Ngan Hang Cau Hoi Toan 6 Ki I

I

Ngn hng cu hi ton 6Hc k I nm hc 2012-2013Gio vin: o Duy Hin - Trng THCS o M --------------------------------------------------I. PHN I S

Cu hi 1: (Nhn bit, kin thc tun 1, thi gian 2 ph)Cho tp hp B= {2; 3; 4}. in k hiu thch hp vo vung:

2 B ; 4 B ; 1 B ; 12 B

p n:

2 B 4 B 1 B 12 B

Cu hi 2: ( Thng hiu, kin thc tun 1, thi gian 5 ph) Cho tp A= {x N/ x < 4}

Trong N l tp hp cc s t nhin.

Lit k cc phn t ca tp hp A ?

p n: A= {0;1;2;3}

Cu hi 3: ( Vn dng, kin thc tun 1, thi gian 6 ph)

Cho tp hp A= {1; 2} v B= {0; 3; 4}. Vit tt c cc tp hp c hai phn t, trong mt phn t thuc A, mt phn t thuc B.

p n:

{1; 0},{1; 3},{1; 4},{2; 0},{2; 3},{2; 4}.

Cu hi 4: (Nhn bit, kin thc tun 2, thi gian 2 ph) Cho tp hp A={0}

a) A khng phi l tp hp

b) A l tp hp rng

c) A l tp hp c 1 phn t l 0

d) A l tp hp khng c phn t no

p n: C

Cu hi 5: ( Thng hiu, kin thc tun 2, thi gian 3 ph) in vo ch trng ba s mi dng l ba s t nhin lin tip tng dn

; ..; 12

; a ; ..

p n: 10; 11; 12

a-1; a ; a+1

Cu hi 6: ( Vn dng, kin thc tun 2, thi gian 5 ph)Cho tp hp M = {4; 7; 10}. Trong cc khng nh sau, khng nh no ng vit , khng nh no sai vit S:

a) {4; 7} M. b) {4; 10}= M c) {7; 10} M

d) 7 M e) 10 M h) {7} M

p n: a) b) S c) S d) S e) S h)

Cu hi 7: ( Nhn bit, kin thc tun 3, thi gian 3 ph)

S lin trc v lin sau ca s 69 l:

A. 70 v 71 B. 68 v 70 C. 71 v 72 D. 69 v 70

p n: B

Cu hi 8: ( Thng hiu, kin thc tun 3, thi gian 5 ph)a) c cc s la m sau: XIV, XXVII, XXIX.

b) Vit cc s sau bng ch s La m: 26; 19 p n:

a) XIV = X-I+V = 10 -1+5= 14 XXVII = X+X+V+II = 27

XXIX = X+X- I+X = 29

b) 26 = XXVI

19 = XIX

Cu hi 9: (Vn dng, kin thc tun 3, thi gian 8ph)

Tnh:

a) 25 + 19 + 75 b) 4 .53 .25 c) 72 . 18 + 72 .82

p n: a) ( 25 + 75) + 19 = 100 + 19 = 119

b) ( 4 . 25) . 53 = 100 . 53 = 5300

c) ( 18 + 82 ) . 72 = 100 . 72 = 7200.

Cu hi 10 ( Nhn bit, kin thc tun 4, thi gian 5 ph) Cho tp hp M={1;2;3}. Trong cc tp hp sau tp hp no l tp hp con ca M

M1={0;1} B. M2={0;2}

C. M3={3;4}

D. M4={1;3}

p: D

Cu hi 11: (Hiu, kin thc tun 4, thi gian 5 ph)Cho tp hp N v N*. Vit tp hp A cc s t nhin x khng thuc N* ?

p n:

A= {x N/ x < 1}

Cu hi 12: (Vn dng, kin thc tun 4, thi gian 7 ph) Vit cc tch sau y di dng mt lu tha ca mt s:

a/ A = 82.324

b/ B = 273.94.243p n: a/ A = 82.324 = 26.220 = 226. hoc A = 413 b/ B = 273.94.243 = 322 Cu hi 13: (Nhn bit, kin thc tun 5, thi gian 5 ph)

Mi tp hp sau c bao nhiu phn t?

a) Tp hp A cc s t nhin x m x- 8 = 12

b) Tp hp B cc s t nhin x m x+ 7 = 7

c) Tp hp C cc s t nhin x m x . 0 = 0

d) Tp hp D cc s t nhin x m x . 0 = 3

p n:

a) A = { 20 } ; A c mt phn t .

b) B = {0} ; B c 1 phn t .

c) C = N ; C c v s phn t .

d) D = ; D khng c phn t no c .

