design of two way hollow block slab

Fcu = 350 kg\cm2

Fy = 4600 kg\cm2

Ts = 0.07 m L.L. = 0.2 t\m2

F.C. = 0.2 t\m2

e = 0.4 m b = 0.1 m h = 0.25 m

γc = 2.5 t \ m2

S = 0.5 m 0.02 ton

m = 1 m\ = 1

L = 8.705 Ls = 8.705

* steps of design

0.32 cm

2) Get the loads on the slab Wrib = 0.692 t \ 1 X s m2

3) Calculate the load factors ά , β r = 1

ά= FALSE ά=

β= FALSE β=

Weight of one Block =

Input Data

1) choose t = ts + h =

( L.L LESS THAN 0.5 t\m2

PLEASE ENTER ά&β )

0.396

0.396

4) take strips at load directions

ά direction M 1 = 2.595666

β direction M2 = 2.595666

5) Design The Ribs. (Dimensions & RFT.)

Short Direction

d = 0.29 m B= 0.5 m

C1 = 7.529959 c/d = 0.05038 J= 0.826

A sά 2.355662 cm2

2Ø12 = 2.26 1Ø12+1Ø14 = 2.67

use 1Ø12+1Ø14 mm 2Ø14 = 3.08 1Ø14+1Ø16 = 3.55

2Ø16 = 4.02 1Ø16+1Ø18 = 4.55

2Ø18 = 5.09

Long Direction

d = 0.28 m B= 0.5 m

C1 = 7.270305 c/d = 0.054126 J= 0.826

A sά 2.439793 cm2

2Ø12 = 2.26 1Ø12+1Ø14 = 2.67

use 1Ø12+1Ø14 \mm 2Ø14 = 3.08 1Ø14+1Ø16 = 3.55

2Ø16 = 4.02 1Ø16+1Ø18 = 4.55

2Ø18 = 5.09

Fcu = 250 kg\cm2

Fy = 3600 kg\cm2

Ts = 0.06 m L.L. = 0.2 t\m2

F.C. = 0.15 t\m2

e = 0.4 m b = 0.15 m h = 0.2 m

γc = 2.5 t \ m2

S = 0.55 m 0.02 ton

L = 8 Ls = 5

* steps of design

0.26 cm

2) Get the loads on the slab Wrib u.l. = 0.708 t \ 1 X s m2

3) take strips at load directions

M = 2.2125

4) Design The Ribs. (Dimensions & RFT.)

d = 0.23 m B= 0.55 m

C1 = 5.7337341 c/d = 0.08825 J= 0.826

A s = 3.2349896 cm2

2Ø12 = 2.26 1Ø12+1Ø14 = 2.67

use 1Ø14+1Ø16 mm 2Ø14 = 3.08 1Ø14+1Ø16 = 3.55

2Ø16 = 4.02 1Ø16+1Ø18 = 4.55

2Ø18 = 5.09

5 ) Design of The Beam

W rib = 0.708 t \ 1 X s m2

l rib = 5 m

S = 0.55 m

W b =( W rib x l rib )/2S = 3.21818 t\m\

Weight of one Block =

Input Data

1) choose t = ts + h =

DESIGNED BY: Eng ehab abd el moniem

design of one way hollow block slab

SLAB NO:

GROUND SLAB

villa

1

PROJECT NAME:

BULDING NAME:

النعيرية مسجد

FLOOR NO:

Fcu = 350 kg\cm2

Fy = 4200 kg\cm2

Ts = 0.1 m L.L. = 0.3 t\m2

F.C. = 0.2 t\m2

e = 0.4 m b = 0.1 m h = 0.25 m

γc = 2.5 t \ m2

S = 0.5 m 0.02 ton

m = 0.76 m\ = 0.76

L = 10 Ls = 10

* steps of design

0.35 cm

2) Get the loads on the slab Wrib = 0.7825 t \ 1 X s m2

3) Calculate the load factors ά , β r = 1

ά= FALSE ά=

β= FALSE β=

4) take strips at load directions

ά direction M 1 = 3.873375

β direction M2 = 3.873375

5) Design The Ribs. (Dimensions & RFT.)

