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tH 3.08627 1017× sec:=tH 3.086 1017× sec=
Rgsv tH c⋅:=
Ovde sam pokusao da pronadjem tacne cifre magicnih brojeva sa Vajnbergove skale.Moja istrazivanja su dovela do zakljucka da su magicni brojevi samo koeficijenti srazmernosti izmedju clanova na skali.Kad je rec o koincidenciji velikih brojeva to,cini se, nema neko dublje znacenje. Rec je ,naime, samo o blizini clanova na skali.Sve su to razliciti brojevi kad vodimo racuna o tacnosti.
n 1.591 1021×:=
Hablovo vreme
tH37987220447284.3450480
gm π G⋅⋅( )313⋅ gm π⋅ G⋅ cm⋅( )
1
2⋅ cm⋅:=
1
Msv a02⋅
Msv Md⋅ a0⋅ Rgsv⋅( )1
2⋅ te⋅ Rgsv⋅
tH31=
tH3 3.086 1017× sec=
Veliki magicni brojevi su kolicnici energije svemira i energija sa kvantnim brojevima 10^n gde je n=od 10 do 40 u deseticama.
n11 2.704 1083×:=
n10 1.352 1083×:=
n9 8.111 1082×:=
n8 1.351 1083×:=
n7 4.054 1082×:=
n6 2.703 1082×:=
n5 1.351 1082×:=
n4 8.109 1081×:=
n3 4.054 1081×:=
n2 2.703 1081×:=
n1 1.351 1081×:=8.109 1092× K
Temperatura svemira.Koeficijenti proporcionalnosti na Vajnbergovoj skali iz knjige "Gravitacija i kosmologija" na ruskom,str.577 Tablica 15.4
tH31−( )2 4
3π⋅ G⋅ ρsv4⋅− 0
1sec2
=
ρsv43
4 tH32 π G⋅⋅⋅( )
:=
tH31−( )2
1.05 10 35−×1
sec2=
n12 8.111 1083×:=
n13 2.704 1084×:=
n14 8.111 1084×:=
n15 8.111 1085×:=
n16 8.111 1086×:=
n17 8.111 1087×:=
n18 8.111 1088×:=
n19 2.028 1089×:=
tH31−( )2 8
3π⋅ G⋅ ρsv4⋅− Rgsv− Rgsv⋅⋅
Msvkb n1⋅
⋅ 6.004 1011× K=
tH31−( )( )2 8
3π⋅ G⋅ ρsv4⋅− Rgsv
2−⋅Msv
kb n2⋅⋅ 3.001 1011× K=
tH31−( )( )2 8
3π⋅ G⋅ ρsv4⋅− Rgsv
2−⋅Msv
kb n3⋅⋅ 2.001 1011× K=
tH31−( )( )2 8
3π⋅ G⋅ ρsv4⋅− Rgsv
2−⋅Msv
kb n4⋅⋅ 1 1011× K=
tH31−( )( )2 8
3π⋅ G⋅ ρsv4⋅− Rgsv
2−⋅Msv
kb n5⋅⋅ 6.004 1010× K=
tH31−( )( )2 8
3π⋅ G⋅ ρsv4⋅− Rgsv
2−⋅Msv
kb n6⋅⋅ 3.001 1010× K=