Cu hi 14 : (Hiu, kin thc tun 5, thi gian 7 ph)S chn l s t nhin c ch s tn cng l: 0,2,4,6,8

S l l s t nhin c ch s tn cng l: 1,3,5,7,9 . Hai s chn ( hoc l) lin tip hn km nhau 2 n v.

a/ Vit tp hp C cc chn nh hn 10.

b/ Vit tp hp L cc l ln hn 10 nhng nh hn 20.

c/ Vit tp hp A ba s chn lin tip, trong s nh nht l 18.

d/ Vit tp hp B bn s l lin tip, trong s ln nht l 31.

p n:

a/ C = {0; 2; 4; 6; 8}

b/ L = {11; 13; 15; 17; 19}

c/ A = {18; 20; 22}

d/ B = {25; 27; 29; 31}

Cu hi 15 : (Vn dng, kin thc tun 5, thi gian 7 ph)Tnh tng ca:

a/ Tt c cc s t nhin c 3 ch s.

b/ Tt c cc s l c 3 ch s.

p n:

a/ S1 = 100 + 101 + + 998 + 999

Tng trn c (999 100) + 1 = 900 s hng. Do

S1= (100+999).900: 2 = 494550

b/ S2 = 101+ 103+ + 997+ 999

Tng trn c (999 101): 2 + 1 = 450 s hng. Do

S2 = (101 + 999). 450 : 2 = 247500

Cu hi 16: (Nhn bit, kin thc tun 6, thi gian 5 ph)

Th t thc hin cc php tnh i vi biu thc khng c du ngoc

A. 1- Nhn v chia

2- Ly tha

3- Cng v tr

B. 1- Cng v tr

2- Nhn v chia3- Ly tha

C. 1- Cng v tr

2- Ly tha

3- Nhn v chia

D. 1- Ly tha

2- Nhn v chia3- Cng v tr

p n: D

Cu hi 17 : (Hiu, kin thc tun 6, thi gian 7 ph) in s thch hp vo trng:

A.2007 + = 2007

C. 2007 - = 2007

B.2007 = 2007

D. 2007 : = 2007

p n:

A. 0 B. 1

C. 0

D.1

Cu hi 18: (Vn dng, kin thc tun 6, thi gian 10 ph)

Tnh nhanh : a) 4 . 37 . 25

b) 56 + 16 + 44

p n: Tnh nhanh :

a/ 4.37.25= (4.25).37= 3700

b/ 56+16+44 = (56+44)+16 = 116

Cu hi 19:(Nhn bit, kin thc tun 7, thi gian 3 ph) Kt qu ng ca php tnh 26:2 l:

A. 27

B. 26

C. 25

D. 17p n. C

Cu hi 20: (Hiu, kin thc tun 7, thi gian 10 ph)

Khi no ta ni c s t nhin a chia ht cho s t nhin b (b ( 0)?

Khi no ta ni php chia s t nhin a cho s t nhin b (b ( 0) l php chia c d?

p n:

Nu c s t nhin q sao cho a = bq

S b chia = s chia . thng + s d, a = bq + r (r < b)

Cu hi 21: (Vn dng, kin thc tun 7, thi gian 10 ph) nh du x vo trng:CuS

33 . 32 = 36

33 . 32 = 96

33 . 32 = 35

a) 23 . 22 . 24

b) 102 . 103 . 105

c) x . x5

d) a3. a2 . a5

p n.CuS

33 . 32 = 36X

33 . 32 = 96X

33 . 32 = 35X

a) 23 . 22 . 24 = 29

b) 102 . 103 . 105 = 1010

c) x . x5 = x6

d) a3. a2 . a5 = a10Cu hi 22: :(Nhn bit, kin thc tun 8, thi gian 3 ph) Chn cu tr li ng nht sau y :

A. S chia ht cho 5 c ch s tn cng l 5

B. S chia ht cho 2 c ch s tn cng l 8

C. S c ch s tn cng l 0, 2, 4, 6, 8 th chia ht cho 2

D. C ba cu trn u ng

p n: CCu hi 23: (Hiu, kin thc tun 8, thi gian 8 ph) Nu du hiu chia ht cho 2 ; cho 5?. Gii bi tp sau?:

a) 1 . 2 . 3 . 4 . 5 . 6 + 42 c chia ht cho 2, cho 5 khng?

b) 1 . 2 . 3 . 4 . 5 . 6 + 35 c chia ht cho 2, cho 5 khng?

p n:

Cc s c ch s tn cng l ch s chn th chia ht cho 2 v ch nhng s mi chia ht cho 2.

