Gv: Nguyn Hng Khnh _ HKP CHNG VI: LNG T NH SNGDi ng: 09166.01248 Email: Khanhcaphe@gmail.com Gio Dc Hng Phc - Ni Khi u c M! Trang 1 CHNG VI: LNG T NH SNG BI 1: HIN TNG QUANG IN NGOI I. PHNG PHP 1.NH NGHA HIN TNG QUANG IN NGOI 1.1. Th nghin hin tng quang in ngoi n h quangn h quang e n h quang e H1. C tm thy tinh H2. Khng c tm thy tinh ab 1..2. Nhn xt: hnh 1: Ta t tm thy tinh trc n h quang, thy khng c hin tng g sy ra vi hai tm km tch in m hnh 2: Khi b tm thy tinh trong sut ra mt lc sau thy hai l km tch in m b cp xung. Chng t in tch m ca l km b gii phng ra ngoi.Th nghim s 2 gi l th nghim v hin tng quang in 1.3.nh ngha v hin tng quang in ngoi Hin tng khi chiu nh sng vo tm kim loi lm cc electron bt ra ngoi gi l hin tng quang in ngoi. ( Hin tng quang in)2.CC NH LUT QUANG IN 2.1.nh lut 1: ( nh lut v gii hn quang in) Hin tng quang in ch xy ra khi nh sng kch thch chiu vo tm kim loi c bc sng nh hn hoc bng bc sng 0. 0 c gi l gii hn quang in ca kim loi . ( 0 ) 2.2.nh lut 2: (nh lut v cng dng quang in bo ha) i vi mi nh sng kch thch c ( 0 ), cng dng quang in bo ha t l vi cng ca chm sng kch thch. 2.3.nh lut 3: ( nh lut v ng nng cc i ca quang electron) ng nng ban u cc i ca quang electron khng ph thuc cng ca chm kich thch, m ch ph thuc bc sng nh sng kch thch v bn cht kim loi. c tuyn trn th hin mi quan h gia hiu in th U AK v cng dng quan in bo ha. -Khi U AK < - U h th dng quanin bo ha b trit tiu hon ton ( I = 0). S d nh vy v v: electron b bt ra t catot, vi tc ban u v omaxv ng nng ban u W dmax , chu tc dng ca lc in trng hng v catot ( do U h gy ra) lc ny ngn khng cho eletron ti anot gy ra dng quang in. - KhiU AK = 0 vn c dng quang in v, electron cvn tc ban ban u to ra s dch chuyn c hng ca cc ht mang in c dng in. - Hiuin th U AKtngdn, lmcho dngquang intng dn, nhng khi tng n gi tr U 1th khi tng tip U AK cng khng lm chodng quang in tngthm( I = I bh ). Gi tr I bh gi l dng quang in bo ha.- ng s (1) v(2) th hin dng quang in ca hai nh sng khc nhau, c cng bc sng, nhng cng ca chm sng to ra dngquangin(2)lnhndngcngcachmsngtora dng quang in (1). I U I bh1 I bh2 U 10- U h1 2 c tuyn vn - ampe k ca t bo quang in 3.LNG TNH SNG HT CA SNG IN T Sng in t va mang tnh cht sng va mang tnh cht ht. -Vi sng c bc sng cng ln th tnh cht sng th hin cng r ( cc hin tng nh giao thoa, khc x, tn sc) -Vi cc sng c bc sng cng nh th tnh cht ht th hin cng r ( cc hin tng nh quang in, kh nng m xuyn) 4.THUYT LNG T NH SNG Gv: Nguyn Hng Khnh _ HKP CHNG VI: LNG T NH SNGDi ng: 09166.01248 Email: Khanhcaphe@gmail.com Gio Dc Hng Phc - Ni Khi u c M! Trang 2 nh sng c to bi cc ht gi l phton( cc lng t nh sng) . Mi ph tn c nng lng xc nh c = h.f. ( f l tn s ca sng nh sngn sc tng ng). Cng ca chm sng t l vi s ph tn pht ra trong 1 giy. Phn t, nguyn t, eletron pht ra hay hp th nh sng, cng c ngha l chng pht x hay hp th ph tn. Cc ph tn bay dc theo tia sng vi tc c = 3.108 m/s trong chn khng. 5.CC CNG THC QUANG IN C BN Ct1: Cng thc xc nh nng lng ph tn:c = h f = hc Ct2: Cng thc anh tanh v hin tng quang in ngoi hc= A 0 + 12 mv2 o hoc hc= hc 0+12 mv2 o ( W dmax=12 mv2 o= e. |U h| ) Ct3:Cng sut ca ngun sng- hoc cng sut chiu sng: P =n .c = n .hf =n hc. n =Phc

Ct4: Cng dng quang in bo ha: I bh = n e.e = Nt e n e= I bhe

Ct5: Hiu sut pht quang: H = n en . 100% = I.hce.P. .100% Gii thch v k hiu: -: Nng lng photon ( J) - h: Hng s plank h= 6,625.10-34 j.s. - c: Vn tc nh sng trong chn khng. c = 3.108 m/s. -f : Tn s ca nh sng kch thch ( Hz) - : Bc sng kch thch ( m) - 0 : Gii hn quang in ( m) - m : Khi lng e. m e = 9,1. 10-31 kg -v : Vn tc e quang in ( m/s) - W dmax : ng nng cc i ca e quang in ( J) - U h : Hiu in th hm, gi tr hiu in th m cc e quang in khng th bt ra ngoi -P: Cng sut ca ngun kch thch ( J) - n : s ph tn p ti ca tt trong 1s - n e : S e bt ra khi catot trong 1 s - e :in tch nguyn t |e| = 1,6. 10-19 C -H : Hiu sut lng t. ( %). - 1 MeV = 1,6. 10-13 J; 1 eV = 1,6. 10-19 J. nh l ng nng: W d = W do + Uq ( nu U Ak >0)W d = W do - |U|q ( nu U Ak < 0)

trit tiu dng quang in th khng cn e quang in tr v Anot. Cng c ngha l W d = 0 hoc e b ht ngc trli catot.|U|.q W do = 12 m.v o2 + + + + + - - - - - W doW d U e K 6. MT S BI TON CN CH Bi ton 1: Bi ton xc nh bn knh qu o ca electron trong t trng F lorenxo = qvB = m. v2 R= F hng tm R = m.vqB

Bi ton 2: Bi ton xc nh in tch ca qu cu kim loi t trongkhngkhkhib chiu snghintng quang in ngoi sy ra: Cng thc Gauxo ta c: E.S = qc.c o

R Gv: Nguyn Hng Khnh _ HKP CHNG VI: LNG T NH SNGDi ng: 09166.01248 Email: Khanhcaphe@gmail.com Gio Dc Hng Phc - Ni Khi u c M! Trang 3 Trong : E in trng trng to ra ca qu cu S l din tch mt cu q l in tch ca qu cu c = 14tk

c o hng s in mi Trong khng kh: c o = 1.U hR .4t.R2 = q.4t.k q = U h.Rk

Bi ton 3: Bi ton xc nh bn knh cc i ca e quang in khi n anot: R = V o.t d = at2 2 Vi a = q.Em= q.Um.d d = q.U.t2 2m.d t = 2md2 q.U

m V o2 2= q.|U h | V o =2.q.|U h |m

R = 2m.d2 .2.q.|U h | q.U.m = 2d U hU

+++++++ - - - - - - - d R

II.BI TP MU V d 1: Mt ngn n ra pha nh sng mu c bc sng = 0,7 m. Vi h = 6,625.10-34 Js; c = 3.108 m/s. Hy xc nh nng lng ca pho ton nh sng. A. 1,77 MeVB. 2,84 MeVC. 1,77 eVD. 2,84 eV Hng dn: [ ]p n C Ta c: c= hc= 6,625.10-34 . 3.108 0,7.10-6 = 2,84.10-19 J = 1,77 eV V d 2: Mt ngn n pht ra nh sng vi cng sut P = 2W, bc sng ca nh sng = 0,7 m. Vi h = 6,625.10-34 Js; c = 3.108 m/s. Xc nh s ph tn n pht ra trong 1s. A. 7,04.1018 htB. 5,07.1020 htC. 7.1019 htD. 7.1021 ht Hng dn: [ ]p n A Ta c: P = n . hc n =P. hc = 2. 0,7.10-6 6,625.10-34 .3.108 = 7,04.1018 ht. V d 3: Mt tm kim loi c gii hn quang in o = 0,6 m, c chiu sng bi bc x n sc c bc sng = 0,7 m. Hy xc nh vn tc cc i ca e quang in. A. 3,82.106 m/sB. 4,57.105 m/sC. 5,73.10 4m/sD. Ht quang in Khng sy ra.Hng dn: [ ]p n D V > o hin tng quang in khng sy ra. V d 4: Mt tm kim loi c gii hn quang in o = 0,6 m, c chiu sng bi bc x n sc c bc sng = 0,5 m. Hy xc nh vn tc cc i ca e quang in. A. 3,82.105 m/sB. 4,57.105 m/sC. 5,73.10 4m/sD. Ht quang in Khng sy ra Hng dn: [ ] p n A p dng cng thc Anhtanh ta c: hc= hc o+ 12 m. V o2 hc( 1- 1 o ) = 12 m. V o2 V o = 2hcm ( 1 - 1 o ) Gv: Nguyn Hng Khnh _ HKP CHNG VI: LNG T NH SNGDi ng: 09166.01248 Email: Khanhcaphe@gmail.com Gio Dc Hng Phc - Ni Khi u c M! Trang 4 =2. 6,625.10-34 .3.108 9,1.10-31 . ( 10,5.10-6 - 10,6.10-6 )= 3,82.105 m/s V d 5: Chiu bc x c bc sng ph hp vomt tm kim loi, th hin tng quang in xy ra. Ngi ta o c cng dng quang in bo hal I = 2mA. Hy xc nh s e quang in pht ra trong mt giy? Cho e = 1,6.10-19 C. A. 1,25.1016 htB. 2.1016 htC. 2,15.1016 htD. 3.1015 htHng dn: [ ] p n A Ta c: I = n e.e n e = Ie = 2.10-3 1.6.10-19 = 1,25.1016 ht V d 4: Mt tm kim loi c gii hn quang in o = 0,6 m, c chiu sng bi 2 bc x n sc c bc sng 1 = 0,5 m v 2 = 0,55 m . Hy xc nh vn tc cc i ca e quang in. A. 3,82.105 m/sB. 4,57.105 m/sC. 5,73.10 4m/sD. Ht quang in Khng sy ra Hng dn: [ ] p n A Khi tm kim loi b chiu sng bi 2 hay nhiu bc x khc nhau th khi tnh v max hoc |U h|ln nht theo bc x c nng lng ln nht( tc l c bc sng nh nht). V 1 < 2, Nn khi tnh V max ta tnh theo 1.p dng cng thc Anhtanh ta c: hc= hc o+ 12 m. V o hc( 1- 1 o ) = 12 m. V o2 V o = 2hcm ( 1 - 1 o ) =2. 6,625.10-34 .3.108 9,1.10-31 . ( 10,5.10-6 - 10,6.10-6 )= 3,82.105 m/s V d 7 : Chiu vo catot ca mt t bo quang in cc bc x c bc sng = 400nm v 1= 0,25m th thy vn tc ban u cc i ca electron quang in gp i nhau. Xc nh cng thot eletron ca kim loi lm catot. Cho h = 6,625.10-34Js v c = 3.108m/s. A.A = 3, 9750.10-19J.B.A = 1,9875.10-19J.C.A = 5,9625.10-19J. D.A = 2,385.10-18J Hng dn: [ ]p n A Gi v 1 l vn tc ban u cc i ca e quang in khi chiu 1vo t bo quang in v l vn tc ban u cc i ca e quang in khi chiu vo t bo quang in. Theo : 1< v 1 = 2v W d1 max= 4 W d max Ta c h phng trnh sau: hc = A + W d max (1)hc 1 = A + 4 W d1max (2) T (1) W dmax= hc- A (3) Thay (3) vo (2): hc 1= A + 4

(hc - A

4hc- hc 1= 3A A = 13 hc

((4 - 1 1 = 13 1,9875.10-25

(40,4.10-6 - 10,25.10-6 = 3,975.10-19 JV d 8 : Chiu ln lt cc bc x c tn s f, 3f, 5f vo catt ca t bo quang in th vn tc ban u cc i ca electron quang in ln lt l v, 3v, kv. Gi tr k l A. 34B. 5C. 17D. 15 Hng dn: [ ]p n C Theo bi ta c: hf = A + W d max (1) 3.hf = A + 9 W d max (2) Tr (2) cho (1) v theo v ta c: 2hf = 8 W dmax hf = 4W dmax (3) Thay (3) vo (1) ta c: A = hf - W dmax = 3W dmax.

5hf = A + k2 . W dmax

5.4W dmax= 3 W dmax+ k2 . W dmax k2 = 17. Gv: Nguyn Hng Khnh _ HKP CHNG VI: LNG T NH SNGDi ng: 09166.01248 Email: Khanhcaphe@gmail.com Gio Dc Hng Phc - Ni Khi u c M! Trang 5 k =17

V d 9: Catt ca t bo quang in chn khng l mt tm kim loi phng c gii hn quang in l o = 0,6 m . Chiu vo catt nh sng c bc sng = 0,5 m. Ant cng l tm lim loi phng cch catt 1cm. Gia chng c mt hiu inth 10V. Tm bn knh ln nht trn b mt ant c quang electron p ti. A. R = 4,06 mmB. R = 4,06 cmC. R = 8,1 mm D. R = 6,2 cmHng dn: [ ]p n C p dng cng thc: R = 4d U hU AK Trong :U h =hc|e|

