46
69174 תרגול בקורס כימיה כללית ־ מתרגל: שחר סוקניק סוכם ע"י עמוס שטמר. תוכן עניינים2 ............................................. רקע1 2 .................................... לוגריתמים1.1 3 ............................... ספרות משמעותיות1.2 4 ..................................... חוק קולון1.3 4 ..................................... הטבלה המחזורית2 4 ...................................... מסה ומושג המול3 6 ......................................... מודל בוהר4 6 ....................... חוק האיסור של פאולי ומספרים קוונטיים5 7 ................................ ניוון ־ האנרגיה שלהם זהה6 7 ........................................ כללי איכלוס7 8 ............................................. יונים8 8 ............................... קונפיגורציות יציבות8.1 9 ................................. מגמות בטבלה המחזורית9 מטען אפקטיבי ־ כמות המטען שאלקטרוני הערכיות מרגישים שמושך9.1 9 .................................. אותם מהגרעין9 .. מהזמן90% רדיוס אטומי ־ המרחק הכי ארוך שבו אלקטרונים מבלים9.2 10 ...................... זיקה אלקטרונית ־9.3 10 ........................ אנרגיית יינון־9.4 10 ............................... רישום והבנת מבנה מולקולה10 10 ....................................... לואיס10.1 11 ..................................... VSEPER 10.2 12 ................................ תכונות המולקולה10.3 14 ....................................... סטויכיומטריה11 16 ........................................ הרכב אמפירי12 16 ..................................... נוסחא מולקולרית13 17 ......................................... גורם מגביל14 18 ........................................... ניצולת15 18 ..................................... ריכוז ־ מולאריות16 19 ....................................... סוגי ריאקציות17 19 ....................................... המסה17.1 19 ........................ (סתירה) ריאקציה חומצה־בסיס17.2 20 ........................................ שיווי משקל18 23 ......................... שיווי משקל ספציפי בחומצות ובסיסים19 28 ...................................... עקומות טטרציה20 30 ...................... שיווי משקל בריאקציה של שיקוע ־ מסיסות21 33 ......................................... קומפלקסים22 33 ................................ ריאקציות של חמצון חיזור23 35 ........................ כללים כדי לקבוע דרגות חמצון23.1 36 ......................................... תרמוכימיה24 1

שאלות פתורות בכימיה 2

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  • 47196

    :

    " .

    1 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 21.1 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 22.1 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 33.1 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 42 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 43 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 44 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 65 . . . . . . . . . . . . . . . . . . . . . . . 66 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 77 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 78 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 81.8 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 89 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 9

    1.9 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 92.9 %09 . . 93.9 ytina nortcele . . . . . . . . . . . . . . . . . . . . . . 014.9 ygrene noitazinoi . . . . . . . . . . . . . . . . . . . . . . . . 0101 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 011.01 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 012.01 REPES V . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 113.01 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 2111 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 4121 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 6131 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 6141 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 7151 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 8161 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 8171 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 911.71 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 912.71 )( . . . . . . . . . . . . . . . . . . . . . . . . 9181 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 0291 . . . . . . . . . . . . . . . . . . . . . . . . . 3202 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 8212 . . . . . . . . . . . . . . . . . . . . . . 0322 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 3332 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 331.32 . . . . . . . . . . . . . . . . . . . . . . . . 5342 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 63

    1

  • 52 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 7362 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 8372 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 9382 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 0492 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 3403 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 4413 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 64

    1

    30.0g

    lm5 ro

    g

    L

    30.0g

    lm

    lm0001

    L

    03 =g

    L

    . 3001

    m0101 = 13mc1 = lm1 lmg 1 =

    3001(

    m0101(3)

    mc001

    m

    (3)g1

    lm

    )g2201 =

    " sm043 = V

    = ces0063 = ruoh1

    (ces0063

    rh1

    )

    043m

    s

    (s0063

    rh1

    ()mk1

    m0001

    )4221 =

    mk

    h

    1.1

    301 3.0 + 601 4.0

    x = N01gol N = x01

    3 = 000101gol

    2

  • 0 = 101gol

    nl = egol

    ygol +xgol = )yx(gol

    (golx

    yygol )x(gol = )

    )x(goly = y)x(gol

    2.1 5

    gk061.17 gk181.17 gk341.17 gk531.17 gk251.17

    , 1.17

    , . :

    1. 02. 4.3017

    3. 301 4.5 = 4500.04. 201 1 gid gis1 001 0.001

    0.001 gid gis4.001 gid gis3 .001

    s301 050.8 4 hmk 201 5.1 = hmk051 2

    , , 4

    5 .

