18
Phased (Scanning) Arrays They direct the main beam of an array by controlling the phase excitation between elements: o o kd kd kd o θ β β θ β θ ψ θ θ cos 0 cos 0 cos = = + = + = = (16)

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  • Phased (Scanning) Arrays

    They direct the main beam of an array by controlling the phase excitation between elements:

    oo kdkd

    kdo

    cos0cos

    0cos

    ==+

    =+= = (16)

  • [Array factor pattern of a 10-element uniform amplitude scanning array. = -kd cos 0, 0 = 600, d = /4]

  • 2 - dimensional pattern

  • Hansen- Woodyard End fire Array

    Hansen and Woodyard found that a larger directivity can be achieved for if the phase :oo or 1800 ==

    oforkd

    Nkd

    Nkd

    0

    94.2

    ==

    +

    +

    is used instead of:

    (17)

  • and

    oforkd

    Nkd

    Nkd

    180ofinstead

    94.2

    ==

    ++

    ++

    (18)

    These conditions yield larger directivity than in the ordinary end fire antennas, but not the maximumpossible.

  • For Maximum Radiation along =0

    =+

    =+

    =

    =

    o

    o

    kd

    andN

    kd

    180

    0

    cos

    cos

    (20) Must be satisfied

    (19)

    For Maximum Radiation along =180

    =+

    =+

    =

    =

    o

    o

    kd

    andN

    kd

    0

    180

    cos

    cos

    (22) Must be satisfied

    (21)

  • Directivity of Hanson Woodyard in Figure is 19

    Directivity of ordinary end Fire is 11

    3-dB Beamwidth of Hanson Woodyard is 37o

    3-dB Beamwidth of ordinary End Fire is 74o

    What happens if we do not satisfy both conditions?

    If both conditions are not satisfied you may end up with some side lobes that are larger than the main beam.

    [See Derivation in the Book]

  • N-element Linear Array Directivity

    Broadside arrayCan one calculate the directivity of a uniform array as a function of N & d ?

  • How do we calculate Do in this case?

    For the Broadside array ( ) and for small spacing we have:0=

    2

    2)(

    cos2

    cos2

    sin)(

    cos2

    cos2

    sin)(

    ==

    =

    kdN

    kdN

    AFU

    kdN

    kdN

    AF(23)

    (24)

  • ddkdN

    kdN

    U

    PU

    o

    rado

    sincos

    2

    cos2

    sin

    41

    41&

    2

    2

    0 0

    =

    =

    (25)

    Since the integration w.r.t. will yield 2

    dkdN

    kdN

    Uo sincos

    2

    cos2

    sin

    21

    2

    0

    = (26)

  • dkdNdzkdNz sin2

    cos2

    ==Let

    Eqn (26) becomes:

    zdzz

    NkdU

    Nkd

    Nkdo

    2

    2

    2

    sin1

    = (27)

    zdzz

    NkdUor

    Nkd

    Nkdo

    2

    2

    2

    sin1

    = (28)

  • For very large arrays

    Eqn (28) becomes:

    Hence:

    NkdUor

    zdzz

    NkdU

    o

    o

    =

    2sin1

    (29)

    Nkd

    NddND

    Nkd

    NkdUUD

    o

    oo

    22

    1max

    ==

    ===

    (30)

  • arraysbroadsidefordNDo

    = 2Endfire array

    Similarly, for ordinary end fire arrays the directivity is:

    dNDo 4 (31)

    For the Hansen Woodyard end fire:

    dNDo 4805.1 (32)

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