tH31−( )( )2 8
3π⋅ G⋅ ρsv4⋅− Rgsv
2−⋅Msv
kb n7⋅⋅ 2.001 1010× K=
tH31−( )( )2 8
3π⋅ G⋅ ρsv4⋅− Rgsv
2−⋅Msv
kb n8⋅⋅ 6.004 109× K=
tH31−( )( )2 8
3π⋅ G⋅ ρsv4⋅− Rgsv
2−⋅Msv
kb n9⋅⋅
1 1010× K=
a 2 10..:=
tH31−( )( )2 8
3π⋅ G⋅ ρsv4⋅− Rgsv
2−⋅Msv
n10 kb⋅⋅ 5.999 109× K=
tH31−( )( )2 8
3π⋅ G⋅ ρsv4⋅− Rgsv
2−⋅Msv
kb n11⋅⋅ 3 109× K=
tH31−( )( )2 8
3π⋅ G⋅ ρsv4⋅− Rgsv
2−⋅Msv
kb n12⋅⋅ 1 109× K=
tH31−( )( )2 8
3π⋅ G⋅ ρsv4⋅− Rgsv
2−⋅Msv
kb n13⋅⋅ 3 108× K=
tH31−( )( )2 8
3π⋅ G⋅ ρsv4⋅− Rgsv
2−⋅Msv
kb n14⋅⋅ 1 108× K=
tH31−( )( )2 8
3π⋅ G⋅ ρsv4⋅− Rgsv
2−⋅Msv
kb n15⋅⋅ 1 107× K=
tH31−( )( )2 8
3π⋅ G⋅ ρsv4⋅− Rgsv
2−⋅Msv
kb n16⋅⋅ 1 106× K=
tH31−( )( )2 8
3π⋅ G⋅ ρsv4⋅− Rgsv
2−⋅Msv
kb n17⋅⋅ 1 105× K=
tH31−( )( )2 8
3π⋅ G⋅ ρsv4⋅− Rgsv
2−⋅Msv
kb n18⋅⋅ 1 104× K=
Iz skalarne Fridmanove jednacine kosmosa izracunati energije vodonika, to jest mini-crne rupe sa masom Md (a to je identicno).
tHHa0
c α⋅:= avo 1 12..:=nvod 5.137− 1087×:=ρH 3
Md4 π⋅ a0
3⋅⋅:=
2.
tHH1−( )( )2 8
3π⋅ G⋅ ρH⋅−
a02.− me⋅
2⋅ 13.607 eV=
13.60636
0.378=
tH31−( )( )2 8
3π⋅ G⋅ ρsv4⋅− Rgsv
2Msv
nvod avo2⋅
⋅
⋅
13.6063.4021.512
0.850.5440.3780.2780.2130.1680.1360.1120.094
eV
=
EnHH tHH1−( )( )2 8
3π⋅ G⋅ ρH⋅−
a02.− me⋅
2⋅:=
EnH tH31−( )( )2 8
3π⋅ G⋅ ρsv4⋅− Rgsv
2 Msv⋅( )⋅:=
Koeficijent proporcionalnostiEnHEnHH
5.137− 1087×=
R0 3.061 1018× cm:= a 1 8..:= r1 1.758 1016× cm:=
tH31−( )( )2 8
3π⋅ G⋅ ρsv4⋅− Rgsv
2Msvnvod
⋅
⋅ tH31−( )( )2 8
3π⋅ G⋅ ρsv4⋅− Rgsv
2⋅Msv
avo nvod⋅⋅−
06.8039.071
10.20510.88511.33911.66311.90612.09512.24612.36912.473
eV
=
akvant 1 8..:=a0 4⋅
c α⋅9.676 10 17−× sec=
tvoda
a0 a⋅
c α⋅:=
tvoda2.419·10 -17
4.838·10 -17
7.257·10 -17
9.676·10 -17
1.209·10 -16
1.451·10 -16
1.693·10 -16
1.935·10 -16
sec
= nt 1.276 1034×:=
tH31−( )( )2 8
3π⋅ G⋅ ρsv4⋅−
1−1−⋅ akvant⋅
nt2.419·10 -17
