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7/25/2019 Bai Giang Qttc Tc Ltcd Nct
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QUN TR TI CHNHThcs: NguynHuTh
Ging vin Khoa Qun tr Kinh doanhi hc Kinh t Tp.HCM
Email : [email protected]
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Thngtin lphc
Stithc: 45 tithoc02 tnch
itng: Sinh vin
Thigian hc: 10bui
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Mctiumnhc
Nmrcckhinimvtichnh;
PhntchvnhgitnhhnhhotngtichnhcaDoanh
nghip; Hiuccnguyntc, cngc,phngphpra quytnh
ut, huy ngvn;
Cung cpkinthccbncho ccmnhcQuntrdn,
Thtrngchngkhon, v.v
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Phngphpgingbi
Tholunvtrao ihcvin
Biging;
Tnhhung;
Bitp;
Trlithcmchcvin;
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nhgimnhc
imqutrnh30% trong :
Tham dlp: 15%
Bitpkimtra: 15%
imkimtra cuik: 70%
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Nidung:
Chng1: Tngquan vQuntrtichnh
Chng2: PhntchbocoTichnh
Chng3: Quntrvnlung
Chng4: Tintcgitrtheo thigian
Chng5: nhgichngkhon
Chng6: Riro vlinhun
Chng7: Chiphsdngvn
Chng8: nhgihiuquut
Chng9: Khochngnlu
Chng10: CcuvnDoanh nghip
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Tiliutham kho
Brealey, Myers and Marcus, Fundamentals of corporate finance.
International Edition, Mc.Graw Hill Inc. 1995.
Eugene F. Brigham, Fundamental of Financial management.
University of Florida, Sixth Edition.
NguynMinh Kiu, Tichnhdoanh nghip, NXB Thngk, nm
2013,
Nguyn Quang Thu, Qun tr ti chnh cnbn, NXB Kinh t
Tp.HCM, nm2013, in lnth6.
NguynVnThun, Quntrtichnh, NXB Thng K, nm2012
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CHNG 1:
TNG QUAN V TI CHNH
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Nidung
Cckhinim
Tmquan trngcaQuntrtichnh
CcloihnhDoanh nghip
MctiuDoanh nghip
Ccquytnhtichnhtrong doanh nghip
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Khinim
Tichnhlg?
Quntrtichnhlg?
Quntrtichnhtrong doanh nghiplg?
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Tmquan trngcaQuntrtichnh
Lnkhochtichnh
Dondoanh thuchiphnhhngnlinhun
Quytnhut
Huy ngvnvay ngnhn, dihn.
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CcloihnhDoanh nghip
Doanh nghiptnhn
Cngty hpdanh
Cngty Cphn
Cngty TNHH 1TV2 TV trln
Doanh nghipnhnc
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CcloihnhDoanh nghip
So snhcclaihnhdoanh nghip:
Thtcthnhlpdoanh nghip
Vnkinh doanh
QuntrCngty
Hnhthcthu
Phnphilinhun
Tngvn
Thihnkinh doanh
v.v..
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MctiuDoanh nghip
Tora gitr
Tiahalinhunsau thu
Tiahalinhuntrncphn
Tiahathgicphiu
Smuthungiachshuvngiiuhnh
Trchnhimxhi
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MctiucaccchthiviDoanh nghip
15
itng Mc tiu Ch s nh gi
Nhqunl Li nhun, phc li doanh nghip, pht
trinbnvng
ROA, ROE, ROI, linhunrng.
Chshu Tiaut, phttrinbnvng Li nhun, gi tr gia tng kinh t
(EVA), gi tr gia tng th trng
(MVA).
Cng C tc Tng linhuncphiu, Ctc, P/E,
gitrthtrngcphiu.
i tc thng mi Quan hthngminnh S n nh.
Thchtndng Hontrcckhonvay nghn Dng tin.
Ngilao ng Nilmvican ton,lng,chingh
nghip
S n nh.
Nhnc Thu -
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Ccquytnhtichnhchyucadoanh nghip
16
ut
PhnphiTN
Khc
Ti tr
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Quytnhut
17
Quytnhlinquan nphntisntrongbngcnitisnca
doanh nghip
Quytnhuttisnlung: tnqu, tnkho, chnhsch
bnchu.
Quytnhuttisncnh: mua sm, thay th, utd
n.
Quytnhccutisnlungtisncnh: sdngnbyhotng, imhavn
Lquytnhquan trngnhtvtora gitrcho doanh nghip
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Quytnhtitr
18
Quytnhlinquan nphnngunvntrongbngcnitisn
cadoanh nghip
Quytnhhuy ngvnngnhn: vay ngnhntndng
thngmi?; vay ngnhnngnhngphthnhtnphiu?
Quytnhhuy ngvndihn: ndihn vncphn?; vay
dihnngnhngtriphiucngty?; vncphnphthng
vncphnuindihn? Quytnhccun- vnchshu(nbytichnh)
Quytnhvay mua hay thutisn
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Quytnhphnphilinhun
19
Quytnhnylinquan nchnhschctccacngty
Lachngililinhuntiutchia ctc
Cngty nntheo uichnhschctcno?
Chnhschctctcngnhthnongicphiuca
cngty trnthtrngtichnh?
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Ccquytnhkhc
20
Spnhp, thutmcngty
Phngngariro tichnh
Chnhschtinlng
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Phnbitchcnngtichnhchcnngktontrongquntrtichnhktoncngty
21
Tichnh Kton
Hochnhutvn
Quntrtinmt
Quan hgiao dchviNHQuntrkhonphithu
Phnchia ctc
Phntchvhochnhtichnh
Quan hvinhut
Quntrquhubng
Quntrbohimvriro
Phntchvhochnhthu
Ktonchiph
Quntrchiph
XldliuSkton
Bococho cquan nhnc
Kimsotnib
Lpbocotichnh
Lpkhochvccdbotichnh
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Hivtrli
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CHNG 2:
PHN TCH BO CO TI CHNH
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Nmrccbocotichnhtrong Doanh nghip:
Bocoktqukinh doanh
Bngcnikton
Bocoluchuyntint
Thuytminhbocotichnh
Phntchbocotichnh
Phntchcctstichnh
PhntchtichnhDuPont
Lukhiphntchbocotichnh
Nidung:
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Bocotichnhphnnhtnhhnhtichnhcadoanh
nghipbngcchtnghpvthuytminh vtnhhnh
kinh t, tichnhcanvkton.
Bocotichnhgm4boco:
Khinim
bng
cn ik ton
Bo co
kt qukinh doanh
bng
lun chuyntin t
Thuyt minhBCTC
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Trung thc:
ngbiumu:
Chnhxcvthngnhtsliu:
nghnnh
Yucucabocotichnh
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Phn nh tng qut tnh hnh thu nhp, chi ph v li nhun
ca doanh nghip trong mt k k ton, chi tit theo hot
ngkinh doanh chnhvcchotngkhc;
Bocoktqukinh doanhcthnhgi:
Ktquhotngkinh doanh cadoanh nghipthngqua ch
tiuli(l)
Hot ng no gi vai tr quan trng trong vic to ra li
nhuncadoanh nghip.
Nnglctora nguntinvcckhontngngtinca
doanh nghiptrong tnglai.