(1 - 1 o =1,9875.10-25 1,6.10-19

(10,5.10-6 - 10,6.10-6 = 0,414 V U AK= 10 V d = 1 cm = 10-2 m R = 4.10-2 0,41410= 8,1. 10-3 m= 8,1 mm. III. BI TP THC HNH Cu 1: Chn cu ng : A: Hin tng giao thoa d quan st i vi nh sng c bcsngngn . B: Hin tng quang in chng t tnh cht sng ca nh sng . C: Nhng sng in t c tn s cng ln th tnhcht sng th hin cng r . D: Sng in t c bc sng ln th nng lng ph tn nh . Cu 2: Khi chiu sng in t xung b mt tm kim loi, hin tng quang in xy ra nu : A: sng in t c nhit caoB: sng in t c bc sng thch hp C: sng in t c cng lnD: sng in t phi l nh sng nhn thy c Cu 3: Cng thc lin h gia gii hn quang in0, cng thot A, hng s Planck h v vn tc nh sng c l : A:0 = chAB:0 = hcAC:0 = hAcD:0 = Ahc Cu 4: Gii hn quang in ca mi kim loi l : A: Bc sng di nhtca bc x chiu vo kim loi gy ra c hin tng quang in B: Bc sng ngnnhtca bc x chiu vo kim loi gy ra c hin tng quang inC: Cng nh nht dng bt electron ra khi kim loi D: Cnglnnht dng bt electron ra khi kim loi Cu 5:Hin tng kim loi b nhim in dng khi c chiu sng thch hp l : A: Hin tng quang in.B: Hin tng quang dn. C: Hin tng tn sc nh sng.D: Hin tng giao thoa nh sng. Cu 6: Chn cu ng. Nu chiu mt chm tia hng ngoi vo tm km tch in m, th : A: Tm km mt dn in tch dng. B: Tm km mt dn in tch m.C: Tm km tr nn trung ho v in. D: in tch m ca tm km khng i Cu 7: Pht biu no sau y l ng khi ni v hin tng quang in ? A: L hin tng lectron bt ra khi b mt tm kim loi khi c nh sng thch hp chiu vo n B: L hin tng lectron bt ra khi b mt tm kim loi khi tm kim loi b nung nng. C: L hin tng lectron bt ra khi b mt tm kim loi b nhim in do tip xc vi mt vt nhim in khc D: L hin tng electron b bt ra khi kim loi khi t tm kim loi vo trong mt in trng mnh. Cu 8: Chn cu ng. Theo thuyt phtn ca Anh-xtanh, th nng lng : A: ca mi phtn u bng nhau. B: ca mt phtn bng mt lng t nng lng C: gim dn khi phtn ra xa dn ngun sng. D: ca phton khng ph thuc vo bc sng. Cu 9: Vi 1, 2, 3 ln lt l nng lng ca phtn ng vi cc bc x mu vng, bc x t ngoi v bc x hng ngoi th A: 3 > 1 > 2 B: 2 > 1 > 3 C: 1 > 2 > 3 D: 2 > 3 > 1 Cu 10:Kim loi Kali (K) c gii hn quang in l 0,55 m. Hin tng quang in khng xy ra khi chiu vo kim loi bc x nm trong vng: A: nh sng mu tm. B: nh sng mu lam. C: hng ngoi. D: t ngoi. Cu 11:Nu quan nim nh sng ch c tnh cht sng th khng th gii thch c hin tng no di y? A: Khc x nh sng.B: Giao thoa nh sng.C: Quang in.D: Phn x nh sng. Gv: Nguyn Hng Khnh _ HKP CHNG VI: LNG T NH SNGDi ng: 09166.01248 Email: Khanhcaphe@gmail.com Gio Dc Hng Phc - Ni Khi u c M! Trang 6 Cu 12:Trong th nghim Hcx, nu chiu nh sng tm vo l nhm tch in m ( gii hn quang in ca nhm nm trong vng t ngoi)thA: in tch m ca l nhm mt iB: tm nhm s trung ha v in C: in tch ca tm nhm khng thay i. D: tm nhm tch in dng Cu 13:Chiu bc x c tn s f n mt tm kim loi .Ta khiu oocf=,o lbc sng gii hnca kim loi .Hin tng quang in xy ra khi : A: f> fo . B: f < fo C: f> 0 D: fs fo

Cu 14:Nu chn chm nh sng h quang bng mt tm thy tinh dy (mt cht hp th mnh nh sng t ngoi) th hin tng quang in khng xy ra iu chng t: A: Hin tng quang in ch xy ra khi cng ca chm nh sng kch thch ln. B: Hin tng quang in ch xy ra i vi nh sng nhn thy. C: Hin tng quang in ch xy ra i vi tia hng ngoi. D: Hin tng quang in ch xy ra i vi tia t ngoi.Cu 15:Trong cc trng hp sau y, lectrn no c gi l lectrn quang in? A: lectrn trong dy dn in. B: lectrn chuyn t tm kim loi ny sang tm kim loi khc khi 2 tm c xt. C: lectrn bt ra t catt ca t bo quang in. D: lectrn to ra trong cht bn dn n. Cu 16:Chm tia bc x no sau y gy ra hin tng quang in cho hu ht cc kim loi? A: chm tia Rn ghen.B: chm tia t ngoi. C: chm nh sng nhn thy.D: chm tia hng ngoi. Cu 17:Tm pht biu sai v th nghim vi t bo quang in? A: ng c trng vn ampe ca t bo quang in cho thy, khi UAK c gi tr cn nh m tng th dng quang in cng tng. B: Khi UAK t n mt gi tr no th cng dng quang in t n gi tr bo ha Ibh. C: Gi tr cng dng quang in bo ha t l thun vi cng chm sng chiu vo t bo quang in. D: Khi UAK s 0 th dng quang in trit tiu v cc lectrn quang in khi khng v c ant to nn dng quang in. Cu 18:Chn cu sai khi ni n nhng kt qu rt ra t th nghim vi t bo quang in? A: Hiu in th gia ant v catt ca t bo quang in lun c du m khi dng quang in trit tiu. B: Dng quang in vn tn ti ngay c khi hiu in th gia ant v catt ca t bo quang in c gi tr bng khng. C: Cng dng quang in bo ha khng ph thuc vo cng chm sng kch thch. D: Gi tr ca hiu in th hm ph thuc vo bc sng ca nh sng kch thch. Cu 19:Tm pht biu sai v c tuyn vn ampe ca t bo quang in? A: UAK bng 0 ta vn c dng quang in I0 khc 0. iu chng t cc lectrn bt ra t kim loi lm catt c mt ng nng ban u. B: UAK < - Uh < 0th cng dng quang in bng 0 chng t rng in p ngc mnh ko mi lectrn quang in tr li catt d chng c ng nng ban u. C: Khi UAK ln (UAK > U1) dng quang in t bo ha. Gi tr cng dng quang in bo ha ch ph thuc vo tn s ca bc x chiu n m khng ph thuc vo cng chm sng mnh hay yu. D: Thc nghim chng t rng gi tr cng dng quang in bo ha t l thun vi cng chm nh sng chiu vo t bo quang in. Cu 20:Mt chm sng n sc chiu n mt tm kim loi gy ra hin tng quang in. Gi cho cng nh sng khng thay i, mi quan h gia s lectrn pht ra trong mt n v thi gian v thi gian chiu sng c biu din bng th dng no? A: ng thng song song trc thi gianB: ng thng i qua gc ta . C: ng parabol.D: ng cong i qua gc ta .Cu 21:Tm pht biu sai v cc nh lut quang in? A: i vi mi kim loi dng lm catt c mt bc sng gii hn nht nh gi l gii hn quang in. B: Vi nh sng kch thch thch hp, cng dng quang in bo ha t l thun vi cng ca chm sng kch thch. C: Hin tng quang in ch xy ra khi tn s ca nh sng kch thch nh hn tn s gii hn ca kim loi. D: ng nng ban u cc i ca cc lectrn quang in khng ph thuc vo cng ca chm sng kch thch m ch ph thuc vo bc sng ca nh sng kch thch v bn cht ca kim loi lm catt. Cu 22:Mt chm sng n sc tc dng ln b mt mt kim loi lm bt cclectrn ra khi kim loi ny. Nu tng cng chm sng ln 3 ln th A: ng nng ban u cc i ca cc lectrn quang in tng 3 ln. B: ng nng ban u cc i ca cc lectrn quang in tng 9 ln. C: cng thot ca lectrn quang in gim 3 ln. D: s lng lectrn thot ra khi tm kim loi mi giy tng 3 ln. Cu 23:Gii hn quang in l A: bc sng nh nht ca nh sng kch thch hin tng quang in c th xy ra B: bc sng di nht ca nh sng kch thch hin tng quang in c th xy ra C: cng cc i ca nh sng kch thch hin tng quang in c th xy ra D: cng cc tiu ca chm nh sng kch thch hin tng quang in c th xy ra Cu 24:Tm pht biu sai v cc nh lut quang in? Gv: Nguyn Hng Khnh _ HKP CHNG VI: LNG T NH SNGDi ng: 09166.01248 Email: Khanhcaphe@gmail.com Gio Dc Hng Phc - Ni Khi u c M! Trang 7 A: Hin tng quang in ch xy ra khi nh sng kch thch chiu vo kim loi c bc sng nh hn hoc bng bc sng 0 gi l gii hn quang in ca kim loi : s 0.B: Cc kim loi kim v mt vi kim loi kim th, c gii hn quang in 0 trong min nh sng nhn thy. C: Cc kim loi thng dng c gii hn quang in trong min hng ngoi. D: ng nng ban u cc i ca lectrn ph thuc vo bn cht ca kim loi dng lm catt. Cu 25:Khi chiu nh sng c bc sng < 0 vo catt ca mt t bo quang in th dng quang in bng khng khi UAK = - Uh < 0. Nuchiu nh sng c bc sng' < vo catt trn, cng dng quang in vn bng khng th ln ca hiu in th hm Uh phi A: khng cn thay i g.B: gim i.C: tng ln.D: ly gi tr bng khng. Cu 26:Hiu in th hm A: ph thuc vo bc sng ca nh sng kch thch v bn cht ca kim loi dng lm catt. B: ph thuc vo cng ca chm sng kch thch. C: t l vi cng ca chm sng kch thch. D: ph thuc vo bc sng ca nh sng kch thch. Cu 27:Kt lun no sau y l sai khi dng quang in bo ha xut hin? A: Tt c cc lectrn bt ra trong mi giy u chy ht vant. B: Khng c lectrn no bt ra quay tr v catt. C: C s cn bng gia s lectrn bay ra khi catt vi s lectrn b ht tr li catt. D: Ngay c cc lectrn c vn tc ban u rt nh cng b ko v ant. Cu 28:Pht biu no sau y l ng khi ni v cng dng quang in bo ha? A: Cng dng quang in bo ha t l nghch vi cng chm sng kch thch. B: Cng dng quang in bo ha khng ph thuc vo cng chm sng kch thch. C: Cng dng quang in bo ha t l thun vi cng chm sng kch thch. D: Cng dng quang in bo ha tng theo quy lut hm s m vi cng chm sng kch thch. Cu 29:Cng dng quang in s bin i nh th no khi tng dn hiu in th gia ant v catt? A: Cng dng quang in tng dn. B: Cng dng quang in gim dn. C: Cng dng quang in tng dn v khi UAK vt qua mt gi tr ti hn no th dng quang in gi gi tr khng i. D: Cng dng quang in bin thin theo quy lut sin hay cosin theo thi gian. Cu 30:Khi c dng quang in chy trong t bo quang in th nhn nh no sau y l sai? A: Mt phn nng lng ca phtn dng thc hin cng thot lectrn. B: Hiu in th hm lun c gi tr m. C: Cng dng quang in khi cha bo ha ph thuc vo hiu in th gia ant v catt? D: Cng dng quang in bo ha t l nghch vi cng ca chm sng kch thch. Cu 31:ng nng ban u ca cc lectrn quang in s c gi tr cc i khi A: cc lectrn quang in l cc lectrn nm ngay trn b mt tinh th kim loi. B: cc lectrn quang in l cc lectrn nm su trong tinh th kim loi. C: cc lectrn quang in l cc lectrn lin kt. D: cc lectrn quang in l cc lectrn t do. Cu 32:Khi hin tng quang in xy ra, nugi nguyn bc sng nh sng kch thch v tngcng chm nh sng kch thch th A: ng nng ban u cc i ca cc lectrn tng ln. B: cng dng quang in bo ha tng ln. C: hiu in th hm tng ln. D: cc quang lectrn n ant vi vn tc ln hn. Cu 33:Tm cng thc ng cho lin h gia ln hiu in th hm Uh, ln ca in tch lectrn e, khi lng lectrn m v vn tc ban u cc i ca cc lectrn quang in v0? A: eUh = m.v02.B: 2eUh = m.v02.C: mUh = 2e.v02.D: mUh = e.v02. Cu 34:Tm pht biu sai v gi thuyt lng t nng lng ca Planck? A: Nng lng bc x m mi nguyn t pht ra hoc hp th khng th c gi tr lin tc bt k. B: Nng lng c gi tr hon ton xc nh, bao gi cng l bi s nguyn ln ca mt nng lng nguyn t khng th chia nh c na gi l lng t nng lng c. C: Lng t nng lng c t l vi tn s f: c = hf vi hng s Planck h = 6,625.1034J/s. D: Gi thuyt ca Planck c rt nhiu s kin thc nghim xc nhn l ng. Vn dng gi thuyt ny ngi ta gii thch c tt c cc nh lut v bc x nhit. Cu 35:Pht biu no sau y l khng ng? A: ng nng ban u cc i ca lectron quang in ph thuc vo bn cht ca kim loi. B: ng nng ban u cc i ca lectron quang in ph thuc bc sng ca chm nh sng kch thch. C: ng nng ban u cc i ca lectron quang in ph thuc tn s ca chm nh sng kch thch. D: ng nng ban u cc i ca lectron quang in ph thuc cng ca chm nh sng kch thch. Cu 36:Chn cu ng. A: Khi tng cng ca chm nh sng kch thch kn hai ln th cng dng quang in tng ln hai ln. B: Khi tng bc sng ca chm nh sng kch thch ln hai ln th cng dng quang in tng ln hai ln. C: Khi gim bc sng ca chm nh sng kch thch xung hai ln th cng dng quang in tng ln hai ln. Gv: Nguyn Hng Khnh _ HKP CHNG VI: LNG T NH SNGDi ng: 09166.01248 Email: Khanhcaphe@gmail.com Gio Dc Hng Phc - Ni Khi u c M! Trang 8 D: Khi nh sng kch thch gy ra c hin tng quang in. Nu gim bc sng ca chm bc x th ng nng ban u cc i ca lectron quang in tng ln. Cu 37:Theo quan im ca thuyt lng t pht biu no sau y l khng ng? A: Chm nh sng l mt dng ht, mi ht l mt phtn mang nng lng. B: Cng chm sng t l thun vi s phtn trong chm. C: Khi nh sng truyn i cc phtn nh sng khng i, khng ph thuc khong cch n ngun sng. D: Cc phtn c nng lng bng nhau v chng lan truyn vi vn tc bng nhau. Cu 38:Pht biu no sau y l khng ng? A: ng nng ban u cc i ca lectron quang inkhng ph thuc vo cng ca chm nh sng kch thch. B: ng nng ban u cc i ca lectron quang inph thuc vo bn cht kim loi dng lm catt. C: ng nng ban u cc i ca lectron quang in khng ph thuc vo bc sng ca chm nh sng kch thch. D: ng nng ban u cc i ca lectron quang in ph thuc vo bc sng ca chm nh sng kch thch. Cu 39:Chiu mt chm bc x n sc vo mt tm km c gii hn quang in 0,35 m . Hin tng quang in s khng xy ra khi chm bc x c bc sng l A: 0,1m B: 0,2m C: 0,3m D: 0,4m Cu 40:Chiu mt chm bc x n sc vo catt ca t bo quang in trit tiu dng quang in th hiu in th hm c gi tr tuyt i l 1,9V. Vn tc ban u cc i ca quang lectron l bao nhiu? A: 5,2 . 105 m/s.B: 6,2 . 10 5 m/s.C: 7,2 . 105 m/s.D: 8,17 . 105 m/s. Cu 41:Chiu mt chm nh sng n sc c bc sng 400 nm vo catt ca mt t bo quang in, c lm bng Na. Gii hn quang in ca Na l 0,50m . Vn tc ban u cc i ca lectron quang in l A: 3,28 . 105 m/s.B: 4,67 . 10 5 m/s.C: 5,45 . 105 m/s.D: 6,33 . 105 m/s. Cu 42:Chiu vo catt ca mt t bo quang in mt chm bc x n sc c bc sng 0,330 m . trit tiu dng quang in cn mt hiu in th hm c gi tr tuyt i l 1,38V. Cng thot ca kim loi dng lm catt l A: 1,16 eVB: 1,94 eVC: 2,38 eVD: 2,72 eV Cu 43:Chiuvocatt camt t bo quang in mt chm bc x n sc c bc sng 0,330m. trit tiu quang in cn mt hiu in th hm c gi tr tuyt i l 1,38 V. Gii hn quang in ca kim loi dng lm catt lA: 0,521mB: 0,442mC: 0,440mD: 0,385m Cu 44:Chiu mt chm bc x n sc c bc sng 0,276m vo catt ca mt t bo quang in th hiu in hm c gi tr tuyt i bng 2 V. Cng thot ca kim loi dng lm catt l:A: 2,5eV. B: 2,0eV.C: 1,5eV. D: 0,5eV. Cu 45:Chiu mt chm bc x n sc c bc sng 0,20m vo mt qa cu bng ng, t c lp v in. Gii hn quang in ca ng l 0,30m. in th cc i m qu cu t c so vi t l:A: 1,34 V.B: 2,07 V.C: 3,12 V. D:4,26 V. Cu 46:Chiu mt chm bc x c bc sng = 0,18m. Vo catt ca mt t bo quang in. Gii hn quang in ca kim loi dng lm catt l 0 = 0,3m. Hiu in th hm trit tiu dng quang in l A: Uh = -1,85 VB: Uh = -2,76 V C: Uh = -3,20 VD: Uh = -4,25 VCu 47:Kim loi dng lm catt ca mt t bo quang in c cng thot l 2,2 eV. Chiu vo catt bc x in t c bc sng. trit tiu dng quang in cn t mt hiu in th hm Uh = UKA = 0,4 V. Gii hn quang in ca kim loi dng lm catt l A: 0,4342 . 10 6 m.B: 0,4824 . 10 6 m.C: 0,5236 . 10 6 m.D: 0,5646 . 10 6 m. Cu 48:Kim loi dng lm catt ca mt t bo quang in c cng thot l 2,2 eV. Chiu vo catt bc x in t c bc sng. trit tiu dng quang in cn t mt hu in th hm Uh = UKA = 0,4 V. tn s ca bc x in t l A: 3,75 . 1014 Hz.B: 4,58 . 1014 Hz.C: 5,83 . 1014 Hz.D: 6,28 . 1014 Hz. Cu 49:Cng thot ca kim loi Na l 2,48 eV. Chiu mt chm bc x c bc sng 0,36m vo t bo quang in c catt lm bng Na. Vn tc ban u cc i ca lectron quang in l: A: 5,84 . 105 m/s. B: 6,24 .105 m/s.C: 5,84 . 106 m/s.C: 6,24 .106 m/s. Cu 50:Cng thot ca kim loi Na l 2,48 eV. Chiu mt chm bc x c bc sng 0,36m vo t bo quang in c catt lm bng Na th cng dng quang in bo ho l 3A. S lectron b bt ra khi catt trong mi giy l A: 1,875 . 1013 B: 2,544 .1013 C: 3,263 . 1012 D: 4,827 .1012

