TaiLieuCauTao1

7/29/2019 TaiLieuCauTao1

1/151

TRNG I HC BCH KHOA H NI

VI

N C

KH

NG L

C

B MN T V XE CHUYN DNG

TI LIU

PHC V MN HC

CU TO T 1

(Dng cho SV K52)

BCH KHOA 2010


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M u

Nhim v ca sinh vin:

D l

Bi tp, thc hnh

nh gi kt qu: KT/BT(0.3)-T(TN/TL:0.7)

im qu trnh: trng s 0.3

Bi tp lm y (chm im bi tp)

o n n p n

Kim tra gia k

.

Ti liu hc tp:

Sch io trnh chnh: Kt cu t Nh xut bn Bch KhoaH Ni, 2010.

Vi nt lch s

cng nghip t

- t l g?- Bn bit g v t?

- Hin nay, cng nghip t l mt trong nhng ngnh cngn hi ln nht trn th ii. M Nh t c Hn uc TQ

- Ti Nht khong 5 triu ngi lm vic phc v cho ngnh.

- Ti M, khong 12 triu ngi lm vic trong ngnh t,khong 1 triu ngi lm dch v k thut cho t; 1 ngil r t cn 2 0 n i lm vi c theo anh ta.

-Ti VN c rt nhiu trngH, C, Trng Ngho to.

?? Thc trng v tng lai ca nn cng nghip t VN


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Vi nt lch scng nghip t

Vi nt lch s

cng nghip t


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Vi nt lch scng nghip t

- Nm 1885-1886 c coi l nm ra i ca chic t utin ti c, do Karl Benz ch to-

Cu trc ca xe lun c hon thin nhm nng cao cctnh nng k thut v s dng: tin nghi, tc , an ton ca

- 1934: AT

- 1971: ABS

- :

- 1980: Airbag

- 1986: 4WS th h mi- 1990: VVT

- 2001: Direct EFI-

Ngy nay, cc thut ng kiu VSC, ESP, Active system, by-wire control tr nn rt ph bin

Chng 1: Cu to chung t1. Cu to chung ca t


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1. Cu to chung ca t

2. Phn loi teo c ng ng:- Xe du lch- Xe khch- Xe ti- Xe chuyn dng

a) Sedan; b) cupe;c) Combi;

d) Cabriolet;

e roadster f t

con a dng;g) Combi ln;

-

dng


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Phn loi t

a) t ti nh thng kn b) t ti nha dng

c) t ti a dng d) t ti chuyn dng

e) t ti thng kn f) t ko (u ko)

Phn loi t


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Phn loi t

Theo tiu chun chu u:

- Loi M: t ch ngi- Loi N: t ch hng- o : o n xe

- Lo i M1: t ch n i n 9 c h khi l nton b


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Phn loi t

- Loi O1:on xe t ch hng c khi lng- = ,

- Lo i O2:on xe t ch hn c khi l n ton bca r-moc t 0,75 tn n 3,5 tn

- o : o n xe c ng c ngton b ca r-moc t 3,5 tn n 10 tn

- Loi O4:on xe t ch hng c khi lngton b ca r-moc trn 10 tn

?? ngha ca vic phn loi t

Phn loi tCng thc bnh xe:4x2

6x46x68x48x6

?? Gii thch cc cng thc bnh xe


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3. B tr chung ca t

B tr chung ca t l b tr cc phn, h thng ca t

B tr chun ca t cn:

- m bo kh nng hot ng tt nht ca ccphn, h thng v ton b t;

- m bo kch thc gn, to s phn b khilng ln cc cu hp l, thun li trong ch tov b o dng, s a cha

?? Cch b tr chungnh hng ti kt cu v shotng ca t ntn

B tr chung ca tB tr chung ca t con

- ng ct trc, c u sau chng:- ng ct trc, cu trc chng:- n c t sau cu sau ch n :- ng ct trc, hai cu chng:- ng ct sau, hai cu chng:

?? Phng n b tr no trn y ph bin nht. Ti sao.


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B tr chung ca t

B tr chung ca t khch

-- ng ct sau

B tr chung t ti

- ng ct trc bung li- ng ct di bung li- ng ct sau bung li, di thng hng

?? Phng n b tr no trn y ph bin nht. Ti sao.


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Chng 2: NGUYN L LM VIC C BNC A NG C T TRONG

2.1. Cc loi ng c dng trn t- ng c nhit: l loi ng c bi n i nhit nng thnh c

nng.ng c nhit bao gm cc loi ng c t trong, ngc phn lc, ng c hi nc, tuc bin kh

- ng c in: l ng c s dng in nng to r a cnng. Gm ng c in mt chiu v ng c in xoayc u.

?? So snh ng c t trong v ng c in v: tnh phbin trn t, tnh thn thin, hiu sut, tnh tin dng.??So snh n c in 1 chiu v xoa chiu trn t v: tnh hbin v tnh tin dng.??Xu hng pht trin ca ng c t

2.2. ng ct trong

ng c t trong l loing c m qu trnh chy

cng c hc c thchin trong bung kn.

c phn bit thnh:

- ng c pt-tng tnh tin(ng c pt-tng)- ng c pt-tng quay n c Van-ken ha n

c r-to).

?? Cc phng n btrng cpt-tng?? Phng n btr no thng sdng cho ng c t


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2.3. CC KHI NIM C BN V THNG S CHNH CACT

- C cu trc khuu thanhtruyn

- im cht trn v im chtdi

- C cu phi kh S

- n r n p ng

- K, ng c 4 k v 2 k

- Bung t

- c c u ph i kh

CC KHI NIM C BN V THNG S CHNH CACT

- Th tch bung t Va;

- Th tch lm vic ca xian

- Th tch lm vic ca ngc

S

- T s nn ca ng c

- S xi lanh ca ng c- Cng sut ln nht cang c v tc ng ctn n

- M men xon ln nht cang c v tc tng ng

- Sut tiu th nhin liu


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2.4. Nguyn l lm vic ca ng c 4 k (t)

2.4. Nguyn l lm vic ca ng c 4 k (t)


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2.6. Nguyn l lm vic ca ng c 2 k

- Hnh trnh piston i xung:

- Hnh trnh piston i ln:

?? So snh ng cvi ng c4 k v: cng sut, hiu sut, tnh phbin

2.7.ng c 4 k nhiu xi lanh

xi lanh 4xi lanh 3xi lanh 2xi lanh 1

?? Ti sao trn t sdngng cnhiu xi lanh?? Kt cu v NLLV ca cc xi lanh ca mtC c khc nhau khn?? Gc lch pha lm vic ca cc xi lanh l g?? Thtnca ng cv nguyn tc btr thtn


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2.7.ng c 4 k nhiu xi lanh (t)

- m bo cho m men ca ng c pht ra trong mt chutrnh lm vic l ng u nh t. => Gc l ch pha lm vic gia

hai xi lanh lm vic lin tip c xc nh ntn?

- khng ti trng tp trung qu nhiu vo mt hay mt s trc no . => Th t n c b tr theo cc quy lut

V d: C 4 xi lanh: 1-3-4-2 hoc 1-2-4-3.C 6 xi lanh: 1-5-3-6-2-4,C 8 xi lanh ch V: 1-5-4-2-6-3-7-8.

- tr c khu u cn c d n n l c h c h l nhm mbo cn bng tt nht. =>Nhm mc ch g?



