Thiết Kế Cấp Điện Cho Trường Trung Học Phổ Thông

MC LC

CHNG I: GII THIU TI ....................................... 2

1.1 GII THIU ................................................ 2

1.2 S MT BNG TRNG HC ................................... 3

CHNG 2: XC NH CNG XUT TNH TON ............................ 4

2.1 GII THIU CC PHNG PHP TNH PH TI TNH TON ........... 4

2.2 XC NH CNG SUT PH TI TNH TON CA TRNG HC ......... 9

2.2.1 CHIA NHM CC PH TI TRONG TRNG HC .................. 9

2.2.2 XC NH CNG SUT T CA TNG NHM ................... 11

S mt bng chiu sng v qut nhm 1: ................... 30

S mt bng chiu sng v qut nhm 2: ................... 44

S mt bng chiu sng v qut nhm 3 .................... 59

Tng Kt Cng Sut t Ca Cc Nhm Ph Ti: ................ 65

2.2.3 XC NH CNG SUT TNH TON CA TRNG HC ........... 66

CHNG 3: CHN PHNG N CUNG CP IN CHO TRNG HC ............ 71

3.1 CC PHNG N CUNG CP IN. ............................... 71

3.2 LA CHN PHNG N CP IN CHO TRNG HC ................. 75

S Tng Qut Ca Trng Hc. .............................. 75

S Mt Bng i Dy Tng Th ............................... 76

S mt bng i dy khi thc hnh: ........................ 77

S Mt Bng i Dy Khi Phng Hc: ........................ 81

CHNG 4: CHN THIT B CHO MNG IN ............................ 84

4.1 CHN DY DN ............................................... 84

4.1.1 PHNG PHP LC CHN TIT DIN DY DN. ................ 84

4.1.2 LA CHN TIT DIN DY DN. ............................ 88

4.1.3 KIM TRA TN THT IN P ............................... 102

4.2 CHN MY BIN P .......................................... 110

4.3 CHN CB (APTOMAT) ......................................... 113

4.3.1 TNG TR MNG IN. ................................... 113

4.3.2 TNH TON NGN MCH ................................... 115

4.3.3 LA CHN CB. .......................................... 119

S Nguyn L: .............................................. 126

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CHNG 5: CHNG ST ............................................. 127

5.1 TNH TON CHIU CAO CT THU ST ........................... 127

5.2 CHN CP DN ST .......................................... 132

5.3 H THNG TIP T CHNG ST ............................... 132

5.3.1 Tm Tt L Thuyt V Ni t Chng St ................ 132

5.3.2 Thit K Ni t Cho Trng Hc ....................... 135

KT LUN ...................................................... 137

TI LIU THAM KHO ............................................ 138

N 2A

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CHNG I: GII THIU TI

1.1 GII THIU

Trng hc trung hc ph thng c khu nh chnh gm ba tng, mi tng c cc phng hc ,

phng dnh cho gio vin , phng dng c h tr vic hc tp v ging dy, phng thc

hnh ...Ph ti chnh ca trng hc ch yu l ph ti chiu sng v qut, my lnh.

Sau y l din tch ca tng khu vc trong trng hc

Tng trt bao gm phng hc v phng hnh chnh tng din tch :23402m

Tng mt bao gm cc phng hc v phng hnh chnh tng din tch :23002m

Tng hai bao gm cc phng hc v phng hnh chnh tng din tch :23002m

Din tch sn trng :24782m

Khu thc hnh c din tch :din tch 7752m /1 lu

Sn tp th thao :din tch 6002m

Sn thi u :din tch 600 2m

Nh s l nc cp: din tch 242m

Nh s l nc thi : din tch 322m

Nh xe hc sinh : din tch 4802m

Nh xe gio vin: din tch 2402m

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1.2 S MT BNG TRNG HC

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4

CHNG 2: XC NH CNG XUT TNH TON

2.1 GII THIU CC PHNG PHP TNH PH TI TNH TON

Hin nay c nhiu phng php tnh ph ti tnh ton. Nhng phng php n gin, tnh

ton thun tin, thng kt qu khng tht chnh xc. Ngc li, nu chnh xc c

nng cao th phng php phc tp. V vy ty theo giai on thit k, yu cu c th m

chn phng php tnh cho thch hp. Sau y l mt s phng php thng dng nht:

2.1.1 Xc nh Ph Ti Tnh Ton Theo Cng Sut t V H S Nhu Cu.

Cng thc tnh:

Ptt= knc.

Qtt=Ptt.tg

Stt=

=

Mt cch gn ng c th ly P=Pm.

Do Ptt=knc.

Trong :

Pi ,Pmi cng sut t v cng sut nh mc ca thit b th i, kW;

Ptt , Qtt, Stt cng sut tc dng, phn khng v ton phn tnh ton ca nhm thit b,kW,

kVAr, kVA;

n s thit b trong nhm.

Nu h s cos ca cc thit b trong nhm khng ging nhau th phi tnh h s cng sut

trung bnh theo CT sau:

H s nhu cu ca cc my khc nhau thng cho trong cc s tay.

Phng php tnh ph ti tnh ton theo h s nhu cu c u im l n gin, thun tin, v

th n l mt trong nhng phng php c dng rng ri. Nhc im ca phng php

ny l km chnh xc. Bi v h s nhu cu knc tra c trong s tay l mt s liu c nh

cho trc khng ph thuc vo ch vn hnh v s thit b trong nhm my. M h s

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5

knc=ksd.kmax c ngha l h s nhu cu ph thuc vo nhng yu t k trn. V vy, nu ch

vn hnh v s thit b nhm thay i nhiu th kt qu s khng chnh xc.

2.1.2 Xc nh ph ti tnh ton theo sut ph ti trn mt n v din tch sn xut .

Cng thc:

Ptt=p0.F

Trong :

P0- sut ph ti trn 1m2 din tch sn xut, kW/m2;

F- din tch sn xut m2 ( din tch dng t my sn xut ).

Gi tr p0 co th tra c trong s tay. Gi tr p0 ca tng loi h tiu th do kinh nghim

vn hnh thng k li m c.

Phng php ny ch cho kt qu gn ng , nn n thng c dng trong thit k s

b hay tnh ph ti cc phn xng c mt my mc sn xut phn b tng i u,

nh phn xng gia cng c kh, dt, sn xut t, vng bi.

2.1.3 Xc nh ph ti tnh ton theo sut tiu hao in nng cho mt n v sn phm

Cng thc tnh:

Ptt=

Trong :

M- s n v sn phm c sn xut ra trong 1 nm (sn lng);

w0- sut tiu hao in nng cho mt n v sn phm, kWh/n v sp;

Tmax- thi gian s dng cng sut ln nht, h

Phng php ny thng c dng tnh ton cho cc thit b in c th ph ti

t bin i nh: qut gi, bm nc, my kh nn. Khi ph ti tnh ton gn bng ph

ti trung bnh v kt qu tng i trung bnh.