Bocoktqukinh doanh
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Bocoktqukinh doanh
1. Doanh thu
2. Cckhongimtr
3. Doanh thu thun
4. Givnhngbn
5. Ligp
6. Doanh thu hotngtichnh
7. ChiphtichnhTrong : Chiphlivay
8. Chiphbnhng
9. Chiphqunl
10.Linhunthotngkinh
doanh
11. Thu nhpkhc
12. Chiphkhc
13. Linhunkhc
14. Linhunktontrcthu
15. Thuthu nhpdoanh nghip
16. Linhunsau thu
17. Ctcui
18. Linhundnhcho cng
thng
19. Ctcthng
20. Linhunli
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Bngcniktonlbngbocotnhhnhtisnvngun
vncaDoanh nghipmtthiim
Bngcniktonphnnh:
Gitrtisnhinctheo ccucatisn;
CcungunvnhnhthnhcctisncaDN timtthi
imnhtnh.Cthnhnxtnhgikhiqut:
Tnhhnhtichnh
Tnhhnhphnbtisn
Tnhhnhphnbngunvn
Tnh hnh qun l v s dng vn ca
doanh nghiptithiimthnhlp
Bngcniktan
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Bngcnikton
A. Tisnngnhn
Tin Cckhonphithu
Tnkho
utngnhn
TSNH khc
B. Tisndihn
TSC huhnh
TSC vhnh
Btngsnut
utdihn
TngTisn
A.Nphitr
+Nngnhn Cckhonphitr
Ntchly
Vay ngnhn
Nngnhnkhc
+Ndihn
B. Vnchshu
Vniul
Thngdvn
Linhunli
Tngngunvn
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Ngunvn:
Tngngunvn=Nphitr+ vnchshu
Nphitr=Nngnhn+Ndihn
Vnchshu= Vniu l+ Thngdvn+ Linhun
chaphnphisau khi chia ctc Tisn
Tngtisn= Tisnngnhn+ Tisndihn
Tisnngnhn= TSL+utngnhnTisndihn= TSC(thun) + utdihn
Mtsngthctrong bngcnikton
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Trnghp1: TngtisnnyGimtisnkhc
Nghipvktonphtsinh chnhhngnphntisnca
bngcnikton
Loi ti snny tng ln th loi ti snkhcgim i tng
ng
Tng cng ti sn khng thay inhng t trng cc khon
mctisnbnhhngbinghipvktonphtsinh th
thay i
Nguyntccbn
N b
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Trnghp2: TngngunvnnyGimngunvnkhc
Nghipvktonphtsinh chnhhngnphnngunvn
cabngcnikton
Loingunvnnytnglnthloingunvnkhcgimi
tngng
Tng cng ngun vn khng thay i nhng t trng cc
khon mc ngun vnb nh hngbi nghip v k ton
phtsinh ththay i
Nguyntccbn
N b
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Trnghp3: TngtisnnyTngngunvntngng
Nghip v k tonpht sinh nh hng c hai phn ti sn v
ngunvncabngcnikton
Nu lm ti sn tng ln th cng lm ngun vn tng ln
tngng
Tng cng ti sn v tng cng ngun vn u tng ln, t
trngcattccckhonmctisnvngunvnuthay
i
Nguyntccbn
N t b
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Trnghp4: GimtisnnyGimngunvntngng
Nghip v k tonpht sinh nh hng c hai phn ti sn v
ngunvncabngcnikton
Nu lm ti sn gim th cng lm ngun vn gim xung
tngng
Tngcngtisnvtngcngngunvnugimxung, t
trngcattccckhonmctisnvngunvnuthayi.
Nguyntccbn
B l h ti t
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Phnnhvichnhthnh( dngtin thu vo) vsdng(dng
tin chi ra) lng tinpht sinh trong kbo co ca doanh
nghip
Cthnhgic
Khnngtora tin
Sbinngtisnthuncadoanh nghip
Khnngthanh toncadoanh nghip
Donclungtintrong ktiptheo
Bocoluchuyntint
Ni d kt B l h ti t
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Gm3 phnnhsau:
Luchuyntinthotngkinh doanh
Luchuyntinthotngut
Luchuyntinthotngtichnh
Nidung vktcuBocoluchuyntint
L h ti t h t ki h d h
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Phnnhtonbdngtinthu vovchi ra linquan trc
tipnhotngkinh doanh cadoanh nghip.
Chai phngphpxcnh luchuyn tin thotng
kinh doanh:
Phngphpgintip
Phngphptrctip
Luchuyntinthotngkinh doanh
B l h ti t Ph h t ti
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Thu: Tin thu bn hng; tin thu t cc khonphi thu
thngmi
Chi: Tin trcho ngicung cp(trngay trong kvtin
trcho khonntktrc),tinthanh toncho cngnhnvin v tin lng v BHXH, v.v) v cc chi ph khc
bngtin(chiphvnphngphm,cngtcph,v.v)
Lu chuyn tin thun t hot ng kinh doanh = Thu - Chi
Bngluchuyntint- Phngphptrctip
B l h ti t Ph h i ti
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Cs: Phngtrnhkton
Tngtisn= Tngngunvn
Tngtisn=Nphitr+ Vnchshu
Tisnngnhn+ Tisndihn=Nphitr+ Vnchshu
Tinvcckhontngngtin=NPT + VCSHTS dihnKPTHTKTS ngnhnkhc
Mtthay itrongNphitrhay VnchshuslmTinvcckhontngngtinthay icngchiu
Mt thay i trong khon Ti sn s lm Tin v cc khontngngtinthay ingcchiu
BnglunchuyntintPhngphpgintip
L ch n tin t hot ng t
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Phnnhtonbdngtinthu vovchi ra linquan trc
tipnhotngutcadoanh nghip
Hotngutbao gm2phn:
utcsvtchtkthutchobnthndoanh nghip:
nhhotngxydngcbn, mua smtisncnh.
u tvoccnvkhcdihnhthcgpvn lindoanh, utchngkhon, cho vay, khngphnbitu
tngnhnhay dihn.
Luchuyntinthotngut
Lu chuyn tin t hot ng u t
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Thu: Cckhonthu dobn,thanh ltisncnh,thu hi
cckhonutvoccnvkhc,..
Chi: Cckhonchi mua sm,xydng tisncnh,chiutvoccnvkhc,
Lu chuyn tin thun t hot ng u t = Thu - Chi
Luchuyntinthotngut
Lu chuyn tin thun t hot ng ti chnh
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Phnnhtonbdngtinthu vovchi ra linquan trc
tipnhotngtichnhcadoanh nghip
Hotngtichnhbao gmccnghipvlmtng,gimvn kinh doanh ca doanh nghip nh: ch doanh nghip
gpvn,vay vn(khngphnbitvay dihnhay vay ngn
hn),nhnvnlindoanh,phthnhcphiu,triphiu,trnvay, v.v.
Luchuyntinthunthotngtichnh
Lu chuyn tin thun t hot ng ti chnh
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Thu: Tinvay nhnc,tinthu cdo nhnvngplin
doanhbngtin,dophthnhcphiu,triphiu,v.v..
Chi: Tinchi trlicho ccbngpvn,trlicphiu,tri
phiubngtin,thu litingi,v.v.
Lu chuyn thun t hot ng ti chnh = Thu Chi
Luchuyntinthunthotngtichnh
Bng lu chuyn tin
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Dng tin rng = Thu nhp rng + Chi ph khu hao
Bngluchuyntin
Thuyt minh Bo co ti chnh
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Mtvphntchchi tithnccsliucthhintrong
Bngcnikton,bocoKtqukinh doanh,bocoLuchuyntintvccthngtinbsung khc
Cung cpthngtin
CslpBocotichnhChnhschktoncthcchn
Ccthngtinbsung chactrnhby
trong ccbocotichnhkhc.Mikhonmctrong Bngcnikton, Bocoktqukinh
doanh, vBocoluchuyntintcncnhdudn
nccthngtin linquan trongbnthuytminh Bocoti
chnh.
Thuytminh Bocotichnh
Mi quan h gia 4 bng bo co
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Miquan hgia4 bngboco
Bng cn i k ton
01/01/200x
Tin v cc khon
tng ng tin
BCKQKD
Nm 200x
Bng cn i k ton
31/12/200x
Tin v cc khon
tng ng tin
Thuyt minhBo co ti
chnh
BCLCTT
Nm 200x
Chi tit
Chi tit
Chi tit
Phn Tch cc t s ti chnh
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PhnTchcctstichnh
Nhmchtiukhnngthanh ton;
Nhmchtiuqunltisn;
Nhmchtiuqunln;
Nhmchtiusinh li;
Nhmchtiugithtrng.
