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Department of Electronic EngineeringNational Taipei University of Technology
••••••• Y ∆
•
Department of Electronic Engineering, NTUT2/47
(Linear Circuits)
• :
• :y = Kx Kx y
R y = Kx
, where 0dy
ax adt
= ≠
, where 0dx
y b bdt
= ≠
v Ri=( ) ( )Kv K Ri R Ki= =
Department of Electronic Engineering, NTUT3/47
1
• 1: i1i2 vg1 ig2
KVL vg1 = i1 i2
KCL i1 + i2 = ig2
×2
+−
3 Ω
i1
6 Ω
i2
vg1 ig2
2 1 13 6 gi i v− + =
1 1 2
2 1 2
1 19 31 2
9 3
g g
g g
i v i
i v i
= + = − +
Department of Electronic Engineering, NTUT4/47
(Practical Sources) I
•
(a)(a)
(b) :
• Rs Rs
Rs Rs
= 0
sL
s L
vi
R R=
+L s
Ls L
R vv
R R
⋅=+
+−
(a)
Rs
vs
(b)
+−
+
−
Rs
iL
vs vL RL
Department of Electronic Engineering, NTUT5/47
II
•
Rg
+
−
is VRg
Department of Electronic Engineering, NTUT6/47
(Equivalent Circuit) I
•
• (a)
• (b)
+ − +
−
(a)
+−vs
v11
s
s s
v vvi
R R
−= =
222
s gs s
g g
i R vvi i i i
R R
−= − = − =
Rs i1
v1
+
−
(b)
i
i2
v2is Rg
i
–
Department of Electronic Engineering, NTUT7/47
II
• i1=i2 , v1=v2
i1= i2
v1= v2
•
21 s gs
s g
i R vv v
R R
−− =
11 s gs
s g
i R vv v
R R
−− =
+ − +
−
(a)
+−vs
v
Rs i1
v1
+
−
(b)
i
i2
v2is Rg
i
and s s g s gv i R R R= =
Department of Electronic Engineering, NTUT8/47
2
• 2: (a) I
(c)
+− 8 V
I
(a)
+−
3 Ω
4 AI
12 Ω 1 Ω
6 Ω 6 Ω 2 Ω32 V
(b)
+− 8 VA
332 I
12 Ω 1 Ω 2 Ω
6 Ω6 Ω3 Ω
12 Ω 3 Ω
6 Ω2 ΩA332
Department of Electronic Engineering, NTUT9/47
2
+−
16 Ω
16 VI
(g)
(a) (f) (g)
(e)
+−
IV3
64A3
8
12 Ω2 Ω
2 Ω
(d)
+−
IV3
64
12 Ω2 Ω
6 Ω 3 Ω A38
(f)
+−
+−
I
2 Ω 12 Ω 2 Ω
V316
V364
( ) ( )64 162 12 2 1 A
3 3I I+ + = − ⇒ =
Department of Electronic Engineering, NTUT10/47
I
• (Superposition Theorem)
Department of Electronic Engineering, NTUT11/47
II
•
1)
2)
3) (1) (2)
4)
5) ( ) KK
Department of Electronic Engineering, NTUT12/47
3
• 3: (a)I
(b) (c)(b) (c) 4Ia 4Ib
5Ω
(b):
+ −
+−
4 Ω
(a)
I
4I
18 Ω4 A20 V
5 Ω
+ −
+−
(b)
4 Ω 4Ia
18 Ω20 V
Ia
5 Ω
+ −
(c)
4 Ω 4Ib
18 Ω4 ΑIb
5 Ω
4 − Ib
( ) ( )20 4 4 18 5 0.87 Aa a aI I I− = − + + ⇒ = −( ) ( ) ( )4 4 5 4 18 3.13 Ab a b bI I I I= + − − ⋅ ⇒ =
( )2.26 Aa bI I I= + =
Department of Electronic Engineering, NTUT13/47
4
• 4: (a) 5 Ω
+ −
