REKAYASA TEKNIK JALAN RELWESEL SIMETRIS

KETERANGAN Menghitung panjang lengkung bagian dalamtg α = 1/12.75 = 0.078 d =tg β = 1/57.5 = 0.0174 2e =

α = 4.4846

β = 0.9963sin 1/2α = 0.0391cos 1/2α = 0.9992sin 1/2β = 0.0087cos 1/2β = 0.99996

tg 1/2α = 0.03916tg 1/2β = 0.0086950S = 1067 mmVt= 3 mmS'= 533.5 mmS'= 535.02 mm

PERHITUNGANPanjang Jarum (P)d = 16 mmC = kaki = 110 mmB = kepala = 68.5 mm

Rumus Pelebaran :

Ketentuan :p = 4544.4859 mm Jika Ru < 600 m, maka gunakan rumus Vb diatas.p = 4544.4859 mm jika Vb > 20 mm maka ambil 20 mm dan Vt= 3 mm.Panjang Lidah (t)

Jika Ru > 600 m, tetap gunakan rumus Vb diatas.Jika Vb > 3 mm maka Vt= 3mm, Jika Vb < 3 mm maka Vt = Vb.

t = 7878.10 mmt = 7878.10 mm Vb =Perhitungan Jari - Jari lengkung luar (Ru) Vt =

Menghitung panjang kaki bagian dalamSt =Sb =

Ru = 394555.825714736 mm Rt =Pembulatan Ru Ri =Ru = 394000.00 mm Rp =Nilai P sebenarnya

Menghitung panjang lengkung bagian luar

o

o

t = B cot 1/2

d = jarak gandar roda = 4 me = kelonggaran roda = 4 mm

p= 4554.82659754905 mm HK =Menghitung Panjang I KN =

NO =PQ =

I = 24418.9173 mmMenghitung Panjang Wesel (L)x = 2 batang relPjg rel R 42 = 25000 mmd = 16 mm

L = 50032 mmtg γ =

Jika, ln = jarak bantalan biasa γ =ld = jarak bantalan sambungan tg δ =

ln = 700 mm δ =ld = 600 mmMaka, jarak antar dua bantalan (AB) Menghitung lengkung OP

OP =

AB = 1000 mmMenghitung panjang lengkung luar (CD) Kontrol

NO + OP + < CD11960.8609

CD = 11993.6730786936 mmMenghitung panjang Jarum (EF)d = 16 mm

EF = 4552.4859 mm

GEOMETRIK

a. Gaya sentrifugal diimbangi sepenuhnya oleh gaya berat

Ru= 394000.00 mmS= 1067 mmw= 1120 mmv= 45 km/hg= 9.81 m/d2

Menghitung γ dan δ

R= 393466.5 mm

h= 0.587579020197294 m

Dengan peninggian maksimum, h maks = 110 mm maka :

R= 162 mm

Rmin= 162 mm

b.Gaya sentrifugal diimbangi oleh gaya berat dan daya dukung komponen jalan rel.

a= 0.956391898870484 m/d

Percepatan sentrifugal maksimum diambil sebesar a maks = 0,0478 g

R min= 109.35 m

c. Jari-jari minimum pada lengkung yang tidak memerlukan busur peralihan

h= 56.46 mm

Jika h = 0 , maka :

R= 332.1 m

d.Lengkung peralihan

Gaya sentrifugal

F = lokomotif cc 201 = 78 tongerbong eksekutif = 35.5 ton

Rmin = 0,054.v2

R = 0,164.v2

gerbong bisnis = 32 ton

R= 392920.70 mm =Ri =

F lok. cc 201 = 401989.51553456 kgF g.eksekutif = 182956.766685601 kgF g.bisnis = 164918.775603922 kg

Diketahui a maks = 0,0478.g = 0,0478.9.81 = 0,469

l= 13.9150216915809 mh= 30.6130477214781 mm

Maka : lk = 0.01 h v13.7758714746651 13 m

Menghitung panjang lengkung bagian dalam4000 mm

8 mm

Jika Ru < 600 m, maka gunakan rumus Vb diatas.jika Vb > 20 mm maka ambil 20 mm dan Vt= 3 mm.

Jika Ru > 600 m, tetap gunakan rumus Vb diatas.Jika Vb > 3 mm maka Vt= 3mm, Jika Vb < 3 mm maka Vt = Vb.

