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Home > Quantitative aptitude questions and answers withexplanation > Calendar > Solved Examples
1. Important Formulas2. Solved Examples
1. What day of the week does May 28 2006 fall on
A. Saturday B. MondayC. Sunday D. Thursday
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| Notebook
| Discuss
Here is the answer and explanation
Answer : Option C
Explanation :
28th May 2006 = (2005 years + period from 1-Jan-2006 to 28-May-2006)
We know that number of odd days in 400 years = 0
Hence the number of odd days in 2000 years = 0 (Since 2000 is a perfectmultiple of 400)
Number of odd days in the period 2001-2005
= 4 normal years + 1 leap year
= 4 x 1 + 1 x 2 = 6
Days from 1-Jan-2006 to 28-May-2006 = 31 (Jan) + 28 (Feb) + 31 (Mar) +30 (Apr) + 28(may)
= 148
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148 days = 21 weeks + 1 day = 1 odd day
Total number of odd days = (0 + 6 + 1) = 7 odd days = 0 odd day
0 odd day = Sunday
Hence May 28 2006 is Sunday.
2. What will be the day of the week 15th August, 2010?A. Thursday B. Sunday
C. Monday D. SaturdayHide Answer |
Notebook | Discuss
Here is the answer and explanation
Answer : Option B
Explanation :
15th Aug 2010 = (2009 years + period from 1-Jan-2010 to 15-Aug-2010)
We know that number of odd days in 400 years = 0
Hence the number of odd days in 2000 years = 0 (Since 2000 is a perfectmultiple of 400)
Number of odd days in the period 2001-2009
= 7 normal years + 2 leap year
= 7 x 1 + 2 x 2 = 11 = (11 - 7x1) odd day = 4 odd day
Days from 1-Jan-2010 to 15-Aug-2010
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= 31 (Jan) + 28 (Feb) + 31 (Mar) + 30 (Apr) + 31(may) + 30(Jun) +31(Jul) + 15(Aug)
= 227
227 days = 32 weeks + 3 day = 3 odd day
Total number of odd days = (0 + 4 + 3) = 7 odd days = 0 odd day
0 odd day = Sunday
Hence 15th August, 2010 is Sunday.
3. Today is Monday. After 61 days, it will beA. Thursday B. SundayC. Monday D. Saturday
Hide Answer |
Notebook | Discuss
Here is the answer and explanation
Answer : Option D
Explanation :
61 days = 8 weeks 5 days = 5 odd days
Hence if today is Monday, After 61 days, it will be = (Monday + 5 odd days)
= Saturday
4. On what dates of April, 2001 did Wednesday fall?A. 2 nd, 9 th, 16 th, 23 rd B. 4 th, 11 th, 18 th, 25 th C. 3 rd, 10 th, 17 th, 24 th D. 1 st, 8 th, 15 th, 22 nd, 29 th
Hide Answer | | Discuss
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Notebook Here is the answer and explanation
Answer : Option B
Explanation :
We need to find out the day of 01-Apr-2001
01-Apr-2001 = (2000 years + period from 1-Jan-2001 to 01-Apr-2001)
We know that number of odd days in 400 years = 0
Hence the number of odd days in 2000 years = 0 (Since 2000 is a perfectmultiple of 400)
Days from 1-Jan-2001 to 01-Apr-2001 = 31 (Jan) + 28 (Feb) + 31 (Mar) +1(Apr) = 91
91 days = 13 weeks = 0 odd day
Total number of odd days = (0 + 0) = 0 odd days
0 odd day = Sunday. Hence 01-Apr-2001 is Sunday.
Hence first Wednesday of Apr 2011 comes in 04 th and successiveWednesdays
come in 11 th , 18 th and 25 th
5. How many days are there in x weeks x daysA. 14x B. 8xC. 7x 2 D. 7
Hide Answer | | Discuss
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Notebook Here is the answer and explanation
Answer : Option B
Explanation :
6. The calendar for the year 2007 will be the same for the year
A. 2017 B. 2018C. 2014 D. 2016
Hide Answer |
Notebook | Discuss
Here is the answer and explanation
Answer : Option B
Explanation :
For a year to have the same calendar with 2007 ,the total odd days from2007 should be 0.
Year : 2007 2008 2009 2010 2011 2012 2013 2014 2015 2016 2017
Odd Days : 1 2 1 1 1 2 1 1 1 2 1
Take the year 2014 given in the choice.
