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GIẢI TÍCH HÀM NHIỀU BIẾN CHƢƠNG I: ĐẠO HÀM VÀ VI PHÂN CHƢƠNG II : TÍCH PHÂN BỘI CHƢƠNG III: TÍCH PHÂN ĐƢỜNG CHƢƠNG IV: TÍCH PHÂN MẶT CHƢƠNG V: CHUỖI SỐ - CHUỖI LŨY THỪA

ĐH va VP - Phần 1

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  • GII TCH HM NHIU BIN

    CHNG I: O HM V VI PHN

    CHNG II : TCH PHN BI

    CHNG III: TCH PHN NG

    CHNG IV: TCH PHN MT

    CHNG V: CHUI S - CHUI LY THA

  • CHNG I: O HM V VI PHN

    1: Cc khi nim c bn

    2: o hm ring

    3: Kh vi v Vi phn

    4: o hm ring v vi phn hm hp

    5: o hm ring v vi phn hm n

    6: o hm theo hng Vecto gradient

    7: Cng thc Taylor Maclaurint

    8: Cc tr hm nhiu bin : Cc tr t do, cc tr c iu kin, GTLN-GTNN trong min ng

  • 1 : Cc khi nim c bn

    Min (Tp) xc nh ca hm l tt c cc gi trca (x,y) lm biu thc ca hm c ngha

    Min (Tp) gi tr ca hm l tp cc gi tr m hm c th nhn c

    Hm 2 bin f(x,y) l nh x f : D R

    nh ngha hm 2 bin : Cho D l tp con ca R2

    Hm 2 bin f(x,y) l nh x f : D R

    nh ngha hm 2 bin : Cho D l tp con ca R2

    ( , ) ( , )x y f x y z

  • V d : Tm MX, MGT ca hm 2 2( , ) 9f x y x y

    MGT l on [0,3]

    MX l hnh trn 2 2 2( , ) : 9D x y R x y

    MX 3

    3

    MGT

    30

    f(x,y)

    (x,y)

    1 : Cc khi nim c bn

  • 1 : Cc khi nim c bn

    Gii :

    a. f(2,1) = 2

    V d: Cho hm1

    ( , )1

    x yf x y

    x

    Tnh f(2,1) v tm MX ca f

    b. MX :

    Ta ly na mt phng pha trn ng thng x+y+1 = 0 v b i ton b ng x = 1

  • th hm z = f(x, y) l phn mt cong S, khc

    vi th hm 1 bin y = f(x) l phn ng cong.

    Cho f(x, y) l hm 2 bin vi MX l D. th ca f l

    tp tt c cc im M(x, y, z)R3, vi (x,y)D, z= f(x, y)

    1 : Cc khi nim c bn

  • 2

    0 0

    2 2 2

    0 0

    ( , ) : ( , )

    ( , ) : ( ) ( )

    B M r M R d M M r

    x y R x x y y r

    Hnh trn (khng

    tnh ng trn) m ny cn cgi l mt r - lncn ca im M0

    Hnh trn m tm M0(x0,y0), bn knh r k hiu B(M0,r) l tp

    1 : Cc khi nim c bn

    M0r

    B(M0,r)

  • im trong : M1 gi l imtrong ca D nu tn ti tnht r1 > 0 sao cho r1- lncn ca M1 l B(M1,r1) nmhon ton trong D.

    im bin : M2 gi lim bin ca D nu vimi r2 > 0, hnh cu mB(M2,r2) cha nhng imthuc D v nhng imkhng thuc D.

    Cho tp D v 1 im M thuc R2. Ta nh ngha 2 loi im nh sau :

    1 : Cc khi nim c bn

    M1

    M2

  • 1 : Cc khi nim c bn Gii hn v lin tc

    Tp D c gi l tp ng nu D cha mi im binca n. Tp cc im bin ca D gi l bin ca D

    Tp D c gi l tp m nu R2\D l tp ng, khi ,mi im thuc D u l im trong, D khng cha btk im bin no

    : ( , )r D B O r Tp D c gi l tp b chn nu n c cha trongmt hnh cu no , tc l

    Nh vy, c nhng tp ch cha 1 phn bin mkhng cha ton b bin nn s l tp khng m,khng ng.

