S GD&T VNH PHC
TRNG THPT YN LC 2
KHO ST CHT LNG CUI HC K 2
NM HC 2013 -2014
MN: HA KHI 10Thi gian lm bi: 90 pht, khng k thi giao .
thi gm: 01. trang.
Cu 1: Phn t MX3 c tng s ht p, n, e l 196, trong s ht mang in
nhiu hn s ht khng mang in l 60. Tng s ht mang in trong M3+ t hn
trong X- l 12. Xc nh v tr ca M v X trong bng tun hon?
Cu 2: Trong t nhin clo c hai ng v bn: 37Cl chim 24,23% tng s
nguyn t, cn li l 35Cl . Tnh thnh phn% theo khi lng ca 37Cl trong
HClO4 ? ( cho NTK ca H=1, O=16)
Cu 3:Nguyn t ca nguyn t X c cu hnh e lp ngoi cng l ns2np3. Trong
oxit bc cao nht ca R, nguyn t oxi chim 74,07% v khi lng. Tnh % khi
lng ca nguyn t X trong hiroxit cao nht ca n?
Cu 4: Vit cng thc electron, cng thc cu to ca cc hp cht sau: O3,
N2, CO2, CH4, NH3Cu 5: Cn bng cc ptp sau bng phng php thng bng
eletron:
a. FeCl2 + H2SO4 + KMnO4 ............> Fe2(SO4)2 + Cl2+
K2SO4+ MnSO4+ H2O
b. Mg + H2SO4c .................> MgSO4 + H2S + H2O
Cu 6: Ho tan m gam hn hp A gm FeO, Fe(OH)2, FeCO3, Fe2O3, Fe3O4
c cng s mol tc dng vi dung dch H2SO4 long d thu c 1,568 lt kh CO2
(ktc) v dung dch X. Dung dch X c th lm mt mu bao nhiu ml dung dch
KMnO4 1M?
Cu 7: Cho kh H2S li t t n d vo 500 ml dung dch hn hp cha CuCl2
1M v FeCl3 1M. Sau khi cc phn ng xy ra hon ton khi lng kt ta thu c
l bao nhiu?
Cu 8: Dng phng php ha hc nhn bit cc dung dch mt nhn sau: NaCl,
Kl, HCl, H2SO4, KOH
Cu 9: Vit cc phng trnh phn ng theo s sau:
CaOCl2 Cl2 CaCl2 CO2(6) ( (4)
Cl2NaClONaHCO3 Na2CO3 Cu 10: un nh hn hp MnO2 v HCl c. Dn kh Cl2
sinh ra i vo dung dch KI th thu c 12,7g It. Tnh khi lng axit HCl v
MnO2 tham gia phn ng?
Cho NTK ca Fe=56; C=12; O=16; K=39; Mn=55; Cl= 35,5. HS khng c s
dng bng tun
hon............................................................................Ht..........................................................................p
n ha 10_kho st cui k 2CuNi dungim
1Ta c: 2pM + nM + 3(2pX + nX ) =196
2pM + 6pX ( nM + 3nX) = 60
(2pM 3) +12 =(2pX + 1)
Gii h ta c: pX= 17: 1s22s22p63s23p5 v tr: s 17, chu k 3, nhm
VIIA pM = 13: 1s22s22p63s23p1 v tr: s 13, chu k 3, nhm
IIIA0,50,5
2S khi trung bnh ca Clo: 37* 0,2423 + 35*(1 0,2423) = 35,4846%m
37Cl trong HClO4 l: 37 * 0,2423/ (35,4846 + 1+ 16*4) = 8,922
(%)
0,50,5
3Do cu hnh e ngoi cng ca X l ns2np3 nn oxit cao nht c dng X2O5
%m O trong oxit = 16*5/ ( 2X + 16*5) = 0,7407 ....> X = 14
Hiroxxxit tng ng ca X c dng: HXO3%m X trong hiroxit = 14/(14 +1
+16*3) = 22,22%
0,250,250,250,25
4Mi cng thc vit ng cho 0,2 im
5a, 2 FeCl2 >2Fe+3 + 2Cl2 + 6e Mn+7 + 5e > Mn+210 FeCl2
+19H2SO4 + 6KMnO4 ............> 5Fe2(SO4)2 + 10Cl2+ 3K2SO4+
6MnSO4+ 19H2Ob, Mg0 .................> Mg+2 + 2e
S+6 + 8e .........> S-24Mg + 5H2SO4c ..........> 4 MgSO4 +
H2S +4 H2O
0,250,25
0,25
0,25
6nFeO = n Fe(OH)2 = nFeCO3= n Fe2O3=n Fe3O4= nCO2 = 0,07
mol..... .> nFe+2 = 0,28 mol
Ta c: Fe+2 > Fe+3 + 1e Mn+7 + 5e .> Mn+2 0,28 0,28 0,056
0,28
Vdd KMno4 = 56 ml0,250,250,25
0,25
8Dng qu tm th chia thnh 3 nhm nhm 1: Lm qu tm ha : HCl, H2SO4
nhm 2: Lm xanh qi tm: KOH
nhm 3: Khng lm i mu qu : NaCl, KI
Dng dd BaCl2 nhn cc cht nhm 1.
Dng dd AgNO3 nhn bit cc cht nhm 3
(mi cht nhn ra cho 0,2 im- c th dng cch khc nhn bit)
7Ta c: H2S + CuCl2 ......> CuS + 2HCl
0,5 0,5 (mol)
H2S + 2FeCl3 .......> 2 FeCl2 + 2HCl + S
0,5 0,25 (mol)
Khi lng kt ta l: 0,5(64 + 32) + 0,25*32 =56 gam0,25
0,25
0,5
9Mi pt ng cho 0,125 imCl2 + 2NaOH NaCl + NaClO + H2O
NaClO + CO2 + H2O NaHCO3 + HCl.
NaHCO3 + NaOH Na2CO3 + H2O.
Na2CO3 + 2HCl 2NaCl + H2O + CO2.
CO2 + H2O + 2CaOCl2 CaCO3 + CaCl2 + 2HClO.
Cl2 + Ca(OH)2 CaOCl2 + H2O.
CaOCl2 + 2HCl Cl2 + CaCl2 + H2O.
CaCl2 Ca + Cl2.
10nI2 = 0,05 molMnO2 + 4HCl ......> MnCl2 + Cl2 + 2H2O
0,05 0,2 0,05 (mol)
Cl2 + 2KI .......> 2KCl + I2
0,05 0,05 (mol )
Theo ptp: m MnO2 = 0,05*87 = 4,35 gam
MHCl = 0,2 * 36,5= 7,3 gam0,250,25
0,25
0,25
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