Đồ án cầu thép_hoan thanh

7/27/2019 n cu thp_hoan thanh

1/131

CHNG I - GII THIEU CHUNG GVHD: PHAN QUC BO

SVTH: NGUYEN NGOC HAN Trang: 1

Chng I

GII THIEU CHUNG

I.1. Cac so lieu thiet ke:- Loai dam thep lien hp co tiet dien ch I- Kho cau: B - K =10500 mm 2x1500 mm- Chieu dai dam chnh: L = 26000 mm.- So dam chnh: 7 dam.- Khoang cach 2 dam chnh: 2000 mm.- So sn tang cng ng (mot dam): 46. Trong o co 8 sn tang

cng tai goi.- Khoang cach cac sn tang cng: 2000 mm. Khoang cach gia cac

sn tai goi la 150 mm. Khoang cach gia sn tang cng tai goi visn trung gian la 1000 mm.

- So lien ket ngang (gia 2 dam): 10- Khoang cach 2 lien ket ngang: 2000 mm- Khoang cach 2 tru lan can: 4 m.

I.2. Phng phap thiet ke:- Thiet ket theo tieu chuan 22TCN272-05- Ban mat cau tnh theo ban hang va lam viec theo phng ngang cau.- Dam chnh: Tnh nh dam gian n. Tiet dien dam thep lien hp, khoang

cach - gia cac dam la 2 m.- Kiem toan.

I.3. Vat lieu dung trong thi cong:

- Thanh va cot lan can (phan thep): Thep CT3

+ yF 240 MPa

+ 5 3s 7.85 10 N / mm

- Le bo hanh, lan can:

+ Betong: 'cf 30 MPa 5 32.5 10 N / mm

+ Thep AII: yF 280 MPa 5 3

s 7.85 10 N / mm

- Ban mat cau, vut ban

+ Betong: 'cf 30 MPa 5 32.5 10 N / mm

+ Thep AII: yF 280 MPa 5 3

s 7.85 10 N / mm

- Dam chnh, sn tang cng, lien ket ngang


2/131

CHNG I - GII THIEU CHUNG GVHD: PHAN QUC BO


+ Thep tam M270M cap 345: yF 345 MPa 5 3

s 7.85 10 N / mm

+ Thep goc: L 102 x 76 x 12.7: yF 240 MPa 5 3

s 7.85 10 N / mm


3/131

Chng II LAN CAN & LE BO HANH


Chng II

LAN CAN - LE BO HANH

II.1. LAN CAN:II.1.1. Thiet ke thanh lan can:

- Chon thanh lan can thep ong co:+ ng knh ngoai D =80 mm.+ ng knh trong d = 70 mm.

- Khoang cach 2 cot lan can la: L = 4000 mm.- Khoi lng rieng thep lan can: 5 3s 7.85 10 N / mm

.

- Thep cacbon so hieu CT3: yf = 240 MPa.

II.1.1.1. Tai t ro ng t ac d ung len t hanh l an c an :

w=0.37N/mm

w=0.37N/mm

g=0.0925N/mmP=890N

4000

Hnh 2.1: S o tai trong tac dung len thanh lan can.

- Theo phng thang ng (y):+ Tnh tai: Trong lng tnh toan cua ban than lan can:

2 2 2 2

-5D -d 80 -70g 7.85 10 3.14 0.0925 N / mm4 4

+ Hoat tai:Tai phan bo: w = 0.37 N/mm

- Theo phng ngang:+ Hoat tai:

Tai phan bo: w = 0.37 N/mm


4/131



- Tai tap trung P = 890 N c at theo phng hp lc cua g va w.

II.1.1.2. Noi lc cua t hanh lan can :

Theo phng y:- Momen do tnh tai tai mat cat gia nhp:

2 2y

g

g L 0.0925 4000

M 185000 N.mm8 8 - Momen do hoat tai tai mat cat gia nhp:

+ Tai phan bo:

2 2y

w

w L 0.37 4000M 740000 N.mm

8 8

+ Tai tap trung:

y

P

P L 890 4000M 890000 N.mm

4 4

Theo phng x:- Momen do hoat tai tai mat cat gia nhp:

+ Tai phan bo:

2 2x

w

w L 0.37 4000M 740000 N.mm

8 8

To hp noi lc tac dung len thanh lan can:y y 2 x 2

DC g LL w LL w LL PM . ( .M .M ) ( .M ) M - Trong o:

+ : la he so ieu chnh tai trong:

D I R. . Vi:

D 0.95: he so deo cho cac thiet ke thong thng va theo ungyeu cau.

I 1: he so quan trong.

R 1: he so d tha (mc thong thng).0.95 1 1 0.95

+ DC 1.25 : he so tai trong cho tnh tai.

+ LL 1.75 : he so tai trong cho hoat tai.

2 2M 0.95 (1.25 185000 1.75 740000) (1.75 740000)

1.75 890000 3381160 N.mm

II.1.1.3. K iem tr a kha nang c hu lc cua thanh l an can :

n.M M Trong o:+ : la he so sc khang: = 1.+ M: la momen ln nhat do tnh va hoat tai.+ Mn: sc khang cua tiet dien: n yM f S .

S la momen khang uon cua tiet dien


5/131



3 3 3 3 3

3.14S .(D d ) (80 70 ) 16592 mm

32 32

n

M 240 16592 = 3981969 N.mm

n.M 1 3981969 = 3981969 N.mm 3381160 N.mm

Vay thanh lan can am bao kha nang chu lc.II.1.2. Ct lan can:

Ta tnh toan vi cot lan can gia, vi s o tai trong tac dung vao cotlan (hnh 2.2):

150

80

150

80

150

80

690

230

230

190

650

P"=2370N

P"=2370N

P"=2370N

I I

Hnh 2.2 :S o tai trong tac dung vao cot lan can.

e n gian tnh toan ta ch kiem tra kha nang chu lc lc xo ngang vaocot, bo qua lc thang ng va trong lng ban than.

II.1.2.1. Th iet k e cot th ep ch o cot l an can :

- Kch thc: nh hnh ve 2.2.- Lc tac dung: (ch co hoat tai)

+ Lc phan bo: w = 0.37 N/mm 2 thanh lan can hai ben cot truyen vaocot 1 lc tap trung: P= w.L = 0.37 x 4000 = 1480 N

+ Lc tap trung: P = 890 N+ Suy ra lc tap trung vao cot la:

P'' P' P 1480+890 = 2370 N Nhan xet: mat cat I-I la mat cat nguy hiem nhat, v vay can kiem tra kha

nang chu lc va thiet ke cot thep tai mat cat nay.- Momen tai mat cat I-I:


6/131



I I 1 2 3

M P'' (h h h )

2370 (190 420 650) 2986200 N.mm

- Mat cat I-I am bao kha nang chu lc khi:

n u LL I IM M . .M 1 1.75 2986200 5225850 N.mm

Thiet ke cot thep cho cot lan can:- Tiet dien chu lc: b x h = 140 mm x 160 mm- Chon a = 30 mm: khoang cach t trong tam cot thep en mep ngoai be

tong:ds = ha = 160 30 = 130 mm

- Xac nh chieu cao vung nen a:

2 2 u

s s '

c

2

2 Ma d d

0.85 f b

2 5225850130 130 13.12 mm

0.9 0.85 30 140

- Ban le bo hanh co 28 MPa < f'c = 30 MPa < 56 Mpa, vay:'

1 c

0.05 0.050.85 .(f 28) 0.85 (30 28) 0.836

7 7

- Xac nh khoang cach t th chu nen en truc trung hoa c:

1

a 13.12c 15.76 mm

0.836

- Xac nh trng hp pha hoai cho bai toan cot n:

s

c 15.760.131 0.42

d 120 bai toan thuoc trng hp pha hoai deo

- Xac nh dien tch cot thep:

'

2c

S

y

0.85 f a b 0.85 30 13.12 140A 167.28 mm

f 280

- Kiem tra ham lng cot thep toi thieu:

2s

2csmin

y

A 167.28 mm

f ' 30A 0.03 b h 0.03 140 160 72 mm

f 280

Ta thay As > Asmin.- Chon vung keo 2 10a80 dien tch As = 201,06 mm2- Cot thep c bo tr nh hnh 2.3.

II.1.2.2. K iem tra kha nang c hu lc cua cot lan can :- Chiu cao vung chu nen :

s y

'

c

A f 201 06280a 15 77 mm

0 85f b 0 8530140


7/131



Hnh 2.3:Bo tr cot thep trong cot lan can.- Kim tra:

s 1 s

c a 15 77 0 145 0 42d d 0 836130

Vy ct lan can chu pha hoi do.- Sc khang mo-men cua cot lan can:

'

n c s

aM 0,85f ab(d )

2

15 770,85 30 15 77 140 (130 ) 6874940 N.mm

2

- Ta co: ieu kien an toan cho cot lan can la:

n

u LL I I

n u

M 6874940 0 9 6187446 N.mm

M M 1 1 75 2986200 5225850 N.mm

Vay M M

Vay tiet dien u an toan.

II.1.2.3. K iem toan trang thai gii han s dung: (k iem tra nt)

- Tiet dien kiem toan:+ Tiet dien ch nhat co b x h = 160 mm x 140 mm

- Khoang cach t th chu keo ngoai cung en trong tam cot thep chukeo gan nhat:

c 1d a 30 mm < 50 mm

- Dien tch trung bnh cua betong boc quanh 1 thanh thep:

21 2c

(2 a a ) b (2 30 0) 140A 4200 mm

n 2

Trong o:+ a1 la khoang cach t th chu keo ngoai cung en trong tam cot

thep chu keo.+ a2 la khoang cach gia 2 tim cua thanh cot thep chu keo hang

tren va thanh cot thep chu keo hang di.- Momen do ngoai lc tac dung vao tiet dien:

80

30

30

140

30

160

100 30


8/131



s

M 2986200 N.mm

- Khoi lng rieng cua betong: 3c 2500 Kg/ m - Moun an hoi cua betong:

1.5c c cE 0.043 f '

1 5

0 043 2500 30 29440 MPa- Moun an hoi cua thep: sE 200000 MPa

- He so tnh oi t thep sang be tong: sc

E 200000n 6 7934

E 29440

- Chieu cao vung nen cua betong khi tiet dien nt:

s s

s

A 2 d bx n 1 1

b n A

201 06 2 130 1406 7934 1 1 41 54 mm

140 6 7934 201 06

- Momen quan tnh cua tiet dien be tong khi a nt:

32

cr s s

32

4

b xI n A (d x)

3

140 416 7934 201 06 (130 41 54)

3

14034536 mm

- ng suat trong cot thep do ngoai lc gay ra:

s

s scr

M

f d x nI

2986200130 41 54 6 7934 127 87 MPa

14034536

- Kh hau khac nghiet: Z 23000 N / mm - ng suat cho phep trong cot thep:

sa 33c c

Z 23000f 458 78 MPa

d A 30 4200

- So sanh:

sa yf 458 78 MPa 0 6 f 0 6 280 168 MPa

chon yf 168 MPa e kiem tra:

s

f 127 87 MPa 168 MPa

Vay thoa man ieu kien ve nt.


