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BITS EDU CAMPUS
HYDRAULIC RAM
Presented by : RAJNEESH A JOSHI(140050119026) MANTHAN R KANANI(140050119028)
FUNCTION: It is used for pumping small quantity of water to higher level from the available large quantity of low level.
CONSTRUCTION: It consist of supply tank, supply pipe with supply valve, valve box, delivery pipe & delivery tank. The valve box consist of waste valve V1 and delivery valve V2. the valve V1 open inwards and valve V2 open outwards. Both valve are non return type. Valve V2 connects valve box with air vessel.
WORKING: hydraulic ram works on the principle of water hammer as when aa flowing water is suddenly brought to rest the change in momentum of water masses causes a sudden rise in pressure. This rise in pressure is utilizes to raise a small quantity of water to higher level.
As water is coming into chamber from supply tank the level of water rises in the chamber and waste valve V1 start moving upwards a stage comes when the waste valve V1 suddenly closes. This sudden closer of valve V1 creates high pressure inside the chamber. This high pressure force opens the delivery valve V2. the water from chamber enters from the air vessel and compresses the air inside the air vessel. This compressed air exerts force on the water in the air vessel and small quantity of water is raised to a greater height of delivery tank.
LET, W=weight of water flowing per second into chamber w=weight of water raised per second h=height of water in supply tank above the chamber. H=height of water raised from the chamber.
Energy released from supply tank=W x h
Energy delivered by the ram= w x HEfficiency of hydraulic ram η =energy delivered / energy supplied= w x H / W x h The above equation of efficiency was given by D’ AUBUISSON and therefore it is known as D’ AUBUISSON EFFICIENCY.
• According to Rankine the weight of water w is raised to a height of H-h and not H. The water initially at a height of h from the ram and hence the water is only raised to a height equal to H-h.
• Therefore energy supplied = (W-w)h• Energy delivered by the ram = w(H-h)• Therefore efficiency of ram according
to Rankine η = w(H-h)/(W-w)h
Above D’ AUBUISSON and Rankine efficiency in terms of discharge.
η =qH/Qh D’ AUBUISSON EFFICENCY
η =q(H-h)/(Q-q)h Rankine efficiency where Q = Discharge
through supply pipe q=discharge
through delivery pipe.
THANK YOU