2.1.4 Xc nh ph ti tnh ton theo h s cc i kmax v cng sut trung bnh Ptb

(cn gi l phng php s thit b hiu qu nhq).

Khi khng c cc s liu cn thit p dng cc phng php tng i n gin

nu trn, hoc khi cn nng cao trnh chnh xc ca ph ti tnh ton th nn dng

phng php tnh theo h s i.

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Cng thc tnh:

Ptt=kmax.ksd.Pm

Trong :

Pm- cng sut nh mc, W;

kmax, ksd- h s cc i v h s s dng

h s s dng ksd cacc nhm my c th tra trong s tay.

Phng php ny cho kt qu tng i chnh xc v khi xc nh s thit b hiu qu

nhq chng ta xt ti mt lot cc yu t quan trng nh nh hng ca s lng thit b

trong nhm,s thit b c cng sut ln nht cng nh s khc nhau v ch lm vic ca

chng.

Khi tnh ph ti theo phng php ny,trong mt s trng hp c th ma dng cc

phng php gn ng nh sau:

Trng hp n 3 v nhq < 4, ph ti tnh theo cng thc:

Ptt=.

i vi thit b lm vic ch ngn hn lp li th:

Stt=

Trng hp n > 3 v nhq < 4, ph ti tnh theo cng thc:

Ptt=.

Trong :

Kpt- h s ph ti ca tng my

Nu khng c s liu chnh xc, c th tnh gn ng nh:

Kpt=0,9 i vi thit b lm vic ch di hn

Kpt=0,75 i vi thit b lm vic ch ngn hn lp li

nhq > 300 v ksd < 0,5 th h s cc i kmax c ly ng vi nhq = 300. Cn khi

nhq > 300 v ksd 0,5 th:

Ptt=1,05.ksd.Pm

i vi cc thit b c th ph ti bng phng ( cc my bm, qut nn

kh,) ph ti tnh ton c th ly bng ph ti trung bnh:

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Ptt = Ptn = ksd.Pm

Nu trong mng c cc thit b mt pha th phi c gng phn phi u cc thit

b ln ba pha ca mng.

2.1.5 Phng php tnh ton chiu sng:

Co nhieu phng phap tnh toan chieu sang nh:

- Lien Xo co cac phng phap tnh toan chieu sang sau:

+ Phng phap he so s dung.

+ Phng phap cong suat rieng.

+ Phng phap iem.

- My co cac phng phap tnh toan chieu sang sau:

+ Phng phap quang thong.

+ Phng phap iem.

- Con Phap th co cac phng phap tnh toan chieu sang sau:

+ Phng phap he so s dung.

+ Phng phap iem.

va ca phng phap tnh toan chieu sang bang cac pham mem chieu sang.

Tnh toan chieu sang theo phng phap he so s dung gom co cac bc:

1/ Nghien cu oi tng chieu sang.

2/ La chon o roi yeu cau.

3/ Chon he chieu sang.

4/ Chon nguon sang.

5/ Chon bo en.

6/ La chon chieu cao treo en:

Tuy theo: ac iem cua oi tng, loai cong viec, loai bong en, s giam choi, be

mat lam viec. Ta co the phan bo cac en sat tran (h=0) hoac cach tran mot khoang h.

Chieu cao be mat lam viec co the tren o cao 0.8 m so vi san (mat ban) hoac ngay tren

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san tuy theo cong viec. Khi o o cao treo en so vi be mat lam viec: htt= H - h-0.8

(vi H: chieu cao t san en tran).

Can chu y rang chieu cao htt oi vi en huynh quang khong c vt qua 4 m,

neu khong o sang tren be mat lam viec khong u. Con oi vi cac en thuy ngan cao

ap, en halogen kim loai nen treo tren o cao t 5m tr len e tranh choi.

7/ Xac nh cac thong so ky thuat anh sang:

- Tnh ch so a iem: ac trng cho kch thc hnh hoc cua a iem

)( bah

abK

tt

Vi: a,b chieu dai va rong cua can phong; htt chieu cao h tnh toan

- Tnh he so bu: da vao bang phu luc 7 cua tai lieu [2].

- Tnh ty so treo:

tthh

hj

'

'

Vi: h chieu cao t be mat en en tran.

Xac nh he so s dung:

Da tren cac thong so: loai bo en, ty so treo, ch so a iem, he so phan

xa tran, tng, san ta tra gia tr he so s dung trong cac bang do cac nha che tao

cho san.

8/ Xac nh quang thong tong yeu cau:

U

SdEtctong

Trong o: Etc o roi la chon theo tieu chuan (lux)

S dien tch be mat lam viec (m2).

d he so bu.

tong quang thong tong cac bo en (lm).

9/ Xac nh so bo en:

bocacbong

tong

bodenN1/

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Kiem tra sai so quang thong:

%100..

%1/

tong

tongbocacbongbodenN

Trong thc te sai so t 10% en 20% th chap nhan c.

10/ Phan bo cac bo en da tren cac yeu to:

- Phan bo cho o roi ong eu va tranh choi, ac iem kien truc cua oi tng,

phan bo o ac.

- Thoa man cac yeu cau ve khoang cach toi a gia cac day va gia cac en

trong mot day, de dang van hanh va bao tr.

11/ Kiem tra o roi trung bnh tren be mat lam viec:

Sd

UNE

bocacbongboden

tb

.. 1/

2.2 XC NH CNG SUT PH TI TNH TON CA TRNG HC

2.2.1 CHIA NHM CC PH TI TRONG TRNG HC

tin cho vic xc nh ph ti tnh ton v cp in cho trng ta c th chia ph ti ra

lm 5 nhm nh sau:

-Nhm I :

+Tng trt gm: phng hc 1, phng hc 2, phng hc 3, phng hc 4, phng

y t , vn phng on i, phng hnh chnh t chc, phng gio v gim th, phng

tip khch , phng truyn thng , phng v sinh gio vin.

+Tng 1 gm: phng hc 1, phng hc 2, phng hc 3, phng hc 4, 2 phng

ngh gio vin, phng gio vin, phng hiu ph 1, phng hiu ph 2, phng gim

hiu v snh chung, phng hiu trng, phng hi ng, phng v sinh gio vin.

+Tng 2 gm: phng hc 1, phng hc 2, phng hc 3, phng hc 4, 2 phng

dng c ging dy, phng hc 18, phng hc 17, phng hc 16, phng hc 15, kho

chung.

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+Chiu sng ngoi tri

-Nhm II:

+Tng trt gm: phng hc 5, phng hc 6, phng hc 7, phng hc 8, phng

hc 9, phng hc 10, phng hc 11, phng hc 12, kho chung , nh v sinh, phng

thit b dy hc, nh v sinh.

