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DATE : CUSTOMER : PT. BUKAKA TEKNIK UTAMA DOC. NO : ENGINEERING DEPARTMENT REV : 1.) Design the lightest LC-shape Purlin, use AISC-ASD and A36 Steel Mpa degrees m m For the Normal Axis: Wn = ( W L + Wg cos θ ) ( s ) 40 Wn = ( 0.980665 + 0.36774937 (1.375) Wn = KN/m For the Tangential Axis: W T = Wg sin θ ( s ) W T = 0.367749375 sin 14 (1.375) W T = KN/m 0.125 (w) (L) 2 0.125 ( 1.839 ) ( 2.75 2 KN-m With Sag Rod: considering the tangential axis: W T L/2 from table 9.-28 under misc Tables of the ASEP steel handbook <for continuous beams> 0.07 (w) (L/2) 2 0.07 ( 0.122 ) ( 1.375 2 KN-m 0.125 (w) (L/2) 2 0.125 ( 0.122 ) ( 1.37 2 KN-m [ Use this value ] Assume fx and fy to be 0.66 of Fy for compact members mm 3 mm 3 KN/m 2 My + = My + = L = s 1 = 1.375 1.839 0.122 2.75 F y = 400 Wg = 0.368 My + = θ = 14 W L = 0.981 0.0288 264 264 1.73843 KN/m 2 KN/m 2 6,584.96 109.09 L/2 0.0161 Mx = 0.0288 My - = My - = Mx = Mx = 1.7384 S x = Mx fx = My - = fy = = S y = My = DESIGN CALCULATION OF PURLINS SHELTER FOR SUPPORT PIPE 07 Februari 2011 Chevron Indonesia Co. 013/DC-BB/E/12/2010 0 Design of Purlins

4. Design Of Purlins

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Page 1: 4. Design Of Purlins

DATE :CUSTOMER :

PT. BUKAKA TEKNIK UTAMA DOC. NO :ENGINEERING DEPARTMENT REV :

1.) Design the lightest LC-shape Purlin, use AISC-ASD and A36 SteelMpadegreesmm

For the Normal Axis:Wn = ( WL + Wg cos θ ) ( s ) 40Wn = ( 0.980665 + 0.36774937(1.375)Wn = KN/m

For the Tangential Axis:WT = Wg sin θ ( s )WT = 0.367749375 sin 14 (1.375)WT = KN/m

0.125 (w) (L) 2

0.125 ( 1.839 ) ( 2.752

KN-m

With Sag Rod:considering the tangential axis:

WT

L/2

from table 9.-28 under misc Tables of the ASEP steel handbook <for continuous beams>

0.07 (w) (L/2) 2

0.07 ( 0.122 ) ( 1.3752

KN-m

0.125 (w) (L/2) 2

0.125 ( 0.122 ) ( 1.372

KN-m [ Use this value ]

Assume fx and fy to be 0.66 of Fy for compact membersmm3

mm3

KN/m2

My+ =My+ =

L =s1 = 1.375

1.839

0.122

2.75

Fy = 400 Wg = 0.368

My+ =

θ = 14 WL = 0.981

0.0288264

264

1.73843

KN/m2

KN/m2

6,584.96

109.09

L/2

0.0161

Mx =

0.0288

My- =My- =

Mx =

Mx = 1.7384

Sx = Mxfx

=

My- =

fy

=

=Sy = My =

DESIGN CALCULATION OF PURLINS SHELTER FOR SUPPORT PIPE

07 Februari 2011Chevron Indonesia Co.013/DC-BB/E/12/2010

0

Design of Purlins

Page 2: 4. Design Of Purlins

Try SectionRelative properties

x 103 mm3 L = 2.8 mx 103 mm3 Ix = x 103 mm4

Kg/m

Total Wn = Wn + W (0.00981)(cos θ)Total Wn = 1.839 + 6.13 ( 0.00981 ) ( cos 14 )Total Wn = KN/m

Total WT = WT + W (0.00981)(sin θ)Total WT = 0.122 + 6.13 ( 0.00981 ) ( sin 14 )Total WT = KN/m

0.125 (w) (L) 2

0.125 ( 1.897 ) ( 2.752

KN-m0.125 (w) (L/2) 2

0.125 ( 0.137 ) ( 1.372

KN-m

Mpa

Mpa

Checking the interaction:

SAFE

Check Resultant Deflection∂ = √ ∂N ² + ∂T ² L/300 = mm

5 4

ת4

∂ = √ ∂N ² + ∂T ²= √ + `=

or < mm

using 10 mm dia. Sag rod

USE

181

= 8.8431E-102750

mm

9.1667

0.000021

100 x 50 x 20 x 3,2

mm 9.1667 OK!!!Therefore:

7.81997E-19 4.2485E-162.06308E-08

1.375 = 2.0612E-0810 ² 200000

= 0.23546875

∂T = Rs S =As Es

384 EIx 384

0.23546875

181000∂N = 5 Wn L4

= 1.897200000

8Rs = 5 Wt L

=

Sy = 0.00

Mx =Mx =

W = 6.13

1.897

0.137

0.04fx + fy0.66 ( Fy )

4.374 + 5.2850.66 ( 400 )

= =

4.374

5.285

1.793

My- =My- = 0.0324

=6.13Sy

Sx =

=0.0324410.00

1.793

fx = Mx

My- =

fy = My

Mx =

410.00Sx =

100 x 50 x 20 x 3,2Design of Purlins