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PRESSURE VESSEL:PRESSURE VESSEL:Perancangan, FabrikasiPerancangan, Fabrikasi
dan Inspeksidan Inspeksi
Ir. Tri Prakosa, M.Eng.Ir. Tri Prakosa, M.Eng.
LAPI-ITB (22-25 Oktober 2009)LAPI-ITB (22-25 Oktober 2009)
11
2. DESIGN OVERVIEW2. DESIGN OVERVIEW
22
33
OVERVIEW PERANCANGAN BEJANA TEKANOVERVIEW PERANCANGAN BEJANA TEKAN((PRESSURE VESSELPRESSURE VESSEL), BERDASARKAN ASME ), BERDASARKAN ASME
CODE SECTION VIIICODE SECTION VIII
ASME International
PengantarPengantar Material Material Pressure VesselPressure Vessel Perancangan (Perancangan (DesignDesign)) Pertimbangam Pertimbangam
Perancangan LainPerancangan Lain Pembuatan (Fabrikasi)Pembuatan (Fabrikasi) Inspeksi dan TestingInspeksi dan Testing
44
Definisi Pressure VesselsDefinisi Pressure Vessels
Wadah fluida yang bertekananWadah fluida yang bertekananDigunakan di beberapa industri, antara Digunakan di beberapa industri, antara lain:lain:– – Perusahaan minyakPerusahaan minyak– – Perusahaan kimiaPerusahaan kimia– – Pembangkit tenagaPembangkit tenaga– – Pabrik pulp dan kertasPabrik pulp dan kertas– – Pabrik makanan, dllPabrik makanan, dll
55
Jenis-jenis pressure vesselJenis-jenis pressure vessel
66
Drum HorisontalDrum Horisontaltumpuan Saddletumpuan Saddle
77
Gambar 2.1
Drum Vertikal tumpuan KakiDrum Vertikal tumpuan Kaki
88Gambar 2.2
1. Sebagian besar head berbentuk kurva lengkung karena alasan kekuatan, tipis dan ekonomi.
2. Bentuk Semi eliptik (Semi-elliptical shape) adalah bentuk yang umum digunakan.
3. Drum kecil vertikal biasanya ditumpu dengan kaki.• Perbandingan maksimum
antara panjang kaki dengan diameter biasanya 2:1.
• Jumlah kaki, ukuram dan detail tambahan tergantung pada besar beban.
Menara Vertikal TinggiMenara Vertikal Tinggi
99Gambar 2.3
1. Nozzel dihubungkan dengan:• Sistem perpipaan• Koneksi instrumen• Manways• Sambungan instrumen
lainnya2. Ujung nozzel biasanya
berbentuk flens.3. Kadangkala nozzel
menjorok ke dalam vessel.
Reaktor VertikalReaktor Vertikal
1010
Gambar 2.4
Tangki BolaTangki BolaPenyimpan (bertekanan)Penyimpan (bertekanan)
1111Gambar 2.5
Vertical Vessel on Lug SupportsVertical Vessel on Lug Supports
1212Gambar 2.6
1 – 10 ft diameter
2:1 to 5:1 height/diameter ratio
Ruang LingkupRuang LingkupASME Code Section VIIIASME Code Section VIII
Section VIII digunakan di seluruh duniaSection VIII digunakan di seluruh dunia
Tujuan: Penyajian syarat minimal untuk Tujuan: Penyajian syarat minimal untuk keamanan konstruksi dan operasikeamanan konstruksi dan operasi
Terdiri dari tiga divisi: 1, 2, dan 3Terdiri dari tiga divisi: 1, 2, dan 3
1313
Section VIII Division 1Section VIII Division 1
15 psig < P ≤ 3000 psig15 psig < P ≤ 3000 psig
Berlaku sampai dengan koneksi pertama ke pipaBerlaku sampai dengan koneksi pertama ke pipa
Pengecualian lainPengecualian lain
– – Peralatan internal (kecuali yang dilas ke vessel)Peralatan internal (kecuali yang dilas ke vessel)
– – Pemanas proses yang menggunakan apiPemanas proses yang menggunakan api
– – Bejana tekan yang bersatu dengan mesinBejana tekan yang bersatu dengan mesin
– – Sistem perpipaanSistem perpipaan
1414
Section VIII, Division 2,Section VIII, Division 2,Aturan AlternatifAturan Alternatif
Ruang lingkup identik dengan divisi 1 tetapi Ruang lingkup identik dengan divisi 1 tetapi berbeda persyaratan dalam hal:berbeda persyaratan dalam hal:
– – Tegangan yang diijinkanTegangan yang diijinkan
– – Perhitungan teganganPerhitungan tegangan
– – PerancanganPerancangan
– – Kontrol kualitasKontrol kualitas
––Fabrikasi dan inspeksiFabrikasi dan inspeksi
Pemilihan antara divisi 1 dan 2 tergantung Pemilihan antara divisi 1 dan 2 tergantung pertimbangan ekonomipertimbangan ekonomi
1515
Division 3, Alternative RulesDivision 3, Alternative RulesHigh Pressure VesselsHigh Pressure Vessels
Applications over 10,000 psiApplications over 10,000 psi
Pressure from external source, processPressure from external source, process
reaction, application of heat, combinationreaction, application of heat, combination
of theseof these
Does not establish maximum pressureDoes not establish maximum pressure
limits of Division 1 or 2 or minimum limitslimits of Division 1 or 2 or minimum limits
for Division 3.for Division 3.