Short Direction

d = 0.32 m B= 0.5 m

C1 = 6.801806 c/d = 0.062039 J= 0.826

A sά 3.489074 cm2

2Ø12 = 2.26 1Ø12+1Ø14 = 2.67

use 1Ø14+1Ø16 mm 2Ø14 = 3.08 1Ø14+1Ø16 = 3.55

2Ø16 = 4.02 1Ø16+1Ø18 = 4.55

2Ø18 = 5.09

Long Direction

d = 0.31 m B= 0.5 m

C1 = 6.589249 c/d = 0.06622 J= 0.826

A sβ 3.601625 cm2

2Ø12 = 2.26 1Ø12+1Ø14 = 2.67

use 2Ø16 \mm 2Ø14 = 3.08 1Ø14+1Ø16 = 3.55

2Ø16 = 4.02 1Ø16+1Ø18 = 4.55

2Ø18 = 5.09

6 ) Design of The Long Beam

W ribά = 0.30987 t \ 1 X s m2

l rib = 10 m

S = 0.5 m

W b =( W rib x l rib )/2S = 3.0987 t\m\

6 ) Design of The Short Beam

W ribβ = 0.30987 t \ 1 X s m2

l rib = 10 m

S = 0.5 m

W b =( W rib x l rib )/2S = 3.0987 t\m\

0.396 ( L.L LESS THAN 0.5 t\m2

PLEASE ENTER ά&β )0.396

1

design of two way hollow block slab

SLAB NO:

Input Data

Weight of one Block =

1) choose t = ts + h =

FLOOR NO: GROUND SLAB

PROJECT NAME: النعيرية مسجد DESIGNED BY: Eng ehab abd el moniem

BULDING NAME: MOSQUE

Fcu = 350 kg\cm2

Fy = 4200 kg\cm2

Ts = 0.1 m L.L. = 0.3 t\m2

F.C. = 0.2 t\m2

e = 0.4 m b = 0.15 m h = 0.25 m

γc = 2.5 t \ m2

S = 0.55 m 0.02 ton

L = 20 Ls = 9.55

* steps of design

0.35 cm

2) Get the loads on the slab Wrib u.l. = 0.88175 t \ 1 X s m2

3) take strips at load directions

M = 10.05223

4) Design The Ribs. (Dimensions & RFT.)

d = 0.31 m B= 0.55 m

C1 = 4.2898879 c/d = 0.162679 J= 0.813

A s = 9.4964371 cm2

2Ø12 = 2.26 1Ø12+1Ø14 = 2.67

use الديزاين عيد فضلك من mm 2Ø14 = 3.08 1Ø14+1Ø16 = 3.55

2Ø16 = 4.02 1Ø16+1Ø18 = 4.55

2Ø18 = 5.09

5 ) Design of The Beam 2

W rib = 0.88175 t \ 1 X s m2

l rib = 9.55 m

S = 0.55 m

W b =( W rib x l rib )/2S = 7.655193 t\m\

O.W OF BEAM 3.92

W WALL 1.4

TOTAL LOAD BEAM 12.97519

BULDING NAME: villa

PROJECT NAME: النعيرية مسجد DESIGNED BY: Eng ehab abd el moniem

Weight of one Block =

1) choose t = ts + h =

FLOOR NO: GROUND SLAB

SLAB NO: 2

design of one way hollow block slab

Input Data

Fcu = 350 kg\cm2

Fy = 4200 kg\cm2

Ts = 0.1 m L.L. = 0.3 t\m2

F.C. = 0.2 t\m2

e = 0.4 m b = 0.1 m h = 0.25 m

γc = 2.5 t \ m2

S = 0.5 m 0.02 ton

m = 0.87 m\ = 0.87

L = 10 Ls = 10

* steps of design

0.35 cm

2) Get the loads on the slab Wrib = 0.7825 t \ 1 X s m2

3) Calculate the load factors ά , β r = 1

ά= FALSE ά=

β= FALSE β=

4) take strips at load directions

ά direction M 1 = 3.873375

β direction M2 = 3.873375

5) Design The Ribs. (Dimensions & RFT.)