+tng 1 gm: phng c hc sinh, phng c gio vin, kho sch phng nghe

nhn, 2 nh v sinh, phng hc 5, phng hc 6, phng hc 7, phng hc 8, phng hc

9, phng hc 10.

+Tng 2 bao gm: phng hc 5, phng hc 6, phng hc 7, phng hc 8, kho

chung, 2 nh v sinh, phng hc 9, phng hc 10, phng hc 11, phng hc 12,

phng hc 13, phng hc 14.

-Nhm III: Khi thc hnh

+Tng trt: phng v sinh, phng LAB, 2 phng chun b, phng hc b mn

tin hc 1, phng gio vin, phng hc b mn tin hc 2, kho chung , phng chun b ,

phng m nhc.

+Tng 1: nh v sinh, phng hc b mn l,4 phng chun b-kho, phng hc

a phng tin (multimedia), phng hc n cng, phng gio vin, phng chun b

th nghim, phng thc hnh ha, phng hc mn sinh, kho chung.

+Tng 2: nh v sinh , phng phc v -kho, phng chun b, sn khu , ging

ng 300 ch, phng gii lao.

-Nhm IV: Trm s l nc thi v nh gi xe hc sinh.

-Nhm V: Trm s l nc cp-trm bm, nh gi xe gio vin.

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2.2.2 XC NH CNG SUT T CA TNG NHM

1) Nhm I:

*Tng trt nhm 1:

+Phng hc: c 4 phng hc mi phng c din tch 552m ta tin hnhtnh ton

chiu sng theo phng php ri tiu chun nh sau:

Kch thc phng hc:

Chiu di: a=8 (m), chiu rng: b=6.9(m), chiu cao:3.5(m) ,din tch phng S=55.22( )m

Th tch phng T=193 3m

ri yu cu: 300( )tcE lux theo TCVN 8794

-Chn h chiu sng chung , khng nhng b mt lm vic c chiu sng m tt c mi

ni trong phng c chiu sng .

-Chn bng n loi bng hunh quang mu trng ngy 6500k (standard 26mm) Ra=75p,

P=36w, d =2500(lm).

-Chn b n loi profil paralume laque , cp b n : 0.58D, hiu sut trc tip 0.58d

, s n trn b:2 , quang thng cc bng trn mt b :5000(lm) ,

max max1.35 , 1.6doc tt ngang ttL h L h

-Phn b cc n : cch trn h=0 , b mt lm vic:0.8(m) ,chiu cao n so vi b mt lm

vic : 2.7( )tth m

-Ch s a im: ( )tt

abK

h a b

8.6,91.37

2.7(8 6,9)

-H s b d=1.25 t bi (tra bng)

-T s treo '

0' tt

hj

h h

-h s s dng : u d d i iK u u

trong : ,d i -hiu sut trc tip v gin tip ca b n

,d iu u -h s c ch ng vi nhm trc tip v gin tip

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Ta c :H s phn x trn (mu trng) 0.7tran (tra bng)

H s phn x tng (vt liu xi mng) 0.5tuong (tra bng)

H s phn x sn (vt liu gch) 0.2san (tra bng)

T ch s a im K=1,37, cp b n : 0.58D v h s phn x trn ,tng , sn ta tra bn

c gi tr du =0.73

0,58.0.73 0.42uK

-Quang thng tng ca phng :. . 300.55,2.1,25

492860,42

tctong

u

E S d

K (lm)

-T quang thng tng ta xc nh c s b n cn lp t

/

tong

boden

cacbong bo

N

=49286

5000 =9.8

Cn phi lp t thm mt b n pha trn ca bn tng sng cho bng.

Vy s b n cn lp l 11bodenN b

Vy ta c cng sut chiu sng ca mi phng nh sau:

/1 11.2.36 792cs phongP W

Tng trt c tt c 4 phng hc c din tch v chc nng ging nhau nn ta c:

4 4.792 3168tret cs phonghocP W

-Ph ti ng lc:

Ta chn qut lp t cho phng l qut trn v theo kinh nghim ta ly gn ng l

30-50m2/1 qut trn.

Chn loi qut treo trn c cng sut P=61W lu lng gi Q=213(m3/min)

Mi phng hc c trang b 2 qut treo trn mi qut c cng sut P=61W vy ta c cng

sut ph ti ca 1 phng hc l _ _1 122ttret dl phonghocP W

=>_ _ 4 4.122 488ttret dl phonghocP W

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- Phng hc c trang b lp t 2 cm in loi cm 2 chu 16A Sino S18AU3.

300ocamP W

T cng sut chiu sng csP v cng sut ng lc dlP ta c cng sut tng ca 4 phng hc

nh sau:

_ _ 4ttret tong phonghocP _ _ 4 _dl_ 4phonghocttret cs phonghoc ttretP P 3168+488+300=3956 W

+Phng y t : di a=6,7 ,rng b=3,8 , din tch s=25,84m2 , th tch T=89m3,

200( )tcE lux , bng n loi bng hunh quang mu trng ngy 6500k (standard 26mm)

Ra=75p, P=36w, d =2500(lm), b n loi profil paralume laque , cp b n : 0.58D,

quang thng cc bng trn mt b :5000(lm) , 2.7( )tth m , Ch s a im:

( )tt

abK

h a b

6,7.3,80.89

2.7(6,7 3,8)

, 0.7tran , 0.5tuong , 0.2san , du

=0,59, t s treo j=0, h s s dng 0,58.0,59 0.3422uK , h s b d=1.25 , quang

thng tng . . 200.25,84.1,25

188870,3422

tctong

u

E S d

K (lm),

T quang thng tng ta xc nh c s b n cn lp t

/

188773,77

5000

tong

boden

cacbong bo

N

=>S b n cn lp t l 4 b.

=> Vy ta c cng sut chiu sng ca phng : tret_ _ 4.2.36 288cs phongyteP W

-Ph ti ng lc: Ta chn qut lp t cho phng l qut treo tng v theo kinh nghim

ta ly gn ng l 30-50m2/1 qut .