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Bng trng thi lm vic ca cc xi lanh

o ng g c quay

trc khuu (o

)

- - - -

an n

Xi lanh 2 Nn N X Ht

Xi lanh 3 X Ht Nn N

?? Thc tcc pha lm vic ca ng cc ko di nhnhau khng

2.8.c tnh tc ca ng ct trong

?? Phn bitc tnh ngoi v c tnh cc b ca ng c?? So snh c tnh ca hailoaij ng c: xng v diesel


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2.9.ng c pt-tng quay

?? So snh ng cpt tng tnh tin v ng cpt tng quay vt c v tu i th

2.9.ng c pt-tng quay (t)

o s n ng cp t tng tn ti n v ng cp t tng quay vcng sut


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2.9.ng c pt-tng quay (t)

2.10. Cu to ng c t

C u to chung c a ng c t trong bao g m nhng bphn chnh nh sau

- C cu trc khuu thanh truyn: chc nng?- C cu phi kh: chc nng?-

- H thng nh la: chc nng?

- H thng bi trn: chc nng?- ng m m : c c nng?- H thng khi ng: chc nng?


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3.2. Np my

?? Chc nn?? Vt liu?? Kt cu

3.2. Np my (t)

?? M t kt cu np my trn hnh v?? Cch tho/lp np my


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3.2. Np my (t)

3.3. Pt-tng

?? Chc nng

?? Vt liu?? Kt cu


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3.3. Pt-tng (t)

3.3. Pt-tng (t)

?? Cc bin php kt cu gim ting g v gim b kt pt tng


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3.4. Cht pt-tng

?? Chc nng?? Yu cu

?? Kt cu

3.4. Cht pt-tng (t)

?? Phn tch kt cu lp ghp trn hnh v


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3.4. Cht pt-tng (t)

?? Kt cu m bo bi trn cht

3.5. Xc mng ?? Chc nng?? Yu cu?? Vt liu?? Kt cu


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3.5. Xc mng (t)

?? Gii thch hin tng bm du ln bungt

3.5. Xc mng (t)

?? Phn tch cc dng k t c u trn hnh v


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3.6. Thanh truyn

?? Yu cu?? Vt liu

3.6. Thanh truyn (t)

?? Phn tch kt cu


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3.6. Thanh truyn (t)

?? Phn tch kt cu v tchc lp ghp vi cht pt tng

3.7. Trc khuu

?? Chc nng?? Yu cu?? Vt liu


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3.7. Trc khuu (t)

?? Phn tch kt cu

3.7. Trc khuu (t)


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3.7. Trc khuu (t)

?? Cc bin php kt cu tng bn cho TK

3.8. Bc trc khuu

?? C c nng?? Yu cu?? Vt liu?? Kt cu


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3.9. Bnh

c n ng

?? Yu cu?? Vt liu?? Kt cu


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CHNG 4: C CU PHI KH. . ,

?? Chc nng?? Yu c u

4.1. Chc nng, phn loi (t)

?? Nu cc loi CCPK?? So snh cc loi trn hnh v?? Lo i no h bin


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4.2. Xu pp v dn ng xu pp

ng xu p p?? So snh xu pp np v x

4.2. Xu pp v dn ng xu pp (t)

??iu kin lm vic. Yu cu. Vt liu?? Kt cu chung ca xu pp. Tc dng ca mi phn?? Lp ghp v stip xc ca xu pp vi cc chi tit khc


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c u n n m

?? Bin php kt cu nhm gim b k t v t ng bn cho xu pp


?? Cc phng n d n ng xu pp.


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?? Khe hnhit.Cch iu chnh

.

So snh

?? NLLV con it y c?? Ch khi

tho/l xu

4.3. Pha phi kh v trc cam

?? Ti sao btr msm, ng mun?? Cc gc msm, ng mun ti u thay i khng


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4.3. Pha phi kh v trc cam (t)

?? VVT


?? Cc phng n d n ng trc cam?? Kt cu trc cam


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?? Cc phng n thc hin VVT


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CHNG 5: H THNG LM MT V H

5.1. H thng lm mt ng c

5.1.1. Chc nng, phn loi

ng c m v c n n n c rong o n c

ca xi lanh vo khong 80 95C.

ng cqu cao ay qu p n ng s mvic ca ng cnh thno

?? HTLM ly i bao nhiu nng lng sinh ra trongng cu c c o ng m m ng c v c m c a c ng

?? Phm vi ng dng ca mi loi h thng lm mt

5.1.2. H thng lm mt bng nc

?? Trn y NLLV

1- Kt lm mt nc;2- ng nci tt v bm;3- van h ng nhit;4- o nc lm mt;5- bm nc; 6- qut gi


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r n y


?? Trn y NLLV


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?? Ti sao btr tm chn iu chnh gi trc kt nc

1- ng nc mtn bm nc; 2- van x; 3- khoang nc ra; 4- tay iu khintm chn; 5- tm chn iu chnh lu lng khng khi qua kt lm mt nc; 6-khoang nc vo; 7- n p; 8- ming; 9- ng nc nng tng cvo khoang ncvo ca kt; 10- b phn tn nhit (thn kt); 11- tm dn hng dng khng khi iqua kt


Pha trn kt lm mt

lm mt, c ykn bng np kt nc

uy r m p su

d nh trong h

thng.1- kt nc, 2- bnh cha nc ph, 3- van hi ,

4- van chn khng, 5- ca ni bnh cha nc pha) khi p sut cao, b) khi p sut thp

?? Tc dn ca sut d?? Ti sao phi btr hai van mt chiu trong np kt nc?? Hi nc ra khi bnh => kt qu g. Cch khc phc


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i i t c t c ng c a ncha nc ph


1- Trc trt

1

-

3-Bc nha

4-Cht dn n nhit

a) t < 80oC

2

3

4

h

4

b) t > 95oC

c ng c a van ng n it

?? Trnh by NLLV


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1- mt bch, 2- qut gi, 3- pu-li,4- c c cha , 5- thn bm, 6- bnh

bm, 7- m lm kn, 8,9- bi,10- trc

?? Tc dng ca bm nc

?? Bm nc thuc loi bm g

?? Cc n ng m nc

?? Tc dng ca qut gic n ng qut g

?? u, nhc im ca mi PA


Cc yu cu i vi cht lng (nc) lm mt:

- n ng trao n t t t. i sao

-C nhit im si cao hn nhit ti a cho php trong h .

-C nhit im ng c (ng bng) thp. (? Ti sao?)

- . sao

-Khng n mn cc chi tit trong h thng lm mt.

- n c p. sao

-Khng c hi i vi mi tr ng v gi thnh khng qu cao.

? Cht lng lm mt thng dng?