Short Direction

d = 0.32 m B= 0.5 m

C1 = 6.8018058 c/d = 0.062039 J= 0.826

A sά 3.4890744 cm2

2Ø12 = 2.26 1Ø12+1Ø14 = 2.67

use 1Ø14+1Ø16 mm 2Ø14 = 3.08 1Ø14+1Ø16 = 3.55

2Ø16 = 4.02 1Ø16+1Ø18 = 4.55

2Ø18 = 5.09

Long Direction

d = 0.31 m B= 0.5 m

C1 = 6.5892494 c/d = 0.06622 J= 0.826

A sβ 3.6016252 cm2

2Ø12 = 2.26 1Ø12+1Ø14 = 2.67

use 2Ø16 \mm 2Ø14 = 3.08 1Ø14+1Ø16 = 3.55

2Ø16 = 4.02 1Ø16+1Ø18 = 4.55

2Ø18 = 5.09

6 ) Design of The Long Beam

W ribά = 0.30987 t \ 1 X s m2

l rib = 10 m

S = 0.5 m

W b =( W rib x l rib )/2S = 3.0987 t\m\

6 ) Design of The Short Beam

W ribβ = 0.30987 t \ 1 X s m2

l rib = 10 m

S = 0.5 m

W b =( W rib x l rib )/2S = 3.0987 t\m\

3

design of two way hollow block slab

Input Data

BULDING NAME: MOSQUE

PROJECT NAME: النعيرية مسجد

1) choose t = ts + h =

0.396 ( L.L LESS THAN 0.5 t\m2

PLEASE ENTER ά&β )0.396

DESIGNED BY: Eng ehab abd el moniem

Weight of one Block =

FLOOR NO: GROUND SLAB

SLAB NO:

Fcu = 350 kg\cm2

Fy = 4200 kg\cm2

Ts = 0.1 m L.L. = 0.3 t\m2

F.C. = 0.2 t\m2

e = 0.4 m b = 0.15 m h = 0.25 m

γc = 2.5 t \ m2

S = 0.55 m 0.02 ton

L = 30 Ls = 5.4

* steps of design

0.35 cm

2) Get the loads on the slab Wrib u.l. = 0.88175 t \ 1 X s m2

3) take strips at load directions

M = 3.213979

4) Design The Ribs. (Dimensions & RFT.)

d = 0.31 m B= 0.55 m

C1 = 7.5867463 c/d = 0.049613 J= 0.826

A s = 2.9884911 cm2

2Ø12 = 2.26 1Ø12+1Ø14 = 2.67

use 2Ø14 mm 2Ø14 = 3.08 1Ø14+1Ø16 = 3.55

2Ø16 = 4.02 1Ø16+1Ø18 = 4.55

2Ø18 = 5.09

5 ) Design of The Beam 1

W rib = 0.88175 t \ 1 X s m2

l rib = 5.4 m

S = 0.55 m

W b =( W rib x l rib )/2S = 4.328591 t\m\

O.W OF BEAM

W WALL 0.5

TOTAL LOAD BEAM 4.828591

BULDING NAME: villa

PROJECT NAME: النعيرية مسجد DESIGNED BY: Eng ehab abd el moniem

Weight of one Block =

1) choose t = ts + h =

FLOOR NO: GROUND SLAB

SLAB NO: 4

design of one way hollow block slab

Input Data

Fcu = 300 kg\cm2

Fy = 4200 kg\cm2

Ts = 0.1 m L.L. = 0.2 t\m2

F.C. = 0.2 t\m2

e = 0.4 m b = 0.1 m h = 0.25 m

γc = 2.5 t \ m2

S = 0.5 m 0.02 ton

L = 10 Ls = 5.8

* steps of design

0.35 cm

2) Get the loads on the slab Wrib u.l. = 0.7025 t \ 1 X s m2

3) take strips at load directions

M = 2.954013

4) Design The Ribs. (Dimensions & RFT.)

