN NG KHOA K THUT CNG NGH N CHI TIT MY GVHD: Minh Tin TrangSVTH: Nguyn Minh Cng30 RBy =1042 N > , Lc RBy c chiu nh hnh v. 75,5169,5 Pd dAB n ARAy A Pr1 rP1 1RBx BRBy Bn 128,5 176619 136685,5 230231 222397,3 Muy uMux uMu xy z x oRAx m m o TRNG I HC PHM VN NG KHOA K THUT CNG NGH N CHI TIT MY GVHD: Minh Tin TrangSVTH: Nguyn Minh Cng31 +Tnh phn lc ti gi A : RAy 1 r By d AyP R P R + = = 1063,7 1042 +1740,9 = 1762,6 N Chiu ln mt phng xoz. + Tnh phn lc ti gi B: + + = ) (1c b a R c P mBx Ax Nc b ac PRBx3 , 135880 5 , 16980 1 , 42361=+=+ + = + Tnh phn lc ti gi A: N R P RBx Ax8 , 2877 3 , 1358 1 , 42361= = =-Tnh Momen un tit din nguy him: + tit din n-n ta c Mu n-n= Pdl = 1063,7128,5 = 136685,5 Nmm + tit din m-m ta c: 2 2ux uy m m uM M M + =

Trong :+ Muy= RBy(a+b)= 1042 169,5 = 176619 Nmm + Mux= RBx(a+b) =1358,3 169,5 = 230231 Nmm mm N Mm m u = + =4 , 290173 230231 1766192 2

-ng knh trc ti tit din nguy him: p dng cng thc] 1 [1173 7 ta c:| |31 , 0 o >tdMdmm Trong :+ Mtd Momen tng ng. p dng cng thc] 1 [1174 7 2 275 , 0x u tdM M M + =+ Tra bng ((

I ] [1192 7 ta chn [] = 63 N/mm2 ng knh trc tit din n-n Ta c: Mu n-n = 136685,5 Nmm Mx =3 , 2223972928 , 610 55 , 9 10 55 , 96 6= = IInNNmm mm N Mtd = + = 4 , 236174 ) 3 , 222397 75 , 0 ( 5 , 1366852 2 Vymm dn n5 , 3363 1 , 04 , 2361743 =>

ng knh trc tit din m-m Ta c : Mu m-m= 290173,4 Nmm Mx = 222397,3 Nmm mm N Mtd = + = 8 , 348275 ) 3 , 222397 75 , 0 ( 4 , 2901732 2 TRNG I HC PHM VN NG KHOA K THUT CNG NGH N CHI TIT MY GVHD: Minh Tin TrangSVTH: Nguyn Minh Cng32 Vymm dm m1 , 3863 1 , 08 , 3482753 => Dng knh tit din n-n ly bng 34 mm (ngng trc lp ) v ng knh tit din m-m ly bng 38 mm.ln hn gi tr c tnh v trc c rnh then. b. S phn tch lc trn trc II: 75,5 9277,5 R Mx P r3 P 3 r2 P P 2 R Mx R My N M e e i i 546312 784749,5 712203,4 uy M M ux M x 462792 209025,3 R My y z x TRNG I HC PHM VN NG KHOA K THUT CNG NGH N CHI TIT MY GVHD: Minh Tin TrangSVTH: Nguyn Minh Cng33 -Cc thng s ch yu + a = 77,5 mm + b = 92 mm + c = 80 mm -Cc lc tc dng ln trc II bao gm : + Lc tc dng ln bnh rng nh -Lc vng : P2 = 12718 N-Lc hng tm:Pr2 = 4629,4 N + Lc tc dng ln bnh rng ln : -Lc vng: P3= 4236,1 N -Lc hng tm :Pr3 = 1541,6 N -Tnh phn lc ti gi : Chiu ln mt phng yOz. + Tnh phn lc ti gi N: RNy