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5.1.3. H thng lm mt bng khng kh

u, n c m c aHTLM bng KK

HTLM bng khng kh


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5.2. H thng bi trn ng c

5.2.1. Chc nng, phn loi

?? Chc nn ca h thn bi tr n n c?? Nu h thng bi trnng ckhng lm vic: hu qug?? Cc loi HTBT sdng cho CT. c im v phm vi s

S chung ca h

1- cc-te n c; 2- hu ht du; 3- bm du;4- thc thm du; 5- cm bin nhit du;6- bu lc


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5.2.2. Cc h thng bi trn thng dng

H th n bi tr ncc-te t

?? Nguyn l hotng??Tc dng ca

, ,

6, 17

1- cc-te ng c; 2- phu ht du; 3- bm du; 4- van an ton; 5- bu lc th;6- van an ton 7- n h chth sut du 8- n du chnh 9- tr c khu u10- trc cam; 11- dn c mv xu pp; 12- bu lc tinh; 13- thc thm du;14- ngdu; 15- ng h chth nhit du; 16- kha mch lm mt du;17- van nh p; 18- kt lm mt du

H thn bi tr n cc-te kh ?? Nguyn l hotng

5.2.2. Cc h thng bi trn thng dng

?? So snh vi HTBT cc te kh

1- cc-te ng c; 2- bm chuyn du; 3- thng cha du; 4- phu ht du vi li lc;- - - - -

du bi trn ccu trc khuu thanh truyn; 10- ng du bi trn trc cam v cc chi titca ccu phi kh; 11- bu lc tinh; 12- ng h chth nhit du; 13 kt lm mt du;14- van mt chiu iu p


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5.2.3. Cu to cc b phn chnh

Bm du

?? Tc dng ca bm d u?? Cc loi bm du. NLLV?? So snh cc lo i bm du


Bu lc

?? Cc loi bu lc du?? Tc d n ca bu l c th tinh?? NLLV v phm vi sdng


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u c

?? NLLV v phm vi sdng


Kt lm mt

?? Ti sao hi lm mt du?? So snh vi kt lm mt nc?? Bin php iu chnh nhit du


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5.2.4. Du bi trn ng c v vic chm sc bo dng

Yu cu vi du bi trn

- n m o c o m c m v c c a ng c.

- C kh nng chng -xy ha cho cc chi tit c bi trn.

-

keo hay mui bm trn b mt cc chi tit.

- C kh nng ty ra tt

- C nhit bt chy cao.

u rn c ngu n g c u m c m c c c p g a


nh gi d u bi trn

Du bi trn c nh gi theo cc chs do SAE v API xut.

Ch s SAE l chs phn loi du theo nht nhit 100 C v m18 C.

V d: SAE 40 SAE 10 W SAE 20W/50

Ch s API cho bit cp hng du khi s dng cho mi loi ng cxng hay diesel.V d:API-CF l loi du chuyn dng cho ng c diesel

- u c uy n ng c o ng c x ngAPI-SG/CD

o s n u v i

?? So snh du API-SG/CD vi du API-SG


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Chm sc bo dng HTBT

ung c m s c o ng ng r n

?? V sao cn chm sc bo dng h thng bi trn


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CHNG 6: H THNG CUNG CP NHIN LIU

6.1. Nhin liu v s chy ca nhin liu

??c im ca xng

?? Hin tng kch n

?? Tr sc tan ca xng l g?

?? Gii thch cc k hiu xng:

A90, A92, A95, MOGAS90, MOGAS92, MOGAS95.

?? Ti sao trong xng c cc cht ph gia

6.1. Nhin liu v s chy ca nhin liu (t)??c im ca diesel

?? Kh nng tchy

?? Tr sX tan ca diesel l g? Xe: 35, 45, 48, 55

?? Ti sao trong diesel cso cc cht ph gia

A90, A92, A95, MOGAS90, MOGAS92, MOGAS95.


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6.1. Nhin liu v s chy ca nhin liu (t)

?? Phng trnh chy

?? Thnh phn hn hp

?? H sdlng khng kh

?? Sn phm chy

6.2. H thng nhin liu ng c xng

. . . c n ng, y u c u, p n o

Chc nng: cung cp xng v hnh thnh hn hp nhin liu cho

Yu cu:

-

vic ca ng c.

- Nhin liu xng phi c cp dng hi v ho trn ng u.- Hn hp cp vo cc xi lanh phi ng u nh nhau.

Phn loi: hai loi chnh:

- h thng cung cp nhin liu dng ch ho kh (CHK),

- h thng cung cp nhin liu bng phun xng.

?? Phn tch cc yu cu nu trn


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6.2.2. H thng cung cp nhin liu dng ch ha kh (CHK)

1 thng xng, 2 bu lc,3 bm xng, 4, CHK,

u ng p ao, g c ,7 hng khuch tn,8 bm ga.

?? Trnh by NLLV chung ca h thng

6.2.2. H thng cung cp nhin liu dng ch ha kh (t)

KK

4

1 Bm ga2 Phao xng

B

X

3

5

-

4 Lc tinh5 Ming vi phun xng chnh

C

2

HH

KK: Khng kh

X:ng cp xngHH: Hn hp xng v khng khB: Bung cha xng v phao xng

ng m ng ng uy c n

?? CHKn gin ny c c tnh gn vi c tnh l tng khng


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KKX


4

756

1

3

2

HH

1 Gicl xng chnh2Hng khuych tn

3 Bm ga4 Mi n hun xn5 Gicl khng kh6 Bung phao7 Bm gi?? NLLV ca ng cp xng chnh

KK


1

8

3

7

6

2

1 Gicl xng khng ti

5HH

2 ng dn3 L cp chuyn tip4 Vt chnh5 L phun khng ti6 Bm ga7 Vi phun chnh

8 Gicl kh khng ti

?? NLLV ca ng cp xng khng ti?? Ti sao cn b tr l cp chuyn tip


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ng c p lm m

?? T i sao cn btrn lm m?? Yu cu lm m?? NLLV ca ng lm m

KK


ng c p tng t c

2

1

7

4

HH

56

3

1 Vi phun tng tc2 Pittong

3 Gicl chnh4 Van r i5 n dn ng6 Bm ga7 Vi phun xng chnh

?? Ti sao cn btrng tng tc?? NLLV ca ng tng tc


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KK


2

1

3

6

54

HH

1Van an ton

2 Bm gi

4 Bm ga5 L cp xng khng ti6 C cu dn ng lin ng

?? Ti sao cn b tr h thng ny?? NLLV

1


53

4

1 Bm gi2 Vi phun chnh

3 Bm ga4 L xo

5 Mt vt bm ga?? Ti sao cn b tr h thng ny?? NLLV


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c a a ngTwo-stagecarburetora) Primary stage,

.

1 Idle cutoff valve,

2 Accelerator pump,

3 Idle circuit, 4 Choke,

5 Boost venturi,

6 Main systems with

venturi tubes, 7 Full-

throttle enrichment,

, ,

10 Needle valve,

11 Bypass plug,

12 Idle mixture screw,

13 Throttle valves,

14 Venturi wall,

15 Part-throttle control

valve, 16 Venturichamber..

?? u nhcim ca loi CHK ny so vi loi 1 hng


1 ECU, 2 Cm bin nhit , 3 Ch ha kh, 4 C cu dn ng bm ga, 5 C cu dnng bm gi, 6 Bm gi, 7 Cng tc khng ti, 8 Bm ga, 9 Cm bin v tr bm ga.

