Mhhmp Bao Cao

1

MC LC

S 1 ...................................................................................................................... 2

1. Xy dng hm truyn v phng trnh sai phn ca h. ..................................... 2

2. Code chng trnh vi ngn ng C# ................................................................... 3

3. In kt qu ng cong qu ............................................................................ 10

4. So snh kt qu vi phn mm Matlab. ............................................................. 12

5. In kt qu y[k] .................................................................................................... 13

6. Cc ch tiu cht lng ca h thng ................................................................. 13

7. Nhn xt ............................................................................................................. 14

8. Ti liu tham kho ............................................................................................. 14

2

S 1

1. Xy dng hm truyn v phng trnh sai phn ca h. Ta c hm truyn kn ca h thng l:

() =

11 + 1

2

2 + 1

1 +1. 2. 3

(1 + 1)(2 + 1)

=12

(1 + 1)(2 + 1) + 123

() =12

122 + (1 + 2) + 123 + 1

Thay =2

.

1

+1 vo hm W(s) ta c:

() =12. (

2 .

1 + 1)

12. (2 .

1 + 1)

2

+ (1 + 2) (2 .

1 + 1) + 123 + 1

() =12

2( + 1)2

412( 1)2 + (123 + 1)2( + 1)2 + 2(1 + 2)( + 1)( 1)

Bin i v dng:

()

()=

122(2 + 2 + 1)

2 + +

Trong :

3

= 41 2 + 2(1 + 2) + (123 + 1)2

= 81 2 + 22(123 + 1)

= 41 2 2(1 + 2) + (123 + 1)2

Az2Y(z) + BzY(z) + CY(z) = K1K2T2 [z2U(z) + 2zU(z) + U(z)]

Dng tnh cht dch hm gc c bin i Z ta tm c phng trnh sai phn tng

ng:

AY[k+2] + BY[k+1] + CY[k] = K1K2T2 (U[k+2] + 2 U[k+1] + U[k]) V tn hiu vo l tn hiu nhy cp U(t) = 1(t) nn ta c:

U[k+2] = U[k+1] = U[k] = 1

AY[k+2] + BY[k+1] + CY[k] = 4K1K2T2

Y[k+2] = (4K1K2T2 BY[k+1] CY[k]) /A

T ta c cng thc tnh cc gi tr p ng y(t) nh sau:

y[0] = y[1] = 0;

y[k+2] = (4K1K2T2 By[k+1] Cy[k]) /A;

k=0, 1, 2999; A, B, C l cc hng s tnh trn.

2. Code chng trnh vi ngn ng C# using System;

using System.Collections.Generic;

using System.ComponentModel;

using System.Data;

using System.Drawing;

using System.Drawing.Drawing2D;

using System.Linq;

using System.Text;

using System.Threading.Tasks;

using System.Windows.Forms;

namespace test

{

public partial class Form1 : Form

4

{

private Graphics graph;

private int x0, y0, xMax, yMax; // ta gc O, xMax, yMax

private int min, max;

private int delta_x=30;

private int delta_y=30; // lch trc ta khi v

private double dx, x, y;

private float x1, y1, x2, y2;

private bool OnDinh = true;

private float K1, K2, K3, T1, T2, T; //thng s u vo

private float Tmin;

private float ymax, yod, x_ymax, Tod, Tmax, xicma; //Thng s u ra cn tnh ton

private int x_Tod; // Xc nh ta ca Tod;

private float unit_x, unit_y; // chia v th

private float A, B, C;

public Form1()

{

InitializeComponent();

graph = DrawArea.CreateGraphics();

xMax = DrawArea.Width;

yMax = DrawArea.Height;

x0 = 0;

y0 = DrawArea.Height;

}

private void button1_Click(object sender, EventArgs e)

{

int sopt = 1000;

graph.Clear(Color.White);

float[] y = new float[sopt];

PointF[] pnt = new PointF[sopt];

Pen blackPen = new Pen(Color.Black, 1);

Pen redPen = new Pen(Color.Red, 1);

Pen greenPen = new Pen(Color.Green, 3);

int index = 0;

for (int i = 0; i < 100; i++)