Phng php so snh
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Phngphpso snh
So snhtuyti
So snhtngiBntrong
Bnngoi
Nhm ch tiu kh nng thanh ton
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Nhmchtiukhnngthanh ton
Tsthanh tonhinhnh: TisnNgnhn
= --------------------------
Nngnhn
Tsthanh tonnhanh: TSNHTnkho
= ----------------------Nngnhn
Nhm ch tiu qun l ti sn
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Nhmchtiuqunltisn
Vngquay tnkho Doanh thu= -------------------------
Hngtnkho
Sngytnkho Sngytrong nm
= ---------------------------
Svngquay tnkho
Kthu tinbnhqun Cckhonphithu
= --------------------------- Doanh thu /360
Nhm ch tiu qun l ti sn
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Nhmchtiuqunltisn
Vngquay tisncnh Doanh thu= -------------------------
Tisncnh
Vngquay tngtisn Doanh thu
= --------------------------
Tngtisn
Nhm ch tiu qun l n
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Nhmchtiuqunln
Tsn/tngtisnNphitr
= --------------------
TngTisn
Tsthanh tonlivayLinhuntrcthulivay
= -------------------------------------
tinlivay
Tsn/vncphn Nphitr= ----------------------
Vnchshu
Nhm ch tiu kh nng sinh li
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Nhmchtiukhnngsinh li
Linhuntrndoanh thu Linhunrngsau thu= -------------------------------------
Doanh thu
Khnngsinh licnbn Linhuntrcthuvlivay= -------------------------------------
Tngtisn Tslinhuntrntngtisn
Linhunrngsau thu= -----------------------------------
Tngtisn
TslinhuntrnvnchshuLinhunrngsau thu= -----------------------------------
Vnchshu
Nhm ch tiu gi tr th trng
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Nhmchtiugitrthtrng
LN rngsau thu- LichCthius Linhunmicphiu= ----------------------------------------
Cphiuthngangluhnh
Tnggitrvnchshu Gitrssch = ----------------------------------------
Cphiuthngangluhnh
Nhm ch tiu gi tr th trng
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Nhmchtiugitrthtrng
TsP/E GithtrngP/E = ----------------------------------
Linhunmicphiu
TsP/BGithtrng
P/B = ----------------------
Gitrssch
Phn tch ti chnh DuPont
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PhntchtichnhDuPont
LNST LNST DTT TTS
------- = --------- x ---------- x ----------
VCSH DTT TTS VCSH
TTS
ROE = ROA x -------------------------
TTS x (1t s n)ROA
ROE = -------------------------
(1t s n)ROA = Li nhun trn Doanh thu x Vng quay ti sn
Li nhun trn Doanh thu (ROS) x Vng quay ti snROE = ---------------------------------------------------------------------
(1t s n)
Phn tch ti chnh DuPont
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PhntchtichnhDuPont
ROA nhhngbiLinhuntrnDoanh thu vVngquay tisn,
ikhi 2 tsnythay ingcchiunhngvntcngROA
tng.
Theo Anh, Ch, LinhuntrnDoanh thu vVngquay tisn,
tsnoquan trnghn?.
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Doanh nghipangnh
Tnhthivu
Phngphphchtonvkhuhao
Sliussch Tnhminhbchcabocotichnh
Mtsvncnlu khi phntchtichnh
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Hivtrli
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Chng: 3
QUN TR VN LU NG
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CHNG 4
GI TR CA TIN T THEO THI GIAN
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Mctiu
Hiurcchthctnhlin, likp
Xcnhchuitint- cchtnhthigicatint
Lachncchthchuy ngvntiu
63
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Lin, Likp
Khinim, ngha;
Cngthctnhlin, likp;
Lisutthc, lisutdanh ngha; Bitp.
64
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Khinim
Litc:
ivingicho vay hay nhutvn, litclstintng
thm trn s vn u t ban u trong mt giai an thi gian
nhtnh
ivingiivay hay ngisdngvn, litclstinm
ngiivayphitrcho ngicho vay (lngichshu)
csdngvntrong mtthigian nhtnh.
65
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Khinim
Lisutn:L tin li ch tnh trn s vn vay hoc vn gc ban u
trong sut thigian vay ( hocu t), hay tin lisau mi
k trong thi gian vay (hoc u t) khng c cng vovngcsinh licho ktiptheo.
Vd:
ut(vay) 1,000 $, trong 3 nm, lisut1 nm6%, thli
nchxtnvnut(vay) ban u1,000 $ khngquan
tmtinliphtsinh hngnmcct6%/nm.66
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67/234
Cngthctnhlin
V= V0+ V0* i + V0* i + + V0* i= V0+ n * V0* i
= V0* (1 + n * i)
67
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
68/234
Cngthctnhlin
V0: Vn(cho) vay ban u;
i: lisut(cho) vay;
n: Thigian (cho) vay (sk);
I: Litctheo lin;
V: Vngc+ litctheo lin
68
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
69/234
Bitp:
ut(vay) 1,000,000 ng, trong 4 nm, lisut1 nm10%, thli
nchxtnvnut(vay) ban u..
1. Xcnhtngstintchlyhngnm
2. Xcnhtinlihngnm
3. cc2,800,000 ng sau 4 nm, thhin ti, bnphigi
tinvongnhnglbao nhiu? Bitlisut10% vtinlikhngnhpvovngc
69
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
70/234
Khinim
Likp:
Likplphngphptnhlimtinlisau mikut
cnhpvovngctnhtinlicho ksau
Likpphnnhgitrtinttheo thigian cavngcv
litcphtsinh
70
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
71/234
Cngthctnhlikp
V0: Vn(cho) vay ban u;i: lisut(cho) vay;
n: Thigian (cho) vay (sk);
I: Litctheo likp;Vk: Vngc+ litctheo
Vk= V0*Lu: gilthascalisut
71
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
72/234
Bitp:
ut(vay) 1,000,000 ng, trong 4 nm, lisut1 nm10%, tin
linhpvovngchngk.
1. Xcnhtngstintchlyhngnm
2. Xcnhtinlihngnm
3. cc2,800,000 ng sau 4 nm, thhin ti, bnphigi
tinvongnhnglbao nhiu? Bitlisut10% vtinli nhp
vovngchngk.
72
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
73/234
So snhgialinvlikp
Theo linta c:
V= V0* (1 + n * i)Theo likpta c:
Vk= V0* (1+i)n
73
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
74/234
So snhgialinvlikp
Nun = 1, ta c(1+n*i) = (1+i)n
V= VkI= Ik=> gitrtcclinvlikpsbngnhau nuthigian utl1 nm
Nun > 1, ta c(1+n*i) < (1+i)n
V< VkI< Ik=> gitrtccalinsthphncalikpnuthigian uttrn1 nm
Nun < 1, ta c(1+n*i) > (1+i)n
V> VkI> Ik=> gitrtccalinscao hncalikpnuthigian utdi1 nm
74
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
75/234
Bitp
CA angcmtstinnhnri500,000 nhgititkimtingnhng. hnch ri ro, C chia s tin ra 2 phnkhcnhau. StinthnhtgivongnhngX, stinthhai givongnhngY. Chobittngtinlithu ctrongmtnmhai ngnhng l58,500. Tuy nhin, nu thay li
sutngnhngXbnglisutngnhngY vngclithtnglithu cl59,000.
Bit chnh lch li sut hai ngn hng l 0.5%, tin likhngnhpvn.
XcnhstinCA givomingnhngvlisuttingimingnhng?
75
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
76/234
Khinim
Lisutthc:
Bn c ngn hng cngb li sut huy ng li hng
thng1%, vylisutcuinm,bnnhncl12% ng
hay sai?
76
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
77/234
Khinim
Lisutthc:
Lisutthct(lisuthiuqu)llisutmbnthcsthu c tmtkhonu thocphi tr cho mtkhonvay sau khi tnhntcngcalisutghp
iellisutthc
inllisutdanh ngha
n lschu kgpli
77
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
78/234
Khinim
Lisutthc:Lisutthcghplitheo qu(3 thng)
Lu:Nulisutcngbhngnmtrlicuinmthlisutthchngk(di1 nm) ctnhnhsau:
78
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
79/234
Khinim
Lisutthc:
Bncngnhnghuy ng lisut12%/nm tr licuik,bnnhn1%/thngnghay sai?
79
Xydngkhinimthigitint
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80/234
Bnbao ginghe ninthigitinthay cha?
Nucslachn,bnschnhnhthcno?
Nhnngay 100,000,000 ng
Nhnsau 02 nm100,000,000 ng
Nuccyutkhckhngi? Tisao?
80
Tisao phisdngthigitint
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81/234
p g g
ngtin nhngthiimkhcnhau cgitrkhcnhaudo:
Chisdngtin
Lmpht
RiroDngthigitint:
Qui vgitrtngng
Cthso snhvinhau
81
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
82/234
Khinimthigitintcxydngnhthno?