(c) (d)
v+ −
(a)
+−4 Ω
3 Ω
5 Ω
5 A
2 A
10 V
+ −
(b)
v1
5 Ω
4 Ω
3 Ω
5 A
v2
5 Ω
4 Ω
3 Ω2 A
+ −−+
v3
5 Ω
4 Ω
3 Ω10 V
( )5
5 41.67 A
4 3 5I Ω
⋅= =+ +
( )1 1.67 5 8.33 Vv = ⋅ =
( )5
2 30.5 A
4 3 5I Ω
⋅= =+ +
( )2 0.5 5 2.5 Vv = ⋅ = ( )3
10 54.17 V
4 3 5v
⋅= =+ +
( )1 2 3 15 Vv v v v= + + = ( )2 215
45 W5
vp
R= = =
Department of Electronic Engineering, NTUT14/47
III
• :
•
• p = i2R p = v2/R
( )2 21
1
8.3313.95 W
5
vp
R= = =
( )2 22
2
2.51.25 W
5
vp
R= = =
( )2 23
3
4.173.48 W
5
vp
R= = =
( )1 2 3 18.63 Wp p p p= + + =
Department of Electronic Engineering, NTUT15/47
IV
•
1)
2)
Department of Electronic Engineering, NTUT16/47
I
• (Thevenin’s Theorem)
• (voc eth) (Rth)
1) voc eth
(a)
2) Rth () (b)
( )
(a)
+
-
voc
a
b(b)
()
Rth
a
b
Department of Electronic Engineering, NTUT17/47
II
•
+
-
(a)
+-
+
-
(b)
voc
I
v
Rth I
v
a
b
a
b
Department of Electronic Engineering, NTUT18/47
5
• 5: (a) v1
Rth
(b)
voc
:
1)(c)
+−
+
−(a)
v1
a
b
6 Ω 4 Ω
3 Ω 2 Ω
2 A
12 V
(b)Rth
a
b
6 Ω 4 Ω
3 Ω
(c)
+− ′Voc
a
b
6 Ω 4 Ω
3 Ω12 V
( )6//3 4 6 thR = + = Ω
( )312 4 V
3 6ocv′ = =+
Department of Electronic Engineering, NTUT19/47
5
a-b (e)
(f)
2 A 4 Ω 3 Ω 6 Ωb c
1)
2) (d)
( )2 4 8 Vocv′′ = ⋅ =
( )2 4 8 Voc ab acv v v′′ = = = ⋅ =
( )12 Voc oc ocv v v′ ′′= + =
( )1
212 =3 V
6 2v =
+
(d)
c
′′voc
a
b
4 Ω6 Ω
3 Ω
2 Α
(e)
+−
6 Ω
12 V +−
(f)
+
−v1
a
b
6 Ω
2 Ω12 V
Department of Electronic Engineering, NTUT20/47
I
• (Norton’s Theorem)
• (Isc) (Rth)
1) Isc:
2) Rth:
Isc
a
b
Department of Electronic Engineering, NTUT21/47
II
•
• (a) a-b(b)
(a) (b)
a
b
Isc Rth
a
b
(a)
Isc
a
b
ocsc
th
vI
R=
oc ab th scv v R I= =
+-
(b)
voc
Rth a
b
Isc
+
-
(c)
a
b
vocRthIsc
Department of Electronic Engineering, NTUT22/47
6
• 6: (a) I
A. (a) Rth
B. a-b (b)
C. a-b (c)
D. (d) I
+− Ω3V24
(a)
I
Rth
a
b
Ω2
Ω6 Ω3
+− V24
(b)
I1
Isc
a
b
Ω6 Ω3
Ω3
A2.8
(c)
a
b
Ω5
(d)
Ia
b
A2.8 Ω5 Ω2
( )6 //3 3 5 thR = + = Ω
( )1
425.6 A
6 3//3I = =
+3
5.6 2.8 A3 3scI = =
+
52.8 2 A
5 2I = =
+
Department of Electronic Engineering, NTUT23/47
III
• () Rth
•Rth Rth
voc Isc
(Driving Point)v( I ) I(
v)
octh
sc
vR
I=
th
vR
I=
Department of Electronic Engineering, NTUT24/47
IV
• (a)(b)
v I+ −
+ −Rth
(a)
+ −+−
S.C.