Cc s c ch s tn cng l ch s 0 hoc 5 th chia ht cho 5 v ch nhng s mi chia ht cho 5.

a) 1 . 2 . 3 . 4 . 5 . 6 chia ht cho 2 ; 42 chia ht cho 2 ( 1 . 2 . 3 . 4 . 5 . 6 + 42 chia ht cho 2

1 . 2 . 3 . 4 . 5 . 6 chia ht cho 5 m 42 khng chia ht cho 5 ( 1 . 2 . 3 . 4 . 5 . 6 + 42 khng chia ht cho 5

b) 1 . 2 . 3 . 4 . 5 . 6 chia ht cho 2 m 35 khng chia ht cho 2 ( 1 . 2 . 3 . 4 . 5 . 6 + 35 khng chia ht cho 2

1 . 2 . 3 . 4 . 5 . 6 chia ht cho 5 v 35 chia ht cho 5 ( 1 . 2 . 3 . 4 . 5 . 6 + 35 chia ht cho 5

Cu hi 24: (Vn dng, kin thc tun 8, thi gian 10 ph)

Cho s , thay du * bi ch s no :

a / A chia ht cho 2

b/ A chia ht cho 5

c/ A chia ht cho 2 v cho 5

p n:

a/ A chia ht 2 th * { 0, 2, 4, 6, 8}

b/ A chia ht 5 th * { 0, 5} c/ A chia ht cho 2 v cho 5 th * { 0}

Cu 25:(Nhn bit, kin thc tun 9, thi gian 3 ph)

in s thch hp tip theo vo cc cu sau

A) C hai ch s t nhin lin tip u l s nguyn t l:.

B) C ba s l lin tip u l s nguyn t l:...

C) C mt s nguyn t chn l:.

D) S nguyn t nh nht l:

p n: A: 2;3

B: 3;5;7

C: 2

D:2

Cu hi 26: (Hiu, kin thc tun 9, thi gian 7 ph)

a) Tm cc c ca 8?

b) Tm cc bi nh hn 30 ca 7?

p n:

(8) = (1; 2; 4; 8( B(7) = (0; 7; 14; 21; 28(Cu hi 27: (Vn dng, kin thc tun 9, thi gian 7 ph)

Tm cc s t nhin x sao cho:

a/ v

b/ (12) v 3 < x < 12p n:

a/ B(5) = {0, 5, 10, 15, 20, 25, 30, 35, }

Theo bi v nn

b/ (12) = {1; 2; 3; 4; 6; 12}, (12) v 3 < x < 12 nn x { 4; 6},Cu 28:(Nhn bit, kin thc tun 10, thi gian 3 ph) Phn tch 24 ra tha s nguyn t - cch tnh ng l:

A. 24 = 4.6 = 22.6B. 24 = 23.3

C. 24 = 24.1

D. 24 = 2.12

p n: BCu hi 29: (Hiu , kin thc tun 10, thi gian 8 ph)

Phn tch mt s t nhin ln hn 1 ra tha s nguyn t l g? p dng phn tch cc s 60, 84, 285 ra tha s nguyn t

p n:

Phn tch mt s t nhin ln hn 1 ra tha s nguyn t l vit s di dng mt tch cc tha s nguyn t.

a) 60( 22.3.5

b) 84 ( 22.3.7

c) 285 (3.5.19

Cu hi 30: (Vn dng , kin thc tun 10, thi gian 8 ph)

Mt lp hc c 24 HS nam v 18 HS n. C bao nhiu cch chia t sao cho s nam v s n c chia u vo cc t?

p n: S t l c chung ca 24 v 18

Tp hp cc c ca 18 l A =

Tp hp cc c ca 24 l B =

Tp hp cc c chung ca 18 v 24 l C = A B =

Vy c 3 cch chia t l 2 t hoc 3 t hoc 6 t.