Cu 51:Kim loi lm catt ca t bo quang in c cng thot A= 3,45eV. Khi chiu vo 4 bc x in t c1= 0,25 m, 2= 0,4 m, 3= 0,56 m, 4= 0,2 m th bc x no xy ra hin tng quang inA: 3, 2 B: 1, 4. C: 1,2, 4 D: c 4 bc x trn Cu 52:Mt kim loi lm catt ca t bo quang in c cng thot l A = 3,5eV. Chiu vo cattbc x c bc sng no sau y th gy ra hin tng quang in. Cho h = 6,625.10-34Js ; c = 3.108m/s A:= 3,35m B:= 0,355.10- 7m. C:= 35,5 m D:= 0,355 m Cu 53:Nng lng photn ca mt bc x l 3,3.10-19J .Cho h = 6,6.10-34Js .Tn s ca bc x bngA: 5.1016Hz B: 6.1016Hz C: 5.1014Hz D: 6.1014HzCu 54: Mt ngn n pht ra nh sng n sc c bc sng = 0,6m. Cng sut n l P = 10W. bit h = 6,625.10-34 Js; c = 3.108 m/s; s ph tn m ngn n pht ra trong 10s l: A: N = 3.1020 B: N = 5.1015 C: N = 6.1018 D: N = 2. 1022

Cu 55:Cng dng quang in bo ha trong tbo quang in l I = 0,5mA. Bit e = 1,6.10-19 C; S electron n c anot trong mi pht l? A: N = 3,125.1015 B: N = 5,64.1018 C: N = 2,358.1016 D: N = 1,875.1017 Gv: Nguyn Hng Khnh _ HKP CHNG VI: LNG T NH SNGDi ng: 09166.01248 Email: Khanhcaphe@gmail.com Gio Dc Hng Phc - Ni Khi u c M! Trang 9 Cu 56:Cng dng quang in bo ha l I = 0,32mA. Ly e = 1,6.10-19 C. Bit rng ch c 80% s electron tch ra khi catot c chuyn ng v anot. S electron tch ra khi catot trong thi gian 20s l? A: N = 3,2.1016 B: 6,8.1015 C: N = 5.1016 D: 2,4.1017

Cu 57:Chiu mt bc x in t c bc sng = 0,5m vo mt b mt ca t bo quang in to ra dng bo ho I = 0,32A. Cng sut bc x chiu vo catot l P = 1,5W. Bit h = 6,625.10-34 Js; c = 3.108 m/s; e = 1,6.10-19 C: Hiu sut lng t l? A: H = 46%B: H = 53%C: H = 84%D: H = 67% Cu 58:Gii hn quang inca Xesi l 0,66m,chiuvokim loikim loi nybcx in tcbcsng 0,5m.Lyh= 6,625.10-34 Js; c = 3.108 m/s; ng nng ban u cc i ca electron quang in khi bt ra khi kim loi l? A: W dmax = 2,48.10-19 J B: W dmax = 5,40.10-20 JC: W dmax = 8,25.10-19 JD: W dmax = 9,64.10-20 J Cu 59:Chiu mt chm photon c bc sng vo tm kim loi c gii hn quang in o. Hin tng quang in xy ra ng nng ban u cc i ca cc quang electron l 2,65.10-19 J. Tm vn tc cc i ca cc electron quang in. Bit h = 6,625.10-34 Js; c = 3.108 m/s; m e = 9,1.10-31 kg. A: v max = 7,063.105 mB: v max = 7,63.106 mC: v max = 7,63.105 mD: v max = 5,8.1011 m Cu 60:Mt chm photon c f = 4,57.1014 Hz. Tm s photon c pht ra trong mt s, bit cng sut ca ngun trn l 1W. h = 6,625.10-34 Js; c = 3.108 m/s. A: 3,3.1018 B: 3,03.1018 htC: 4,05.1019 D: 4.1018

Cu 61: Chiu cc bc x c f 1 = 6,5.1014 Hz; f 2 = 5,5.1014 Hz; f 3 = 7.1014 Hz. Vo tm kim loi c gii hn quang in l 0,5m. C bao nhiu bc x c th gy ra hin tng quang in? A: 0B: 1C: 2D: 3 Cu 62:Chiu mt bc x c bc sng = 0,4m vo catot ca mt t bao quang in. Cho cng thot electron ca catot l A = 2eV. t gia anot v catot hiu in th U AK = 5V. ng nng cc i ca cc electron quang in khi n n anot l? A: 4,2eVB: 6,1eVC: 9,8eVD: 12,4eV Cu 63:Ln lt chiu 2 nh sng c bc sng 1 = 0,54 m v 2 = 0,35m vo mt tm kim loi lm catot ca mt t bo quang in ngi ta thy vn tc ban u cc i ca cc quang electron thot ra t catot trng hp dng bc x ny gp i bc x kia. Cng thot electron ca kim loi l? A: 1,05eVB: 1,88eVC: 2,43eVC: 3,965eV Cu 64:Kim loi dng lm catot ca t bo quang in c cng thot electron l 2,5eV. Chiu vo catot bc x c tn s f = 1,5.1015 Hz. ng nng ban u cc i ca cc electron quang in l:A: 3,71eVB: 4,85eVC: 5,25eVD: 7,38eV Cu 65:Catot ca mt tbo quang in lm bng kim loi c gii hn quang in o = 0,5m. Mun c dngquang in trong mch th nh sng kch thch phi c tn s: A: f 2,5.1014 HzB: f 4,2.1014 HzC: f 6.1014 HzD: f 8.1014 Hz Cu 66:Khi chiu ln lt hai bc x in t c bc sng 1 v 2 vi 2 = 2 1 vo mt tm kim loi th t s ng nng ban u cc i ca quang electron bt ra khi kim loi l 9. Gii hn quang in ca kim loi l o.Mi quan h gia bc sng 1 v gii hn quang in o l? A: 1 = 35 0 B: 1 = 57 o C: = 516 o D: 716 o

Cu 67:Chiu nh sng c bc sng = 0,4m vo catot ca mt t bo quang in lm bng kim loi c cngthot A = 2,48eV. Nu hiu in th gia anot v catot l U AK = 4V th ng nng ln nht ca quang electron khi p vo anot l: A: 52,12.10-19 JB: 7,4.10-19 JC: 64.10-19 JD: 45,72.10-19 J Cu 68:Mt tm kim loi c gii hn quang in o = 0,275 m c t c lp v in. Ngi ta chiu sng nbngbc x c bc sng th thy in th cc i ca tm kim loi ny l 2,4V. Bc sng ca nh sng kch thch l. A: 0,2738mB: 0,1795mC: 0,4565mD: 3,259m Cu 69:Khi chiu vo catot ca mt t bo quang in c dng quang in bo ha I bh = 5A v hiu sut quang in H = 0,6%. S photon ti catot trong mi giy l: A: 2,5.1015 B: 3,8.1015 C: 4,3.1015 D: 5,2.1015

Cu 70:Khi chiu vo catot ca mt t bo quang in bng xeri mt bc x , ngi ta thy vn tc caquang electron cc i ti anot l 8.105 m/s nu hiu in th gia anot v catot U AK = 1,2V. Hiu in th hm U h i vi bc x trn l: A: 0,62VB: 1,2VC: 2,4VD: 3,6V Cu 71:Chiu nh sng c bc sng = 0,3m vo catot ca mt t bo quang in, dng quang in bo ha c gi tr 1,8mA. Bit hiu sut lng t ca hin tng quang in H = 1%. Cng sut bc x m catot nhn c l: A: 1,49WB: 0,149WC: 0,745WD: 7,45W Cu 72:Chiu vo catot ca mt t bo quang in mt bc x bc sng vi cng sut P, ta thy cng dng quang in bo ho c gi tr I. Nu tng cng sut bc x ny ln 20% th thy cng dng quang in bo ha tng 10%. Hiu sut lng t s: A: Tng 8,3%B: Gim 8,3%C: Tng 15%D: Gim 15% Cu 73:Chiu mt bc x in t c bc sng 0,5m ln mt kim loi dng lm catot ca mt t bo quang in, thu c dng bo ha c I = 4mA. Cng sut ca bc x in t l P = 2,4W. Hiu sut lng t ca hiu ng quang in l: A: 0,152%B: 0,414%C: 0,634%D: 0,966% Cu 74:Chiu bc x c bc sng = 0,546m ln mt tm kim loi c gii hn quang in o. Dng mn chn tch ra mt chm hp cc electron quang in v cho chng bay vo t trng u theo hng vung gcvi cc ng cm ng t c B = 10-4 T. Bit bn knh cc i ca qu o cc electron l R = 23,32mm. Gii hn quang in l: A: 0,38mB: 0,52mC: 0,69mD: 0,85m Gv: Nguyn Hng Khnh _ HKP CHNG VI: LNG T NH SNGDi ng: 09166.01248 Email: Khanhcaphe@gmail.com Gio Dc Hng Phc - Ni Khi u c M! Trang 10 Cu 75: Chiu ln lt cc bc x c tn s f, 2f, 4f vo catt ca t bo quang in th vn tc ban u cc i ca electron quang in ln lt l v, 2v, kv. Xc nh gi tr k? A:10B: 4 C:6D:8 Cu 76:Mt tm kim loi c gii hn quang in ngoi 0=0,46m. Hin tng quang in ngoi s xy ra vi ngun bc xA: Hng ngoi c cng sut 100W.B: T ngoi c cng sut 0,1W. C: C bc sng 0,64m c cng sut 20W. D: Hng ngoi c cng sut 11W. Cu 77:Catt ca mt t bo quang in lm bng Vnfram c cng thot l 7,2.10-19J, bc sng ca nh sng kch thch l 0,18m. trit tiu hon ton dng quang in phi t vo hai u Ant v Catt mt hiu in th hm l A: 2,37V; B: -2,4VC: 2,57V;D: 2,67V. Cu 78:Chiu mt chm sngt ngoi c bc sngm 25 , 0vo mt l Volfram c cng thot 4,5eV. Bit khi lng lctrn l me = 9,1.10-31 kg. Vn tc ban u cc i ca cc elctrn quang inkhi bn ra khi mt l Vonfram l:A: 4,06.105 m/s B:3,72.105 m/s; C: 4,81.105 m/s;D: 1,24.106 m/s. Cu 79:Chiu bc x c bc sng = 0,552m vi cng sut P = 1,2W vo catot ca mt t bo quang in, dng quang in bo ha c cng Ibh = 2mA. Tnh hiu sut lng t ca hin tng quang in.Cho h = 6,625.10-34Js ; c = 3.108m/s, e = 1,6.10-19C. A:0,65%B:0,375%C:0,55%D:0,425% Cu 80:Chiu bc x c bc sng = 0,4m vo catot ca mt t bo quang in. Cng thot electron ca kim loi lm catot l A = 2eV. Cho h = 6,625.10-34Js v c = 3.108m/s. 1eV = 1,6.10-19J.Gi trin p t vo hai u anot v catot trit tiu dng quang in l A:UAK s - 1,1V.B:UAK s - 1,2V.C:UAK s - 1,4V.D:UAK s 1,5V. Cu 81: Chiu mt bc x = 0,41 m vo katt ca t bo quang in th Ibh = 60mA, cng sut ca ngun l 3,03W. Hiu sut lng t lA: 6%B: 9% C: 18% D: 25% Cu 82:Khi chiu nh sng c bc sngvo katt ca t bo quang in th e bt ra c v0max = v, nu chiu ' = 0,75 th v0max = 2v, bit= 0,4m. Bc sng gii hn ca katt l A:0,42mB: 0,45mC : 0,48mD: 0,51 mCu 83:Chieu bc xacobc songbang 0,489 m vao catot cua tebao quang ien. Biet cong suat cua chum bc xakch thch chieu vao catot la20,35mW. Sophoton ap vao mat catot trong 1 gi ay la: A: 1,3.1018B: 5.1016 C: 4,7.1018D: 1017 Cu 84:Mt qu cu bng kim loi c gii hn quang in l 0,277m c t c lp vi cc vt khc . Chiu vo qu cu nh sng n sc c cL > e.B: cT > c > eL.C: c > cL > eT.D: cL > cT > e. Cu 121:(C - 2009) Mt ngun pht ra nh sng c bc sng 662,5 nm vi cng sut pht sng l 1,5.10-4 W. Ly h = 6,625.10-34 J.s; c = 3.108 m/s. S phtn c ngun pht ra trong 1 s l A: 5.1014.B: 6.1014.C: 4.1014.D: 3.1014. Gv: Nguyn Hng Khnh _ HKP CHNG VI: LNG T NH SNGDi ng: 09166.01248 Email: Khanhcaphe@gmail.com Gio Dc Hng Phc - Ni Khi u c M! Trang 13 Cu 122:(H 2009) Cng thot lectron ca mt kim loi l 7,64.10-19J. Chiu ln lt vo b mt tm kim loi ny cc bc x c bc sng l 1 = 0,18 m, 2 = 0,21 m v 3 = 0,35 m. Ly h=6,625.10-34 J.s, c = 3.108 m/s. Bc x no gy c hin tng quang in i vi kim loi ? A: Hai bc x (1 v 2).B: Khng c bc x no trong ba bc x trn. C: C ba bc x (1, 2 v 3). D: Ch c bc x 1. Cu 123:(H 2009) Chiu ng thi hai bc x c bc sng 0,452 m v 0,243 m vo catt ca mt t bo quang in. Kim loi lm catt c gii hn quang in l 0,5 m. Ly h = 6,625. 10-34 J.s, c = 3.108 m/s v me = 9,1.10-31 kg. Vn tc ban u cc i ca cc lectron quang in bng A: 2,29.104 m/s.B: 9,24.103 m/sC: 9,61.105 m/s D: 1,34.106 m/s Cu 124:(H - 2010)Mt kim loi c cng thot lectron l 7,2.10-19 J. Chiu ln lt vo kim loi ny cc bc x c bc sng 1 = 0,18 m, 2 = 0,21 m, 3 = 0,32 m v = 0,35 m. Nhng bc x c th gy ra hin tng quang in kim loi ny c bc sng l A: 1, 2 v 3.B: 1 v 2.C: 2, 3 v 4.D: 3 v 4. Cu 125:(H - 2010)Mt ngun sng ch pht ra nh sng n sc c tn s 5.1014Hz. Cng sut bc x in t ca ngun l 10 W. S phtn m ngun pht ra trong mt giy xp x bng A: 3,02.1019.B: 0,33.1019.C: 3,02.1020.D: 3,24.1019. Cu 126:(H - 2010)Theo thuyt lng t nh sng, pht biu no di y l sai? A: nh sng c to thnh bi cc ht gi l phtn. B: Nng lng ca cc phtn nh sng l nh nhau, khng ph thuc tn s ca nh sng. C: Trong chn khng, cc phtn bay dc theo tia sng vi tc c = 3.108 m/s. D: Phn t, nguyn t pht x hay hp th nh sng, cng c ngha l chng pht x hay hp th phtn Cu 127:(H -2011)Cng thot lectron ca mt kim loi l A = 1,88 eV. Gii hn quang in ca kim loi ny c gi tr lA: 1057 nm. B: 220 nm. C: 661 nm. D: 550 nm. Cu 128:(H -2011)Hin tng quang in ngoi l hin tng lectron b bt ra khi tm kim loi khiA: chiu vo tm kim loi ny mt bc x in t c bc sng thch hp.B: cho dng in chy qua tm kim loi ny.C: tm kim loi ny b nung nng bi mt ngun nhit.D: chiu vo tm kim loi ny mt chm ht nhn heli. Gv: Nguyn Hng Khnh _ HKP CHNG VI: LNG T NH SNGDi ng: 09166.01248 Email: Khanhcaphe@gmail.com Gio Dc Hng Phc - Ni Khi u c M! Trang 14 CHNG VI: LNG T NH SNG BI 3: TIA X I.PHNG PHP nh ngha Tia X l sng in t c bc sng t10-8 n 10-12 m Ngun phtDomy X quangpht ra. Tc dng-Kh nng nng m xuyn cao -Lm en knh nh -Lm pht quang mt s cht -Gy ra hin tng quang in ngoi hu ht cc kim loi -Lm in ha khng kh -Tc dng sinh l, hy dit t bo ng dng-Chun on hnh nh trong y hc -Pht hin khuyt tt trong cc sn phm c -Kim tra hnh l trong lnh vc hng khng -Nghin cu thnh phn cu trc vt rn Cc cng thc bi tp Ct1:q.U AK = 12 mV2 max = hf max = hc minTrong : *q.U AK = 12 mV2 max = hf max = hc minTrong : * Cng dng in trong ng Rnghen: I = n e.e * Tng ng nng ca e khi va chm i ca tt trong 1s: E W d = n e.W d = Ie .U AK.q * Cng thc xc nh hiu sut ng Cu - lit - gi: H =EcEW d .Vi Ee l tng nng lng tia X Ee = EW d.H EQ =EW d( 1 - H) -q l ln in tch ca electron = 1,6. 10-19 C - U AK l hiu in th gia anot v catot ca my( V ) - m l khi lng cc electron; m = 9,1.10-31 kg - V max l vn tc cc i ca cc khi p vo i catot ( m/s) -h l hng s plank - f max l tn s ln nht ca bc x pht ra (Hz) - min l bc sng ca bc x ( m) II. BI TP MU V d 1: Mt ng rnghen cin p gia ant v katt l 2000V, cho h = 6,625.10-34Js, c = 3.108m/s. Bc sng ngn nht ca tia rnghen m ng c th pht ra l A. 4,68.10-10mB. 5,25.10-10mC. 3.46.10-10m D. 6,21.10-10m Hng dn: [ ]p n D Gv: Nguyn Hng Khnh _ HKP CHNG VI: LNG T NH SNGDi ng: 09166.01248 Email: Khanhcaphe@gmail.com Gio Dc Hng Phc - Ni Khi u c M! Trang 15 Ta c: U.q = hc min min =h.cU.q=6,625.10-34 .3.108 2000.1,6.10-19 = 6,21.10-10 m Chn p n DV d 2: bc sng ngn nht tia X pht ra l 0,05nm hiu in th hot ng ca ng Culitgi t nht phi l A. 24,84KVB. 25KVC. 10KVD. 30KV Hng dn: [ ]p n A