{

// 100 ch s im y[k] cn in ra.

comboBox_item.Items.Add(index);

5

index += 10;

}

listBox1.Items.Clear(); // phi xa rng listbox mi ln cp nht li th

// Kim tra nhp thng s hp l hay khng

if (float.TryParse(textBoxK1.Text, out K1) && float.TryParse(textBoxK2.Text, out K2)

&& float.TryParse(textBoxT2.Text, out T2) && float.TryParse(textBoxT1.Text, out T1) &&

float.TryParse(textBoxT.Text, out T)

&& float.TryParse(textBoxT2.Text, out K3))

{

if (T1 < T2) { Tmin = T1/20; }

else { Tmin = T2 / 20; }

if (T > Tmin)

{ MessageBox.Show("Xin nhp li chu k trich mu T, T

6

for (int j = 0; j pnt

float toado_x = +j * T;

float toado_y = y[j];

pnt[j].X = (float)(delta_x + toado_x * unit_x);

//nhn vi chia full mn hnh

pnt[j].Y = (float)( y0 - toado_y * unit_y - delta_y);

if (j % 10 == 0)

{ //Ly 4 ch s sau du phy

int tmp = (int)(y[j] * Math.Pow(10, 4));

float _item = (float)(tmp / Math.Pow(10, 4));

listBox1.Items.Add(_item); // C 10 phn t th thm y[] vo listbox

}

// listBox1.DataSource = y; add c mng y

// listBox1.Items.Add(y[0]); add tng phn t

}

VeTrucToaDo(); // V trc ta

graph.DrawLines(greenPen, pnt); // V th

// V vch chia honh

Font f = new Font("Tahoma", 12);

Brush b = new SolidBrush(Color.Red);

float chi_so = 0;

for (int i = 0; i < 10; i++)

{ chi_so += 100;

graph.DrawLine(blackPen, delta_x + chi_so * T * unit_x, y0 - delta_y - 3, delta_x + chi_so

* T * unit_x, y0 - delta_y + 3);

graph.DrawString(chi_so.ToString(), f, b, delta_x + (chi_so - 15) * T * unit_x, y0 - 20);

}

if (OnDinh)

{

//==============Tnh thi gian h thng bt u n nh

int k = 999;

do

{

Tod = k * T; // Thi gian n nh

--k;

x_Tod = k;

}

while ((Math.Abs((y[k] - y[999]) / y[999]) = x_ymax));

k = 999;

do

{ --k; }

while (Math.Abs((y[k] - (1 / K2)) / (1 / K2))

7

yod = 0;

for (int i = k; i < 1000; i++)

{

yod += y[i];

}

yod = yod / (999 - k + 1);

xicma = Math.Abs(ymax - yod) * 100 / yod;

Tmax = x_ymax * T;

// a ra cc thng s u ra

textBoxHT.Text = "n nh";

textBoxTod.Text = Tod.ToString();

textBoxYod.Text = yod.ToString();

textBoxTmax.Text = Tmax.ToString();

textBoxYmax.Text = ymax.ToString();

textBoxxicma.Text = xicma.ToString();

// V ging ta ca ymax

float toa_do_x = delta_x;

float toa_do_y = y0 - ymax * unit_y - delta_y;

do

{

graph.DrawLine(blackPen, toa_do_x, y0 - ymax * unit_y - delta_y, toa_do_x + 3, y0 -

ymax * unit_y - delta_y); //giong ngang

toa_do_x += 6;

} while (toa_do_x

8

toa_do_x += 6;

} while (toa_do_x

9

graph.DrawLine(p, delta_x, y0 - delta_y, xMax - 2, y0 - delta_y);//truc hoanh

graph.DrawLine(p, delta_x, 4, delta_x, yMax - delta_y);//truc tung

MuiTen(graph, new Pen(Color.Black), new PointF((float)(xMax - 2.5), (float)(y0 - delta_y)), new

PointF((float)(xMax - 2), (float)(y0 - delta_x))); //mui ten Ox

MuiTen(graph, new Pen(Color.Black), new PointF((float)delta_y, (float)0), new

PointF((float)delta_y, (float)(-2.5))); //mui ten Oy

VeOXY();