Cu hi 31: (Nhn bit, kin thc tun 11, thi gian 5 ph) BCNN(3;4;6;8;24) l:

A. 24 B. 192 C. 72

D. 12

p n: ACu hi 32:(Hiu,kin thc tun 11, thi gian 6 ph) a/ Tm CLN ( 24 , 36 , 160 )

b/ Tm BCNN ( 18 , 24 , 72 )

p n:

a/ CLN ( 24 , 36 , 160 ) = 4

b/ BCNN ( 18 , 24 , 72 ) = 72

Cu hi 33:(Vn dng ,kin thc tun 11, thi gian 6 ph) Thc hin php tnh ri phn tch kt qu ra tha s nguyn t :

999 : 111 + 35 : 32

p n:

9 + 27 = 36 = 22 . 32

Cu hi 34:(Vn dng ,kin thc tun 11, thi gian 10 ph) Hai i thiu nin : Chi i Nguyn Thi Bnh c 36 i vin , chi i L Vn Tm c c 40 i vin , khi sinh hot Anh tng ph trch i mun chia thnh nhiu t . Hi c th chia thnh nhiu nht bao nhiu t ( s i vin ca hai i c chia u vo cc t )

p n:

Gi a l s t phi chia ( a N* )

Ta c : 36 chia ht cho a ; 40 chia ht cho a

V a nhiu nht a = CLN( 36,40 ) = 4

Vy s t phi chia l 4 t .

Cu hi 35: (Nhn bit , kin thc tun 12, thi gian 10 ph)

Nu quy tc tm BCNN ca hai hay nhiu s?

p n:

Mun tm bi chung nh nht ca hai hay nhiu s ln hn 1 ta thc hin ba bc sau:

Bc 1: phn tch mi s ra TSNT.

Bc 2: chn ra cc TSNT chung v ring.

Bc 3: lp tch cc tha s chn, mi tha s ly s m ln nht ca n. Tch l BCNN phi tmCu hi 36:(Hiu,kin thc tun 12, thi gian 10 ph)Mt n v b i khi xp hng, mi hng c 20 ngi, hoc 25 ngi, hoc 30 ngi u tha 15 ngi. Nu xp mi hng 41 ngi th va (khng c hng no thiu, khng c ai ngoi hng). Hi n v c bao nhiu ngi, bit rng s ngi ca n v cha n 1000?

p n:

Gi s ngi ca n v b i l x (xN)

x : 20 d 15 x 15 chia ht 20

x : 25 d 15 x 15 chia ht 25 x : 30 d 15 x 15 chia ht 30

Suy ra x 15 l BC(20, 25, 35)

Ta c 20 = 22. 5; 25 = 52 ; 30 = 2. 3. 5; BCNN(20, 25, 30) = 22. 52. 3 = 300

BC(20, 25, 35) = 300k (kN)

x 15 = 300k x = 300k + 15 m x < 1000 nn

300k + 15 < 1000 300k < 985 k < (kN)

Suy ra k = 1; 2; 3

Ch c k = 2 th x = 300k + 15 = 615 41

Vy n v b i c 615 ngi

Cu hi 37: (Nhn bit, kin thc tun 13, thi gian 5 ph )

Tp hp cc s nguyn gm cc loi s no? K hiu nh th no?

p n:

Tp hp :gm cc s nguyn m, s 0 v cc s nguyn dng l tp hp cc s nguyn. Tp hp cc s nguyn c kh hiu l Z.

Z =

Cu hi 38: (Hiu, kin thc tun 13, thi gian 5 ph )

a/ Sp xp cc s nguyn sau theo th t tng dn

2, 0, -1, -5, -17, 8

b/ Sp xp cc s nguyn sau theo th t gim dn

-103, -2004, 15, 9, -5, 2004

p n: a/ -17. -5, -1, 0, 2, 8

b/ 2004, 15, 9, -5, -103, -2004

Cu hi 39: (Hiu, kin thc tun 13, thi gian 5 ph ) Biu din cc s nguyn -4, 4, 6 trn trc s nguyn? .p n: D O C A

( ( ( ( ( ( ( ( ( ( ( ( ( ( ( -4 0 4 6


Trong tp hp cc s nguyn sau, tp hp no c cc s nguyn c xp theo th t tng dn

A. {2; -17; 5; 1; -2; 0}B. {-2; -17; 0; 1; 2; 5}

C. {0; 1; -2; 2; 5; -17}D. {-17; -2; 0; 1; 2; 5}

p n: D

Cu hi 41: ( Hiu , kin thc tun 14, thi gian 8 ph )