Thigitintcxydngdatrncs: Lisut
Phngphptnhli
Thigitintccthhabihai khinimcbn
Gitrhinti
Gitrtnglai
82
ngdngmhnhchitkhudngtin
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
83/234
g g g
nhgitisn
Tisnhuhnh Tisntichnh
Triphiu
Cphiu
Phn tch v ra quyt nh u t
Dn
Thuti chnh
Lachnnguntitrngnhn Nnmua chuhay vay ngnhng
Nnvay ngnhnghayphthnhtnphiu
83
Gi tr tng lai v gi tr hin ti ca mt s tin
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
84/234
Nm 0 1 2 n-1 n
Lisut i i i i
Gitrhinti
PV
Gitrtnglai
FV1=
PV x (1+i)
FV2=
PV x (1+i)2 FVn-1=
PV x (1+i)n-1FVn=
PV x (1+i)n
i = Lisuthngnm(%/nm)
n = Snm
PV = Gitrhinti
FV = Gitrtnglai
84
Cngthctnhgitrtnglai vgitrhinti ca mt s tin
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
85/234
ticamtstin
Gitrtnglai lgitrmtthiimnotrong tnglai camt
stinhintidatheo mtmclisutbit. Cngthc:
FVn= PV * ( 1+i )n
Gitrhintilgitrquy vthiimhinticamtstintrong
tnglai datheo mtmclisutbit. Cngtc:
PV = FVn/(1+i)n= FVn* (1+i)
-n
85
BitpTmFV, PV
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
86/234
p ,
Bngi100,000,000 ngvotikhonnhktrlihng
nm5%. Bnsnhnvcbao nhiusau 5 nm?
Gis5 nm tibnmunc100,000,000 ng,ngay bygibnphigibao nhiuvotikhontinginhktr
li10%?
86
Bitp: Tmlisut
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
87/234
Gi sbn mua mt cphiu gi 100,000 ng s c tr150,000 ngsau 5 nm.
Bn kim c li tc bao nhiuphn trm cho khon u tny?
87
Bitp: Tmthigian
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
88/234
Gisbnbitmtchngkhonsmang lilinhun5%/nm
vbnphibra 100,000 ngmua chngkhonny.
Bnphi gi chng khon ny bao lu khi o hnbn c
c120,000 ng?
88
Ch i i
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
89/234
Chuitint
Khinim:Chui tin t lmt latcckhan tinpht sinh nhk theo
nhngkhangcchthigianbngnhau
Mtchuitinthnhthnhkhi xcnhc: Skphtsinh: n
Stinphtsinh mik(thu hocchi): C
Lisuttnhcho mik: i
dicaklkhangcchthigian cnhgiahai ktr
(nm, qu, thng)89
Ch i ti t
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
90/234
Chuitint
PhnlaiTheo stinphtsinh mik:
Chui tin t c nh: s tinpht sinh trong mi kbngnhau.
Chui tin tbini: s tinpht sinh trong mikkhngbngnhau.
90
Ch i ti t
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
91/234
Chuitint
Phnlai
Nm0 1 2 3 n-1 n
a1 a2 a3 an-1 an
Nm0 1 2 3 n-1 n
a2 an-1
a1 a3 an
91
Ch i ti t
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
92/234
Chuitint
Phnlai
Theo skkhanphtsinh mik:
Chuitintcthihn: skphtsinh lhuhn
Chuitintkhngkhn: stinphtsinh lvhn
Theophngthcphtsinh:
Chuiphtsinh uk: stinphtsinh umik
Chuiphtsinh cuik: stinphtsinh cuimik
92
Bi di l i d ti
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
93/234
Biudincclaidngtin
Lai dng tin Nm
0 1 2 3 4 n - 1 n
Dng tin u CK C C C C C C
Dng tin u VH C C C C C C
Dng tin u K C C C C C C
Dng tin khng u C0 C1 C2 C2 -C4 Cn Cn
Dng tin tng qut CF0 CF1 CF2 CF3 CF4 CFn-1 CFn
93
V d l i d ti
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94/234
Vd: cclaidngtin
Lai dng tin Nm
0 1 2 3 4 n - 1 n
u CK 100 100 100 100 100 100
u VH 100 100 100 100 100 100
u u k 100 100 100 100 100 100
Khng u - 1000 100 120 50 - 80 500 900
94
Gi tr tng lai ca dng tin c i k
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
95/234
Gitrtnglai cadngtinucuik
Gi tr tng lai ca dng tin u cui k (FVAn) chnhl tng gi tr tng lai ca tng khon tin C xy ra tng thi im khc nhau
S tin Ti thi imT Gi tr tng lai thi im n
C T = 1 FVn= C(1+i)n-1
C T = 2 FVn= C(1+i)n-2
C T = 3 FVn= C(1+i)n-3
.
C T = n1 FVn= C(1+i)n(n-1)= C(1+i)1
C T = n FVn= C(1+i)n-n= C((1+i)0
95
Gitrtnglai cadngtinucuik
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
96/234
n
t
tn
n iCFVA
1
)1(
i
1i)(1C1]/i-i)C[(1FVA
nn
n
t:
C: Gi tr ca tng khon tin ca dng tin u cui k n: s lng k hn
i: lisut
Cng thc tnh gi tr tng lai ca dng tin u:
96
Bi tp Gi tr tng lai ca dng tin u cui k
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
97/234
Mtnmsau khi sinh con gi,chA lnkhochhngnmvo
ngysinh nhtcon mnh,chA utrchra 10 triunggivo
tikhontchlytrlisut12%/nm.
Hin nm 18 tui, con gich A cc bao nhiu tin
trntikhon?
97
BitpGitrtnglai cadngtinucuik
Cch tnh Gi tr tng lai ca dng tin u cui k
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
98/234
CchtnhGitrtnglai cadngtinucuik
SdngExcel
Chnfx, financial, FV, chn OK, nh vo rate, nper, pmt,
cui cng chn OK
98
Gi tr hin ti ca dng tin u cui k
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
99/234
Gitrhinticadngtinucuik
Hin gi ca dng tin u cui k (PVA0) bng tng hingi ca tng khon tin tng thi im khc nhau.
S tin thi im T Gi tr hin tiC T = 1 PV0= C/(1+i)
1
C T = 2 PV0= C/(1+i)2
C T = 3 PV0= C/(1+i)
3
C T = n1 PV0= C/(1+i)n1
C T = n PV0= C/(1+i)n
99
Gitrhinticadngtinucuik
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
100/234
t:
C: Gi tr ca tng khon tin ca dng tin u cui k n: s lng k hn
i: lisut
Cng thc tnh gi tr tng lai ca dng tin u:
n
nn
0i)(1*i
1i)1(C]/ii)1/(1-[1*CPVA
n
n
t
t
iii
CiCPVA
)1(
11)1/(1
10
100
Bi tp Gi tr hin ti ca dng tin u cui k
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
101/234
BitpGitrhinticadngtinucuik
ChNmchunbnghhu. Cngty trtinhutrcho chtheo
mttrong hai lachn:
(1) Chsnhnhngthng2 triungtrong vng10 nm,k
nhntinutinvothngti.
(2) Chnhnngaybygimtstinl150 triung.
Nungnhngtrli1%/thngcho stinhumchNmgi
vo
Theo bnchNmnnnhntinhutheo phngnno?
101
Tmlisut
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
102/234
Nubnbit:
Gi tr tng lai hoc hin gi ca dng tin t Cckhonthu hocchi qua cckhn
S lng k hn
Bn c th gii phng trnh tm sut chit khu
Phng php tm sut chit khu bao gm:
Trabng
Dngmytnhtichnh DngExcel
102
BitpTmlisut
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
103/234
Gis5 nmtiMs. A cn100 triungvocuinmidulchncngoi. Hngnmcygi20 triungvotikhon
titkim.
Nungnhngtnhlikphngnm,lisutckvnglbaonhiucstinnhhochnh?
103
CchtnhTmlisut
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
104/234
Cchgii
Trabng
Sdngfinancial calculator
S dng Excel: Chnfx, financial, rate, chn OK, nh vonper, pmt, FV, cui cng chn OK,
104
Tmcckhanthu - chi qua ccthik
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
105/234
Nubnbit:
Gi tr tng lai hoc hin gi dng nin kim
Lisut, vSkhnli
Bn c th tm c khon thu hoc chi qua cc k hn
Cc phng php tm C bao gm:
Trabng
Sdngmytnhtichnh
SdngExcel
105
BitpTmkhanthuchi qua cckhn
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
106/234
Gis5 nmtiMs. A cnc100 triungvocuinmidu lchncngoi. Hicyphigivotikhontitkimvo
cui mi nm bao nhiu c c s tin hoch nh nu ngn
hngtrlikphngnml12% ?
106
CchtnhTmkhanthuchi qua cckhn
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
107/234
q
S dng Excel: Chnfx, financial, PMT, chn OK, nh vo
nper, rate, FV, cui cng chn OK
107
Dngtinuuk
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
108/234
Dng tin u u k dng tin m cc khon thu hoc chi xyra u mi k hn
Gi tr tng lai ca dng tin u u k (FVADn)
FVADn= FVAn(1+i)
Hin gi ca dng tin u u k (PVADn)
PVAD0= PVAn(1+i)
108
Bi tp Gi tr tng lai ca dng tin u u k
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
109/234
Bitp Gitrtnglai cadngtinuuk
Gi s bn cho thu nh vi gi 20 triu ng mt nm v k gi
ton b tin nhn c u mi nm vo ti khon tin gi tit kim
tr li kp hng nm 10%.
