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abbreviation According again all all all all Alltogether, also always and and and

and andapplied are arguments as at at atbe belongondition considerDiedericha enough E. ex- expressionOollowing following, For for for for for for for for Fornaess functionsget get getgives gives:Save have holdtf In in in in inequality instead is It it1.K.Leviform Leviformmust

(, ) C2= (2).h C2(r), (, ) C2, (,) C2. L(p; (, )) 2

ww =

1; =exp(i ln |z|2)= 0, p= (z, 0) Mr.

2

z k = 2

|z|2;

|pz r. r : r.) 0 < < 1(, )0 < < 1.1 |z| r1 |z| r1 |z| r

z C, R

z= 0; (, )(, ) C2

p= (z, exp(i ln |z|2))].

w = (1 )exp(i ln |z|2);

2

zw =

i

Zexp(i ln |z|2);

[) = (z, w) = (z, exp(i ln |z|2))

+ h+(1 )(1 )2

2 h)||2}.(z, w) =h(|z|2, w)(r(z, w))

1/

+(2 )(2(2 ) 2h

ww+ 2 (1 )Re(

h

w)

+2(2 )Re[((2 ) 2h

zw+(1 )

h

z +

i

Zh)

g{p; (, )) =2(2 )2(2(2 )((2 )

h

zz+ 2h

1

|z|2)||2

+(2(2 ) 2h

ww+ 2 (1 )Re(

h

w) + h+(1 )

(1 )2

2 h)||2 0

(2

2h

zz+2

|z|2h)||2+2Re

([ (h

z +

i

Zh)] +

1

2(1 )h||2 0

((2)

2h

z5z+2

|z|2h)||2+2Re

([((2 ) 2h

ww+(1 )

h

z +

i

Zh)

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