Gi tr tuyt i ca mt s nguyn l g? Tnh ; ; ; ; ; ? p n:

Khong cch t in a n im 0 trn trc s l gi tr tuyt i ca s nguyn a

; ; ; ; ;

Cu hi 42: ( Hiu , kin thc tun 14, thi gian 10 ph ) Tm x bit:

a/ |x 5| = 3

b/ |1 x| = 7

p n:

a/ |x 5| = 3 nn x 5 = 3

x 5 = 3 x = 8

x 5 = -3 x = 2

b/ |1 x| = 7 nn 1 x = 7

1 x = 7 x = -6

1 x = -7 x = 8

Cu hi 43: ( Nhn bit, kin thc tun 15, thi gian 3 ph )

Hy nu quy tc cng hai s nguyn cng du?. Nu quy tc cng hai s nguyn khc du?

p n: Cng hai s nguyn dng chnh l cng hai s t nhin khc 0

Cng hai s nguyn m, ta cng hai gi tr tuyt i ca chng ri t du (- ) trc kt qu.

Mun cng hai s nguyn khc du khng i nhau, ta tm hiu hai gi tr tuyt i ca chng (s ln tr s nh) ri t trc kt qu tm c kt qu tm c du ca s c gi tr tuyt i ln hn.

Cu hi 44: ( Hiu, kin thc tun 15, thi gian 8 ph )

p dng tnh:

a. (-38)+27

b. 273+(-123)p n: a. (-38)+27= -(38-27)= -11

b. 273+(-123)= (273-123)=150

Cu hi 45: ( Vn dng, kin thc tun 15, thi gian 12ph )

Tnh:

a/ 11 - 12 + 13 14 + 15 16 + 17 18 + 19 20

b/ 101 102 (-103) 104 (-105) 106 (-107) 108 (-109) 110

p n:a/ 11 - 12 + 13 14 + 15 16 + 17 18 + 19 20

= [11 + (-12)] + [13 + (-14)] + [15 + (-16)] + [17 + (-18)] + [19 + (-20)]

= (-1) + (-1) + (-1) + (-1) + (-1) = -5

b/ 101 102 (-103) 104 (-105) 106 (-107) 108 (-109) 110

= 101 102 + 103 104 + 105 106 + 107 108 + 109 110

= (-1) + (-1) + (-1) + (-1) + (-1) = -5


Vit cng thc tng qut cc tnh cht ca php cng cc s nguyn?

p n:+) Php cng cc s nguyn cng c tnh cht giao hon, ngha l:

x + y = y + x

+) Tnh cht kt hp ca php cng cc s nguyn.

(x + y)+ z = x + (y + z)

+) Cng vi s 0

x + 0 = 0 + x = x

Cu hi 47: ( Hiu, kin thc tun 16, thi gian 8 ph ) Nu quy tc tr hai s nguyn? p dng tnh:

a. 2-7 b. 1-(-2) c. (-3)-4

p n:

Mun tr s nguyn a cho s nguyn b, ta cng a vi s i ca b

a - b = a + (-b)

a. 2-7=2+(-7)= -5 b. 1-(-2)=1+2=3 c. (-3)-4= (-3)+(-4)= -7

Cu hi 48: ( Vn dng, kin thc tun 16, thi gian 10 ph ) Tnh :

a) /-5/ + /-6/

b) /-8/ + /2/

p n:

a) 5 + 6 = 11

b) 8 + 2 = 10

Cu hi 49: ( Vn dng, kin thc tun 16, thi gian 10 ph ) Tm s t nhin x bit :

a/ x2 = 16

b/ 36 chia ht cho x

p n:

a/ x = 4 b/ x { 1,2,3,4,6,9,12,18,36 }

Cu hi 50: (Hiu , kin thc tun 17, thi gian 7 ph )in s thch hp vo trng

(-15) + = -15;

(-25) + 5 =

(-37) + = 15;

+ 25 = 0

p n:

(-15) + = -15;

(-25) + 5 =

(-37) + = 15;

+ 25 = 0


Pht biu quy tc nhn hai s nguyn khc du?

p n:

Mun nhn hai s nguyn khc du, ta nhn hai gi tr tuyt i ca chng ri t du trc kt qu nhn c.