4.837·10 -17
7.256·10 -17
9.675·10 -17
1.209·10 -16
1.451·10 -16
1.693·10 -16
1.935·10 -16
sec
=
9.675 10 17−⋅ sec⋅ 2.419 10 17−⋅ sec⋅−( ) 1−
2
a02 me⋅( )⋅ 3.024eV=
tH31−( )( )2 8
3π⋅ G⋅ ρsv4⋅−
1−1−⋅
nt4⋅
2
1−
a02⋅ me⋅ 2⋅ 3.402eV=
3tH3
2
3− 8 π⋅ G⋅ ρsv4⋅ tH32⋅+( )
1
2
⋅ 3.086 1017× sec=
3tH3
2
3− 8 π⋅ G⋅ ρsv4⋅ tH32⋅+( )
1
2⋅ 3.086 1017× sec=
nmkr 3.004 1092×:=amkr 1 14..:=
tH31−( )( )2 8
3π⋅ G⋅ ρsv4⋅− Rgsv
2−⋅ Msv
nmkr amkr2⋅ kb⋅
⋅
2.70.675
0.30.1690.1080.0750.0550.0420.0330.0270.022
K
=
0.0220.0190.0160.014
tH31−( )( )2 8
3π⋅ G⋅ ρsv4⋅−
Rgsv2− Msv⋅
nmkr kb⋅⋅ 2.7 K=
2.32710 4− eV⋅
kb2.7 K=
nmkr1 8.111 1092×:=
tH31−( )( )2 8
3π⋅ G⋅ ρsv4⋅−
Rgsv2− Msv⋅
nmkr1 kb⋅⋅ 1 K=
8 111 1092
nnaj 8.111 1092×:=
tH31−( )( )2 8
3π⋅ G⋅ ρsv4⋅−
Rgsv2− Msv⋅
nnaj kb⋅⋅ 1 K=
nsunce 6.264 1022×:=
tH31−( )( )2 8
3π⋅ G⋅ ρsv4⋅−
Rgsv2− Msv⋅
nsunce kb⋅⋅ 1.295 1070× K=
nzemlja 2.085 1028×:=
tH31−( )( )2 8
3π⋅ G⋅ ρsv4⋅−
Rgsv2− Msv⋅
nzemlja kb⋅⋅ 3.89 1064× K=
tH31−( )( )2 8
3π⋅ G⋅ ρsv4⋅−
Rgsv2− Msv⋅
nzemlja⋅ 5.371 1048× erg=
Svemirska skala vremena
23
8 π⋅ G⋅⋅
1
ρsv4⋅
3.086 1017× sec=
avodonik 1.276 1034×:=
aV 1 8..:=
a0 4⋅
cα⋅2
2.419 10 17−× sec( )8=
( )
nV 1.804 1034×:=
2.419 10 17−× sec( )( ) 9⋅ 2.177 10 16−× sec=
Nize je postignuta potpuna analogija sa Vajnbergovom jednacinom
2 aV2⋅
nV
3
4 π⋅ G⋅⋅
1
ρsv4⋅
2 1⋅nV
3
4 π⋅ G⋅⋅
1
ρsv4⋅−
07.258·10 -17
1.936·10 -16
3.629·10 -16
5.807·10 -16
8.468·10 -16
1.161·10 -15
1.524·10 -15
sec
=a0
c α⋅aV
2⋅a0
c α⋅−
07.257·10 -17
1.935·10 -16
3.628·10 -16
5.805·10 -16
8.466·10 -16
1.161·10 -15
1.524·10 -15
sec
=
12
2⋅ 3⋅
1
π G⋅( ) 1
2
β ρsv4
1
2⋅ ⋅ =
β
14
2⋅ 6⋅
1
π G⋅( ) 1
2
β ρsv4
1
2⋅ ⋅ =
β
14
2⋅ 6⋅1
π G⋅( ) 1
2⋅ c⋅
α
a0 ρsv4
1
2⋅ ⋅ 1.276 1034×=
1
14
2⋅ 6⋅1
π G⋅( ) 1
2⋅ c⋅
α
a0 ρsv4
1
2⋅ ⋅ 1.276 1034×=
tvoda0
c α⋅( ):=a 1 8..:= nρ 20 30..:=