    311.13 = 310.1 0.81 1.21

    1.13

    .

    301 50.1531.6

    401 5117.1 =

    3 401 17.1

    3

  • 3.1

    = F2q1qk2r

    2c2mN901 99.8 = k

    c9101 6.1 = 1qc9101 6.1 = 2q

    51

    = F2C12q 2c2mN901 99.82)mc001m1 ( 2mc51

    = F 2c2mN801 99.8

    2c 2)9101 6.1(2m4011 251

    1102.11.01:

    2

    aXz

    x .z: ' +p = z

    a: 0n + +p = a

    .

    3

    g4201 45066.1 = uma1+pm 0nm uma1

    21mc 6

    uma21 = )uma(

    lom1 3201 220.6 = aN

    4

  • g1 = 3201 220.6 g3201 45066.1 uma1 ) lomg (wm

    5.4 n

    660.23 = swmg

    lomsn sm

    )g(sm

    (s1wm

    lom

    g

    ))lom(sN =

    1 g5.4lomg 660.23

    lom41.0 = lom341.0 =

    mota# sNsmota#aN lom41.0

    lomsmota# =

    1 3201 220.6 lom41.0lom

    smota2201 4.8 =

    lom57.0 ?

    uAm uAN791769.691 = uAwm uA 97

    g

    lom

    769.691(lomng

    lom)g(m = )

    g 769.691 lom57.0lom

    g051 = 52527.741 =

    iN, ?

    396.85 = iNwmg

    lomg001 = uAm

    g05 = iNm

    )g(m

    (1wm

    lom

    g

    ))lom(n =

    = uAng001

    lomg 796.691lom5.0 =

    = iNng05

    lomg 396.85lom9.0 =

    459.51 = Hwm2 + owm = o2Hwmg

    lomg 800.1 2 +

    lom50.81 =

    g

    lom

    5

  • 4 n .

    nE

    = nEB2n

    J8101 971.2 = B:

    3 = n?

    B = 1E 3E = laitiniE lanifE = E(

    1

    231

    21

    )=

    8

    9J8101 739.1 = B

    : J8101 169.1 ?

    B = J8101 169.1 = E(

    1

    2n1 )

    J8101 269.1B

    =1

    2n01 269.1 1 1

    J81B

    =1

    2n161.3 = n 099.9 = 2n 1001.0 =

    ,

    5

    1. n: . .

    2. l: . 0 ,1 ,...1 n: 0 : s 1 : p 2 : d 3 : f

    3. lm: , : l ,1l... ,0 ,... ,1+l,l = lm p = 1 = l zp ,yp ,xp ro 1 ,0 ,1 = lm

    4. sm: 21 = sm 3 = n

    3 = n

    2 ,1 ,0 = l

    lm l n0 0 31 1 30 1 31 1 32 2 31 2 30 2 31 2 32 2 3

    6

  • 3 = n 81 n

    n 2n2

    6 ' n

    s2 ,yp2 ,xp2 , 2zd3

    s2 ,yp2 ,xp2 " l n.

    7 1. .

    2. )( .

    3. .

    P51

    7

  • E

    p3

    s3

    p2

    s2s1

    3p32s36p22s22s1 : P

    3p32s3]eN[ : P

    8 1. .

    2.

    3

    6p32s3]eN[ : 3 P

    2p32s3]eN[ : +P

    1.8 1.

    2.

    s p . ?

    uC92

    8

  • E

    d3 s4

    p3 s3

    p2

    s2s1

    s4 d3

    d3]rA[ : uC921s401

    9 n

    1.9

    Z

    )e eroc#( Z = ffeZ

    1. .