Cu hi 52: (Hiu, kin thc tun 18, thi gian 10 ph )

p dng tnh:

a. (-5).6 b. 9.(-3) c. (-10).11 d. 150.(-4) p n: a. (-5).6 = -30 c. (-10).11 = -110

b. 9.(-3) = -27 d. 150.(-4) = -600

Cu hi 53: ( Vn dng, kin thc tun 18, thi gian 10 ph )

Tm s nguyn x bit:

a) x + 7 = - 5 - 14

b) 311 x + 82 = 46 + (x 21)

c) 4 - (27 - 3) = x - (13 - 4)

p n:a) x + 7 = - 5 - 14

x = -19 7

x = - 26

b) 311 x + 82 = 46 + (x 21)

311 + 82 46 + 21 = x + x

2x = 368

x = 184

c) 4 - (27 - 3) = x - (13 - 4)

4 - 24 = x - 13 + 4

- 24 = x - 13

-24 + 13 = x

- 11 = x hay x = -11

**************************************

II. Phn Hnh Hc.Cu 1: (Nhn bit, kin thc tun 1, thi gian 3 ph )

t tn cho mt im ngi ta thng dng

A. 1 ch ci vit thng (a,b,c,...)

B. 1 ch ci vit hoa nh (A,B,)

C. Bt k ch ci vit thng hoc vit hoaD. Tt c cc cu trn u ng

p n: BCu hi 2 : (Nhn bit, kin thc tun 1, thi gian 5 ph)

1. Em hy nu vi b mt c coi l phng?

2. Chic thc di cc em ang k c c im im g ?

p n: 1. Mt t knh, mt nc h khi khng gi

2. Thng, di...)

Cu 3: (Hiu, kin thc tun 1, thi gian 8 ph )a) xt xem cc im C v E thuc hay khng thuc ng thng a? b) in k hiu vo vung: C a ; E a ? p n:

a) im C thuc ng thng a, im E khng thuc ng thng a. b) C a ; E a

Cu 4: (Nhn bit, kin thc tun 2, thi gian 5 ph )Khoanh trn vo ch ci ng trc cu ng

Trong ba im phn bit thng hng

A. Phi c mt im l trung im ca on thng m hai u mt l hai im cn li

B. Phi c mt im nm gia hai im cn li

C. Phi c mt im cch u hai im cn li

D. Ch c cu C ng

p n: B


Qua ba im phn bit A, B, C thng hng

A. Ch v c mt ng thng

B. V c ng ba ng thng phn bit

C. V c nhiu hn ba ng thng phn bit

D. C ba cu trn u ng

p n: A Cu 6: (Hiu, kin thc tun 2, thi gian 7ph ) Chn kt qu tng ng ca ct B cho cc php tnh ct A

Ct ACt B

1. Hai ng thng trng nhau

2. Hai ng thng phn bit ct nhaua. khng c im chung no

b. c v s im chung

c. ch c mt im chung

p n: 1b, 2c

Cu 7: (Vn dng, kin thc tun 2, thi gian 10 ph ) V im M, ng thng b sao cho M b?

V ng thng a, M a, A b, A a, ? V im N a, N b?

Hnh v c c im g? p n:

C hai ng thng a,b cng i qua im A .

C ba im M, N, A cng nm trn ng thng a.


t tn cho mt tia ngi ta thng dng

A. Hai ch ci vit thng

B. Mt ch ci vit hoa

C. Mt ch ci vit thng

D. Mt ch ci vit hoa (lm gc) v mt ch ci vit thng

p n: DCu 9: (Hiu, kin thc tun 3, thi gian 8 ph ) -V 3 im M,N,O thng hng.

- im N,O nm nh th no i vi im M?.

- im M,O nm nh th no i vi im N?.

p n: - im N,O nm cng pha i vi im M

- im M,O nm khc pha i vi im N

Cu 10: (Vn dng, kin thc tun 3, thi gian 10 ph )

Cho hnh v sau :

a? Trn hnh v c nhng im no, ng no.