Ta trang b cho phng 1 qut treo tng c cng sut P=46W vy ta c cng sut ph ti

ca phng y t l _ _phongyte 46ttret dlP W


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600ocamP W

T cng sut chiu sng csP v cng sut ng lc dlP ta c cng sut tng ca phng y t

nh sau:

_ _phongytettret tongP _ _phongyte _dl_phongytettret cs ttretP P 288+46+600=934 W

+ Vn phng on i: di a=6,7 ,rng b=3,8 , din tch s=25,84 , th tch T=89m3,



quang thng cc bng trn mt b :5000(lm) , 2.7( )tth m , Ch s a im:

( )tt

abK

h a b

6,7.3,80.89

2.7(6,7 3,8)


=0,59, t s treo j=0, h s s dng 0,58.0,59 0.3422uK , h s b d=1.25 , quang

thng tng . . 300.25,84.1,25

283170,3422

tctong

u

E S d

K (lm),


/

283175,66

5000

tong

boden

cacbong bo

N


=> Vy ta c cng sut chiu sng ca phng :

tret_ _vanphongdoandoi 6.2.36 432csP W

-Ph ti ng lc: Ta chn qut lp t cho phng l qut trn v theo kinh nghim ta ly

gn ng l 30-50m2/1 qut

vn phng on i c trang b 1 qut treo trn c cng sut P=61W vy ta c cng sut

ph ti ca vn phng on i l _ _vanphongdoandoi 61ttret dlP W


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300ocamP W

T cng sut chiu sng csP v cng sut ng lc dlP ta c cng sut tng ca vn phng

on i nh sau:

_ _vanphongdoandoi _ _vanphongdoandoi _dl_vanphongdoandoittret tong ttret cs ttretP P P 432+61+300=793W

+Phng hnh chnh t chc: di a=6,7 ,rng b=7,9 , din tch s=52,93 , T=185m3



quang thng cc bng trn mt b :5000(lm) , 2.7( )tth m , ch s a im:

( )tt

abK

h a b

6,7.7,91,34

2.7(6,7 7,9)


=0,73, t s treo j=0, h s s dng 0,58.0,73 0,4234uK , h s b d=1.25 , quang

thng tng . . 300.52,93.1,25

477650,4234

tctong

u

E S d

K (lm),


/

477659,55

5000

tong

boden

cacbong bo

N


=> Vy ta c cng sut chiu sng ca phng :

tret_ _ 10.2.36 720cs phonghanhchanhtochucP W

Ph ti ng lc: Ta chn qut lp t cho phng l qut trn v theo kinh nghim ta ly


Phng hnh chnh t chc c trang b 2 qut treo trn mi qut c cng sut P=61W vy

ta c cng sut ph ti ca Phng hnh chnh t chc l _ _phonghanhchanhtochuc 122ttret dlP W


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600ocamP W

-T cng sut chiu sng csP v cng sut ng lc dlP ta c cng sut tng ca phng hnh

chnh t chc nh sau:

_ _phonghanhchanhtochuc _ _phonghanhchanhtochuc _dl_phonghanhchanhtochucttret tong ttret cs ttretP P P

=720+122+600=1442 W

+Phng gio v -gim th: di a=6,7 ,rng b=3,9 , din tch s=26,13 , T=92m3




( )tt

abK

h a b

6,7.3,90,91

2.7(6,7 3,9)



thng tng . . 300.26,13.1,25

255980,3828

tctong

u

E S d

K (lm),


/

255985,1

5000

tong

boden

cacbong bo

N


=> Vy ta c cng sut chiu sng ca phng : tret_ _ 6.2.36 432cs phonggiaovugiamthiP W



Phng gio v -gim th c trang b 1 qut treo trn qut c cng sut P=61W vy ta c

cng sut ph ti ca phng gio v -gim th l _ _phonggiamthi 61ttret dlP W

- to khng kh mt m cho phng ta lp thm my lnh cho phng. Theo kinh nghim th

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ta c 40-45m3/1HP . Ta chn loi m lnh TOSHIBA RAS-18N3KCV-V/18N3ACV-V

cng sut 2 HP lp cho phng. T th tch ca phng ta c th lp t cho phng 2 my

lnh . Vy cng sut my lnh ca phng l P=3000 W.


800ocamP W

-T cng sut chiu sng csP v cng sut ng lc dlP ta c cng sut tng ca phng gio

v -gim th nh sau:

_ _phonghanhchanhtochuc _ _phonggiamthi _dl_phonggiamthittret tong ttret cs ttretP P P

=432+61+3000+800=4293 W

+Phng tip khch: di a=4,8 ,rng b=3,9 , din tch s=18,72 ,T=66m3




4,8.3,90.797

( ) 2,7.(4,8 3,9)tt

abK

h a b



thng tng . . 300.18,72.1,25

205140,3422

tctong

u

E S d

K (lm),


/

205144,1

5000

tong

boden

cacbong bo

N


=> Vy ta c cng sut chiu sng ca phng : tret_ _ 4.2.36 288cs phongtiepkhachP W



N 2A

18

Phng tip khch c trang b 1 qut treo trn qut c cng sut P=61W vy ta c cng

sut ph ti ca phng tip khch l _ _phongtiepkhach 61ttret dlP W

- to khng kh mt m cho khch ch ta lp thm my lnh cho phng. Theo kinh

nghim th ta c 40-45m3/1HP . Ta chn loi m lnh TOSHIBA RAS-18N3KCV-

V/18N3ACV-V cng sut 2 HP lp cho phng. T th tch ca phng ta c th lp t

cho phng 1 my lnh . Vy cng sut my lnh ca phng l P=1500 W.


v -gim th nh sau:

_ _ _ _ _dl_ttret tong phongtiepkhach ttret cs phongtiepkhach ttret phongtiepkhachP P P

=288+61+1500=1849 W

+Phng truyn thng : di a=6,7 ,rng b=7,8 , din tch s=52,26 ,T=183m3




6,7.7,81,34

( ) 2,7.(6,7 7,8)tt

abK

h a b


=073, t s treo j=0, h s s dng 0,58.0,73 0.4234uK , h s b d=1.25 , quang

thng tng . . 300.52,26.1,25

453230,4324

tctong

u

E S d

K (lm),


/

453239,06

5000

tong

boden

cacbong bo

N


=> Vy ta c cng sut chiu sng ca phng : tret_ _ 9.2.36 648cs phongtruyenthongP W


N 2A

19


Phng truyn thng c trang b 2 qut treo trn qut c cng sut P=61W vy ta c cng

sut ph ti ng lc ca truyn thng l _ _p 122ttret dl truyenthongP W


300ocamP W


v -gim th nh sau:

_ _ _ _ _dl_ttret tong ptruyenthong ttret cs ptruyenthong ttret ptruyenthongP P P

=648+122+300=1070 W

+Nh v sinh: di a=4,8 ,rng b=3,9 , din tch s=18,72 ,T=65,52m3 ,




4,8.3,90.797

( ) 2,7.(4,8 3,9)tt

abK

h a b



thng tng . . 100.18,72.1,25

68380,3422

tctong

u

E S d

K (lm),


/

68381,36

5000

tong

boden

cacbong bo

N


=> Vy ta c cng sut chiu sng ca phng : ttret_ _nhavesinh 2.2.36 144csP W

Ph ti ng lc: Nh v sinh cn lp t qut thng gi

N 2A

20

Bi s trao i khng kh ca nh v sinh X=10 ln/gi theo TCVN 5687 2010

T th tch phng ta c th tnh c lng kh lu chuyn ca phng

Tg=T.X=65,52.10=655,2 (m3/h)

