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Буди спреман 2014 1 -Студентска организација ЕЛЕКТРОН- Материјал студентске организације Електрон ДРУГА ГЛАВА ИНТЕГРАЛНИ РАЧУН Припремио Немања Нешковић

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Integrali

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  • 2014

    1 - -

  • 2014

    2 - -

    1. () .

    () ( )() = (), - ()

    ().

    () :

    () = () +

    1. :

    ( () + ()) = () + ()

    1. ,

    (), . [, ]

    ()

    .

    .

    .

    2.

    e. Ba :

    () = ()

    () = () +

  • 2014

    3 - -

    ( )

    +

    ++

    +

    +

    +

    +

    +

    +

    || +

    +

    +

    + +

    +

    +

    +

    +

    +

    :

    a) (8 + 4 3 5) e) 2

    2+1

    b) (1 + )3

    f)

    sin2 cos2

    c) (+1)(23)

    3 g) tan2

    d) ()(1+)

    3

    2.1. 2.1.1

    :

    a)

    +=

    +

    = { =

    =

    } =

    +=

    +=

    + =

    +

    b) :

    2+32.

    c)

    =

    (

    )

    = {

    =

    =

    } =

    = + =

    +

    d)

  • 2014

    4 - -

    e)

    ()

    f) :

    =

    |

    + | +

    =

    |

    +

    | +

    g)

    =

    =

    =

    = {

    = =

    } =

    =

    ()(+)=

    { } =

    (

    +) =

    (| | | + |) + =

    |

    +| + =

    |

    +| + =

    |

    +

    | + =

    |

    +

    +

    | + =

    |(

    )| + = |

    | +

    h)

    i) ( ) j) k) ( + )

    l)

    m)

    -

    sin

    sin

    cos

    cos

    n)

    o)

    ---------------------------------------------------------------------------------------------------------------

    :

    2 2 = sin ( = cos ).

    2 + 2 = sinh .

    2 2 = cosh .

    2++

    .

    :

    2 + + = ( +

    2)

    2

    +4 2

    4

    ----------------------------------------------------------------------------------------------------------------

  • 2014

    5 - -

    :

    a) sin1 +

    12

    b) 2 + 2 = { = sinh

    = cosh } = 1 + sinh2 cosh = 2

    cosh2 = 2 1+cosh 2

    2 = 2 (

    2+ sinh 2) +

    c)

    22

    d) ln

    ln ln(ln )

    e)

    1+cos =

    2cos

    2

    2.1.2

    =

    , . .

    :

    a) ln = { = ln

    =1

    | =

    = } = ln

    1

    = ln +

    b) sin1 tan1

    c) 72

    d) sin cos e) (2 + 5 + 6) cos 2

    f) sin1 = { = sin1

    =1

    12| =

    2

    2=

    } =1

    2 2 sin1

    1

    2

    2

    12=

    { = sin

    = cos } =

    1

    2 2 sin1

    1

    2

    sin2 cos

    cos =

    1

    22 sin1

    1

    4(1

    cos 2) =1

    22 sin1

    1

    4 +

    1

    8sin 2 + =

    1

    22 sin1

    1

    4sin1 +

    1

    4

    1 2 + g) tan1

    h) ln( + 1 + 2)

    i) cos

    sin2

    j) sin2

    k) cos2 ln tan2 2

    l) tan

    1

    (1+2)32

    m) sin ln

    2.1.3.

    :

  • 2014

    6 - -

    a)

    (+1)(+2)(+3)

    b)

    (1)2(+1)2

    c)

    3+1

    d)

    2+2+5

    e) 3+1

    352+6 - ,

    .

    f) 10

    2+2

    ----------------------------------------------------------------------------------------------------------------

    2.1.4.

    a) (1

    11 , 2

    22 , 3

    33 , ) , ( = 1,2, . ) ,

    = , = (1, 2, ).

    ,

    :

    a)

    + 3 = {

    = 6

    = 65} =

    65

    3+2

    b) 1+

    1

    3

    c)

    (1+2+ 3

    )

    d) 2+

    3

    + 2+3

    ----------------------------------------------------------------------------------------------------------------

    2.1.5.

    (sin , cos ) =

    tan

    2, : cos =

    12

    1+2, sin =

    2

    1+2.

    :

    a) (tan ) = tan , =1

    1+2

    b) (sin , cos ) (sin , cos ) = (sin , cos ) =

    tan , sin =2

    1+2, cos =

    1

    1+2

    c) (sin , cos ) ( sin , cos )=- (sin , cos ) = cos d) (sin , cos ) (sin , cos ) = (sin , cos ) =

    sin

  • 2014

    7 - -

    :

    1) () = 0

    2) () = ()

    3) (() + ()) = () + ()

    4) [, ] ( [, ]) () = ()

    +

    ()

    :

    a)

    sin2 = {

    = = sin1 } =

    1

    212

    12=

    2(12)

    b) sin2 cos3

    c)

    tan

    d) sin2

    cos3

    e)

    2 sin cos +5

    f)

    cos4 +sin4

    g) sin2

    sin +2 cos

    h)

    sin3

    i) sin cos

    cos4 +sin4

    3.

    1. [, ] .

    2. : - :

    () = () () = () |

    :

    a) (2 2 + 3)2

    1

    b) 1+

    2

    4

    1

    c) sin(ln )

    1

    d) tan

    4

    4

    e) sin 5

    60

    = sin !!!

  • 2014

    8 - -

    :

    1. () = ( )

    0

    0

    2. [, ]

    () = 2 ()

    0

    3. [, ] :

    () = 0

    f) ln(1+)

    1+2 = {

    = tan = tan1

    =

    1+2} = ln(1 + tan ) = ln(1 +

    40

    40

    1

    0

    tan(

    4 )) = ln (1 +

    1tan

    1+tan ) = ln

    2

    1+tan = (ln 2 ln(1 + tan ) =

    40

    40

    40

    4ln 2

    2 =

    4ln 2 =

    8ln 2

    g) sin

    20

    h) sin1 2

    0

    4.

    :

    () = lim

    ()

    () = lim

    ()

    ()

    = lim

    ()

    :

    a)

    2= lim

    2= lim

    (

    1

    |1

    ) = lim

    (1

    ) + 1 = 1

    1

    1

    b)

    1

    c)

    1

    0

    d)

    ln

    2

    1

    e)

    1+2

    f) tan1

    (1+)2

    0

  • 2014

    9 - -

    5.

    = (), :

    1 + 2()

    :

    ()

    :

    |()|

    2 () () :

    (() ())

    = () - . :

    = 2 ()1 + 2()

    :

    = 2()