Total odd days in the period 2007-2013 = 5 normal years + 2 leap year
= 5 x 1 + 2 x 2 = 9 odd days
= 2 odd day (As we can reduce multiples of 7 from odd days which will notchange
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anything)
Take the year 2016 given in the choice.
Number of odd days in the period 2007-2015 = 7 normal years + 2 leapyear
= 7 x 1 + 2 x 2 = 11 odd days
= 4 odd days(Even if the odd days were 0, calendar of 2007 will not be same as thecalendar of 2016 because 2007 is not a leap year whereas 2016 is a leapyear. In fact, you can straight away ignore this choice due to this factwithout even bothering to check the odd days)
Take the year 2017 given in the choice.
Number of odd days in the period 2007-2016 = 7 normal years + 3 leapyear
= 7 x 1 + 3 x 2 = 13 odd days
= 6 odd days
Take the year 2018 given in the choice.
Number of odd days in the period 2007-2017 = 8 normal years + 3 leapyear
= 8 x 1 + 3 x 2 = 14 odd days
= 0 odd day (As we can reduce multiples of 7 from odd days which will notchange
anything)
Also, both 2007 and 2018 are not leap years.Since total odd days in the period 2007-2017 = 0 and both 2007 and 2018are of same type, 2018 will have the same calendar as that of 2007
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7. Which of the following is not a leap year?A. 1200 B. 800C. 700 D. 2000
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Here is the answer and explanation
Answer : Option C
Explanation :
Remember the leap year rule (Given in the formulas)
1. Every year divisible by 4 is a leap year, if it is not a century.
2. Every 4th century is a leap year, but no other century is a leap year.
800,1200 and 2000 comes in the category of 4th century (such as400,800,1200,1600,2000 etc).
Hence 800,1200 and 2000 are leap years
700 is not a 4th century, but it is a century. Hence it is not a leap year
8. 01-Jan-2007 was Monday. What day of the week lies on 01-Jan-2008?A. Wednesday B. SundayC. Friday D. Tuesday
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Here is the answer and explanation
Answer : Option D
Explanation :
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Given that January 1, 2007 was Monday.
Odd days in 2007 = 1 (we have taken the complete year 2007 because weneed to find out
the odd days from 01-Jan-2007 to 31-Dec-2007, that is the whole year2007)
Hence January 1, 2008 = (Monday + 1 Odd day) = Tuesday
9. 8th Dec 2007 was Saturday, what day of the week was it on 8th Dec, 2006?
A. Sunday B. TuesdayC. Friday D. Tuesday
Hide Answer |
Notebook | Discuss
Here is the answer and explanation
Answer : Option C
Explanation :
Given that 8th Dec 2007 was Saturday
Number of days from 8th Dec, 2006 to 7th Dec 2007 = 365 days
365 days = 1 odd day
Hence 8th Dec 2006 was = (Saturday - 1 odd day) = Friday
10. On 8th Feb, 2005 it was Tuesday. What was the day of the week on 8th Feb, 2004?A. Sunday B. FridayC. Saturday D. Monday
Hide Answer | | Discuss
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Notebook Here is the answer and explanation
Answer : Option A
Explanation :
Given that 8th Feb, 2005 was Tuesday
Number of days from 8th Feb, 2004 to 7th Feb, 2005 = 366
(Since Feb 2004 has 29 days as it is a leap year)
366 days = 2 odd days
Hence 8th Feb, 2004 = (Tuesday - 2 odd days) = Sunday
11. The last day of a century cannot be
A. Monday B. WednesdayC. Tuesday D. Friday
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Notebook | Discuss
Here is the answer and explanation
Answer : Option C
Explanation :
We know that number of odd days in 100 years = 5
Hence last day of the first century is Friday
Number of odd days in 200 years = 5 x 2 = 10 = 3 ( As we can reducemultiples of 7
from odd days which will not change anything )
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Hence last day of the 2 nd century is Wednesday
Number of odd days in 300 years = 5 x 3 = 15 = 1 ( As we can reduce
multiples of 7
from odd days which will not change anything )
Hence last day of the 3 rd century is Monday
We know that umber of odd days in 400 years = 0. (? 5 x 4 + 1 = 21 = 0)
Hence last day of the 4 th century is Sunday
Now this cycle will be repeated.