0 ) ( ) (2 3= + + + + =c b a R b c P c P mNy r r My 1 , 269780 92 5 , 7780 6 , 1541 ) 80 92 ( 4 , 4629 ) (3 2=+ + + =+ + + = c b ac P c b PRr rNy N RNy =2697,1 N > 0, Lc RNy c chiu nh hnh v. +Tnh phn lc ti gi M : RMy N R P P RNy r r My9 , 5784 1 , 2697 6 , 1541 4 , 46293 2= + = + = Chiu ln mt phng xOz. + Tnh phn lc ti gi N: 0 ) ( ) (2 3= + + + + =c b a R c b P c P mNx Mx Nc b ac b P c PRNx8 , 1012580 92 5 , 77) 80 92 ( 12718 80 1 , 4236 ) (2 3=+ ++ + =+ ++ + = + Tnh phn lc ti gi M N R P P RNx Mx9 , 6828 8 , 10125 12718 7 , 42362 3= + = + =-Tnh Momen un tit din nguy him: + tit din e-e ta c 2 2ux uy e e uM M M + = +Mux = RMxc = 6828,9 80 = 546312 Nmm +Muy = RMyc = 5784,9 80 = 462792 Nmm mm N Me e u = + = 715984 462792 5463122 2 + tit din i-i ta c: 2 2ux uy i i uM M M + =

+ Muy= RNya= 2697,1 77,5 = 209025,3 Nmm TRNG I HC PHM VN NG KHOA K THUT CNG NGH N CHI TIT MY GVHD: Minh Tin TrangSVTH: Nguyn Minh Cng34 + Mux= RNxa =10125,8 77,5 = 784749,5 Nmm mm N Mi i u = + =4 , 812110 5 , 784749 3 , 2090252 2

-ng knh trc ti tit din nguy him: p dng cng thc ((

] [1173 7Ita c:| |31 , 0 o >tdMdmm Trong :+ Mtd Momen tng ng. p dng cng thc] 1 [1174 7 2 275 , 0x u tdM M M + =+ Tra bng ((

] [1192 7Ita chn [] = 50 N/mm2 ng knh trc tit din e-e Ta c: Mu e-e = 715984 Nmm Mx =4 , 7122035 , 886 , 610 55 , 9 10 55 , 96 6= = IIIInNNmm mm N Mtd = + = 7 , 945017 ) 4 , 712203 75 , 0 ( 7159842 2 Vymm de e4 , 5750 1 , 07 , 9450173 =>

ng knh trc tit din i-i Ta c : Mu i-i= 812110,4 Nmm Mx = 712203,4 Nmm mm N Mtd = + = 7 , 1019778 ) 4 , 712203 75 , 0 ( 4 , 8121102 2 Vymm di i8 , 5850 1 , 07 , 10197783 => Dng knh tit din e-e ly bng 57 mm (ngng trc lp ) v ng knh tit din i-i ly bng 60 mm.ln hn gi tr c tnh v trc c rnh then. c. S phn tch lc trn trc III: -Cc thng s ch yu + a = 77,5 mm + b +c= 92 + 80 = 172 mm -Cc lc tc dng ln trc III bao gm : - Lc tc dng ln bnh rng+ Lc vng : P4 = 12718 N + Lc hng tm:Pr4 = 4629,4 N TRNG I HC PHM VN NG KHOA K THUT CNG NGH N CHI TIT MY GVHD: Minh Tin TrangSVTH: Nguyn Minh Cng35 -Tnh phn lc ti gi : Chiu ln mt phng yOz. + Tnh phn lc ti gi F: RFy

= + + + = 0 ) ( ) (4c b a R c b P mFy r Ey Nc b ac b PRrFy8 , 3179170 5 , 77170 4 , 4629 ) (4=+=+ ++ = RFy = 3179,8 N > 0, Lc RNy c chiu nh hnh v. +Tnh phn lc ti gi E : REy N R P RFy r Ey6 , 1449 8 , 3179 4 , 46294= = = Chiu ln mt phng xOz. + Tnh phn lc ti gi F = + + + = 0 ) ( ) (4c b a R c b P mFx Ex P x ux M uy M 246432 Fy R Fx R r4 P 4 h h F E EX R Ex R 167,5 77,5 677008 M 1952715,7 y z x TRNG I HC PHM VN NG KHOA K THUT CNG NGH N CHI TIT MY GVHD: Minh Tin TrangSVTH: Nguyn Minh Cng36 Nc b ac b PRFx6 , 8735170 5 , 77170 12718 ) (4=+=+ ++ = +Tnh phn lc ti gi EN R P RFx Ex4 , 3982 6 , 8735 127184= = =-Tnh Momen un tit din nguy him: tit din h-h ta c 2 2ux uy h h uM M M + = +Mux = REx(b+c) = 3982,4 170 = 677008 Nmm +Muy = REy(a+b) = 1449,6 170 = 246432 Nmm mm N Mh h u = + = 1 , 720464 246432 6770082 2 -ng knh trc ti tit din nguy him: p dng cng thc ((