?? u nhcim ca loi CHK ny so vi loi ckh


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6.2.3. H thng cung cp nhin liu kiu phun xng

?? Cc loi h thng phun xng. Loi no phbin hin nay

?? u im ca ng csdng h thng phun xngin tso vi ng

csdng CHK

6.2.3. H thng cung cp nhin liu kiu phun xng (t)

?? u nhc im ca phng php btr phun n im v a im?? u nhc im ca btr phun trn ngng np v phun trc tip vo xi lanh


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-


1 Thng xng2 Bm xn3 Bu lc xng4 ECU

5 Vi phung chnh

6 B i u 7 Khoang cha kh8 Vi ph khi ng9 CB v tr bm ga10 CB lu ln i11 CB o O2 kh x12 CB nhit ng c13 CB kch n14 B chia i n15 Van kh khng ti16c quy

17 Kha in

?? NLLV

S khi chc nng ca h thng



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iu khin bm ga


trong h thng phun xng

?? Chc nng ca bm ga- -

?? u im ca h thng cung cp nhin liu xng drive-by-wire so vi h thngcung cp nhin liu iu khin bm ga bng ckh

Phng php phun xng


?? u im ca cc phng php phun xng


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L n xn hun voC

?? Lng xng phun vo ng cc i u chnh b ng cch no?? Lng xng phun cbn ph thuc vo nhng thng tin no?? Cc lng phun hiu chnh

Thng xng


?? Kt cu thng xng??Ti sao np thng xng c hai van mt chiu

n m so x ng o ra ng x ng n n?? Tc dng ca van chng trn (rollover check valve)


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Lc xng


H thng cung cp xng b tr 3 b phn lcnhin liu: lc s b trongthng xng trc khi a vo bm xng, lc th trc bm xng, lc tinh lc sch cn bn, hi nc v hi nc ngng t.

B phn quan trng ca b u lc l ph n t lc:- phn t lc gm cc tm kim loi xp kht- phn t lc l li giy v li lc bng ceramic

Bm xng


?? u nhcim ca bm in so vi bm ckh


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Vi phun xng



u p v r xungp sut


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6.3. H thng cung cp nhin liu ng c diesel

Chc nng:

. . . , ,

p sut cao vo trong xi lanh, qua vi phun, cui k nn nhin liut bc chy.

Yu cu:

- Nhin liu cn c p sut cao (ti thiu khong 70 bar tr ln) phunvo bung t cui k nn.

- .

- Tng cp lng nhin liu ph hp vi ch ti v tc ng c

- ,

tia nhin liu phi ph hp vi hnh dng bung t.

6.3.1. Chc nng, yu cu, phn loi

Phn loi:

- iu khin bng c kh

- i u khi n b ng in t

- iu khin bng in t c ng phn

?? So snh cc loi trn


67/151

6.3.2. Cu to chung

1. Thng nhin liu2. Bu lc

86

. ng ng

4. Bm thp p

5. Bm cao p6. Vi phun cao p

7

. ng ng cao p8. C cu chn ga

123

5

4

?? NLLV ca h thng

6.3.2. Cu to chung

Common-rail accumulator injection system1 Fuel tank, 2 Filter, 3 Presupply pump, 4 High-pressure pump, 5 Pressure-control valve,

, , , , .

?? NLLV ca h thng


68/151

6.3.3. Bm chuyn nhin liu (bm thp p)

Bm thp p c nhim v chuyn nhin liu t thng qua cc bu lc n bm cao p,vi p sut ti a 3,5 n 4,5 bar.

Bm thp p thng l loi bm pt tng hoc bm cnh gt tch hp trong bm cao p

1. Thn bm2. Pittng bm my

14

109

11 AA

. xo

4. Cn y bm my5. L xo

6. Con ln

107

. an y

8. Thn bm tay9. Xi lanh bm tay10. Pit tng bm tay

a)

6

. n n

12. Tay bm13. Van ht

14. Cam ca BCA

137

A

2

34

A

b)

?? NLLV

6.3.4. Bm cao p (BCA) kiu dy?? Chc nng

?? Phn loi

3

2

1. Khp ni2. ng cp nhin liu3. c x khng kh.

5. B bm n6. Cn iu khin mc ga7. B iu tc ng c.

9. Trc cam BCA10. My bm thp p11. Bu lc nhin liu

.8 9

7 10 11 12


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1

6.3.4. Bm cao p (BCA) kiu dy?? iu khi n lng phun ntn

1. ng cp p cao36

Mt trch

2 ?? Bin php ch ng phun r t

.

3. Van m cao p

4. Thn bm5. Xy lanh bm

5

7

6

8

7

.

7. Vnh rng8. Pittng bm9. ng trt

11

10

1220

.

11. L xo

12. l xo13. Con i14

13

15

1919

.

15. Cam bm16. Con ln

14. Rnh phng

16

17

.

19. L cp du20. Mt gii hn

Hnh trnh np Hnh trnh nn u

C cu iu chnh thi im phun theo tc ng c c b tr trong khp ni dn

6.3.4. Bm cao p (BCA) kiu dy

ng m cao p.

84

27

2 6

7

3

4 56

a T c th

8

C u t oGc xoay

1. L xo, 2. Qu vng 3. Trc BCA 4. Np 5. Ming l xo 6. V 7. Gi 8. Cht t trn qu vng

?? Khi tc n ctn cn tn ha im c hun sm. T i sao?

?? Gii thch NLLV


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6.3.5. Bm cao p (BCA) kiu phn phi

3

1- Trc dn ng2- Cn iu khin ga

2

1

- c u qu v ng4- Cn iu tc5- Van in t6- Pittng cao p

- ng n cao p

8- Vnh chia cao p

9- ng chia du10- Vnh trn13

- n

12- a cam13- Bm thp p

12

11

9 8

S nguyn l BCA kiu phn phi


a) Vng nhin liu thpp

3 4

5c)

c) C cu iu tc

1. Thng

2 6

a)

2. B lc3. Van iu p4. Cn iu khin ga7

.

6. Bung nn7. Vi phun

8. Van mt chiu811 10 9

12

.

10. Biu chnh thiim phun

11.a cam.

ngang)


71/151


1 Vane-type supply pump, 2 Governor drive, 3 Timing device, 4 Cam plate, 5 Control collar,

6 Distributor plunger, 7 Delivery valve, 8 Solenoid-actuated shutoff, 9 Governor lever

mechanism, 10 Overflow throttle, 11 Mechanical shutoff device, 12 Governor spring, 13 Speed-

control lever, 14 Control sleeve, 15 Flyweight, 16 Pressure-control valve.


?? NLLV. Lng phun c iu chnh ntn

?? Ttng cdiesel bng cch no


72/151




73/151

6.3.6. C cu iu tc

?? T i sao cn iu tcng cdiesel

?? NLLV ca biu tcn ch

1- tr c cam ca bm cao p; 2- cc qu vng; 3- l xo; 4- trciu tc; 5- thanh gt; 6- thanh rng cm cao p

B iu tc l tm a ch

6.3.6. C cu iu tc

1- thanh rng bm cao p; 2- thanh gt; 3- l xo;4- bn p ga; 5- ln; 6- thanh y; 7- cc

-

?? NLLV ca biu tca ch ny


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6.3.6. C cu iu tc

B iu tc trn ng c diesel c tc dng hiu chnh lng phun cho ph hp vi tc v ti ng c. ng c diesel s dng b iu tc c kh v iu tc in t

1. Cn lin ng2. n by lin ng3. L du bi tr n4. im ta 16

18

12

14

15

5. Cht lin kt6. Trc dn7. Cht ta8. Tay n

4 1

11

173

12

13

9. Trc quay10.Qu vng11. L xo

12. Cht t qu vng14

10

10

4

5

11

13. im ta bn p14. C cu gim va

15. Gi im t16. Bn p ga 6

7 8

9

17. Thanh rng18. Pittng bm

C cu iu tc l tm a ch trm bm cao kiu hn hi

6.3.6. C cu iu tc


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6.3.7. Vi phun cao p

?? Gi trp sut ti vi phun btu phun ciu chnh ntn

6.3.7. Vi phun cao p

?? u im ca loi vi phun hai giai on

ny so vi loi mt giai on


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77/151

6.4.1. Thit b np

- bu lc khng kh,

- ng ng np

- c c ng p

- (c th c) thit b sy nng kh np.