Hi bn s c bao nhiu tin vo cui nm th ba?
109
CchtnhGitrtnglai cadngtinuuk
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
110/234
Cch tnh Gi tr tng a ca dng tin u u k
Phng php s hc
FVAD3 = FVA3(1+i) =
= [20[(1+0,1)3
1]/0,1](1+0,1)= 72,82 triu ng
SdngExcel
Chnfx, financial, FV, chn OK, nh vo rate = 0.1, nper = 3, pmt= - 20, type = 1 cui cng chn OK
110
BitpGitrhinticadngtinuuk
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
111/234
p g
Gi sbn hoch nh hng nm s rt 20 triu ng vo u
nmtrong vng3 nmtittikhontitkimtrlisuthng
nm10%.
Hintibygibnphikgibao nhiuvotikhon
cthrtstinnhhochnh?
111
CchtnhGitrhinticadngtinuuk
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
112/234
g
Phng php s hc
PVAD0 = PVA0(1+i)
= {20[(1+0,1)3-1]/0,1(1+0,1)3(1+0,1)
= 54,71 triu ng
SdngExcel
Chnfx, financial, PV, chn OK v nh vo rate = 0.1, nper = 3,
pmt = -20, type = 1 cui cng chn OK.
112
Dngtinuvhn
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
113/234
Dng tin v hn l dng tin u cui k c khon thu hoc
chi xy ra mi mi.Dng tin u thng c:
Vi dng tin u v hn:
Hin gi dng tin u v hn c ng dng nh gi cphiu u i
n
n
t
t
n
iii
CiCPVA
)1(
11)1/(1
1
i
C
iiiCPVA
)1(
11
113
Dngtinkhngu
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
114/234
Dng tin khng u Dng tin t c cc khon thu hoc chithay i t k hn ny sang k hn khc.
Hingi:
Gi tr tng lai:
n
t
tCFPVPV
1
)(
)(1
n
t
tn CFFVFV
114
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
115/234
Hivtrli
CHNG 5
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
116/234
C NG
NH GI CHNG KHON
nhgichngkhon
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
117/234
g g
Cckhinim
nhgitriphiu
nhgicphiu
Xcnhgicphiucho ngygiao dchkhnghngquyn
Trngthicnbngcagicphiutrnthtrng.
Riro vlinhun
Cckhinim
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
118/234
Triphiu lmtchngtcgi, mtcngccandihn,
nquy nhngiphthnhtriphiu(phthnhn)phithanh
toncho ngigitriphiu(trich) hngnmmtkhonli
xcnhcho nkhi triphiuhthn(ohn).
Triphiucthanh tontheo mnhgikhi nkohn.
Tri phiu
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
119/234
p
c trng catriphiu:
Ngiphthnh:Chnhph, Cngty (theolut doanhnghip).
C thihnxcnh;
Lic nh, khng ph thucvoktqukinh doanh;
tri ro (phiri rotriphiuchnhph).
c thuhivngcbngmnhgi;
Khigiith,trich c utinthanhtontrc.
Phnloitriphiu
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
120/234
p
Triphiuchnhph
TriphiuCngty
Triphiuchuyni
Triphiukhngchuyni.
Triphiuciukinmua li
v.v
nhgitriphiu
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
121/234
121
nhgitriphiuthngthng
- Xcnhmnhgi, lisutcungphiu, thigian ohn
- Hingiccdngtindkinthu cttriphiu
Cngthctngqut
C M
(1+i)t (1+i)nt = 1
+P = +
t=1
n
nhgitriphiu
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
122/234
122
Trong :
P: Gitriphiu
n: Sk
C: LicungphiuM: Mnhgitriphiu
i: Lisutchiukhu
t: Skcho tikhi ohn
nhgitriphiu
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
123/234
g p
Triphiucmnhgi1.000.000 ng, thigian ohn10nm, lisuttriphiul10%.
a. HyxcnhgiTriphiu,bitlisutthtrngvn(chit
khu) 12%.b. HyxcnhgiTriphiu,bitlisutthtrngvn(chit
khu) 10%.
c. HyxcnhgiTriphiu,bitlisutthtrngvn(chitkhu) 8%
Nhnxt.
nhgitriphiu
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
124/234
g p
Triphiutrnhknmnhiulnthpdngsau:Chia i cho sln
Nhnn cho sln
Chia C cho sln
Vd: triphiutrlinm2 ln
nhgitriphiu
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
125/234
125
nhgitriphiukhngkhn
- Xcnhmnhgi, lisutcungphiu, thigian ohn
- Hinccdngtindkinthu cttriphiu
Cngthctngqut
C
(1+i)tt = 1
+P =
t=1
n
Tnhlisuttriphiu
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
126/234
Sdngphngphpthvloi:
TnhlisuttriphiubitGitriphiutrnthtrngl
1,051,500 ng, lisuttriphiu10%, khn5 nm, mnhgi
1,000,000 ng.
Tnhlisuttriphiu
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
127/234
Sdngphngphpthvloi:
i1= 9% P0(9%) = 1,038,900
i2= 8% P0(8%) = 1,079,900 ng
P0= 1,051,500 ng
i2+ P0(8%)-P0(9%)/P0(8%)-P0
8% + (1,079,9001,038,900)/(1,079,9001.051,500) = 8,69%
Cphiu
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
128/234
Cphiu: chngchhocbttonghi sxcnhnccquynv
lichhpphpcangishucphiuivitisnhoc
vncatchcphthnh.
Cphiuthng
Cphiuui
Cphiuthng
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
129/234
Phnloicphiuthng:
Cphiu thng l loicphiuc thu nhpph thucvo
hotngkinh doanh cacngty.
Blue chip (thnghng):
Growth (tngtrng):
Income (thu nhp):
Cyclical (chu k):
Seasonal (theo ma):
Cphiuui
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
130/234
Phnloicphiuui:
Cphiuuilchngchxcnhnquynshutrong mt
cngty, ngthichophpnginmgiloicphiuny
chngmtsquynliutinhnso vicngph
thng.
Nginmgicphiuuicgilcnguica
cngty
Cphiuui
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
131/234
Phnloicphiui:
Cphiuuitchly
Cphiuuikhngtchly
Cphiuuitham d
Cphiuuikhngtham d
nhgicphiu
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Phngphpchitkhudngtin
Phngphpchitkhuctc
Phngphpchitkhudngtinthun
Phngphpso snh: P/E ; P/B
Phngphpchitkhudngtin:
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PhngphpchitkhuctcGitrthccacphiulhingicattcccdngtinnhnctcphiutrong tnglai
CF1 CF2 CFn
PV = --------- + ---------- + . + ----------(1+i)1 (1+i)2 (1+i)n
Phngphpchitkhudngtin:
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Lichthu vtcphiusau 01 nm:+ Ctccchia ltinmtsau 01 nm(D1)
+ Gicphiusau 1 nm(P1)
+ tlchitkhur
D1 P1
PV = --------- + ----------
(1+i)1 (1+i)1
Phngphpchitkhudngtin:
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BndoncphiuACB strctc1,500 ng/c
phiuvgicphiusau 1 nml18,000 ng/CP.Nubn
yuculisutchitkhul8%/nm,bnsmua cphiu
nygibao nhiu?
Phngphpchitkhudngtin:
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Tlctctngtrngun
Dt= D0x (1 + g)t
D1 D0x (1 + g)
PV = --------- = ---------- ----------(i-g) (i-g)
D1: ctcdonnmsaug: tltngtrngctci: tlchitkhu
Phngphpchitkhudngtin:
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Cngty PLC vatrctc1,500 ng/cphiu, dkintc
tng trngcaCng ty mcnnh10%. Xcnh
gicphiunutlchitkhuyucul18%.
Cng ty ABC c chnh sch chi tr c tc c nh 2,500
ng/cphiu. Xc nh gi cphiu nu t l chit khuyucul10%.
Phngphpchitkhudngtin:
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Tlctctngtrngnhiugiai on
CphiuA vatrctc3,000 ng/cphiu, dkinctc
caCngty stng10% trong 3 nmtiv mc6% nnhcho nhngnmsau. XcnhgihintimAnh/Chcthmua
nulisutchitkhul15%
Phngphpchitkhudngtin:
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GisCngty A cctc10%/nm, mctngtrngg =
8%/nm, sutsinh livnchshul14%, gicphiu
dkinbnra sau 3 nml35,000 ng/cphiu.