    V d: Hnh v slide trc l tp khng ng, khng m

  • 1 : Cc khi nim c bn

    V d : Cho D l phn hnh cu

    3 2 2 2( , , ) : 4D x y z R x y z

    Bin ca D l ton b mt cu x2 + y2 + z2 = 4, do D khng cha bt k im bin no tc l mi im thuc D u l im trong. Vy D l tp m

    V d : Cho hnh vnh khn

    2 2 2( , ) :1 4D x y R x y

    Bin ca D l 2 ng trn x2 + y2=1 v x2+y2 = 4 nm hon ton trong D nn D l tp ng

  • OB

    A

    Bin ca D l 3 on OA, OB, AB. Min D khng cha on AB tc l D khng cha mi im bin nn D khng l tp ng.

    Tuy nhin, D khng l tp m v D cha cc im bin thuc on OA, OB

    Tp D l tp b chn v ta c th ly ng trn ngoi tip tam gic OAB, ng trn ny cha min D tc l D nm hon ton trong 1 hnh cu m

    1 : Cc khi nim c bn

    V d : Trong R2 cho min D

    2( , ) : 3, 0, 0D x y R x y x y

  • 1 : Cc khi nim c bn

    Gii hn hm : Hm f(x,y) vi min xc nh D c gi l c gii hn bng L khi M(x,y) dn n M0(x0,y0), k hiu

    0 0( , ) ( , )lim ( , )

    x y x yf x y L

    nu 0, 0 : 0( , ) , ( , ) ,M x y D d M M

    ,f x y L

    hoc 0

    0

    lim ,x xy y

    f x y L

    nh ngha ny tng t nh ngha gii hn hm 1 bin: Khong cch gia M v M0 gim dn th khong cch gia f(x,y) v L cng gim dn

  • 1 : Cc khi nim c bn

    ngha: Khi khong cch gia M v M0 gim dn th khong cch gia f(x,y) v L cng gim dn

  • 1 : Cc khi nim c bn

    Hm lin tc : Hm f(x,y) c gi l lin tc ti (x0,y0) nu f (x0,y0) xc nh v

    0 00 0

    ( , ) ( , )lim ( , ) ( , )

    x y x yf x y f x y

    Hm lin tc trn min D nu n lin tc ti miim thuc min D

    Tng, tch, thng ca 2 hm lin tc l hm lin tc

    Cc hm s cp lin tc ti mi im thuc MX

    Hp ca 2 hm lin tc l mt hm lin tc

  • 2 : o hm ring

    Ta c:

    0

    00

    0

    limx x

    g x g xg x

    x x

    t g(x)=f(x,y0); nu hm g(x)c o hm ti x=x0 th ta gi l o hm ringtheo bin x ca hm f ti im (x0,y0) v k hiu l

    0, x x x

    0 00 0

    0

    0 00 0

    ( , ) ( , )( , ) ( , ) lim

    xx

    f y f yf x x xxf y yx

    x x

    0 00 0 00 0, , ,x xf

    g x f y yx x f xx

    yD

    nh ngha o hm ring:Cho hm 2 bin f(x,y), 1 im (x0,y0) thuc minxc nh ca hm f.

  • Tng t, ta c nh ngha hr ca hm f theo bin y

    Quy tc: Khi tnh o hm ring ca hm nhiu bin theo 1 bin no , ta coi cc bin khc l hng s

    2 : o hm ring

    Cc o hm ring ca hm n bin x1, x2, , xn (ni chung) li l cc hm n bin x1, x2, , xn

    00 0 00 0, , ,y yf

    f x x D f xy y yy

    00

    0 00x , ,limy

    y y y

    y

    f f x

    Nu f l hm nhiu hn 2 bin, ta cng nh ngha o hm ring tng t

  • 2 : o hm ring 2 : o hm ring

    V d: Trong nhng ngy nng, ta s cm thynng hn khi m trong khng kh thp (khhanh) v mt m hn khi m trong khng khcao hn.