??Chc nng ca ccthit b

6.4.1. Thit b np

?? Bu lc gi sb trn hotng ntn


78/151

6.4.1. Thit b np

u c ng

?? Bu lc gi trn hotng ntn

1

6.4.1. Thit b np

Bu lc khng kh

a) Bu lc khb) Bu lct

12

a)

1. Phn t lc2. V bu lc

3. Khoang cha cn 3b)

?? Tc hi ca bu lc gi tc

?? Tc hi ca bu lc gi hng


79/151

?? Mc ch sy kh np

?? Cc phng php tchc sy kh np

6.4.1. Thit b np

s y

6.4.1. Thit b np

?? Cc phng php tng p

?? u nhc im ca mi phng php


80/151

6.4.1. Thit b np

ng p

5

6

7

1. Bnh tuc bin

48

.

3. Bnh nn kh np4. Xupap np5. Xupap x

9

.

7. ng kh phn hi8. Xi lanh iu khin

9. Mch gim ti

X kh

123 ?? Bin php nng cao nhy ca tng p

6.4.2. Thit b x

ng c t lm nhim nghim trng

kha cnh ting nv cht thi trongkh x.

Vn kim sot

mc nhim ca t ang r t cquan tm v qun lcht ch bng cc

1- ng ng x; 2- B x l kh x; 3- ng dn; 4- B gim thanhu c u n u .

??Chc nng??Yu cu


81/151

6.4.2. Thit b x

?? Cc cht thi chnh gy nhim khngkh

?? Cc bin php hn chpht thi cht n i m c aC

6.4.2. Thit b x

?? Cch lm gim ting ntrongng gim thanh


82/151

B x l kh thi TWC

6.4.2. Thit b x

TWC s dng cht xc tc

Platin xc tc phn ng -xi

ho CO, HC thnh CO2 vH2O.

Radium s gip CO kh NOxthnh N2 v CO2.

TWC dng cho ng cxng

6.4.2. Thit b x


83/151

Lun h i kh x

6.4.2. Thit b x

?? Tc d n ca vi c lun hi kh x

?? Cc ch lm vic ca h thng lun hi kh x

?? Ti sao khng thc hin lun hi kh xcc ch ngui, khng ti v ton ti

Lun h i kh x n c VVT-i

6.4.2. Thit b x


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85/151


86/151

7.2. H thng cung cp in

?? Chc nng?? Cc thit b chnh

. . . u c ung

?? Cc ch lm vic

?? Ti sao cn biu chnh in


?? Ti sao my pht c

. . . u c ung

.


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88/151

3. My pht in

My pht in trn t l ngun pht ra in nng cung cp cho cc thit b tiuthin, np in c quy.

C hai loi my pht in: mt chiu v xoay chiu.

M ht i n m t chiu ht ra dn i n h h vi i n c u u cu ,tuy nhin do trng lng, kch thc ln, ngy nay khng cn c s dng na.

My pht xoay chiu c nhiu u im: kt cu n gin, gn nh, lm vic nn , u cao, c p n c p , n n c s ng p n.

My pht xoay chiu cn c thm b chnh lu dng in.

Cu to ca my pht in xoay chiu gm 3 phn c bn: phn cm (r-to), phnng (stato) v b chnh lu dng in.

My pht xoay chi u c phn bit thnh: cun dy kch t c nh (n m stato)v cun dy kch t quay (nm ro-to), loi ny ph bin trn t.

7.2. H thng cung cp in (t)

7.2.2. M ht i n

?? Chc nng v phn loi

End Frame CoverDrive Frame Cover Identification

Label

Regulator, Diode,Drive Pulley

Circulation Vent

Alternator B+

Out ut Terminal


89/151


90/151

7.2. H thng cung cp in (t)

7.2.3. B i u chnh i n

MF- my pht in; C- biu- -

cun kch t; 2- l xo ko cn m vt;

3- cp m vt; 4- nam chm in;

?? NLLV


7.2.3. B i u chnh i n t

?? NLLV


91/151

7.3. H thng khi ng ng c

ng p p ng ng c?? Trn t sdng phng php no?? Yu cu i vi my khi ngin

7.3. H thng khi ng ng c (t)


92/151



?? NLLV


93/151

7.4. H thng nh la

?? Chc nng?? Yu cu

. . . , ,

7

?? Phn loi

56

1

48

1- c u 2- kha i n 3- bin nh la 4- b chia

3

in 5- dy cao p chung 6- dy cao p xi lanh 7- Bugi (nn nh la) 8- Biu chnh gc nh la sm

7.4. H thng nh la (t)

. . .

?? Cu to


94/151


95/151

7.4. H thng nh la

1

d) cc dng cc

bu i

e) Lin kt renNn nh la

. . .

, ,

s truyn nhit

ca bu gi1- m ni dy 2

- n

3- s cch in4- ai c5- in tr

4

6- m lm kn7- Ren bt8-Cc + bu gi

5

6

7-

10- Cc - bu gi 89

10

S

A

N

A L

a) Cu to

bugi tiu chun

b) bugi nng c) bugi lnh

7.4.3. H thn nh la bn dn khn ti im


?? Nguyn l lm vic v c im


96/151

7.4. H thng nh la

7.4.3. H thn nh la bn dn khn ti im t

84 2 6

1

2

B tr cun dy tn hiu

3

4

5 6 7

5

6

4

9

5

Tn hiu in cun dy

72

1- Vch ngn trn 2- R to c cnh 3- Gi cnh 4- Nam chm 5- cun dy tn hiu

6- V dn t trng 7- Vch ngn di 8- Trc chia in 9- Khe h t

7.4.4 H thn nh la in t


?? Nguyn l lm vic v u im


97/151

7.4. H thng nh la

7.4.4 H thn nh la in t t

2

1

W1

W2

8MECU

5

6

8

10 M

11

W1,W2- cun dy bin p nh la1- c quy 2- kha in 3- bi n p nh la 4- b chia in 5- transitor

6- bugi 7- cm bin gc quay trc khuu 8- CB v tr trc cam9- CB v tr bm ga 10- CB nhit nc 11- CB lu lng kh np

7.4.4 H thng nh la in t (t)

7.4. H thng nh la Tn hiu vo

HTLT trc tip (khng c b chia in) ECU

1S

S1

2

M

+2 2

IV

M IIVIIIII

M- Ni cc m chung+ : Ni cc dngS- tn hiu iu khin

M

I, II, III,IV- cc bu gi

1- khi tran-zi-tor2- cc bin p nh la?? Nguyn l lm vic v u im


98/151

7.4. H thng nh la

7.4.4 H thn nh la in t t

7.4.5. H thn nh la v ln ma-nh-tc


3 6

7W1 W2C

158

24

910

M M

1- r-to 2- Khung t 3- bin p nh la 4- cam 5- khain 6- in cc bo v 7- b chia in 8- dy cao p9- Bu gi nh la 10- bnh rng dn ng

?? Nguyn l lm vic v c im


99/151

7.4.5. H thn nh la v ln ma-nh-tc t

7.4. H thng nh la

45 C

C- Tin M- Ni mt

1- r-to 2- Nam chm3- Cun dy tn hiu 4- kha 3

7

W1 W2- - - -

zi-tor 7- bin p nh la8- Bu gi nh la

6

8

MM

?? Nguyn l lm vic v u im

7.5. H thng chiu sng v thng tin tn hiu

. .