Xcnhgicphiu.
Phngphpchitkhudngtin:
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PhngphpchitkhudngtinthunDatrngitrhinticaccdngtintrong tnglai
CF1 CF2 CFn
PV = CF0 + --------- + ---------- + . + ----------
(1+i)1 (1+i)2 (1+i)n
PhngphpdatrnP/E ; P/B:
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PhngphpP/E
DatrnhsP/E ngnhhay cngty cngcimtng
ng
PhngphpP/B
DatrnhsP/B ngnhhay cngty cngcimtng
ng(chyulcccngty thuclnhvctichnh), khngquan tmnthu nhpcamicphiu.
Tnhsutsinh litrnvnchshutheo mhnhnhgitisnvn
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g
Ki= Krf+ (KmKrf) x i
Trong :
Kisutsinh likvng
Krfsutsinh liphi riro
Kmsutsinh likvngcathtrng
ihsbtariro cachngkhonI trnthtrngchngkhon
Tnhsutsinh litrnvnchshutheo mhnhnhgitisnvn
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g
Ki= Krf+ (KmKrf) x i
Cphiuthngchsriro l1.2. Triphiukhobccli
sut8%, lisutbnhqunthtrngl11%. Tnhsutsinh li
cacphiuA.
Ki= Krf+ (KmKrf) x i = 8% + (11% - 8%) x 1.2 = 11.6%
Sutsinh licacphiuA l11.6%
Trngthicnbngcagicphiutrnthtrng
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Trngthicnbngliukintrong sutsinh likvng
cacphiubngngsutsinh liyucucanhut, nh
vygicphiuskhngi.
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Hivtrli
CHNG 6
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RI RO V LI NHUN
Nidung
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Khinim
Sutsinh likvng
Riro cadanh mcut
Khinim
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Riro: lsbinngtimngiaccktquthu ctrong
tnglai.
Trong utccloiriro sau cnlu:
Riro thanh khon
Riro thtrng
Riro trongphmvi cadoanh nghip
Khinim
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Li nhun: l thu nhp c c t mt khon u t, thng
cbiuthbngchnhlchgiathu nhpvgitrkhonu
tbra
Sutsinh likvng
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150
Sutsinh likvng:ltnggitrcacckhnngsinh livi
xcsutxuthincckhnng
Cngthctnhsutsinh likvng:
K = p1k1+ p2k2+ p3k3+.+pnkn= pix ki
Trong :
K: Sutsinh likvng
Pi: xcsutphnphichobinci
ki: gitrkhnngkhibinci xyra
i=1
n
Phngsai vlchchun
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151
Phngsai:lgitrtrungbnhcalchbnhphngcacc
gitrkhnngso vigitrtrungbnhcakhnng.
lch chun: o lng phn tn hay sai bit gia li
nhunthctso vilinhunkvng
Ccbctnhlchchun:
K = pix ki
2= (KiK)2Pi
= (KiK)2Pi
i=1
n
i=1
n
i=1
n
Hsbinthin
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152
lchchunikhi cho chng ta nhngktlunkhngchnh
xckhi so snhriro cahai dnnunhchngrtkhcnhau
vquy m
CV =
K
Riro danh mcut
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153
lchchun:
= Wi Wjrij i jviij= riji j
lchchundanh mc u t2 hngmci vj:
= Wi2i2 + 2 WiWjij + Wj2j2Trong :
: lchchundanh mc
ij: ngphngsai
WiWj: Ttrngcahngmci vj trong danh mc
i, j: lch chun hngmci vj
rijhstng quan kvng gia li nhun i vj
i = 1 j= 1
mn
Vd:
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154
Ni dung C phiu A C phiu B
Li nhun k vng 16% 14%
lch chun 15% 12%
Hstngquan ca2 chngkhonl0.4
Nhutbtinvo2 loichngkhonlnhnhau
Xcnh linhunkvngvlchchuncadanh mc.
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Hivtrli
CHNG 7
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
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CHI PH S DNG VN
Nidung
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Khinim
Chiphvnbphn
Chiphvntrungbnhtrngs
Chiphvnbintvquytnhut
Khinim
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Chiphsdngvnlmtsutsinh limccnhuttrnth
trngihikhibvnvodoanh nghip
Chiphvntrungbnhcacngty ltrungbnhgia quyncatng
tsutlinhuntrong nhngnguntitr
Chiphvnbintcacngty lchiphvntrungbnhtrnnhng
ngvnhuy ngmi.
Chiphsdngvncaminguntitrlchiphsdngvn
sau thuctnhtrnnntngcaccchiphtitr hinti
Khinim
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Ngunvntitrdihn:
Vay dihn
Vncphnui
Vnchshu
Chi phvncandihn
Chi h di h l t t i h li t h
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160
Chiphvncandihnltsutsinh liyucutrnnhng
tisnctitrdihn
Huy ngvnhnhthcny, khngnhhngnEPS caCng
ty vlchiphphitrtrcthu
I M
(1+kd)t (1+kd)
n
Trong :
P ltnggibntriphiu
C ltngchiphphthnh
t = 1
+
P - C = +t=1
n
Chi phvncphnthng
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Chiphsdngtlinhungili
Chiphsdngvncphnmi
Chi phvntlinhungili
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Chiphvntlinhungililtsutsinh liyucutrn
nhngtisncuttlinhungili.
Cngtyphitrcho nhutchiphchinunhnhut
cnhnctcvutvohotngkhc(giskhngri
ro)
Kr = K
Chi phvntcphnmi
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D0x (1 + g)
P0x (1 - F)
Trong : F lchiphphthnh
Chiphphthnhphthucvo:
Gicphiutrnthtrng
Tltngvn
Riro cadoanh nghip
v.v
Ke = + g
So snhchi phtvicsdngngunvngilivphthnhcphiumi
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NhnthythngthngKr< Ke
Chiphphthnhlmgimstinrngmdoanh nghip
nhnc
Gimgicphiucho ngygiao dchkhnghngquyn
Tlthnhcngkhiphthnh
v.v
Tnhchi phsdngvnchshu
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Mhnhchitkhuctc
MhnhCAPM
Chi phvntrung bnhcttrng
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WACC = Wsx Ks+ Wex Ke+ Wdx Kdx (1 - T%)
Trong : Ws, We, Wdlttrngcavncphnui, vnt
cvvnvay dihn
Ks, Ke, Kdlchiphsdngvntngng
T % thuTNDN
Vd:
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Ngunvn S tin T trng(W) Gasdng%(r)
- Vay ngnhng 1,000 10% 6,1
- Triphiu 1,500 15% 6,2
- Cphiuui 1,000 10% 10,0
- Cphiuthng 5,500 55% 12,0
- Lili 1,000 10% 12,0
Tng Cng 10,000 100%
Vd:
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Tbngsliutrnta c
WACC = 10%*6,1%+15%*6,2%+10%*10%+55%*12%+10%*12% = 10,34 %
Nhnxt:
CcnhntnhhngnWACC
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Chnhschthtrng
TlD/E
Mcriro huy ngvn
Chnhschctc
Chi phvnbint(MCC)
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Quytnhutnndatheo tiuchun: sutsinh licadnphilnhnchiphvnbint
Timchuy ngvnmngay sau MCC stnggilimgy
Xcnhimgy:
BPj= AFj/Wj
AFjltngnguntitrj
Wj lttrngnguntitrtrong tngvn
Cng ty A c thu nhp gi li l 300.000$( vi chi ph s dng vn
tngngl13,0%) , cngtyphisdngthmnguntitrbng
Chi phvnbint(MCC)
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vncphnthngphthnhmicthginguyncutrcti
ucamnh. Ngoi ra cng ty ckhnngvay n them tia l
400.000$ vi chiphsdngvnvay sau thutngngl5,6% ,
vttrnmcnythchiphsdngvnvay sau thutnglnl
8,4%.Nhvyta thychai imgy: imgythnhtxuthin
khi 300.000$ thu nhpgilivichiphsdngvnl13% c
sdnghtvimgythhai xuthinkhi 400.000$ nvay di
hnvichiphsdngvnlrd=5,6% csdnght. cngty
ccutrcvnmctiul50% vncphn, 10% cphnui
v40% nvay. Ccimgynycthcxcnhnhsau:
Khi dimgycxcnh, chiphsdngvnbnhqunwacc trntonb
Chi phvnbint(MCC)
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g y p g q
phmvi nguntitrmigiaccimgyphictnh` ton. trcht, mc
chiphsdngvnbnhqun-wacc catngnguntitrmigiaimzero
vimgythnhtcncxcnh. Ktipchiphsdngvnbnhqunca
tanbnguntitrmigiaimgythnhtvimgythhai cncxc
nhvcnh th tip tcnu sau vncnxuthinnhngimgykhc.