1616
Structure of Section VIII,Structure of Section VIII,Division 1Division 1
Subsection ASubsection A– – Part UG applies to all vesselsPart UG applies to all vesselsSubsection BSubsection B– – Requirements based on fabrication methodRequirements based on fabrication method– – Parts UW (weld), UF (Forged), UB (brazed)Parts UW (weld), UF (Forged), UB (brazed)Subsection CSubsection C– – Requirements based on material classRequirements based on material class– – Parts UCS, UNF, UHA, UCI, UCL, UCD (Cast Parts UCS, UNF, UHA, UCI, UCL, UCD (Cast Ductile Iron), UHT (heat treatment),Ductile Iron), UHT (heat treatment), ULW (layered construction), ULT (low ULW (layered construction), ULT (low temperature)temperature)Mandatory and Nonmandatory AppendicesMandatory and Nonmandatory Appendices
1717
Contoh Mandatory (Wajib)Contoh Mandatory (Wajib)
Rumus-rumus Rancangan tambahanRumus-rumus Rancangan tambahan
Aturan untuk sambungan flens baut, Aturan untuk sambungan flens baut, dengan gasket tipe ringdengan gasket tipe ring
Vessel yang penampangnya bukan Vessel yang penampangnya bukan lingkaranlingkaran
Aturan rancangan untuk sambungan Aturan rancangan untuk sambungan clampclamp
1818
Contoh yang Non-mandatoryContoh yang Non-mandatory
Saran (Saran (good practicegood practice) untuk struktur ) untuk struktur internalinternal
Aturan rancangan tubesheetAturan rancangan tubesheet
dlldll
1919
Kelas BahanKelas Bahan
Material Covering
Code part
Applicable Code
stress value tables
Remarks
Carbon and
low-alloy
steels
UCS Code Section II,
Part D, Table 1A
Basis for establishing stress values—Code Appendix P,UG-23
Low-temperature service requires Pars. UCS-65,UCS-66, UCS-67, UCS-68, UG-84 Code Figs. UCS-66, UCS-66.1,UCS-66.2
In high-temperature operation, creep strength is essential
Design temperature—Code Par. UG-20
Design pressure—Code Par. UG-21, Fn. 8
Temperature above 800°F may cause carbide phase of carbon steel to convert to graphite
Pipe and tubes—Code Pars. UG-8, UG-10, UG-16, UG-31,UCS-9, UCS-27
Creep and rupture properties—Code Par. UCS-151
2020
Kelas Bahan, Kelas Bahan, ((sambungan)sambungan)Material Covering
Code part
Applicable Code
stress value tables
Remarks
Nonferrous
metals
UNF Code Section II,
Part D, Table 1B
Basis for establishing values— Code, Appendix P, UG-23
Metal characteristics—Code
Par. UNF, Appendix NF, NF-1 to NF-14
Low-temperature operation— Code Par. UNF-65
Nonferrous castings—Code Par. UNF-8
High-alloy
steels
Castings
UHA Code Section II,
Part D, Table 1A
Selection and treatment of austenitic chromium–nickel
steels—Code Par. UHA-11, UHA Appendix HA, UHA-100
to UHA-109
Inspection and tests—Code Pars. UHA-34,UHA-50, UHA-
51, UHA-52
Liquid penetrant examination required if shell thickness
exceeds 3⁄4 in—all 36% nickel steel welds—Code Par. UHA-34
Low-temperature service—Code Pars. UHA-51, UG-84
High-alloy castings—Code Pars. UHA-8, UG-7 Code Par. Ug-7
Code Pars. UG-11, UG-24, UCS-8—Code Appendix 7
2121
Kelas Bahan , Kelas Bahan , ((sambungan)sambungan)
Material Covering
Code part
Applicable Code
stress value tables
Remarks
Cast iron
Dual cast iron
UCI
UCI
UCI-23 Vessels not permitted to contain lethal or flammable substances —Code Par. UCI-2
Selection of materials—Code Pars. UCI-5, UCI-12, UG-11,
UCS-10, UCS-11, UCI-3, UCI-1,UG-10
Inspection and tests—Code Pars. UCI-90, UCI-99, UCI-101,UCI-3
Repairs in cast-iron materials— Code Par. UCI-78
Code Pars. UCI-1, UCI-23, UCI 29
Integrally
clad plate,
weld metal
overlay, or
applied
linings
UCL (See Code Pars.
UCL-11, UCL 23.)
Suggest careful study of entire metal UCL section
Selection of materials—Code Pars. UCL-1, UCL-3, UCL 10,
UCS-5, UF-5, ULW-5, UCL-11, UCL-12, UG-10
Qualification of welding procedure—Code Pars. UCL-40 to -46
Post-weld heat treatment—Code Pars. UCL-34, UCS-56 (including cautionary footnote)
Inspection and test—Code Pars.UCL-50, UCL-51, UCL-52
Spot radiography required if cladding is included in computing required thickness—Code Par. UCL-23(c)
Use of linings—Code Par. UG- 26 and Code Appendix F
2222
Kelas Bahan , Kelas Bahan , ((sambungan)sambungan)
Material Covering
Code part
Applicable Code
stress value tables
Remarks
Welded and
seamless pipe
and tubes (carbon
and low alloy
steels)
Welded and
seamless pipe
(high-alloy
steels)
UCS
UHA
Code Section II,
Part D, Table 1A
Code Table 1A
Thickness under internal pressure—Code Par. UG-27
Thickness under external pressure—Code Par. UG-28
Provide additional thickness when tubes are threaded and
when corrosion, erosion, or wear caused by cleaning is expected —Code Par. UG-31
For calculating thickness required, minimum pipe wall thickness is 87.5 percent of nominal wall thickness
30-in maximum on welded pipe made by open-hearth, basic oxygen, or electric-furnace process— Code Par. USC-27
2323
Kelas Bahan , Kelas Bahan , ((sambungan)sambungan)
Material Covering
Code part
Applicable Code
stress value tables
Remarks
Forgings
Low- temperature materials
Layered
Construction
Ferritic steels with tensile
properties
enhanced by
Hea-ttreatment
UF
ULT
ULW
UHT
Code Section II,
Part D, Table 1A
ULT-23
Code Table 1A
Materials—Code Pars. UG-6, UG-7, UG-11, UF-6, UCS-7 and Section II, Part D, Table 1A
Welding—Code Par. UF-32 (see also Section IX Code Par. QW- 250 and Variables, Code Pars. QW-404.12, QW-406.3, QW- 407.2, QW-409.1 when welding forgings)
Operation at very low temperatures, requires use of notch
tough materials
Vessels having a shell and/or heads made up of two or more separate layers—Code Par. ULW-2
Scope—Code Par. UHT-1
Marking on plate or stamping, use “low-stress” stamps—Code Par. UHT-86
2424
Material Selection FactorsMaterial Selection Factors
Strength
Corrosion Resistance
Resistance to Hydrogen Attack
Fracture Toughness
Fabricability
2525
StrengthStrength
Determines required component thicknessDetermines required component thickness
Overall strength determined by:Overall strength determined by:
– – Yield StrengthYield Strength
– – Ultimate Tensile StrengthUltimate Tensile Strength
– – Creep StrengthCreep Strength
– – Rupture StrengthRupture Strength
2626
Corrosion ResistanceCorrosion Resistance
Deterioration of metal by chemical actionDeterioration of metal by chemical action
Most important factor to considerMost important factor to consider
Corrosion allowance supplies additionalCorrosion allowance supplies additional
thicknessthickness
Alloying elements provide additionalAlloying elements provide additional
resistance to corrosionresistance to corrosion
2727
Resistance toResistance toHydrogen AttackHydrogen Attack
At 300 - 400°F, monoatomic hydrogenAt 300 - 400°F, monoatomic hydrogen
forms molecular hydrogen in voidsforms molecular hydrogen in voids
Pressure buildup can cause steel to crackPressure buildup can cause steel to crack
Above 600°F, hydrogen attack causesAbove 600°F, hydrogen attack causes
irreparable damage through componentirreparable damage through component
thicknessthickness
2828
Serangan HidrogenSerangan Hidrogen
Hydrogen permeated into the steel can react with Hydrogen permeated into the steel can react with carbon, resulting in the formation of methane: C(Fe) + carbon, resulting in the formation of methane: C(Fe) + 2H2 <==> CH4.2H2 <==> CH4.The methane is more or less trapped in the metal The methane is more or less trapped in the metal structure and will accumulate in voids in the metal structure and will accumulate in voids in the metal matrix. The gas pressure in these voids can generate matrix. The gas pressure in these voids can generate an internal stress high enough to fissure, crack or an internal stress high enough to fissure, crack or blister the steel. blister the steel. As the reaction that forms methane consumes the As the reaction that forms methane consumes the carbon that is present in the steel, hydrogen attack is carbon that is present in the steel, hydrogen attack is also called "internal also called "internal decarburization".".Hydrogen attack will result in degradation of Hydrogen attack will result in degradation of mechanical properties, as tensile strength and mechanical properties, as tensile strength and ductility drop dramatically, and can lead to failure due ductility drop dramatically, and can lead to failure due to crack formation.to crack formation.