Ta chn loi qut thng gi panasonic FV-20RL7 lu lng gi 546 m3/h cng sut

P=20W

Vy ta lp t 1 qut thng gi cho nh v sinh P=20 W

Cng sut tng ca nh v sinh _N1_NVS20 144 164tongP W

Cng sut tng nhm 1 tng trt:

=>_ 1_ tangtret 14501tong NP W

*Tng 1 nhm 1:

+Phng hc: t phng 1 n phng 4 , c din tnh v ri yu cu ging nh cc

phng tng 1 tnh ton trc nn ta c 11bodenN cng sut chiu sng l:

1 4 4.792 3168t cs phonghocP W


gn ng l 30-50m2/1 qut .Chn loi qut trn panasonic F-60MZ2


sut ph ti ca 1 phng hc l 1_ _1 122t dl phonghocP W

=>1_ _ 4 4.122 488t dl phonghocP W


300ocamP W

-T cng sut chiu sng csP v cng sut ng lc dlP ta c cng sut tng ca 4 phng

hc nh sau:

N 2A

21

1_ _ 4t tong phonghocP 1_ _ 4 1_dl_ 4phonghoct cs phonghoc tP P 3168+488+1200=4856 W

+Phng ngh gio vin: c 2 phng ngh gio vin mi phng c kch thc, di

a=3,8 ,rng b=6,7 , din tch s=25,46, T=89m3, 300( )tcE lux , chn bng n loi bng

hunh quang mu trng ngy 6500k (standard 26mm) Ra=75p, P=36w, d =2500(lm),

b n loi profil paralume laque , cp b n : 0.58D, quang thng cc bng trn mt b

:5000(lm) , 2.7( )tth m , ch s a im: 3,8.6,7

0,9( ) 2,7.(3,8 6,7)tt

abK

h a b

,

0.7tran , 0.5tuong , 0.2san , du =0,66, t s treo j=0, h s s dng

0,58.0,66 0,3828uK , h s b d=1.25 , quang thng tng

. . 300.25,46.1,2524941

0,3828

tctong

u

E S d

K (lm),


/

249415

5000

tong

boden

cacbong bo

N


=> Vy ta c cng sut chiu sng ca 1 phng : /1 5.2.36 360cs phongP W

=>Cng sut chiu sng 2 phng ngh gio vin tng 1:

t1_ _ 2phongnghigiaovien 2.360 720csP W



Phng c trang b 1 qut treo trn c cng sut P=61W vy ta c:

1_ _ 2 2.61 122t dl pnghigiaovienP W


300ocamP W

N 2A

22

T cng sut chiu sng csP v cng sut ng lc dlP ta c cng sut tng ca phng nh

sau:

1_ _ 2t tong pnghigiaovienP 1_ _ 2 1_dl_ 2t cs pnghigiaovien t pnghigiaovienP P 720+122+300=1142 W

+Phng gio vin: kch thc, di a=6,7 ,rng b=11,8, din tch s=79,06 , T=277m3,

300( )tcE lux , chn bng n loi bng hunh quang mu trng ngy 6500k (standard

26mm) Ra=75p, P=36w, d =2500(lm), b n loi profil paralume laque , cp b n :

0.58D, quang thng cc bng trn mt b :5000(lm) , 2.7( )tth m , ch s a im:

6,7.11,81,58

( ) 2,7.(6,7 11,8)tt

abK

h a b



thng tng . . 300.79,06.1,25

655340,4524

tctong

u

E S d

K (lm),


/

6553413

5000

tong

boden

cacbong bo

N


=> Vy ta c cng sut chiu sng ca phng : 1_ _ 13.2.36 936t cs phonggiaovienP W



phng c trang b 2 qut treo trn c cng sut P=61W vy ta c:

1_ _ 2.61 122t dl phonggiaovienP W


ta c 40-45m3/1HP . Ta chn loi my lnh Panasonic C45FFH cng sut 5 HP lp cho

phng. T th tch ca phng ta c th lp t cho phng 1 my lnh . Vy cng sut my

lnh ca phng l P=3750 W.

N 2A

23


800ocamP W

-T cng sut chiu sng csP v cng sut ng lc dlP ta c cng sut tng ca phng nh

sau:

1_ _ 1_ _ 1_dl_t tong phonggiaovien t cs phonggiaovien t phonggiaovienP P P =936+122+3750+800=5608W

+Phng hiu ph: kch thc, di a=3,3 ,rng b=3,9, din tch s=12,87 , T=45m3




3,3.3,90,66

( ) 2,7.(3,3 3,9)tt

abK

h a b



thng tng . . 300.12,87.1,25

166420,29

tctong

u

E S d

K (lm),


/

166423,3

5000

tong

boden

cacbong bo

N


=> Vy ta c cng sut chiu sng ca 1 phng : 4.2.36 288phonghieuphoP W

C 2 phng hiu ph , phng hiu ph 1 v phng hiu ph 2 c din tch ging nhau nn ta

c cng sut chiu sng ca 2 phng : 1_ _ 2 2.288 578t cs phonghieuphoP W




N 2A

24

1_ _ 2 2.61 122t dl phonghieuphoP W

- to khng kh mt m cho phng ta lp thm my lnh cho phng. Theo kinh nghim

th ta c 40-45m3/1HP . Ta chn loi my lnh Panasonic KC9QKH-8 cng sut 1 HP

lp cho phng. T th tch ca phng ta c th lp t cho phng 1 my lnh . Vy cng sut

my lnh ca phng l P=750 W.


600ocamP W


sau:

1_ _ 2 1_ _ 2 1_dl_ 2t tong phieupho t cs phieupho t phieuphoP P P =578+122+750+600=2050 W

+Phng hi ng: c kch thc v chiu sng bng phng gio vin nn ta c

1_ _ 13.2.36 936t cs phonghoidongP W



Phng c trang b 2 qut treo trn c cng sut P=61 W

1_ _ 122t dl phonghoidongP W


ta c 40-45m3/1HP . Ta chn loi my lnh Panasonic C45FFH cng sut 5 HP lp cho

phng. T th tch ca phng T=277m3 ta c th lp t cho phng 1 my lnh . Vy cng

sut my lnh ca phng l P=3750 W.


800ocamP W

-T cng sut chiu sng csP v cng sut ng lc dlP ta c cng sut tng ca phng

nh sau:

N 2A

25

1_ _ 1_ _ 1_dl_t tong phoidong t cs phoidong t phoidongP P P =936+122+3750+800=5608 W

+Phng hiu trng: kch thc, di a=4,8 ,rng b=3,9, din tch s=18,72 , T=66m3,




4,8.3,90,79

( ) 2,7.(4,8 3,9)tt

abK

h a b



thng tng . . 300.18,72.1,25

205140,3422

tctong

u

E S d

K (lm),


/

205144,1

5000

tong

boden

cacbong bo

N


=> Vy ta c cng sut chiu sng ca phng : 1_ _ 4.2.36 288t cs phonghieutruongP W




1_ _ 61t dl phonghieutruongP W

- to khng kh mt m cho phng ta lp thm my lnh cho phng. Theo kinh nghim

th ta c 40-45m3/1HP . Ta chn loi my lnh Panasonic KC9QKH-8 cng sut 1 HP

lp cho phng. T th tch ca phng ta c th lp t cho phng 1 my lnh . Vy cng sut

my lnh ca phng l P=750 W.


