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L 1
A. PRORAČUN REZERVOARA ZA KOMPRIMIRANI VAZDUH
Pritisak vazduha….…..p=15⋅ 105 Pa = 1,5 N/mm2 Usvojeni materijal…..Č 0371Prečnik rezervoara…...D=780 mm Granica tečenja….…..Re=235 N/mm2
Dužina rezervoara……L=3800 mm Faktor slabljenja…….ϕ =0,7Radijus danceta……....R=0,8⋅ D=625mm Stepen sigurnosti……S=1,5 Širina otvora cjevi……d1=0,15⋅ D=117 mm
Proračun debljine limova:
σdoz= ==5,1
/235 2mmN
S
Re 157 N/mm2
Debljina lima : δ= =+⋅⋅
⋅=+⋅
⋅1
/1577,02
/5,17801
2 2
2
mmN
mmNmmkorozijuzamm
pD
dozϕσ 6,3 mm
Debljina danceta : δd= =⋅⋅
⋅=+⋅⋅⋅
2
2
/1577,02
/5,16251
2 mmN
mmNmmpR
dozσϕ 5,3 mm
Debljina cjevi : δ c= =+⋅⋅⋅=+
⋅⋅⋅
1/1577,02
/5,11171
2 2
21
mmN
mmNmmpd
dozσϕ 1,8 ≈ 2 mm
Spoljašnji prečnik cjevi : d2=d1+2δc=117mm+2⋅ 2mm=121 mm
Proračun zavarenih sastavaka :Detalj A: τ s=Fs/As < τ s doz ; Fs=p⋅ d2
2⋅π /4 ; As=d2⋅π ⋅ a ; a(debljina vara)=0,7⋅δ d
τ s= ≈⋅⋅
⋅=⋅⋅
⋅=
⋅⋅⋅⋅⋅
mm
mmmmNdp
ad
dp
d 3,57,04
121/5,1
7,044
22
2
22
δππ
12,23 N/mm2
Detalj B: σz=Fz/Az < σz doz ; Fz=[D+2(δ-δd)]2⋅π ⋅ p/4 ; Az=[D+2(δ-δd)]⋅πδ d
σz= ≈⋅
⋅−+=⋅
++=
−+−+
mm
mmNmmmmpD
D
pD
d
d
dd
d
3,54
/5,1])3,53,6(2780[
4
)](2[
)](2[4
)](2[ 22
δδδ
πδδδπδδ
55,3N/mm2
Detalj C: σz=Fz/Az < σz doz ; Fz=p⋅ D2⋅π /4 ; Az=D⋅π ⋅δ
σz = =⋅
⋅=⋅⋅=
⋅⋅⋅⋅⋅
mm
mmmmNDp
D
Dp
3,64
780/5,1
44
22
δδππ
46,42 N/mm2
B.1 ZAVARENI SPOJ RUČICE I VRATILA (sl.2_)
Prečnik vratila………….….d=110 mmSila ručice……………….…F=± 9900 NKrak ručice………………....R=145 mmRačunska debljina vara.…….a=5 mmZavarivanje………………….NMaterijal…………………….Č 0545Dozvoljeni τ napon………….τD(-1)=140 N/mm2
L 2
Radni napon uvijanja : τ t=Mt/W0 ; Mt= F⋅ R , W0=)2(16
])2[( 44
ad
dad
+⋅−+ π
τ t= =⋅−⋅+
⋅+⋅⋅⋅=⋅−+
+⋅⋅14,3])110()52110[(
)52110(161459900
])2[(
)2(164444 mmmmmm
mmmmmmN
dad
adRF
π 14,4 N/mm
Radni napon smicanja : τ s=Fs/As ; As= π⋅−+4
)2( 22 dad
τ s= =⋅−⋅+
⋅=⋅−+ 14,3])110()52110[(
99004
])2[(
42222 mmmmmm
N
dad
Fsπ 5,48 N/mm2
Ukupna amplituda napona (oba napona tangencijalna) : τa= ± (τs+τt)= ± (14,4+5,48)= ± 19,88 N/mm2
ξ1=0,9 τ naponi i ugaoni sastavakξ2=0,5 Normalno zavarivanjeξ3=0,8 Ugaoni sastavak bez zavarenog korena