H thng chiu sng s dng nh sng in soi sng cc ni khc.

H thng ny gm c cc n pha, cc n soi sng bung li vkhoan hnh khch, n soi sn khoan hnh l v khoan n c,n soi sng bc ca ln xung v n soi sng bin kim sot.


100/151

Room lampFluorescent lam


u. . .

chiu sng (t)

Map

Head lamp lamp

Fog lamp

Step lamp

Luggage lampRear combination lamp

License plate lamp


7.5.1. H thn chiu sn t

n pha

n pha chiu xa n pha chiu gn Vng chiu sng trc xe

?? Tc dng, yu cu, phn loi n pha.?? Ti sao phi sdng 3 loi n pha chiu sng pha trc.?? Cc loi n pha pha trc c c im g khc nhau.


101/151


7.5.1. H thng chiu sng (t)

n pha1

2

3

4

6

7

23 8 9

1

1- Bu lng bt, 2- Knh khuych tn 3- gng lm 4- Gng che5- Bng n 6- Chui bng n 7- Bng ph 8- Gng ph9- Knh lc

?? Tc dng ca gng phn chi u 3.?? Hnh dng ca gng phn chiu.?? Btr cc bngn pha



n pha1 2

1- si dy pha

2- si dy ct

-

4- Mi trng kh

34

b n X-nn 1 2

1, 2- Cc in cc3- Bung kh

?? Cc im khc nhau gia bngn pha si t v bngn pha X-nn

3


102/151



n pha tch cc

Trn cc t hin i c trang b cc h thng t ng cm nhn cng

nh sng n ngc chiu v iu khin cng nh sng npha.

Khi xe i trn ng mp m, h thng t ng iu chnh hng npha gi c hng ca chm nh sng khng i.

Khi t i vo ng vng, h thng t ng iu chnh hng n phaquay theo chiu quay ca vnh li m bo soi sng tt qung

.

7.5.2. H thng thng tin tn hiu

7.5. H thng chiu sng v thng tin tn hiu (t)

Cc thit b tn hiu trn t gm c:- cc n bo r,- n u,- n bo phanh,- n bo tnh trng c s c,- ci- cc n bo bin xe- v n pha chy li.

Mt s t chuyn dng cn c thm n hiu v ci hiu u tin.Cc thit b thng tin gm cc thit b ch th trng thi hot ng cang c v t: bo nhit , bo du bi trn, bo tc , Cc thngtin v trng thi hot ng ca ng c v t c trao i vi nhaugia cc ECU to thnh h thng thng tin v truyn thng trn t


103/151

7.5.2. H thng thng tin tn hiu (t)


1- c quy 2- cu ch 3- kha in 4- mch vr-le n r 5- cng tc n bo r 6- cng tcn bo s c 7- n bo bt n bo r?? Mu sc ca n bo r

?? Cch sng ca n bo r

7.5.2. H thng thng tin tn hiu (t)


ci in

1- ci in; 2- tip im;3- cn tip im; 4- ntcng tc ci; 5- r-le ci;

-

61

1- Mng rung

2- Tm bo v3- Tm t tip im

-52

5- Li thp t6- Cun dy4

3 ?? Cc loi ci trn t?? Nguyn l lm vic ca ci in


104/151

CHNG 8: B TR H THNG NG LC (HTL)

?? HTTL, HTL l g

. .

?? N gm nhng cm, tng thnh no. Chc nng ca mi cm

?? Cc dng h thngng lc t?? Btr HTL l ?? Yu cu i vi vic btr HTL

8.2. Cc dng b tr HTL

HTL c kh c c trn t con

1 2 3 4 5 8

7

a)

6

1 2 3

4 512

3

5

6

b) c)

13

4 12 3

6

256

d)

4 5

e)

5

42 31 6

5

8 8

8

4

5 4

2 31 9 48

5

6

?? u nhc im v phm vi sdng ca cc dng btr trn hnhf)

6 6

g)


105/151


HTL c kh c cp trn t ti 1, 2, 3 76

a) 4x2

8 56

1,2,3 1,2,3

8

55

b) 6x2 c) 6x2

9 7 7

d) 6x4 e) 6x4

1,2,3 1,2,3

10

55

11

g) 8x4 h) 8x4

?? u nhc im v phm vi sdng ca cc dng btr trn hnh


HTL c kh c cp trn t ti (t)

1,2,3

5

5

5

5

5

5

1,2,3

9

9

a) 4x4 c) 8x8

, ,

5 5

5

1,2,3 9

b) 6x6



106/151


HTL c kh c cp a)1,2,31,2,3

5

6

trn t but

1,2,36

6

5

6

6

c)1,2

,35

6

d)1,2,3

5

6

6

e)1,2,35

6

6



HTL c kh c cp trn t but



107/151


HTL c kh v cp

?? u nhc im v phm vi sdng


HTL thy c

1 2 3 42 3

1 4

a)

3

2 b)