Trn hnh v c nhng im no thuc ng thng a? im no khng thuc ng thng a?p n: Trn hnh v c 3 im: A,M,N

Trn hnh v c ng thng a

M a

A a

N a

Cu 11: (Hiu, kin thc tun 5, thi gian 6 ph )

Khoanh trn vo ch ci ng trc cu ng

Cho bit hai tia Ox v Oy c chung gc O, c ngi ni:

A. Hai tia Ox v Oy chung gc th i nhau

B. Hai tia Ox v Oy nm trn mt ng thng c x, y cng pha vi O th i nhau

C. Hai tia Ox v Oy nm trn mt ng thng c x, y khc pha vi nhau th i nhau

D. C ba cu trn u ng

p n: C

Cu 12: (Hiu, kin thc tun 5, thi gian 7 ph )

V ng thng xy. Trn ly im M . Tia Mx l g ? c tn cc tia i nhau trong hnh v?

p n:

- Tia Mx l hnh gm im M v mt phn x M yng thng xy b chia ra bi im M.

- Tia Mx v tia My i nhau.


V hai tia chung gc M, ng thng BT ct hai tia B v T. Hy v hnhTheo ni dung bi ton.

p n: - V hai tia chung gc M. - V ng thng ct hai tia ti hai im B v T.


Quan st hnh v cho bit c tt c bao nhiu ng thng?, k tn cc ng thng ?

p n:

C tt c 6 ng thng:

- ng thng AB

- ng thng BC

- ng thng CD

- ng thng DA

- ng thng AC

- ng thng BD Cu 15: (Nhn bit, kin thc tun 7, thi gian 4 ph )Khoanh trn vo ch ci ng trc cu ng

t tn cho mt on thng ngi ta thng dng:

A. Hai ch ci vit hoa

B. Mt ch ci vit hoa v mt ch ci vit thng

C. Hai ch ci vit thng

D. C ba cu trn u ng

p n: A

Cu 16: (Nhn bit, kin thc tun 7, thi gian 4 ph ) Khoanh trn vo ch ci ng trc cu ng

Gi I l mt im bt k thuc on thng MN

A. im I phi trng vi M hoc N

B. im I phi nm gia hai im M v NC. im I hoc trng vi im M hoc nm gia hai im M v N hoc trng vi im N

D. im I l trung im ca on thng MN

p n: C

Cu 17: (Hiu, kin thc tun 7, thi gian 7 ph ) Khoanh trn vo ch ci ng trc cu ng

Cho bit hai tia Ox v Oy c chung gc O, c ngi ni:

A. Hai tia Ox v Oy chung gc O th trng nhau

B. Hai tia Ox v Oy nm trn mt ng thng c x, y cng pha vi O th trng nhau

C. Hai tia Ox v Oy nm trn mt ng thng c x, y khc pha vi nhau th trng nhau

D. C ba cu trn u ng

p n: B


on thng MN l hnh gm

A. Hai im M v N

B. Tt c cc im nm gia M v N

C. Hai im M, N v mt im nm gia M v N

D. im M, N v tt c cc im nm gia M v N

p n: D Cu 19: (Hiu, kin thc tun 8, thi gian 6 ph ) Chn kt qu tng ng ca ct B cho cc php tnh ct ACt ACt B

1. Bit AB=3cm, CD=4cm, th

2. Bit AB=3cm, CD=2cm, th

3. Bit AB=3cm, CD=3cm, tha) AB=CD

b) ABCD

p n: 1b, 2c, 3a

Cu 20: (Vn dng, kin thc tun 8, thi gian 7 ph ) V on thng AB bt k, ly im M nm gia A v B. o AM, MB, AB.

p n.

AM = 1,5 cm BM = 1,6 cm AB = 1,5 + 1,6 = 3,1cm Cu 21:(Nhn bit, kin thc tun 9, thi gian 5 ph )Khoanh trn vo ch ci ng trc cu ng

Nu im M nm gia hai im A v B th:

A. MA + AB = MBB. MB + BA = MA

C. AM + MB = ABD. AM + MB # AB

p n: C

Cu 22: (Hiu, kin thc tun 9, thi gian 7ph ) Chn kt qu tng ng ca ct B cho cc php tnh ct A

Trn tia Ox, OM=a v ON=b

Ct ACt B

a) Nu a=2cm, b=3cm th

b) Nu a=5cm, b=3cm th1. im O nm gia hai im M v N

2. im M nm gia hai im O v N

3. im N nm gia hai im M v O

p n: a 2, b 3


Cho on thng IK, im N nm gia I, K sao cho

NI = 3 cm, NK = 6 cm. Tnh di IK?.

p n: V N nm gia I v K nn

IN + NK = IK

Thay s, ta c 3 + 6 = IK

Vy IK = 9 cm

Cu 24: (Nhn bit, kin thc tun 10, thi gian 5 ph )