}

//============================================//

private void VeOXY()

{ Font f = new Font("Tahoma", 12);

Brush b = new SolidBrush(Color.Black);

graph.DrawString("O", f, b, x0, y0 - delta_y);

graph.DrawString("T", f, b, xMax - 20, y0 - 18);

graph.DrawString("Y", f, b, x0 + 3, 5);

}

//============================================//

public static void MuiTen(Graphics graphics, Pen p, PointF diemDau, PointF diemCuoi)

{ Pen myPen = new Pen(Color.Black);

myPen.Width = 5;

myPen.EndCap = LineCap.ArrowAnchor;

PointF endPoint = new PointF((diemDau.X + diemCuoi.X) / 2, (diemDau.Y + diemCuoi.Y) / 2);

graphics.DrawLine(myPen, diemDau, endPoint);

}

private void listBox1_SelectedIndexChanged(object sender, EventArgs e)

{ // a ch s ca y ra comboBox

comboBox_item.Text = ((listBox1.SelectedIndex) * 10).ToString();

}

private void comboBox_item_SelectedIndexChanged(object sender, EventArgs e)

{

listBox1.SelectedIndex =int.Parse(comboBox_item.Text ) /10;

}

}

}// END OF PROGRAM

10

Giao din chnh ca chng trnh:

3. In kt qu ng cong qu ng vi b thng s:

Ta c ng cong qu nh sau:

11

Trc x th hin gi tr T (1000 ln chu k trich mu).

Trc y th hin gi tr ca y(t) theo T.

12

4. So snh kt qu vi phn mm Matlab. S simulink:

ng cong qu thu c qua Matlab

Nhn xt:

th thu c bng chng trnh m phng c dng ging vi th m

phng bi Matlab. Nh vy, nu b qua sai s khng th trnh khi trong qu trnh

m phng, chng ta c th kim chng c phng php tm phng trnh sai phn

ca h thng, v tnh ton ca chng trnh m phng l ng.

13

5. In kt qu y[k]

In ra mn hnh kt qu y[k], cch 10 s in 1 ln

S dng listbox a ra 100 gi tr, c 10 gi tr th add phn t vo listbox.

comboBox cha ch s k ca y[k] trong listbox, listbox v comboBox tham chiu

n nhau.

V d: y y[160] = 0.667

6. Cc ch tiu cht lng ca h thng Cc ch tiu cht lng ca h thng c tnh ton t ng trong giap din

chnh ca chng trnh, ph thuc vo b tham s u vo.

14

Nu h thng n nh, textbox H thng s a ra thng bo n nh, ng

thi cc ch tiu cht lng c a ra cc tng ng.

Nu h thng khng n nh, textbox H thng s a ra thng bo khng

n nh, cc ch tiu a ra thng bo N/A

(Tnh n nh ca h thng c nh gi theo tiu chun Hurwitz)

V d: Vi b thng s u vo nh phn trn, h thng l n nh vi cc ch tiu

nh sau:

7. Nhn xt Vi b thng s T1, T2, K1, K2, K3, T ph hp, h thng s n nh. Cn chn thi

gian trch mu T nh hn hoc bng 1/10 min(T1, T2). Cc thng s trn u phi

khc 0.

ng cong xut pht t gc ta , vt ln ti gi tr Ymax ti thi im Tmax,

dao ng xung quanh gi tr Yod. Gi tr vt qu ti a so vi Yod l h (%).

n thi gian Tod, h n nh, ch dao ng trong phm vi 5% xung quanh gi

tr Yod.

8. Ti liu tham kho [1] Nguyn Cng Hin, Nguyn Phm Thc Anh, M hnh ha h thng v m

phng, NXB Khoa hc v K thut, 2006

[2] http://msdn.microsoft.com/ , C# Tutorials, truy nhp ln cui 10/04/2014

[3] http://congdongcviet.com/ , din n C#, truy nhp ln cui 10/04/2014

Documents

Mhhmp Bao Cao