108/151


HTL thy tnh

6 6

1 2 3

4

5 5

455 55

6 6

1 ng ct trong,2 Bm thy lc3 Bnh cha du4 Bnh tch nng p sut

5 ng c thy lc v hp gim tc



HTL in

3 4

1

6

3 Cu chng4ng cin5 Phanh a6Hp gim tc c kh7 Bnh xe

?? Nhng ngun in no c sdng cho HTL t?? u nhc im v phm vi sdng


109/151


CT ng c nhit

a) B tr ni tip

Aq - c quy

G My pht in ,

cin

b) B tr song song

c) B tr kt hp?? NL lm vic ca mi s ?? u nhc im v phm vi sdng


110/151

9.1. Chc nng, phn loi, yu cu

CHNG 9: LI HP T

1 43

2

?? Cc loi l i hp v phm vi sdng?? Cc yu cu i vi l i hp

9.2. Li hp ma st kh

9.2.1. Li hp 1 a 2311

1 a) Mt ct

1. Cc te2. v li hp 5

9

12

8

. a p4.a bng5. Moay a bng6. Trc li hp 8

.8. Tm ma st9. bi t

10. L xo gim chn

b) S cu to v nguyn l lm vic

4 3 2

.12. Cng gt13. Trc khuu14. Bn p

9

6

7 11

.16. Thanh truyn mmen xon

14

1213

?? C u t o?? Nguyn l lm vic?? M men li hp ph thuc g Trng thi ng Trng thi m

15


111/151


112/151

9.2. Li hp ma st kh

9.2.2. Li hp 2 a

1 2 34 5 6

167

1519

10

918

14

HW: S haHW: Trnh by nguyn l lm vic 78

9.2. Li hp ma st kh

9.2.3. Cc chi tit chnh

Bnh v a p

?? Phn tch kt cu bnh ?? Phn tch kt cu a p, a p trung gian


113/151


114/151


115/151

9.2. Li hp ma st kh

9.2.3. Cc chi tit chnha b ng (a ma st)

1 2 3 4 5 6 7 8 6 910 5 1

125

76

3 1011

1. Tm ma st 2. l tn inh 3. Cnh l xo (T) 4.inh tn a5. Xng a 6.m ma st 7. Cht tn 8.a moay

9.m 10. L xo gim chn 11.inh tn tm ma st 12. Moay

?? Kt cu xnga phc tp => nhm mc ch g

9.2. Li hp ma st kh

9.2.3. Cc chi tit chnha b ng (a ma st)

1. Xng a,2. Tm ma st3. L xo l gn sng


116/151

9.2. Li hp ma st kh

9.2.3. Cc chi tit chnh?? Tc dng ca b gim chn?? Nguyn l lm vic

Ca s trn xng a

B gim chn

3

81

1 7

8 2

1112

Xng aMoa

3

6

5

610

12a) Trng thi ban u

3 4

5

6

10

2 Ca s trna moay

b) Trng thi b nn

1. xng a 2.inh tn 3. L xo gim chn 4. Tm l xo a 5. Tm ma st6. moay 7.a trong xng a 8.a moay 9. bu lng kp 10. L xo kp11. Ca s cha l xo 12. tm m l xo

9.2. Li hp ma st kh

9.2.3. Cc chi tit chnh

?? Ti sao cn cc kt cu tla

?? Ti sao cn btr kt cu iu chnhn m li hp

1

1 32 1 39

2 34 7

8

5

7

6

5

10

a) t la b) Gi t la c)n m t la

1.a p 2. bi kim 3. v li hp 4. t la 5.n m6. c iu chnh 7.ai c iu chnh 8. l xo 9. Gi ta 10. bi t


117/151

9.3. Dn ng iu khin li hp

9.3.1. Nhn vn chun

?? Chc nng?? Phn loi

4

2

3

7

13

19A9.3.2. Dn ng c kh

??c im

8

12

m v ng ng?? Hnh trnh tdo thay i ntn khili hp b mn => hu qu g

10 11

. . . . .6. V cp 7. c iu chnh 8.n quay 9. Trc nng gt 10.n m11. bi t 12. Cm li hp 13. L xo hi v A- Khong iu chnh


9.3.2. Dn ng thy lc

??c im?? Phm vi ng dng


118/151


119/151


9.3.4. Dn ng thy lc tr lc kh nn

1

1. Bn p2. Cn pit tng3. xi lanh chnh4. Pit tn duD

6 7 8

E14

9

2

5. Xi lanh tng hp6. Van np kh7. Van x kh8. L thot kh

3

AB C

134

9. Pit tng van iu khin10. Pit tng du11. Thanh y pit tng12. Pit tn kh nn

511 10

12

?? H thng lm vic ntn khi:- p bn p li hp,

- th bn p

13. Cng m14. Bi t

A,E: Khoang khB,C,D: Khoan du- p v ginguy n n p v tr n o- tng dn kh nn vo?? Phm vi ng dng

: Khe h bc m - nm


9.3.5. Dn ng thy lc tr lc chn khng

1 Thanh iu khin2. Thn van3. Pt tng

65 4

3

4. Mng cao su5. Xi lanh tr lc6 ng chn khng7n y

B

1I

2 mm

8. L xo h i v9. Trc ni10. Chc lin kt

11. Van A

7

II98

10

mm2

A,B. Cc khoangI, II.ng dn kh

?? H thng lm vic ntn khi:- p bn p li hp,- th bn p

II

- p v ginguyn bn p v tr no - tngng ni chn khng?? Phm vi ng dng


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CHNG 10: HP S T. . , ,

?? Chc nng?? Yu cu?? Phn loi

10.2. Hp s c kh c cp (MT - hp s thng)

10.2.1. Hp s c kh 2 trc

G1 G2Z5

I

Z4 Z3ZL

Z2 Z1

C1

ZL2

G3

Z'5 Z'4Z'3

Z'2Z'1

C2

?? NLLV??c im v phm vi sdng


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10.2. Hp s c kh c cp (MT- hp s thng) (t)

10.2.1. Hp s c kh 2 trc

5. 4. 3. LG1

G2

123456

. . .

2. 4. 6.L

I

.

I

7

II

C

II

2.1.

1C2G3 8 9 10

11

1

C2

12

13

HW: S ha, NLLV, so snh hai HS

10.2.2. Hp s c kh 3 trc


4. 3.2. 1.

0

G3G2

0

I III I,III

Za

ZaZ3

Z2 Z1ZL1

L 0.G1

II

IV

3 Z2 Z1 ZL

ZL2

IIIV

ZL2

?? Cu to?? NLLV??c im v phm vi sdng


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10.2.2. Hp s c kh 3 trc


3. 2.

1. L0

G1

G2G3. .

00

I III

ZaZa

Z4

Z3

Z2 Z

II

4 3 2

Z1ZL

IVZL1 ZL2

?? NLLV?? So snh vi loi 4 cp s

10.2.2. Hp s c kh 3 trc


HW: S ha, trnh by NLLV. Vtch cc trc


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10.2.2. Hp s c kh 3 trc


HW: S ha, trnhby NLLV. Vtch cctrc. Vtch BR gi s1 v BR trung gian s

li

10.2.3. Hp s c kh kp


m1

m2

m3

n1

A B C

m4

m5

n2

mL

M: Phn chnh N: Phn ph

HW: So snh hp skp vi hp sn


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Phn chnh hp s (HSC)I: Trc ni hp sII: Trc trung gian

5. 4.3. 2. 1. L

000

G1G2G3

Lo H.G4

III: rc ngIV: Trc s li

G1, G2, G3: Cc khpg is1., 2., 3., 4., 5., L: Cc v tr gi s

I

IIIIp

2Lo.Phn ph ca HSCIp: Trc ch ngIIp: Trc ph s thpG4: Khpg is thp v s cao

Za

ZaZ4Z4

Z3

Z3Z2

Z2

Z1ZL

ZL

Zo

Zo

Zo, Zo: Cp BR s thpH: V tr gi thng (s cao)Lo: V tr gi s thp

II

IV

Z1

ZL1ZL2

IIp

Phn ph HSC Phn chnh HSC

HW: So snh hp skp vi hp sn



Phn chnh HS5. 4.3. 2. 1. L

00

G1G2G3

H G4

CCHT

II: Trc trung gianIII: Trc b ngIV: Trc s liG1, G2, G3: Cc khpg is

I

III. TIIp

H

1., 2., 3., 4., 5., L: Cc v tr gi

Phn ph ca HS

CCHT: C cu hnh tinh

a

ZaZ4Z4

Z3Z3

Z2Z2

Z1Z

L

ZL

p G4: Khpg is trong phn phZo, Zo: Cp BR s thpT: V tr gi thngH: V tr gi s cao (truyn tng)

II

IV

Z1

ZL1ZL2

Ph n h HSCPh n chnh HSC

??: NLLV


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Khoang li hp Phn ph HS Phn chnh HS