Chn kt qu tng ng ca ct B cho cc php tnh ct A

Cho M l trung im ca on thng AB

Ct ACt B

a) Nu AB=6cm th

b) Nu AB=4cm th1. AM=MB=4cm

2. AM=MB=3cm

3. AM=MB=2cm

p n: a 2, b 3

Cu 25: (Vn dng, kin thc tun 10, thi gian 10 ph ) Cho on thng EF , im M nm gia E,F v EF = 8 cm, EM= 4 cm So snh hai on thng EM v FM?

p n:

V M nm gia E v F nn

EM + MF = EF

Thay s, ta c 4 +MF = 8

MF = 8 4

MF = 4 (cm)

Vy EM = MF


Cho ba im thng hng A, B, C. Bit AB=7cm, AC=3cm, CB=4cm. Ta c:

A. im A nm gia hai im B v C

B. im B nm gia hai im A v C

C. im C nm gia hai im B v A

D. Khng c im no nm gia hai im cn li

p: C

Cu 27: (Hiu, kin thc tun 11, thi gian 8 ph )Khoanh trn vo ch ci ng trc cu ng

Vi ba im A, M, B phn bit, M l trung im ca on thng AB nu

A. AM + MB = AB v AM MBB. AM + MB AB v AM = MB

C. AM + MB AB v AM MB

D. AM + MB = AB v AM = MB

p n: D

Cu 28: (Vn dng, kin thc tun 11, thi gian 10 ph) - Khi no th AM + MB = AB ?

Lm bi tp :

Cho ba im thng hng A, B, C. Lm th no ch o hai ln m bit c di ca c ba on thng AB, BC, CA ?

p n:

- Nu im M nm gia hai im A v B th AM + MB = AB v ngc li, nu AM + MB = AB th im M nm gia hai im A v B.

- Ta ch cn o 2 on thng AB v BC, bit AC ta cng AB v BC vi nhau.

Cu 29: (Hiu, kin thc tun 12, thi gian 8 ph ) V tia Ox , v hai im A, B sao cho OA = 2 cm, OB = 4 cm.a) im A c nm gia hai im O v B khng?b) So snh OA,OB.

c) im A c l trung im ca on thng OB khng?. V sao?.

p n:

a. A nm gia O v B

b. OA = AB( =2 cm)

c. im A l trung im ca AB v A nm gia A, B (theo a), v cch u A, B ( theo b)Cu 30: (Vn dng, kin thc tun 12, thi gian 8 ph )Cho on thng AB di 4 cm , trn tia AB ly im C sao cho AC = 1 cm. Tnh CB ?

p n:

V C nm gia hai im A v B nn:

AC + CB = AB

CB = AB AC

CB = 4 1

CB = 3 (cm)

Cu 31: (Vn dng, kin thc tun 12, thi gian ph )Cho on thng AB = 5 cm, im M l trung im

ca AB. Tnh di MA, MB? p n: V M l trung im ca AB nn:

AM + MB = AB

MA = MB

Suy ra AM = MB = AB: 2 = 5: 2 = 2,5 (cm)

EMBED Equation.3

EMBED Equation.3

EMBED Equation.3

EMBED Equation.3

EMBED PBrush

B

M

T

A

B

M

PAGE 21

_1286107004.unknown

_1286355394.unknown

_1320514052.unknown

_1320514185.unknown

_1320514228.unknown

_1351251744.unknown

_1375470412.unknown

_1320514252.unknown

_1320514211.unknown

_1320514165.unknown

_1297428146.unknown

_1302976539.unknown

_1302976461.unknown

_1297420171.unknown

_1286355147.unknown

_1286355299.unknown

_1286355332.unknown

_1286355180.unknown

_1286352128.unknown

_1286353141.unknown

_1286353207.unknown

_1286352828.unknown

_1286352946.unknown

_1286352530.unknown

_1286106930.unknown

_1286106966.unknown

_1286106974.unknown

_1286106950.unknown

_1286056197.unknown

_1286106896.unknown

_1286058006.unknown

_1286058007.unknown

_1286058004.unknown

_1286058005.unknown

_1286057337.unknown

_1270892038.unknown

_1270892066.unknown

_1087201477.unknown

Documents

Ngan Hang Cau Hoi Toan 6 Ki I