BO CO TH NGHIM: IU KHIN QU TRNHGio vin hng dn: Th.s ng Vn MH v
tn sinh vin: Nguyn nh Ngc MSSV: 20109340Nhm: 06 Thng s cho bi th
nghim: Course : 55 Class : 50272 Number: 9340 Stoptime : 34000Bi 1:
Xy dng h thng iu khin mt bnh mc.1.3.M phng i tng bnh mc bng khi
Single-Tank trn matlab Phng php ng cong p ngVi b thng s Course
Number = 55( kho 55 ) Class Number = 6 ( nhm 272) Namelist Number =
340 ( SHSV 20109340)
T l thuyt v th ta xc nh c cc tham s ca m hnh nh sau : T = 1.5 K
= 30 / ( 10 -1.5 ) kim chng m hnh ta s dng m hnh sau :
1. Thit k sch lc iu khin cho h thng :Tnh ton thng s b iu khin
theo cng thc Ziegler Nichol 1
B iu khinKc
P1/K=0.23 -
PI0.9/K=0.2110T/3=5-
PID1.2/K=0.282T=30.5/T=0.33
Dng hm truyn t PID : K(s) = Kc(1 ++Td*s)
Chnstoptime Ta c 3 sch lc iu khin l sch lc iu khin truyn thng
,=34000(=SHSV 2019340)a. Truyn thngP(Kc=0.23) th :
PI(Kc=0.21, Ti=5) th :
PID( Kp=0.28,Ti=3,Td=0.33)
b.sch lc iu khin phn hi :P (Kp=0.23)
th :
PI (Kp=0.21,Ti=5 )
th :
PID (Kp=0.28,Ti=3,Td=0,33)
th :
Phn hi chng bo ha tch phn :PI-RW (Kp=0.21, Ti=5)
th :
PID RW (Kp=0.28,Ti=3,Td=0,33)
th :
c.sch lc iu khin tng c1.Trng hp khng o lu lng ra: b iu khin P/P
(Kp=1000,Kp1=0.23)
th :
B iu khin P/PI-RW(Kp=1000,Kp1=0.21,Ti=5) th :
C2.Trng hp o lu lng ra B iu khin P/P (Kp=1000,Kp1=0.23)
th :
B iu khin P/PI