9/131



II.2. Le bo hanh:II.2.1. Tai trong tac dung len le bo hanh gom:

Xet tren 1000 mm dai- Hoat tai ngi: PL = 0.003 x 1000 = 3 N/mm- Tnh tai: DC = 1000 x 100 x 0.25 x 10-4 = 2.5 N/mm

Hnh 2.4: S o tnh noi lc le bo hanh

II.2.2. Tnh noi lc:

- Momen tai mat cat gia nhp:

+ Do tnh tai:

2 2

DC

DC L 2,5 1500M 703125 N.mm

8 8

+ Do hoat tai:

2 2

PL

PL L 3 1500M 843750 N.mm

8 8

- Trang thai gii han cng o:

U DC DC PL PLM . M M

0,95 (1,25 703125 1,75 843750) 2237695,313 N.mm

- Trang thai gii han s dung:

S DC PLM M M 703125 843750 1546875 N.mm

II.2.3. Tnh cot thep:

- Tiet dien chu lc b x h = 1000 mm x100 mm- Chon a = 20 mm: khoang cach t trong tam cot thep en mep ngoai be

tong:ds = ha = 100 20 = 80 mm

- Xac nh chieu cao vung nen a:

PL=3N/mmDC=2.5N/mm

1500

100


10/131



2 2 us s '

c

2

2 Ma d d

0.85 f b

2 2237695,31380 80 1,23 mm

0,9 0,85 30 1000

- Ban le bo hanh co 28 MPa< f'c = 30 Mpa < 56 Mpa

'1 c0.05 0.05

0.85 .(f 28) 0.85 (30 28) 0.8367 7

- Xac nh khoang cach t th chu nen en truc trung hoa c:

1

a 1,23c 1,47 mm

0,836

- Xac nh trng hp pha hoai cho bai toan cot n:

s

c 1,470,018 0,45

d 80 bai toan thuoc trng hp pha hoai deo

- Xac nh dien tch cot thep:

' 2c

S

y

0,85 f a b 0,85 30 1,23 1000A 112,02 mmf 280


2csy

f ' 30A 0,03 b h 0,03 1000 100 321,43 mm

f 280

- Chon 10a200 1000 mm co 5 thanh thep (dien tch As = 392.5 mm2) va theophng doc le bo hanh bo tr 10a200 .

Hnh 2.5:Bo tr cot thep tren le bo hanh.

II.2.4. Kiem toan trang thai gii han s dung: (kiem tra nt)

- Tiet dien kiem toan:+ Tiet dien ch nhat co b x h = 1000 mm x 100 mm+ Khoang cach t th chu keo ngoai cung en trong tam cot thep

chu keo gan nhat:

cd a' 20 mm < 50 mm- Dien tch cua vung be tong boc quanh 1 nhom thep:

2c cA 2 d b 2 20 1000 40000 mm


c 2A 40000A 8000 mmn 5

100 200 200 200 200 100

1000

80

20

100


11/131



- Momen do ngoai lc tac dung vao tiet dien:sM 1546875 N.mm

- Khoi lng rieng cua betong: 3c 2500 Kg/ m - Moun an hoi cua betong:

1.5c c cE 0.043 f '

1.50.043 2500 30 29440,09 MPa

- Moun an hoi cua thep: sE 200000 MPa

- He so tnh oi t thep sang be tong: sc

E 200000n 6,79

E 29440,09


s s

s

A 2 d bx n 1 2

b n A

392.5 2 80 10006,79 1 2 15,49 mm

1000 6,79 392.5

- Momen quan tnh cua tiet dien be tong khi a nt:

32

cr s s

32

4

b xI n A (d x)

3

1000 15,496,79 392.5 (80 15,49)

3

12329707,0 mm


s

s scr

M 1546875f d x n 80 15,49 6,79 54,95 MPa

I 12329707,0


sa 33c

Z 23000f 423.66 MPa

d A 20 8000

- So sanh: sa yf 423.66 MPa 0.6 f 0.6 280 168 MPa chon yf 168 MPa e kiem tra:

sf 54,95 MPa 168 MPa

Vay thoa man ieu kien ve nt.

II.3. Bo va:- Gia thiet ta bo tr cot thep cho bo va nh: hnh 2.6 va hnh 2.7- Ta tien hanh kiem tra kha nang chu lc cua bo va dang tng nh sau:

+ S o tnh toan cua lan can dang tng la s o deo+ Chon cap lan can la cap 3 dung cho cau co xe tai

Bang 2.1: Lc tac dung vao lan canPhng lc tac dung Lc tac dung (KN) Chieu dai lc tac


12/131



dung(mm)Phng mam ngang Ft = 240 Lt = 1070Phng thang ng FV = 80 LV = 5500

Phng doc cau FL = 80 LL = 1070

+ Bieu thc kiem toan cng o cua lan can co dang

W tR F 2

c cW b W

c t

M .L2R 8 M 8 M .H

2 L L H

+ Khi xe va vao gia tng:2

t t b Wc

c

L L 8 H.(M M .H)L

2 2 M

+ Khi xe va vao au tng:2

t t b Wc

c

L L H.(M M .H)L

2 2 M

Trong o:+ WR : sc khang cua lan can

+ WM : sc khang momen tren mot n v chieu dai oi vi truc thang

ng+ cM : sc khang momen tren mot n v chieu dai oi vi truc nam

ngang+ bM : sc khang cua dam nh+ H: chieu cao tng+ cL : chieu dai ng chay

+ tL : chieu dai phan bo cua lc theo phng doc cau+ Ft : lc xo ngang quy nh bang 2.1

II.3.1. Xac nh cM : (Tnh tren 1000 mm dai)

Tiet dien tnh toan b x h = 1000 mm x 200 mm va bo tr cot thep (hnh 2.6)

200200200100

1000

5 14200

25

175

100200

Hnh 2.6:Tiet dien va bo tr cot thep bo va theo phng ng.

- Cot thep dung 14a200 mm, 1000 mm dai co 5 thanh- Tnh toan vi bai toan cot n, tnh cot thep cho 1 ben roi ben con lai

bo tr tng t.- Dien tch cot thep As:


13/131



2 22

s

. 3.14 14A 5 5 769.3 mm

4 4

- Chon a = 26 mm (khoang cach t trong tam thep en mep ngoai cua betong)

sd h a' 200 26 174 mm

- Xac nh chieu cao vung nen a:S y

'c

A f 769.3 280a 8.45 mm

0.85 f b 0.85 30 1000

- Khoang cach t th chu nen en truc trung hoa:

1

a 8.45c 10.11 mm

0.836

- Xac nh trng hp pha hoai cua tiet dien:

s

c 10.110.058 0.45

d 175

Tiet dien thuoc trng hp pha hoai deo:

n S y sa 8.45M A f (d ) 769.3 280 37853713.1 N.mm1742 2

- Sc khang uon cot thep ng tren 1 mm:

nc

M 37853713.1M 37853.713 N.mm/mm

1000 1000

- Kiem tra lng cot thep toi thieu:

c 2s

y

f ' 30A 0.03 b.h. 0.03 1000 200 642.86 mm

f 280

Vay thoa man ieu kien cot thep nho nhat.

II.3.2. Xac nh WM H - WM H : La sc khang momen tren toan chieu cao tng oi vi truc

ng:- Tiet dien tnh toan b x h = 300 mm x 200 mm va bo tr cot thep (hnh 2.7)

200

300

2 14

40160

40

264

36

Hnh 2.7:Tiet dien va bo tr cot thep theo phng doc cau

- Cot thep dung 2 14 mm.


14/131



- Tnh toan vi bai toan cot n, tnh cot thep cho1 ben roi ben con lai botr tng t.

- Dien tch cot thep As:2 2

2s

. 3.14 14A 2 2 307.72 mm

4 4

- a= 40 mmds h a' 200 40 160 mm - Xac nh chieu cao vung nen: a

S y

'c

A f 307.72 280a 11.26 mm

0.85 f b 0.85 30 300

- Khoang cach t th chu nen en truc trung hoa

1

a 11.26c 13.47 mm

0.836

- Xac nh trng hp pha hoai cua tiet dien

s

c 13.470.084 0.45

d 160

- Tiet dien thuoc trng hp pha hoai deo

n S y s

a 11.26M A f (d ) 307.72 280 160

2 2

12815676.38 N.mm

- Sc khang uon cot thep ngang tren toan bo chieu cao bo va:

w nM H M 12815676.38 N.mm - Kiem tra lng cot thep toi thieu:

c 2s

y

f ' 30A 0.03 b.h. 0.03 300 200 289.29 mm

f 280

Vay thoa man ieu kien cot thep nho nhat.

II.3.3. Chieu dai ng chay: c(L )

Chieu cao bo va: H = 300 mm, v khong bo tr dam nh nen bM 0 . Vi trng hp xe va vao gia tng:

- Chieu dai ng chay:2

t t b WC

c

L L 8 H.(M M .H)L

2 2 M

2

C

1070 1070 8 300 (0 12815676.38)

L 1583.22 mm2 2 37853.713

- Sc khang cua tng:

2c c

W b Wc t

M .L2R 8 M 8 M .H

2 L L H


15/131



2

W

2 37853.713 1583.22R 8 0 8 12815676.38

2 1583.22 1070 300

399538.25 N

t WF 240000 N R 399538.25 N Thoa man

Vi trng hp xe va vao au tng:2

t t b Wc

c

L L H.(M M .H)L

2 2 M

2

C

1070 1070 300 (0 12815676.38)L 1157.73 mm

2 2 37853.713

- Sc khang cua tng:2

c cW b W

c T

M .L2R M M .H

2 L L H

2

W 2 37853.713 1157.73R 0 12815676.382 1157.73 1070 300

292162.47 N

t WF 240000 N R 292162.47 N => Thoa man.


16/131

Chng III BAN MAT CAU GVHD: PHAN QUC BO


Chng III

BAN MAT CAU

III.1. So lieu tnh toan:- Khoang cach gia 2 dam chnh la: S = 2000 mm.- Ban mat cau lam viec theo mot phng.- Chieu day ban mat cau: hf= 200 mm.- Chon lp phu mat cau gom cac lp sau:

+ Lp betong Atphan day 50 mm.+ Lp phong nc day 30 mm.+ Lp mui luyen day trung bnh 52+ Tong chieu day trung bnh DW= 132mm .

- o doc ngang cau: 1.5 % c tao bang thay oi chieu day lp mui luyen

III.2. S o tnh toan ban mat cau:

- Ban mat cau se c tnh toan theo 2 s o: Ban cong-xol va ban loaidam. Trong o phan ban loai dam n gian c xay dng t s o damlien tuc do o sau khi tnh toan dam n gian xong phai nhan vi he soke en tnh lien tuc cua ban mat cau.

Hnh 3.1 :S o tnh ban mat cau.


17/131



III.3. Tnh noi lc cho ban cong-xol: (ban hang)

Hnh 3.2:S o tnh cho ban cong-xol.

III.3.1. Tai trong tac dung len ban Cong-xol:III.3.1.1. Tnh tai:

Tai trong tac dung len ban co tnh tai, ta se xet tnh tai tac dung lendai ban rong 1000 mm theo phng doc cau:

Hnh 3.3:S o tnh tai lan can, le bo hanh tac dung len ban mat cau

Trong lng thanh lan can se c truyen vao cot lan can va truyen xuongban, do vay anh hng cua thanh lan can len ban se la trong lng cua cathanh lan can dai 2000mm moi pha, hay ta tnh vi 1 thanh dai 4000 mmm.


18/131



- Trong lng cua thanh nay la:2 2 -5 2 2

1 thp 1 2 lan canP (R -R )L 7.8510 (40 -35 )4000 370 N - Tai mot cot lan can co 3 thanh lan can, vay trong lng do lan can tac dung

len cot la: 1 1P 3P 3 370 1110 N - Trong lng cua cot (bo qua lo rong do thanh lan can, xem cot lan can la

be-tong ac):5

2P 2.5 10 140 160 740 414.4 N

- Trong lng lan can phan be-tong quy ve lc tap trung tai cot lan can (tnhcho dai 1000mm):

5

3P 2.5 10 1000 250 755 4718.75 N

- Trong lng le bo hanh (mot na tac dung len bo va, mot na tacdung len lan can be-tong): xet cho dai 1000 mm

5

4

1500P 2.5 10 1000 100 1875 N

2

- Vay trong lng toan bo do lan can va le bo hanh gay ra tren ban mat

cau la:3 1 2 3 4DC P +P +P +P 1110+414.4+4718.75+1875 8118.15N

- Trong lng ban than ban mat cau:-5

2DC 2.5 10 (750 250) 200 5 N/mm

III.3.1.2. Hoat tai:

- Hoat tai tac dung cho dai ban rong 1000 mm trong trng hp nay ch cotai cua ngi i bo truyen xuong (hoat tai nay c chia oi bo vanhan mot na va lan can phan be tong chu mot na, la lc tap trungtai au ban hang)

3

PL

PL 1000 b 3 10 1000 1500P 2250 N

2 2

+ b = 1500 mm: be rong phan le bo hanh

III.3.2. Noi lc trong ban cong-xol:

- S o tnh noi lc (hnh 3.4):

Hnh 3.4:S o tai trong tac dung len ban hang.