O.C.
v
(b) Rth
I
a
b
a
b
th
vR
I=
Department of Electronic Engineering, NTUT25/47
7
• 7 (a) a-b
A. isc a-b (b)
+−
6 Ω4 ΩA10
2i1V
i1
a
b(a)
3 Ω
2 110 sci i i= − −
( )1 1 14 10 2 6 0sci i i i− − − − + =
16 3 0sci i− + =
5 Asci =
A10
+−V
(b)
4 Ω 6 Ω
3 Ω2i1
i2 i1 isc
Department of Electronic Engineering, NTUT26/47
7
B. Rth
Rth
(c)
(d)
C. a-b(e)
+−A10
+
−
a
b(c)
(e)
16ocv i=( )1 1 16 2 4 10i i i= + −
30 Vocv⇒ =
( )306
5oc
thsc
vR
i= = = Ω
13 6v i i= +( )1 1 16 2 4i i i i= + −
( )1 0.5 , 6 , 6 th
vi i v i R
i= = = = Ω
3 ΩV2i1i1
4 Ω 6 Ωi110−i1 voc
(d)
+−
+−
a
b
v
Rth
i4 Ω 6 Ω
V2i1
i−i1 i1
3 Ω
a
b
5 A6 Ω
Department of Electronic Engineering, NTUT27/47
8
• 8 (a)
A. (b)
+−a
b(a)
6 Ω
V2i1
i14 Ω
0, 0oc scv i= =
( ) 1th
v vR v
i= = = Ω
121
4 6
v i v− + =
16v i= ( ) ( )1 0.5 A , 3 Vi v= = ( )3 thR = Ω
(b) Rth
+−
b
a
1A
+
−v
Rth
vV2i1
v−2i1
6 Ω4 Ωi1
Department of Electronic Engineering, NTUT28/47
8
(c) Rth
(d)
C. (d)
B. (c)
16v i=( )1 1 16 2 4i i i i= + −
1 0.5 , 3i i v i= =
( )3 th
vR
i= = Ω
v
+−
b
a
V
+
−v
Rth
vV2i1
i−i1
6 Ω4 Ωi1 +
−
i
a
b
3 Ω
Department of Electronic Engineering, NTUT29/47
I
•
•
• ,
•
sL
s L
vi
R R=
+
( )
2 22
2s s L
L L Ls L s L
v v Rp i R R
R R R R
= = ⋅ = + +
0L
dp
dR=
( ) ( )( )
2 2 2
4
2s L s s L s L
L s L
R R v v R R Rdp
dR R R
+ − + =+
( ) ( )( )
2 2
4
2s L s L s s L
s L
R R R R v v R
R R
+ + − =+
( )( )( )
22 2
3 3s L ss s L s
s L s L
R R vR v R v
R R R R
−−= =+ +
s LR R= 0L
dp
dR=
s LR R=( )
2 2
2 4s L s
Ls L
v R vp
RR R= =
+
+−
Rs
+
−vs
iL
RLvL
Department of Electronic Engineering, NTUT30/47
II
• Rs RL = Rs
RL
•
•
RL=Rth RL
+−
Rth
+
−eth RL = Rth
2
max 4s
L
vp
R=
2
max 4g gR i
p =
2
max 4th
th
ep
R=
Department of Electronic Engineering, NTUT31/47
9
• 9 (a) RL
+ −30V
RL
6 Ω
3A8 Ω
20V
1A
4 Ω
2 Ω
+ −20V
(a)
30V
6 Ω
3A8 Ω
20V
1A
4 Ω
2 Ω
20V + −1A
3A
2A
+ −eth+ −
(b)
(b)
8 4 2 6 20 thR = + + + = Ω30 20 8 1 4 2 2 2 6 3 72 Vth the e+ + = ⋅ − ⋅ − ⋅ − ⋅ ⇒ = −
( )22 7264.8 W
4 4 20th
mth
ep
R
−= = =