300ocamP W

N 2A

26

-T cng sut chiu sng csP v cng sut ng lc dlP ta c cng sut tng ca phng

nh sau:

1_ _ 1_ _ 1_dl_t tong phieutruong t cs phieutruong t phieutruongP P P =288+61+750+300=1399W

+Nh v sinh: di a=4,8 ,rng b=3,9 , din tch s=18,72 ,T=65,52m3 ,




4,8.3,90.797

( ) 2,7.(4,8 3,9)tt

abK

h a b



thng tng . . 100.18,72.1,25

68380,3422

tctong

u

E S d

K (lm),


/

68381,36

5000

tong

boden

cacbong bo

N


=> Vy ta c cng sut chiu sng ca phng : _nhavesinh 2.2.36 144csP W

Ph ti ng lc: Nh v sinh cn lp t qut thng gi



Tg=T.X=65,52.10=655,2 (m3/h)


P=20W


N 2A

27

Cng sut tng ca nh v sinh _NVS20 144 164tongP W

Cng sut tng tng 1 nhm 1:

=>_ 1_ tang1 20827tong NP W

*Tng 2 nhm 1:

+Phng hc: c 8 phng hc , phng hc 1, phng hc 2, phng hc 3, phng hc 4,

phng hc 18, phng hc 17, phng hc 16, phng hc 15, din tch ciu sng v ri cc

phng nh tng trt v tng 1 nn ta c cng sut chiu sng ca 4 phng hc nh sau:

11bodenN

2 _ _8 8.792 6336t cs phonghocP W




sut ph ti ca 1 phng hc l 2 _ _1 122t dl phonghocP W

=>2 _ _8 8.122 976t dl phonghocP W


300ocamP W


hc nh sau:

2 _ _8t tong phonghocP 2 _ _8 2 _dl_8phonghoct cs phonghoc tP P 6336+976+2400=9712 W

+Kho dng c ging dy:

C 2 kho dng c ging dy mi phng c kch thc, di a=3,8 ,rng b=6,7 , din tch

s=25,46, T=89m3, 100( )tcE lux , chn bng n loi bng hunh quang mu trng ngy

N 2A

28

6500k (standard 26mm) Ra=75p, P=36w, d =2500(lm), b n loi profil paralume

laque , cp b n : 0.58D, quang thng cc bng trn mt b :5000(lm) , 2.7( )tth m , ch

s a im: 3,8.6,7

0,9( ) 2,7.(3,8 6,7)tt

abK

h a b

, 0.7tran , 0.5tuong ,

0.2san , du =0,66, t s treo j=0, h s s dng 0,58.0,66 0,3828uK , h s b

d=1.25 , quang thng tng . . 100.25,46.1,25

83140,3828

tctong

u

E S d

K (lm),


/

83141,66

5000

tong

boden

cacbong bo

N


=> Vy ta c cng sut chiu sng ca 1 phng : /1 2.2.36 144cs phongP W

=>Cng sut chiu sng 2 kho dng c ging dy:

t 2 _ _ 2 2.144 288cs khodcgiangdayP W

-Ph ti ng lc : Ta chn qut lp t cho phng l qut treo tng v theo kinh nghim

ta ly gn ng l 11-18m2/1 qut .Chn loi qut trn 400E- vinawind cng sut P=46 W

Ta lp t cho phng 2 qut treo tng mi qut cng sut P=46 W

Vy cng sut ng lc tng ca 2 kho dng c ging dy l:

t 2 _dl_ 2 2.(2.46) 184khodcgiangdayP W

T cng sut chiu sng csP v cng sut ng lc dlP ta c cng sut tng ca phng hc

nh sau: 2 _ _ 2khodcgiangday 288 184 472t tongP W

+Kho chung: di a=6,7 ,rng b=3,9 , din tch s=26,13 ,T=91m3, ri yu cu v l

nh kho nn khng cn nhiu nh sng nn ly ri tiu chun l 100( )tcE lux , bng

n loi bng hunh quang mu trng ngy 6500k (standard 26mm) Ra=75p, P=36w, d

N 2A

29

=2500(lm), b n loi profil paralume laque , cp b n : 0.58D, quang thng cc bng

trn mt b :5000(lm) , 2.7( )tth m , ch s a im: ( )tt

abK

h a b

6,7.3,90,91

2.7(6,7 3,9)

, 0.7tran , 0.5tuong , 0.2san , du =0,66, t s treo j=0,

h s s dng 0,58.0,66 0,3828uK , h s b d=1.25 , quang thng tng

. . 100.26,13.1,258533

0,3828

tctong

u

E S d

K (lm),


/

85331,7

5000

tong

boden

cacbong bo

N


=> Vy ta c cng sut chiu sng ca phng : t 2 _cs_khochung 2.2.36 144P W

-Ph ti ng lc Ta chn qut lp t cho phng l qut treo tng v theo kinh nghim ta

ly gn ng l 11-18m2/1 qut .Chn loi qut trn 400E- vinawind cng sut P=46 W


Vy cng sut ng lc ca kho chung l:

t 2 _dl_ 2 92khodcgiangdayP W

Cng sut tng ca tng 2 nhm 1 :

=>_ tang 2 _nhom1 10276tongP W

Thng k ph ti nhm 1:

_ 1_ tangtret 14501tong NP W

_ 1_ tang1 20827tong NP W

_ tang 2 _nhom1 10276tongP W

N 2A

30

3000chieusangngoaiP W

=>_ hom1 48604tong nP W

S mt bng chiu sng v qut nhm 1:

N 2A

31

Tng trt nhm 1:

RA

MP D

OC

C

HO

N

G

I K

HU

YE

T TA

T

i=10%

RA

MP D

OC

C

HO

N

G

I K

HU

YE

T TA

T

i=10%

VACH NGAN

NHOM KNH

VACH NGAN

NHOM KNH

VACH NGAN

NHOM KNH

N 2A

32

Tng 1 nhm 1:

N 2A

33

Tng 2 nhm 1:

i=2%

i=2%

i=2%

i=2%

i=2%

i=2%

CT1

N 2A

34

2) NHM 2:

*Tng trt nhm 2:

-Phng hc: C 8 phng hc bao gm phng hc 5, phng hc 6, phng hc 7, phng

hc 8, phng hc 9, phng hc 10, phng hc 11, phng hc 12 , mi phng c kch thc

nh sau chiu di 8m, rng 6m, din tch S= 255m ta thy chng c cng din tch vi cc

phng hc tnh ton nhm trc v th ta c :

11bodenN

_ _1 792ttret cs phonghocP W

=>_ _8 8.792 6336ttret cs phonghocP W

-Ph ti ng lc : Ta chn qut lp t cho phng l qut trn v theo kinh nghim ta ly



sut ph ti ca 1 phng hc l 2 _ _1 122t dl phonghocP W

=>2 _ _8 8.122 976t dl phonghocP W


300ocamP W


sau:

_ _8 6336 976 2400 9712ttret tong phonghocP W

-kho chung: di a=6,7 ,rng b=3,9 , din tch s=26,13 ,T=91m3, ri yu cu v l nh

kho nn khng cn nhiu nh sng nn ly ri tiu chun l 100( )tcE lux , bng n

loi bng hunh quang mu trng ngy 6500k (standard 26mm) Ra=75p, P=36w, d


N 2A

35

trn mt b :5000(lm) , 2.7( )tth m , ch s a im:

( )tt

abK

h a b

6,7.3,90,91

2.7(6,7 3,9)

, 0.7tran , 0.5tuong , 0.2san ,

du =0,66, t s treo j=0, h s s dng 0,58.0,66 0,3828uK , h s b d=1.25 ,

quang thng tng . . 100.26,13.1,25

85320,3828

tctong

u

E S d

K (lm),


/

85321,7

5000

tong

boden

cacbong bo

N


=> Vy ta c cng sut chiu sng ca phng : ttret_cs_khochung 2.2.36 144P W

-Ph ti ng lc : Ta chn qut lp t cho phng l qut treo tng v theo kinh nghim

ta ly gn ng l 11-18m2/1 qut .Chn loi qut treo tng 400E- vinawind cng sut

P=46 W


Vy cng sut ng lc ca kho chung l

ttret_dl_khochung 92P W


sau:

_ _ 144 92 236ttret tong khochungP W

-Phng thit b dy hc : chiu di a=11,8m chiu rng b=6,7m din tch S=79,062m

,T=277m3, ly ri tiu chun l 200( )tcE lux , chn loi bng n loi bng hunh

quang mu trng ngy 6500k (standard 26mm) Ra=75p, P=36w, d =2500(lm), b n

loi profil paralume laque , cp b n : 0.58D, quang thng cc bng trn mt b

N 2A

36

:5000(lm) , 2.7( )tth m , ch s a im:

( )tt

abK

h a b

11,8.6,71,58

2.7(11,8 6,7)

, 0.7tran , 0.5tuong , 0.2san

, tra c du =0,78, t s treo j=0, h s s dng 0,58.0,78 0,4524uK , h s b

d=1.25 , quang thng tng . . 200.79,06.1,25

436890,4524

tctong

u

E S d

K (lm),


/

436898,7

5000

tong

boden

cacbong bo

N


=> Vy ta c cng sut chiu sng ca phng : ttret_cs_pthietbidayhoc 9.2.36 648P W

-Ph ti ng: Ta chn qut lp t cho phng l qut treo tng v theo kinh nghim ta ly

gn ng l 11-18m2/1 qut .Chn loi qut treo tng 400E- vinawind cng sut

P=46 W

Ta lp t cho phng 4 qut treo tng:

ttret_dl_pthietbidayhoc 4.46 184P W


300ocamP W


sau:

_ _ 648 184 300 1132ttret tong pthietbidayhocP W

-Nh v sinh: di a=4,8 ,rng b=3,9 , din tch s=18,72 ,T=65,52m3 ,



N 2A

37


4,8.3,90.797

( ) 2,7.(4,8 3,9)tt

abK

h a b



thng tng . . 100.18,72.1,25

68380,3422

tctong

u

E S d

K (lm),


/

68381,36

5000

tong

boden

cacbong bo

N



-Ph ti ng lc: Nh v sinh cn lp t qut thng gi



Tg=T.X=65,52.10=655,2 (m3/h)


P=20W



v c 2 nh v sinh nn ta c : _ _ 2 sinh 2.164 328ttret cs nhaveP W

Cng sut tng tng trt nhm 2

2 _ _ tangtret 11408N tongP W

*Tng 1 nhm 2:

N 2A

38

-Phng c (phng c gio vin v phng c hc sinh): c chiu di a=6,7m

chiu rng b=17,9m din tch S=119,932m ly ri tiu chun l 300( )tcE lux , chn

loi bng n loi bng hunh quang mu trng ngy 6500k (standard 26mm) Ra=75p,

P=36w, d =2500(lm), b n loi profil paralume laque , cp b n : 0.58D, quang

thng cc bng trn mt b :5000(lm) , 2.7( )tth m , ch s a im:

( )tt

abK

h a b

17,9.6,71,8

2.7(17,9 6,7)

, 0.7tran , 0.5tuong , 0.2san ,

tra c du =0,84, t s treo j=0, h s s dng 0,58.0,84 0,4872uK , h s b

d=1.25 , quang thng tng . . 300.119,93.1,25

923110,4872

tctong

u

E S d

K (lm),


/

6154012,308

5000

tong

boden

cacbong bo

N


=> Vy ta c cng sut chiu sng ca phng : t1_cs_phongdoc 12.2.36 864P W

-Ph ti ng lc : Ta chn qut lp t cho phng l qut trn v theo kinh nghim ta ly


Lp t cho phng 3 qut treo trn mi qut c cng sut P=61 W.

t1_dl_phongdoc 183P W


800ocamP W


sau:

1_ _ 864 183 800 1847t tong phongdocP W

N 2A

39

-Khoa sch: c chiu di a=6,7m chiu rng b=5,7m din tch S=38,192m ly ri

tiu chun l 100( )tcE lux , chn loi bng n loi bng hunh quang mu trng ngy

6500k (standard 26mm) Ra=75p, P=36w, d =2500(lm), b n loi profil paralume

laque , cp b n : 0.58D, quang thng cc bng trn mt b :5000(lm) , 2.7( )tth m , ch

s a im:

( )tt

abK

h a b

5,7.6,71,14

2.7(5,7 6,7)

, 0.7tran , 0.5tuong , 0.2san ,

tra c du =0,73, t s treo j=0, h s s dng 0,58.0,73 0,4234uK , h s b

d=1.25 , quang thng tng . . 100.38,19.1,25

112740,4234

tctong

u

E S d

K (lm),


/

112742,25

5000

tong

boden

cacbong bo

N


=> Vy ta c cng sut chiu sng ca phng : t1_cs_khosach 2.2.36 144P W



P=46 W

Ta lp t cho phng 3 qut treo tng :

t1_dl_ 3.46 138khosachP W


sau:

