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 LI GII MT SBÀI TP TOÁN CAO CP 2  Li gii mt sb ài t p trong t ài liu này dùng để tham kho. Có mt sb ài t p do mt ssinh viên gii. Khi hc, sinh vi ên cn la chn nhng phương pháp phù hp và đơn gin hơn. Chúc anh chem sinh vi ên hc tp t t  BÀI TP GII VÀ BIN LUN THEO THAM S Bài 1:Gii và bin lun: 1 2 3 4 1 2 3 4 1 2 3 4 1 2 3 4 3 2 5 4 3 2 3 6 8 5 6 9 20 11 4 4 2  x x x x  x x x x  x x x x  x x x x      Gi i:

Bai Tap Ma Tran 5 877

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  • LI GII MT S BI TP

    TON CAO CP 2

    Li gii mt s bi tp trong ti liu ny dng tham kho. C mt s bi tp do mt s

    sinh vin gii. Khi hc, sinh vin cn la chn nhng phng php ph hp v n gin

    hn. Chc anh ch em sinh vin hc tp tt

    BI TP GII V BIN LUN THEO THAM S

    Bi 1:Gii v bin lun:

    1 2 3 4

    1 2 3 4

    1 2 3 4

    1 2 3 4

    3 2 5 4 32 3 6 8 5

    6 9 20 114 4 2

    x x x xx x x x

    x x x xx x x x

    Gii:

  • 1 3

    11( 2) 2 21( 3) 3 3

    11( 4) 4 34

    3 2 5 4 3 1 6 9 20 112 3 6 8 5 2 3 6 8 51 6 9 20 11 3 2 5 4 34 1 4 2 4 1 4 2

    1 6 9 20 11 1 60 15 24 48 270 20 32 64 360 25 40 80 46

    h h

    h h hh hh h h

    A B

    2( 1) 3 3 42( 5) 4

    1 2 3 4

    2 3 4

    9 20 110 5 8 16 90 5 8 16 90 25 40 80 46

    1 6 9 20 11 1 6 9 20 110 5 8 16 9 0 5 8 16 90 0 0 0 0 0 0 0 10 0 0 1 0 0 0 0 0

    6 9 20 11(1) 5 8 16 9

    h h h hh h

    x x x xx x x

    4

    1

    2

    3

    4

    1 2 3 4

    2 3 4

    (2) 1

    1 3 451 9 8 16

    1) 0 : (2) 5

    1

    1 6 9 20 112) 0 : (3) 15 24 48 27 :

    0 1

    x

    tx

    txKhi t R

    x t

    x

    x x x xKhi x x x

    he vo nghiem

  • Bi 2:

    Cho h phng trnh:

    1 2 3 4

    1 2 3 4

    1 2 3 4

    1 2 3 4

    2 3 4 54 2 5 6 76 3 7 8 9

    4 9 10 11

    x x x xx x x xx x x x

    mx x x x

    a) Tm m vi h phng trnh c nghim

    b) Gii h phng trnh khi m = 10

    Gii:

    a) Ta c:

    1 4 1

    1( 2) 21( 3) 3 2( 2) 31( 4) 4 2( 3) 4

    2 1 3 4 5 1 4 3 2 54 2 5 6 7 2 6 5 4 76 3 7 8 9 3 8 7 6 9

    4 9 10 11 4 10 9 11

    1 4 3 4 5 1 40 2 1 0 30 4 2 0 60 6 3 8 9

    c c c

    h hh h h hh h h h

    A B

    m m

    m

    3 4

    3 4 50 2 1 0 30 0 0 0 00 0 0 8 0

    1 4 3 4 50 2 1 0 30 0 0 8 00 0 0 0 0

    h h

    m

    m

    Ta thy: : 4m R r A B r A . Suy ra h c nghim vi mi gi tr cu m

    b) Gii h khi m = 10:

    Bin i s cp trn hng ta c:

  • 11 2 3 4

    22 3 4

    33 4

    4

    2 1 3 4 5 2 1 3 4 54 2 5 6 7 0 1 6 10 14

    / ...6 3 7 8 9 0 0 2 4 6

    10 4 9 10 11 0 0 0 0 0

    02 3 4 5

    4 2(1) 6 10 14

    3 22 4 6

    A B

    xx x x x

    x tx x x t R

    x tx x

    x t

    Bi 3

    Gii v bin lun h phng trnh sau theo tham s :

    1 2 3

    1 2 3

    21 2 3

    1 1

    1

    1

    x x x

    x x x

    x x x

    Gii:

    Ta c

    3 2 1

    1( 1) 2 21( 1) 3

    1 1 1 3 3 3 1 1 11 1 1 1 1 1 3 1 1 11 1 1 1 1 1 1 1 1

    1 1 13 0 0 3

    0 0

    h h h

    h h

    h h

    D

    21

    1( ) 22 21( ) 3

    2 2 2

    2 2 2 2 3 3 2

    1 1 1 1 1 11 1

    1 1 0 1 1 11 1

    1 1 0 1 1

    1 1 1 1 1 2 2

    h hx h h

    D

  • 2

    1 3

    2 2

    1( 1) 22 21( ( 1)) 3

    2 2

    2 2 3 2 2 3 2

    2

    1 1 1 1 1 11 1 1 11 1 1 1

    1 1 11

    0 1 11 2

    0 1 2

    1 2 1 2 2

    2 2 1

    c cx

    h h

    h h

    D

    3

    1 2

    2 2

    21( ( 1)) 2 2

    21( 1) 32

    2

    2 3 2

    1 1 1 1 1 11 1 1 11 1 1 1

    1 1 12 1

    0 2 1 11

    0 1

    2 11 1

    2 1 1 2 1

    c cx

    h h

    h h

    D

    Ta thy:

    (1) 23

    3 00

    D

    Khi h c nghim duy nht:

    2 21

    1 2

    22 2

    3 23

    3

    2 23 3

    2 1 2 13 3

    2 13

    DxxD

    DxxD

    DxxD

    (2) Nu 3 th 1

    3(2 9) 21 0xD : H v nghim

    (3) Nu 0 th h tr thnh:

  • 1 2 3

    1 2 3

    1 2 3

    100

    x x xx x xx x x

    H v nghim

    Bi 4

    Gii v bin lun h phng trnh sau theo tham s :

    1 2 3 4

    1 2 3 4

    1 2 3 4

    1 2 3 4

    5 3 2 4 34 2 3 7 18 6 5 97 3 7 17

    x x x xx x x xx x x xx x x x

    Gii

    2( 1) 12( 2) 32( 1) 4

    1( 4) 2 2 31( 3) 4 2( 1) 4

    5 3 2 4 3 1 1 1 3 24 2 3 7 1 4 2 3 7 18 6 1 5 9 0 2 7 19 77 3 7 17 3 1 4 10 1

    1 1 1 3 20 2 7 19 70 2 7 19 70 2 7 19 7

    h hh hh h

    h h h hh h h h

    A B

    4 3

    1 1 1 3 20 2 7 19 70 0 0 0 00 0 0 0

    1 1 1 3 20 2 7 19 70 0 0 00 0 0 0 0

    h h

    H phng trnh tng ng vi h:

  • 1 2 3 4

    2 3 4

    3 22 7 19 7

    0

    x x x xx x x

    Ta thy:

    (1) Khi 0 th h v nghim

    (2) Khi 0 th h tr thnh:

    1 2 3 4

    2 3 4

    2 3 4

    1 3 4 3 4 1 3 4

    3 2 (1) 2 7 19 7 (2)

    7 19(2) : 72 27 19 5 13(1) 7 3 2 52 2 2 2

    x x x xx x x

    x x x

    x x x x x x x x

    Vy nghim ca h khi l:

    1 3 4

    2 3 4

    3 4

    5 13 52 27 19 72 2

    ,

    x x x

    x x x

    x x

    tuy y

    Bi 5

    Gii v bin lun h phng trnh sau theo tham s

    1 2 3 4

    1 2 3 4

    1 2 3 4

    1 2 3 4

    3 2 5 4 32 3 6 8 5

    6 9 20 114 4 2

    x x x xx x x x

    x x x xx x x x

  • Gii

    Ta c:

    3 1

    11( 2) 2 3 21( 3) 3 41( 4) 4

    3 2 5 4 3 1 6 9 20 112 3 6 8 5 2 3 6 8 51 6 9 20 11 3 2 5 4 34 1 4 2 4 1 4 2

    1 6 9 20 11 1 60 15 24 48 270 20 32 64 360 25 40 80 46

    h h

    h h h hh hh h

    A B

    9 20 110 5 8 16 90 15 24 48 270 25 40 80 46

    2( 3) 3 3 42( 5) 4

    1 6 9 20 11 1 6 9 20 110 5 8 16 9 0 5 8 16 90 0 0 0 0 0 0 0 10 0 0 1 0 0 0 0 0

    h h h hh h

    Khi :

    (1) Nu 0 th 3 4r A B r A : h c v s nghim (tm nghim nh bi trn)

    (2) Nu 0 th :

    3

    2

    r A Br A B r A

    r A

    : h v nghim

    Bai 6

    Gii v bin lun h phng trnh sau theo tham s

    21 2 3

    3 21 2 3

    4 31 2 3

    1 3

    1 3

    1 3

    x x x

    x x x

    x x x

  • Gii

    Ta c:

    3 2 1

    1( 1) 2 21( 1) 3

    1 1 1 3 3 3 1 1 11 1 1 1 1 1 3 1 1 11 1 1 1 1 1 1 1 1

    1 1 13 0 0 3

    0 0

    h h h

    h h

    h h

    D

    1

    2

    2

    3 2 2

    4 3 3 2

    1( ) 22 21( ) 3

    2 2

    2 2 2 2 3

    3 1 1 3 1 1 1 1 13 1 1 3 1 1 3 1 13 1 1 3 1 1 1 1

    1 1 11 1

    3 0 1 1 3 11 1

    0 1 1

    3 1 1 1 3 1 1

    x

    h h

    h h

    D

    3 2 23 2 3 2

    2

    2

    3 2 2

    4 3 3 2

    1 3 1( 1) 2

    1( ( 1)) 32 2 2

    2 2

    1 3 1 1 3 1 1 1 11 3 1 1 3 1 3 1 11 3 1 1 3 1 1 1

    1 1 1 1 1 13 1 1 3 0 1

    1 1 0 1 2

    13 1

    1 2

    x

    c c h h

    h h

    D

    2 2

    3 2 2 3 2

    2 2

    3 1 2 1

    3 2 2

    3 2 3 2 1

  • 3

    2

    3 2 2

    4 3 3 2

    1 2 1( ( 1)) 2 21( 1) 3

    2 2

    22

    2

    1 1 3 1 1 3 1 1 11 1 3 1 1 3 3 1 11 1 3 1 1 3 1 1

    1 1 1 1 1 13 1 1 3 0 2 1

    1 1 0 1

    2 13 1 3

    1

    x

    c c h h

    h h

    D

    2

    2 2 2 3 2

    2 11 1

    3 2 1 1 3 2 1

    Ta thy:

    (1) Khi: 0

    03

    D

    . Suy ra h c nghim duy nht:

    2 221

    1 2

    22

    2 2

    2 3 23 23

    3 2

    3 22

    3

    3 2 12 1

    3

    3 2 12 1

    3

    DxxD

    DxxD

    DxxD

    (2) Khi 0

    03

    D

    v 1 2 3

    0x x xD D D suy ra h c v s nghim