Modul Struktur Kayu6 New

Perencanaan Kuda-Kuda (2)

S8 = 300,15 kg (tarik)

TITIK BUHUL H

Fy = 0,

S9 = 0

Fx = 0,

S8 S7 = 0

S7 = S8 = 300,15 kg (tarik)

Pusat Pengembangan Bahan Ajar - UMB

IR. ALIZAR, M.T

STRUKTUR KAYU


TITIK BUHUL C

Fy = 0,

S2 sin2 S10 sin3 S1 sin1 Pa2 cos1 Pa3 cos2 S9 = 0

0,5145 S2 0,5734 S10 (-29,86) (0,8137) (26,4) (0,5812) (112,51) (0,8575) 0

=0

0,5145 S2 0,5734 S10 + 24,29 15,34 96,48 = 0

0,5145 S2 0,5734 S10 = 87,53

S2 = 1,1145 S10 + 170,13 ........................................................................(i)

Fx = 0,

Pa2 sin1 + S2 cos2 + Pa3 sin2 + S10 cos3 S1 cos1 = 0

(26,4) (0,8137) + 0,8575 S2 + (112,51) (0,5145) + 0,8193 S10 (-29,86) (0,5812) = 0

21,48 + 0,8575 S2 + 57,89 + 0,8193 S10 + 17,35 = 0

0,8575 S2 + 0,8193 S10 + 96,72 = 0

S10 = - 1,0466 S2 118,05 .......................................................................(ii)

(i) dan (ii)

S2 = (1,1145) (-1,0466 S2 118,05) + 170,13

S2 = - 1,1664 S2 131,57 + 170,13


IR. ALIZAR, M.T

STRUKTUR KAYU


2,1664 S2 = 38,56

S2 = 17,80 kg (tarik)

S10 = (-1,0466) (17,80) 118,05

S10 = -136,68 (tekan)

TITIK BUHUL D

Fx = 0,

S3 cos2 + Pa5 sin2 + Pa4 sin2 S2 cos2 = 0

0,8575 S3 + (65,29) (0,5145) + (112,51) (0,5145) (17,80) (0,8575) = 0

0,8575 S3 + 33,59 + 57,89 15,26 = 0

0,8575 S3 = - 76,22

S3 = - 88,89 kg (tekan)

Fy = 0,

Pa5 cos2 S2 sin2 Pa4 cos2 S3 sin2 S11 = 0

(65,29) (0,8575) (17,80) (0,5145) (112,51) (0,8575) (-88,89) (0,5145) S11 = 0

55,98 9,16 96,48 + 45,73 S11 = 0

S11 = - 3,93 kg (tekan)


IR. ALIZAR, M.T

STRUKTUR KAYU


TITIK BUHUL G

Fy = 0,

S11 + S12 sin3 = 0

- 3,93 + 0,5734 S12 = 0

S12 = 6,85 kg (tarik)

Fx = 0,

S6 + S12 cos3 S10 cos3 S7 = 0

S6 + (6,85) (0,8193) (-136,68) (0,8193) 300,15 = 0

S6 + 5,61 + 111,98 300,15 = 0

S6 = 182,56 kg (tarik)


IR. ALIZAR, M.T

STRUKTUR KAYU


TITIK BUHUL F

Fy = 0,

S13 = 0

Fx = 0,

S5 S6 = 0

S5 = S6 = 182,56 kg (tarik)


IR. ALIZAR, M.T

STRUKTUR KAYU

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Modul Struktur Kayu6 New