Mathsf3Ch.9 #2 & Chp.10

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    SCALE DRAWINGS

    CHAPTER 9MATHEMATICS

    FORM 3

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    (1) SKECTH SHAPES

    Same size as object

    Smaller than the object

    Larger than the object

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    Same size as object

    OBJECT IMAGE

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    Smaller than the object

    OBJECT

    IMAGE

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    Larger than the object

    OBJECT

    IMAGE

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    Sketch figure : Same size

    OBJECT

    IMAGE

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    Sketch figure : Smaller size

    OBJECT

    IMAGE

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    Sketch figure : Larger size

    OBJECT

    IMAGE

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    (2) DRAW GEOMETRICALSHAPE USING SCALE

    Scale, d = scaled length

    actual length

    1 = scaled length

    n actual length

    IMAGE

    OBJECT

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    Draw the following shape to a scale 1:2

    A

    B

    C

    1 = scaled length

    n actual length

    Find length AB

    and AC

    1 = AB

    2 AB

    1 = AB

    2 2

    1 x 2 = AB

    2

    AB = 1

    BC = 1

    1 = AC

    2 AC

    1 = AC2 4

    1 X 4 = AC

    2

    AC = 2

    A

    B

    C

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    Draw the following shape to a scale 1:

    A

    B

    C

    1 = scaled length

    n actual length

    Find length AB

    and AC

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    NOW , lets try PMR ExamQuestions!!

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    (3) SOLVING PROBLEMS

    SUPERSCORE book, page 90

    Lets try Question (a) and (b)

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    TRANSFORMATIONS ll

    CHAPTER 10

    MATHEMATICS

    FORM 3

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    (1) SIMILARITY

    Same shapes, same size

    Same shapes, different size

    All the corresponding angles are equal All the corresponding lengths have thesame ratio.

    Corresponding angles

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    SIMILAR ?

    A

    B

    CE

    D

    F

    Corresponding angles

    Corresponding lengths

    M L R ?Corresponding angles

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    SIMILAR ?

    A

    B

    CE

    D

    F

    Corresponding angles

    Corresponding lengths

    10

    4

    6

    15

    9

    6

    BA = 6 = 2

    DE 9 3

    AC = 4 = 2

    EF 6 3

    BC = 10 = 2

    DF 15 3

    P E

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    SKILL PRACTICE 10.1a, page 205

    AB =

    DE

    BC =

    EF

    AC =

    DF

    2(b)

    3 cm

    6 cm

    4 cm12 cm

    6 cm

    8 cm

    A

    BC

    D

    E

    F

    LL PR E 10 1 205

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    SKILL PRACTICE 10.1a, page 2052(d) 3 cm

    8 cm

    5 cm 6cm

    5

    8

    3 = 1

    6 2

    The ratio is

    not the same

    NOT SIMILAR

    K LL PR CT CE 10 1b 207

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    SKILL PRACTICE 10.1b, page 2071(a)

    7 cm

    3 cmx cm

    y cm

    6 cm

    8 cm

    x = 3

    8 6

    x = ?

    y = 6

    7 3

    y = ?

    (2) ENLARGEMENT

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    (2) ENLARGEMENTScale factor, k

    = length of side of image

    length of side of object

    = distance of a point of image from O

    distance of a point of object from O

    B

    B

    A

    CC

    O is the centre of enlargement

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    HOW to find the centre of enlargement ?

    0 1 2 3 4 5 6 7 8 9 x

    1

    9

    8

    7

    6

    5

    4

    3

    2

    y

    We have

    found the

    centre of

    enlargement!

    (2, 1)

    CHECK YOURSELF

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    CHECK YOURSELFCentre of

    enlargement, O

    = the point of

    intersection

    CHECK YOURSELF

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    CHECK YOURSELFCentre of

    enlargement, O

    = the point of

    intersection

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    Scale factor, k= length of side of imagelength of side of object

    = distance of a point of image from O

    distance of a point of object from O

    IMAGE OF ENLARGEMENT

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    IMAGE OF ENLARGEMENTDraw the image with a scale factor using O

    as a centre of enlargement

    O

    AB

    C D

    x :1

    2

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    AREA OF IMAGE

    Area of image = k2 x Area of object

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    ASSESSMENT

    exam-type questions

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    THE END

    PREPARED BY: SHERLLY SIMUNSubject Teacherform3@2009_Highlanders