⋅Department of Electronic Engineering, NTUT32/47
• (Millman’s Theorem)
• N a
• N
+−v1
+−
+−
b
a+
−vv2 vN
R1 R2 RN
1 2
1 2
0N
N
v vv v v v
R R R
−− −+ + + =⋯
( ) ( ) ( )( ) ( ) ( )1 1 2 2
1 21 1 1N N
ocN
v R v R v Rv v
R R R
+ + += =
+ + +⋯
⋯ ( ) ( ) ( )1 2
1
1 1 1thN
RR R R
=+ + +⋯
Department of Electronic Engineering, NTUT33/47
10
• 10
+−
+− +
−
4 Ω 4 Ω
3 Ω
2 Ω
24V32V40V
+
−
v
( )40 32 0 24
184 4 3 2 4.5 V1 1 1 1 44 4 3 2
v+ + −
= = =+ + +
Department of Electronic Engineering, NTUT34/47
Y ∆ I
• Y ∆
∆
RY
R R y
∆∆
=
′a ′b
′c
ba
c
R1 R2
R3RA RC
RB( ) 1 2//ab a b B A CR R R R R R R′ ′= ⇒ + = +
( ) 2 3//bc b c C B AR R R R R R R′ ′= ⇒ + = +
( ) 3 1//ca c a A B CR R R R R R R′ ′= ⇒ + = +
1 2 2 3 3 1
2A
R R R R R RR
R
+ +=
1 2 2 3 3 1
3B
R R R R R RR
R
+ +=
1 2 2 3 3 1
1C
R R R R R RR
R
+ +=
Department of Electronic Engineering, NTUT35/47
Y ∆ II
• Y ∆
• Y
Ry
R
R= ∆
∆
′a ′b
′c
ba
c
R1 R2
R3RA RC
RB( ) 1 2//ab a b B A CR R R R R R R′ ′= ⇒ + = +
( ) 2 3//bc b c C B AR R R R R R R′ ′= ⇒ + = +
( ) 3 1//ca c a A B CR R R R R R R′ ′= ⇒ + = +
1A B
A B C
R RR
R R R=
+ +
2B C
A B C
R RR
R R R=
+ +
3C A
A B C
R RR
R R R=
+ +
Department of Electronic Engineering, NTUT36/47
11
• 11 (a) I vab
2 Ω+
−vab
4 Ω
4 Ω
2 Ω
3 Ω
5 Ω
I
2.5 Ωd b
+ −200V
c a3.4 Ω
(a)
∆ (b) Y
+
−
d b
+ −200V
c a
I1
IT
2.5 Ω
3.4 Ω
1 Ω0.6 Ω
1.5 ΩI2
vab
0.8 Ω
16 Ω0.8 Ω
(b)
( ) ( ) ( )1 0.6 3.4 0.8 // 1.5 2.5 0.8 1.6 5 TR = + + + + + + = Ω ( )20040 AT
T
IR
= =
( )1 2 2 20 ATI I I= = = ( )1 20.6 1.5 18 Vcdv I I= − + =
( )6 A3cdv
I = = ( )1 20.8 0.8 0 Vabv I I= − =
Department of Electronic Engineering, NTUT37/47
I
• Y - ∆ Y ( ) → ∆( )
•
1 2 2 3 3 1 1 2 2 3 3 1 1 212 1 2
3 3 1 2 1 2 3
1 1 1R R R R R R R R R R R R R RR R R
R R R R R R R
+ + + += = = + +
1
1,2, ,1
,where 1,2, ,N
ij i jp p
i N
R R R j NR
i j=
== =
≠∑
⋯
⋯
∆ ( )
23
1
23
1
Y( )
R1
R3 R2
R31 R12
R23
Department of Electronic Engineering, NTUT38/47
II
• N = 4
(1) (Star to Mesh Conversion)
= ( ) × ( )
4 3
1 2
R1 R2
R4 R3
