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8/7/2019 bai tap toan 10 HK II
1/4
TOAN LP 10 - ON TAP HOC KY II
A. Ni dung n tp
1. Gii cc loi bt phng trnh bng cch xt du biu thc ( du nh thc , tam thc bc hai) , bin lun theo mv du ca tam thc bc hai 2. Tnh gi tr cc biu thc lng gic , rt gn cc biu thc lng gic , chng minh cc ng thc lng gic
da vo cc cng thc lng gic hc ( c bn , cng, nhn i, bin i)3. Vit cc phng trnh ng thng(tham s , tng qut) i qua hai im , i qua 1 im v song song hocvung gc vi mt ng thng , i qua 1 im v c h s gc cho trc4. Vn dngcccng thc tnh khong cch gia hai im , khong cch t 1 im n mt ng thng , tnh gcgia hai ng thng , v tr tng i ca hai ng thng 5. Vit cc phng trnh ng trn bit tm v bn knh , i qua ba im , bit ng knh , bit tm v tip xcvi ng thng .6. Vit phng trnh tip tuyn ca ng trn ti im thuc ng trn , song song (vung gc ) vi mt ngthng , i qua 1 im ngoi ng trn 7. V tr tng i gia ng trn v ng thng : ct nhau , tip xc , khng giao nhau..
B. Bi tp n tp
I. Bt phng trnhBai 1 Giai cac bat phng trnh :
a)2 1 3 1
13 2
x x b) (2x + 3)(5 3x) > 0 c) 2x(x 7)(4 3x) 0
d)( 3)(2 1)
0( 1)(5 )
x x
x x
e)
1 30
3 2 3x x
f) x2 5x + 4 0
g) x2 x 12 0 h)2
2
3
4
x x
x
1 i)
(2 3)(4 1)0
2
x x
x
Bai 2 Giai cac bat phng trnh:
a) 012
5
1
2
xxb) 0
1
1
13
5
xxc)
1
5
1
42
xx
d)3
3
4
21
xxx
e) 22 )12()31( xx f)12
2
13
2
x
x
x
xf)
1
8
1
2
1 2
xxx
x
Bai 3 Giai cac bat phng trnh:a) 2( 3 2)(2 1) 0x x x b) 2 2( 2 )( 1) 0x x x x c) 2 2(4 4 1)( 2) 0x x x x
Bai 4 Giai cac bat phng trnh sau:
a)43
3
4
122
xxx
b)23
2
65 22
xxxx
xc ) 1
352
1542
2
xx
xx
d) 2222 )73()5( xxxx e) 1103
1432
xx
xf) 1
325
622
2
xx
xx
Bai 5
Vi gia tr nao cua m th bat phng trnh sau c nghiem ung vi moi x:a) x2 + 2x 3m > 0 b) 0252)23( 22 mmxmx
c) 025)14(2 mxmmx d) (m 2)x2 2(m 3)x + m 1 < 0
Bai 6 Cho f(x) = (m + 1)x2 2(m 1)x 3m 3a) Tm m bt phng trnh f(x) > 0 nghim ng vi mi x Rb)Tm m bt phng trnh f(x) 0 v nghim .
Bi 7
Gii cc phng trnh v bt phng trnh sau:
a)2 25 4 6 5x x x x b) 24 4 2 1 5x x x c) 2 6 8 2 3x x x
8/7/2019 bai tap toan 10 HK II
2/4
II. Gi tr lng gic cng thc lng gic
Bi 1 Cho cosa =25
3 a
4vi . Tnh cos2a , sin2a.
Bi 2
2
3
3
2cos,
25
3sin
bbaaCho . Tnh cos(a + b).
Bai 3 Cho tana = 2 va < a