    2.

    ffeZ ) (

    2.9 %09 , :

    1.

    2. ) (

    F ,eB,aN

    1 = ffeZ3 = n : aN

    2 = ffeZ2 = n : eB

    7 = ffeZ2 = n : F

    aN eB F.eB .

    9

  • 3.9 ytina nortcele

    A e +A

    .

    1. ffeZ .

    2.

    4.9 ygrene noitazinoi

    e + +A A

    . ffeZ

    1.

    2.

    :

    F + +O Fdna Oro

    +F + O Fdna O

    01 1.

    2. REPES V

    3.

    4. .

    1.01 NC

    1. : 1+5+4 = 01

    2. ,

    N C

    01

  • 3.

    4.

    C :..

    N..

    :

    5. ,

    C :: N

    6.

    sdnob# egnidnobnon# eecnelav# = CF1 = 3 2 4 = )C(CF0 = 3 2 5 = )N(CF

    1

    7.

    2.01 REPES V1. ,

    2 2. ,

    ) ( pi

    ps

    C p p2

    ps s2

    N p p2

    ps s2

    ps p

    11

  • 3.01 1.

    C : C : N

    C .

    2.

    C C H +H+ N

    N

    42OS

    1. 23 = 2 + 42 + 6 : elav

    2. S 5

    3. 1 = 1 6 6 = )O(CF 2 = 4 0 6 = )S(CF

    21

  • , S d

    . O

    S 4 .

    3ps4 , 4 3 3 2ps 3 ) p d

    pi( 43ps

    :

    ) ( ?

    . .

    OOC3HC

    42

    31

  • 1 = CF

    3 2ps3 p .

    021 09 ?

    .

    11

    3OS 2O+ 2OS .

    1. .

    2. , .

    3. . ) 2H2O (

    4. .

    3OS 2O+ 2OS+ 2OS

    1

    23OS 2O

    2etorwew

    2 OSsdnob tnelevoc etirw tndid ewsmota ynamwoh

    3OS2 2O+

    41

  • 4OP3H O2H+ 01O4P4OP3H4 O2H+ 01O4P4OP3H4 O2H6 + 01O4P

    3ONaN+ 4OSbP 4OS2aN+ 2)3ON(bP3ONaN2 + 4OSbP 4OS2aN+ 2)3ON(bP

    2OS + 3O2eF 2SeF + 2O 42 2SeF 2O, 3O2eF ?

    3O2eFlom# 2SeFm2OS8 + 3O2eF2 2SeF4 + 2O11

    eFwm+ swm2 = 2SeFwm

    2SeFm = 3O2eFlom#

    (1

    2SeFwm

    )2SeF(lom

    g

    ()2

    4

    )3O2eF(lom

    )2SeF(lom

    )g0.42 =

    1

    779.911)2SeF(lom

    g1

    2)3O2eF(lom )2SeF(lom

    )3O2eF(lom001.0 =

    2 2O

    )g(2Om )3O2eF(lom#)3O2eF(lom# = )g(2Om

    (11

    2

    )2O(lom

    )3O2eF(lom

    )2Owm

    (g

    )2O(lom

    ) ))3O2eF(lom( 001.0 =

    (11

    2

    )2O(lom

    )3O2eF(lom

    )899.13

    (g

    )2O(lom

    )g6.71 =

    3 ?

    g6.14 = g6.71 + g0.42

    01g gM gM

    2O OgM 2F 2FgM 32.6 , 2FgM?

    )2FgM(lom 2FgMm= )2FgM(lom

    2FgMm2FgMwm

    (glom

    32.6 = )203.26

    lom001.0 =

    , gM ?

    51

  • OgM 2O+ gMOgM2 2O+ gM22O+ 2FgM 2F + OgM

    2O+ 2FgM2 2F2 + OgM2)gM( lom# )2FgM( lom#

    )2FgM( lom# = )gM( lom#(

    2

    2

    )OgM( lom

    )2FgM( lom

    )(

    2

    2

    )gM( lom

    )OgM( lom

    ))gM( lom001.0 =

    3, 01 .