d = 0.32 m B= 0.5 m

C1 = 7.2108995 c/d = 0.055042 J= 0.826

A s = 2.6609273 cm2

2Ø12 = 2.26 1Ø12+1Ø14 = 2.67

use 1Ø12+1Ø14 mm 2Ø14 = 3.08 1Ø14+1Ø16 = 3.55

2Ø16 = 4.02 1Ø16+1Ø18 = 4.55

2Ø18 = 5.09

5 ) Design of The Beam 5

W rib = 0.7025 t \ 1 X s m2

l rib = 5.8 m

S = 0.5 m

W b =( W rib x l rib )/2S = 4.0745 t\m\

BULDING NAME: villa

PROJECT NAME: النعيرية مسجد DESIGNED BY: Eng ehab abd el moniem

Weight of one Block =

1) choose t = ts + h =

FLOOR NO: GROUND SLAB

SLAB NO: 5

design of one way hollow block slab

Input Data

Fcu = 300 kg\cm2

Fy = 4200 kg\cm2

Ts = 0.1 m L.L. = 0.2 t\m2

F.C. = 0.2 t\m2

e = 0.4 m b = 0.1 m h = 0.25 m

γc = 2.5 t \ m2

S = 0.5 m 0.02 ton

L = 8.65 Ls = 5.25

* steps of design

0.35 cm

2) Get the loads on the slab Wrib u.l. = 0.7025 t \ 1 X s m2

3) take strips at load directions

M = 2.420332

4) Design The Ribs. (Dimensions & RFT.)

d = 0.32 m B= 0.5 m

C1 = 7.9663271 c/d = 0.044912 J= 0.826

A s = 2.1801965 cm2

2Ø12 = 2.26 1Ø12+1Ø14 = 2.67

use 2Ø12 mm 2Ø14 = 3.08 1Ø14+1Ø16 = 3.55

2Ø16 = 4.02 1Ø16+1Ø18 = 4.55

2Ø18 = 5.09

5 ) Design of The Beam 6

W rib = 0.7025 t \ 1 X s m2

l rib = 5.25 m

S = 0.5 m

W b =( W rib x l rib )/2S = 3.688125 t\m\

BULDING NAME: villa

PROJECT NAME: النعيرية مسجد DESIGNED BY: Eng ehab abd el moniem

Weight of one Block =

1) choose t = ts + h =

FLOOR NO: GROUND SLAB

SLAB NO: 6

design of one way hollow block slab

Input Data

Fcu = 300 kg\cm2

Fy = 4200 kg\cm2

Ts = 0.1 m L.L. = 0.2 t\m2

F.C. = 0.2 t\m2

e = 0.4 m b = 0.1 m h = 0.25 m

γc = 2.5 t \ m2

S = 0.5 m 0.02 ton

L = 5.25 Ls = 5.25

* steps of design

0.35 cm

2) Get the loads on the slab Wrib u.l. = 0.7025 t \ 1 X s m2

3) take strips at load directions

M = 2.420332

4) Design The Ribs. (Dimensions & RFT.)

d = 0.32 m B= 0.5 m

C1 = 7.9663271 c/d = 0.044912 J= 0.826

A s = 2.1801965 cm2

2Ø12 = 2.26 1Ø12+1Ø14 = 2.67

use 2Ø12 mm 2Ø14 = 3.08 1Ø14+1Ø16 = 3.55

2Ø16 = 4.02 1Ø16+1Ø18 = 4.55

2Ø18 = 5.09

5 ) Design of The Beam 7

W rib = 0.7025 t \ 1 X s m2

l rib = 5.25 m

S = 0.5 m

W b =( W rib x l rib )/2S = 3.688125 t\m\

BULDING NAME: villa

PROJECT NAME: النعيرية مسجد DESIGNED BY: Eng ehab abd el moniem

Weight of one Block =

1) choose t = ts + h =

FLOOR NO: GROUND SLAB

SLAB NO: 7

design of one way hollow block slab

Input Data

Fcu = 300 kg\cm2

Fy = 4200 kg\cm2

Ts = 0.1 m L.L. = 0.2 t\m2

F.C. = 0.2 t\m2

e = 0.4 m b = 0.1 m h = 0.25 m

γc = 2.5 t \ m2

S = 0.5 m 0.02 ton

L = 8.4 Ls = 5.25

* steps of design

0.35 cm

2) Get the loads on the slab Wrib u.l. = 0.7025 t \ 1 X s m2

3) take strips at load directions

M = 2.420332

4) Design The Ribs. (Dimensions & RFT.)