Ta c: U.q = hc min U = h.cq. min= 6,625.10-34 .3.108 1,6.10-19 . 0,05.10-9 = 24843 V V d 3: Tn s ln nht trong chm bc x pht ra t ng Rnghen l 4.1018 Hz. Choh = 6,625.10-34 Js, e = 1,6.10-19 C. Hiu in th gia hai cc ca ng l A. 16,4 kVB. 16,56 kV C. 16,6 kV D. 16,7 V Hng dn: [ ]p n B Ta c:h.f max = U.q U = h.f maxq=6,625.10-34 . 4.1018 1,6.10-19 = 16,56.103 = 15,56kV V d 4: Mt ng Culigio mi giy c 2.1018 electron chy qua ng. Xc nh cng dng in chy trong ng?

A. 3,2 AB. 3,2mAC. 0,32 AD. 32.10-3 A Hng dn: [ ]p n A I = n e.q =2.1018 . 1,6.10-19 = 3,2.10-1 = 0,32 A Gv: Nguyn Hng Khnh _ HKP CHNG VI: LNG T NH SNGDi ng: 09166.01248 Email: Khanhcaphe@gmail.com Gio Dc Hng Phc - Ni Khi u c M! Trang 16 Vd 5:Mt my X quang c duy tr bi hiu in th20kV, cng dng in chy trong ng l 5mA.i m cc ca my c lm mt bngnc. Bit nc c nhit dung C = 4200 J/kg/,nc u vo c nhit l 25o C v ra l 35o C, hiu sut ca my l 5%. Hy xc nh lu lng nc qua my. ( D H 2O= 1g/ml) A.2 ml/sB. 2,26 ml/sC. 3ml/sD. 4ml/s Hng dn: [ ] p n B - Nng lng ca 1 e khi va chm i catot l: W d = U.q - S e n i ca tt trong 1 s l: I = n e.e n e= Ie

- Tng ng nng ca ekhi va chm i catot l: E W d = n e. W d =I.U.qe

- Nhit nng sinh ra l: Q = 0,95. E W d= 0.95. I.U.qe= 0,95 UI Ta li c: Q = m.C. At - Suy ra: Khi lng nc c ung nng trong 1s: m = QC. At= 0,95.I.UC. At = 0,95 5.10-3 . 20.103 4200.10= 2,26g - Lu lng nc qua ng l: V = mD=2,261= 2,26 ml/s

III. BI TP THC HNH

Bi 1:Tm pht biu sai v tia X A: Tia X l sng in t B: Tia X khng b lch khi i qua t trng C: Tia X c kh nng gy ra hin tng quang in hu ht cc kim loi D: Tia X c bc sng ln hn tia Bi 2:Tm pht biu sai khi ni v tia X A.Tia X do ngun in c hiu in th ln phng ra B.Tia X c kh nng m xuyn qua ming ba nhm dy c vi mm C.Tia X gy ra hin tng ion ha cht kh D.Tia X c bc sng ln hn tia gama Bi 3:Tm pht biu sai v tia X? A:Tia X c nhiu ng dng trong y hc nh chiu, chp in B:Tia X c kh nng lm pht quang nhiu cht C: Tia X l sng in t c bc sng nm trong khong 10-11 m n 10-8 m. D:Tia X b lch trong in t trngBi 4:Chn cu ng? Tia X c bc sng. A:Ln hn tia hng ngoiB: Ln hn tia t ngoi C: Nh hn tia t ngoiD: Khng th o c Bi 5:Hiu in th gia anot v catot ca mt Culitgio l 10 kV. Tnh ng nng cc i ca cc electron khi p vo anot. Cho bit khi lng v in tch ca electron m e = 9,1.10-31 kg; e = 1,6.10-19 C. A: 2,6.10-15 JB: 1,98.10-15 JC: 2.10-20 JD: 1,6.10-15 J Bi 6:Hiu in th gia anot v catot ca mt Culitgio l 10 kV. Tnh tc cc i ca cc electron khi p vo anot. Cho bit khi lng v in tch ca electron m e = 9,1.10-31 kg; e = 1,6.10-19 C. A:5,9.107 m/sB: 59.105 m/s C: 5,9.105 m/s D: 5,9.104 m/s Bi 7:Cng dng in qua ng tia X l I = 2mA. Bit e = 1,6.10-19 C; s electron p vo i catot trong mi pht l? A: N = 7,5.1017 B: N = 1,25.1016 C: N = 5,3.1018 D: 2,4.1015 Bi 8:MtngtiaXchiuinthgiaanotvcatotl20kV.Tmbcsngnhnhtmbcxcthphtra?Bith= 6,625.10-34 Js; e = 1,6.10-19 C;c = 3.108 m/s. A: 0,62pmB: 0,62mC: 6,2pmD: p n khc Bi 9:Mt ng tia X c hiu in th gia anot v catot l 20kV. Tm Tn s ln nht bc x c th pht ra? Bit h = 6,625.10-34 Js; e = 1,6.10-19 C;c = 3.108 m/s. A: 4,84GHzB: 4,8.1018 HzC: 4,83.1018 HzD: p n khcBi 10: Hiu in th gia anot v catot ca ng tia X l U = 20KV. B qua ng nng ban u ca ccelectron bt ra khi catot. Cho e = 1,6.10-19 C; m e = 9,1.10-31 kg. Vn tc ca electron khi va ti i catot l? A: v = 4,213.106 m/sB: v = 2,819.105 m/sC: v = 8,386.107 m/sD: v = 5,213.106 m/sBi 11: Hiu in th gia hai in cc ca ng tia X lU = 18kV; e = 1,6.10-19 C; m e = 9,1.10-31 kg . B qua ng nng lc electron bt ra khi catot. Vn tc lc p vo i catot? A: v = 5,32.106 m/sB: v = 2,18.105 m/sC: v = 7,96.107 m/sD: v = 3,45.107 m/s Gv: Nguyn Hng Khnh _ HKP CHNG VI: LNG T NH SNGDi ng: 09166.01248 Email: Khanhcaphe@gmail.com Gio Dc Hng Phc - Ni Khi u c M! Trang 17 Bi 12: Tn s ln nht trong chm bc x pht ra t ng tia X l 3.1018 Hz. Ly e = 1,6.10-19 C; h = 6,625.10-34 Js; Hiu in th gia hai u in cc ca ng l? A: U = 9,3kVB: 12,4KVC: U = 11,5kVD: 14,5kV Bi 13: Hiu in th gia anot v catot ca mt tia X l 2.104 V. B qua ng nng ban u ca electron khi va bt ra khi catot. Bit e = 1,6.10-19 C; c = 3.108 m/s; h = 6,625.10-34 Js. Bc sng nh nht ca chm tia X do ng pht ra l? A: = 0,62 Ao B: min = 0,52 Ao C: min = 0,82 Ao D: min = 0,65 Ao