2929
Brittle FractureBrittle Fractureand Fracture Toughnessand Fracture Toughness
Fracture toughness: Ability of material toFracture toughness: Ability of material to
withstand conditions that could causewithstand conditions that could cause
brittle fracturebrittle fracture
Brittle fractureBrittle fracture
– – Typically at “low” temperatureTypically at “low” temperature
– – Can occur below design pressureCan occur below design pressure
– – No yielding before complete failureNo yielding before complete failure
3030
Brittle Fracture andBrittle Fracture andFracture Toughness, cont’dFracture Toughness, cont’d
Conditions required for brittle fractureConditions required for brittle fracture
– – High enough stress for crack initiationHigh enough stress for crack initiation
and growthand growth
– – Low enough material fracture toughnessLow enough material fracture toughness
at temperatureat temperature
– – Critical size defect to act as stressCritical size defect to act as stress
concentrationconcentration
3131
Factors That InfluenceFactors That InfluenceFracture ToughnessFracture Toughness
Fracture toughness varies with:Fracture toughness varies with:- Temperature- Temperature- Type and chemistry of steel- Type and chemistry of steel- Manufacturing and fabrication processes- Manufacturing and fabrication processes
Other factors that influence fracture toughness:Other factors that influence fracture toughness:- Arc strikes, especially if over repaired area- Arc strikes, especially if over repaired area- Stress raisers or scratches in cold formed thick- Stress raisers or scratches in cold formed thick plateplate
3232
Setup Uji Charpy V-NotchSetup Uji Charpy V-Notch
3333
http://www.twi.co.uk/j32k/twiimages/jk71f2.gif
ASME Code andASME Code andBrittle Fracture EvaluationBrittle Fracture Evaluation
Components to considerComponents to consider– – ShellsShells – Nozzles– Nozzles– – ManwaysManways – Tubesheets– Tubesheets– – HeadsHeads – Flanges– Flanges– – Reinforcing padsReinforcing pads – Flat cover plates– Flat cover plates– – Backing stripsBacking strips – Attachments essential– Attachments essential that remain inthat remain in to structural integrity to structural integrity placeplace that are welded to that are welded to
pressure parts pressure parts (contoh:(contoh:
pressure support)pressure support)
3434
Temperatures to ConsiderTemperatures to Consider
Minimum Design Metal TemperatureMinimum Design Metal Temperature
(MDMT)(MDMT)
– – Lowest temperature at which componentLowest temperature at which component
has adequate fracture toughnesshas adequate fracture toughness
Critical Exposure Temperature (CET)Critical Exposure Temperature (CET)
– – Minimum temperature at which significantMinimum temperature at which significant
membrane stress will occurmembrane stress will occur
3535
Simplified ASMESimplified ASMEEvaluation ApproachEvaluation Approach
Material specifications classified intoMaterial specifications classified intoMaterial Groups A through DMaterial Groups A through DImpact test exemption curvesImpact test exemption curves– – For each Material GroupFor each Material Group– – Acceptable MDMT vs. thickness where impactAcceptable MDMT vs. thickness where impact testing not requiredtesting not requiredIf combination of Material Group andIf combination of Material Group and
thickness not exempt, then must impact test at thickness not exempt, then must impact test at CETCET
3636
Material GroupsMaterial Groups
MATERIAL
GROUPAPPLICABLE MATERIALS
Curve A
•All carbon and low alloy steel plates, structural shapes, and bars not listed in Curves B, C & D•SA-216 Gr. WCB & WCC, SA-217 Gr. WC6, if normalized and tempered or water-quenched and tempered
Curve B
•SA-216 Gr. WCA, if normalized and tempered or water-quenched and tempered•SA-216 Gr. WCB & WCC for maximum thickness of 2 in., if produced to fine grain practice and water-quenched and tempered•SA-285 Gr. A & B•SA-414 Gr. A•SA-515 Gr. 60•SA-516 Gr. 65 & 70, if not normalized•Except for cast steels, all materials of Curve A if produced to fine grain practice and normalized which are not included in Curves C & D•All pipe, fittings, forging, and tubing which are not included in Curves C & D
3737
Material Groups, cont’dMaterial Groups, cont’d
MATERIAL GROUP APPLICABLE MATERIALS
Curve C
•SA-182 Gr. 21 & 22, if normalized and tempered•SA-302 Gr. C & D•SA-336 Gr. F21 & F22, if normalized and tempered•SA-387 Gr. 21 & 22, if normalized and tempered•SA-516 Gr. 55 & 60, if not normalized•SA-533 Gr. B & C•SA-662 Gr. A•All material of Curve B if produced to fine grain practice and normalized which are not included in Curve D
Curve D
•SA-203 • SA-537 Cl. 1, 2 & 3
SA-508 Cl. 1 • SA-612, if normalized
• SA-516, if normalized • SA-662, if normalized
• SA-524 Cl. 1 & 2 • SA-738 Gr. A
Bolting and Nuts
See Gambar UCS-66 of the ASME Code Section VIII, Div. 1, for impact
test exemption temperatures for specified material specifications
3838Table 3.1 (Excerpt)
Impact Test Exemption CurvesImpact Test Exemption Curvesfor Carbon and Low-Alloy Steelfor Carbon and Low-Alloy Steel
3939
Gambar 3.1
Additional ASME Code ImpactAdditional ASME Code ImpactTest RequirementsTest Requirements
Required for welded construction over 4 Required for welded construction over 4 in. thick, or nonwelded construction over 6 in. thick, or nonwelded construction over 6 in.in. thick, if MDMT < 120°Fthick, if MDMT < 120°F
Not required for flanges if temperatureNot required for flanges if temperature
≥ ≥ -20°F-20°F
Required if SMYS > 65 ksi unlessRequired if SMYS > 65 ksi unless
specifically exemptspecifically exempt
4040
Additional ASME CodeAdditional ASME CodeImpact Test Requirements, cont’dImpact Test Requirements, cont’d
Not required for impact tested lowNot required for impact tested low
temperature steel specificationstemperature steel specifications
– – May use at impact test temperatureMay use at impact test temperature
30°F MDMT reduction if PWHT P-1 steel30°F MDMT reduction if PWHT P-1 steel
and not required by codeand not required by code
MDMT reduction if calculated stress <MDMT reduction if calculated stress <
allowable stressallowable stress
4141
FabricabilityFabricability
Ease of constructionEase of construction
Any required special fabrication practicesAny required special fabrication practices
Material must be weldableMaterial must be weldable
4242
Maximum Allowable StressMaximum Allowable Stress
Stress: Force per unit area that resists loadsStress: Force per unit area that resists loadsinduced by external forcesinduced by external forcesPressure vessel components designed toPressure vessel components designed tokeep stress within safe operational limitskeep stress within safe operational limitsMaximum allowable stress:Maximum allowable stress:– – Includes safety marginIncludes safety margin– – Varies with temperature and materialVaries with temperature and materialASME maximum allowable stress tables forASME maximum allowable stress tables forpermitted material specificationspermitted material specifications
4343
Maximum AllowableMaximum AllowableStress, cont’dStress, cont’d
4444ASME Maximum Allowable Stress (Table 1A Excerpt)
Gambar 3.2
Maximum AllowableMaximum AllowableStress, cont’dStress, cont’d
4545
ASME Maximum Allowable Stress (Excerpt), cont'dGambar 3.2, cont'd
Material Selection BasedMaterial Selection Basedon Fracture Toughnesson Fracture Toughness
Exercise 1Exercise 1New horizontal vesselNew horizontal vesselCET = - 2°FCET = - 2°FShell and heads: SA-516 Gr. 70Shell and heads: SA-516 Gr. 70Heads hemispherical: ½ in. thickHeads hemispherical: ½ in. thickCylindrical shell: 1.0 in. thickCylindrical shell: 1.0 in. thickNo impact testing specifiedNo impact testing specified Is this correct?Is this correct? If not correct, what should be done?If not correct, what should be done?