Hence last day of a century will not be Tuesday or Thursday or Saturday.
its better to learn this by heart which will be helpful to save time in objectivetype
exams
12. January 1, 2008 is Tuesday. What day of the week lies on Jan 1, 2009?A. Saturday B. WednesdayC. Thursday D. Saturday
Hide Answer |
Notebook | Discuss
Here is the answer and explanation
Answer : Option C
Explanation :
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Number of odd days in 2008 = 2 (since it is a leap year)
(we have taken the complete year 2008 because we need to find out the odddays from
01-Jan-2008 to 31-Dec-2008, that is the whole year 2008)
Given that January 1, 2008 is Tuesday
Hence January 1, 2009 = (Tuesday + 2 odd days) = Thursday
13. If Jan 1, 2006 was a Sunday, What was the day of the week Jan 1, 2010?
A. Friday B. ThursdayC. Tuesday D. Saturday
Hide Answer |
Notebook | Discuss
Here is the answer and explanation
Answer : Option A
Explanation :
Given that Jan 1 2006 was a Sunday
Number of odd days in the period 2006-2009
= 3 normal years + 1 leap year
= 3 x 1 + 1 x 2 = 5
(note that we have taken the complete year 2006 because the period in2006
is from 01-Jan-2006 to 31-Dec-2006, which is the whole year 2006. Thenthe
complete years 2007, 2008 and 2009 are also involved)
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Hence Jan 1 2010 = (Sunday + 5 odd days) = Friday
14. What was the day of the week on 17th June 1998?A. Monday B. SundayC. Wednesday D. Friday
Hide Answer |
Notebook | Discuss
Here is the answer and explanation
Answer : Option C
Explanation :
17 Jun 1998 = (1997 years + period from 1-Jan-1998 to 17-Jun-1998)
We know that number of odd days in 400 years = 0
Hence the number of odd days in 1600 years = 0 (Since 1600 is a perfectmultiple of 400)
Number of odd days in the period 1601-1900
= Number of odd days in 300 years
= 5 x 3 = 15 = 1
(As we can reduce perfect multiples of 7 from odd days without affectinganything)
Number of odd days in the period 1901-1997
= 73 normal years + 24 leap year
= 73 x 1 + 24 x 2 = 73 + 48 = 121 = (121 - 7 x 17) = 2 odd days
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Number of days from 1-Jan-1998 to 17-Jun-1998
= 31 (Jan) + 28 (Feb) + 31 (Mar) + 30 (Apr) + 31(may) + 17(Jun)
= 168
168 days = 0 odd day
Total number of odd days = (0 + 1 + 2 + 0) = 3
3 odd days = Wednesday
Hence 17th June 1998 is Wednesday.
15. 6th March, 2005 is Monday, what was the day of the week on 6th March, 2004?A. Friday B. SaturdayC. Wednesday D. Sunday
Hide Answer |
Notebook | Discuss
Here is the answer and explanation
Answer : Option D
Explanation :
Number of days from 6th March, 2004 to 5th March 2005 = 365 days
(Though Feb 2004 has 29 days as it is a leap year, it will not come in therequired period)
365 days = 1 odd day
Given that 6th March, 2005 is Monday
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Hence 6th March, 2004 = (Monday - 1 odd day) = Sunday
16. What day of the week was 1 January 1901A. Monday B. TuesdayC. Saturday D. Friday
Hide Answer |
Notebook | Discuss
Here is the answer and explanation
Answer : Option B
Explanation :
1 Jan 1901 = (1900 years + 1-Jan-1901)
We know that number of odd days in 400 years = 0
Hence the number of odd days in 1600 years = 0 (Since 1600 is a perfectmultiple of 400)
Number of odd days in the period 1601-1900
= Number of odd days in 300 years
= 5 x 3 = 15 = 1
(As we can reduce perfect multiples of 7 from odd days without affectinganything)
1-Jan-1901 = 1 odd day
Total number of odd days = (0 + 1 + 1) = 2
2 odd days = Tuesday
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Hence 1 January 1901 is Tuesday.
