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Lecture Cutting technology
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Wedged (cutting) deformation of worksheet
and its stress analysis with the slab method
The 9th lesson
L8
くさび刃の基本的な形状
http://en.wikipedia.org/wiki/File:Microtome-knife-profile.svg
のみ,たがねの形状,二段刃 (多段くさび刃)
片刃 (side beveled)
一段刃(くさび刃)
対称刃 (symmetric wedge)
これらの対称刃もある
くさび(wedge)
堅い木材や金属で作られたV字形または三角形の道具. 一端を厚く,
もう一端に向かってだんだん薄くなるように作られている.切れ目を作
る,あるいは,隙間に打ち込むための形状である. その用途として
物を割る(切断する)
物と物とが離れないように圧迫する
というまったく異なる目的がある.
裁断機と断裁機
一般的に裁断機という言葉は、布・皮革などの素材や印刷物を含む紙全般を裁ったり、抜き型でプレスして型抜き加工したりする機械を指す言葉として広く使われる。これに対し断裁機という言葉は紙を直線的に切り離す機械に限定される。--
決められた寸法(長さ)を合わせて紙・プラスチックなどを切断するための機械のこと。製本の加工工程の一つで多く利用されているほか、合成樹脂や、カーボンシート等の切断加工にも広く利用される。
(http://ja.wikipedia.org/wiki/断裁機)
Observation of cutting process of several work
sheets (introduction for pushing cut)
1) Paperboard … orthotropic, laminated, quasi-
plastic (non-metallic)
No necking, de-lamination, surface breaking
v.s. last bursting
2) Resin sheet … isotropic, plastic unstable-
sticky, fragile for cracking
3) Aluminum sheet … isotropic, plastic
Necking at the lower layer, wedge
indentation at the surface layer
Structure of laminated plies in case of
paperboard
Observation of surface breaking at near the
first peak load fC1
Cutt
ing d
irec
tion
(2) Previous
stage of fC1
(1) Post stage
of fC1
Sectional view of white-coated paperboard
Stroke, x
Lin
e fo
rce,
f fc1
fc2
(1)(2)
0
5
10
15
20
25
30
35
40
0 0.2 0.4 0.6 0.8 1Indentation depth d/t
Lin
e fo
rce
f
k
N/m
C,w=91m
N,w=91m C,w=51m
N,w=51m
C,w=12m
N,w=12m
n = 350 g/m2
V = 1 mm/min
C:coated,N:non
Direction: CD
fC1
fC2
[ ]
Lower crosshead
Upper crosshead
Blade
Load cell
Holder
Paperboard
Counter plate
V : Feed velocity
Cross direction
b
wDetail of blade tip
b
wDetail of blade tip
White-coated paperboard
(recycled paper)
d1/t =50%
d2/t =85%
Pushed cutting test
Need
theoretical
estimation
models
1) Paperboard … orthotropic, laminated,
quasi-plastic (non-metallic)
No necking, de-lamination, surface
breaking v.s. last bursting
2) Resin sheet … isotropic, plastic
Necking at the lower layer, wedge
indentation at the surface layer
Video demonstration
White-coated paperboard (0.42mm),
A 42 deg. center bevel blade
Resin sheet [PC] (0.5mm) mounted on underlays,
A 42 deg. center bevel blade
Elementary analysis of the second stage by the slab method
The contact surface generates the in-plane tensile force and the out-of-plane upsetting force.
The wedge friction and the counter plate friction are considered.
From the principle of Saint-Venant, the projected area with the contact surface is only considered as a free body which is used for the equilibrium of the cutting forces.
The equilibrium of applied forces are locally satisfied with the contact surface zone
if there is not any external loads else on the body.
’p’c (t-d)s
p’c
pb
pbd
tc
pbcos(/2) pbsin(/2)
pbpbcos (/2)
pbsin(/2)pb
t-d
Wedge
Counter plate
Sheet material
Line force
f
A trapezoidal slab element which is subjected to a line force
p: the pressure on the contact surface of blade
p’: the pressure on the counter plate
s : the separation stress
1- tan(/2) s = { ―――――― -' } ―――――
tan(/2) + t-d )
- f = -'
t
s = l(,,') f / (t-a)
’p’c (t-d)s
p’c
pb
pb
= (,,') f / (t-d)
Converting efficiency of wedge separation force
2(
s L
Relationship between the in-
plane tensile stress s and the
line force f
…(A)
…(B)
t-d = L(,,') f / s,
smaller as the line force f is smaller, while it is smaller as the
friction coeff. of counter plate and the burst strength s are higher.