19/131



- Xet he so ieu chnh tai trong:D R I

Trong o:+ D 0.95: he so deo cho cac thiet ke thong thng va theo ung

yeu cau

+ I 1: he so quan trong+ R 1: he so d tha (mc thong thng)

0.95 1 1 0.95 - Gia tr mome am tai ngam:

2h

DC 2 DC 3 h PL PL h

bM DC DC b P b

2

+ Trang thai gii han cng o1:

DC 1.25 ; PL 1.75 ; 0.95

2

u

1000M 0 95 1 25 5 1 25 8118,15 1000 175 2250 1000

216349678,13 N.mm

+ Trang thai gii han s dung:

DC 1 ; PL 1 ; 0.95

2

s

1000M 1 1 5 1 8118,15 1000 1 2250 1000

2

12868150 N.mm

III.4. Tnh noi lc cho ban dam canh dam bien:

Ban at tren 2 goi la 2 dam chu, nhp cua ban la khoang cach giahai dam:S = 2000 mm, cach tnh ta se tnh nh dam n gian at tren hai goi, xet

cho dai ban rong 1000 mm

III.4.1. Tnh tai va noi lc do tnh tai tac dung len ban dam bien:

III.4.1.1. Tnh tai:

- Trong lng ban than:5

2 f cDC 1000 h 1000 200 2.5 10 5 N / mm

- Trong lng le bo hanh ngi i truyen xuong bo va:

5

2 2 c2

b h 1000 100 1500 2.5 10 1000P 1875 N

2 2

- Trong lng bo va: 5

4 4 4 cP b h 1000 200 280 2.5 10 1000 1400 N

(b4 = 200 mm chieu rong bo va, h4 = 280 mm chieu cao bo va) 3 1 4DC P P 1875 1400 3275 N

- Trong lng lp phu mat cau:+ Tong chieu day lp phu mat cau: DWh 132 mm


20/131



+ Trong lng rieng lp phu: 5 3c ' 2.3 10 N/ mm

5DW cDW h 1000 ' 132 1000 2.3 10 3.04 N/ mm

III.4.1.2. Noi lc

- S o tnh nh sau:

Hinh 3.5:S o tnh ban dam+ Vi L2 = 1250 mm ; L1 =750 mm ; S = 2000 mm

- Xet he so ieu chnh tai trong: D R I + D : He so o deo, trng hp thiet ke thong thng D 1

+ R : He so d tha, ban dam co tnh d R 0.95

+ I : He so quan trong, I 1 0.95

- Gia tr momen dng tai gia nhp:

22 22 1

DC DW 2 3 1

DC DW DC

LDW.L ( L )

DC S DC LS2M DW.8 2 8 2

+ Trang thai gii han cng o: DC 1.25 ; DW 1.5; 0.95

2 2

DC DWu

12503,04.1250( 750)

5 2000 200021.25 1.5 3.04

8 2 8M 0.95

3275.7501.25

2

5983960,94 N.mm

+ Trang thai gii han s dung: DC 1 ; DW 1; 1


21/131



2 2DC DW

s

12503,04.1250( 750)

5 2000 2000 3275.7502M 1 3.048 2 8 2

=4820625N.mm

III.4.2. Hoat tai va noi lc do hoat tai tac dung len ban dam:

III.4.2.1. Hoat Tai:

- Gom co 2 hoat tai: tai trong ngi i truyen xuong ban mat cau thongqua bo va, tai trong xe 3 truc at nh hnh 3.6:

- Tai ngi: lc tap trung co gia tr nh sau

3

PL

PL 1000 b 3 10 1000 1500P 2250 N

2 2

(b = 1500 mm : be rong le bo hanh)- Tai xe3 truc: at mot banh xe 3 truc (hnh 3.6):

Hnh 3.6:Tai trong ong tac dung len ban bien.

III.4.2.2. Noi lc: S o tnh c the hien nh tren hnh ve

- Be rong banh xe tiep xuc vi ban mat cau 510 mm- Dien truyen tai cua banh xe xuong ban mat cau:

1 2 DWb b 2 h 510 2 132 774 mm

- Gia tr tai p:

1

0.5 P 0.5 145000p 46,83 N / mm

2 b 2 774

- Dien lam viec cua ban:


22/131



+ Khi tnh momen am tai goi: SW 1220 0.25 S 1220 0.25 2000 1720 mm

+ Khi tnh momen dng tai gia nhp: SW 660 0.55 S 660 0.55 2000 1760 mm

- Gia tr momen tai gia nhp: Do tai xe3 truc:

2

LL

LL

SCD p DEACAE 22M (1 IM) 1.2 p CD

AE 2 2

- Trang thai gii han cng o: 0.95; LL 1.75; IM 0.25

2

LL

u

2000774 46,83. 2639632000 22M 0,95 1,75.(1 0,25).1,2 46,83 .

2000 2 2

31637437,89 N.mm

- Trang thai gii han s dung: 1; LL 1; IM 0.25

2

LL

S

2000774 46,83. 2639632000 22M 1. 1.(1 0,25).1,2 46,83 .

2000 2 2

=19030037,83 N.mm

Do tai ngi: PL PL 1PLP L

M2

- Trang thai gii han cng o: 0.95 ; PL 1.75

PL PL

u PL

P ABM

2

2250 7500.95 1.75 1402734,38 N.mm

2

- Trang thai gii han s dung: 1 ; PL 1

PL PLs PL

P ABM 2

2250 750843750 N.mm2

Gia tr momen tai gia nhp do tnh tai va hoat tai gay ra co xet entnh lien tuc cua ban mat cau (Vi dai ban 1000 mm) c tnh nh sau:- Trang thai gii han cng o:

+ Tai goi :


23/131



LLDC DW PLu

u u u

M 1000M 0.7 M M

SW

31637437,89 10000,7 5983960,94 1402734,38

1720

18046388,19 N.mm

+ Tai gia nhp:

LLDC DW PLu

u u u

M 1000M 0.5 M M

SW

31637437,89 10000.5 5983960,94 1402734,38

1760

12681256,15 N.mm

- Trang thai gii han s dung:+ Tai goi:

LLDC DW PLs

s s s

M 1000M 0.7 M M

SW

19030037,83 10000.7 4820625 843750

1720

11709845,34 N.mm

+ Tai gia nhp:

LLsDC DW PL

s s S

MM 0.5 M M

SW

19030037,83 10000.5 4820625 8437501760

8238448,25 N.mm

III.5. Tnh noi lc cho ban dam gia:III.5.1. Tnh tai va noi lc do tnh tai tac dung len ban dam:

III.5.1.1. Tnh tai:

- Cung giong nh trng hp ban dam canh dam bien nhng oi vi bandam gia th se khong co tai trong bo va va tai trong lp phu matcau se phan bo ay dam.

- Trong lng ban than: 52 f cDC 1000 h 1000 200 2.5 10 5 N / mm

- Trong lng lp phu mat cau:

+ Tong chieu day lp phu mat cau: DWh 132 mm

+ Khoi lng rieng lp phu: 5 3c 2.3 10 N/ mm

5DW cDW h 1000 132 1000 2.3 10 3.04 N / mm


24/131



III.5.1.2. Noi lc:

- S o tnh nh sau:

Hnh 3.7: S o tnh tnh tai cho ban dam gia- He so ieu chnh tai trong lay nh ban dam bien- Gia tr momen dng tai gia nhp:

2 22DC DWDC DWDC S DW SM 8 8

+ Trang thai gii han cng o: DC 1.25 ; DW 1.5 ; 0.95

2 2DC DW

u

5 2000 3.04 2000M 0 95 1 25 1 5

8 8

5134750 N.mm

+ Trang thai gii han s dung: DC 1 ; DW 1 ; 1

2 2DC DW

s

5 2000 3.04 2000M

8 8

4020000 N.mm

III.5.2. Hoat tai va noi lc do hoat tai tac dung len ban dam :

- Ch co xe3 truc, ay ta khong xet tai trong lan v nhp banS =2000 mm < 4600 mm theo quy nh khong can xet tai trong lan

- ay se co 2 trng hp at tai:- Trng hp ch co 1 banh xe cua 1 xe- Trng hp co 2 banh xe cua 2 xe khac nhau at trong ban khi o khoang

cach gia 2 banh xe la 1200 mm

III.5.2.1. Xet trng hp 1 c h co 1 b anh xe:

Ta se at banh xe ngay tai gia nhp e tnh toan


25/131



Hnh 3.8 :Tai trong ong tac dung len ban gia(Trng hp at 1 banh xe)

- Gia tr noi lc: Tng t nh tren ta co:+ 1b 774 mm

+

1

0.5 P 0.5 145000p 46,83 N / mm

2 b 2 774

+ SW 1220 0.25 S 1220 0.25 2000 1720 mm

+ SW 660 0.55 S 660 0.55 2000 1760 mm+ Gia tr momen tai gia nhp:

LL 1 1

LL

p b bM 1 IM 1.2 S

4 2

Trang thai gii han cng o: 0.95 ; LL 1.75 ; IM 0.25

LL

u

46,83 774 774M 0.95 1.75 1 0.25 1.2 2000

4 2

36449569,86 N.mm

Trang thai gii han s dung: 1 ; LL 1 ; IM 0.25

LL

s

46,83 774 774M 1 1 1 0.25 1.2 2000

4 2

21924553,3 N.mm

Gia tr momen tai gia nhp do tnh tai va hoat tai gay ra co xet en tnh lientuc cua ban mat cau (Vi dai ban 1000 mm) c tnh nh sau: Trang thai gii han cng o:

- Tai goi:


26/131



LLDC DW u

u u

M 1000M 0.7 M

SW

36449569,86 10000.7 5134750

1720

18428452,27 N.mm

- Tai gia nhp:

LLDC DW u

u u

M 1000M 0.5 M

SW

36449569,86 10000.5 5134750

1760

12922366,44 N.mm

Trang thai gii han s dung:

- Tai goi:

LLDC DW s

s s

M 1000M 0 7 M

SW

21924553,3 10000,7 4020000

1720

11736783,32 N.mm

- Tai gia nhp:

LLDC DW s

s s

M 1000M 0 5 M

SW

21924553,3 10000 5 4020000

1760

8238566,28 N.mm


27/131



III.5.2.2. Xet trng hp 2 (co 2 b anh xe)

Hnh 3.9: Tai trong ong tac dung len ban gia(Trng hp at 2 banh xe).