17. What day of the week will 22 Apr 2222 be?A. Monday B. TuesdayC. Sunday D. Thursday
Hide Answer |
Notebook | Discuss
Here is the answer and explanation
Answer : Option A
Explanation :
22 Apr 2222 = (2221 years + period from 1-Jan-2222 to 22-Apr-2222)
We know that number of odd days in 400 years = 0
Hence the number of odd days in 2000 years = 0 (Since 2000 is a perfectmultiple of 400)
Number of odd days in the period 2001-2200
= Number of odd days in 200 years
= 5 x 2 = 10 = 3
(As we can reduce perfect multiples of 7 from odd days without affectinganything)
Number of odd days in the period 2201-2221
= 16 normal years + 5 leap years
= 16 x 1 + 5 x 2 = 16 + 10 = 26 = 5 odd days
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Number of days from 1-Jan-2222 to 22 Apr 2222
= 31 (Jan) + 28 (Feb) + 31 (Mar) + 22(Apr) = 112
112 days = 0 odd day
Total number of odd days = (0 + 3 + 5 + 0) = 8 = 1 odd day
1 odd days = Monday
Hence 22 Apr 2222 is Monday.
18. Today is Thursday. The day after 59 days will be?A. Monday B. TuesdayC. Saturday D. Sunday
Hide Answer |
Notebook | Discuss
Here is the answer and explanation
Answer : Option D
Explanation :
59 days = 8 weeks 3 days = 3 odd days
Hence if today is Thursday, After 59 days, it will be = (Thursday + 3 odddays)
= Sunday
19. What is the year next to 1990 which will have the same calendar as that of the year 1990?A. 1992 B. 2001C. 1995 D. 1996
Hide Answer | | Discuss
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Notebook Here is the answer and explanation
Answer : Option B
Explanation :
For a year to have the same calendar with 1990 ,total odd days from 1990should be 0.
Take the year 1992 from the given choices. Total odd days in the period 1990-1991= 2 normal years 2 x 1 = 2 odd days
Take the year 1995 from the given choices.
Number of odd days in the period 1990-1994 = 4 normal years + 1 leapyear 4 x 1 + 1 x 2 = 6 odd days
Take the year 1996 from the given choices. Number of odd days in the period 1990-1995= 5 normal years + 1 leap year 5 x 1 + 1 x 2 = 7 odd days 0 odd days(As we can reduce multiples of 7 from odd days which will not changeanything)
Though number of odd days in the period 1990-1995 is 0, there is a catchhere.1990 is not a leap year whereas 1996 is a leap year.Hence calendar for 1990 and 1996 will never be the same.
Take the year 2001 from the given choices. Number of odd days in the period 1990-2000= 8 normal years + 3 leapyears 8 x 1 + 3 x 2 = 14 odd days 0 odd days Also, both 1990 and 2001 are normal years.Hence 1990 will have the same calendar as that of 2001
20. January 1, 2004 was a Thursday, what day of the week lies on January 1 2005.A. Saturday B. MondayC. Saturday D. Tuesday
Hide Answer | Discuss
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| Notebook
Here is the answer and explanation
Answer : Option C
Explanation :
Given that January 1, 2004 was Thursday.
Odd days in 2004 = 2 (because 2004 is a leap year)
(Also note that we have taken the complete year 2004 because we need tofind out
the odd days from 01-Jan-2004 to 31-Dec-2004, that is the whole year2004)
Hence January 1, 2005 = (Thursday + 2 Odd days) = Saturday
21. If the first day of a year (other than leap year) was Friday, then which was the last day ofthat year?A. Saturday B. Friday
C. Tuesday D. Monday
Hide Answer |
Notebook | Discuss
Here is the answer and explanation
Answer : Option B
Explanation :
Given that first day of a normal year was Friday
Odd days of the mentioned year = 1 (Since it is an ordinary year)
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Hence First day of the next year = (Friday + 1 Odd day) = Saturday
? Last day of the mentioned year = Friday
22. If 1 st October is Sunday, then 1 st November will beA. Saturday B. ThursdayC. Wednesday D. Tuesday
Hide Answer |
Notebook | Discuss
Here is the answer and explanation
Answer : Option C
Explanation :
Given that 1 st October is Sunday
Number of days in October = 31
31 days = 3 odd days
(As we can reduce multiples of 7 from odd days which will not changeanything)
Hence 1 st November = (Sunday + 3 odd days) = Wednesday
23. Arun went for a movie nine days ago. He goes to watch movies only on Thursdays. Whatday of the week is today?A. Wednesday B. SaturdayC. Friday D. Sunday
Hide Answer |
Notebook | Discuss
Here is the answer and explanation
Answer : Option B
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Explanation :
Clearly it can be understood from the question that 9 days ago was aThursday
Number of odd days in 9 days = 2 (As 9-7 = 2, reduced perfect multiple of 7from total days)
Hence today = (Thursday + 2 odd days) = Saturday
24. 1.12.91 is the first Sunday. Which is the fourth Tuesday of December 91?