d = 0.32 m B= 0.5 m

C1 = 7.9663271 c/d = 0.044912 J= 0.826

A s = 2.1801965 cm2

2Ø12 = 2.26 1Ø12+1Ø14 = 2.67

use 2Ø12 mm 2Ø14 = 3.08 1Ø14+1Ø16 = 3.55

2Ø16 = 4.02 1Ø16+1Ø18 = 4.55

2Ø18 = 5.09

5 ) Design of The Beam 7

W rib = 0.7025 t \ 1 X s m2

l rib = 5.25 m

S = 0.5 m

W b =( W rib x l rib )/2S = 3.688125 t\m\

BULDING NAME: villa

PROJECT NAME: النعيرية مسجد DESIGNED BY: Eng ehab abd el moniem

Weight of one Block =

1) choose t = ts + h =

FLOOR NO: GROUND SLAB

SLAB NO: 8

design of one way hollow block slab

Input Data

Fcu = 350 kg\cm2

Ts = 0.1 m L.L. = 0.3 t\m2

e = 0.4 m b = 0.1 m

γc = 2.5 t \ m2

S = 0.5 m

L = 15 Ls = 10.6

* steps of design

0.35 cm

2) Get the loads on the slab Wrib u.l. = 0.7825 t \ 1 X s m2

3) take strips at load directions

M = 10.99021

4) Design The Ribs. (Dimensions & RFT.)

d = 0.32 m B= 0.5 m

C1 = 4.037997 c/d = 0.185412 J= 0.806

A s = 10.14546 cm2

2Ø12

use الديزاين عيد فضلك من mm 2Ø14

2Ø16

2Ø18

5 ) Design of The Beam 7

W rib = 0.7825 t \ 1 X s m2

l rib = 10.6 m

S = 0.5 m

W b =( W rib x l rib )/2S =8.2945 t\m\

Weight of one Block =

1) choose t = ts + h =

FLOOR NO: GROUND SLAB

SLAB NO: 9

design of one way hollow block slabInput Data

PROJECT NAME: النعيرية مسجد DESIGNED BY:

BULDING NAME: villa

Fy = 4200 kg\cm2

F.C. = 0.2 t\m2

h = 0.25 m

0.02 ton

= 2.26 1Ø12+1Ø14 = 2.67

= 3.08 1Ø14+1Ø16 = 3.55

= 4.02 1Ø16+1Ø18 = 4.55

= 5.09

Weight of one Block =

design of one way hollow block slab

DESIGNED BY: Eng ehab abd el moniem

Fcu = 350 kg\cm2

Fy = 4200 kg\cm2

Ts = 0.1 m L.L. = 0.3 t\m2

F.C. = 0.2 t\m2

e = 0.4 m b = 0.1 m h = 0.25 m

γc = 2.5 t \ m2

S = 0.5 m 0.02 ton

L = 8.4 Ls = 8.5

* steps of design

0.35 cm

2) Get the loads on the slab Wrib u.l. = 0.7825 t \ 1 X s m2

3) take strips at load directions

M = 7.066953

4) Design The Ribs. (Dimensions & RFT.)

d = 0.32 m B= 0.5 m

C1 = 5.035619 c/d = 0.11574 J= 0.826

A s = 6.365799 cm2

2Ø12 = 2.26 1Ø12+1Ø14 = 2.67

Weight of one Block =

1) choose t = ts + h =

FLOOR NO: GROUND SLAB

SLAB NO: 10

design of one way hollow block slabInput Data

PROJECT NAME: النعيرية مسجد DESIGNED BY: Eng ehab abd el moniemBULDING NAME: villa

use الديزاين عيد فضلك من mm 2Ø14 = 3.08 1Ø14+1Ø16 = 3.55

2Ø16 = 4.02 1Ø16+1Ø18 = 4.55

2Ø18 = 5.09

5 ) Design of The Beam 7

W rib = 0.7825 t \ 1 X s m2

l rib = 8.5 m

S = 0.5 m

W b =( W rib x l rib )/2S =6.65125 t\m\