    = %tw)g(gMm

    latotm001

    )g(gmm )gM(lom#)gM(lom# = )g(gmm

    (gMwm

    g

    lom

    )g34.2 =

    = %tw3.42

    01%3.42 = 001

    21 .

    5H2C 01H4C .

    31 .

    O,H,C , %38.85C

    H %8.9 O %73.13 ? 001 .

    = C)g(38.85

    lomg 110.21894.2 = 169.1/898.4 lom898.4 =

    = O)g(73.13

    lomg 999.511 = 169.1/169.1 lom169.1 =

    = Hg08.9

    lomg 800.189.4 = 169.1/27.9 lom27.9 =

    : 2O01H5C lomg 662.402 .

    celomwmpmewm

    =lomg 662.402lomg 331.201

    2 =

    61

  • 4O02H01C ) 2OC + O2H(

    2OC + O2H 2O+ 4O02H01C2OC01 + O2H01 2O31 + 4O02H01C

    g8.3 g7.8 , .

    ON 2ON O2N 3O2N

    = Ng8.3

    lomg 700.4172.0 72.0 =

    72.01 =

    = Og7.8

    lomg 999.5145.0 45.0 =

    72.02 =

    2ON

    41 : 8H3C

    1. 2. 054 2 .

    3.

    )g(O2H+ )g(2OC )g(2O+ )g(8H3C)g(O2H4 + )g(2OC3 )g(2O5 + )g(8H3C

    1 g054 = ))g(8H3C(lom#1.44

    lom

    glom2.01 =

    5 lom2.01 = )2O(lom#1

    lom

    lom)2O(lom15 =

    15 , 15

    1 2 g0002 = 2Olom#4999.51

    lom

    glom5.26 =

    )8H3C(lom# = )g(O2Hm4

    1

    )O2H( lom

    lom= g)O2H(wm

    g437 = 0.81 4 g4.01 =

    = )2O(wm )lom# lom#( = 2Ormg863 = 0.23 )0.15 5.26( =

    71

  • 51 : 808

    2OC

    = %dleiydleiy laer

    dleiy yroeht001

    )8H3C(lom# = 2OCm3

    1

    lom

    lom= 0.44 3 2.04 = )2OC(wm

    = dleiy%g808

    %06 = 001 0.44 3 2.04

    61

    = M1lom1

    L1

    c

    : lm042 g02.4 ? 11O22H21C

    )qa(11O22H21C )s(11O22H21C

    = )11O22H21C(cglom wm1 )g(m

    )puc( V= l

    glom 2.2431 g2.4L042.0

    1150.0 =lom

    LMm1.15 = M1150.0 =

    M73.0 )Lm033(?

    = snoops#)puc ragus(m

    )noops regus(m=puc regusC

    (lomL

    )lomg ( raguswm )L(pucV ))noops regus(m

    =lomg 2.243 L33.0 Llom73.0

    g02.4snoops01 =

    niV niC = nifV nifC )lom#(nin = )lom#(nifnL33.0 M73.0 = nifV L33.0 M73.0 = nifV M1150.0

    M1150.0L83.2 =

    L1.2 = niV nifV = ddaV

    81

  • 71 1.71

    " .

    .

    .

    )s(lCaN)qa(lC + )qa(+aN )l(O2H

    )4OS( 2+3lA

    23)4OS(2lA )s(3

    )s(3)4OS(2lA42OS3 + +3lA2 )l(O2H

    :

    1. 3ON

    )s(3ONgA+ )s(rBaN)qa(3ON+ )qa(+gA+ )qa(rB+ )qa(+aN )l(O2H

    ) (

    )qa(3ON+ )qa(+aN+ )s(rBgA

    2.71 )(

    aB+ )s(lCH)s(2)HO(+2

    )qa(lC + )qa(+2aB+ )l(O2H lO2HaB+ )s(lCH2

    )s(2)HO(+2)qa(lC2 + )qa(+2aB+ )l(O2H2 lO2H

    :

    )s(3lCeF + )s(HOK)qa(lC3 + +3eF + )qa(HO+ )qa(+K lO2H

    )qa(lC3 + )qa(+K3 + 3)HO(eF )s(3lCeF + )s(HOK3

    )l(4OP3H+ )s(2)HO( aB43OP + )qa(+2aB+ )l(O2H lO2H

    )s(2)4OP( 3aB+ )l(O2H6 )l(4OP3H2 + )s(2)HO( aB3

    g412.43 2)4OS(2lA 1 .