4 3
21
R23
R34
R41
R13
R24
R12
(a) N = 4 ( )
(b) (1/2)N(N-1) = 6 ( )
23 2 31 2 3 4
1 1 1 1R R R
R R R R
= + + +
34 3 4
1 2 3 4
1 1 1 1R R R
R R R R
= + + +
41 4 1
1 2 3 4
1 1 1 1R R R
R R R R
= + + +
13 1 31 2 3 4
1 1 1 1R R R
R R R R
= + + +
24 2 4
1 2 3 4
1 1 1 1R R R
R R R R
= + + +
12 1 2
1 2 3 4
1 1 1 1R R R
R R R R
= + + +
Department of Electronic Engineering, NTUT39/47
III
(2) (Mesh to Star Conversion)
N
R ( ) = R ( ) / N R ( ) = N × R ( )
12 1 21 2 3 4
23 2 31 2 3 4
24 2 41 2 3 4
1 1 1 1
1 1 1 1
1 1 1 1
R R R RR R R R
R R R RR R R R
R R R RR R R R
= + + + =
= + + + =
= + + + =
⋮
12 23 24R R R R= = = =⋯
2312 241 2 3 4 4 4 4 4
RR R RR R R R= = = = = = = =⋯
Department of Electronic Engineering, NTUT40/47
•
()
D
A B
C
C
D
10 ΩA B
D
A B
C
(C, D )
(C, D )
Department of Electronic Engineering, NTUT41/47
12
• 12 (a) A-B Req
(a)
C
A4 Ω 4 Ω
6 Ω
2 Ω2 Ω
B
D
10
Ω
C
A4Ω 4Ω
6Ω
2 Ω2 Ω
B
D
C
A4Ω 4Ω
6Ω
2 Ω2 Ω
B
D
∆
C
A
RA RB
B
D
10 ΩRC
(b)
C
A4 Ω 4 Ω
6 Ω
2 Ω2 Ω
B
D
10
Ω
(C, D ) (C, D )
( )24
13eqR = Ω
Department of Electronic Engineering, NTUT42/47
13
• 13 AC Req
E
CD
A B10 Ω
10 Ω12 Ω
12 Ω
E
CD
A B10 Ω
10 Ω12 Ω
12 Ω
E
CD
A
B
10 Ω
10 Ω12 Ω
12 Ω
(D-E, E-B )
(D-E, E-B )
( ) ( ) ( ) ( )4012 12 // 6 6 // 10 10
7eqR = + + + = Ω
( ) ( ) ( )4012 //6 //10 12 //6 //10
7eqR = + = Ω
Department of Electronic Engineering, NTUT43/47
•
()
C
5 Ω
A B
D
(a)
C D,
5 ΩA B
12 Ω
(b)
(C, D )
Department of Electronic Engineering, NTUT44/47
14
• 14 AD Req
1.
2. BC 10 ΩAD
Req ( )
B
A5 Ω 2 Ω
2 Ω
12 Ω
10 Ω12 Ω
C
D
B C,
A D5 Ω
12 Ω
2 Ω
B
A
5 Ω
2 Ω12 Ω
10 Ω
12 Ω
C
D
(a)
( ) ( ) ( )3512 12 2 // 2 //5
12eqR = + + = Ω
(B, C )
Department of Electronic Engineering, NTUT45/47
15
• 15 R = 10 ΩAB Req
( )
10 Ω
G
H
BA
D
CF
E
5 Ω
5 Ω
5 ΩF
G E× D
B H× C
A
5 Ω
5 Ω
10 Ω
10 Ω
(B-H, G-E )
10 Ω
GF
E D
H C
BA
( ) ( )355 10 5 //5 5 5 //10
6eq eqR R′= = + + + + = Ω
Department of Electronic Engineering, NTUT46/47
•
•
•
• Y ∆
Department of Electronic Engineering, NTUT47/47