n 1.591 1021×=ρvod3
4 π⋅ G⋅ tvod( )2⋅:=
ρsv4 3.756 10 29−×gm
cm3=
3 Md⋅
4 π⋅ a0 a2⋅( )3⋅
6.115·10 39
9.554·10 37
8.388·10 36
1.493·10 36
3.914·10 35
1.311·10 35
5.198·10 34
2.333·10 34
gm
cm3
= ρvod 6.114 1039×gm
cm3=
a 1 8..:=n 3.737 1033×:=
a0c α⋅
an
3
8 π⋅ G⋅1
ρsv4 ⋅
2
n3
8 π⋅ G⋅1
ρsv4 ⋅
−
-5.84·10 -17
017
sec
= tvoda
a0 a⋅
c α⋅:=
tvoda2.419·10 -17 sec
=
5.84·10 -17
1.168·10 -16
1.752·10 -16
2.336·10 -16
2.92·10 -16
3.504·10 -16
2.419 10 4.838·10 -17
7.257·10 -17
9.676·10 -17
1.209·10 -16
1.451·10 -16
1.693·10 -16
1.935·10 -16
2
7.257 10 17−⋅ 2.419 10 17−⋅− 4.838 10 17−×=2.419 10 17−⋅4.838 10 17−⋅
0.5=
a2.419 10 17−⋅ sec⋅
3
8 π⋅ G⋅2
ρsv4
1
ρsv4−
⋅ 3.737·10 33
7.474·10 33
1.121·10 34
1.495·10 34
1.868·10 34
2.242·10 34
2.616·10 34
2.989·10 34
=
14
6⋅1
π G⋅( ) 1
2⋅ 2 1−( )⋅ c⋅
α
a0 ρsv4
1
2⋅ ⋅ 3.737 1033×=
3
8 π⋅ G⋅
n19
ρsv4
⋅ 1.402 1099× yr=
a0 4⋅
c α⋅ 1.935 10 16−× sec=
a0c α⋅
a0 2⋅
c α⋅( )− 2.419− 10 17−× sec=
2 ( )
1
ρvod( )3
8 π⋅ G⋅⋅ 1.71 10 17−× sec=
a1 1 8..:=
1
ρvod
3
4 π⋅ G⋅⋅
1
ρvod( )3
8 π⋅ G⋅⋅
1
a1⋅−
7.085·10 -18
1.209·10 -17
1.431·10 -17
1.564·10 -17
1.654·10 -17
1.721·10 -17
1.772·10 -17
1.814·10 -17
sec
=
1
ρvod( )3
8 π⋅ G⋅⋅ 1.71 10 17−× sec=
a0c α⋅
a0
c α⋅ 2⋅ a1⋅−
7.085·10 -18
1.209·10 -17
1.431·10 -17
1.564·10 -17
1.654·10 -17
1.721·10 -17
1.772·10 -17
1.814·10 -17
sec
=
2 a1⋅( )2
2468
10121416
=
a0c α⋅ 2⋅
1.71 10 17−× sec=
1
ρvod( )3
4 π⋅ G⋅⋅ 2.419 10 17−× sec=
ρvod 6.114 1039×gm
cm3= ρvod 6.114 1039×
gm
cm3=
23
8 π⋅ G⋅⋅
1
ρsv4⋅
23
8 π⋅ G⋅1
ρsv4⋅− 0 sec=
Ovo je za me*c^2
ne 1.367 1083×:=
ne2 5.136 1087×:=
Negde oko mikrotalasne temperature
tH31−( )( )2 8
3π⋅ G⋅ ρsv4⋅− Rgsv
2−⋅Msv
ne2 m2⋅ h⋅⋅
3.291 1011×1
cm2sec=
ne3 1080:= c α⋅
a0 2⋅ m2⋅2.067 1012×
cm=
tH31−( )2 8
3π⋅ G⋅ ρsv4⋅− Rgsv
2−⋅Msv