Dinamički stepen sigurnosti : Sd= =⋅⋅⋅⋅=⋅⋅⋅
2
2321
/88,19
/1408,05,05,09,0
mmN
mmN
a
d
ττξξξ
1,268
B.2 ROTOR SA ZAVARENIM RUKAVCEM (sl.4_)
Sila savijanja………………..F=1580 N Materijal……………………..Č. 0545 Računska debljina vara……...a=7 mmPrerčnik osovine…………….d=115 mmKrak sile……………………..L=1,5⋅ d=172,5 mmMoment uvijanja…………….Mu=0,28 kNm=0,28⋅ 106NmmMoment savijanja…………….Mf=F⋅ L=272550 NmmSpoljašni prečnik zavara….…dz=d+2a=129 mm
Površina preseka zavara…….A= ≈⋅+ πz
z
d
dd 22
2680 mm2
Polarni otporni moment ……..W0= =⋅−
16
44 πz
z
d
dd174103,2 mm3
Otporni moment za osu………Wx= =⋅−
32
44 πz
z
d
dd87051,6 mm3
Napon savijanja na zavaru……σ= ==3
0 6,87051
272550
mm
Nmm
W
M f3,131 N/mm2
Napon uvijanja u zavaru………τ t= =⋅=3
6
0 2,174103
1028,0
mm
Nmm
W
M u1,61 N/mm2
Napon smicanja zavara………..τ s= ==22680
1580
mm
N
A
F
s
s0,59 N/mm2
Sabiranje tangencijalnih napona……….τmin=τt=1,61 N/mm2
τmax=τt+τs=1,61N/mm2+0,59N/mm2=2,2 N/mm2
τ sr=(τmin+τmax)/2=1,905 N/mm2
Trajna dinamička izdržljivost…………..τd=140 N/mm2 Koeficijenti otpornosti za τ napone….. . ξ1=0,4 , ξ2=1 , ξ3=0,5 , ξ4=0,75
Din.stepen sigurnosti za τ napone..Sτ= =⋅⋅⋅⋅=⋅⋅⋅⋅
2,2
/14075,05,014,0 24321 mmN
a
d
ττξξξξ
9,5
L 3
Koeficijenti otpornosti za savijanje……ξ1=0,2 , ξ2=1 , ξ3=0,5 , ξ4=0,75
Din. stepen sigurnosti za savijanje…….Sf= =⋅⋅⋅⋅=⋅⋅⋅⋅
2
24321
/131,3
/24075,05,012,0
mmN
mmN
a
d
σσξξξξ
5,7
Ukupni stepen sigurnosti………….Sd= 22τσ
τσ
SS
SS
+
⋅=4,89
B.3 DINAMIČKI STEPEN SIGURNOSTI ZAVARENOG SPOJA (sl.3)
-Napomena : Radi zadovoljavanja stepena sigurnosti dimenzije R i l su dva puta umanjene u odnosu na zadate .F=5200 N R=105 mm l=50 mmd=48 mm D=64 mm a=3 mm
Otporni moment za osu……………..…Wx= =⋅−−32
)2( 44 πD
aDD5603,14 mm3
Površina poprčnog preseka vara………..As= =⋅−−4
])2([ 22 πaDD1407 mm2
Polarni otporni moment…………………W0= =⋅−−16
)2( 44 πD
aDD11206,28 mm3
Moment savijanja u zavaru……………....Mf=F⋅ l=5200 N⋅ 50 mm=260 000 NmmMoment torzije u zavaru……………..…..Mt=F⋅ R=5200 N⋅ 105 mm=546 000 Nmm
Dozvoleni dinamički napon savijanja za jednosmerna opterećenja …………..…..σd(0)=180 N/mm2
Dozvoljeni dinamički napon uvijanja za jednosmerna opterećenja…………..……τd(0)=120 N/mm2