Bi 14: Hiu in th gia anot v catot ca mt tia X l 2.104 V. B qua ng nng ban u ca electron khi va bt ra khi catot. Bit e = 1,6.10-19 C; c = 3.108 m/s; h = 6,625.10-34 Js. Tn s ln nht ca chm tia X do ng pht ra l? A: f max = 2,15.1017 Hz B: f max = 5,43.1016 HzC: f max = 8,2.1019 HzD: f max = 4,83.1018 Hz Bi 15: Vn tc ca electron khi p vo i catot ca ng tia X l 8. 107 m/s. Bit e = 1,6.10-19 C; m e = 9,1.10-31 kg; vn tc ti i catot gim 6.106 m/s th hiu in th gia hai cc ca ng phi A: Gim 5200VB: Tng 2628VC: Gim 2628VD: Gim 3548VBi 16: Hiu in th gia hai in cc ca ng tia X l 10kV. B qua ng nng ca electron lc bt ra khi catot. Ly e = 1,6.10-19 C; h = 6,625.10-34 Js;c = 3.108 m/s; Bc sng ngn nht trong chm tia X l? A: min = 9,5.10-11 mB: min = 8,4.10-10 mC: min = 5,8.10-10 m D: min = 12,4.10-11 m Bi 17: Nuhiu in thUgia haicc cangtiaXgim1000Vthvn tc electron tiicatotgim 5.106 m/s.Vn tcca electron ti i catot lc u l bao nhiu? Bit e = 1,6.10-19 C; m e = 9,1.10-31 kg. A: v = 3,75.107 m/sB: v = 8,26.106 m/sC: v = 1,48.107 m/sD: v = 5,64.106 m/sBi 18: Tn s ln nht ca tia X bc x l f max = 2,15.1018 Hz. Tm vn tc cc i ca cc electron khi n va chm vi i catot? A: 5,5.107 m/sB: 5,6.107 m/sC: 7.107 m/sD: 0,56.107 m/sBi 19: Hiu in th gia anot v catot l 30kV, tm tn s cc i ca tia X c th pht ra Bit h = 6,625.10-34 Js; e = 1,6.10-19 C; c = 3.108 m/s. A: 7.1018 HzB: 8.1018 HzC: 9.1018 HzD: 7,2.1018 HBi 20: Cng dng quang in qua ng tia X l I = 5mA. Bit e = 1,6.10-19 C. S electron ti p vo i catot trong 1 pht l: A: n = 1,775.1018 B: n = 1,885.1018 C: n = 1,875.1018 D: n = 1,975.1018 Bi 21: Cng dng quang in qua ng tia X l I = 5mA, hiu in th trong ng l 20kV v hiu sut chuyn i thnh tia X l 5%. Tm nng lng photon do my pht ra trong mt pht? Bit e = 1,6.10-19 C; m e = 9,1.10-31 kg. A: 10JB: 15JC: 5JD: 20J Bi 22: Chm tia Rghen pht ra t ng Cu-lt-gi , ngi ta thy c nhng tia c tn s ln nht v bng 19ax5.10mf C= .Tnh hiu in th cc i gia hai cc ca ng :A: 20,7kVB: 207kVC: 2,07kVD: 0,207kV Bi 23: Mt ng pht ra tia Rghen , pht ra bc x c bc sng nh nht l 5.10-10m .Tnh nng lng ca photn tng ng : A: 3975.10-19JB: 3,975.10-19JC: 9375.10-19JD: 9,375.10-19J Bi 24: Mt ng pht ra tia Rghen .Khi ng hot ng th dng in qua ng l I = 2mA. Tnh s in t p vo i m cc trong mi giy : A: 125.1013B: 125.1014 C: 215.1014 D: 215.1013 Bi 25: Mt ng pht ra tia Rghen .Cng dng in qua ng l 16m .in tch electrn | e | = 1,6.10-19C .S electrn p vo i m cc trong mi giy : A: 1013B: 1015C: 1014D: 1016 Bi 26: Trong mt ng Cu-lt-gi ngi ta to ra mt hiu in th khng i gia hai cc.Trong mt pht ngi ta m c 6.1018 in t p vo ant. Tnh cng dng in qua ng Cu-lt-gi: A: 16mAB: 1,6A C: 1,6mAD: 16A Bi 27: Trong mt ng Cu-lt-gi , bit hiu in th cc i gia ant v catt l Uo = 2.106V. Hy tnh bc sng nh nht minca tia Rghen do ng pht ra : A: 0,62mmB: 0,62.10-6mC: 0,62.10-9mD: 0,62.10-12m Bi 28: in p cc i gia ant v catt ca mt ng Cu-lt-gi l Uo = 25 kV. Coi vn tc ban u ca chm lectrn (lectron) pht ra t catt bng khng. Bit hng s Plng h = 6,625.10-34J.s , in tch nguyn t bng 1,6.10-19C. Tn s ln nht ca tia Rnghen do ng ny c th pht ra l: A: 6,038.1018 Hz B: 60,380.1015 Hz. C: 6,038.1015 Hz. D: 60,380.1018 Hz. Bi 29: Mt kim loi c gii hn quang in l 0,3m .Bit h = 6,625.10-34Js ; c = 3.108m/s .Cng thot ca lectron ra khi kim loi l A: 6,625.10-19J.B: 6,625.10-25J C: 6,625.10-49JD: 5,9625.10-32J Bi 30: ng Cu-lt-gi hot ng vi hiu in th cc i 50(kV). Bc sng nh nht ca tia X m ng c th to ra l:(ly gn ng). Cho h = 6,625.10-34J.s, c = 3.108(m/s).A: 0,25(A0)B: 0,75(A0).C: 2(A0).D: 0,5(A0). Bi 31: Mt ng Cu-lt-gi pht ra bc x c bc sng ngn nht l 2,65.10-11m .B qua ng nng ban u ca cc lectron khi thot ra khi b mt catt .Bit h = 6,625.10-34Js , e = 1,6.10-19C .in p cc i gia hai cc ca ng l : A: 46875V. B: 4687,5V C: 15625VD: 1562,5V Bi 32: in p cc i gia antvcatt ca mt ng Cu-lt-gi l Uo = 18200V .B qua ng nngca lectronkhi bt khicatt .Tnh bc sng ngn nht ca tia X do ng pht ra .Cho h = 6,625.10-34Js ; c = 3.108m/s ; |e| = 1,6.10-19C : A: 68pm. B: 6,8pmC: 34pm D: 3,4pm Gv: Nguyn Hng Khnh _ HKP CHNG VI: LNG T NH SNGDi ng: 09166.01248 Email: Khanhcaphe@gmail.com Gio Dc Hng Phc - Ni Khi u c M! Trang 18 Bi 33: Hiu in th hiu dng gia ant v catt ca mt ng Cu-lt-gi l 10kV. B qua ng nng ca cc lectron khi bt khi catt .Tc cc i ca cc lectron khi p vo ant A: 70000m/sB: 50000m/sC: 60000m/sD: 80000m/sBi 34: Mt ng Cu-lt-gi pht ra bc x c bc sng ngn nht l 6,21.10-11 m. Bit ln in tch lectrn (lectron), tc sng trong chn khng v hng s Plng ln lt l 1,6.10-19 C, 3.108 m/s v 6,625.10-34 J.s .B qua ng nng ban u ca lectrn. in p cc i gia ant v catt ca ng l:A: 2,00 kV. B: 20,00 kVC: 2,15 kV. D: 21,15 kV. Bi 35: in p cc i gia ant v catt ca mt ng Cu-lt-gi l 18,75 kV. Bit ln in tch lectrn (lectron), tc sng trong chn khng v hng s Plng ln lt l 1,6.10-19C ; 3.108 m/s v 6,625.10-34J.s. B qua ng nng ban u ca lectrn. Bc sng nh nht ca tia Rnghen do ng pht ra l: A: 0,4625.10-9 m. B: 0,5625.10-10 m. C: 0,6625.10-9 m. D: 0,6625.10-10 m Bi 36: Hiu in th cc i gia hai cc ca ng Cu-lt-gi l 15kV. Gi s electrn bt ra t cathode c vn tc ban u bng khng th bc sng ngn nht ca tia X m ng c th pht ra l bao nhiu ? A: 75,5.10-12mB: 82,8.10-12mC: 75,5.10-10mD: 82,8.10-10m Bi 37: Mt ng Cu-lt-gi pht ra bc x c bc sng nh nht l 5A0. Cho in tch electrn l 1,6.10-19C, hng s Planck l 6,625.10-34Js, vn tc ca nh sng trong chn khng l 3.108 m/s. Hiu in th cc i Uo gia ant v catt l bao nhiu ? A: 2500 VB: 2485 V. C: 1600 VD: 3750 V Bi 38: Mt ng Rnghen hot ng hiu in th khng i 5kV th c th pht ra tia X c bc sng ngn nht l A: ~2,48.10-13mB: ~2,48.10-9mC: ~2,48.10-10mD: ~2,48.10-11m Bi 39: Mt ng Rnghen c hiu in th gia ant v catt l 25kV, cho h = 6,625.10-34Js, c = 3.108m/s. Bc sng ngn nht ca tia Rnghen m ng c th pht ra l: A: 4,969.10-10mB: 4,969nmC: 0,4969A0D: 0,4969m Bi 40: Hiu in th gia anot v catot ca mt ng tia X l U = 18kV, cng dng in qua ng l I = 5mA. B qua ng nng lc e lectron bt ra khi catot. Bit rng c 95% s electron n catot ch c tc dng nhit. Nhit lng lm nng i catot trong mt pht l? A: Q = 3260JB: Q = 5130JC: Q = 8420JD: Q = 1425J Bi 41: Hiu in th gia hai cc ca ng tia X l U = 2,1KV v cng dng in qua ng l I = 0,8mA. B qua ng nng electron lc bt ra khi catot . Cho rng ton b nng lng ca electron ti i catot u chuyn thnh nhit. lm ngui i catot, ta cho dng nc chy qua, nhit li ra cao hn li vo 10o C: Bit nhit dung ring ca nc l C = 4200J/kg. . Khi lng n. c chy qua i catot trong mi giy l? A: m = 0,04g/sB: m = 2g/8sC: m = 15g/sD: m = 0,5g/s Bi 42: (C 2007): Mt ng Rnghen pht ra bc x c bc sng ngn nht l 6,21.10 11 m. Bit ln in tch lectrn (lectron), vn tc nh sng trongchnkhngvhngs Plng ln lt l1,6.10-19C; 3.108m/s; 6,625.10-34 J.s.B qua ng nngbanu ca lectrn. Hiu in th gia ant v catt ca ng l A: 2,00 kV.B: 2,15 kV.C: 20,00 kV.D: 21,15 kV.Bi 43: (H 2007): Hiu in th gia ant v catt ca mt ng Rnghen l 18,75 kV. Bit ln in tch lectrn (lectron), vn tc nh sng trongchnkhngv hngs Plng ln lt l 1,6.10-19 C, 3.108m/sv 6,625.10-34 J.s. B qua ng nngbanu ca lectrn. Bc sng nh nht ca tia Rnghen do ng pht ra lA: 0,4625.10-9 m.B: 0,6625.10-10 m.C: 0,5625.10-10 m.D: 0,6625.10-9 m.Bi 44: (H 2008):Hiu in thgiaantvcattcamtng Rnghenl U=25kV. Coivn tcbanucachmlectrn (lectron) pht ra t catt bng khng. Bit hng s Plng h = 6,625.10-34J.s, in tch nguyn t bng 1,6.10-19C: Tn s ln nht ca tia Rnghen do ng ny c th pht ra l A: 60,380.1018Hz.B: 6,038.1015Hz.C: 60,380.1015Hz.D: 6,038.1018Hz. CHNG VI: LNG T NH SNG BI 4: MU NGUYN T BOR - QUANG PH HIDRO I. PHNG PHP 1.TIN V TRNG THI DNG -Nguyn t ch tn ti trong mt s trng thi c nng lng xc nh gi l cc trng thi dng. Khi trong cc trng thi dng th nguyn t khng bc x -Trong cc trng thi dng ca nguyn t, electron ch chuyn ng xung quanh ht nhn trn nhng qu o c bn knh hon ton xc nh gi l cc qu o dng. i vi nguyn t Hidro bn knh qu o dng tng t l vi bnh phng ca cc s nguyn lin tip:R n = n2 r ovi r o = 5,3.10-11 m. Trong :R n l bn knh qu o th n n l qu o th n r o l bn knh c bn r o 4r o 9r o 16r o 25r o 36r o Gv: Nguyn Hng Khnh _ HKP CHNG VI: LNG T NH SNGDi ng: 09166.01248 Email: Khanhcaphe@gmail.com Gio Dc Hng Phc - Ni Khi u c M! Trang 19 KLMNOP

2.TIN V HP TH V BC X NNG LNG. -Khi nguyn t chyn t trng thi dng c nng lng ( E n ) sang trng thi dng c nng lng thp hn ( E m ) th n pht ra mt pho ton c nng lng ng bng hiu: E n - E m - c = hf nm= E n - E m n m c = E n - E m

-Ngc li,nu nguynt ang trong trng thi dng c nng lngE m m hp th mt photon c nng lng ng bng hiu E n- E mth n chuyn ln trng thi dng c nnglng E n. c = hf nm= E n - E m = hc n m c = E n - E m

- T tin trn: Nu mt cht hp th c nh sng c bc sng no th n cng c th pht ra nh sng y. 3.QUANG PH VCH HIDRO. -Mc nng lng trng thi n :E n =- 13,6 eVn2 vi ( n = 1,2,3)- e lectron b ion ha khi: E = 0.- E = E 12 + E 23 hf 13 = hf 12 + hf 23 f 13 = f 12 + f 23

hc = hc 1 + hc 2 1 = 1 1 + 1 2 = 1 2 1 + 2 -Cng thc xc nh tng s bc x c th pht ra khi e trng thi nng lngth n:

S bx = ( n - 1) + ( n- 2) + + 2 + 1Cn2 | o o12 3 4 56 n 6 KL MN OP DyPachen:honton trong vng hng ngoi DyLai-man:honton trong vng t ngoi Dy Ban- me: nm trong vng kh kin v t ngoi II. BI TP MU V d 1: nguyn t hidro, qu o no sau y c bn knh ln nht so vi bn knh cc qu o cn li? A. OB. NC.LD. P Hng dn: [ ] p n D Ta c: R n = n2 .r o ( trong r o l bn knh qu o c bn: r o = 5,3.10-11 m) Qu o O c n = 5. Qu o Nc: n = 4 Qu o L c n = 2 Qu o P c n = 6. Trong cc qu o trn, qu o P c n ln nht ln bn knh l ln nht. Gv: Nguyn Hng Khnh _ HKP CHNG VI: LNG T NH SNGDi ng: 09166.01248 Email: Khanhcaphe@gmail.com Gio Dc Hng Phc - Ni Khi u c M! Trang 20 Vd 2: Xc nh bn knh qu o dng M ca nguyn t, bit bn knh qu oK l R K = 5,3.10-11 m. A. 4,77 Ao B. 4,77pmC. 4,77 nmD. 5,3 Ao Hng dn: [ ]p n A R K= r o= 5,3.10-11 m. R n= n2 .r o

Qu o M n = 3r o = 5,3.10-11 m R M = 32 .5,3.10-11 = 4,77.10-10 m. V d 3: e lec tron ang qu o n cha r th chuyn v qu o L, v thy rng bn knh qu o gim i 4 ln. Hi ban u electron ang qu o no? A. OB. MC. ND. P Hng dn: [ ] p n C Bn knh qu o L:R 2 = 22 .r o = 4.r o

Bn knh qu o n: R n = n2 .r o

Theo bi: R nR 2 = n2 4= 4Suy ra: n = 4, Vy electron ban u ang qu o N V d 4: Nng lng ca lectron trong nguyn t hyr c tnh theo cng thc: En = --13,6n2 eV, A l hng s dng, n = 1,2,3, Xc nh nng lng qu o dngL. A. 5,44.10-20 J B. 5,44eV C. 5,44MeV D. 3,4.eV Hng dn: [ ] p n D Qu o dng th L ng vi n = 2 E L= -13,622 = - 3,4 eV. V d 5: Nng lng ca lectron trong nguyn t hyr c tnh theo cng thc: En = --13,6n2 eV, A l hng s dng, n = 1,2,3, Hi khi electron chuyn t qu o L v qu o K th n pht ra mt photon c bc sng l bao nhiu? A. 0,2228 m.B. 0,2818 m. C.0,1281 m.D. 0,1218 m. Hng dn: [ ] p n D Khi e chuyn t qu o L v qu o K th n pht ra mt photon: hc= E 2- E 1. Suy ra: = hcE 2 - E 1 =1,9875.10-25

(- 13,64 + 13,6 .1,6.10-19 =0,1218 m. V d 6: Trong quang phca nguyn t hiro, ba vch u tin trong dy Lai man c bc sng 1 2 = 121,6 nm; 13= 102,6 nm; 14 = 97,3 nm. Bc sng ca vch u tin trong dy Ban m e = 9,1.10-31 kg v vch u tin trong dy pasen lA. 686,6 nm v 447,4 nm.B. 660,3 nm v 440,2 nm. C. 624,6nm v 422,5 nm. D. 656,6 nm v 486,9 nm. Hng dn: [ ]p n D K L M N 1 2 3 4 12 13 14 23 24

23= 13. 12 12 - 13= 121,6.102,6121,6 - 102,6= 656,64 nm 24 = 14. 12 12 - 14=97,3.121,6121,6 - 97,3= 486,9 nm III.BI TP THC HNH