] [1173 7I ta c:| |31 , 0 o >tdMdmm Trong :+ Mtd Momen tng ng. p dng cng thc ((

] [1174 7I 2 275 , 0x u tdM M M + =+ Tra bng ((

] [1192 7I ta chn [] = 48 N/mm2 Ta cmm N Mh uh =1 , 720464Mx =7 , 19527153 , 314 , 610 55 , 9 10 55 , 96 6= = IIIInN Nmm mm N Mtd = + = 4 , 1838176 ) 7 , 1952715 75 , 0 ( 1 , 7204642 2 Vymm dh h01 , 7348 1 , 04 , 18681763 =>

Dng knh tit din h-h ly bng 73 mm ln hn gi tr c tnh v trc crnh then. 3.Tnh chnh xc trc: Kim tra h s an ton ti cc tit din nguy him . H s an ton tnh theo cng thc ((

] [1205 7I t ot on nn nn+= Trong : n h s an ton ch xt ring ng sut phpn h s an ton ch xt ring ng sut tip n h s an ton. [n] h s an ton cho php thng ly[n] = 1,5 2,5.V trc quay nn ng sut php (un) bin i theo chu k i xng. TRNG I HC PHM VN NG KHOA K THUT CNG NGH N CHI TIT MY GVHD: Minh Tin TrangSVTH: Nguyn Minh Cng37 0 ;min max= = = =mUaWMo o o om: l gi tr trung bnh ng sut php. Theo cng thc ((

I ] [1206 7 ta c: m o aokno o| cooo + =1 B truyn lm vic mt chiu nn ng sut tip (xon) bin i theo chu k mch ng oXm aWM= = =2 2maxtt tTheo cng thc ((

I ] [1207 7ta c m aknt t| cttttt + =1 Trong :-1: l gii hn mi un v xon vi mt chu k i xng. a : Bin ng sut php v tip sinh ra trong tit din ca trc. W: M men cn un ca tit din. Wo: M men cn xon ca tit din. k : H s tp trung ng sut thc t khi un v xon tra bng ((

((

] [12913 7] [1256 7I v I . : H s tng bn b mt trc. : H s xt n nh hng ca tr s ng sut trung bnh n sc bn mi m: L tr s trung bnh ng sut tip. MU, Mx: l m men un v m men xon. a. Trc I: Xt tit din (n n) ng knh trc d = 34 mm. Tra bng ((

Ib] [1223 7 ta c: W = 3330 mm3; Wo = 7190 mm3; b h = 10 8 mm2 b: Chiu rng then (mm) h: Chiu cao then (mm) C th ly gn ng : ) 300 240 ( 600 ) 5 , 0 4 , 0 ( ) 5 , 0 4 , 0 (1 = = ~ bo oChn 21/ 270 mm N =o TRNG I HC PHM VN NG KHOA K THUT CNG NGH N CHI TIT MY GVHD: Minh Tin TrangSVTH: Nguyn Minh Cng38 ) 180 120 ( 600 ) 3 , 0 2 , 0 ( ) 3 , 0 2 , 0 (1 = = ~ bo tChn 21/ 150 mm N =tMU = 136685,5 Nmm; MX = 222397,3 Nmm mm NWMUa/ 4133305 , 136685= = = omm NWMoXa/ 4 , 157190 23 , 2223972=== tChn h s v theo vt liu, i vi thp cacbon trung bnh = 0,1 v = 0,05, h s tng bn = 1. Theo bng ((

I ] [1234 7ly, 86 , 0 mmo = cmm 75 , 0 =tcTheo bng ((

I ] [1278 7, tp trung ng sut do rng then k = 1,63; k = 1,5. Xt t s : 9 , 186 , 063 , 1= =okco95 , 177 , 05 , 1= =ttck V do lp ghp trc vi then c di nn ly p sut b mt lp ghp lP = 30 N/mm2 . Tra bng ((

I ] [12810 7ta c6 , 2 =okco 96 , 1 ) 1 6 , 2 ( 6 , 0 1 1 6 , 0 1 = + =||.|

\| + =ok kc cott 5 , 241 6 , 2270==on9 , 44 , 15 05 , 0 4 , 15 96 , 1150= + =tn5 , 49 , 4 5 , 29 , 4 5 , 2=+= n> [n] = (1,52,5) Vy tit din (n n) m bo an ton cho php. Xt tit din (m m) ng knh trc d = 38 mm. Tra bng ((