    2)4OS(2lA)qa(2)4OS(3 + )qa(+3lA2 lO2H

    = )M(+3lAClAlom 12 wm1 tlasm

    +3

    tlaslom

    L1M2.0 =

    42OSC+3lAC =

    (3

    2

    ) 42OS(lom)+3lA(lom

    )M3.0 =

    91

  • 81

    6H2C )s(2H+ )s(4H2C qeK=

    = qeKrazot zukir

    mivigam zukir

    1M99.0 = qeK M533.0

    M625.0 ? :

    1.

    2.

    3. Q

    4. ECI

    5.

    )g(6H2C )g(2H+ )g(4H2C

    = Q]6H2C[

    ]2H[]4H2C[0 =

    ,

    0 M625.0 M533.0 Ix+ x x CM890.0 = x M824.0 = x 625.0 M732.0 = x M533.0 E

    = qeK]6H2C[

    ]2H[]4H2C[=

    Mx

    M99.0 = 2M)x 625.0( )x 533.0(= 1

    =Mx

    = 2x +x625.0 x533.0 625.0 533.0x

    99.0 = 671.0 +x168.0 2x71.0 +x9.1 2x99.0 = 0 M890.0 ,M8.1 = 21x

    M890.0 = x 890.0 = 6H2C M824.0 = 2H M732.0 = 4H2C

    , 4.13 = qeK 02

    02 ?

    )g(2H+ )g(2OC )g(O2H+ )g(OC

    qeK = Vlom = C

    02

  • = qeK]2OC[]2H[

    ]O2H[]OC[=

    )2H(ntotV

    totV)2OC(n )OC(ntotv

    totv)O2H(n

    )g(2H+ )g(2OC )g(O2H+ )g(OC

    = OCn IOCm= O2Hn lom417.0 = OCwm

    )O2H(m)O2H(wm

    lom011.1 =

    x+ x+ x x Clom386.0 == lomx lom386.0 = lomx lom724.0 = lomx 011.1 lom130.0 = lomx 417.0 E

    = qek2OCn 2Hn= OCn O2Hn

    2x

    4.13 = )x 011.1( )x 417.0(

    0 = 88.42 +x3.75 2x4.03M386.0 ,M02.1 = 21x

    M386.0 = x

    g967.0 g600.3 2OC

    ?

    n = 2OC(nqe2OC

    +2Ocm2OCwm

    lom3860.0 + lom386.0 =

    O2H(n+ O2Hqen = )