12.3 mm3.0 mm

Menghitung panjang kaki bagian dalam1070 mm St= 2S' + Vt

1079.304569 mm Sb= 2S'+ Vb392930.0000 mm Rt= Ru-St392920.6954 mm Ri= Ru-Sb392959.4006 mm

Menghitung panjang lengkung bagian luar

d = jarak gandar roda = 4 me = kelonggaran roda = 4 mm

Peraturan Dinas No.10

650.3222 mm8218.4830 mm

2704.0713098 mm4554.9859 mm

0.0069

0.39430.0116

0.6642

Menghitung lengkung OP9256.7896 mm

mm < 11993.67308 mm OK

0.0000

Menghitung γ dan δ

o

o

78000 kg35500 kg

32000 kg

392.92069543147 m

Kordinat Rumus Perhitungan KoordinatTitik X Y * Titik A * Titik E

A 1000 533.5 X = AB X

B 0 533.5 Y = 1/2S YC -7877.7978 465.0026 * Titik B * Titik FD -19867.578320002 178.21023728236 X = 0 XE -24418.9173 0 Y = S' YF -28971.4032 0 * Titik C * Titik F'

F' -28964.434212481 -177.982 X = XH 1000 -533.5 Y = YK 349.6778 -533.5 * Titik D * Titik HM -3452.0994 465.0026 X = - (l - p cos 1/2α) XN -1035.7042 -604.9570 Y = p sin 1/2α YO -3739.4475 -647.0756

P -12992.559606413 -900.2679

Q -17544.522550622 -1066.1882

Line 1000,533.5Line 0,533.5Line -7877.79782045548,465.002589253668Line -19867.5783200017,178.210237282356Line -24418.9172927731,0Line -28971.4032084246,0Line -28964.4342124809,-177.982271520161Line 1000,-533.5Line 349.677819259803,-533.5Line -3452.09938013796,465.002589253668Line -1035.70423253907,-604.956965470057Line -3739.44750203871,-647.075619177903Line -12992.5596064134,-900.267909146856Line -17544.5225506219,-1066.1881885552

- t cos1/2 bY(B)- t sin 1/2b

Titik E * Titik K * Titik P

= - l X = X(H) - HK X

= 0 Y = -1/2S YTitik F * Titik M * Titik Q

= l - EF X = X= 0 Y = Y(C.) Y

Titik F' * Titik N

= X == - EF cos1/2α sin1/2α Y =

Titik H * Titik O= X(A) X == -1/2S Y =

-1000 10000 0

7877.79782045548 -7877.7978219867.5783200017 -19867.578324418.9172927731 -24418.917328971.4032084246 -28971.403228964.4342124809 -28964.4342

-1000 1000-349.677819259803 1650.322183452.09938013796 -3452.099381035.70423253907 -7868.494533739.44750203871 -10572.237812992.5596064134 -19825.349917544.5225506219 -24377.3128

0 0

-(t cos 1/2b - Ru sin1/2 b - AB)

I - EF (cos 1/2α)2 X(M) - AB+ Rt sin 1/2bY(M)-St cos 1/2b

X(N) - (Ri sin (1/2β + g ) - Rt sin 1/2β)Y(N) - (Rt cos1/2β - Ri cos (1/2β + g ))

=

=

==

X(O) - Ri (sin 1/2α - sin (1/2β + g))

Y(O) - Ri ( cos (1/2β + g) - cos 1/2α )

X(P) - (Rp sin (1/2α + d ) - Ri sin 1/2α)Y(P) - (Ri cos1/2 α - Rp cos (1/2α + d ))

REKAYASA TEKNIK JALAN RELWESEL INGGRIS

KETERANGANtg α = 0.0816 Kordinattg β = 0.019048 Titik

α = 4.6669 E1

β = 1.0912 Asin α = 0.0814 Ccos α = 0.9967 Dsin β = 0.0190 Ecos β = 0.9998 Ncos (1/2α-b) = 0.9998 Osin (1/2α-b) = 0.0217 Ptan (1/2α-b) = 0.0217 A'S = 1067 mm C'

D'Panjang Jarum (P) N'd = 16 mm O'C = kaki = 110 mm P'B = kepala = 68.5 mm

P = 2174.2618 mm

Panjang Lidah (t)

t = 3596.25 mm

Perhitungan Jari - Jari lengkung luar (Ru)S'= 13103.3545213821 mm

Ru = 338368.382546738 mmPembulatan RuRu = 338000.00 mm

Menghitung panjang EDED = 12857.4309826521

Menghitung lengkung luar CD= 7328.07868577063

AD1= 2172.45893261804 LD1C1= 7327.50460167704 L

o

o

t = B cot

CE1= 3595.59779651259AE1= 13095.5613308077EE1= 533.62517864421DD1= 88.5245585684269CC2= 68.4875770764303DC2= 13548.0682969411