Napon savijanja………….σf = ==314,5603
260000
mm
Nmm
W
M
x
f46,6 N/mm2
Napon uvijanja………….τ t= ==328,11206
546000
mm
Nmm
W
M
x
t48,7 N/mm2
Naponi smicanja………..τ s= ==21407
5200
mm
N
A
F
s3,7 N/mm2
Normalni naponi………..σf=46,4 N/mm2
σfa=46,4 N/mm2
Tangencijalni naponi……τ= τt+τs= 48,7 N/mm2 +3,7 N/mm2 =52,4 N/mm2
Koeficijenti otpornosti za normalne napone…..ξ1=0,9 , ξ2=1 , ξ3=0,7 , ξ4=0,9
Stepen sigurnosti za σ napone…..Sσ= =⋅⋅⋅⋅=⋅⋅⋅⋅
4,46
/1809,07,019,0 24321 mmN
f
d
τσσξξξξ
2,2 N/mm2
Koeficijenti otpornosti za tangecijalne napone…..ξ1=0,9 , ξ2=1 , ξ3=0,7 , ξ4=0,9
Stepen sigurnosti za τ napone…..Sτ= =⋅⋅⋅⋅=⋅⋅⋅⋅
4,52
/1209,07,019,0 24321 mmN
a
d
ττξξξξ
1,3 N/mm2
Ukupni stepen sigurnosti………….Sd= 22τσ
τσ
SS
SS
+
⋅=1,12
L4
B.4 STEPEN SIGURNOSTI ZAVARENOG I NE ZAVARENOG DJELA (sl.5a. i sl.5b.) Proračun ne zavarenog djela:
B=70 mm b=40 mm a=3 mm δ=8 mmF=8040 N ρ=6 mm Ms max=0,056 kNmm
Otporni moment za osu⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ Wx= =⋅=⋅6
408
6
22bδ2133 mm2
Kritični pop.presjek⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ A=b⋅δ =40⋅ 8=320 mm2
⇒
=
=
=
1
085,0
57,0
ρ
ρ
tB
B
b
za zatezanje αk=1,75 ,za savijanje αk=1,5
Nominalni naponi zatezanja⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ σnz=F/A=8040N/320mm2=25,125 N/mm2
Stvarni naponi zatezanja⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ σz=αk⋅σ nz=1,75⋅ 25,125 N/mm2=44 N/mm2
Nominalni naponi savijanja⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ σnf= Mf max/Wx =0,056 kNmm /2133 mm2=0,03 NStvarni naponi sanijanja⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ σf=αk⋅σ nf=1,5⋅ 0,03 N/mm2=0,045 N/mm2
Maksimalni napon⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ σmax=σf max+σz=0,045+44 N/mm2 =44,045 N/mm2
Minimalni napon⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ σmin= σz =44 N/mm2
Srednji napon⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ σsr= =+2
minmax σσ44,0225 N/mm2
Dinamički stepen sigurnosti :ηk=0,7 ; βk=(αk -1)⋅η k+1=(1,75-1)⋅ 0,7+1=1,525 ; σd=250 N/mm2
ξ1=0,8 ; ξ2=0,9 ; ξ3=1,2