Trong phm vi tngngun ti trmigiaccimgy , chcchn chi ph s
dngvnthnhphnsgia tngvdnnchiphsdngvnbnhqungia tng
timccao hnso viphmvi trc. Ttcnhngdliunyscngcs
dngchunbcho vicxcnhchiphsdngvnbintvnslthbiudinmilien quan giaWACC ccmccatngnguntitrmi
Chiphsdngvnbnhquntheo tngmcquy mnguntitrmica
cngty A
Quy mcatng nguntitr ttrng chiph chiphtheo ttrng0$ n600.000$
Chi phvnbint(MCC)
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0$ 600.000$
Nvay 40% 5,6% 2,2%
Cphnui 10% 9,0% 0,9%Cphnthng 50% 13,0% 6,5%
WACC1 = MCC1 = 9,6%
T600.000$n1.000.000$
nvay 40% 5,6% 2,2%CP 10% 9,0% 0,9%CPthng 50% 14,0% 7,0%
WACC = 9.8% (600 x 9.6% + 400 x 10.1%) MCC2 = 10,1%
T1.000.000$ trln
nvay 40% 8,4% 3,4%CP 10% 9,0% 0,9%CPthng 50% 14,0% 7,0%
MCC3 = 11,3%
Chi phvnbint(MCC)
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Bngtrntmttqutrnhtnhtonchiphsdngvnbnhquncacngty A .
Ba quy mcatngnguntitrmitocbihai imgy:600.000$ v
1.000.000$.
imgy1: 300,000/0.5 = 600,000 $
imgy2: 400,000/0.4 = 1,000,000 $
So snhchiphtrong ctthba ngviba quy mkhcnhau khi tngngunti
trtngln, chngta cththyrngchiphphtsinh trong giai onthnht
( t0$ n600.000$) khngcgthay inhtrong phnvd trn tnh
tan. trong giai onthhai (600.000$ n1.000.000$) ta thychiphsdng
vncphn thnggia tng thm ln14%. V trong giai oncuicng ta
thychiphsdngvnvay sau thutngln8,4%.
Chi phvnbint(MCC)
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11,5 MCC =11,0
10,5
10,0
9,5
0
Tngnguntitrmi
11.3%
9.8%9.6%
10.1 %
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Hivtrli
CHNG 8
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
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NH GI HIU QU S DNG VN
U T
Nidung
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
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Khinim
Tngquan vutdihn
Ccchtiusdngtrong nhgihiuquvlachndn
ut
Khinim
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Dnlbtknlctmthivctchcnhmtora mt
snphm, dchv, quy trnhhay khochnnht
Hiuqudnut
+ Kinh t
+ Xhi
+ Chnhtr
Tngquan vdnut
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
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Cutrcdnutgm:1. Scnthitcadn
2. Giithiuchut
3. Csphpl4. Giithiuslcdn
5. Nghincuvphntchthtrng
6. Khitonvutvtnmcut7. Bmytchcvnhns
Tngquan vdnut
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8. Phntchtichnh9. Bngcnili/l(hiuqutichnh)
10. Riro dnut
11. nhgitcngmitrng12. v.v
Phnloidnut
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Dnclpldnmchpnhnhay loibcngkhng
nhhngndngtincaccdnkhc
Dnloitrldnmchpnhnthccdnkhcbloi
b
Dnphthucldnmdngtinphthucvoccd
nkhc
Dng tin ca d n u t
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Dng tin ra: k hiu du (-)
Bao gm: Chi ph u t rng hinh thnh ti sn c nh v ti
sn lu ng ban u
Dng tin vo: K hiu du (+)
Dngtinthunt
vnhnhdn
Dngtinthanh l
ti sn khi d nktthc+
Dng tin ca d n u t
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Dngtinthunt
vnhnhdn
Khu hao ti sn c
nh
Thanh l ti sn cnh rng
Dngtinthanh l
tisnkhi dn
ktthc
Thanh l ti sn
(thu hi vn) lu
ng
Thu nhpsau thu
=
=
+
+
Ccchtiunhgihiuqudn
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
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Thigian honvn- PP HingitrrngNPV
Sutsinh linitiIRR
Sut sinh li ni tic iu chnh - MIRR
Chssinh li- P/I
Chtiuthigian honvn- PP
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
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Thi gian honvncadnlthigian cnthitcthhontrsvnuttlichrngthu ccadn
Thigian honvnkhngchitkhu
Thigian honvn=Nmtrckhi honvn+ scnntrong nmSthu trong nm
Thigian honvncchitkhulthigian honvncaccdnc
tnhngtrcatinttheo thigian
It1 +
=0+ 1 +
= = 0
CchtnhPP (#1)
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(c)10 K 22 K 37 K 47 K 54 K
0 1 2 3 4 5
-40 K 10 K 12 K 15 K 10 K 7 K
(a)
(-b) (d)
iukinchpnhnPP
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188/234
Gisnhqun la ra di thu hivnmong icadnl3.5 nm
Liu d n c c chp nhn khng?
nh gi phng php PP
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
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u im: Dhiuvsdng
Thngcpdngcho ccdncnthu hivnnhanh
D xc nh c thi giancnthitthu hilivnut
Nhcim: B qua yu t ga tr theo thi
gian catin;
Khngxem xtnktcudng
tindn; Ch xem xt c li ch ngn
hn.
CchtnhPP chitkhu
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
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Svncha thuhi
-40 K 10 K 12 K 15 K 10 K 7 K
0 1 2 3 4 5
-40 K -31.1K -21.5K -10.8K -4.4K -0.4K
-40 K 8.9K 9.6K 10.7K 6.4K 4.0K
Dng tin
chitkhu(i=12%)
Phng php gi tr hin ti thun
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
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NPV lgitrhinticadngtinthuncadn(I)tridngtinutra ban ucadn(C).
I1 I2 In(1+i)1 (1+i)2 (1+i)n
+ . . . ++ - CNPV =
TnhNPV
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
192/234
C.Ty A xc nh c t l li sut chit khu (i)cho d n l 13%.
iukinchpnhnNPV
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
193/234
D n c c chp nhn khng?
NhnxtNPV
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
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uim: Nhn nhnctrctiphiu
qukinh tcadn.
Ctnhtiyutgitrtheo
thigian catin. C xem xt n c cu ca
dngtin.
Nhcim:
Khng cho bit c khnngsinh licadn.
Kh xc nh c t lchitkhutnhNPV cadn.
Phng php t sut sinh li ni b
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
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IRR ltlchitkhulcnbnggitrhinticaccdngtinthuntrong tnglai tdnmang li(I) vichiphutban u(dngtinra ban u)cadn(C).
I1 I2 In
(1+IRR)1 (1+IRR)2 (1+IRR)n+...+
+C =
Tm IRR theo phng php ni suy
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
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NPV1 * (i2i1)
Cngthctngqut
Bc1: Chn i1sao cho NPV1 > 0
Bc2: Chn i2sao cho NPV2 < 0
NPV1 + NPV2IRR = i
1
+
Tm IRR theo phng php ni suy
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
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NPV1 (i2i1)
NPV1 + NPV2
IRR = i1+
iukinchpnhnIRR
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
198/234
Gi thit, nh qun l xc nh t l sinh li cn thit ca dn l 13% .
D n ny c c chp nhn hay khng?
Nhn xt phng php IRR
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
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u im:
Xem xtnyutgatrtheothigian catin
Chnktcudngtindn
Phnnhtngthmcsinh licadn
Nhc im:
Khng xem xt n quy m cad n
Khlachntlchitkhulmtiuchunso snh
IRR khng tnh n vic sdng dng tin c c qua ccnm t d n vo mc ch tiu t
Phng php chssinh liiuchnh- MIRR
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
200/234
Nhmkhcphcnhngnhcimca tsutsinh linib,
chngta dngchtiutsutsinh linibchiuchnh.
Tsutsinh linibchiuchnhlsut chit khu lmcho
hingicadn (dng ngnlura)bngvihin gica tng
giatnglai ca dng ngnluvo c tch ly theo mc chi
phvn ca Cngty.