    O2HmO2Hwm

    lom7240.0 + lom724.0 =

    Q

    = Q)2H(n )2OC( n= )O2H(n )OC(n

    )lom3860.0 + lom386.0( 386.0= )7240.0 + 724.0( 130.0

    )386.0( 1.1 386.0qeK = )724.0( 1.1 130.0

    1. Q > qeK

    2. Q < qeK

    3. Q = qeK

    M301 72.1 = qeK

    003

    )g(O2H )l(O2H

    12

  • M301 72.1 = ])g(O2H[ = qeK

    0 = Q

    = qeK)g(O2HqentotV

    totV qeK = )g(O2Hqen

    n = )l(O2Hnlaitini= )g(O2Hqen O2H

    O2Hnim)O2H(wm

    totV qeKdlroweht fo

    0 =

    0

    gk3 L001

    n = )l(O2Hnlaitini= )g(O2Hqen O2H

    O2Hnim)O2H(wm

    g0003 = totV qeKlomg 0.81

    lom35.661 = L001 M301 72.1

    )g(2H3 + )g(2H2C )g(4HC2

    )g(2H3 + )g(OC )g(2H+ )g(4HC012.1 = qeK

    2M52

    M201 11.1 = qeK )g(O2H2 + )g(OC4 )g(2O3 + )g(2H2C2+ 2H

    1

    21M0401 1.1 = qeK O2H 2O

    = qeK )g(2H6 + )g(OC2 O)g(2H2 + )g(4HC2(2)2M5201 2.1

    1 2 1 2

    + )g(2H2C )g(O2H+ )g(OC23

    2= qeK)g(2O

    (21 )M201 11.1

    3

    + 2H33

    2= qeK O2H3 2O

    (3)1M0401 1.1

    22

  • + 2H33

    2+ )g(2H2C+ )g(2H6 + )g(OC2 +O2H3 )g(O2H+ )g(OC2 +O)g(2H2 + )g(4HC2 + 2O

    3

    2)g(2O

    2H2C + 2H3 4HC2

    K = qeK2K 1

    12

    33K 2

    91 1

    3HN 3OCH ? qeK 52.01=aKp 47.4 = bKp

    OCH+ )qa(3HNHN )qa(3

    +OC + 4

    23

    .aKp

    gol = aKp(OCH(aK

    )32OC + +O3H )l(O2H+ )qa(3OCH )

    HO+ 4+HN O2H+ 3HN ))3HN(bk(gol = bKp

    .

    OC O2H2 + )qa(3HN+ )qa(3OCH2HN+ )qa(3

    +O3H+ )qa(4

    +HO+ )qa(

    )qa(

    O3H+ )qa(HO )l(O2H2+01 = wK = )qa(

    41

    w1K

    = w1K bK aK = qeKbKaKwK

    = qeK47.401 52.0101

    410101.0 =

    ? , 0901

    .

    2 Hp Mm2 HOOClC2HC

    Hp gol +O3H HOp gol HO .

    M301 4.1 = )HOOClC2HC(aK

    32

  • O3H+ )qa(OOClC2HC )l(O2H+ )qa(HOOClC2HC+)qa(

    ECI

    0 701 0 M00200.0 Ix+ x+ x Cx+ x+ x 301 2 E

    = aK2x

    01 4.1 = )x 301 2(M3

    ?

    . ?

    ]egnahc[

    ]dica[50.0

    . 301 2

    = aK2x

    01 4.1 = )301 2(301 76.1 = x 301 2 301 4.1 = 2x M3

    301 76.150.0 > 301 2

    .

    = aK2x

    01 4.1 = )x 301 2(0 = 601 8.2 x301 4.1 + 2x M3

    M301 1.1 ,M301 5.2 = 21x

    M301 1.1 .

    69.2 = )301 1.1(gol = Hp

    3 Hp M1 )s(aN3OCH M1

    )qa(3OC2H Hp 1 M 3OC2H?

    701 4.4 = )3OC2H(aK ,

    42

  • )s(aN3OCH)qa(+aN+ )qa(3OCH O2H

    +O3H+ 3OCH O2H+ 3OC2H

    3OCH 3OC2H .

    1 1 .

    0 701 M1 M1 Ix x x Cx x + 1 x 1 E

    Q

    = QM1701

    M1aK < Q M701 =

    x)x + 1(

    01 4.4 = x 17

    701

    x)1(

    1x = 701 4.4 =

    701 M1 M1 I

    x x x C701 +x x + 1 x 1 E

    M701 4.3 = x M701 4.4 = x + 701 701 4.4635.6 = )701 4.4(gol = Hp

    Hp ECI 0 ) (

    0 701 0 M1 Ix x x Cx x x 1 E

    2x

    01 4.4 = x 1= x 7

    401 6.6 = 701 4.4

    31.3 )401 6.6(gol = Hp

    4 Hp L1 HOOC7H3C M21 501 5.1 = aK

    52

  • 1. 20.0 )s(HOaN ) (

    2. 20.0 )g(lCH ) ( I

    ECI

    HOaN)qa(HO+ +aN O2H

    HO+ )qa(HOOC7H3C)qa(O2H+ )qa(OO7H3C )qa(

    HO

    FCI

    0 lom20.0 lom5.0 = L1 M5.0 Ilom20.0+ lom20.0 lom20.0 Clom20.0 0 lom84.0 = 20.0 5.0 F