- Gia tr noi lc: Tng t nh tren ta co:+ 1b 774 mm

+ SW 1220 0.25 S 1220 0.25 2000 1720 mm

+ SW 660 0.55 S 660 0.55 2000 1760 mm

+ 1 1b'' b 1200 774 1200 1974 mm

+

1

0.5 P 0.5 145000p 36,73 N / mm

b'' 1974

- Gia tr momen tai gia nhp:

2

LLLL

p SM 1 IM 1

8

+ Trang thai gii han cng o: 0.95 ; LL 1.75 ; IM 0.25

2LL

u

36,73 2000M 0.95 1.75 1 0.25 1

8

38164765,63 N.mm

+ Trang thai gii han s dung: 1 ; LL 1 ; IM 0.25

2LL

s

36,73 2000

M 1 1 0.25 1 8

22956250 N.mm

Gia tr momen tai gia nhp do tnh tai va hoat tai gay ra co xet en tnhlien tuc cua ban mat cau (Vi dai tnh toan 1000 mm) c tnh nh sau:- Trang thai gii han cng o:

+ Tai goi:


28/131



LLDC DW u

u u

M 1000M 0.7 M

SW

38164765,63 10000.7 5134750

1720

19126497,06 N.mm

+ Tai gia nhp:

LLDC DW u

u u

M 1000M 0 5 M

SW

38164765,63 10000 5 5134750

1760

13409637,96 N.mm

- Trang thai gii han s dung:+ Tai goi:

LLDC DW s

s s

M 1000M 0 7 M

SW

22956250 10000 7 4020000

1720

12156659,88 N.mm

+ Tai gia nhp:

LL

DC DW s

s s

M 1000M 0 5 M

SW

22956250 10000 5 4020000

1760

8531661,93 N.mm

Vay gia tr momen am va momen dng ln nhat ng vi trang thai giihan cng o va trang thai gii han s dung thuoc trng hp at haibanh xe tren ban dam la:

- Trang thai gii han cng o:+ Momen dng: uM 13409637,96 N.mm

+ Momen am: uM 19126497,06 N.mm - Trang thai gii han s dung:

+ Momen dng: sM 8531661,93 N.mm

+ Momen am: sM 12156659,88 N.mm

III.6. Thiet ke cot thep cho ban mat cau:Ta se thiet ke cot thep tng ng vi cac gia tr noi lc TTGH cng

o va tnh tren:


29/131



III.6.1. Thiet ke cho phan ban chu momen am:

- Thiet ke cot thep cho 1000 mm chieu dai ban mat cau, khi o gia tr noilc trong 1000 mm ban mat cau nh sau:

- Momen am: uM 19126497,06 N.mm

- Chieu rong tiet dien tnh toan: b 1000 mm - Chieu cao tiet dien tnh toan: h 200 mm - Cng o cot thep: yf 280 MPa

- Cap betong: cf ' 30 MPa

- Tai trong tac dung: M 19126497,06 N.mm - Chon khoang cach t mep chu keo ngoai cung cua tiet dien en

trong tam vung cot thep chu keo la: a' 25 mm - Chieu cao lam viec cua tiet dien: 1sd h a 200 25 175 mm - Chieu cao vung betong chu nen cua betong:

2 us s

c

2

2 Ma d d0 85 f ' b

2 19126497,06175 175 4,83 mm

0 9 0 85 30 1000

- Xac nh 1 : do c28 (MPa) f ' 30 (MPa) 56 (MPa) nen:

1 c

0 05 050 85 (f ' 28) 0 85 (30 28) 0 836

7 7

- Chieu cao vung betong chu nen trong trng hp can bang:

1

a 4,83c 5,78 mm

0 836

- Kiem tra ieu kien: s

c 5,780 033 0 42

d 175

- Dien tch cot thep cho bi cong thc:

2csy

0 85 f ' a b 0 85 30 4,83 1000A 439,88 mm

f 280


2csy

f ' 30A 0 03 b.h. 0 03 1000 200 642 86 mm

f 280

Chon 14a200 e bo tr: trong 1000 mm co 5 thanh 14 va co

2s

A 769 3 mm

III.6.2. Thiet ke cho phan ban chu momen dng:

Qua trnh tnh toan tng t nh tren, ta c ket qua la bo tr thep 514a200

III.7. Kiem tra nt cho ban mat cau:Ta se kiem tra nt cua ban mat cau bang trang thai gii han s dung


30/131



+ Momen dng: sM 8531661,93 N.mm

+ Momen am: sM 12868150 N.mm

III.7.1. Kiem tra nt vi momen am:

- Cac gia tr cua sb, h, a', d a co tren- Khoang cach t th chu keo ngoai cung en trong tam cot thep chu

keo gan nhat: c 1d a 25 mm < 50 mm

- Dien tch cua vung betong boc quanh 1 nhom thep: 2c cA 2 d b 2 25 1000 50000 mm


c 2A 50000

A 10000 mmn 5

- Momen do ngoai lc tac dung vao tiet dien:M 12868150 N.mm

- Khoi lng rieng cua betong: 3c 2500 Kg/ m - Modul an hoi cua betong:

1.5c c cE 0.043 f '

1.50.043 2500 30 29440,09 MPa

- Modul an hoi cua thep: sE 200000 MPa

- He so tnh oi t thep sang betong: sc

E 200000n 6,79

E 29440,09


s s

s

A 2 d b

x n 1 2b n A

769.3 2 175 10006,79 1 2 32,63 mm

1000 6,79 769.3

- Momen quan tnh cua tiet dien betong khi a nt:

32

cr s s

32 4

b xI n A (d x)

3

1000 32,636,79 769.3 (175 32,63) 117457777,9 mm

3


ss scr

M 12868150f d x n 175 32,63 6,79 106 MPa

I 117457777,9


sa 33c

Z 23000f 365.1 MPa

d A 25 10000


31/131



so sanh: sa yf 365.1 MPa 0.6 f 168 MPa Chon 168 MPa e kiem tra

sf 106 MPa 168 MPa Vay thoa man ieu kien ve nt

III.7.2. Kiem tra nt vi momen dng

Tnh toan tng t ta cung c ng suat do ngoai lc gay ra nho hn ng

suat trong cot thep.


32/131


33/131

Chng IV DAM CHNH GVHD: PHAN QUC BO


Mot dam co: 38 sn tang cng giaKhoang cach cac sn: do = 2000 mm

Khoi lng mot sn tang cng: s1g 281.72 N + Sn tang cng goi: kch thc nh hnh 4.2:

Mot dam co: 8 sn tang cng goi

Khoang cach cac sn: 150 mmKhoi lng mot sn: s2g 296.2 N - Lien ket ngang:

+ Khoang cach gia cac lien ket ngang 2600 mm.+ Dung thep L 102 x 76 x 12.7 (cho ca thanh xien va thanh ngang)

+ Trong lng moi met dai: lkg 164 N Thanh ngang dai: 1670 mmThanh xien dai: 1175 mm

+ Moi lien ket ngang co: 2 x 1 = 2 thanh lien ket ngang. 2 x 1 = 2 thanh lienket xien

+ Moi dam co 10 lien ket ngang

IV.2. XAC NH AC TRNG HNH HOC CUA TIET DIEN DAM :IV .2 .1 . Xac nh ac trng hnh hoc cua t iet dien dam giai oan 1:

(T iet d ien dam thep)IV.2.1.1. Dien tch mat cat ngang phan dam thep:

s c c w f f f f

2

A b .t D.t b .t b' .t '

280 20 840 15 360 20 460 20 34600 mm

IV.2.1.2.Xac nh momen quan tnh cua tiet dien oi vi truc trung hoa:+ Chon truc X-X i qua mep tren cua tiet dien nh hnh ve:

Hnh 4.3:Chon truc trung hoa cho dam thep+ Moun tnh cua dam thep oi vi truc X-X:

c f fx' x i c c w c f f c f f

3

t t t 'DS A Y b .t . D.t . t b .t . D t b' .t ' . d2 2 2 2

20 840 20280 20 840 15 20 360 20 840 20

2 2 2

20460 20 840 20052000 mm

2

+Khoang cach t truc X-X ti trong tam cua tiet dien:


34/131



x' x0

s

S 20052000Y 579.54 mm

A 34600

IV.2.1.3. Xac nh momen quan tnh cua tiet dien dam thep oi vi truc trunghoa X-X:

2NC i i i3 3

2 2

3 32 2 4

I (I a .A )

280 20 15 840569.54 280 20 139.54 840 15

12 12

360 20 460 20290.46 360 20 310.46 460 20 4297645935 mm

12 12

IV.2.1.4.Xac nh momen khang uon cua tiet dien (Th di dam thep):

b 3NCNC b

I 4297645935S 13410865 mm

900 579.54y

IV.2.1.5.Xac nh momen khang uon cua tiet dien (Th tren dam thep):

t 3NCNC

0

I 4297645935S 7415616 mm

Y 579.54

IV2.2 . Xac nh cac ac trng hnh hoc cua t iet d ien dam gia g iai oan 2(Tiet dien lien hp):

Trong tiet dien dam lien hp thep-BTCT co hai loai vat lieu chnh- Thep: Thep dam chu + cot thep doc trong ban mat cau- Be tong: Ban be tongHai loai vat lieu nay co moun an hoi khac nhau, v vay e xac nh cac

ac trng hnh hoc chung cho tiet dien, khi tnh toan ta phai a vao he so tnh oico gia tr bang t so moun gia hai vat lieu e qui oi phan vat lieu betong trong tiet dien thanh vat lieu thep:

ay ban lam bang be tong co cf ' 30 MPa .Theo ieu 6.10.3.1.1.b-

22TCN 272-05 ta co gia tr t so moun an hoi n = 8IV.2.2.1.Xac nh chieu rong co hieu cua ban canh ( ib ):

- Chieu rong cua ban be tong tham gia lam viec vi dam thep. Theo ieu4.6.2.6.1 22TCN 272-05 qui nh:

- oi vi dam gia: Be rong ban canh hu hieu la tr so nho nhatcua:

tt

i s w c

L 260006500 mm

4 4

b min 12 t max(t ,b / 2) 12 200 max(15;280/ 2) 2540 mm

S 2000

ib 2000 mm .IV.2.2.2. Tiet dien lien hp ngan han:

* Xac nh mat cat ngang dam:- Dien tch phan dam thep:

2s

A 34600 mm

- Dien tch cot thep doc ban:


35/131



22

ct

14A 20 3077,2 mm

4

- Dien tch phan ban be tong:

2cc t

A 2000 200 280 100 2 100 100/ 2A 54750 mm

n 8

- Dien tch mat cat ngang dam:

2

d s ct c cdA A A A 92427,2 mm

* Xac nh momen quan tnh cua t iet dien lien hp oi vi truc trunghoa cua no:

- Xac nh truc trung hoa cua tiet dien lien hp

+ Moun mat cat (Momen tnh) cua dam lien hp oi vi truc 'NC NCX X

NC NCX ' X i i c td c td ct ct

3

S A Y A Y A Y

54750 720,86 3077,2 779,54 41865885,49 mm

Khoang cach t truc 'NC NCX X (Trong tam phan dam thep) en truc trung

hoa cua tiet dien lien hp:

'NC NCX X

0 s

d

S 41865885,49Y ' a 452,96 mm

A 92427,2

- Momen quan tnh cua tiet dien lien hp oi vi truc trung hoa cua no( ST STX ' X ):

2 2 2 2ST i i i NC s s ci ci ci ct ct3

2 2

32 2

4

1I I a A I a A (I a A ) A a

n

1 2000 2004297645935 452,96 34600 326,58 2000 200

8 12

1 380 100176,58 380 100 3077,2 326,58

8 12

17376277880 mm

- Xac nh momen khang uon cua tiet dien tai nh ban be tong:

t c 3STST t c

I n 17376277880 8S 32587140,9 mm

426,58y

- Xac nh momen khang uon cua tiet dien tai nh dam thep (xet taiiem ngay th di ban vut be tong):

b c 3STST b c

I n 17376277880 8S 1098200530 mm

126,58y

- Xac nh momen khang uon cua tiet dien (xet cho th tren dam thep):

t 3STST tI 17376277880

S 137275066,2 mm126,58y

- Xac nh momen khang uon cua tiet dien (xet cho th di dam thep):

b 3STST bI 17376277880

S 22466807,01 mm773,42y


36/131



IV.2.2.3. Tiet dien lien hp dai han:* Xac nh dien tch mat cat ngang dam:- Dien tch phan dam thep:

2s

A 34600 mm

- Dien tch phan cot thep doc ban:

2

2

ct14A 20 3077,2 mm4

- Dien tch phan ban be tong a tnh oi:

2c

c t

A 2000 200 280 100 2 100 100/ 2A 18250 mm

3 n 3 8

- Dien tch mat cat ngang dam: 2

dA 55927,2 mm


- Xac nh truc trung hoa cua tiet dien lien hp:+ Moun mat cat(momen tnh cua dam lien hp oi vi truc '

NC NC

X X


3

S A Y A Y A Y

18250 720,86 3077,2 779,54 15554495,49 mm

+ Khoang cach t truc 'NC NCX X en truc trung hoa cua tiet dien lienhp:

'NC NCX X

0

d

S 15554495,49Y" 278,12 mm

A 55927,2

- Momen quan tnh cua tiet dien lien hp oi vi truc trung hoa cua no

LT LT(X ' X ) :

2 2 2 2

LT i i i NC s s ci ci ci ct ct

32 2

32 2

4

1I I a A I a A (I a A ) A a3.n

1 2000 2004297645935 278,12 34600 451,42 2000 200

3.8 12

1 380 100351,42 380 100 3077,2 501,42

3.8 12

11396401140 mm

- Momen khang uon cua tiet dien (tai nh ban be tong):

t c 3LTLT t c

I 3 n 11396401140 3 8S 454779733,6 mm601,42y

- Momen khang uon cua tiet dien tai nh dam thep (Tai iem ngay thdi ban vut be tong)

b c 3LTLT b c

I 3 n 11396401140 3 8S 907416984,1 mm

301,42y

- Momen khang uon cua tiet dien (Xet cho th tren dam thep)


37/131



t 3LTLT tI 11396401140

S 37809041,01 mm301,42y

- Momen khang uon cua tiet dien (Xet cho th di dam thep)

b 3LTLT bI 11396401140

S 19039061,01 mm

598,58y

IV .2 .3 . Xac nh cac ac trng hnh hoc cua t iet d ien dam bien g iai oan 2(Tiet dien lien hp):

IV.2.3.1.Xac nh chieu rong co hieu cua ban canh (e

b ):

- Chieu rong cua ban be tong tham gia lam viec vi dam thep. Theo ieu4.6.2.6.1 22TCN 272-05 qui nh:

- oi vi dam bien: Be rong ban canh hu hieu la tr so nho nhatcua:

tt

ie s w c

hang

L 260003250 mm

8 8b

b min 6 t max(t / 2,b / 4) 6 200 max(15/ 2;280/ 4) 1270 mm

2 S 1000

eb 2000 mm

IV.2.3.2. Tiet dien lien hp ngan han:* Xac nh mat cat ngang dam:- Dien tch phan dam thep:

2s

A 34600 mm

- Dien tch cot thep doc ban:

22

ct

14A 20 3077,2 mm

4

- Dien tch phan ban be tong:

2c

c t

A 2000 200 280 100 2 100 100/ 2A 54750 mm

n 8

- Dien tch mat cat ngang dam:

2

d s ct c cdA A A A 92427,2 mm


- Xac nh truc trung hoa cua tiet dien lien hp

+ Moun mat cat (Momen tnh) cua dam lien hp oi vi truc 'NC NCX X


3

S A Y A Y A Y

54750 720,86 3077,2 779,54 41865885,49 mm

Khoang cach t truc 'NC NCX X (Trong tam phan dam thep) en truc trunghoa cua tiet dien lien hp:

'NC NCX X

0 s

d

S 41865885,49Y ' a 452,96 mm

A 92427,2


38/131



- Momen quan tnh cua tiet dien lien hp oi vi truc trung hoa cua no( ST STX ' X ):

2 2 2 2ST i i i NC s s ci ci ci ct ct3

2 2

32 2

4


n

1 2000 200

4297645935 452,96 34600 326,58 2000 2008 12

1 380 100176,58 380 100 3077,2 326,58

8 12

17376277880 mm

- Xac nh momen khang uon cua tiet dien tai nh ban be tong:

t c 3STST t c

I n 17376277880 8S 32587140,9 mm

426,58y

- Xac nh momen khang uon cua tiet dien tai nh dam thep (xet taiiem ngay th di ban vut be tong):

b c 3STST b c

I n 17376277880 8S 1098200530 mm126,58y

- Xac nh momen khang uon cua tiet dien (xet cho th tren dam thep):

t 3STST tI 17376277880

S 137275066,2 mm126,58y

- Xac nh momen khang uon cua tiet dien (xet cho th di dam thep):

b 3STST bI 17376277880

S 22466807,01 mm773,42y

IV.2.3.3. Tiet dien lien hp dai han:* Xac nh dien tch mat cat ngang dam:

- Dien tch phan dam thep: 2s

A 34600 mm

- Dien tch phan cot thep doc ban:

22

ct

14A 20 3077,2 mm

4

- Dien tch phan ban be tong a tnh oi:

2c

c t

A 2000 200 280 100 2 100 100/ 2A 18250 mm

3 n 3 8

- Dien tch mat cat ngang dam: 2

dA 55927,2 mm


- Xac nh truc trung hoa cua tiet dien lien hp:+ Moun mat cat(momen tnh cua dam lien hp oi vi truc 'NC NCX X


3

S A Y A Y A Y

18250 720,86 3077,2 779,54 15554495,49 mm


39/131



+ Khoang cach t truc 'NC NCX X en truc trung hoa cua tiet dien lienhp:

'NC NCX X

0

d

S 15554495,49Y" 278,12 mm

A 55927,2

- Momen quan tnh cua tiet dien lien hp oi vi truc trung hoa cua noLT LT(X ' X ) :

2 2 2 2LT i i i NC s s ci ci ci ct ct3

2 2

32 2

4


3.n

1 2000 2004297645935 278,12 34600 451,42 2000 200

3.8 12

1 380 100351,42 380 100 3077,2 501,42

3.8 12

11396401140 mm

- Momen khang uon cua tiet dien (tai nh ban be tong):

t c 3LTLT t c

I 3 n 11396401140 3 8S 454779733,6 mm

601,42y

- Momen khang uon cua tiet dien tai nh dam thep (Tai iem ngay thdi ban vut be tong)

b c 3LTLT b c

I 3 n 11396401140 3 8S 907416984,1 mm

301,42y

- Momen khang uon cua tiet dien (Xet cho th tren dam thep)

t 3LTLT tI 11396401140

S 37809041,01 mm

301,42y

- Momen khang uon cua tiet dien (Xet cho th di dam thep)

b 3LTLT bI 11396401140

S 19039061,01 mm598,58y

Bang 4.1: Tong hp cac ac trng hnh hoc cua dam chu

DAM GIA (DAM TRONG)

ac trng

Tiet dien damthep

Tiet dien damlien hp


Giai oan 1 Ngan han-giaioan 2 Dai han-giaioan 2Dien tch tiet dien

( 2mm )34600 92427.2 55927.2

Momen khang uonth di dam thep

( 3mm )13410865 22466807.01 19039061.01

Momen khang uon 7415616 137275066.2 37809041.01


40/131



th tren dam thep( 3mm )

Momen khang uon taimep di ban be

tong ( 3mm )1098200530 907416984.1

Momen khang uon tainh ban be tong( 3mm )

32587140.9 454779733.6

Momen quan tnh cuatiet dien ( 4mm )

4297645935 17376277880 11396401140

DAM BIEN (DAM NGOAI)

ac trng

Tiet dien damthep



Giai oan 1Ngan han-giai

oan 2Dai han-giai

oan 2

Dien tch tiet dien( 2mm )

34600 92427.2 55927.2

Momen khang uonth di dam thep

( 3mm )13410865 22466807.01 19039061.01

Momen khang uonth tren dam thep

( 3mm )7415616 137275066.2 37809041.01

Momen khang uon taimep di ban be

tong ( 3mm )1098200530 907416984.1

Momen khang uon tainh ban be tong

( 3mm )32587140.9 454779733.6

Momen quan tnh cuatiet dien ( 4mm )

4297645935 17376277880 11396401140

IV.3 .. XAC NH HE SO PHAN BO TAI TRONG THEO PHNG NGANG CAU:IV.3.1. Tnh cho dam gia:IV.3.1.1. He so phan bo cho momen:

Kiem tra ieu kien ap dung phng phap dam n

+1100 S=2000 4900mm+110 ts=200 300mm+6000 L=26000 73000mm+So dam N=7 >4+4.109 Kg=171946322600 3.1012 Thoa ieu kien

* Kh i x ep 1 lan xe t ren cau:


41/131



0.10.4 0.3gSI

momen 3s

KS Smg 0.06

4300 L L t

Trong o:+ m: He so lan+ SI

momeng : He so phan bo momen cho dam trong trng hp 1 lan xe tren

cau+ S: Khoang cach gia cac dam chu+ ttL : Chieu dai tnh toan cua ket cau nhp

+ st : Chieu day ban be tong mat cau

+ gK : Tham so o cng doc. Xac nh theo 22TCN-272-05 4.6.2.2.1

2g NC gK n I A e Vi:

n: Ty so gia mo un dan hoi cua vat lieu dam (E B) va mo unan hoi vat lieu ban mat cau (ED)

Ban mat cau lam bang be tong co cf ' 30 MPa , mo un an hoic xac nh theo cong thc:

1.5 ' 1.5D c cE 0.043 f 0.043 2500 30 29440,09 MPa

Dam chu lam bang thep co BE 200000 MPa

Vay B

D

E 200000n 6,79

E 29440,09

2 4gK 6,79 4297645935 34600 779,54 171946322600 mm

I: Momen quan tnh cua tiet dien phan dam c banA: Dien tch cua tiet dien phan dam c ban

ge =Yo+200=779,54mm : Khoang cach gia trong tam dam c ban va

ban mat cauVay:

0.4 0.3 0.1

SI

momen 3

2000 2000 171946322600mg 0.06 0,33

4300 26000 26000 200

* He so phan bo tai t rong cho momen dam tro ng cho nh ieu lan xechat t ai:

0.10.6 0.2gMI

momen 3s

0.6 0.2 0.1

3

KS Smg 0.075

2900 L L t

2000 2000 1719463226000.075 0.5452900 26000 26000 200

MImomeng : He so phan bo momen cho dam trong trng hp xep nhieu lan

xe tren cauIV.3.1.2.Xac nh he so phan bo cho lc cat:

* Kh i x ep 1 lan xe t ren cau:

SIluccatS 2000

mg 0.36 0.36 0.6237600 7600


42/131



Trong o:SIluccatg : H s phan b lc ct cho dm trong trng hp ch xp 1 lan xe tren cau

* Kh i xep >1 lan xe chat tai:

2 2

MI

luccat

S S 2000 2000mg 0.2 0.2 0.721

3600 10700 3600 10700

MIluccatg : H s phan b lc ct cho dm trong trng hp xp >1 lan xe tren cau

He so phan bo tai trong cho momen va lc cat do tai trong ngi (PL)

1 1 1

.(0,375.750 0,375.750) 01500 2

PL PL

PL

gB

IV.3 .2. Tnh cho dam bi ende = -750


43/131



Hnh 4.8:Phng phap on bay (chat tai xe 2 truc va xe 3 truc)

1SEmomeny 0.325

g 0.1632 2

Theo ieu 3.6.1.1.2 trng hp tren cau ch co 1 lan xe chat tai ta cohe so lan xe tng ng la: m=1.2. Vay

SE SEmomen momenmg m g 1.2 0.163 0.196Xet cho tai trong lan va tai trong le bo hanh:


44/131



Hnh 4.9:Chat tai trong lan va ngi bo hanh len ban mat cauTa co:

y0=1.5,y1'=1.375 y1=0,625

SEmomen lan Lane

1 1 0,625 1250mg m 1,2 0,156

3000 3000 2;

_1 1 1

(1,375 0,625) 15001500 2

=1

momem PL PL

PLg B

* K h i xep >1 lan xe t ren mat cau: he so lan m se nho hn trong khi yi, i khong oi do vay he so phan bo ngang se nho hn trng hp mot lan

IV.3.2.2He so phan bo cho lc cat:Giong he phan bo ngang cua momen

Bang 2.2: Bang t ong hp h e so phan b o ngang dung t rong tnh toan

mg

Loai dam

Xe tai

thiet ke

Xe 2 truc

thiet ke

Tai trong

lan

Ngi

bo hanh

Dambien

Momen

0.196 0.196 0.156 1

Lccat

0.196 0.196 0.156 1

Damgia

Momen

0.545 0.545 0.545 0


45/131



Lccat

0.721 0.721 0.721 0

I V.4.XC NH NI LC DO HOT TI TI CC MT CT:Kim tra dm ch ti cc mt ct sau:

Ti mt ct gi (I-I): cch gi mt khong L1 = 0

Ti mt ct dm (II-II): cch gi mt khong L2 = 6500 mmTi mt ct mi ni (III-III): cch gi mt khong L3 = 8500 mmTi mt ct lin kt ngang gn mt ct gia dm (IV-IV): cch gi mt khong L4 = 11000 mmTi mt ct gia dm (V-V): cch gi mt khong L5 = 13000 mmI V.4.1.Hot ti tc dng ln dm chnh:

Hot ti tc dng ln dm gm c:0,5xHL93 + Ti trng ngi iTi trng xe 0.5HL93 gm c:

+ Ti trng xe 3 trc v ti trng ln+ Ti trng xe 2 trc v ti trng ln

Xe 3 trc:+ Trc trc: P3 = 0.5 x 35000 = 17500 N+ Trc sau: P1 = P2 = 0.5 x 145000 = 72500 N

Xe 2 trc: P1 = P2 = 0.5 x 110000 = 55000 NTi trng ln: Wln = 9.3 N/mmTi trng ngi i: WPL = 0.003 x 1500 = 4.5 N/mmI V.4.2.Mt ct I-I :

Xt cho xe 3 trc:Xp ti tnh M:

Ti v tr mt ct gi th .a.h.M c gi tr bng 0 nn M3trc = 0Xp ti tnh V:

Hnh 4.10:Cht xe 3 trc ln .a.h.VV tr bt li nht khi xp ti tnh lc ct: xp xe quay u v pha bn phi, trc sau xe t ti

gi triTung : y1 = 1; y2 = 0.835; y3 = 0.669

V3trc = P1.y1 + P2.y2 + P3.y3= 72500 x 1 + 72500 x 0.835 + 17500 x 0.669= 144745 N

Xt cho xe 2 trc:

P1 P2 P3

y1 y2 y3

d.a.h.V

Ltt=26000

+

43004300


46/131



- Xp ti tnh M:Ti v tr mt ct gi th .a.h.M c gi tr bng 0 nn M2trc = 0

- Xp ti tnh V:


gi triTung : y1 = 1; y2 = 0.954

V2trc = P1.y1 + P2.y2 = 55000 x 1 + 55000 x 0.954= 107470 N

Xt cho ti trng ln v ti trng ngi i:- Xp ti tnh M:

Ti v tr mt ct gi th .a.h.M c gi tr bng 0 nn Mln = 0 v MPL = 0Xp ti tnh V:

Hnh 4.12:Cht ti trng ln, ngi b hnh ln .a.h.VTung : y1 = 1

Vln = Wln.V(+) = 9.3 x x 1 x 26000 = 120900 NVPL = WPL.V(+) = 4.5 x x 1 x 26000 = 58500 N

Xep cho ti trng mi:

y1 y2

d.a.h.V

Lt=26000

+

P1 P2

1200

y1

d.a.h.V

Lt=26000

+

Wln

WPL


47/131



Xp ti tnh M:Ti v tr mt ct gi th .a.h.M c gi tr bng 0 nn M3trc = 0

Xp ti tnh V:


gi triTung : y1 = 1; y2 = 0.654; y3 = 0.488

V3trc = P1.y1 + P2.y2 + P3.y3= 72500 x 1 + 72500 x 0.654 + 17500 x 0.488

= 128455 N

I V.4.3.Mt ct II- I I :Xt cho xe 3 trc:Xp ti tnh M:

Hnh 4.14:Cht xe 3 trc ln .a.h.MV tr bt li nht khi xp ti tnh momen: xp xe quay u v pha bn phi, trc sau xe t

cch gi tri mt khong L2 = 6500 mmTung : y1 = 4875 mm; y2 = 3800 mm; y3 = 2725 mm

y1 y2 y3

d.a.h.V

Lt=26000

+

P1 P2 P3

9000 4300

4300 4300

P1 P2 P3

y1 y2 y3

Lt=26000L2 =6500

d.a.h.M


48/131



M3trc = P1.y1 + P2.y2 + P3.y3= 72500 x 4875 + 72500 x 3800 + 17500 x 2725

= 676625000 N.mmXp ti tnh V:

Hnh 4.15:Cht xe 3 trc ln .a.h.VV tr bt li nht khi xp ti tnh lc ct: xp xe quay u v pha bnphi, trc sau xe t gi

tri mt khong L2 = 6500 mmTung : y1 = 0.75; y2 = 0.585; y3 = 0.419

V3trc = P1.y1 + P2.y2 + P3.y3= 72500 x 0.75 + 72500 x 0.585 + 17500 x 0.419

= 104120 N



cch gi tri mt khong L2 = 6500 mmTung : y1 =4875 mm; y2 = 4575 mm

M2trc = P1.y1 + P2.y2 = 55000 x 4875 + 55000 x 4575

y1 y2 y3+

4300 4300

P1 P2 P3

d.a.h.V

Lt=26000

-

L2 =6500

y1 y2

Lt=26000

P1 P2

1200

L2 =6500

d.a.h.M


49/131



= 519750000 N.mmXp ti tnh V:

Hnh 4.17:Cht xe 2 trc ln .a.h.VV tr bt li nht khi xp ti tnh lc ct: xp xe quay u v pha bn phi, trcsau xe t

cch gi tri mt khong L2 = 6500 mmTung : y1 = 0.75; y2 = 0.704

V2trc = P1.y1 + P2.y2 = 55000 x 0.75 + 55000 x 0.704= 79970 N

Xt cho ti trng ln v ti trng ngi i:Xp ti tnh M:

Hnh 4.18:Cht ti trng ln, ngi b hnh ln .a.h.MTung : y1 = 7875 mm

Mln = Wln.M = 9.3 x x 4875 x 26000 = 589387500 N.mmMPL = WPL.M = 4.5 x x 4875 x 26000 = 285187500 N.mm

Xp ti tnh V:

y1 y2+

d.a.h.V

Lt=26000

-

P1 P2

1200

L2 =6500

y1

Lt=26000

Wln

WPL

L2 =6500

d.a.h.M


50/131



Hnh 4.19:Cht ti trng ln, ngi b hng ln .a.h.VTung : y1 = 0.75

Vln = Wln.V(+) = 9.3 x x 0.75 x (260006500) = 68006.25 NVPL = WPL.V(+) = 4.5 x x 0.75 x (260006500) = 32906.25 NXt cho ti trng mi:Xp ti tnh M:

Hnh 4.20:Cht xe 3 trc ln .a.h.MV tr bt li nht khi xp ti tnh momen: xp xe quay u v pha bn tri, trc trc xe t

cch gi tri mt khong L = 2200 mmTung : y1 = 4650 mm; y2 = 4875 mm; y3 = 1650 mm

M3trc = P1.y1 + P2.y2 + P3.y3

= 72500 x 4650 + 72500 x 4875 + 17500 x 1650= 719437500 N.mm

y1+

d.a.h.V

Lt=26000

-

Wln

WPL

L2 =6500

y2y3

4300 9000

y1

Lt=26000

P1P2P3

L2 =6500

d.a.h.M


51/131



Xp ti tnh V:

Hnh 4.21:Cht xe 3 trc ln .a.h.VV tr bt li nht khi xp ti tnh lc ct: xp xe quay u v pha bn phi, trc sau xe t

cch gi mt khong L2 = 6500 mmTung : y1 = 0.75; y2 = 0.404; y3 = 0.238

V3trc = P1.y1 + P2.y2 + P3.y3= 72500 x 0.75 + 72500 x 0.404 + 17500 x 0.238

= 87830 N

I V.4.4.Mt ct III- I I I : Xt cho xe 3 trc:Xp ti tnh M:


cch gi tri mt khong L3 = 8500 mmTung : y1 = 5721.154 mm; y2 = 4315.385 mm; y3 = 2909.615 mm

M3trc = P1.y1 + P2.y2 + P3.y3

y1+

9000 4300

P1 P2 P3

y2 y3

Lt=26000

-

L2 =6500

y2 y3

L3 =8500

4300 4300

P1 P2 P3

y1

Lt=26000

d.a.h.M


52/131



= 72500 x 5721.154 + 72500 x 4315.385 + 17500 x 2909.615= 778567340 N.mm

Xp ti tnh V:

Hnh 4.23:Cht xe 3 trc ln .a.h.VV tr bt li nht khi xp ti tnh lc ct: xp xe quay u v pha bn phi, trc sau xe t gi


V3trc = P1.y1 + P2.y2 + P3.y3= 72500 x 0.673 + 72500 x 0.508 + 17500 x 0.342

= 91607.5 N



cch gi tri mt khong L3 = 8500 mmTung : y1 = 5721.154 mm; y2 = 5328.846 mm

M2trc = P1.y1 + P2.y2 = 55000 x 5721.154 + 55000 x 5328.846

y1+

L3 =8500

4300 4300

P1 P2 P3

y2 y3d.a.h.V

Lt=26000

-

y2

L3 =8500

y1

Lt=26000

P1 P21200

d.a.h.M


53/131



= 607750000 N.mmXp ti tnh V:



V2trc = P1.y1 + P2.y2 = 55000 x 0.673 + 55000 x 0.627= 71500 N


Hnh 4.26:Cht ti trng ln, ngi b hnh ln .a.h.MTung : y1 = 5721.154 mm

Mln = Wln.M = 9.3 x x 5721.154 x26000 = 691687518.6 N.mmMPL = WPL.M = 4.5 x x 5721.154 x26000 = 334687509 N.mm

y1+

L3 =8500

y2

d.a.h.V

Lt=26000

-

P1 P2

1200

L3 =8500

y1

Lt=26000

Wln

WPL

d.a.h.M


54/131



Xp ti tnh V:

Hnh 4.27:

Cht ti trng ln, ngi b hnh ln .a.h.V

Tung : y1 = 0.673Vln = Wln.V(+) = 9.3 x x 0.673 x (260008500) = 54765.38 NVPL = WPL.V(+) = 4.5 x x 0.673 x (260008500) = 26499.38 N

Xt cho ti trng mi:Xp ti tnh M:

Hnh 4.28:Cht xe 3 trc ln .a.h.MV tr bt li nht khi xp ti tnh momen: xp xe quayu v pha bn tri, trc trc xe t

cch gi tri mt khong L =4200 mmTung : y1 = 2778.846 mm; y2 = 5721.154 mm; y3 = 2826.92 mmM3trc = P1.y1 + P2.y2 + P3.y3

= 72500 x 2778.846 + 72500 x 5721.154 + 17500 x 2826.92= 665721100 N.mm

Wln

WPL

y1+

L3 =8500

d.a.h.V

Lt=26000

-

y2y3

4300 9000

L3 =8500

y1

Lt=26000

P1P2P3

d.a.h.M


55/131



Xp ti tnh V:



V3trc = P1.y1 + P2.y2 + P3.y3= 72500 x 0.673+ 72500 x 0.327 + 17500 x 0.162

= 75335 N

I V.4.5.Mt ct IV-IV:Xt cho xe 3 trc:Xp ti tnh M:

Hnh 4.30:Cht xe 3 trc ln .a.h.MV tr bt li nht khi xp ti tnh momen: xp xe quay u v pha bn tri, trc trc xe t

cch gi tri mt khong L = 6700 mmTung : y1 = 4526.923 mm; y2 = 6346.154 mm; y3 = 3865.38 mm

M3trc = P1.y1 + P2.y2 + P3.y3

y1+

9000 4300

P1 P2 P3

L3 =8500

y2 y3

d.a.h.V

Lt=26000

-

L4 =11000

43004300

P2P3 P1

y1

Lt=26000

d.a.h.M

y2y3


56/131



= 72500 x 4526.923+ 72500 x 6346.154 + 17500 x 3865.38= 855942232.5 N.mm

Xp ti tnh V:



V3trc = P1.y1 + P2.y2 + P3.y3= 72500 x 0.577 + 72500 x 0.412 + 17500 x 0.246

= 76007.5 N



cch gi tri mt khong L4 = 11000 mm

L4 =11000

4300 4300

P2 P3P1

y2y3

d.a.h.V

Lt=26000

-

y1 +

L4 =11000

y1

Lt=26000

P1 P2

1200

d.a.h.M

y2


57/131



Tung : y1 = 6346.154 mm; y2 = 5838.462 mmM2trc = P1.y1 + P2.y2 = 55000 x 6346.154 + 55000 x 5838.462

= 670153880 N.mmXp ti tnh V:



V2trc = P1.y1 + P2.y2 = 55000 x 0.577 + 55000 x 0.531= 60940 N


Hnh 4.34:Cht ti trng ln, ngi b hnh ln .a.h.MTung : y1 = 6345.154 mm

Mln = Wln.M = 9.3 x x 6346.154 x 26000 =767250018.6 N.mmMPL = WPL.M = 4.5 x x 6346.154 x 26000 = 371250009 N.mm

L4 =11000

y2

d.a.h.V

Lt=26000

-

P1 P2

1200

y1 +

L4 =11000

y1

Lt=26000

Wln

WPL

d.a.h.M


58/131



Xp ti tnh V:

Hnh 4.35:Cht ti trng ln, ngi b hnh ln .a.h.VTung : y1 = 0.577

Vln = Wln.V(+) = 9.3 x x 0.577 x 2600011000) = 40245.75 NVPL = WPL.V(+) = 4.5 x x 0.577 x (2600011000) = 19473.75 N


Hnh 4.36:Cht xe 3 trc ln .a.h.MV tr bt li nht khi xp ti tnh momen: xp xe quay u v pha bn tri, trc trc xe tcch gi tri mt khong L = 6700 mm

Tung : y1 = 6346.154 mm; y2 = 2538.462 mm; y3 = 3865.38 mmM3trc = P1.y1 + P2.y2 + P3.y3

= 72500 x 6346.154+ 72500 x 2538.462 + 17500 x 3865.38

= 711778810 N.mmXp ti tnh V:

L4 =11000

d.a.h.V

Lt=26000

-

y1 +

Wln

WPL

L4 =11000

y1y2y3

Lt=26000

P1P2P3

d.a.h.M

4300 9000


59/131





V3trc = P1.y1 + P2.y2 + P3.y3= 72500 x 0.577 + 72500 x 0.231 + 17500 x 0.065

= 59717.5 N

I V.4.6.Mt ct V-V:Xt cho xe 3 trc:Xp ti tnh M:


cch gi tri mt khong L = 8700 mmTung : y1 = 4350 mm; y2 = 6500 mm; y3 = 4350 mm

M3trc = P1.y1 + P2.y2 + P3.y3

L4 =11000

d.a.h.V

Lt=26000

-

y1y2 y3+

9000 4300

P1 P2 P3

L5= 13000

4300 4300

P2 P3P1

y1 y2 y3

Lt= 26000

d.a.h.M


60/131



= 72500 x 8350 + 72500 x 6500 + 17500 x 4350= 1152750000 N.mm

Xp ti tnh V:



V3trc = P1.y1 + P2.y2 + P3.y3= 72500 x 0.5 + 72500 x 0.335 + 17500 x 0.169

= 63495 N

Xt cho xe 2 trc:

Xp ti tnh M:

Hnh 4.40:Cht xe 2 trc ln .a.h.M

L5= 13000

4300 4300

P2 P3P1

d.a.h.V

Lt=26000

-

y1 y2 y3+

L5= 13000

y1 y2

Lt= 26000

P1 P2

1200

d.a.h.M


61/131



V tr bt li nht khi xp ti tnh momen: xp xe quay u v pha bn phi, trc sau xe tcch gi tri mt khong L5 = 13000 mm

Tung : y1 = 6500mm; y2 = 5900 mmM2trc = P1.y1 + P2.y2 = 55000 x 6500+ 55000 x 5900

= 682000000 N.mmXp ti tnh V:



V2trc = P1.y1 + P2.y2 = 55000 x 0.5 + 55000 x 0.454=52470 N


Hnh 4.42:Cht ti trng ln, ngi b hnh ln .a.h.M

L5= 13000

+d.a.h.V

Lt= 26000

-

P1 P2

1200

y1 y2

L5= 13000

y1

Lt=26000

Wln

WPL


62/131



Tung : y1 = 6500 mmMln = Wln.M = 9.3 x x 6500 x 26000 = 785850000 N.mmMPL = WPL.M = 4.5 x x 6500 x26000 = 380250000 N.mm

Xp ti tnh V:

Hnh 4.43:Cht ti trng ln, ngi b hnh ln .a.h.VTung : y1 = 0.5

Vln = Wln.V(+) = 9.3 x x 0.5 x (2600013000) =30225 NVPL = WPL.V(+) =4.5 x x 0.5 x (2600013000) = 14625 N



cch gi tri mt khong L = 4000 mm

L5= 13000

+d.a.h.V

Lt= 26000

-

y1

Wln

WPL

L5= 13000

y1y2

Lt= 26000

d.a.h.M

y3

9000 4300

P1 P2 P3


63/131



Tung : y1 = 2000 mm; y2 = 6500 mm; y3 = 4350 mmM3trc = P1.y1 + P2.y2 + P3.y3

= 72500 x 2000 + 72500 x 6500 + 17500 x 4350= 692375000 N.mm

Xp ti tnh V:


cch gi mt khong L5 = 13000 mmTung : y1 = 0.5; y2 = 0.154; y3 = 0

V3trc = P1.y1 + P2.y2 + P3.y3= 72500 x 0.5 + 72500 x 0.154 + 17500 x 0

= 47415Bang 4.3: Bang tong hp noi lc do hoat tai tac dung len dam chu

(cha nhan he so)

Mat cat I-I II-II III-III IV-IV V-V

Xe 3 truc(4300)

M 0 676625000 778567340 855942232.5 1152750000

V 144745 104120 91607.5 76007.5 63495

Xe 3 truc(9000)

M 0 719437500 665721100 711778810 692375000

V 128455 87830 75335 59717.5 47415

Xe 2 trucM 0 519750000 607750000 670153880 682000000

V 107470 79970 71500 60940 52470

LanM 0 589387500 691687518.6 767250018.6 785850000

V 120900 68006.25 54765.38 40245.75 30225

NgiM 0 285187500 334687509 371250009 380250000

V 58500 32906.25 26499.38 19473.75 14625

I V.4.7. Ni lc do hot ti theo trng thi gii hn:

L5= 13000

+ y3d.a.h.V

Lt= 26000

-

y1y2

9000 4300

P1 P2 P3


64/131



Trng hp 1: Xe tai 3 truc + tai trong lan + tai trong ngi i bo

LL 3truc 3truc 3truc lan lan lan bohanh bohanh bohanh


M [ .M .(m.g ).(1 I M) .M .(m.g ) .M .(g )]

V [ .V .(m.g ).(1 I M) .V .(m.g ) .V .(g )]

Trng hp 2: Xe tai 2 truc + tai trong lan + tai trong ngi i bo



M [ .M .(m.g ).(1 I M) .M .(m.g ) .M .(g )]

V [ .V .(m.g ).(1 I M) .V .(m.g ) .V .(g )]

Trong o:+ : He so ieu chnh tai trong.

+ IM: He so xung kch.+ 3truc : He so tai trong hoat tai xe tai 3 truc

+ 2truc : He so tai trong hoat tai xe tai 2 truc

+ lan : He so tai trong hoat tai lan

+ bohanh : He so tai trong hoat tai ngi bo hanh+ m.g: He so phan bo ngang

Bang 4.4: He so , IM, cua c ac trang thai gi han

THGH 3truc 2truc lan bohanh IM

C1 0.95 1.75 1.75 1.75 1.75 0.25C2 0.95 0.00 0.00 0.00 0.00 0.25C3 0.95 1.35 1.35 1.35 1.35 0.25SD 1.00 1.30 1.30 1.30 1.30 0.25M 1.00 0.75 0.00 0.00 0.00 0.15B 1.00 0.50 0.50 0.50 0.50 0.25

Bang 4.5: Bang tong hp momen (M) do hoat t ai t heo trang thai gii h an(Dam bien)


Xe 2truc

C1 0 838682539 983351314 1089151485 1113762948

C2 0 0 0 0 0

C3 0 646983673 758585299 840202574 859188560

SD 0 655811910 768936365 851667326 870912380

M 0 0 0 0 0

B 0 252235350 295744756 327564356 334966300

Xe 3truc

C1 0 902579687 1052927351 1164825403 1305505307C2 0 0 0 0 0

C3 0 696275759 812258242 898579596 1007104094

SD 0 705776598 823341688 910840917 1020846255

M 0 620514844 574184449 613909224 597173438

B 0 271452538 316669880 350323429 392633175


65/131



Bang 4.6: Bang tong hp momen (M) do hoat t ai t heo trang thai gii h an(Dam gia)


Xe 2truc

C1 0 1122679392 1315036478 1454178095 1484447497

C2 0 0 0 0 0

C3 0 866066960 1014456711 1121794530 1145145212

SD 0 877884638 1028299201 1137101668 1160770975

M 0 0 0 0 0

B 0 337647938 395499693 437346795 446450375

Xe 3truc

C1 0 1300352586 1508500460 1664597919 2017608649

C2 0 0 0 0 0

C3 0 1003129137 1163700355 1284118394 1556440958

SD 0 1016817059 1179579307 1301640478 1577678944

M 0 620514844 574184449 613909224 597173438B 0 391083484 453684349 500630953 606799594

Bang 4.7: Bang tong hp lc cat (V ) d o hoat tai theo trang thai gii han(Dam bien)


Xe 2

truc

C1 172385.539 104916.842 87381.464 67634.468 53524.603

C2 0 0 0 0 0

C3 132983.130 80935.850 67408.558 52175.161 41290.408

SD 134797.715 82040.238 68328.363 52887.103 41853.825M 0 0 0 0 0

B 51845.275 31553.938 26280.140 20341.194 16097.625

Xe 3truc

C1 187568.113 114753.439 95571.500 73771.649 58015.223

C2 0 0 0 0 0

C3 144695.401 88524.082 73726.586 56909.558 44754.601

SD 146669.803 89732.013 74732.602 57686.102 45365.288

M 110792.438 75753.375 64976.438 51506.344 40895.438

B 56411.463 34512.313 28743.308 22186.962 17448.188

Bang 4.8: Bang tong hp lc cat (V ) d o hoat tai theo trang thai gii han(Dam gia)


Xe 2 C1 305943.620 201337.842 172775.668 139549.187 114846.851


66/131



truc C2 0 0 0 0 0

C3 236013.650 155317.764 133284.087 107652.230 88596.142

SD 239234.109 157437.109 135102.778 109121.169 89805.056

M 0 0 0 0 0

B 92013.119 60552.734 51962.607 41969.680 34540.406

Xe 3truc

C1 361793.801 237522.466 202903.301 162125.246 131365.918

C2 0 0 0 0 0

C3 279098.075 183231.617 156525.404 125068.047 101339.423

SD 282906.431 185731.853 158661.228 126774.629 102722.222

M 110792.438 75753.375 64976.438 51506.344 40895.438

B 108810.166 71435.328 61023.549 48759.473 39508.547

I V.5.XC NH NI LC DO TNH TI TC DNG LN DM CHNH:I V.5.1. Ti trng tc dng ln dm ch (xt cho 1 mm theo phng dc cu):

- Dm ch:+ Din tch dm ch: As = 34600 mm

2

+ s = 7.85 x 10-5 N/mm3

P1 = 1 x As x s = 1 x 34600 x 7.85 x 10-5 = 2.716 NBn mt cu:

+ Chiu dy: ts = 200 mm+ btng = 2.5 x 10

-5 N/mm3

q1 = 1 x ts x btng = 1 x 200 x 2.5 x 10-5 = 0.005 N/mmBn vt:

+ Din tch phn vt: Avt = bc.th + 2 x x th2 = 280 x 100 + 2 x x 1002

= 38000 mm

2

+ btng = 2.5 x 10-5 N/mm3

P2 = 1 x Avt x btng = 1 x 38000 x 2.5 x 10-5 = 0.95 NLan can: P3= 6.24 N (tnh phn bn mt cu bao gm thanh v ct lan can, tng btng).B va: P4 = 1.5 NL b hnh: P5 = 3.75 NLp ph:

+ Chiu dy lp ph trung bnh: tlp ph = 132mm+ lp ph = 2.3 x 10

-5 N/mm3

q2 = 1 x tlp ph x lp ph = 1 x 132 x 2.3 x 10-5 = 3.036 x 10-3 N/mmTin ch: q3 = 1 N/mmLin kt ngang:

lk

4

tt

g (1670 2 1175 2) 101000

qL

164

1670 2 1175 2 101000

26000

= 0.359 N/mm

Neo: (chn trc): q5 = 0.5 N/mm


67/131



Sn tng cng:

s1 s26

tt

g 38 g 8q

L

281.72 38 296.2 8

26000

= 0.503 N/mm

Mi ni: (chn trc): q7 = 0.5 N/mmI V.5.2. Quy tnh ti tc dng ln dm chnh theo phng dc cu:

Ta c:tt

B 120000.46 0.5

L 26000

Tnh theo phng php nn lch tmI V.5.3. Xc nh ng nh hng v cht tnh ti ca dm chnh theo phng ngang cu:

Xt cho trng hp c 7 dm ch, 6 nhp, c u thaI V.5.3.1.ng nh hng dm bin:

- Tung ng nh hng ca 2 dm bin:

1 i1 2

i

1 i1' 2

i

a .a1 1y

n 2 aa .a1 1

yn 2 a

Trong : n s dm cha1khong cch gia 2 dm binaikhong cch gia 2 dm i xng

Ta c: a1 = 12000 mm; a2 = 8000 mm; a3 = 4000 mm; a4 =0 mm2 2 2 2 6 2

ia 12000 8000 4000 224.10 mm

1 6

1' 6

1 1 12000 12000y 0.464

7 2 224.10

1 1 12000 12000y 0.179

7 2 224.10

Tung ng nh hng ca cc dm gia v u bn hng:


68/131



Hnh 4.46:.a.h theo phng php nn lch tm (dm bin)

Xc nh ti trng tc dng ln dm bin (ti phn b trn 1 mm chiu di dm bin):

Hnh 4.47:Cht tnh ti ln .a.h dm bin+ Ti trng lan can:Ti trng lan can P3= 6.24 N t ti u phn hng

+

lc 0

lc 0 '

y y 0.518

y y 0.233

3 lc 3 lc lcDC P .(y y ) 6.24 (0.518 0.233) 1.78N/mm

+ Ti trng l b hnh:

Ti trng l b hnh 5P 3.75

1.875N2 2

t ti u phn hng v cch u phn hng mt

khong L = 1750 mm

Ni suy ta c:

bh 1 0

bh 2

bh 2

bh 1 0 '

y y 0.518

y 0.424

y 0.139

y y 0.233

5

3 bh bh 1 bh 2 bh 2 bh 1

PDC .(y y y y )

2

3.75(0.518 0.424 0.139 0.233) 1.069N/mm

2

+ Ti trng b va:Ti trng b va P4= 1.5 N t ti v tr cch u phn hng mt khong

L = 1750 mm

Ni suy ta c: bv

bv

y 0.424

y 0.139

3 bv 4 bv bvDC P .(y y ) 1.5 (0.424 0.139) 0.428N/mm

+ Ti trng bn mt cu:


69/131



Ti trng bn mt cu q1 = 0.005 N/mm phnb trn ton b b rng cuDin tch ng nh hng:

0 hng

,

0 ' hng

1 1.y .(x S ) 0.518 (8658 1000) 2501.422mm

2 2

1 1.y .(x S ) ( 0.233) (3341 1000) 505.727mm

2 2

"

2 1DC q .( ) 0.005 (2501.422 505.727) 9.978N/mm

+ Ti trng lp ph:Ti trng lp ph q2 = 3.036 x 10

-3N/mm phn b trn ton b b rng phn xe chy

Din tch ng nh hng:

lp

,

lp

1 1.y .(x 750) 0.424 (8658 750) 1676.496mm

2 2

1 1.y .(x 750) ( 0.139) (3341 750) 180.075mm

2 2

3

2DW q .( ) 3.036 10 (1676.496 180.075) 4.543N/mm

I V.5.3.2.ng nh hng dm gia:- Tung ng nh hng ca 2 dm bin:

1 i1 2

i

1 i1' 2

i

a .a1 1y

n 2 a

a .a1 1y

n 2 a

Trong : n s dm cha1khong cch gia 2 dm binaikhong cch gia 2 dm i xng

Ta c: a1 = 12000 mm; a2 = 8000 mm; a3 = 4000 mm; a4 =0mm2 2 2 2 6 2

ia 12000 8000 4000 224.10 mm

1 6

1' 6

1 1 12000 80000.357

7 2 224.10

1 1 12000 80000.071

7 2 224.10

y

y

Tung ng nh hng ca cc dm gia v u bn hng:


70/131



Hnh 4.48:.a.h theo phng php nn lch tm (dm gia)

Xc nh ti trng tc dng ln dm gia (ti phn b trn 1 mm chiu di dm gia):

Hnh 4.49:Cht tnh ti ln .a.h dm gia

+ Ti trng lan can:Ti trng lan can P3= 6.24 N t ti u phn hng

+

lc 0

lc 0 '

y y 0.393

y y 0.107

3 lc 3 lc lcDC P .(y y ) 6.24 (0.393 0.107) 1.78N/mm

+ Ti trng l b hnh:

Ti trng l b hnh5P 3.75

1.875N2 2 t ti u phn hng v cch u phn hng mtkhong L = 1750 mm

Ni suy ta c:

bh 1 0

bh 2

bh 2

bh 1 0 '

y y 0.393

y 0.33

y 0.107

y y 0.044


71/131



5

3 bh bh 1 bh 2 bh 2 bh 1

PDC .(y y y y )

2

3.75(0.393 0.33 0.044 0.107) 1.073N/mm

2

+ Ti trng b va:

Ti trng b va P4= 1.5 N t ti v tr cch u phn hng mt khongL = 1750 mm

Ni suy ta c: bv

bv

y 0.33

y 0.044

3 bv 4 bv bvDC P .(y y ) 1.5 (0.33 0.044) 0.429N/mm

+ Ti trng bn mt cu:Ti trng bn mt cu q1= 0.005 N/mm phn b trn ton b b rng cuDin tch ng nh hng:

0 hng

,

0 ' hng

1 1.y .(x S ) 0.393 (10009 1000) 2163.269mm

2 2

1 1.y .(x S ) ( 0.107) (1991 1000) 160.019mm

2 2

"

2 1DC q .( ) 0.005 (2163.269 160.019) 10.016N/mm

+ Ti trng lp ph:Ti trng lp ph q2 = 3.036 x 10

-3N/mm phn b trn ton b b rng phn xe chy

Din tch ng nh hng:

lp

,

lp

1 1.y .(x 750) 0.33 (10009 750) 1527.735mm

2 2

1 1.y .(x 750) ( 0.044) (1991 750) 27.302mm

2 2

3

2DW q .( ) 3.036 10 (1527.735 27.302) 4.555N/mm

I V.5.4. Tng hp tnh ti tc dng ln dm ch theo phng dc cu:Da vo qu trnh lm vic ca dm ch ta chia thnh 2 giai on:

Giai on 1: Ti trng bn thn dm ch + phn vt + lin kt ngang + neo + sn tng cng + mi ni+ bn mt cuGiai on 2: Ti trng lp ph + lan can + l b hnh + b va + tin ch cng cng

I V.5.4.1.Dm bin:- Giai on 1:

1 1 2 4 5 6 7

"

2

DC P P q q q q

2.716 0.95 0.359 0.5 0.503 0.5 5.528N/mmDC 9.978N/mm

Giai on 2:DC3 = DC3-lc + DC3-bh + DC3-bv

= 1.78 + 1.069 + 0.428 = 3.277 N/mmDW = DW + q3 = 4.543 + 1 = 5.543 N/mm

I V.5.4.2.Dm gia:- Giai on 1:


72/131


73/131



g "

DC 1 2 M

g "

DC 1 2 V V

M (DC DC ).

(5.528 10.016) 0 0

V (DC DC ).( )

(5.528 10.016) (13000 0) 202072N

Giai on 2:+ Dm bin:

b

DC 3 M

b

DW M

M DC .

3.277 0 0

M DW.

5.543 0 0

b

DC 3 V V

b +

DW V V

V DC .( )

3.277 (13000 0) 42601N

V DW.( )5.543 (13000 0) 72059N

+ Dm gia:g

DC 3 M

g

DW M

g

DC 3 V V

g +

DW V V

M DC .

3.282 0 0

M DW.

5.555 0 0

V DC .( )

3.282 (13000 0) 42666N

V DW.( )

5.555 (13000 0) 72215N

I V.5.5.2.Mt ct II II


74/131



Hnh 4.51:Cht tnh ti ln .a.h.M v .a.h.V

Din tch ng nh hng:

2

M

V

V

63375000mm

7312.5mm

812.5mm

Giai on 1:+ Dm bin:

b "

DC 1 2 M

b "

DC 1 2 V V

M (DC DC ).

(5.528 9.978) 63375000 982692750

V (DC DC ).( )

(5.528 9.978) (7312.5 812.5) 100789N

+ Dm gia:g "

DC 1 2 M

g "

DC 1 2 V V

M (DC DC ).

(5.528 10.016) 63375000 985101000

V (DC DC ).( )

(5.528 10.016) (7312.5 812.5) 101036N

Giai on 2:+ Dm bin:b

DC 3 M

b

DW M

M DC .

3.277 63375000 207679875

M DW.

5.543 63375000 351287625

L2=6500

y'

y

d.a.h.V

Ltt=26000

-

Dw

Dc

d.a.h.M

y" +


75/131



b

DC 3 V V

b +

DW V V

V DC .( )

3.277 (7312.5 812.5) 21300.5N

V DW.( )

5.543 (7312.5 812.5) 36029.5N

+ Dm gia:g

DC 3 M

g

DW M

g

DC 3 V V

g +

DW V V

M DC .

3.282 63375000 207996750

M DW.

5.555 63375000 352048125

V DC .( )

3.282 (7312.5 812.5) 21333N

V DW.( )

5.555 (7312.5 812.5) 36107.5N

I V.5.5.3.Mt ct III III:


Din tch ng nh hng:

2

M

V

V

74375000mm

5889.423mm

1389.423mm

Giai on 1:+ Dm bin:

y'

L3=8500

y

d.a.h.V

Ltt= 26000

-

Dw

Dc

d.a.h.M

y"+


76/131



b "

DC 1 2 M

b "

DC 1 2 V V

M (DC DC ).

(5.528 9.978) 74375000 1153258750

V (DC DC ).( )

(5.528 9.978) (5889.423 1389.423) 69777N

+ Dm gia:g "

DC 1 2 M

g "

DC 1 2 V V

M (DC DC ).

(5.528 10.016) 74375000 1156085000

V (DC DC ).( )

(5.528 10.016) (5889.423 1389.423) 69948N

Giai on 2:+ Dm bin:

b

DC 3 M

bDW M

M DC .

3.277 74375000 243726875

M DW.

5.543 74375000 412260625

b

DC 3 V V

b +

DW V V

V DC .( )

3.277 (5889.423 1389.423) 14746.5N

V DW.( )

5.543 (5889.423 1389.423) 24943.5N

+ Dm gia:g

DC 3 M

g

DW M

g

DC 3 V V

g +

DW V V

M DC .

3.282 74375000 244098750

M DW.

5.555 74375000 413153125

V DC .( )

3.282 (5889.423 1389.423) 14769N

V DW.( )

5.555 (5889.423 1389.423) 24997.5N

I V.5.5.4.Mt ct IV IV:


77/131




Din tch ng nh hng:

2

M

V

V

82500000mm

4326.923mm

232

Documents

Đồ án cầu thép_hoan thanh