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项目七 电路的暂态过程

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项目七 电路的暂态过程. (时间: 5 次课, 10 学时). 项目七 电路的暂态过程. 在前几章中,分析和讨论的由电阻和电源构成的电路,称为 电阻电路 。 在一定条件下,自然界的任何事物都会处于一种稳定状态,但当条件发生变化后,经过一定的时间又会过渡到一种新的稳定状态,而由一种稳态到另一种稳态的转变往往不是突变的,需要经历一个被称做 过渡的过程 。 例如 ,在电路的电源被切断后,电动机的转速从匀速慢慢地减小到零。. 同样电路也有过渡过程, 电路中由于电容元件的存在,电源接通后对电容充电而使其电压渐渐地升高到电源电压,这一过程也是一个过渡过程; - PowerPoint PPT Presentation

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  • 510

  • RC RL RC

  • 7.1.1 7.1.2

  • 7.1.1 1. u-qq(t)uC(t)uC-quC-q 7.17.1

  • (1) (2)ict (3)uc(t)t uC(t)iC(t)7.1(a)

  • 1

    2

    =0

  • 7-1 4.75F 50Hzu(t)= V1

    2

    3

  • 3) iL(t)iL(t)(7.2(a))7.2(b)

    7.2

  • iL(t)

    L

    (7-8)

  • (1) uL(t)=0 (2) 3)()

  • 4)

    5)

  • 2. (1) (2) (3)

  • 3. 7.3(a)7.3(b)RCRL 7.3 RCRL

  • uC(0+)iL(0+) t=0+ t=0+ 7.1.2

  • (1) (2) uC(0-)=0uC(0+)=0 (3) iL(0-)=0iL(0+)=0 (4)

  • 7-2 7.4(a) :(1) 7.4(a)

  • (2)0+7.4(b)7.4 7-2

  • 7-3 7.5(a)t=0 17.5 7-3

  • (27.5(b)

  • RC Z RC

  • RC7.2.1 RC7.2.2 RC7.2.3 RC7.2.4

  • 7.2.1 RC RCuC(0+)

  • 7.6RC1uc(0+)=Us

    7.7 7.6 RC 7.7

  • =RCRC

  • uC(t)i(t)7.8

    7.8 (3~5)

  • 7-4 7.6C=10FR=5k210-3J(1)uC(t)iC(t)(2)8V(3)4s2VR(1)(7-5)

  • uC(0+)iC(0+)(7-22)(7-24) V A(2)uC(t)=8V t=0.018s(3)R=uC(t)=2VC=10Ft=4s R=173.9 k

  • 7.2.2 RC 7.9(a)SRCuC(0+)=0RC SuCUS

  • 7.9 RC

  • KVLRCuC(t) i(t) uC(t)i(t)7.9(b)7.9(c)

  • 7-5 7.9(a)US=12VR=5kC=1000FSt=0uCiC (1) US=12V (2)

  • 7.2.3 RC RCRC

    7.10 RC

  • 7.10(a)2 uC(0+)=uC(0-)=U2 S21U1 (7-36)

  • (7-40) (7-40)RCU1U1

    (7-41) (7-41)RC

  • 7.10(a)3 (1)U1=U2(7-40)uC(t)=U1 (2)U1>U2CU17.10(b) (3)U1
  • 7-6 7.11t 0uc(t)i(t) :(1) :=10 v =2.25v=RC=(R1//R2)C=1.125s V(2)A7.11 7-6

  • 7.2.4 (7-40)RC f(t)(7-40)uC(t)tt+ (7-42) (7-43)

  • (7-44) (RCReqCRLL/Req)3 (7-44)

  • 7-7 7.12R1=R2=R3=2kC=3103pFUS=12VSuC(0-)=0t=0SuC (1) uC(0+)=uC(0-)=07.12 7-7

  • (2) (3)

    (4)uC()uC()(7-44)

  • RL RC RLRCL RLRCRL

  • RL7.3.1 RL7.3.2 RL7.3.3 RL

  • 7.3.1 RL iL(0+)RL 7.14S1S2iL(0+)=iL(0-)= S1S2 (7-45)

  • iL (7-49)

    (7-50)

    (7-50)(7-45)R2 (7-51)

  • 7.15

    7.14 RL 7.15 RL

  • 7.15RL (3~5) RLRL

  • 7-9 7.16RLSt=0SUS=200VR0=10L=0.5HR=40iLuLuR(1)SS A (2) (3)7.16 7-9

  • 7-10 7.17Si L

    t >0 S

    7.17 7-10

  • A

  • 7.3.2 RL 7.18S iLuLKVL

    7.18 RL

  • RL

    7.19iLuLuRRL7.19 RL

  • 7-11 7.18US=10VR=10L=5HS(1)(2)t=0st=+ (1)

    (2)t=0st=+ L

  • 7.3.3 RL RLRL7.20

    7.20 RL

  • 7-12 7.20US=100VR0=R=50L=5HSt=0SiLuL (1)

    (2)

  • RC RC()()RCRC

  • RC7.4.1 RC7.4.2 RC

  • 7.4.1 RC RC7.21(a) 7.21(b)50 TwTTwT =RCTwuoR

  • 7.21

  • 1. 1t=0uC(0+)=uC(0-)=0uo (0+)=ui=U2R t< uCuoR17.21(c)0
  • 2. t=T/2uiRCuo=uC=-UR17.21(c)
  • RC(1) (2)R

  • 7.4.2 RC 7.21(a) 7.22(a)7.22bc

  • 7.22

  • 1. t=0 UuCuo7.22(c) 0
  • 2. t=T/2 U1()U7.22(c)
  • RC(1) (2)

  • Thanks!