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    Soal Perkerasan kaku

     Tanah dasar CBR rata2 = 6%

    Pondasi bawah Sirtu = 10 cm

    Kuat tarik lentur beton ! c! " = #

    Ba$a &' Te(an(an leleh = &'00

    Perkenban(an )alu lintas * +%

    mur Rencana R " = 20

     ,alan -rteri den(an + $alur 2 arah.

    Kom/osisi dan olume lalu lintas /ada tahun /embukaan *

    1 Bis & 6 " ton

    2 Truk 2 as 2 # " ton

    & Truk & as + 12 " ton

    # Truk (anden( 6 12 " ton =

    + Trailer 6 3 . 3 3 . 3 " ton =

    6 Trailer 6 3 . 3 3 . 3 . 3 " =

     T-B4)

    kon

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     ,SK7 rencana = c > ,KS7

    +16'2+.''

    Perhitun(an Re/etisi sumbu rencana

    Pro/orsi Beban

    1 2 & # + 6

    STRT

    6 +'0 0.12& 0.#3 +16'2+.''

    + ++3 0.116 0.#3 +16'2+.''

    # 1#00 0.2'1 0.#3 +16'2+.''

    & 360 0.1' 0.#3 +16'2+.''

    2 1#00 0.2'1 0.#3 +16'2+.''

     TT-) #303 1.000

    STR8 + 360 0.2#1 0.&+&&1# +16'2+.''

    3'# 0.2+1 0.&+&&1# +16'2+.''

    3 +10 0.1#& 0.&+&&1# +16'2+.''

    12 1&02 0.&6+ 0.&+&&1# +16'2+.''

     TT-) &+66 1.000

    STrR8 3 1# 1 0.012# +16'2+.''

     TT-) 1# 1

    K9)-T?

    Perhitun(an tebal /elat beton

    Sumber data Beban = 5asil Sur@ei

     ,enis /erkerasan = BBTT den(an ru

     $enis bahu = beton

    umur rencana = 20 th

     ,SK = +16'2+.''

    ?aktor Keamanan beban = 1.1 tabel #"

    Kuat tarik lentur beton !Ad" umur 23 hari = # 9/a

     ,enis dan tebal la/is /ondasi = stabilitas seme

    CBR tanah dasar = 6%

    CBR e!ekti! = 2+%

     Tebal Taksiran /elat beton = 1.# mm

     ,enis

    sumbu

    Beban sumbu

    ton"

     ,umlah

    sumbu

    Pro/orsi

    Sumbu

    )alu)intas

    Rencana

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    9/a

     k( cm "

      tahun

     tahun

    = 360

    = 1#00

    = 3++

    ##

    3+

    +3

    &0+

     P4R5T78-7 ,9)-5 S9B B4R:-S-RK-7 ,47S :-7 B4B-77;-

     $ml. Sumbu bh"STRT ST

    BS ton" ,S ton" BS ton"

    # + 6 3

    2 120 & 360 +

    2 23002 1#00

    # 1#00

    & 2+6+ + 3++ 12

    12

    + 22&+ 6 ##

    + #2+ 6 3+

    3

    3

    3

    3

    6 6 +3

    3

    3

    100'& +10+

    hun"

     $ml. Sumbu /erkend. bh"

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    =#>+>6 1 2 &

    &0266'0.#1&

    STRT

    60 &&.00

    2362+&0.'&& +0 2.+0

    131'.2+0 #0 22.00

    ##1136.02+ &0 16.+0

    131'.2+0 20 11.00

     TT-)

    ##1136.02+ STR8 +0 2.+0

    #+3620+.#2+ 0 &3.+0

    26162'1.12+ 30 ##.00

    66'2&3.3#2+ 120 66.00

     TT-)

    3'261.12+ STrR8 30 ##.00

     TT-)

    +16'2+.'' TT-)

    Ket * T4 = T48-78-7 4K-)47

    ?RT = ?-KTR R-S T48-78-7

    ?4 = ?-KTR 4RS

      $i TT T:-K T4RB-T-S

    12+mm

    Re/etisi Dan(

    ter$adi

     ,enis

    Sumbu

    Beban sumbu

    ton k7"

    Beban Rencana

    /er Roda k7"

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    8 STrR8

     ,S ton" ,S ton" BS ton" ,S ton"

    ' 11 12 1&

    360

    3++

    ##

    ##

    ##

    3+

    3+

    3+

    3+

    +3

    +3

    3 +3

    3 +3

    3 +3

    &+12 1#

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    -nalisa ?atik dan 4rosi

    -nalisa ?atik -nalis

    Re/etisi i$in % rusak %" Re/etisi i$in

    # + 6 =#E1006 3

    &0266'0.#1& T4 = +0###3#0.21

    2362+&0.'&& ?RT = #033#3.33

    131'.2+0 ?4 = 11'6''621

    ##1136.02+ &+2'6.03

    131'.2+0 11'6''621

    ##1136.02+ T4 = &+2'6.03

    #+3620+.#& ?RT = 6#&6+.33

    26162'1.1& ?4 = #&60#361.33

    66'2&3.3#& 111&206#

    3'261.1& T4 = 1#36'+2.33

    ?RT =

    ?4 =

    Re/etisi Dan(

    ter$adi

    ?aktor Te( F

    4rosi

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    a 4rosi

    % rusak +"

    '=#E1003

    G:0H

    G:0H

    G:0H

    G:0H

    G:0H

    G:0H

    G:0H

    G:0H

    G:0H

    G:0H