    O3H+ )qa(OOC7H3C )l(O2H+ )qa(HOOC7H3C+)qa(

    ECI

    0 701 20.0 M84.0 Ix+ x+ x Cx x + 20.0 x 84.0 E

    Q

    = QM20.0 701

    84.0aK < 701 1.4 =

    = aKx)x + 20.0(

    01 5.1 = x 84.05

    20.0

    = aKx)20.0(

    84.0M401 6.3 = x 501 5.1 =

    44.3 = )401 6.3(gol = Hp

    . Hp

    )qa(lC + )qa(+O3H O2H+ lCH 20.0

    ECI

    01 + lom20.0 0 M21 I20.0 7

    x+ x+ x Cx + 20.0 x x 5.0 E

    62

  • = aKx)x + 20.0(

    01 5.1 = x 5.0M5

    = aKx)20.0(

    5.0401 57.3 = x M501 5.1 =

    76.1 = )401 57.3 + 20.0(gol = Hp 401 57.3 + 20.0 H.H Hp

    .

    gol + aKp = Hp

    (]A[]AH[

    )tini

    gol + bKp = HOp

    (]+HB[

    ]B[

    )tini

    .

    < 1.0]A[]HA[

    01 H .

    .

    63

  • S2gA gA 2O S2H

    , ?, " Jk5.595 = H

    + )s(gA1

    2+ )g(S2H

    1

    41 2O

    2+ )s(S2gA

    1

    2)l(O2H

    , 5.3 S2gA

    .

    gA2)+(S 2

    )2(H2 + )s(

    )+(O 2

    )2()g()2(S 2)1+(H2 + )g(2)0(O+ )s(gA4 )l(

    ,

    .

    2H 4 = 1H= 2H

    5.5954

    Jk5.841 =

    4 .

    . 7

    lom5.3 = S2gAlom5.3H2H

    lom5.0Jk2401 =

    2

    6H2C 4H+ 4H2C

    Jk7.0141 = 1H O2H2 + 2OC2 2O3 + 4H2CJk4.9113 = 2H O2H6 + 2OC4 2O7 + 6H2C2

    Jk6.175 = 3H O2H2 2O+ 2H2

    1 1H = rH2

    + 2H1

    2Jk731 = 3H

    52

    )892 1 (

    + )g(2H1

    2)l(O2H )g(2O

    73

  • .

    8.582 = foHJk

    lom

    )g(2O )g(2O0 = foH

    0

    j,f0H jntcaer=j i,f0H insecudorp=i = rH

    )g(4OC

    8.47 = )g(4HC,f0HJk

    lom

    5.393 = )g(2OC,f0HJk

    lom

    8.582 = )l(O2H,f0HJk

    lom

    )l(O2H2 + )g(2OC )g(2O2 + )g(4HC

    Jk3.098 = 4HC,fH O2H,fH2 + 2OCfH = rH

    '

    J81.4 = lac1

    Jk3.098 = rH(

    lack1

    Jk81.4

    )lack8.212 =

    62 ] J[ = q .

    = Cq

    T

    [J

    oc

    ]

    83

  • T '.

    = SC

    m=

    q

    m T

    g4.27 co001 g001 co01

    ?

    944.0 = eFSJgco

    81.4 = O2HSJgco

    T = feFTO2Hf

    O2Hq = eFq0 = O2Hq+ eFq

    ) iO2HT fT(O2Hm)O2H(S = ) ieFT fT(eFm)eF(S = eFq5.61 = fT

    c0

    g4851.0 ) (

    co45.2 . gJk24.62 = rq

    cq = rq

    q = olacC T C = qr

    T=

    g4851.0 gJk24.6245.2

    56.1 =Jkco

    g312.0 co52.3

    ' .

    Jk56.1 = T C = qcoJk53.5 = co52.3

    Jk53.5 = rqg312.0

    Jk61.52 =g

    72

    93

  • ) (e. ) ( e .

    .

    ?