ne3 m2⋅ kb⋅⋅ 8.111 108×
K
cm2=
tH31−( )2 8
3π⋅ G⋅ ρsv4⋅− Rgsv
2−⋅Msv
kb 8.109 1012× K( )⋅⋅ 1 1080×=
me c2⋅
kb5.93 109× K=kb 5.93 109× K( )⋅ 5.11 105× eV=
ndejstvo 3.276 10121×:=
tH1−( )( )2 8
3π⋅ G⋅ ρsv1⋅−
Rgsv2−
nα⋅ c2= Rgsv
re3.283 1040×=
tH31−( )( )2 8
3π⋅ G⋅ ρsv4⋅− Rgsv
2−⋅ 8.988 1020×cm2
sec2=
8 2 G MRgsv
2
5 137 1087
43
π⋅ G⋅ ρsv4( )⋅ Msv⋅ Rgsv2⋅
nnovo313.606 eV=
nnovo3 5.137 1087×:=
83
π⋅ G⋅ ρsv1( )⋅ Msv⋅ Rgsv2⋅
nnovo22.181 10 11−× erg=
ω cα
a0 2⋅⋅:=
nnovo2nMd
3.128 1047×=
Md c2⋅ 2⋅ 6.823 1036× erg=nnovo2 1.027 1088×:=
83
π⋅ G⋅ ρsv1( )⋅ Msv⋅ Rgsv2⋅
nMd c2⋅
7.591 1015× gm=
el2
RgsvnMd
8.186 10 7−× erg=1.12 1077× erg
Md 3.796 1015× gm=43
π⋅ G⋅ ρsv1( )⋅Msv Rgsv
2⋅
nMd c2⋅⋅
3.795 1015× gm=
ωc α⋅re
:=
Rgsvre
3.283 1040×=nMd 3.283 1040×:=
Veliki magicni brojevi povezuju gravitaciju , elektromagnetizam ,kvantnu mehaniku i kvantnu elektrodinamiku
tH31−( )( )2 4
3π⋅ G⋅ ρsv4( )⋅− Rgsv
2⋅ Msv⋅ 0 erg=
tH31−( )( )2 4
3π⋅ G⋅ ρsv4( )⋅− 0
1sec2
=ρsv1
3
4 π G tH2⋅⋅⋅( )
:=
sec
3π2⋅ G⋅ ρsv1⋅ Msv⋅
ω h⋅( )⋅ 5.137 1087×=
83
π⋅ G⋅ ρsv4⋅ Msv⋅Rgsv
2
ω h⋅( )⋅ 1.635 1087×=
1.12 1077⋅ erg⋅ 1.221 106⋅( )⋅ 1.368 1083× erg= me c2⋅( ) 1−1.221 106×
sec2
gmcm2=
Msv c2⋅
tH1−( )( )2 8
3π⋅ G⋅ ρsv4⋅− 1−⋅ Rgsv
2⋅ Msv⋅
n2
1.396 1067×=
n 1020:=
Msv c2⋅
tH1−( )( )2 8
3π⋅ G⋅ ρsv4⋅− 1−⋅ Rgsv
2⋅ Msv⋅
n2
10 1039×=
n 1030:=
Msv c2⋅
1=
tH1−( )( )2 8
3π⋅ G⋅ ρsv4⋅− 1−⋅ Rgsv
2⋅ Msv⋅ 1
Rgsvre
3.283 1040×=
n 1040:=
Md c2⋅ 3.411 1036× erg=tH1−( )( )2 8
3π⋅ G⋅ ρsv4⋅− 1−⋅ Rgsv
2⋅ Msv⋅ Rgsv
re
2
kb⋅
7.524 1011× K=
13
3− 8 π⋅ G⋅ ρsv4⋅ tH2⋅+( )⋅ Msv⋅
re2
tH2 kb⋅( )
⋅ 7.524 1011× K=
Ovo su bili samo zaokrugljeni stepeni .U stvari postoji onoliko velikih magicnih brojeva koliko je veliki niz. Oni se sve vise smanjuju i prelaze u male brojeve da bi porasle do velikih negativnih .