Ib] [1223 7 ta c: W = 4660 mm3; Wo = 10040 mm3; b h = 12 8 mm2 b: Chiu rng then (mm) h: Chiu cao then (mm) C th ly gn ng : ) 300 240 ( 600 ) 5 , 0 4 , 0 ( ) 5 , 0 4 , 0 (1 = = ~ bo oChn 21/ 270 mm N =o TRNG I HC PHM VN NG KHOA K THUT CNG NGH N CHI TIT MY GVHD: Minh Tin TrangSVTH: Nguyn Minh Cng39 ) 180 120 ( 600 ) 3 , 0 2 , 0 ( ) 3 , 0 2 , 0 (1 = = ~ bo tChn 21/ 150 mm N =tMU = 290173,4Nmm; MX = 222397,3 Nmm mm NWMUa/ 2 , 6246604 , 290173= = = omm NWMoXa/ 1 , 1110040 23 , 2223972=== tChn h s v theo vt liu, i vi thp cacbon trung bnh = 0,1 v = 0,05, h s tng bn = 1. Theo bng ((

I ] [1234 7ly, 85 , 0 mmo = cmm 73 , 0 =tcTheo bng ((

I ] [1278 7, tp trung ng sut do rng then k = 1,63; k = 1,5. Xt t s : 9 , 185 , 063 , 1= =okco273 , 05 , 1= =ttck V do lp ghp trc vi then c di nn ly p sut b mt lp ghp lP = 30 N/mm2 . Tra bng ((

I ] [12810 7ta c7 , 2 =okco 02 , 2 ) 1 7 , 2 ( 6 , 0 1 1 6 , 0 1 = + =||.|

\| + =ok kc cott 61 , 12 , 62 7 , 2270==on5 , 61 , 11 05 , 0 1 , 11 02 , 2150= + =tn6 , 35 , 6 61 , 15 , 6 61 , 1=+= n> [n] = (1,52,5) Vy tit din (m m) m bo an ton cho php. b. Trc II: Xt tit din (e e). ng knh trc d = 57 mm. Tra bng ((

Ib] [1223 7 ta c: W = 16810 mm3; Wo = 36000 mm3; b h = 18 11 mm2 b: Chiu rng then (mm) h: Chiu cao then (mm) C th ly gn ng : ) 300 240 ( 600 ) 5 , 0 4 , 0 ( ) 5 , 0 4 , 0 (1 = = ~ bo oChn 21/ 270 mm N =oTRNG I HC PHM VN NG KHOA K THUT CNG NGH N CHI TIT MY GVHD: Minh Tin TrangSVTH: Nguyn Minh Cng40 ) 180 120 ( 600 ) 3 , 0 2 , 0 ( ) 3 , 0 2 , 0 (1 = = ~ bo tChn 21/ 150 mm N =tMU = 715984 Nmm; MX = 712203,4 Nmm mm NWMUa/ 5 , 4216810715984= = = omm NWMoXa/ 9 , 936000 24 , 7122032=== tChn h s v theo vt liu, i vi thp cac bon trung bnh = 0,1 v = 0,05, h s tng bn = 1. Theo bng ((

I ] [1234 7ly, 78 , 0 mmo = cmm 67 , 0 =tcTheo bng ((

I ] [1278 7, tp trung ng sut do rnh then k = 1,63; k = 1,5. Xt t s : 1 , 278 , 063 , 1= =okco24 , 267 , 05 , 1= =ttck V do lp ghp trc vi then c di nn ly p sut b mt lp ghp lP = 30 N/mm2 . Tra bng ((

I ] [12810 7ta c3 , 3 =okco 38 , 2 ) 1 3 , 3 ( 6 , 0 1 1 6 , 0 1 = + =||.|

\| + =ok kc cott 6 , 25 , 42 38 , 2270==on2 , 69 , 9 05 , 0 9 , 9 38 , 2150= + =tn4 , 52 , 6 6 , 22 , 6 6 , 2=+= n > [n] = (1,52,5) Vy tit din (e e) m bo an tonXt tit din (i i). ng knh trc d = 60 mm. Tra bng ((