    1. \ 2. )

    (

    :

    O2rC + )qa(rB62H41 + )qa(7

    +)l(2rB3 + )l(O2H7 + )qa(+3rC2 )qa(

    e6 + )l(2rB3 )qa(rB6

    .

    O2rC2H41 + )qa(7

    +e6 + )qa(

    )l(O2H7 + )qa(+3rC2

    , " tP Tp

    rB rB 72O2rC +3rC

    82 0E V

    0E

    e .

    04

  • e2 + +H2 2H : o52 M1.

    :

    . .

    E = llec0E0adona0E adotak

    .0EO2rC

    27

    V033.1 =

    V560.1 = 2rB0E

    V562.0 = V)560.1 033.1( = llec0E

    0E . 0 > llec0E

    0 < llec0E .

    )s(tP|)qa(+3rC ,)qa(72O2rC||)l(2rB|)qa(rB|)s(tP

    , .

    .

    = llec0Elom V2950.0

    )lom(n)qeK(gol

    01 = qeKllec0En2950.0

    n 6

    01 = qeK562.066201 8 = 2950.0

    ?

    E = llecE0 llec

    2950.0

    nQgol

    Q ) ( .

    . .

    M1.0 = ]+3rC[M4.0 = ] 72O2rC[ M100.0 = ]rB[ 5.4 = Hp

    14

  • O2rC + )qa(rB62H41 + )qa(7

    +)l(2rB3 + )l(O2H7 + )qa(+3rC2 )qa(

    = Q2]+3rC[

    41]+H[] 72O2rC[6]rB[9701 5.2 =

    +H Hp qeE > Q . .

    2950.0 V562.0 = llecE6

    V815.0 = )9701 5.2(gol

    .

    ]+H[ 41

    2 .

    :

    )s(tP|)qa(lC|)g(2lC||)qa(4OlC|)g(2lC|)S(tP

    lC + O2H8)0(e41 + )qa(+H61 + 4)2(O)+7(lC2 2

    e2 + )g(2lC)qa(lC2

    7

    )qa(+H61 + 4)2(O)+7(lC2 + )qa(lC41 )g(2lC8 + O2H8 llec0E

    V430.0 = llec0EV853.1 = lClc0E

    E = llec0E04OlC0E lClc0E = adona0E adotak

    E = 4OlC0E0V293.1 = llec0E lClc

    . .

    = Q] 4OlC[61]+H[41]lC[

    2

    8]2lC[qeK =

    = Q2]1[61]+H[41]1[

    8]1[qeK =

    24

  • 1 1

    01 = qeK = 61]+H[41llec0E901 1.9 = 2950.0

    M413.0 = ]+H[

    +H M413.0

    92 :

    M401 0.7 M201 5.2

    V5.1 = +2uAuA0E ?

    :

    e2 + )qa(+2uA )s(uA

    :

    e2 + )qa(+2uA)s(uA

    . .

    uA+ )s(NAuATAC+2uA )qa(

    TACuA+ )s(

    NA+2)qa(

    K

    = K]ADONA[

    ]ADOTAC[

    , Q . n 2.

    E = llecE0 llec

    2950.0

    20 > Qgol

    E = llec0E00 = 5.1 5.1 = adotac0E adona

    llecE 0 Qgol

    = QM401 0.7M201 5.2

    Qgol M401 0.7 = ]+2uA[

    M201 5.2 = ]+2uA[ llecE V130.0

    34

  • lA +2lAllecE .

    . V5.1?

    2950.02x (gol

    V5.1 = ) M201 5.201 = x

    V5.12M3501 3.5 = M201 5.2 2950.0

    ) V1(

    .

    03 :

    : .

    : :

    : . .

    44

  • )4HN(+

    )OOC6H5C(

    :

    . :

    . D

    8H3C

    ) ( : .

    : ) ? (

    : B

    CiS

    : ) (

    E

    oC

    . )

    ( A

    3HCOC3HC

    : : )

    ( ) (

    ) ( F

    HOOC3HC

    : :

    54

  • ) ( ) (

    C

    13 ' .

    .

    C

    A B .

    D ) (

    E

    64