4646
Exercise 1 - SolutionExercise 1 - Solution
Must assume SA-516 Gr. 70 not normalized.Must assume SA-516 Gr. 70 not normalized.
Therefore, Curve B material (Ref. Table 3.1).Therefore, Curve B material (Ref. Table 3.1).
Refer to Curve B in Gambar 3.1.Refer to Curve B in Gambar 3.1.
– – ½ in. thick plate for heads: MDMT = -7°F½ in. thick plate for heads: MDMT = -7°F
– – ½ in. thick plate exempt from impact testing½ in. thick plate exempt from impact testing
since MDMT < CETsince MDMT < CET
1 in. shell plate: MDMT = +31°F1 in. shell plate: MDMT = +31°F
– – Not exempt from impact testingNot exempt from impact testing
4747
Exercise 1 - Solution, cont’dExercise 1 - Solution, cont’d
One approach to correct: Impact test 1 in. plateOne approach to correct: Impact test 1 in. plateat -2°F. If passes, material acceptable.at -2°F. If passes, material acceptable.Another approach: Order 1 in. plate normalizedAnother approach: Order 1 in. plate normalized– – Table 3.1: normalized SA-516 is Curve D Table 3.1: normalized SA-516 is Curve D materialmaterial– – Gambar 3.1: 1 in. thick Curve D, MDMT = -Gambar 3.1: 1 in. thick Curve D, MDMT = -30°F30°F– – Normalized 1 in. thick plate exempt fromNormalized 1 in. thick plate exempt from impact testingimpact testing
4848
Exercise 1 - Solution, cont’dExercise 1 - Solution, cont’d
Choice of option based on cost, material Choice of option based on cost, material availability, whether likely that 1 in. thick availability, whether likely that 1 in. thick non-normalized plate would pass impact non-normalized plate would pass impact testingtesting
4949
Design ConditionsDesign Conditionsand Loadingsand Loadings
Determine vessel mechanical designDetermine vessel mechanical design
Design pressure and temperature, otherDesign pressure and temperature, other
loadingsloadings
Possibly multiple operating scenarios toPossibly multiple operating scenarios to
considerconsider
Consider startup, normal operation,Consider startup, normal operation,
anticipated deviations, shutdownanticipated deviations, shutdown
5050
Design PressureDesign Pressure
5151Gambar 4.1
Zones Temperature Zones Temperature pada Vessels Tinggipada Vessels Tinggi
5252Gambar 4.2
Additional LoadingsAdditional Loadings
Weight of vessel and normal contentsWeight of vessel and normal contentsunder operating or test conditionsunder operating or test conditionsSuperimposed static reactions from weightSuperimposed static reactions from weightof attached items (e.g., motors, machinery,of attached items (e.g., motors, machinery,other vessels, piping, linings, insulation)other vessels, piping, linings, insulation)Loads at attached internal components orLoads at attached internal components orvessel supportsvessel supportsWind, snow, seismic reactionsWind, snow, seismic reactions
5353
Additional Loadings, cont’dAdditional Loadings, cont’d
Cyclic and dynamic reactions caused by Cyclic and dynamic reactions caused by pressure or thermal variations, equipment pressure or thermal variations, equipment mounted on vessel, and mechanical loadingsmounted on vessel, and mechanical loadings
Test pressure combined with hydrostatic weightTest pressure combined with hydrostatic weight
Impact reactions (e.g., from fluid shock)Impact reactions (e.g., from fluid shock)
Temperature gradients within vessel component Temperature gradients within vessel component and differential thermal expansion between and differential thermal expansion between vessel componentsvessel components
5454
5555
Weld Joint CategoriesWeld Joint Categories
5656
Gambar 4.3
A : Menahan hoop stress (tegangan keliling/tegak lurus sumbu)B : Menahan longitudinal stress (tegangan searah sumbu)C : sambungan flangeD : sambungan nozzle - shell
Weld TypesWeld Types
5757Gambar 4.4
Weld Joint EfficienciesWeld Joint Efficiencies
5858
Gambar 4.5
Summary ofSummary ofASME Code EquationsASME Code Equations
5959Gambar 4.6
6060
6161
TypicalTypicalFormed Closure HeadsFormed Closure Heads
6262Gambar 4.7
HemisphericalHemisphericalHead to Shell TransitionHead to Shell Transition
6363
Gambar 4.8
Sample Problem 1Sample Problem 1
6464
Gambar 4.9
Sample Problem 1 - SolutionSample Problem 1 - Solution
Required thickness for internal pressure of Required thickness for internal pressure of cylindrical shell (Gambar 4.6):cylindrical shell (Gambar 4.6):
Welds spot radiographed, E = 0.85 (Gambar Welds spot radiographed, E = 0.85 (Gambar 4.5)4.5)S = 14,400 psi for SA- 515/Gr. 60 at 700°F S = 14,400 psi for SA- 515/Gr. 60 at 700°F (Gambar 3.2)(Gambar 3.2)P = 250 psigP = 250 psig
6565
Sample Problem 1Sample Problem 1Solution, cont’dSolution, cont’d
For 6 ft. - 0 in. shellFor 6 ft. - 0 in. shell
r = 0.5D + C = 0.5 x 72 + 0.125 = 36.125 in.r = 0.5D + C = 0.5 x 72 + 0.125 = 36.125 in.
t = tp + c = 0.747 + 0.125t = tp + c = 0.747 + 0.125
t = 0.872 in., including corrosion allowancet = 0.872 in., including corrosion allowance
6666
Sample Problem 1Sample Problem 1Solution, cont’dSolution, cont’d
For 4 ft. - 0 in. shellFor 4 ft. - 0 in. shell
r = 0.5 x 48 + 0.125 = 24.125 in.r = 0.5 x 48 + 0.125 = 24.125 in.
t = 0.499 + 0.125t = 0.499 + 0.125
t = 0.624 in., including corrosion allowancet = 0.624 in., including corrosion allowance
6767
Sample Problem 1Sample Problem 1Solution, cont’dSolution, cont’d
Both heads are seamless, E = 1.0.Both heads are seamless, E = 1.0.
