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MAE 653-1 Advanced Vibration Spring 2010 Lesson #5  Tuesday, Jan. 26, 2010  Textbook Sections 2.7 FREE VIBRATON WITH NON-VISCOUS DAMPING Hermann E. Alcazar

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  • MAE 653-1 Advanced VibrationSpring 2010

    Lesson #5 Tuesday, Jan. 26, 2010Textbook Sections 2.7

    FREE VIBRATON WITH NON-VISCOUS DAMPINGHermann E. Alcazar

    5. Free vibration with non-viscous dampingMAE 653 - Advanced Vibrations/Fall 2010

    2.7 Free vibration with Coulomb damping. Mathematical background.In general a second-order nonhomogeneous linear differential equation with constant coefficients has the form,where a, b, and c are constants and G is a continuous function. Its related homogeneous equation is,The general solution of the nonhomogeneous differential equation can be written as,

    where xh is the general solution of the homogeneous equation and xp is a particular solution.. The particular solution can be found using the method of undetermined coefficients or the method of variation of parameters. In the method of undetermined coefficients the shape of the particular solution is assumed, and its coefficients are obtained after replacing into the differential equation.If G(x)=ekx P(x), where P is a polynomial of degree n, try yp(x)=ekx Q(x), where Q is a n-degree polynomial.If G(x)=ekx P(x) cos mx or G(x)=ekx P(x) sin mx, where P, Q, and R are n-degree polynomials, try yp(x)=ekx Q(x) cos mx + ekx R(x) sin mx.If any term of yp is a solution of the homogeneous equation, multiply yp by x (or by x2 if necessary)

    5. Free vibration with non-viscous dampingMAE 653 - Advanced Vibrations/Fall 2010

    2.7 Free vibration with Coulomb damping. Equation of motionCoulombs law or dry friction states that, when two bodies are in contact, the force required to produce sliding is proportional to the normal force acting in the plane of contact.Case 1:Case 2:Finally:

    5. Free vibration with non-viscous dampingMAE 653 - Advanced Vibrations/Fall 2010

    2.7 Free vibration with Coulomb damping. Solution (1)If a cosine function is considered as the solution, for an initial zero velocity, thenThe amplitudes after the first half cycles are (x0-2xd).In each cycle, the amplitude reduces in 4N/kMotion will stop at the end of the r-th half cycle, when the force exerted by the spring (kx) is less than the friction force (N). The amplitude falls into de dead zone.

    5. Free vibration with non-viscous dampingMAE 653 - Advanced Vibrations/Fall 2010

    2.7 Free vibration with Coulomb damping. Solution (2)For an initial zero velocity, then

    5. Free vibration with non-viscous dampingMAE 653 - Advanced Vibrations/Fall 2010

    Homework # 2Due, Thursday February 04, 2010

    Solve the following problems from the textbook Mechanical Vibrations by Rao: 2.46-2.47 Figure 2.75 2.62 2.74 2.96 2.100 Figure 2.95. Plot the solution (in a single graph, tag all characteristic values) considering m=4 kg, k=1250 N/m, x0=100 mm, and v0=-10 m/s for each of the following cases: (a) c = 0 (b) c = 100 N-s/m (c) c = 200 N-s/m (d) c = 400 N-s/m 2.121Plot the solution (tag all characteristic values). Determine the number of cycles of motion and the final static position. Include the used Matlab code.

    5. Free vibration with non-viscous dampingMAE 653 - Advanced Vibrations/Fall 2010

    Project: Build, test, acquire and analyze data from an experiment at the vibrations laboratory. The topic is open and will be defined by the group in coordination with Dr. Mourad Riad or Mr. Yan Luo. Groups of 2 (3 only depending on the complexity of the proposed experiment).Abstract, due Thursday February 11. In the format of research papers.Presentation, dead week at the vibrations laboratory.Report, after the presentation. In the format of research papers.Take-home questions: The questions for the midterm and final exams will use the concepts of vibration criteria, balancing of rotating machines, critical speed on shafts, balancing of reciprocating engines, vibration isolation, and vibration absorbers (Ch. 9). The knowledge of these topics are your responsibility.

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