Vt= 3d = 40002e = 8

Vb= 20

Menghitung pjg kaki bg dlmSt= 1070Rt= NM = 336930.00Sb= 1087Ri= OM= 336913.00KN= 3743.58901678564NO= 3384.57249885418

sin g = 0.0100453284030932g = 0.575564601502104

Menghitung pjg lengkung OPOP= 3920.0531080872

Menghitung EFEF= 2182.26180838041

GEOMETRIK

a. Gaya sentrifugal diimbangi sepenuhnya oleh gaya berat

Ru= 338000.00 mmS= 1067 mmw= 1120 mmv= 45 km/hg= 9.81 m/d2

R= 337466.5 mm

Menghitung γ

h= 0.685083291379911 m

Dengan peninggian maksimum, h maks = 110 mm maka :

R= 162 mm

Rmin= 162 mm

b.Gaya sentrifugal diimbangi oleh gaya berat dan daya dukung komponen jalan rel.

a= 0.955537865923786 m/d

Percepatan sentrifugal maksimum diambil sebesar a maks = 0,0478 g

R min= 109.35 m

c. Jari-jari minimum pada lengkung yang tidak memerlukan busur peralihan

h= 56.46 mm

Jika h = 0 , maka :

R= 332.1 m

d.Lengkung peralihan

Gaya sentrifugal

F = lokomotif cc 201 = 78 tongerbong eksekutif = 35.5 tongerbong bisnis = 32 ton

R= 336913.00 mm =Ri= OM=

F lok. cc 201 = 468815.391510568 kg

Rmin = 0,054.v2

R = 0,164.v2

F g.eksekutif = 213371.107674682 kgF g.bisnis = 192334.519594079 kg

Diketahui a maks = 0,0478.g = 0,0478.9.81 = 0,469

l= 16.2282250907504 mh= 35.702095199651 mm

Maka : lk = 0.01 h v16.0659428398429 16 m

Kordinat 1X Y 2

0 0 3 POINT

-13095.5613308 0 4 POINT-3595.59779651 387.2047050266 5 POINT-10923.1023982 88.52455856843 6 POINT

0 533.6251786442 7 POINT-10878.84545 -994.871618831 8 POINT

-3575.22054035 -682.601243467 9 POINT0 -533.625178644 10 POINT

13095.56133081 0 11 POINT3595.597796513 387.2047050266 12 POINT10923.10239819 88.52455856843 13 POINT

10878.84545 -994.871618831 14 POINT3575.220540351 -682.601243467 15 POINT

0 -533.625178644 16 POINT

E1 POINTA LineC LineD LineE LineN LineO LineP LineA' LineC' LineD' LineN' LineO' LineP' Line

78000 kg35500 kg32000 kg

336.913 m

Rumus Perhitungan Koordinat* Titik E1

0,0 X

-13095.5613308077,0 Y-3595.59779651259,387.204705026616 * Titik A-10923.1023981896,88.5245585684269 X0,533.62517864421 Y-10878.8454486388,-994.871618830748 * Titik C-3575.22054035082,-682.601243466529 X0,-533.62517864421 Y13095.5613308077,0 * Titik D3595.59779651259,387.204705026616 X10923.1023981896,88.5245585684269 Y10878.8454486388,-994.8716188307483575.22054035082,-682.6012434665290,-533.62517864421

0,0-12821.8196961295,0-3424.31520543152,390.979834469971-10693.9473100633,88.50795562218270,533.318189611266-10648.7730642126,-994.737283590002-3402.91948414795,-678.8062297086360,-533.31818961126612821.8196961295,03424.31520543152,390.97983446997110693.9473100633,88.507955622182710648.7730642126,-994.7372835900023402.91948414795,-678.8062297086360,-533.318189611266

Rumus Perhitungan Koordinat* Titik E * Titik A'

= 0 X = 0 X =

= 0 Y = EE1 Y =* Titik N * Titik C'

= - AE1 X = X == 0 Y = Y =

* Titik O * Titik D'= - CE1 X = X == Y = Y =

* Titik P * Titik N'= XC - D1C1 X = 0 X == YE1 + DD1 Y = - (EE1) Y =

XD + Sb sin 1/2aYD - Sb cos 1/2a

XC + St sin bYE - t sin b YC - St cos b

* Titik O'

AE1 X =

0 Y =* Titik P'

CE1 X = 0Y = EE1

- ( XC - DD1 )YE1 + DD1

- (XC + St sin b)

YC - St cos b

YE - t sin b

- (XD + Sb sin 1/2a)YD - Sb cos 1/2a