Top HeadTop Head - Hemispherical (Gambar 4.6) - Hemispherical (Gambar 4.6)
r = 24 + 0.125 = 24.125 in.r = 24 + 0.125 = 24.125 in.
t = tt = tpp + c = 0.21 + 0.125 + c = 0.21 + 0.125
t = 0.335 in., including corrosion allowancet = 0.335 in., including corrosion allowance
6868
Sample Problem 1Sample Problem 1Solution, cont’dSolution, cont’d
Bottom Head - 2:1 Semi-Elliptical (Gambar Bottom Head - 2:1 Semi-Elliptical (Gambar 4.6)4.6)
D = 72 + 2 x 0.125 = 72.25 in.D = 72 + 2 x 0.125 = 72.25 in.
t = 0.628 + 0.125t = 0.628 + 0.125
t = 0.753 in., including corrosion allowancet = 0.753 in., including corrosion allowance
6969
Design For External PressureDesign For External Pressureand Compressive Stressesand Compressive Stresses
Compressive forces caused by deadCompressive forces caused by dead
weight, wind, earthquake, internal vacuumweight, wind, earthquake, internal vacuum
Can cause elastic instability Can cause elastic instability (buckling`/tekukan)(buckling`/tekukan)
Vessel must have adequate stiffnessVessel must have adequate stiffness
– – Extra thicknessExtra thickness
– – Circumferential stiffening ringsCircumferential stiffening rings
7070
Design For External Pressure andDesign For External Pressure andCompressive Stresses, cont’dCompressive Stresses, cont’d
ASME procedures for cylindrical shells,ASME procedures for cylindrical shells,
heads, conical sections, as function of:heads, conical sections, as function of:
– – Material Material – Temperature– Temperature
– – DiameterDiameter – Thickness– Thickness
– – Unstiffened lengthUnstiffened length
7171
Stiffener RingsStiffener Rings
7272
Gambar 4.10
Sample Problem 2 - SolutionSample Problem 2 - Solution
7373
Gambar 4.11
A tall cylindrical tower is being supplied. The geometry and design conditions are specified in Figure 4.11. The vendor has proposed that the wall thickness of this tower be 7/16 in., and no stiffener rings have been specified. Is the 7/16 in. thickness acceptable for external pressure? If it is not acceptable, what minimumthickness is required? Round your answer upward to the nearest 1/16 in.
7474
L : tangent to tangentSeam
Seam
Sample Problem 2 - SolutionSample Problem 2 - Solution
Calculate L and DCalculate L and Doo of cylindrical shell. of cylindrical shell.
L = Tangent Length + 2 x 1/3 (Head Depth)L = Tangent Length + 2 x 1/3 (Head Depth)L = 150 x 12 + 2/3 x (48/4) = 1,808 in.L = 150 x 12 + 2/3 x (48/4) = 1,808 in.Do = 48 + 2 x 7/16 = 48.875 in. (48 : ID)Do = 48 + 2 x 7/16 = 48.875 in. (48 : ID)
Determine L/DDetermine L/Doo and D and Doo/t/tAccount for corrosion allowance: (CA=0,0625”=1/16)Account for corrosion allowance: (CA=0,0625”=1/16)
t = 7/16 – 1/16 = 6/16 = 0.375 in.t = 7/16 – 1/16 = 6/16 = 0.375 in.Do/t = 48.875 / 0.375 = 130Do/t = 48.875 / 0.375 = 130L/Do = 1808 / 48.875 = 37L/Do = 1808 / 48.875 = 37
7575
Sample Problem 2Sample Problem 2Solution, cont’dSolution, cont’d
Determine A.Determine A.
Use Gambar 4.12, DUse Gambar 4.12, Doo/t, and L/D/t, and L/Doo..
Note: If L/DNote: If L/Doo > 50, use L/D > 50, use L/Doo = 50. = 50.
For L/DFor L/Doo < 0.05, use L/D < 0.05, use L/Doo = 0.05 = 0.05
7676
Sample Problem 2Sample Problem 2Solution, cont’dSolution, cont’d
7777
Factor A
Gambar 4.12
Sample Problem 2Sample Problem 2Solution, cont’dSolution, cont’d
7878
Factor B
Gambar 4.13
Sample Problem 2Sample Problem 2Solution, cont’dSolution, cont’d
Calculate maximum allowable external Calculate maximum allowable external pressurepressure
Where:Where:E = Young's modulus of elasticityE = Young's modulus of elasticityE = 27 x 10E = 27 x 1066 psi (Gambar 4.13) at T = psi (Gambar 4.13) at T = 500°F500°F
PPaa = 9 psi = 9 psi7979
Karena Factor A terletak di sebelah kiri kurva, maka tidak Faktor B tidak ada, sehingga untuk menghitung Pressure, digunakan rumus di samping
Sample Problem 2Sample Problem 2Solution, cont’dSolution, cont’d
Since Pa < 15 psi, 7/16 in. thickness not Since Pa < 15 psi, 7/16 in. thickness not sufficientsufficient
Assume new thickness = 9/16 in.,Assume new thickness = 9/16 in.,
corroded thickness = 1/2 in.corroded thickness = 1/2 in.
8080
Exercise 2 - RequiredExercise 2 - RequiredThickness for Internal PressureThickness for Internal PressureInside Diameter Inside Diameter : 10’ - 6”: 10’ - 6”Design Pressure Design Pressure : 650 psig: 650 psigDesign Temperature Design Temperature : 750°F: 750°FShell & Head Material Shell & Head Material : SA-516 Gr. 70: SA-516 Gr. 70Corrosion Allowance Corrosion Allowance : 0.125 in.: 0.125 in.2:1 Semi-Elliptical heads, seamless2:1 Semi-Elliptical heads, seamless100% radiography100% radiographyVessel in vapor service (no liquid loading)Vessel in vapor service (no liquid loading)
8181
Exercise 2 - SolutionExercise 2 - SolutionFor shell For shell
P = 650 psigP = 650 psigr = 0.5 x D + CAr = 0.5 x D + CA= (0.5 x 126) + 0.125 = 63.125 in.= (0.5 x 126) + 0.125 = 63.125 in.
S = 16,600 psi, Gambar 3.3 for SA-516 Gr. 70S = 16,600 psi, Gambar 3.3 for SA-516 Gr. 70E = 1.0, Gambar 4.8 for 100% radiographyE = 1.0, Gambar 4.8 for 100% radiography
8282
Exercise 2 - Solution, cont’dExercise 2 - Solution, cont’d
Add corrosion allowanceAdd corrosion allowance
ttpp = 2.53 + 0.125 = 2.655 in. = 2.53 + 0.125 = 2.655 in.