n 1039:=
Msv c2⋅
tH1−( )( )2 8
3π⋅ G⋅ ρsv4⋅− 1−⋅ Rgsv
2⋅ Msv⋅
n2
10 1077×=
n 1038:=
Msv c2⋅
tH1−( )( )2 8
3π⋅ G⋅ ρsv4⋅− 1−⋅ Rgsv
2⋅ Msv⋅
n2
10 1075×=
n 1:=
Msv c2⋅
tH1−( )( )2 8
3π⋅ G⋅ ρsv4⋅− 1−⋅ Rgsv
2⋅ Msv⋅
n2
1=
n 2:=
Msv c2⋅ a0⋅
tH1−( )( )2 8
3π⋅ G⋅ ρsv4⋅− 1−⋅ Rgsv
2⋅ Msv⋅
n2
2.117 10 8−× cm=
3 Md⋅
4 π⋅ 4 a0⋅( )3⋅9.554 1037×
gm
cm3=
3 Md⋅
Msv c2⋅ a0⋅
tH1−( )( )2 8
3π⋅ G⋅ ρsv4⋅− 1−⋅ Rgsv
2⋅ Msv⋅
n2
3
4⋅ π⋅
9.555 1037×gm
cm3=
tH1−( )( )2 8
3π⋅ G⋅ ρsv4⋅− 1−⋅ Rgsv
2⋅ Msv⋅
kb 8.109 1080×( )⋅1 1012× K=
tH1−
2 8
3π⋅ G⋅ ρsv4⋅− 1−⋅ Rgsv
2⋅ Msv⋅
kb
tH1−
2 8
3π⋅ G⋅ ρsv4⋅− 1−⋅ Rgsv
2⋅ Msv⋅
kb 1012K( )⋅
n5 1011× K=
1012K 1 1012× K=Ovo je temperatura prva po redu na Vajnbergovoj skali istorije svemira.Pre ove temperature Vajnberg analizira najraniji svemir.
n 1 8..:=
8.109 1092× K8.109 1080×=
1012K8.109 10×
8.109 1092× K
1 1052× K8.109 1040×=
1.688 1023K1 103× K
1.688 1020×=
1.688 1022K1 102× K
1.688 1020×=
me c2⋅
kb5.93 109× K=
1.688 1010K1 10 10−× K
1.688 1020×=
1.688 109K1 10 11−× K
1.688 1020×=
Msv c2⋅
kb
1.368 1083K( )5.929 109×=
1.671 108× cm
9.899 10 13−× cm1.688 1020×=
1.671 108× cm
re5.93 1020×=
Ja cu sada da nadjem neke clanove u nizu temperaturne istorije svemira od temperature 5..725*10^12 do 2.7K na Vajnbergovoj skali, to jest od trenutka anihilacije parova µ+µ- do trenutka iskljucenja interakcije izmedu materije i zracenja
Msv 1.246 1056× gm= n 1 8..:=
Rgsv 9.252 1027× cm=
ρsv4 3.756 10 29−×gm
cm3= Msv c2⋅
kb8.111 1092× K=
tH31−( )2 8
3π⋅ G⋅ ρsv4⋅−
Rgsv2 Msv⋅
kb⋅ 8.111− 1092× K=
tH31−( )2 8
3π⋅ G⋅ ρsv4⋅− Rgsv
2⋅ Msv⋅
kb n⋅
-8.111·10 92
-4.056·10 92
-2.704·10 92
-2.028·10 92
-1.622·10 92
-1.352·10 92
-1.159·10 92
-1.014·10 92
K
=
M
1.−
tH2
83
π⋅ G⋅ ρsv4⋅+ Rgsv
2⋅Msvkb( )⋅
0.836 n70⋅9.702·10 92
8.218·10 71
3.876·10 59
6.961·10 50
1.145·10 44
3.283·10 38
6.761·10 33
5.896·10 29
K
=
A sada energija :
tH1−( )( )2 8
3π⋅ G⋅ ρsv4⋅− 1−⋅ Rgsv
2⋅ Msv⋅ 1.12 1077× erg=
tH1−( )( )2 8
3π⋅ G⋅ ρsv4⋅− 1−⋅ Rgsv
2⋅ Msv⋅
n89 c2⋅1.246·10 56
2.013·10 29
gm
=
4.283·10 13
325.2267.712·10 -7
6.919·10 -14
7.617·10 -20
5.254·10 -25