Cu 1: Mu nguyn t Bo khc mu nguyn t R-d-pho im no? A:M hnh nguyn t c ht nhn.C: Hnh dng qu o ca cc lectron. B:Biu thc ca lc ht gia ht nhn v lectron.D: Trng thi c nng lng n nh. Cu 2: Ni dung ca tin v s bc x v hp th nng lng ca nguyn t c phn nh trong cu no di y? Gv: Nguyn Hng Khnh _ HKP CHNG VI: LNG T NH SNGDi ng: 09166.01248 Email: Khanhcaphe@gmail.com Gio Dc Hng Phc - Ni Khi u c M! Trang 21 A:Nguyn t pht ra mt phtn mi ln bc x nh sng. B:Nguyn t thu nhn mt phtn mi ln hp th nh sng. C:Nguyn t pht ra nh sng no th c th hp th nh sng . D:Nguyn t ch c th chuyn gia cc trng thi dng. Mi ln chuyn, n bc x hay hp th mt phtn c nng lng ng bng chnh lch nng lng gia hai trng thi . Cu 3: Qu o ca lectron trong nguyn t hir ng vi s lng t n c bn knh. A: t l thun vi n.B: t l nghch vi n. C: t l thun vi n2. D: t l nghch vi n2. Cu 4: Pht biu no sau y l ng? A: Dy Laiman nm trong vng t ngoi. B: Dy Laiman nm trong vng nh sng nhn thy. C: Dy Laiman nm trong vng hng ngoi. D: Dy Laiman mt phn trong vng nh sng nhn thy v mt phn trong vng t ngoi. Cu 5: Pht biu no sau y l khng ng? A: Dy Banme nm trong vng t ngoi. B: Dy Banme nm trong vng nh sng nhn thy. C: Dy Banme nm trong vng hng ngoi. D: Dy Banme nm mt phn trong vng nh sng nhn thy v mt phn trong vng t ngoi. Cu 6: Pht biu no sau y l ng khi ni v mu nguyn t Bo? A: Nguyn t bc x khi chuyn t trng thi c bn ln trng thi kch thch. B: Trong cc trng thi dng, ng nng ca lectron trong nguyn t bng khng. C: Khi trng thi c bn, nguyn t c nng lng cao nht. D: Trng thi kch thch c nng lng cng cao th bn knh qu o ca lectron cng ln Cu 7: Pht biu no sau y l sai, khi ni v mu nguyn t Bo? A: Trong trng thi dng, nguyn t khng bc x. B: Trong trng thi dng, nguyn t c bc x C: Khi nguyn t chuyn t trng thi dng c nng lng En sang trng thi dng c nlng Em (Em Em) th nguyn t pht ra 1 phtn c nng lng nh hn hoc bng En Em.Cu 20: i i u u n n o o s sa au u y y l l sai khi ni v s to thnh cc vch trong dy Pasen ca quang ph nguyn t hir?A: Trong dy Pasen ch c ba vch.B: Cc vch trong dy Pasen c to thnh khi cc lectrn chuyn t cc qy o t bn ngoi v qy o M.C: Cc vch trong dy Pasen tng ng vi cc tn s khc nhau.D: Vch c bc sng di nht ng vi s chuyn ca letrn t qy o N v qy o M.Cu 21:Hy xc nh trng thi kch thch cao nht ca cc nguyn t hir trong trng hp ngi ta ch thu c 6 vch quang ph pht x ca nguyn t hir. A: Trng thi L.B: Trng thi M.C: Trng thi N.D: Trng thi O. Cu 22:Cc vch quang ph nm trong vng t ngoi ca nguyn t hir thuc v dy: A: Lyman.B: Banme. C: Pasen. D: Lyman hoc Banme. Cu 23:Nguyn t hir mc nng lng kch thch O, khi chuyn xung mc nng lng thp s c kh nng pht ra s vch ph ti a thuc dy Banme l: A: 3 vch.B: 5 vch.C: 6 vch.D: 7 vch. Cu 24:Cc vch thuc dy Banme ng vi s chuyn ca lectron t cc qu o ngoi v A: Qu o K.B: Qu o L.C: Qu o M.D: Qu o O. Cu 25:Mt nguyn t hir ang trng thi c bn, hp th mt phtn c nng lng o v chuyn ln trng thi dng ng vi qu o N ca lectron. T trng thi ny, nguyn t chuyn v cc trng thi dng c mc nng lng thp hn th c th pht ra phtn c nng lng ln nht l :A: 3o.B: 2o.C: 4o.D: o Cu 26:Chm nguyn t H ang trng thi c bn, b kch thchpht sng th chng c th pht ra ti a 3 vch quang ph. Khi b kch thch electron trong nguyn t H chuyn sang qu o : A:M.B:L C:OD:N Cu 27:Khi mt electron ang trng thi c bn b kch thch hp th mt photon chuyn ln qu o L. Khi electron chuyn vo qu o bn trong th s bc x ti a m n c th pht ra l? A: 1B: 3C: 6D: 10 Cu 28:Nu nguyn t hydro b kch thch sao cho electron chuyn ln qu o N. S bc x ti a m nguyn t Hidro c th pht ra khi cc electron i vo bn trong l? A: 3B: 4C: 5D: 6 Cu 29:Nu nguyn t hydro b kch thch sao cho electron chuyn ln qu o N. S bc x ti a m nguyn t Hidro c th pht ra thuc dy Pasen l l? A: 1B: 3C: 5D: 7Cu 30:Nu nguyn t hydro b kch thch sao cho e chuyn ln qu o N th nguyn t c th pht ra ti a bao nhiu bc x trong dy Banme A: 1B: 2C: 3D: 4 Cu 31: Mt Electron ang chuyn ng trn qu o c bn knh nguyn t 8,48Ao . l qu o? A: K B: LC: MD: NCu 32:Electron ca nguyn t hidro ang chuyn ng trn qu o dng c bn knh l mt trong cc s liu sau y: 4,47Ao ; 5,3 Ao ; 2,12 Ao . l qu oA: KB: LC: MD: NCu 33:Cc vch quang ph ca nguyn t hidro trong min hng ngoi c c l do electron chuyn t cc qu o ngoi v qu o A: KB: LC: MD: N Cu 34:Bn knh qu o dng N ca nguyn t hidro l A: r = 8,48Ao B: r = 4,77Ao C: r = 13,25Ao D: r = 2,12Ao

Cu 35:Chiu di 1,484nm A:L bn knh qu o L ca nguyn t hidroC: L bn knh ca qu o M ca nguyn t hidro B:L bn knh qu o N ca nguyn t hidroD: Khng phi l bn knh qu o dng ca nguyn t hidro Cu 36:Tm pht biu ng v mu nguyn t Bor. A: 1 31 = 1 12 . 1 23 B: 1 31 = 1 12 - 1 23C: 1 31 = 1 12 + 1 23D: 1 31 = 1 12 : 1 23 Gv: Nguyn Hng Khnh _ HKP CHNG VI: LNG T NH SNGDi ng: 09166.01248 Email: Khanhcaphe@gmail.com Gio Dc Hng Phc - Ni Khi u c M! Trang 23 Cu 37:Hy xc nh trng thi kch thch cao nht ca cc nguyn t hir trong trng hp ngi ta ch thu c 10 vch quang ph pht x ca nguyn t hir. A: Trng thi OB: Trng thi N. C: Trng thi L. D: Trng thi M. Cu 38: Nng lng cc trng thi dng ca nguyn t hidro cho bi E n =-13,6n2 eV. Vi n= 1,2,3ng vi cc qu o K,L,M Bit h = 6,625.10-34 Js; c = 3.108 m/s. Nguyn t hidro ang thi c bn th nhnc mt photon c tn s f = 3,08.1015 Hz, electron s chuyn ng ra qu o dng . A: LB: MC: ND: Cu 39:Trong quang ph ca nguyn t hir , nu bit bc sng di nht ca vch quang ph trong dy Laiman l 1 v bc sng ca vch k vi n trong dy ny l 2 th bc sng o ca vch quang ph Ho trong dy Banme l A: 1 21 2 + B: (1 + 2). C: (1 2).D: 1 21 2 Cu 40: Vch quang ph c tn s nh nht trong dy Ban-me l tn s f 1 , Vch c tn s nh nht trong dy Lai-man l tn s f 2. Vch quang ph trong dy Lai-man sat vi vch c tn s f 2 s c tn s bao nhiu A: f 1 + f 2B: f 1 .f 2C: f 1.f 2f+f 2 D: f 1.f 2f 1-f 2 . Cu 41:Trong nguyn t hyr, xt cc mc nng lng t K n P c bao nhiu kh nng kch thch lctrn tng bn knh qu o ln 4 ln ? A: 1B:2C:3.D:4 Cu 42:Nng lng cc trng thi dng ca nguyn t hidro cho bi E n =-13,6n2 eV. Vi n= 1,2,3ngvi cc qu o K,L,M Bit h = 6,625.10-34 Js; c = 3.108 m/s. Nguyn t ang trng thi c bn th hp th photon c nng lng c = 12,09eV. h = 6,625.10-34 Js; c = 3.108 m/s. Trong cc vch quang ph ca nguyn t c th c vch vi bc sng. A: =0,116mB: =0,103mC: =0,628m. D: =0,482m Cu 43:Mt nguyn t hir chuyn t trng thi dng c nng lngEM = -1,5eV sang trng thi nng lng EL = -3,4ev Bc sng ca bc x pht ra l: A: 0,434mB: 0,486mC: 0,564D: 0,654m Cu 44:Nng lng cc trng thi dng ca nguyn t hidro cho bi E n =-13,6n2 eV. Vi n= 1,2,3ng vi cc qu o K,L,M Bit h = 6,625.10-34 Js; c = 3.108 m/s.Vch quang ph trong dy Pasen vi tn s ln nht l? A: f = 1,59.1014 HzB:f = 2,46.1015 HzC: f = 3,65.1014 HzD: f = 5,24.1015 Hz Cu 45: Bc sng di nht trong dy Banme v Pasen ln lt l B = 0,6563m; P = 1,8821m. Bc sng ca vch H | l? A: = 0,4866mB: = 0,4340 mC: = 0,5248mD: = 0,4120 m Cu 46:Bc sng di nht trong dy Banme l 0,6560m. Bc sng di nht trong dy Laiman l 0,1220m. Bc sng di th hai ca dy Laiman l:A: 0,0528mB: 0,1029m C: 0,1112m D: 0,1211mCu 47:Bc sng ca vch quang ph th nht trong dy Laiman l 122 nm, bc sng ca vch quang ph th nht v th hai ca dy Banme l 0,656m v 0,4860m. Bc sng ca vch th ba trong dy Laiman l A: 0,0224mB: 0,4324mC: 0,0975mD: 0,3672m Cu 48:Bc sng ca vch quang ph th nht trong dy Laiman l 122 nm, bc sng ca vch quang ph th nht v th hai ca dy Banme l 0,656m v 0,4860m. Bc sng th nht trong dy Pasen l: A: 1,8754mB: 1,3627mC: 0,9672mD:0,7645m Cu 49:Bit nng lng ca lectron trng thi dng th n c tnh theo cng thc:eVnEn 26 , 13 = , vi n = 1,2,3 nng lng ca lectron qu o M l: A: 3,4 eV.B: - 3,4 eV. C: 1,51 eV. D: - 1,51 eV. Cu 50:Bc sng ca vch quang ph th nht trong dy Laiman ca quang ph hir l0,122 m . Tnh tn s ca bc x trn A: 0,2459.1014HzB: 2,459.1014HzC: 24,59.1014HzD: 245,9.1014Hz Cu 51:Trong nguyn t hir, lectrn t qu o L chuyn v qu o K c nng lng EK= 13,6eV. Bc sng bc x pht ra bng l =0,1218m. Mc nng lng ng vi qu o L bng : A:3,2eVB: 3,4eV. . 4,1eVD: 5,6eV Cu 52:Nng lng ion ha nguyn t Hyr l 13,6eV. Bc sng ngn nht m nguyn t c th bc ra l : A: 0,122m B: 0,0913mC: 0,0656m D: 0,5672m Cu 53:Cho: 1eV = 1,6.10-19J ; h = 6,625.10-34Js ; c = 3.108m/s . Khi lectrn (lectron) trong nguyn t hir chuyn t qu o dng c nng lng Em = - 0,85eV sang qu o dng c nng lng E = - 13,60eV th nguyn t pht bc x in t c bc sng A: 0,0974 m B: 0,4340 m. C: 0,4860 m. D: 0,6563 m. Cu 54:Bit hng s Plng h = 6,625.10-34J.s v ln ca in tch nguyn t l 1,6.10-19C. Khi nguyn t hir chuyn t trng thi dng c nng lng -1,514 eV sang trang thi dng c nng lng -3,407 eV th nguyn t pht ra bc x c tn s A: 2,571.1013 Hz.B: 4,572.1014HzC: 3,879.1014Hz.D: 6,542.1012Hz. Gv: Nguyn Hng Khnh _ HKP CHNG VI: LNG T NH SNGDi ng: 09166.01248 Email: Khanhcaphe@gmail.com Gio Dc Hng Phc - Ni Khi u c M! Trang 24 Cu 55: Nng lng cc trng thi dng ca nguyn t hidro cho bi E n =-13,6n2 eV. Vi n= 1,2,3ng vi cc qu o K,L,M Bit h = 6,625.10-34 Js; c = 3.108 m/s. Bc sng ca vch H | l? A: = 487,1nmB: = 0,4625mC: = 5,599mD: = 0,4327mCu 56: Bc sng ngn nht ca vch quang ph trong quang ph ca nguyn t hidro l min = 91,34nm. Bit h = 6,625.10-34 Js; c = 3.108 m/s. Nng lng ion ha nguyn t hidro l: A: AE = 13,6JB: 13,6. 10-19 JD: AE = 21,76JD: AE = 21,76.10-19 JCu 57: Bit nng lng nguyn t hidro mt trng thi c bn l E 1 = - 13,6eV v bc sng ca mtvch trong dy Lai -man l 121,8nm. Ly h = 6,625.10-34 Js; c = 3.108 m/s. Nng lng ca nguyn t trng thi kch thch pht ra vchquang ph ni trn l: A: E n = - 1,5eVB:E n = - 0,85eVC: E n = - 0,54eVD:E n = - 3,4eVCu 58: Nguyn t hidro ang trng thi c bn c nng lng E 1 = - 13,6eV. Ly h = 6,625.10-34 Js v c = 3.108 m/s. Mun ion ha th nguyn t phi hp th photon c bc sngA: 0,122mB: 0,122mC: 0,091mD: 0,091m Cu 59:Trong quang phca nguyn t hiro, ba vch u tin trong dy Lai man c bc sng 1 = 121,6 nm; 2 = 102,6 nm; 3 = 97,3 nm. Bc sng ca hai vch u tin trong dy Ban me lA: 686,6 nm v 447,4 nm.B: 660,3 nm v 440,2 nm. C: 624,6nm v 422,5 nm.D: 656,6 nm v 486,9 nm. Cu 60:Trongquangph canguyn tHyr, vch c tn snhnht cadyLaimanl f1 =8,22.1014 Hz, vch c