For the headsFor the heads
Add corrosion allowanceAdd corrosion allowance
ttpp = 2.23 + 0.125 = 2.355 in. = 2.23 + 0.125 = 2.355 in.
8383
Reinforcement of OpeningsReinforcement of Openings
Simplified ASME rules - Area replacementSimplified ASME rules - Area replacement
Metal used to replace that removed:Metal used to replace that removed:
- Must be equivalent in metal area- Must be equivalent in metal area
- Must be adjacent to opening- Must be adjacent to opening
8484
Kompensasi (Kompensasi (CompensationCompensation))
Compensation, or Compensation, or reinforcement, reinforcement, is the is the provision of extra stress-transmitting area provision of extra stress-transmitting area in the wall of a cylinder or shell when in the wall of a cylinder or shell when some area is removed by boring a hole for some area is removed by boring a hole for branch attachment.branch attachment.
The principle is sketched. The principle is sketched.
8585
Kompensasi (Kompensasi (CompensationCompensation))
The left sketch shows part of a cylinder's The left sketch shows part of a cylinder's longitudinal section; the major circumferential longitudinal section; the major circumferential stress acts across the critical longitudinal plane. stress acts across the critical longitudinal plane. The nominal thickness is T, and a hole of The nominal thickness is T, and a hole of diameter Ddiameter Dbb is bored - dimensions being is bored - dimensions being
reckoned in the fully corroded condition. The reckoned in the fully corroded condition. The stress-transmitting area removed is A = Dstress-transmitting area removed is A = Dbbt t
where the calculation thickness t is given by where the calculation thickness t is given by ( ( 11). ).
8686
Kompensasi (Kompensasi (CompensationCompensation))
The figure on the right demonstrates The figure on the right demonstrates compensation for area removal by providing compensation for area removal by providing equal area for alternate force paths in otherwise equal area for alternate force paths in otherwise unused material of cylinder and branch. Not all unused material of cylinder and branch. Not all the branch wall can be devoted to compensation the branch wall can be devoted to compensation since the internally pressurised branch is a since the internally pressurised branch is a cylinder in its own right, with calculation and cylinder in its own right, with calculation and nominal thicknesses, tnominal thicknesses, tbb and T and Tbb, determined in , determined in
a manner identical to the main shell. a manner identical to the main shell.
8787
Kompensasi (Kompensasi (CompensationCompensation))
Provided that the longitudinal welds in both shell Provided that the longitudinal welds in both shell and branch do not lie in the critical longitudinal and branch do not lie in the critical longitudinal planeplane, , then - from a compensation point of view - both t then - from a compensation point of view - both t and tand tbb would be reckoned from ( would be reckoned from ( 11) with η = 1. The ) with η = 1. The
thickness differences ( T - t ) and ( Tthickness differences ( T - t ) and ( Tbb - t - tbb ) contribute ) contribute
to compensation - though reinforcement is ineffective to compensation - though reinforcement is ineffective beyond the limits Lbeyond the limits Lnn normal to the vessel wall, and L normal to the vessel wall, and Lpp
from the branch centreline parallel to the wall, as shown from the branch centreline parallel to the wall, as shown below for a set-in branch :-below for a set-in branch :-
8888
Kompensasi (Kompensasi (CompensationCompensation))
8989
Kompensasi (Kompensasi (CompensationCompensation))
9090
AS 1210 gives the limits as :- AS 1210 gives the limits as :- LLnn = maximum [ 0.8 ( D = maximum [ 0.8 ( DbbTTbb ) )1/21/2 + T + Trr , minimum , minimum
( 2.5T, 2.5T( 2.5T, 2.5Tbb + T + Trr ) ] ) ]
or ( D or ( DbbT )T )1/21/2 for a flanged-in head for a flanged-in head
LLpp = maximum [ D = maximum [ Dbb , D , Dbb/2 + T + T/2 + T + Tbb + 2c ] + 2c ]
Kompensasi (Kompensasi (CompensationCompensation))
Usually the first of the LUsually the first of the Lpp limits, D limits, Dbb, controls. , controls.
However However a compensating area cannot a compensating area cannot contribute to more than one branchcontribute to more than one branch, so if the , so if the spacing of two branches Dspacing of two branches Db1b1 and D and Db2b2 is less is less
than ( Dthan ( Db1b1+ D+ Db2b2 ), then by proportion L ), then by proportion Lp1p1 = D = Db1b1 . .
spacing/( Dspacing/( Db1b1+ D+ Db2b2 ). ).
9191
Kompensasi (Kompensasi (CompensationCompensation))
Furthermore, if the branch is attached to a dished Furthermore, if the branch is attached to a dished end, then no compensation area is effective if it end, then no compensation area is effective if it lies outside the aforementioned 80% limits. If the lies outside the aforementioned 80% limits. If the head is torispherical, the hole should lie in the head is torispherical, the hole should lie in the spherical portion and t will be given by ( spherical portion and t will be given by ( vv). If the ). If the head is ellipsoidal, then AS 1210 defines an head is ellipsoidal, then AS 1210 defines an equivalent sphere for the application of ( equivalent sphere for the application of ( vv), since ), since the hole will not lie close to the rim region of sharp the hole will not lie close to the rim region of sharp curvature which dictates the thickness via the curvature which dictates the thickness via the stress concentration factor in ( stress concentration factor in ( viivii). ).
9292
Kompensasi (Kompensasi (CompensationCompensation))
Within the LWithin the Lnn, L, Lpp limits, compensation requires limits, compensation requires
that :- that :-
AA11 + A + A22 + A + A33 + A + A44 + A + A55 ≥ A = D ≥ A = Dbbt t
The inward protrusion '3' is subjected to The inward protrusion '3' is subjected to corrosion on three surfaces but there is no corrosion on three surfaces but there is no pressure differential across it; it will not exist for pressure differential across it; it will not exist for a set-on branch. The sketch indicates that:- a set-on branch. The sketch indicates that:-
AA11 = ( 2L = ( 2Lpp - D - Dbb - 2t - 2tbb ) ( T - t ) ; A ) ( T - t ) ; A22 = 2L = 2Lnn ( (
TTbb - t - tbb ) etc. ) etc.
9393
Cross-Sectional View ofCross-Sectional View ofNozzle OpeningNozzle Opening
9494
Gambar 4.14
Nozzle Design ConfigurationsNozzle Design Configurations
9595Gambar 4.15
Additional ReinforcementAdditional Reinforcement
Necessary if insufficient excess thicknessNecessary if insufficient excess thickness
Must be located within reinforcement zoneMust be located within reinforcement zone
Allowable stress of reinforcement padAllowable stress of reinforcement pad
should be ≥ that of shell or headshould be ≥ that of shell or head
Additional reinforcement sourcesAdditional reinforcement sources
– – PadPad
– – Additional thickness in shell or lower part ofAdditional thickness in shell or lower part of
nozzlenozzle
9696
Sample Problem 3Sample Problem 3
9797
Gambar 4.16
Sample Problem 3 - SolutionSample Problem 3 - Solution
Calculate required reinforcement area, ACalculate required reinforcement area, A
A = dtA = dtrrFF
Where:Where:d =d = Finished diameter of circular opening, orFinished diameter of circular opening, or
finished dimension of nonradial opening infinished dimension of nonradial opening inplane under consideration, in.plane under consideration, in.
ttrr = Minimum required thickness of shell using = Minimum required thickness of shell using
E = 1.0E = 1.0F = Correction factor, normally 1.0F = Correction factor, normally 1.0
9898
Sample Problem 3 -Sample Problem 3 -Solution, cont’dSolution, cont’d
Calculate diameter, d.Calculate diameter, d.d = Diameter of Opening – 2 (Thickness +d = Diameter of Opening – 2 (Thickness +
Corrosion Allowance)Corrosion Allowance)d = 8.625 – 1.0 + .125 = 7.750 in.d = 8.625 – 1.0 + .125 = 7.750 in.