    ,I f T H

    Ngi ta t ra khi nim ch s nhit (K hiu l I) m t s kt hp gia nhit thc t (T) v m trong khng kh (H). Vy I l hm theo 2 bin T v H :

    Di y l bng cc gi tr ca ch s nhit I theo nhit thc t T (0F) v m khng kh H (%)

    Lu : Nhit ng bng ca nc l 00C=320Fv quy i 10C=1.80F

  • 2 : o hm ring

    T: Nhit thc t (0F)

    H: m (%)

    Cho H=70% c nh, ta xem xt tc thay i cach s nhit I khi c nh m H=70%. Lc ny I chcn ph thuc vo T

    t : ,70g T f T, , th o hm ca g khi T=960F l tc thay i ca I khi T=960F=35,60C

  • 0 0

    96 96 96 ,70 96,7096 lim lim

    h h

    g h g f h fg

    h h

    2 : o hm ring

    Ta c:

    Tnh xp x g(96) bng cch s dng bng trn vi 2 trng hp h=2, h=-2

    98 96

    962

    g gg

    98,70 96,70

    2

    f f 4

    94 96 94,70 96,70

    962 2

    g g f fg

    3.5

    Ly gi tr trung bnh, ta c gi tr xp x

    96 3.75g

  • 2 : o hm ring

    96 3.75g

    Tng t, ta nhn hng ng vi T=960, tc l gi c nh T, v t G(H)=f(96,H)

    Tnh o hm G(70) bng cch cho h = 5 v h = -5, ri ly trung bnh cng nh trn, ta c kt qu:

    70 0.9G

    iu ny c ngha l khi nhit l 35.60C v m l 70% th ch s nhit tng khong cho mi phn trm m tng ln.

    0 00.9 0.5F C

    iu ny c ngha l khi m khng kh l 70% vnhit thc t l th ch s nhittng khong cho mi tng thc t

    0 096 35.6F C0 03,75 2.1F C

  • 2 : o hm ring

    ngha hnh hc ca hr ca hm f(x,y) ti (a,b):

    Tng t: fy(a,b) l h s gc ca tip tuyn T2 tc l h s gc ca mt S theo phng Oy ti P

    Ta gi fx(a,b) l h sgc ca mt S theophng Ox ti P(a,b,c)

    Xt trong mp y=b: C1 l

    giao tuyn ca mp vimt S th pt C1 l f(x,b), T1l tip tuyn ca C1 tiP(a,b,f(a,b)) th o hmfx(a,b) l h s gc catip tuyn T1

    Gi S l mt cong z=f(x,y)

  • 2 : o hm ring

    V d: Tnh o hm ring ti (x,y)=(1,1) ca hm 2 2( , ) 4 x 2f x y y

    2 1,1 2x xf x f

    H s gc ca tip tuynvi ng cong C1 ti(1,1,1) l - 2

    4 1,1 4y yf y f

    H s gc ca tip tuynvi ng cong C2 ti(1,1,1) l - 4

    ,v v hnh minh ha

  • 2 : o hm ring

    Gii : 2 2 2 2

    ,x yx y

    f fx y x y

    a.

    V d: Tnh o hm ring ca cc hm sau: 2 2

    cos

    . f(x,y)=

    . f(x,y)=e

    . f(x,y,z)=ln(x+e )

    x

    y

    y

    a x y

    b

    c xyz

    1. f ,f ,

    y

    x y zy y

    ec yz xz f xy

    x e x e

    b.cos cos

    2

    1sin , sin

    x x

    y y

    x y

    x x xf e f e

    y y y y

  • 2 : o hm ring

    0

    ( ,0) ( ,0)( ,0) li

    00 mx

    x

    f x

    x

    ff

    V d : Cho hm 3 33( , )f x y x y Tnh fx, fy ti (0,0)

    Gii :