tn s ln nht ca dy Banme lf2= 2,46.1015 Hz. Nng lng cn thit ion ho nguyn t Hyr t trng thi c bn l: A: E~ 21,74.10-19J.B: E~ 16.10- 19J.C: E~ 13,6.10- 19 J.D: E~10,85.10-19 J Cu 61:Mc nng lng En trong nguyn t hir c xc nh En = 20nE(trong n l s nguyn dng, E0 l nng lng ng vi trng thi c bn). Khi lectron nhy t qu o L v qu o K th nguyn t hir pht ra bc x c bc sng 0 . Bc sng ca vch Hl:A: 5,4 .0 B: 3,2 .0C: 4,8 .0 D: 1,5 .0Cu 62:Bc sng di nht trong dy Laiman; Banme; Pasen ln lt l 0,122m; 0,656m; 1,875m. Bc sng di th hai ca dy Laiman v Banme l A: 0,103m v 0,486B: 0,103m v 0,472mC: 0,112m v 0,486mD: 0,112m v 0,472m Cu 63:Trong nguyn t hir , bn knh Bo l r0 = 5,3.10-11m. Sau khi nguyn t hir bc x ra phtn ng vi vch (vch Ho) th bn knh qu o chuyn ng ca lctrn trong nguyn t gim A: 13,6nm.B: 0,47nm.C: 0,265nm.D: 0,75nm. Cu 64:VchquangphutincadyLaiman,BanmevPasentrongquangphnguynthirctnslnltl 24,5902.1014Hz; 4,5711.1014Hz v 1,5999.1014Hz. Nng lng ca phtn ng vi vch th 3 trong dy Laiman l A: 20,379 JB: 20,379 eVC: 12,737 eVD: p n khc.Cu 65:Bit vch th hai ca dy Lyman trong quang ph ca nguyn t hir c bc sng l 102,6nm v nng lng ti thiu cn thit bt lectron ra khi nguyn t t trng thi c bn l13,6eV. Bc sng ngn nht ca vch quang ph trong dy Pasen l A: 83,2nmB: 0,8321mC: 1,2818mD: 752,3nm Cu 66:Trong quang ph vch ca hyro, bc sng ca vch th nht trong dy Laiman ng vi s chuyn ca lectron t qu o L v qu o K l 0,1217 m, vch th nht ca dy Banme l 0,6563 m. Bc sng ca vch quang ph th hai trong dy Laiman l A: 0,5346 mB: 0,7780 m C: 0,1027 mD: 0,3890 m Cu 67:Cc mc nng lng trong nguyn t Hyr c xc nh theo cng thceVnE26 , 13 = (n = 1,2,3....). Nguyn t Hyr ang trng thi c bn s hp th phtn c nng lng bngA: 6,00eVB: 8,27eVC: 12,75eVD: 13,12eV. Cu 68:(C 2007): Trong quang ph vch ca hir (quang ph ca hir), bc sng ca vch th nht trong dy Laiman ng vi s chuyn ca lectrn (lectron) t qu o L v qu o K l 0,1217 m , vch th nht ca dy Banme ngvi s chuynM L l 0,6563m . Bc sng ca vch quang ph th hai trong dy Laiman ng vi s chuyn M KbngA: 0,1027m .B: 0,5346m .C: 0,7780m .D: 0,3890 m . Cu 69:(C 2007): mt nhit nht nh, nu mt m hi c kh nng pht ra hai nh sng n sc c bc sng tng ng 1v2(vi < 2 ) th n cng c kh nng hp thA: mi nh sng n sc c bc sng nh hn1 . B: mi nh sng n sc c bc sng trong khong t 1n 2 .C: hai nh sng n sc . D: mi nh sng n sc c bc sng ln hn 2 .Cu 70:(H 2007): Cho: 1eV = 1,6.10-19 J; h = 6,625.10-34 J.s; c = 3.108 m/s. Khi lectrn (lectron) trong nguyn t hir chuyn t qu o dng c nng lng Em= - 0,85eVsang qu o dng c nng lngEn = - 13,60eVth nguyn t pht bc x in t c bc sngA: 0,4340 m.B: 0,4860 m.C: 0,0974 m.D: 0,6563 m Cu 71:(H 2008):Trong quang ph ca nguyn t hir , nu bit bc sng di nht ca vch quang ph trong dy Laiman l 1 v bc sng ca vch k vi n trong dy ny l 2 th bc sng oca vch quang ph Ho trong dy Banme l A: (1 + 2).B: 1 21 2 .C: (1 2).D: 1 21 2 + Gv: Nguyn Hng Khnh _ HKP CHNG VI: LNG T NH SNGDi ng: 09166.01248 Email: Khanhcaphe@gmail.com Gio Dc Hng Phc - Ni Khi u c M! Trang 25 Cu 72:(H 2008):Trong nguyn t hir , bn knh Bo l r0 = 5,3.10-11m. Bn knh qu o dng N l A: 47,7.10-11m.B: 21,2.10-11m.C: 84,8.10-11m.D: 132,5.10-11m. Cu 73:(C - 2009) Trong quang ph vch ca nguyn t hir, bc sng di nht ca vch quang ph trong dy Lai-man v trong dy Ban-me ln lt l 1 v 2. Bc sng di th hai thuc dy Lai-man c gi tr l A: 1 21 22( ) + .B: 1 21 2 + .C: 1 21 2 .D: 1 22 1 . Cu 74:(H 2009) Nguyn t hit trng thi c bn c mc nng lng bng -13,6 eV. chuyn ln trng thi dng c mc nng lng -3,4 eV th nguyn t hir phi hp th mt phtn c nng lng A: 10,2 eV.B: -10,2 eV.C: 17 eV.D: 4 eV. Cu 75:(H 2009) Mt m nguyn t hir ang trng thi kch thch m lectron chuyn ng trn qu o dng N. Khi lectron chuyn v cc qu o dng bn trong th quang ph vch pht x ca m nguyn t c bao nhiu vch? A: 3.B: 1.C: 6.D: 4. Cu 76:(H 2009) i vi nguyn t hir, khi lectron chuyn t qu o M v qu o K th nguyn t pht ra phtn c bc sng 0,1026 m. Ly h = 6,625.10-34J.s, e = 1,6.10-19 C v c = 3.108m/s. Nng lng ca phtn ny bng A: 1,21 eVB: 11,2 eV.C: 12,1 eV.D: 121 eV. Cu 77:(H - 2010)Khi lectron qu o dng th n th nng lng ca nguyn t hir c tnh theo cng thc - 26 , 13n(eV) (n = 1, 2, 3,). Khi lectron trong nguyn t hir chuyn t qu o dng n = 3 sang qu o dng n = 2 th nguyn t hir pht ra phtn ng vi bc x c bc sng bng A: 0,4350 m.B: 0,4861 m.C: 0,6576 m.D: 0,4102 m. Cu 78:(H - 2010)Theo tin ca Bo, khi lectron trong nguyn t hir chuyn t qu o L sang qu o K th nguyn t pht ra phtn c bc sng 21, khi lectron chuyn t qu o M sang qu o L th nguyn t pht ra phtn c bc sng 32 v khi lectron chuyn t qu o M sang qu o K th nguyn t pht ra phtn c bc sng 31. Biu thc xc nh 31 l A: 31 = 31 2121 32 .B: 31 = 32 - 21.C: 31 = 32 + 21.D: 31 = 31 2121 32 +. Cu 79:(H - 2010)Nguyn t hir chuyn t trng thi dng c nng lng En = -1,5 eV sang trng thi dng c nng lng Em = -3,4 eV. Bc sng ca bc x m nguyn t hir pht ra xp x bng A: 0,654.10-7m.B: 0,654.10-6m.C: 0,654.10-5m.D: 0,654.10-4m. Cu 80:(H -2011)Trong nguyn t hir, bn knh Bo l r0 = 5,3.10-11 m. mt trng thi kch thch ca nguyn t hir, lectron chuyn ng trn qu o dng c bn knh l r = 2,12.10-10 m. Qu o c tn gi l qu o dng A: N. B: M. C: O. D: L. Cu 81:(H -2011)Khi lectron qu o dng th n th nng lng ca nguyn t hir c xc nh bi cng thc n 213, 6E (eV)n=(vi n = 1, 2, 3, ...). Khi lectron trong nguyn t hir chuyn t qu o dng n = 3 v qu o dng n = 1 th nguyn t pht ra phtn c bc sng 1. Khi lectron chuyn t qu o dng n = 5 v qu o dng n = 2 th nguyn t pht ra phtn c bc sng 2. Mi lin h gia hai bc sng 1 v 2lA: 2 = 41B: 272 = 1281. C: 1892 = 8001.D: 2 = 51. CHNG VI: LNG T NH SNG BI 5: HIN TNG QUANG - PHT QUANG; TIA LAZE 1. HIN TNG QUANG - PHT QUANG A. nh ngha -Mt s cht c kh nng hp th nh sng c bc sng ny pht ra nh sng c bc sng khc. Hin tng trn gi l hin tng quang - pht quang.-V d: Chiu tia t ngoi vo dung dch fluorexein th dung dch ny s pht ra nh sng mu lc. Trong tia t ngoi lnh sng kch thch cn nh sng mu lc l nh sng pht quang.-Ngoi hin tng quang - pht quang ta cn cp n mt s hin tng quang khc nh: ha - pht quang ( om m); pht quang ca tt ( n hnh ti vi); in - Pht quang ( n LED) B. Phn loi quang pht quang Hunh quangLn quang Gv: Nguyn Hng Khnh _ HKP CHNG VI: LNG T NH SNGDi ng: 09166.01248 Email: Khanhcaphe@gmail.com Gio Dc Hng Phc - Ni Khi u c M! Trang 26 S pht quang ca cc cht lng v kh c c im l nh sngphtquangbttnhanhsaukhittnhsngkch thch. Gi l hin tng hunh quang S pht quangca nhiu cht rn li c c im l nh sng pht quang c th ko di mt khong thi gian no sau khi tt nh sng kch thch. S pht quang trn gi l hin tng ln quang. -nhsnghunhquangcbcsngdihnbc sng ca nh sng kch thch - Mts loi sn xanh, ,vng lc quyets trn cc binbogiaothnghocuccccchgii nglccchtlnquangcthigiankodi khong vi phn mi giy. nh lut Stock v hin tng pht quang: k < p - Nng lng mt mt trong qu trnh hp th ph tn : Ac = hf kt - hf hq = hc k- hc p= hc.

((1 k - 1 p

- Cng thc hiu sut pht quang: H =P pP k .100% =n p. kn k. p.100% 2.LASER ( LAZE) A. nh ngha laser -Laze l mt ngun sng pht ra mt chm sng cng ln da trn hin tng pht x cm ng. -S pht x cm ng: Nu mt nguyn t ang trong trng thi kch thch sn sng pht ra mt photon c nng lng c = hf, bt gp mt photon c nng lng c ng bng hf, bay lt qua n, th lp tc nguyn t ny cng pht ra photon c. Photon c c cng nng lng v bay cng phng vi photon c. Ngoi ra, sng in t ng v photon c hon ton cng pha v dao ng trong mt phng song song vi mt phng dao ng ca sng in t ng vi photon c. -c im ca tia laze. Tnh n sc cao v ( c cng nng lng ng vi sng in t c cng bc sng)Tnh nh hng rt cao ( baytheo cng mt phng) Tnh kt hp cao ( cung pha ) Cng ca chumg sng rt ln( s ph tn bay theo cng mt hng rt ln) -ng dng ca tia laze:Trong y hc dng lm dao m trong cc phu thut tinh vi Thng tin lin lc ( v tuyn nh v, lin lc v tinh) Trong cng nghip dng khoan ct, ti chnh xc Trong trc a dng o khong cch, tam gic c. Laze cn dng trong cc u c a . 3. HIN TNG QUANG IN TRONG A. Quang in trong: Hin tng nh sng gii phng cc e lin kt cho chng tr thnh cc electron dn ng thi to ra cc l trng cng tham gia vo qu trnh dn in gi l hin tng quang in trong B. Cht quang dn: hin tng gim in tr sut, tc l tng dn in ca bn dn, khi c nh sng thch hp chiu vo gi l hin tng quang dn. Cht o ( m) Ge1.88 Si1,11 PbS4,14 CdS0,9 PbSe5,65 Gv: Nguyn Hng Khnh _ HKP CHNG VI: LNG T NH SNGDi ng: 09166.01248 Email: Khanhcaphe@gmail.com Gio Dc Hng Phc - Ni Khi u c M! Trang 27 C. Pinquangin:lpinchybng nng lngnhsngnbin i trctipquangnngthnhin nng. Pin hot ng da vo hin tngquangintrongcamt schtbndnnhngoxit, Selen, Silic. + _ in cc trong sut Bn dn loi p Bn dn loi n in cc D. Quang in tr: L mt tm bn dncgitrintrthayi khicngchmsng chiu vo n thay i 2 1 33 4 6 5 4 RG BI TP MU V d 1:Trong cc hin tng sau: hin tng no l hin tng quang - pht quang? A. Than ang chy hngB. om m nhp nhyC. Mn hnh ti vi sngD. n ng sng Hng dn: [ ] p n D - Than chy hng l ngun sng do phn ng t chy - om m nhp nhy l hin tng ha pht quang - Mn hnh ti vi l hin tng pht quang ca tt - n ng sang l hin tng quang pht quang. V d 2: Mt cht pht quang c kh nng pht ra nh sng c bc sng p = 0,7 m. Hi nu chiu vo nh sng no di y th s khng th gy ra hin tng pht quang?A. 0,6 mB. 0,55 mC. 0,68 mD. Hng ngoi Hng dn: [ ] p n DTheo nh lut Stock v hin tng pht quang ta c k p = 0,7 m Ch c tia Hng ngoi c hng ngoi> p = 0,7 m Khng c hin tng quang pht quang sy ra V d 3: Mt cht pht quang c th pht ra nh pht quang mu tm. Hi nu chiu ln lt tng bc x sau, bc x no c th gy ra hin tng pht quang? A. B. T ngoiC. ChmD. Lc Hng dn: [ ]p n B Theo nh lut Stock v hin tng pht quang ta c k p