Calculate required shell thickness, tCalculate required shell thickness, trr (Gambar 4.6)(Gambar 4.6)
ttrr = 0.487 in. = 0.487 in.
Assume F = 1.0Assume F = 1.0
9999
Sample Problem 3 -Sample Problem 3 -Solution, cont’dSolution, cont’d
Calculate ACalculate A
A = dtA = dtrrFF
A = (8.625 - 1.0 + 0.125) x 0.487 x 1A = (8.625 - 1.0 + 0.125) x 0.487 x 1
= 3.775 in.= 3.775 in.22
Calculate available reinforcement area in vesselCalculate available reinforcement area in vessel
shell, Ashell, A11, as larger of A, as larger of A1111 or A or A1212
AA1111 = (E = (Ellt - Ftt - Ftrr)d)d
AA1212 = 2 (E = 2 (Ellt-Ftt-Ftrr)(t + t)(t + tnn))
100100
Sample Problem 3 -Sample Problem 3 -Solution, cont’dSolution, cont’d
WhereWhere::
EEll = 1.0 when opening is in base plate away from welds, = 1.0 when opening is in base plate away from welds,or when opening passes through circumferentialor when opening passes through circumferential
joint in shell (excluding head to shell joints).joint in shell (excluding head to shell joints).EEll = ASME Code joint efficiency when any part of = ASME Code joint efficiency when any part of
opening passes through any other welded joint.opening passes through any other welded joint.F = 1 for all cases except integrally reinforced nozzlesF = 1 for all cases except integrally reinforced nozzles
inserted into a shell or cone at angle to vesselinserted into a shell or cone at angle to vessellongitudinal axis. See Fig. UG-37 for this speciallongitudinal axis. See Fig. UG-37 for this special
case.case.ttnn = Nominal thickness of nozzle in corroded condition, = Nominal thickness of nozzle in corroded condition, in.in.
101101
Sample Problem 3 -Sample Problem 3 -Solution, cont’dSolution, cont’d
AA1111 = (E= (Ellt - Ftt - Ftrr)d)d
= (0.5625 - 0.0625 - 0.487) x 7.75= (0.5625 - 0.0625 - 0.487) x 7.75= 0.1 in.= 0.1 in.22
AA1212 = 2 (E= 2 (Ellt - Ftt - Ftrr) (t + t) (t + tnn))
= 2(0.5625-0.0625-0.487)x(0.5625-0.0625+0.5 -= 2(0.5625-0.0625-0.487)x(0.5625-0.0625+0.5 -0.0625)0.0625)
= 0.0243 in.= 0.0243 in.22
Therefore,Therefore,
AA11 = 0.1 in.= 0.1 in.22 available reinforcement in shell available reinforcement in shell
102102
Sample Problem 3 -Sample Problem 3 -Solution, cont’dSolution, cont’d
Calculate reinforcement area available in Calculate reinforcement area available in nozzle wall, Anozzle wall, A22, as smaller of A, as smaller of A2121 or A or A2222..
AA2121 = (t = (tnn-t-trnrn) 5t) 5t
AA2222 = 2 (t = 2 (tnn-t-trnrn) (2.5 t) (2.5 tnn + t + tee))
103103
Sample Problem 3 -Sample Problem 3 -Solution, cont’dSolution, cont’d
Where:Where:
ttrnrn = Required thickness of nozzle wall, in.= Required thickness of nozzle wall, in.
r r = Radius of nozzle, in.= Radius of nozzle, in.
ttee = 0 if no reinforcing pad.= 0 if no reinforcing pad.
ttee = Reinforcing pad thickness if one installed, = Reinforcing pad thickness if one installed,
in.in.
ttee = Defined in Gambar UG-40 for self-= Defined in Gambar UG-40 for self-
reinforcedreinforced
nozzles, in.nozzles, in.104104
Sample Problem 3 -Sample Problem 3 -Solution, cont’dSolution, cont’d
Calculate required nozzle thickness, trn Calculate required nozzle thickness, trn (Gambar 4.6)(Gambar 4.6)
105105
Sample Problem 3 -Sample Problem 3 -Solution, cont’dSolution, cont’d
Calculate ACalculate A22..
AA2121 = (t= (tnn - t - trnrn)5t)5t= (0.5 - 0.0625 - 0.0784) x 5 (0.5625 - 0.0625)= (0.5 - 0.0625 - 0.0784) x 5 (0.5625 - 0.0625)= 0.898 in.= 0.898 in.22
AA2222 = 2 (t= 2 (tnn - t - trnrn) (2.5 t) (2.5 tnn + t + tee))= 2 (0.5 - 0.0625 - 0.0784) [2.5 x (0.5 - 0625) + 0]= 2 (0.5 - 0.0625 - 0.0784) [2.5 x (0.5 - 0625) + 0]= 0.786 in.= 0.786 in.22
Therefore,Therefore,
AA22 = 0.786 in.= 0.786 in.22 available reinforcement in nozzle. available reinforcement in nozzle.
106106
Sample Problem 3 -Sample Problem 3 -Solution, cont’dSolution, cont’d
Determine total available reinforcement area, ADetermine total available reinforcement area, ATT;;
compare to required area.compare to required area.
AATT = A = A11 + A + A22 = 0.1 + 0.786 = 0.886 in. = 0.1 + 0.786 = 0.886 in.22
AATT < A, nozzle not adequately reinforced, < A, nozzle not adequately reinforced, reinforcement pad required.reinforcement pad required.
Determine reinforcement pad diameter, DDetermine reinforcement pad diameter, Dpp..
AA55 = A - A = A - ATT
AA55 = (3.775 - 0.886) = 2.889 in. = (3.775 - 0.886) = 2.889 in.22
107107
Sample Problem 3 -Sample Problem 3 -Solution, cont’dSolution, cont’d
Calculate DCalculate Dpp
ttee = 0.5625 in. (reinforcement pad thickness)= 0.5625 in. (reinforcement pad thickness)
AA55 = [D= [Dpp - (d + 2 t - (d + 2 tnn)] t)] tee
2.889 = [D2.889 = [Dpp - (7.75 + 2(0.5 - 0.0625)] 0.5625 - (7.75 + 2(0.5 - 0.0625)] 0.5625
DDpp = 13.761 in. = 13.761 in.