A. 20.12.91 B. 22.12.91C. 24.12.91 D. 25.12.91
Hide Answer |
Notebook | Discuss
Here is the answer and explanation
Answer : Option C
Explanation :
Given that 1.12.91 is the first Sunday
Hence we can assume that 3.12.91 is the first Tuesday
If we add 7 days to 3.12.91, we will get second Tuesday
If we add 14 days to 3.12.91, we will get third Tuesday
If we add 21 days to 3.12.91, we will get fourth Tuesday
=> fourth Tuesday = (3.12.91 + 21 days) = 24.12.91
25. If the day before yesterday was Thursday, when will Sunday be?
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A. Day after tomorrow B. TomorowC. Two days after today D. Today
Hide Answer |
Notebook | Discuss
Here is the answer and explanation
Answer : Option B
Explanation :
Day before yesterday was Thursday
=>Yesterday was a Friday
=> Today is a Saturday
=> Tomorrow is a Sunday
26. The second day of a month is Friday, What will be the last day of the next month which has31 days?A. Friday B. SaturdayC. Wednesday D. Data inadequate
Hide Answer |
Notebook | Discuss
Here is the answer and explanation
Answer : Option D
Explanation :
We cannot find out the answer because the number of days of the current
month is not given.
27. How many days will there be from 26 th January,1996 to 15 th May,1996(both days included)?A. 102 B. 103C. 111 D. 120
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Hide Answer |
Notebook | Discuss
Here is the answer and explanation
Answer : Option C
Explanation :
Number of days from 26-Jan-1996 to 15-May-1996 (both days included)
= 6(Jan) + 29(Feb) + 31 (Mar) + 30(Apr)+ 15(May) = 111
28. If 25 th of August in a year is Thursday, the number of Mondays in that month is
A. 4 B. 5C. 2 D. 3
Hide Answer |
Notebook | Discuss
Here is the answer and explanation
Answer : Option B
Explanation :
Given that 25 th August = Thursday
Hence 29 th August = Monday
So 22 nd ,15 th and 8 th and 1 st of August will be Mondays
Number of Mondays in August = 5
29. If the seventh day of a month is three days earlier than Friday, What day will it be on thenineteenth day of the month?
A. Saturday B. MondayC. Sunday D. Wednesday
Hide Answer | Discuss
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| Notebook
Here is the answer and explanation
Answer : Option C
Explanation :
Given that seventh day of a month is three days earlier than Friday
=> Seventh day is Tuesday
=> 14 th is Tuesday
=> 19 th is Sunday
30. Every second Saturday and all Sundays are holidays. How many working days will be therein a month of 30 days beginning on a Saturday?A. 24 B. 23C. 18 D. 21
Hide Answer |
Notebook | Discuss
Here is the answer and explanation
Answer : Option B
Explanation :
Mentioned month has begins on a Saturday and has 30 days
Sundays = 2 nd , 9 th , 16 th , 23 rd , 30 th
=> Total Sundays = 5
Second Saturdays = 8 th and 22 nd
Total Second Saturdays = 2
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Total Holidays = Total Sundays + Total Second Saturdays = 5 + 2 = 7
Total days in the month = 30
Total working days = 30 - 7 = 23
Comments(36)New est
gugan 17 Jul 2014 2:34 PM nice
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Raghu 14 Jul 2014 6:17 PM Good Explanation. I learned some basic stuff today. Thanks for the post.
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Sachin Kasab 30 May 2014 2:02 PM Very nice
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SANJEEV KUMAR 12 Apr 2014 1:59 PM I like it
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lakshmi 16 Feb 2014 8:52 AM How many odd days are der in 302 days?Like | Dislike | Reply | Flag
rahul 09 Aug 2014 12:54 PM 302/7=43 and remainder is 1 so odd day is 1
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deepthireddy 04 Mar 2014 5:47 PM 1
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deepthireddy 04 Mar 2014 5:46 PM 3
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Sreeju 16 Feb 2014 10:33 PM 302 = 43*7 + 1Hence, 1 odd day
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imman 08 Nov 2013 9:37 PM
very easy to learn thanq.. Like | Dislike | Reply | Flag
next last
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4 + 1 =
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