A sada vreme :
tH1−( )( )2 8
3π⋅ G⋅ ρsv4⋅− 1−⋅
n89 0.359 1−⋅
1−
5.151·10 17
1.281·10 31
8.786·10 38
3.188·10 44
6.547·10 48
2.186·10 52
2.083·10 55
7.932·10 57
sec
=
5.253 10 25−⋅ gm⋅ c2⋅h
1−
4.447 10 31−× yr=
mµ c2⋅
h
1−
1.24 10 30−× yr=
Masa muona
mµ( ) 1.884 10 25−× gm=
h 6.626 10 27−×gmcm2
sec=
1.241 1015⋅ K103
1.241 1012× K=
2
h1 6.626 10 27−× gmcm2
sec≡
c2 re⋅ 2.533 108×cm3
sec2=
hh1
2 π⋅≡
h c5⋅G
1.221 1028× eV=
h 1.055 10 27−×gmcm2
sec=
Ekr 1.221 1028× eV⋅:=
G mp2⋅
h1 c⋅9.398 10 40−×=
αgG mp
2⋅
h1 c⋅:=
RgsvLPl
2.284 1060×=
1.4 1032⋅ K 8.738 1043×sec2K
gmcm2eV=
v0 4.092 1011×cm2
sec2:=
R0 2.7 K⋅ kb( )⋅ 1− el2⋅
23
⋅:=
reR0
6.83 10 10−×=
el2
R0
R0
v02
1.366 10 27−× gm=
Mikrotalasno zracenje me c2( )⋅
n2 kb⋅
me v02⋅
n2 kb⋅
2.196·10 9
2.196·10 9
2.196·10 9
2.196·10 9
2.196·10 9
2.196·10 9
2.196·10 9
2.196·10 9
=me c2 α2⋅( )⋅
n2 kb⋅
3.158·10 5
7.894·10 4
3.509·10 4
1.974·10 4
1.263·10 4
8.771·10 3
6.444·10 3
4.934·10 3
K
=me v02⋅
n2 kb⋅
2.70.675
0.30.1690.1080.0750.0550.042
K
=
nah 6.166 1044×:=
α0v0
2
c2:=
tH31−( )2 8
3π⋅ G⋅ ρsv4⋅−
1−c2⋅ 1−⋅
nah re⋅
5.325 10 5−×=
h c2tH3
2
3− 8 π⋅ G⋅ ρsv4⋅ tH32⋅+( )
⋅
1
2⋅
3
re2 me c α⋅⋅⋅( )
⋅ 6.166 1044×=
h 1.055 10 27−×gmcm2
sec=
3 c2tH3
2
3− 8 π⋅ G⋅ ρsv4⋅ tH32⋅+( )
⋅
1
2⋅
a0
re2
⋅ 6.166 1044×=
MsvMd
3.283 1040×=
1−3
3− 8 π⋅ G⋅ ρsv4⋅ tH32⋅+( )⋅
Rgsv2
c2 tH32⋅( )
⋅ 1−=
BASIC SCIENCE REFERENCES
Fundamental Physical Constants
Universal Constants
c 299792458msec
⋅≡
Velocity of light in vacuum
tere 2⋅ π⋅
c≡
re
µ0 4 π⋅ 10 7−⋅newton
amp2⋅≡
Permeability of vacuum
ε0 8.854187817 10 12−⋅farad
m⋅≡
Permittivity of vacuum
G 6.67259 10 11−⋅m3
kg sec2⋅⋅≡
Nuclear magneton
5.0507866 10 27−⋅joule
stattesla⋅
MBor 9.274 10 24−×joule
stattesla=
Bohr magneton
MBor 9.2740154 10 24−⋅joule
stattesla⋅≡
Magnetic flux quantum
Φ0 2.068 10 15−×=
Φ0 2.06783461 10 15−⋅≡
Elementary chargeel 1.60217733 10 19−⋅ coul⋅≡
Electromagnetic Constants
Planck's constant (h)
RgsG Ms⋅
c2≡
h 6.6260755 10 34−⋅ joule⋅ sec⋅≡
Ms 1.989 1033× gm≡
Newtonian constant of gravitation
G 6.6726 10 8−×cm3
gmsec2=
eV 1.60217733 10 19−⋅ joule⋅≡