Confirm DConfirm Dpp within shell reinforcement zone, 2d within shell reinforcement zone, 2d
2d 2d = 2 x 7.75 = 15.5 in.= 2 x 7.75 = 15.5 in.
Therefore, DTherefore, Dpp = 13.761 in. acceptable = 13.761 in. acceptable
108108
Flange RatingFlange Rating
Based on ASME B16.5Based on ASME B16.5
Identifies acceptable pressure/temperature Identifies acceptable pressure/temperature combinationscombinations
Seven classesSeven classes
(150, 300, 400, 600, 900, 1,500, 2,500)(150, 300, 400, 600, 900, 1,500, 2,500)
Flange strength increases with class numberFlange strength increases with class number
Material and design temperature combinations Material and design temperature combinations without pressure indicated not acceptablewithout pressure indicated not acceptable
109109
Material Specification ListMaterial Specification List
110110
Gambar 4.17
ASME B16.5, Table 1a, Material Specification List (Excerpt)
Pressure-Temperature RatingsPressure-Temperature Ratings
111111
Gambar 4.18
Sample Problem 4Sample Problem 4
Determine Required Flange RatingDetermine Required Flange Rating
Pressure Vessel Data:Pressure Vessel Data:
Shell and HeadsShell and Heads : SA-516 Gr.70: SA-516 Gr.70
FlangesFlanges : SA-105: SA-105
Design Temperature: 700°FDesign Temperature: 700°F
Design PressureDesign Pressure : 275 psig: 275 psig
112112
Sample Problem 4 - SolutionSample Problem 4 - Solution
Identify flange material specification SA-105Identify flange material specification SA-105From Gambar 4.17, determine Material Group From Gambar 4.17, determine Material Group No.No.Group 1.1Group 1.1From Gambar 4.18 with design temperature andFrom Gambar 4.18 with design temperature andMaterial Group No. determined in Step 3Material Group No. determined in Step 3– – Intersection of design temperature with Material GroupIntersection of design temperature with Material Group
No. is maximum allowable design pressure for theNo. is maximum allowable design pressure for the flange Classflange Class
113113
Sample Problem 4 -Sample Problem 4 -Solution, cont’dSolution, cont’d
– – Table 2 of ASME B16.5, design information forTable 2 of ASME B16.5, design information for
all flange Classesall flange Classes
– – Select lowest Class whose maximumSelect lowest Class whose maximum
allowable design pressure ≥ required designallowable design pressure ≥ required design
pressure.pressure.
At 700°F, Material Group 1.1: Lowest Class thatAt 700°F, Material Group 1.1: Lowest Class that
will accommodate 275 psig is Class 300.will accommodate 275 psig is Class 300.At 700°F, Class 300 flange of Material GroupAt 700°F, Class 300 flange of Material Group
1.1: Maximum design pressure = 535 psig.1.1: Maximum design pressure = 535 psig.
114114
Flange DesignFlange Design
Bolting requirementsBolting requirements
– – During normal operation (based on design During normal operation (based on design
conditions)conditions)
– – During initial flange boltup (based on stress During initial flange boltup (based on stress
necessary to seat gasket and form tight sealnecessary to seat gasket and form tight seal
115115
Flange Loads and Moment ArmsFlange Loads and Moment Arms
116116
Gambar 4.19
Stresses inStresses inFlange Ring and HubFlange Ring and Hub
Calculated using:Calculated using:
– – Stress factors (from ASME code)Stress factors (from ASME code)
– – Applied momentsApplied moments
– – Flange geometryFlange geometry
Calculated for:Calculated for:
– – Operating caseOperating case
– – Gasket seating caseGasket seating case
117117
Flange Design andFlange Design andIn-Service PerformanceIn-Service Performance
Factors affecting design and performanceFactors affecting design and performance
ASME Code m and y parameters.ASME Code m and y parameters.
Specified gasket widths.Specified gasket widths.
Flange facing and nubbin width, wFlange facing and nubbin width, w
Bolt size, number, spacingBolt size, number, spacing
118118
ASME Code m and y FactorsASME Code m and y Factors
119119
Gambar 4.20
ASME Code Gasket WidthsASME Code Gasket Widths
120120
Gambar 4.21
ASME Code Gasket Widths(Table 2-5.2 excerpt)
Gasket Materials and Gasket Materials and Contact FacingsContact Facings
121121
Gambar 4.22
Maximum AllowableMaximum AllowableWorking Pressure (MAWP)Working Pressure (MAWP)
Maximum permitted gauge pressure at top ofMaximum permitted gauge pressure at top ofvessel in operating position for designatedvessel in operating position for designatedtemperaturetemperature
MAWP ≥ Design PressureMAWP ≥ Design Pressure Designated Temperature = Design TemperatureDesignated Temperature = Design Temperature Vessel MAWP based on weakest componentVessel MAWP based on weakest component
– – Originally based on new thickness less corrosionOriginally based on new thickness less corrosion allowanceallowance– – Later based on actual thickness less future corrosionLater based on actual thickness less future corrosion allowance neededallowance needed
122122
Local LoadsLocal Loads
Piping systemPiping system
Platforms, internals, attached equipmentPlatforms, internals, attached equipment
Support attachmentSupport attachment
123123
Types of Vessel InternalsTypes of Vessel Internals
TraysTrays
Inlet DistributorInlet Distributor
Anti-vortex baffleAnti-vortex baffle
Catalyst bed grid and support beamsCatalyst bed grid and support beams
Outlet collectorOutlet collector
Flow distribution gridFlow distribution grid
Cyclone and plenum chamber systemCyclone and plenum chamber system
124124
ASME Code andASME Code andVessel InternalsVessel Internals
Loads applied from internals on vessel to Loads applied from internals on vessel to be considered in designbe considered in design
Welding to pressure parts must meet Welding to pressure parts must meet ASME CodeASME Code
125125
Corrosion AllowanceCorrosion AllowanceFor Vessel InternalsFor Vessel Internals
Removable internals: CA = CA of shellRemovable internals: CA = CA of shell
– – Costs lessCosts less
– – Easily replacedEasily replaced
Non-removable internals: CA = 2 (CA of Non-removable internals: CA = 2 (CA of shell)shell)
– – Corrosion occurs on both sidesCorrosion occurs on both sides
126126
Typical Head-to-Shell TransitionsTypical Head-to-Shell Transitions
127127
Gambar 6.1
Typical Shell TransitionsTypical Shell Transitions
128128
Gambar 6.2
Nozzle Neck AttachmentNozzle Neck Attachmentto Thinner Pipeto Thinner Pipe
129129
Gambar 6.3
Stiffener Ring AttachmentStiffener Ring Attachment
130130
Gambar 6.4
Post Weld Heat TreatmentPost Weld Heat Treatment
Restores material propertiesRestores material properties
Relieves residual stressesRelieves residual stresses
ASME Code PWHT requirementsASME Code PWHT requirements
– – Minimum temperature and hold timeMinimum temperature and hold time
– – Adequate stress reliefAdequate stress relief
– – Heatup and cooldown ratesHeatup and cooldown rates
131131
ASME Reference ChartASME Reference Chart
132132