EVALUACION 1

Resuelve las siguientes sumas de fracciones algebraicas con denominador monomio.

Escribir el desarrollo paso a paso.

1. = 3(x-2) + 2(3x+2) /12 = 3x-6+6x+4/12= 9x-2/12

2. = 4b(a-2b) +3a (b-a) /60ab = 4ab-8b²+3ab-3a²/60ab = 7ab-8b²-3a²/60ab

3. = 4(a-1)+2(2a)+1(3a+4)/12 = 4a-4+4a +3a +4 /12 = 11a/12

4. = 2 +1 / 30a²b = 6b(2) +10a(1)/30a²b = 12b-10a/30 a3b

5. = n+3+2/m²n = n(m) + m(3) + mn(2) / m²n = n²+3m+2mn/ m²n

6. = 5ab(a+3b) +3(a²b -4ab²) /15a²b² = 5a²b +15b+3a²b-12ab²/15a²b² =

8a²+15b-12ab²/15a²b²

7. = 6x²(3) +15x(x+2)+5(x²+2) / 30x²= 18x²+15x²+30x+5x²+10x²/30x²=

48x²+30x/30x²

8. = 3x(1-x) +6(x+2)+2a(1)/ 6x² = 3x-3x+6x+12x+2a/6x² = 18x+2a/6x²

9. = 10x(2a-3)+3a(3x+2)+6(x-a)/30ax = 20ax-30x+9ax+6x+6a+6x-6a/30ax = 29ax-24x/30ax

10. = 15x(x-2) +9(x²-2) +5(2-3x) /45x² = 15x²-30x+9x²-18+10x-5x4 /45x²= 24x²-20x-18-5x4/ 45x²

11. = m(a+3b)+b(2a -3m) +bm(3) /abm = am+3bm+2ab-3bm+3bm/abm

= am+2ab+3bm/abm

12. = ab²(1) +a(b²-a²) +b(ab+b²)/a²b3 = ab²+ab²-a3+ab²+b3/a²b3

= 3ab²-a3+b3/a²b3

13. = a(m-n) +m(n-a) +n(2a-m) /amn = am-an+mn-am+2an-mn/amn

= an/amn

14. = 5(x-y) +4(2x+y) +2(y-4x) /60 = 5x-5y+8x+4x+2y-8x/60 = 9x-3y/60