2.42631058 10 12−⋅ m⋅
Electron Compton wavelength
1.75881962− 1011⋅coulkg
⋅
Electron specific charge (electron charge to mass ratio)
Electron mass
me 9.1093897 10 31−⋅ kg⋅≡
Electron
3.63694807 10 4−⋅m2
sec⋅
Quantum of circulation
Hartree energy
Eh 4.3597482 10 18−⋅ joule⋅≡
Bohr radius
a0 0.529177249 10 10−⋅ m⋅≡
Rydberg constant
Ryd 10973731.534 m 1−⋅≡
Fine structure constantα 7.29735308 10 3−⋅≡
Atomic Constants
ECw 2.42631058 10 12−⋅ m⋅≡
ECw 2.426 10 10−× cm=
re 2.81794092 10 15−⋅ m⋅≡
Classical electron radius
928.47701 10 26−⋅jouletesla
⋅
Electron magnetic moment
Muon
mµ 1.8835327 10 28−⋅ kg⋅≡
Muon mass
N 6 0221367 1023 l 1−
Physico-Chemical Constants
1.31959110 10 15−⋅ m⋅
Neutron Compton wavelength
Neutron mass
mn 1.6749286 10 27−⋅ kg⋅≡
Neutron
26751.5255 104⋅rad
sec tesla⋅⋅
Proton gyromagnetic ratio
Proton magnetic moment
1.41060761 10 26−⋅jouletesla
⋅
1.32141002 10 15−⋅ m⋅
Proton Compton wavelength
1836.152701
Ratio of proton mass to electron mass
Proton mass
mp 1.6726231 10 27−⋅ kg⋅≡
Proton
NA 6.0221367 1023⋅ mole 1⋅≡
Avogadro constant
Atomic mass constant
AMU 1.6605402 10 27−⋅ kg⋅≡
96485.309coulmole
⋅
Faraday constant
8.314510joule
mole K⋅⋅
Molar gas constant
rs 6.9598 105⋅ km⋅≡
Md 3.796 1015× gm=
el me c α⋅( )2⋅ a0⋅≡
LPl 4.051 10 33−× cm=
re 2.818 10 13−× cm=
LPl Gh
c3⋅≡
mPl 5.456 10 5−× gm=
mPl hcG
⋅≡
Mz 5.977 1027⋅ gm⋅≡
Ms 1.989 1033⋅ gm⋅≡
Second radiation constant0.01438769 m⋅ K⋅
First radiation constant3.7417749 10 16−⋅ watt⋅ m2⋅
Stefan-Boltzmann constant
σ 5.67051 10 8−⋅watt
m2 K4⋅⋅≡
22.41410litermole
⋅
Molar volume of ideal gas at STP
Boltzmann's constant
kb 1.380658 10 23−⋅joule
K⋅≡
Data from CRC Handbook of Chemistry and Physics, 73nd editionedited by David R. Lide, CRC Press (1992).
Mdc2 re⋅
G:=
Msv 1.246 1056× gm=tea0
c α⋅≡
Msv 1.246 1056× gm≡
tH 9.78 109⋅ yr⋅≡
Rgsv tH c⋅≡
Rgsv 9.252 1027× cm=
tH 9.78 109⋅ 365.2564⋅ 24⋅ 60⋅ 60⋅ sec⋅≡
Rgsv 9.252 1027× cm=
c2 Rgsv⋅
G1.246 1056× gm=
tH 3.086 1017× sec=
re α2 a0⋅≡
G 6.673 10 8−×cm3
gmsec2≡
Mdel2
me G⋅≡
rz 6.37817 103⋅ km⋅≡
Rgsv 9.252 1027× cm=
8
1m2sec
n,