Ib] [1223 7 ta c: W = 18760 mm3; Wo = 4000 mm3; b h = 18 11 mm2 b: Chiu rng then (mm) h: Chiu cao then (mm) C th ly gn ng : ) 300 240 ( 600 ) 5 , 0 4 , 0 ( ) 5 , 0 4 , 0 (1 = = ~ bo oChn 21/ 270 mm N =oTRNG I HC PHM VN NG KHOA K THUT CNG NGH N CHI TIT MY GVHD: Minh Tin TrangSVTH: Nguyn Minh Cng41 ) 180 120 ( 600 ) 3 , 0 2 , 0 ( ) 3 , 0 2 , 0 (1 = = ~ bo tChn 21/ 150 mm N =tMU = 812110,4 Nmm; MX = 712203,4 Nmm mm NWMUa/ 3 , 43187604 , 812110= = = omm NWMoXa/ 9 , 840000 24 , 7122032=== tChn h s v theo vt liu, i vi thp cacbon trung bnh = 0,1 v = 0,05, h s tng bn = 1. Theo bng ((

I ] [1234 7ly, 76 , 0 mmo = cmm 65 , 0 =tcTheo bng ((

I ] [1278 7, tp trung ng sut do rng then k = 1,63; k = 1,5. Xt t s : 2 , 276 , 063 , 1= =okco3 , 265 , 05 , 1= =ttck V do lp ghp trc vi then c di nn ly p sut b mt lp ghp lP = 30 N/mm2 . Tra bng ((

I ] [12810 7ta c3 , 3 =okco 38 , 2 ) 1 3 , 3 ( 6 , 0 1 1 6 , 0 1 = + =||.|

\| + =ok kc cott 6 , 23 , 43 38 , 2270==on7 , 79 , 8 05 , 0 9 , 8 38 , 2150= + =tn2 , 67 , 7 6 , 27 , 7 6 , 2=+= n > [n] = (1,52,5) Vy tit din (i i) m bo an tonc. Trc III: Xt tit din (h h). ng knh trc d = 73 mm. Tra bng ((

Ib] [1223 7 ta c: W = 33000 mm3; Wo = 69700 mm3; b h = 20 12 mm2 b: Chiu rng then (mm) h: Chiu cao then (mm) C th ly gn ng : ) 300 240 ( 600 ) 5 , 0 4 , 0 ( ) 5 , 0 4 , 0 (1 = = ~ bo oTRNG I HC PHM VN NG KHOA K THUT CNG NGH N CHI TIT MY GVHD: Minh Tin TrangSVTH: Nguyn Minh Cng42 Chn 21/ 270 mm N =o ) 180 120 ( 600 ) 3 , 0 2 , 0 ( ) 3 , 0 2 , 0 (1 = = ~ bo tChn 21/ 150 mm N =tMU = 720464,1 Nmm; MX = 1952715,7 Nmm mm NWMUa/ 8 , 21330001 , 720464= = = omm NWMoXa/ 1 , 1469700 27 , 19527152=== tChn h s v theo vt liu, i vi thp cacbon trung bnh = 0,1 v = 0,05, h s tng bn = 1. Theo bng ((

I ] [1234 7ly, 74 , 0 mmo = cmm 62 , 0 =tcTheo bng ((

I ] [1278 7, tp trung ng sut do rng then k = 1,63; k = 1,5. Xt t s : 2 , 274 , 063 , 1= =okco4 , 262 , 05 , 1= =ttck V do lp ghp trc vi then c di nn ly p sut b mt lp ghp lP = 30 N/mm2 . Tra bng ((

I ] [12810 7ta c3 , 3 =okco 38 , 2 ) 1 3 , 3 ( 6 , 0 1 1 6 , 0 1 = + =||.|

\| + =ok kc cott 2 , 58 , 21 38 , 2270==on3 , 61 , 14 05 , 0 1 , 14 38 , 2150= + =tn6 , 93 , 6 2 , 53 , 6 2 , 5=+= n> [n] = (1,52,5) Vy tit din (h h) m bo an ton TRNG I HC PHM VN NG KHOA K THUT CNG NGH N CHI TIT MY GVHD: Minh Tin TrangSVTH: Nguyn Minh Cng43 PHN V: TNH THEN. c nh bnh rng theo phng php tip tuyn hay truyn m men v chuyn ng t trc n bnh rng hoc ngc li ta dng then. 1. Tnh Then Lp Trn Trc I: ng knh trc I lp then l dn-n = 34 mm v dm-m = 38 mm. Xt ti tit din (n n) ng knh lp then dn-n = 34 mm Theo bng ((