Since the residual height of work sheet is
1- tan(/2) s = { ―――――― -' } ―――――
tan(/2) + t-d )
- f = -'
t2(…(B)
L(,,’)
Final burst condition is estimated…
f max∝ apex angle “t-d“ is small for a keen angle
A high tensile strength sheet has a small “t-d“ .
-0.5
0
0.5
1
1.5
2
0 40 80 120 160
Tip angle [°]
Fac
tor
L(
,,
')
=0.0,'=0.0
=0.45,'=0.35
=0.45,'=0.0
=0.15,'=0.0
=0.0,'=0.35
楔分力の変換効率に及ぼす角度と摩擦の影響
Effect of apex angle and friction on efficiency of
wedge separation force
L=40%
L=120%
TIP 400HV, Nc=5rpm
TIP 400HV, Nc=5rpm
Experimental response of cutting resistance
Material: a white-coated paperboard, =350 g/m2
Second peak, final burst
dC2/t = 85%~ fC2= 25 kN/m
~
t = 0.424 mm
d
= 0.45 '=0.35
ThicknessFriction coeff.
blade
c/p
=42°
From Eq.(A), we get
s = 0.642081x25
0.848x(1-0.85)
= 126.195 = 3.15sB
sB = 38MPa
In-plane tensilestrength (MD)
sY =26MPa
=4.85sY
sB≒40 MPa ,
= 0.45, '=0.35,
Half angle: /2 = 21°, Thickness of work: t = 0.424 mm,
Burst point: d / t = 0.85, f = 25 kN/m
s /sY ≒4.85
Case study, experimental result
Material: a white-coated paperboard, =350 g/m2
Burst strength (stress) is very high !
In-plane tensile strength:
Friction coeff. (wedge-sheet):
Friction coeff. (c/p – sheet):
Plastic restriction by distortion flow around the notched zone
must be considered. Why is this stress too high ?
p/2
d2
t
YYkkkk ssp
s 96.23
2571.22
2120 =
=
==
Tensile deformation with a sharp notch:
Orowan’s solution
By using the sliding
field theory which
will be explained in
the next lecture, this
restriction resistance
is estimated as 2.96sY.
sY≒26 MPa ,
= 0.45, '=0.35,
Half angle: /2 = 21°, Thickness of work: t = 0.424 mm,
Burst point: d / t = 0.85, f = 25 kN/m
s /sY ≒4.85
Case study, experimental result
Material: a white-coated paperboard, =350 g/m2
Burst strength (stress) is very high !
In-plane tensile strength:
Friction coeff. (wedge-sheet):
Friction coeff. (c/p – sheet):
Plastic restriction by distortion flow around the notched zone
must be considered.
By replacing sY to 2.96 sY, the ratio of burst stress and
the yield strength becomes s / (2.96sY) = 1.64
sB=38MPa
Since sB/sY=1.461, s/(2.96sB) = 1.12 Final burst is estimated from the tensile strength
From a slip-line theory model…
The paperboard has…
Important and useful results
• Final burst stress s at the second peak point
( fC2 , dC2) is estimated from the tensile
strength sB : s = 3sB
• Experimental paperboard cutting says that
dC2/t = 85%, dC1/t=50~60%, while the Slip-line
theory (frictionless) shows that dC1/t =64%,
dC2/t =90%.
~
These information were derived from the slab method, and the experimental observation.
Today’s home work,1
1- tan(/2) s = { ―――――― -' } ―――――
tan(/2) + t-d )
- f = -'
t2(
When we consider the specified trapezoidal free body,
verify that this equation is correct. Consider the
equilibrium of all the forces in the horizontal direction.
…(B)
Today’s home work,2
’p’c’(t-d)s
p’c’
pb
pb
c’
c
When we consider a new free
body as shown here, derive the
relationship between the
separation stress s and the line
force f.
Brief answer
The result is the same as the
case of the trapezoidal free
body.
Assumed to
be a free
surfacenc > c’ > c, n>1