    Nu tnh bng cch thng thng, ta s khng tnh c hr ti im c bit (0,0). Do , ta s tnh cc hr trn bng nh ngha

    3

    0

    30

    lim 1x

    x

    x

    V vai tr ca x, y nh nhau trong hm f nn ta cng c fy(0,0) = 1

  • 2 : o hm ring

    V d : Tnh cc hr ca hm

    Gii: Ta tnh 3 hr ca hm 3 bin

    h theo x: y, z l hng s

    h theo z: x,y l hng s

    , ,z

    xf x y z

    y

    1

    . .

    z

    x

    x

    x xf z

    y y

    1

    .

    zz x

    y y

    h theo y: x, z l hng s

    1

    . .

    z

    y

    y

    x xf z

    y y

    1

    2.

    zzx x

    y y

    .ln

    z

    z

    x xf

    y y

  • 2 : o hm ring

    o hm cp 2 ca hm f(x,y) l o hm ca o hm cp 1:

    o hm cp2 theo x:

    o hm cp 2 theo y:

    o hm cp 2 hn hp:

    2

    0 0 0 0 0 0( , ) ( , ) ( )( , )xy x yf

    f x y xy x

    y f f x y

    2

    0 0 0 0 0 02( , ) ( , ) ( )( , )yy y y

    ff x y x y

    yf f x y

    2

    0 0 0 0 0 02( , ) ( , ) ( )( , )xx x x

    ff x y x y

    xf f x y

    2

    0 0 0 0 0 0( , ) ( , ) ( )( , )yx x yf

    f x y xx y

    y f f x y

  • 2 : o hm ring

    nh l Schwarz : Nu hm f(x,y) v cc o hmring fx, fy, fxy, fyx tn ti v lin tc trong min mcha (x0,y0) th fxy(x0,y0) = fyx(x0,y0)

    Ghi ch :

    1.i vi cc hm s cp thng gp, nh lSchwarz ng ti cc im tn ti o hm

    2.nh l Schwarz cn ng cho cc o hm ringt cp 3 tr ln. Tc l cc o hm ring hnhp bng nhau khi s ln ly o hm theo mibin bng nhau, m khng ph thuc vo th tly o hm theo cc bin

  • 2 : o hm ring

    Gii :

    Hm 2 bin nn ta tnh 2 o hm ring cp 1

    v 4 o hm ring cp 2

    V d: Tnh o hm ring n cp 2 ca hm

    ( , ) sin( )x yf x y e e

    cos( ), cos( )x x y y x yx yf e e e f e e e

    cos( ) sin( ) ,x x y x x yxx

    f e e e e e e

    cos( ) sin( ) ,y x y y x yyy

    f e e e e e e sin( )x y x y

    xy yxf f e e e e

  • 2 : o hm ring

    Tng t, ta c cc o hm ring cp (n+1) l o hm ca o hm cp n

    V d: Tnh o hm ring cp 3 ca hm:

    f(x,y) = x2y 3ex+y

    Gii:

    2 o hm ring cp 1 : 22 3 , 3x y x yx yf xy e f x e

    4 o hm ring cp 2 : 2 3 , 3 ,

    2 3

    x y x y

    xx yy

    x y

    xy yx

    f y e f e

    f f x e

    8 o hm ring cp 3: 3 , 2 3 ,

    3 , 3

    x y x yf e f e f fxxx xxy yxx xyx

    x y x yf e f e f fyyy yyx yxy xyy

  • 2 : o hm ring

    Ghi nh: o hm ring cp cao hn hp bng nhaunu s ln ly o hm theo cc bin bng nhau(khng k n th t ly o hm theo tng bin)

    V d: Cho hm f(x,y,z) = xcosy 2ysinz. Tnh o hm ring cp 2.

    3 o hm cp 1:

    cos , sin 2sin , 2 cosx y zf y f x y z f y z 9 o hm cp 2

    0, sin , 0 ,

    cos , 2cos , 2 sin

    xx xy yx xz zx

    yy yz zy zz

    f f y f f f

    f x y f z f f y z