Phng php chssinh liiuchnh- MIRR
7/25/2019 Bai Giang Qttc Tc Ltcd Nct
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COFt CIFt* (1+k)n-t
(1+k)t (1 + MIRR)n
TV
(1 + MIRR)n
Trong :
COFt= ngnlura (sm), CIFt= ngnluvo (tt calsdng)
k = chiphvn ca dn
Xc nh MIRR theo sliu trnvi chiphti u t l15%.
PV cost =
t=0
t=0
n
n
=
Phng php ch s sinh li
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Chssinh liltlgiagitrhinticacckhonthu (I) dodnmang livigitrhinticacckhonvnutban u(C),i lchiphsdng vn.
I1 I2 In
(1+i)1 (1+i)2 (1+i)n+ . . . ++ CPI =
PI = 1 + [ NPV/ C]
>
iukinchpnhnPI
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Khi PI > 1: D n c chp nhn
Khi PI = 1: Tuthucvotnhchtcadn
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Hivtrli
CHNG 9
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K HOCH NGN LU
Nidung:
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Cutrcbngbocongnlutichnh
Thm nh dncvng i hot ng khngbng nhau
Cutrcbngbocongnlu(TIPV)
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Bocongn lu lmtbngm tcckhon thc thuvthcchibng tin mt thot ng sn xut kinh doanh, ut va huy ng vn ca dn trong tng thi im cpht
sinh.
Bocongnluthngcutrcthnhhaiphnchnh:
Ngnluvo
Ngnlura
Nguyntcvquy cxydngbocongnlu
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Ginh:
Nmbtudn:
Nmktthcdn: Nmthanh l: (tyvodnvtisnut)
Thiimphtsinh lichvchiph:
nvtint:
Khuhao:
Thanh toncckhonmuabnchu:
Phngphp xc nh ngnluca dn
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Theophngphp trc tip:
(Ngnlurng)i= (Dng thu nhp)i(Dng chiph)i
Theophngphp gin tip:Ngnlurng =Ngnluthot ng kinh doanh +Ngnlutu t
Nguyntcvquy cxydngbocongnlu
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Nguyntccbn
Thcthu, thcchi
Ngoil
Chi phchicacctisnhinhuChi phchmcacckhonchi trong qukh
Lu
TrnhtnhtrngPhnbchiphcnh
Tltrtgicakhonthu, chi canhngnm1, 2 .n
Cutrcbngbocongnlu
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Nm 0 1 n
1.Ngnluvo
Tngngnluvo2. Ngn lu ra
Tng ngn lu ra
3. Ngn lu rng trc thu
4. Thu thu nhp doanh nghip
5. Ngn lu rng sau thu
Khuhao
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Mcch:
Tnhchi phkhuhao hngnmavobngBo
cothu nhp,tcnhhngnngnlurngca
dnthngqua lchnthucakhuhao
Tnhgitrthanh llmthngmccangnluvo
Khuhao
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Lu:
Khu hao khngphi l mt hng mc cabo co ngnlu, nhng c nh hng n ngn lu rng ca d n
thngqua lchnthu Nuchiphvnutccnmkhcnhau thnnlpcc
lchkhuhao ring
Btutnhkhuhao khi no?
Khuhao
Lu:
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Nuclmphtthgitrthanh lsctnhbnggi
trcnlitheo ssch(*) ciuchnhchslmpht
trong nc(nmthanh lso vinmut)
Nu d n c u t cc ti sn v hnh th khu hao
c tnhbnggi tru t/vngidn (khngc
gitrthanh l)
Snmkhuhao thngphituntheo quy nhcanh
nc (thng t 45/2013/TT-BTC ngy 25/04/2013 ca
Btichnh
Bocongnlu
Nm 0 1 n
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1. Ngn lu vo
Doanh thu thun
Gitrthanh l
2. Ngn lu ra
u t vn c nh
Chi ph hot ng
3. Ngnlurngtrcthu
4. Thu thu nhp doanh nghip
5. Ngnlurngsau thu
Sdngbocongnlu
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Tnhtoncctiuchnhgidndtrnngnlucha
chitkhu
Vi sut chit khuph hp, ta s tnh c cc tiu chnhgidndavongnluchitkhu.
Phntchriro
Thm nh dnc vng i hot ng khngbngnhau
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i vi cc d n c vng i hot ng khngbng nhau
vic sdngchtiuhin giarngcphnbhn ch. Trong
trng hp ny, chng ta sdng haiphngphp nh giaPhngphp thay th
Phngphp dng thu nhpbng nhau
Phngphp thay th
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Khi so snh cc dncvng i khngbng nhau, chng ta
phi iu chnh thi gian hot ng cc dn cho bng nhau,
bng cch tnh bi s chung nhonht gia cc thi gian hot
ng ca cc dn angthm nh.
Phngphp thay th
Ccbcthchin:
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Bc1: TnhNPV caccdn
Bc2: Tnhbishcung nhnhtcho tnggian hotng
caccdn
Bc 3: Tnh NPV ca cc d n theo vng ibi s
chung nhnht
Bc4: Chndntheo ktqutnhNPV. Chndnno
cNPV max >0.
Phngphp dng thu nhp bng nhau
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Trong trng hp vng i chung ca thi gian hot ng cacc dn angso snhl quln lm cho cc dnphi lp i
lp li nhiu ln, iu nyskhngthc t, khi ngi tas
sdngphngphp dng thu nhpbng nhau
Nguyntc: hiu chnh giatrca cc dn angso snh da
vo dng ngnlubng nhau vavhn ca mi dn
Phngphp dng thu nhp bng nhau
Ccbcthchin
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Bc1: TnhNPV caccdntheo vngicaccdn
Bc2: Chuynidngngnlugc thnhdngngn lubngnhau theo NPV catngdn.
Bc3: Tnhgi trhiuchnhcaccdn theo dng thunhpvhn.
Bc4: Chndn tiukhi cgitrhiuchnhlnnht
cchn
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Hivtrli
CHNG 10
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C CU VN DOANH NGHIP
Nidung
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Khinim Xcnhccuvntiu
Cpncnnhphvncntichnh
Lthuytvccuvn
Khinim
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Ccuvnmctiulsphihpgiaccngunvnvay,vncphnuivvncphnthngtrong khochhuy
ngvncamtdoanh nghip
CcnhntnhhngnquytnhccuvncaDoanh nghip
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Riro kinh doanh Thuthu nhpdoanh nghip
Huy ngvnngnhnvdihn
Cpncninhphvncntichnh
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ncnnhph(DOL) ltl(%) thay ilirnghayEBIT khi doanh thu thay i(theo tlcho trc).
ncntichnh(DFL) ltl(%) thay icaEPS so vi
EBIT
ncnnhphvimhavn
XcnhChiphcnhvChiphbini:
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imhavnxcnh:
Qhv= F/(p-v)
Trong :
Qhv lsnlnghavn
F Chiphcnh
P lgibnsnphm
V lchiphbinicho msnphm
Lu: khinimchiphcnhvchiphbiniltngi, Bicth
doanh nghipnynlchiphbini, nhng doanh nghipkhcnlchi
phcnh
ncnnhphvimhavn
Gisrngmtdoanh nghipchai khochsnxutA vB
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A: chiphcnh20,000 $, v = 1.5$/vsp, p = 2.0$/vsp
B: chiphcnh60,000 $, v = 1.0$/vsp, p = 2.0$/vsp
Dtnhsnlngkhochl80,000 snphmcho 2 dnXcnhimhavncho 2 dn?Nhnxt
CngthctnhDOL
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DOLEBIT/EBIT
Q/Q
CngthctnhDOL theo Q
Q * (pv)
Q * (p-v)F
CngthctnhDOL theo S
SV
SV - F
DOL =
DOL =
DOL =
Trong :
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p: githnhmtnvsnphm
v:binphmtnvsnphm
F: Tngnhph
S: doanh thu
Q: snlngsnxut
Nhnxt: DOL lchtiudngolngnhhngcas
thay idoanh thu nlirnghay EBIT
CngthctnhDFL
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DFLEBIT
EBIT - I
EPS (%)
EBIT
Trong : I llivay vnphitr
DFL =
DFL =
CptnghpDOL vDFL
Cptnghp(DTL) omctnghpcancnnh
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phvncntichnhnsthay icaS vEPS
Cngthc: DTL = DOL * DFL
Tnhtheo snlng:
Q * (p - v)
Q * (pv)FI
Tnhtheo doanh thu:
S - V
SVF - I
DTL = DOL * DFL =
DTL = DOL * DFL =
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Hivtrli