I ] [14323 7chn cc thng s then: b = 10; h = 8; t = 4,5; t1 =3,6; k = 4,2 Chiu di then: l = 0,8lm Trong :lm chiu di may: lm = (1,2 1,5)d=(1,2 1,5)34=(40,851)mm Chn lm = 46 mm. -Kimnghimbndptrnmtcnhlmviccathentheocngthc ((

I ] [13911 7 2/ , ] [2mm Nl k dMdXdo o s =Ta c MX = 222397,3 Nmm; Chiu di then: l = 0,8lm = 0,846 = 36,8 mm. Theo TCVN 150 64 (bng ((

I ] [14323 7) chn l = 40 mm. Tra bng ((

I ] [14220 7vi ng sut mi ghp c nh, ti trng tnh, vt liu CT6 ta c []d = 150 N/mm2

9 , 7740 2 , 4 343 , 222397 2= =doN/mm2 []d -Kim nghim bn ct theo cng thc ((

I ] [13912 7 ] [2cXcl b dMt t s =Theo bng ((

I ] [14221 7c [c] = 120 N/mm2. 7 , 3240 10 343 , 222397 2= =ctN/mm2 []c Xt ti tit din (m m) ng knh lp then dn-n = 38 mm Theo bng ((

I ] [14323 7chn cc thng s then: b = 12; h = 8; t = 4,5; t1 =3,6; k = 4,4 Chiu di then: l = 0,8lm Trong :lm chiu di may: lm = (1,2 1,5)d=(1,2 1,5)38=(45,657)mm Chn lm = 50 mm. TRNG I HC PHM VN NG KHOA K THUT CNG NGH N CHI TIT MY GVHD: Minh Tin TrangSVTH: Nguyn Minh Cng44 -Kimnghimbndptrnmtcnhlmviccathentheocngthc ((

I ] [13911 7 2/ , ] [2mm Nl k dMdXdo o s =Ta c MX = 222397,3 Nmm; Chiu di then: l = 0,8lm = 0,850 = 40 mm. Theo TCVN 150 64 (bng ((

I ] [14323 7) chn l = 40 mm. Tra bng ((

I ] [14220 7vi ng sut mi ghp c nh, ti trng tnh, vt liu CT6 ta c []d = 150 N/mm2

5 , 6640 4 , 4 383 , 222397 2= =doN/mm2 []d -Kim nghim bn ct theo cng thc ((

I ] [13912 7 ] [2cXcl b dMt t s =Theo bng ((

I ] [14221 7c [c] = 120 N/mm2. 4 , 2440 12 383 , 222397 2= =ctN/mm2 []c Nh vy then trn trc I tha mn iu kin bn dp v iu kin ct. 2. Tnh Then Lp Trn Trc II: ng knh trc II lp then l de-e = 57 mm v di-i = 60 mm. Xt ti tit din (e e) ng knh lp then de-e = 57 mm Theo bng ((

I ] [14323 7chn cc thng s then: b = 18; h = 11; t = 5,5; t1 =5,6; k = 6,8 Chiu di then: l = 0,8lm Trong :lm chiu di may:lm = (1,2 1,5)d=(1,2 1,5)57=(68,4 85,5)mm Chn lm = 77 mm. -Kimnghimbndptrnmtcnhlmviccathentheocngthc ((

I ] [13911 7 2/ , ] [2mm Nl k dMdXdo o s =Ta c MX = 712203,4 Nmm; Chiu di then: l = 0,8lm = 0,877 = 61,6 mm Theo TCVN 150 64 (bng ((

I ] [14323 7) chn l = 60 mm. TRNG I HC PHM VN NG KHOA K THUT CNG NGH N CHI TIT MY GVHD: Minh Tin TrangSVTH: Nguyn Minh Cng45 Tra bng ((

I ] [14220 7vi ng sut mi ghp c nh, ti trng tnh, vt liu CT6 ta c []d = 150 N/mm2

2 , 6160 8 , 6 574 , 712203 2= =doN/mm2 []d -Kim nghim bn ct theo cng thc ((

I ] [13912 7 ] [2cXcl b dMt t s =Theo bng ((

I ] [14221 7c [c] = 120 N/mm2. 1 , 2360 18 574 , 712203 2= =ctN/mm2 []c Xt ti tit din (i i) ng knh lp then d i - i = 60 mm Theo bng ((