THW: Vtch cc trc, bnh rng ZL

10.2.4. Cc b phn chnh


V hp s

?? Vt liu?? Kt cu

Bnh rng hp s

?? Cc loi BR dng trong hp s?? Ch g vhng nghing?? Vt liu?? Kt cu


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Trc hp s

?? Cc yu cu i vi vic btr trc?? K t c u

ng trt gi s

?? Kt cu m bo i kh m d u



?? Chc nn

Bng tc

?? Cc loi thng gp?? Cu to chung


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Bng tc1 2 3 4 5

1 2 4 5

6

1. ng gi 2. Tm nh v 3. Vng l xo4. Vnh ma st n i 5. Vnh ma st BR 6. Tr c. . .

hp s

?? Cu to?? NLLV



Bng tc

1. Bnh rng trn trc scp2. Cng gi s3. ng gi s4. Bnh rng trn trc thcp5. Vnh cn ma st6. Cc kho hm7. Cc l xo gikho hm8. Moayng tc

9. Cc rnh cha kho hm

HW: phn tch kt cung tc trn hnh


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10.2.4. Cc b phn chnh 4


Bng tc

1 Trc hp s2 BR c gi3 Vnh rng thng v vnh

9

ma st ca BR4 Vnh ma st ng gi5 Moay ng tc6 L xo

1

7 Cht hng tm8 Mnh nh v9 ng gi

?? Cu to 32 654 7 98 4 3 2



Bng tc

1 Trc hp s

32 465

24

2 BR c gi3 Vnh rng thng v vnhma st ca BR4 Vnh ma st ng gi

1

oay ng t c6 Cht mm7 Cht cng

?? Cu to7

a) b)


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132/151


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10.2.4. Cc b phn chnh10.2. Hp s c kh c cp (MT- hp s thng) (t)

?? Tc dng

C cu bo him gi s li

. ,2. ng bc l xo nh v,3. L xo nh v,4. Cht kho hm,. n v ,

7. Con trt kho hm,10. Np v hp s.

10.3. Hp s tng chuyn s (HST)

10.4.1. Gii thiu chung

?? Cu to chung??c im. Phn tch cc u im so

?? Phn loi


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10.3. Hp s tng chuyn s (HST)10.3.2. Hp s tng (AT) (t)

Bin m thy lc


10.3.2. Hp s tng (AT) (t)Hp s hnh tinh

?? So snh hp shnh tinh vi


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Hp s hnh tinh Trng thica khu

c iukhin

Khu chng

Khu bng

T struyn

Chiu quay cakhu bng i

vi khu chng

Bnh rng

bao c nh

Bnh rngmt tri

Cn dn >1 (gimtc) Cng chiu

Cn dn Bnh r ngmt tri

< 1 (struyn tng)

Bnh rngmt tri c

nh

Bnh rngbao

Cn dn >1 (gimtc) Cng chiu

Cn dn Bnh r ngbao

< 1 (Struyn tng)

Cn dn cnh

Bnh rngmt tri

Bnh rngbao

>1 (gimtc) Ngc chiu

Bnh rngbao

Bnh rngmt tri

< 1 (struyn tng)

Cn dn vbnh rngbao ni c

nh vi nhau

Bnh rngmt tri

hoc bnh

rng bao

Bnh rngbao hocbnh rng

mt tri

= 1 (truynthng) Cng chiu

?? Tnh t struyn ca ccu HT: i = Zb/Zbhoc KCR

CS=

S

R

S

R

r

r

Z

ZK ==


10.3.2. Hp s tng (AT) (t)Hp s hnh tinh Simpson

Bng cc trng thi lm vic ca c cu hnh tinh Simpson

v kh nng ng dngKhu ch

ngKhu b

ngKhu chu

lin ktT s

truyn iKh nngng dng

H2 H1 PT1 c nh i > 1 S truyn

H2 H1 S c nh 1 < i < 2 S truynchm

H2 H1 H1 ni vi i = 1 S tru nH2 thng

S H1 PT1 c nh i < -1 S li


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Hp s hnh tinh phanh

?? So snh li hp nhiu a v phanh nhiu a


10.3.2. Hp s tng (AT) (t)Hp s hnh tinh phanh

?? So snh li hp nhiu a v phanh nhiu a


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H thng iu khin

?? Chc nng ca h thngiu khin hp stng

?? Thng schnh no quytnh trng thi lm vic ca HST

?? Gii thch xu hng chuyn s


10.3.2. Hp s tng (AT) (t)H thng iu khin

?? Phn tch th ngng chuyn strn hnh v


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H thng iu khin

?? So snh ngng chuyn scc ch lm vic ca HST?? ngha vic btr cc ch lm vic khc nhau ca HST


10.3.2. Hp s tng (AT) (t)H thng iu khin

BiuBm dukhin

p sut Cc ccu HSHT

khinHSHT

H van iukhin thy

lc

Li lcVtr bm gaTc tVtr cn chns

y cha du


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10.3. Hp s tng chuyn s (HST)10.3.3. Hp s v cp (CVT)

H 1

3ng

cp duK1K2

H: Bnh rng baoS: Bnh rng trung tmPT: Gi hnh tinhK1 K2: li h kha6

27

ng,

1 V hp s2 Trc chng3 ai thp4 Bnh ai bngPT

S

5

c pdu

rc ng6 Bnh ai chng7 Xi lanh p

8 Na bnh ai cnh34


10.3.3. Hp s li hp kp (DCT)?? So snh DCT ~ MT?? So snh DCT ~ AT


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10.4. Hp phn phi10.4.2. Cu to 2 cp c vi sai (hp s ph - HSP)

?? Tc dng ca vi sai

8 8

5

6

7 9

10

11

12

1Mt ni racu trc

2Khp gi cu trc3BR s cao

Dng truyn

s thp

11

12

3

414

15

p g s cao5BR trung gian6Khp gi s thp7Trc chngDng truyn

s cao Ra cusau

H L5 13

3

1617

18192021`

2223 1BR chng2BR gi ti

3ng gi s thp4BR s thp

B vi sai

trc

a) Mt ct cu trc

LOCK

3 G1G2

5Trc trung gian6BR s thp7V vi sai8Trc ra cu sau

9 BR ra cu sau1BR vi sai1ng gi s cao

Hnh10.48: Hpphnphihaicpstruyncb visaibnhrngcn

1Vnh ma st ng t c1Vnh rng gi1Trc ra cu trc1ng gi trn cu trc1ng gi trn v vi sai1

10.4. Hp phn phi

10.4.2. Cu to c vi sai tng ma st?? Tc dng ph ca vi sai?? Cch hn chtc dng ph

Mvo MSra1

2 3

vo Sra

Ra cu sauG2

M

1 Trc chng2 B li hp3 B vi sai cn

4

ra

nTra

Ra cu trc


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10.4. Hp phn phi10.4.2. Cu to khp ni thy lc

?? M t cu to?? Nguyn l lm vic?? u nh c im

10.4. Hp phn phi

10.4.3.iu khin hp s ph?? Nguyn tc iu khin HSP?? So snh vi ccu iu khin HS thng?? Gii thch slm vic ca cc ccutrn hnh

1. Trc trt gi cu trc,

2. Bi kho,. ,a. V tr ca trc trt chuyn vmt phng m-m gi s cao,b. V tr trung gian,. ,

d. V tr m cu trc,e. V tr gi cu trc

1. Cn gi cu,2. Cn i s tru n3. Bu lng hn ch,4. Thanh ni dn ng gi s truyn,5. Thanh ni dn ng gi cu


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END OF 10th CHAPTER

?? hc nhng g?? Cn nh c bao nhiu

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