Ch c t ngoi < tm

V d 4: Mt vt c th pht ra nh sng pht quang mu vi bc sng = 0.7 m. Hi nu chiu vt trn bng bc x c bc sng = 0,6 m th mi ph ton c hp th v pht ra th phn nng lng tiu hao l bao nhiu? A. 0,5 MeVB. 0, 432 eVC. 0,296 eVD. 0,5 eV Hng dn: [ ]p n C Gv: Nguyn Hng Khnh _ HKP CHNG VI: LNG T NH SNGDi ng: 09166.01248 Email: Khanhcaphe@gmail.com Gio Dc Hng Phc - Ni Khi u c M! Trang 28 Ta c: Ac = c k - c p = hc k- hc p= hc ( 1 k - 1 p ) = 6,625.10-34 .3.108 ( 10,6.10-6 - 10,7.10-6 ) = 4,73.10-20 J = 0,296 eV BI TP THC HNH Cu 1: S pht sng ca ngun sng no di y l s pht quang? A: Bng n xe my. B: Hn than hng.C: n LEDD: Ngi sao bng. Cu 2: Mt cht pht quang c kh nng pht ra nh sng mu vng lc khi c kch thch pht sng. Hi khi chiu vo cht nh sng n sc no di y th cht s pht quang? A: LC: B: Vng.C: Da cam.D: . Cu 3: nh sng pht quang ca mt cht c bc sng 0,5 . m Hi nu chiu vo cht nh sng c bc sng no di y th n s khng pht quang? A: 0,3mB: 0,4mC: 0,5mD: 0,6 m Cu 4: Trong hin tng quang Pht quang, c s hp th nh sng lm g? A. to ra dng in trong chn khng.C: thay i in tr ca vt. B. lm nng vt. D: lm cho vt pht sng. Cu 5: Trong hin tng quang Pht quang, s hp th hon ton mt phtn s a n: A.s gii phng mt lectron t do.C: s gii phng mt lectron lin kt. B.s gii phng mt cp lectron vo l trng.D: s pht ra mt phtn khc Cu 6: Hin tng quang Pht quang c th xy ra khi phtn b A: lectron dn trong km hp th. B: lectron lin kt trong CdS hp th. C: phn t cht dip lc hp th. D: hp th trong c ba trng hp trn. Cu 7: Khi xt s pht quang ca mt cht lng v mt cht rn. A:C hai trng hp pht quang u l hunh quang. B:C hai trng hp pht quang u l ln quang. C:S pht quang ca cht lng l hunh quang, ca cht rn l ln quang. D:S pht quang ca cht lng l ln quang, ca cht rn l hunh quang. Cu 8: Trong trng hp no di y c s quang Pht quang? A:Ta nhn thy mu xanh ca mt bin qung co lc ban ngy. B:Ta nhn thy nh sng lc pht ra t u cc cc tiu trn ng ni khi c nh sng n t chiu vo. C:Ta nhn thy nh sng ca mt ngn n ng. D:Ta nhn thy nh sng ca mt tm knh . Cu 9: Nu nh sng kch thch l nh sng mu lam th nh sng hunh quang khng th l nh sng no di y? A: nh sng .B: nh sng lc C: nh sng lam. D: nh sng chm. Cu 10:Chn cu ng. nh sng hunh quang l : A: tn ti mt thi gian sau khi tt nh sng kch thch.B: hu nh tt ngay sau khi tt nh sng kch thch C: c bc sng nhnh hn bc sng nh sng kch thch.D: do cc tinh th pht ra, sau khi c kch thch bng nh sng thch hp. Cu 11:Chn cu ng. nh sng ln quang l :A: c pht ra bi cht rn, cht lng ln cht kh. B: hu nh tt ngay sau khi tt nh sng kch thch.C: c th tn ti rt lu sau khi tt nh sng kch thchD: c bc sng nh hn bc sng nh sng kch thch. Cu 12:Chn cu sai : A: Hunh quang l s pht quang c thi gian pht quang ngn (di 10-8s). B: Ln quang l s pht quang c thi gian pht quang di (t 10-6s tr ln). C: Bc sng nh sng pht quang bao gi nh hn bc sng ca nh sng hp th < D: Bc sng nh sng pht quang bao gi cng ln hn bc sng ca nh sng hp th Cu 13:S pht sng ca vt no di y l s pht quang ? A: Tia la inB: H quang C: Bng n ngD: Bng n pinCu 14:Pht biu no sau y l sai khi ni v s pht quang? A: S hunh quang thng xy ra i vi cc cht lng v cht kh. B: S ln quang thng xy ra i vi cc cht rn. C: Bc sng ca nh sng pht quang bao gi cng ln hn bc sng ca nh sng kch thch. D: Bc sng ca nh sng pht quang bao gi cng nh hn bc sng ca nh sng kch thch. Cu 15:Trong trng hp no di dy c s quang pht quang ? A: Ta nhn thy mu xanh ca mt bin qung co lc ban ngy B: Ta nhn thy nh sng lc pht ra t u cc cc tiu trn ng ni khi c nh sng n -t chiu voC: Ta nhn thy nh sng ca mt ngn n ngD: Ta nhn thy nh sng ca mt tm knh Cu 16:Chn cu ng? A.Tia hng ngoi ch c th gy ra hin tng pht quang vi mt s cht kh B.Bc sng ca nh sng ln quang nh hn bc sng ca nh sng kch thch Gv: Nguyn Hng Khnh _ HKP CHNG VI: LNG T NH SNGDi ng: 09166.01248 Email: Khanhcaphe@gmail.com Gio Dc Hng Phc - Ni Khi u c M! Trang 29 C.nh sng ln quang tt ngay khi ngng ngun sng kch thch D.Pht quang l hin tng trong xy ra s hp th nh sng. Cu 17:nh sng kch thch c bc sng = 0,5 mkhi chiu vo cht pht quang c th to ra nh sng pht quang c bc sng no sau y? A: 0,4mB: 0,45mC: 0,55mD: 0,43m Cu 18:nh sng kch thch c bc sng = 0,5 mkhi chiu vo cht pht quang khngth to ra nh sng pht quang c bc sng no sau y? A: 0,4mB: 0,55mC: 0,65mD: 0,53m Cu 19:S pht sng no sau y khng phi l s pht quang? A: nh trngB: n LedC: om mD: n ng Cu 20:Mt cht c kh nng pht ra nh sng tm khi b kch thch. Hi khi chiu vo cht trn bc x no th c th gy ra hin tng pht quang. A: Tia vngB: Tia C: Tia lcD: T ngoi Cu 21:Mt nh sng pht quang c tn s 6.1014 Hz. Hi bc x c tn s no s khng gy ra c hin tng pht quang? A: 5.1014 HzB:6.1014 HzC: 6,5.1014 HzD: 6,4.1014 Hz Cu 22:Ta thng thy cc ct mc bn ng sn cht pht quang mu thay v mu tm v? A.Mu d pht quangB: Mu p B.Mu t tn km hnD: D phn bit vi cc mu khc Cu 23:Trng hin tng quang pht quang lun c s hp th hon ton mt pho tn vA.Gii phng ra mt pho tn c nng lng nh hn B.Lm bt ra mt e khi b mt kim loi C.Gii phng mt ph ton c nn lng ln hn D.Gii phng mt pho tn c tn s ln hn. Cu 24:Mt cht c kh nng pht ra mt ph tn c bc sng 0,5m khi b chiu sng bi mt bc x 0,4m. Tm nng lng b mt i trong qu trnh trn: A: 9,9375.10-20 JB: 1,25. 10-19 C: 2,99.10-20 JD: 8.10-20 J Cu 25:Mt cht c kh nng pht ra bc x c bc sng 0,5m khi b chiu sng bi bc x 0,3m. Bit rng cng sut ca chm sng pht quang ch bng 0,1 cng sut ca chm sng kch thch. Hy tm t l gia s ph tn bt ra v ph ton chiu ti? A: 0,667B: 0,001667C: 0,1667D: 1,67 Cu 26:Mt cht c kh nng bc x c bc sng 0,5m khi b chiu sng bi bc x 0,3m. Gi P o l cng sut chm sng kch thch v bit rng c 600 photon chiu ti s c 1 photon bt rA: Cng sut ca chm sng pht ra theo P o l: A: 0,1P oB: 0,01P oC: 0,001P oD: 100P o Cu 27:Nu nh sng kch thch l nh sng mu lam th nh sng hunh quang khng th l nh sng no sau y? A: B: LcC: LamD: Chm Cu 28:S pht sng no di y l s pht quang A: Tia la inB: H quangC: Bng n ngD: Bng n pin Cu 29:Nu chiu tia t ngoi vo dung dch flurexein th ta thy dung dch trn s pht ra nh sng mu lC: Hin tng trn gi l A: in pht quangB: ha pht quangC: quang - pht quangD: pht quang catot Cu 30:Chm sng do laze rubi pht ra c mu g? A: TrngB: xanhC: D: vng Cu 31:Bt laze m ta thng dng ch bng thuc loi laze no? A: KhB: LngC: RnD: Bn dn Cu 32:Laze l my khuych i nh sng da trn hin tngA: Quang pht quangB: Quang dnC: Quang in ngoiD: Pht x cm ng Cu 33:Trong cc ng dng sau, laze khng c dng lm g? A: Thng tin lin lcB: S dng trong y t C: ng dng trong cng nghipD: Si m cho cy trngCu 34:Chn cu sai? Tia laze A: C tnh n sc rt caoB: L chm sng kt hp C: L chm sng hi tD: C cng ln Cu 35:Trong laze rubi c s bin i ca dng nng lng no di y thnh quang nng ? A: in nng B: C nng C: Nhit nng D: Quang nng Cu 36:Tia laze khng c c im no di y? A: n sc cao. B: nh hng cao.C: Cng ln. D: Cng sut ln. Cu 37:Hy chn cu ng.Hiu sut ca mt laze A: Nh hn 1.B: Bng 1.C: Ln hn 1.D: Rt ln so vi 1. Cu 38:S pht x cm ng l g? A. l s pht ra phtn bi mt nguyn t. B. l s pht x ca mt nguyn t trng thi kch thch di tc dng ca mt in t trng c cng tn s. C. l s pht x ng thi ca hai nguyn t c tng tc ln nhau. D. l s pht x ca mt nguyn t trng thi kch thch, nu hp th thm mt phtn c cng tn s Cu 39:Mu ca rubi do ion no pht ra? A: Ion nhm.B: Ion xi. C: Ion crm. D: Cc ion khc Cu 40:Chm sng do laze rubi pht ra c mu: Gv: Nguyn Hng Khnh _ HKP CHNG VI: LNG T NH SNGDi ng: 09166.01248 Email: Khanhcaphe@gmail.com Gio Dc Hng Phc - Ni Khi u c M! Trang 30 A: trng.B: xanh.C: D: vng.Cu 41:Bt laze m ta thng dng ch bng thuc loi laze no? A: Kh.B: Lng.C: Rn.D: Bn dn Cu 42:Khi chiu vo cht pht quang nh sng n sc mu cam th n ch c th pht ra nh sng n sc mu A: VngB: CamC: LcD: Cu 43:nh sng pht quang ca mt cht cbc sng 0,65m. Cht skhng pht quang nu chiu va nh sng c bc sng? A: = 0,43mB: 0,68C: 0,54mD: 0,6m Cu 44:S pht sng ca cc vt sau khng phi l s pht quang? A: Bp thanB: Mn hnh tiviC: n ngD: Bin bo giao thng Cu 45:Chn cu sai? Ln quang A.l hin tng quang pht quang B.xy ra vi cht rn C. c thi gian pht quang di hn 10-8 s tr lnD.C bc sng nh sng pht quang ngn hn bc sng nh sng kch thch : < . Cu 46:Chn cu ng? Hunh quang A:C thi gian pht quang di hn 10-8 s tr lnC: Xy ra vi cht lng v cht kh B:Xy ra vi cht rn v cht lngD:Xy ra ch vi cht lngCu 47:Chn cu sai? A:S pht quang l hin tng vt cht hp th nng lng di dng no ri pht ra cc bc x in t trong min nh sng nhn thy. B:S pht quang xy ra nhit bnh thng C:Cc cht pht quang khc nhau cng nhit cng pht ra quang ph nh nhau D:Sau khi ngng kch thch, s pht quang ca mt s cht cn tip tc ko di thm mt khong thi gian na Cu 48: Hin tng quang in trong l hin tng. A: Bt electron ra khi b mt kim loi khi b chiu sng. B: Gii phng electron khi kim loi bng cch t nng.C: Gii phng electron khi mi lin kt trong bn dn khi b chiu sng. D: Gii phng electron khi bn dn bng cch bn ph ion. Cu 49:Tm pht biu ng? A:nh sng gy ra hin tng quang in trong c bc sng nh hn nh sng gy ra hin tng quang in ngoi. B:nh sng gy ra hin tng quang in trong c tn s ln hn tn s ca nh sng gy ra hin tng quang in ngoi C:nh sng gy ra hin tng quang in trong c nng lng ln hn nh sng gy ra hin tng quang in ngoi D:Khng c pht biu ng. Cu 50:Chn cu ng.A: Hin tng in tr ca cht bn dn gim khi b nung nng gi l hin tng quang dn.B: Hin tng quang dn l hin tng dn in bng cp quang. C: Pin quang in l thit b thu nhit ca nh sng mt tri.D: Hin tng nh sng gii phng cc electron lin kt cho chng tr thnh cc electron dn gi l hin tng quang in trong. Cu 51:Dng c no di y c ch to khng da trn hin tng quang in trong? A: Quang in tr.B: Pin quang in. C:T bo quang in chn khng D: Pin mt tri. Cu 52:Chn cu tr li sai khi ni v hin tng quang in v quang dn: A: u c bc sng gii hn 0 . B: u bt c cc lectron ra khi khi cht . C: Bc sng gii hn ca hin tng quang in bn trong c th thuc vng hng ngoi. D: Nng lng cn gii phng lectron trong khi bn dn nh hn cng thot ca letron khi kim loi.Cu 53:Chn cu saikhi ni v hin tng quang dnA: L hin tng gim mnh in tr ca bn dn khi b chiu sng.B: Mi phtn nh sng b hp th s gii phng mt electron lin kt n tr thnh mt electron dn.C: Cc l trng tham gia vo qu trnh dn in.D: Nng lng cn bt electrn ra khi lin kt trong bn dn thng ln nn ch cc phtn trong vng t ngoi mi c th gy ra hin tng quang dn.Cu 54:Hin tng quang dn l A:Hin tng mt cht b pht quang khi b chiu nh sng vo. B:Hin tng mt cht b nng ln khi chiu nh sng vo. C:Hin tng gim in tr ca cht bn dn khi chiu nh sng vo. D:S truyn sng nh sng bng si cp quang. Cu 55:Hin tng quang in trong l hin tng A: Gii phng electron khi mi lin kt trong bn dn khi b chiu sng. B: Bt electron ra khi b mt kim loi khi b chiu sng. C: Gii phng electron khi kim loi bng cch t nng. D: Gii phng electron khi bn dn bng cch bn ph ion. Gv: Nguyn Hng Khnh _ HKP CHNG VI: LNG T NH SNGDi ng: 09166.01248 Email: Khanhcaphe@gmail.com Gio Dc Hng Phc - Ni Khi u c M! Trang 31 Cu 56:Chn cu ng. Pin quang in l ngun in trong : A: Quang nng c trc tip bin i thnh in nng. B: Nng lng Mt Tri c bin i trc tip thnh in nng.C: Mt t bo quang in c dng lm my pht in.D: Mt quang in tr, khi c chiu sng, th tr thnh my pht in Cu 57:Chn phng n sai khi so snh hin tng quang in bn trong v hin tng quang in ngoi. A: C hai hin tngu do cc phtn ca nh sng chiu vo v lm bt electron. B:C hai hin tngch xy ra khi bc sng nh sng kch thch nh hn bc sng gii hn. C: Gii hn quang in trong ln hn ca gii hn quang in ngoi.D: C hai hin tng electrn c gii phng thot khi khi cht. Cu 58:Pht biu no sau y l ng khi ni v hin tng quang pht quang? A.Hin tng quang pht quang l hin tng mt scht pht sng khi b nung nng. B.Hunh quang l s pht quang ca cht rn, nh sng pht quang c th ko di mt khong thi gian no sau khi tt nh sng kch thch. C.nh sng pht quang c tn s ln hn nh sng kch thch. D.S pht sng ca n ng l hin tng quang pht quang. Cu 59:1 phtn c nng lng 1,79eV bay qua 2 nguyn t c mc kch thch 1,79eV, nm trn cng phng ca phtn ti. Cc nguyn t ny c th trng thi c bn hoc trng thi kch thch. Gi x l s phtn c th thu c sau , theo phng ca phton ti. Cu sai lA: x = 0 B: x = 1C: x = 2 D: x = 3 Cu 60: Dung dch Fluorxin hp th nh sng c bc sng 0,49m v pht ra nh sng c bc sng 0,52m. ngi ta gi hiu sut ca s pht quang l t s gia nng lng nh sng pht quang v nng lng nh sng hp th. Bit hiu sut ca s pht quang ca dung dch Fluorxin l 75%. S phn trm ca phtn b hp th dn n s pht quang ca dung dch l A: 82,7%B: 79,6%C: 75,0% D: 66,8% Cu 61:Chn pht biu ng A.Hin tng mt s cht c kh nng hp th nh sng c bc sng ny ri pht ra nh sng cbc sng khcgi l s pht quang( p > k ). B.Hunh quang l hin tng m nh sng pht quang tt ngay khi ngng nh sng kch thch. N thng xy ra vi cht lng hoc cht kh. C.Ln quang l hin tng m nh sng pht quang cn ko di vi giy, n hng gi ( ty theo cht) sau khi tt nh sng kch thch. N thng xy ra vi cc vt rn. D.C ba trn. Cu 62:Mt vt c kh nng pht quang nh sng c bc sng 1 = 0,5(m), vt khng th hp th nh sng c bc sng 2 no sau y? A: 2 = 0,3(m)B: 2 = 0,4(m) C: 2 = 0,48(m)D: 2= 0,58(m) Cu 63:nh sng ln quang l nh sng A: c pht ra bi c cht rn, lng v kh. B: C th tn ti trong thi gian di hn 10-8s sau khi tt nh sng kch thch. C: C tn s ln hn tn s ca nh sng kch thch. D: Hu nh tt ngay sau khi tt nh sng kch thch. Cu 64:Mt cht pht quang c kh nng pht ra nh sng mu lc khi c kch thch pht sng. khi chiu vo cht nh sng n sc no di y th n s pht quang? A: Lc: B: Vng.C: Lam D: Da cam. Cu 65: Mt cht c kh nng pht quang nh sng mu v mu lc. Nu dng tia t ngoi kch thch s pht quang ca cht th nh sng pht quang c th c mu no? A: Mu lam.B: Mu .C: Mu vngD: Mu lc. Cu 66:(C -2009): Khi chiu vo mt cht lng nh sng chm th nh sng hunh quang pht ra khng th lA: nh sng tm.B: nh sng vng.C: nh sng .D: nh sng lc. Cu 67:(H - 2010)Mt cht c kh nng pht ra nh sng pht quang vi tn s f = 6.1014 Hz. Khi dng nh sng c bc sng no di y kch thch th cht ny khng th pht quang?A: 0,55 m.B: 0,45 m.C: 0,38 m.D: 0,40 m. Cu 68:(H - 2010)Khi chiu chm tia t ngoi vo mt ng nghim ng dung dch fluorexin th thy dung dch ny pht ra nh sng mu lc. l hin tng A: phn x nh sng.B: quang - pht quang.C: ha - pht quang.D: tn sc nh sng. Cu 69:(H -2011)Mt cht pht quang c kch thch bng nh sng c bc sng 0,26 m th pht ra nh sng c bc sng 0,52 m. Gi s cng sut ca chm sng pht quang bng 20% cng sut ca chm sng kch thch. T s gia s phtn nh sng pht quang v s phtn nh sng kch thch trong cng mt khong thi gian lA: 2/5B: 4/5 C: 1/5 D: 1/10