Sd= =⋅
⋅⋅⋅=⋅
⋅⋅⋅045,44525,1
2502,19,08,0
max
321
σησξξξ d
3,22
Proračun stepena sigurnosti za slučaj zavarenog spoja :ξ1=1 ; ξ2=0,5 ; ξ3=1 ; ξ4=0,8
Sd= =⋅⋅⋅⋅045,44
2508,015,012,27
B.5. NOSIVOST SKLOPA GLAVČINA-ZUPČANIK ZA SLUČAJ ZAVARENOG I PRESOVANOG SPOJA (sl.6)
Dimenzije:D=290 mm Materijal Č.0545 Presovani sklopD1=70 mm Stepen sigurnosti S=3 φ 70 H8/za9d=60 mm Normalno zavarivanje he=hi=5 µmb=20 mm Jednosmerno opterećenjea=10 mm
Polarni otporni moment vara⋅ ⋅ ⋅ ⋅ ⋅ ⋅ W0=( )
=⋅+
−+162
2
1
41
41 π
aD
DaD90711 mm3
τd=170 M/mm2 (jednosm. opterećenje) ; ξ1=0,7 ; ξ2=0,5 ; ξ3=0,6 ; ξ4=0,8τ t max=ξ1⋅ξ 2⋅ξ 3⋅ξ ⋅τ d/S =0,7⋅ 0,5⋅ 0,6⋅ 0,8⋅ 170 / 3 =9,52 N/mm2 Mt max=W0⋅τ t max =9,52 N/mm2 ⋅ 90711 mm3 =863568,72 Nmm Fobod.=2⋅ Mt max /D=2⋅ 863568,72 Nmm/290 mm =5956 N (za slučaj zavarenog sklopa)
L 5
φ 70 H8 : φ 70 za9 :Tr=Ag=0,046 mm T0=0,074 mm Ad=0 ad=0,274 mm Dg=D1+Ag=70+0,046=70,046 mm ag=ad+T0=0,274+0,074 = 0,348 mm Dd=D1+Ad=70 +0 =70 mm dg=D1+ag=70 + 0,348 = 70,348 mm dd=D1+ad =70 + 0,274= 70,274 mm
Zg=Dg – dd=70,046 – 70,274 = -0,228 mm = Pg
Zd=Dd - dg =70 – 70,348 = -0,348 mm = Pd
Pd’ =Pd – 1,2(he+hi)=0,348 – 1,2⋅ (0,005+0,005) =0,336 mmPg’ =Pd – 1,2(he+hi)=0,228 – 1,2⋅ (0,005+0,005) =0,216 mmFaktori deformacije :ψ s=D1/D= 70/290 = 0,241 -za rupu ms= mu= 0,3 ; Es=Eu=2,06⋅ 10-5 mm2/Nψu= d/D =60/70 = 0,857 - za osovinu (za Č.0545)
ξs=( ) ( )
( )( ) =
−⋅⋅⋅⋅−++=
−⋅⋅−++
)241,01(1006,23,0
241,0)13,0(13,0
1
1125
2
2
2
ψψ
ss
sss
Em
mm2,16⋅ 10-5 mm2/N
ξu=( ) ( )
( )( ) =
−⋅⋅⋅⋅++−=
−⋅⋅++−
)857,01(1006,23,0
857,0)13,0(13,0
1
1125
2
2
2
ψψ
uu
uuu
Em
mm1,55⋅ 10-5 mm2/N
Najmanji dodirni pritisak :
Pmin= ( ) ( ) =⋅⋅⋅+
=⋅⋅+
−−−−− NmmD
hhP
su
iea
/10701055,116,2
336,0
10
)(2,1'2555
1ξξ 1,2938⋅ 107 N/mm2
Koeficijent trenja za Č.0545⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ µ=0,1Dodirna površina⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ A=D1⋅π ⋅ b = 70⋅ 3,14⋅ 20= 4396 mm2
Sila trenja :Fµ=Pmin⋅ A⋅µ =1,2938 N/mm2 ⋅ 4396 mm2 ⋅ 0,1 = 5,688⋅ 10 9 N
Obodna sila : Fobod. = Fµ ⋅ D1/D = 5,688⋅ 10 9 N ⋅ 70 mm/290 mm = 1,373 ⋅ 109 N (za slučaj presovanog spoja)