I ] [14323 7chn cc thng s then: b = 18; h = 11; t = 5,5; t1 =5,6; k = 6,8 Chiu di then: l = 0,8lm Trong :lm chiu di may:lm = (1,2 1,5)d=(1,2 1,5)60=(72 90)mm Chn lm = 81 mm. -Kimnghimbndptrnmtcnhlmviccathentheocngthc ((

I ] [13911 7 2/ , ] [2mm Nl k dMdXdo o s = y MX = 712203,4 Nmm; Chiu di then: l = 0,8lm = 0,881 = 64,8 mm Theo TCVN 150 64 (bng ((

I ] [14323 7) chn l = 60 mm. Tra bng ((

I ] [14220 7vi ng sut mi ghp c nh, ti trng tnh, vt liu CT6 ta c []d = 150 N/mm2

9 , 4970 8 , 6 604 , 712203 2= =doN/mm2 []d -Kim nghim bn ct theo cng thc ((

I ] [13912 7 ] [2cXcl b dMt t s =Theo bng ((

I ] [14221 7c [c] = 120 N/mm2. TRNG I HC PHM VN NG KHOA K THUT CNG NGH N CHI TIT MY GVHD: Minh Tin TrangSVTH: Nguyn Minh Cng46 8 , 1870 18 604 , 712203 2= =ctN/mm2 []c Nh vy then trn trc II tha mn iu kin bn dp v iu kin ct. 3. Tnh Then Lp Trn Trc III: ng knh trc I lp then l d = 73 mm Theo bng ((

I ] [14323 7chn cc thng s then: b = 20; h = 12; t = 6; t1 =6,1; k = 7,4 Chiu di then: l = 0,8lm Trong :lm chiu di may: lm = (1,2 1,5)73=(1,2 1,5)73= (87,6 109,5)mm Chn lm = 99 mm. -Kimnghimbndptrnmtcnhlmviccathentheocngthc ((

I ] [13911 7 2/ , ] [2mm Nl k dMdXdo o s =Ta c MX = 1952715,7 Nmm; Chiu di then: l = 0,8lm = 0,899 = 79,2 mm. Theo TCVN 150 64 (bng ((

I ] [14323 7) chn l = 80 mm. Tra bng ((

I ] [14220 7vi ng sut mi ghp c nh, ti trng tnh, vt liu CT6 ta c []d = 150 N/mm2

4 , 9080 4 , 7 737 , 1952715 2= =doN/mm2 []d -Kim nghim bn ct theo cng thc ((

I ] [13912 7 ] [2cXcl b dMt t s =Theo bng ((

I ] [14221 7c [c] = 120 N/mm2. 4 , 3380 20 737 , 1952715 2= =ctN/mm2 []c Nh vy then trn trc III tha mn iu kin bn dp v iu kin ct. TRNG I HC PHM VN NG KHOA K THUT CNG NGH N CHI TIT MY GVHD: Minh Tin TrangSVTH: Nguyn Minh Cng47 LI KT Saumtthigiamtmti,nghinculachnvdishngdntntnh ca thy c gio. n nay ti ca em c hon thnh. Trongsutqutrnhtnhtonlmnmnhcemrtramtskinh nghim v nhng kin thc s gip em sau ny. N l nn mng cho vic vn dng cho cng vic sau ny, hn th na n gip em hiu bit thm v mn ch to my. n mn hc ca em hon thnh trc ht em chn thnh cm n s quan tm v gip cc thy khoa k thut cng ngh, cc bn b v c bit l s gip nhit tnh cathy Minh Tin. Trongqutrnhthchintiny,dohiubitcnhnch,ngthikinh nghim cn cha vng nn n ca em nhng thiu st. Mt d c gng tm ti hc hi thy c v bn b cng trao i k nng. Cui cng, mt ln na em xin chn thnh cm n cc thy c gio cng bn b gip em hon thnh ti ny. Emknhmongnhnckinnggpcaccthy,cticaem c hon thin hn na. Qung Ngi, ngy 10 thng 8 nm 2009 Nguyn Minh Cng TRNG I HC PHM VN NG KHOA K THUT CNG NGH N CHI TIT MY GVHD: Minh Tin TrangSVTH: Nguyn Minh Cng48 TI LIU THAM KHO I.THIT K CHI TIT MY , Nguyn Trng Hip Nguyn Vn Lm, NXBGD. II. S TAY DUNG SAI LP GHP , Ninh c Tn, NXBGD,2005.