1_ _ 144 138 282t tong khosachP W

-Phng nghe nhn: chiu di a=11,8m chiu rng b=6,7m din tch S=79,062m ,

N 2A

40

T=277m3,ly ri tiu chun l 300( )tcE lux , chn loi bng n loi bng hunh

quang mu trng ngy 6500k (standard 26mm) Ra=75p, P=36w, d =2500(lm), b n

loi profil paralume laque , cp b n : 0.58D, quang thng cc bng trn mt b

:5000(lm) , 2.7( )tth m , ch s a im:

( )tt

abK

h a b

11,8.6,71,58

2.7(11,8 6,7)

, 0.7tran , 0.5tuong , 0.2san

, tra c du =0,78, t s treo j=0, h s s dng 0,58.0,78 0,4524uK , h s b

d=1.25 , quang thng tng . . 300.79,06.1,25

655340,4524

tctong

u

E S d

K (lm),


/

6553413,1

5000

tong

boden

cacbong bo

N


=> Vy ta c cng sut chiu sng ca phng : t1_cs_pnghenhin 13.2.36 1008P W

-Ph ti ng lc: phng c 2 qut treo trn v 2 qut treo tng

t1_dl_ 2.61 2.46 214phongnghenhinP W


600ocamP W


sau:

1_ _ 1008 214 600 1822t tong phongnghenhinP W

-Phng hc: c 6 phng hc phng hc 5, phng hc 6, phng hc 7, phng hc 8,

phng hc 9, phng hc10 din tch mi phng nh nhau chiu di 8m, rng 6m, din tch

S= 255m ta thy chng c cng din tch vi cc phng hc tnh ton nhm trc v

N 2A

41

th ta c :

11bodenN

2 _ _1 792t cs phonghocP W

=>2 _ _8 8.792 6336t cs phonghocP W


gn ng l 30-50m2/1 qut .Chn loi qut trn panasonic F-60MZ2 mi qut cng sut

P=61W

Ta lp t cho phng 2 qut treo trn :

t1_dl_8 8.2.61 976phonghocP W


300ocamP W


sau:

1_ _8 6336 976 2400 9712t tong phonghocP W

-Nh v sinh: di a=4,8 ,rng b=3,9 , din tch s=18,72 ,T=65,52m3 , 100( )tcE lux ,

bng n loi bng hunh quang mu trng ngy 6500k (standard 26mm) Ra=75p,

P=36w, d =2500(lm), b n loi profil paralume laque , cp b n : 0.58D, quang

thng cc bng trn mt b :5000(lm) , 2.7( )tth m , ch s a im:

4,8.3,90.797

( ) 2,7.(4,8 3,9)tt

abK

h a b



thng tng . . 100.18,72.1,25

68380,3422

tctong

u

E S d

K (lm),


N 2A

42

/

68381,36

5000

tong

boden

cacbong bo

N






Tg=T.X=65,52.10=655,2 (m3/h)


P=20W



=>c 2 nh v sinh nn ta c : 1_ _ 2 sinh 2.164 328t cs nhaveP W


2 _ _ tang1 13451N tongP W

*Tng 2 nhm 2:

-Phng hc: c 10 phng hc phng hc 5, phng hc 6, phng hc 7, phng hc 8,

phng hc 9, phng hc10, phng hc 11, phng hc 12, phng hc 13, phng hc 14, din

tch mi phng nh nhau chiu di 8m, rng 6m, din tch S= 255m ta thy chng c cng

din tch vi cc phng hc tnh ton nhm trc v th ta c :

11bodenN

2 _ _1 792t cs phonghocP W

=>2 _ _10 10.792 7920t cs phonghocP W

N 2A

43



P=61W

Ta lp t cho mi phng 2 qut treo trn vy cng sut ng lc ca 8 phng hc:

t 2 _dl_10 10.2.61 1220phonghocP W


300ocamP W


sau:

2 _ _10 7920 1220 3000 12140t tong phonghocP W

-Kho chung: di a=6,7 ,rng b=3,9 , din tch s=26,13 ,T=91,5m3, ri yu cu v

l nh kho nn khng cn nhiu nh sng nn ly ri tiu chun l 100( )tcE lux , bng

n loi bng hunh quang mu trng ngy 6500k (standard 26mm) Ra=75p, P=36w, d


trn mt b :5000(lm) , 2.7( )tth m , ch s a im: ( )tt

abK

h a b

6,7.3,90,91

2.7(6,7 3,9)

, 0.7tran , 0.5tuong , 0.2san , du =0,66, t s treo j=0,

h s s dng 0,58.0,66 0,3828uK , h s b d=1.25 , quang thng tng

. . 100.26,13.1,258532

0,3828

tctong

u

E S d

K (lm),


/

85321,7

5000

tong

boden

cacbong bo

N


N 2A

44

=> Vy ta c cng sut chiu sng ca phng : t 2 _cs_khochung 2.2.36 144P W

-Ph ti ng lc phng c 1 qut treo tng :

t 2 _dl_ 46khoachungP W


sau:

2 _ _ 144 46 190t tong khoachungP W


=>2 _ _ tang 2 12330N tongP W

Cng sut tng nhm 2:



2 _ _ tang 2 12330N tongP W

=> _ 2 37189tong NP W

S mt bng chiu sng v qut nhm 2:

N 2A

45

Tng trt nhm 2

RAMP DOC CHO NGI KHUYET TAT RAMP DOC CHO NGI KHUYET TAT

N 2A

46

Tng 1 nhm 2

LAM

CHE NANG

BTCT

LAM

CHE NANG

BTCT

VACH NGAN

NHOM KNH

N 2A

47

Tng 2 nhm 2

3

7

8

8

8

SL1 SL1

N 2A

48

3) Nhm III: Khi thc hnh

*Tng 2 nhm 3:

-Khi thc hnh hnh tng trt bao gm ging ng 300 ch v i snh, phng gii

lao, sn khu, phng chun b, phng phc v-kho tng din tch cn chiu sng l S=645

2m trong chiu di a=43,9 m chiu rng b=14,7m. Ly ri tiu chun l

300( )tcE lux , chn loi bng n loi bng hunh quang mu trng ngy 6500k

(standard 26mm) Ra=75p, P=36w, d =2500(lm), b n loi profil paralume laque ,

cp b n : 0.58D, quang thng cc bng trn mt b :5000(lm) , 2.7( )tth m , ch s a

im:

( )tt

abK

h a b

43,9.14,74,09

2.7(43,7 14,7)

, 0.7tran , 0.5tuong ,

0.2san , tra c du =0,95 , t s treo j=0, h s s dng 0,58.0,95 0,551uK ,

h s b d=1.25 , quang thng tng . . 300.645.1,25

4733370,551

tctong

u

E S d

K (lm),


/

47333795

5000

tong

boden

cacbong bo

N


=> Vy ta c cng sut chiu sng ca tng : t 2 _cs_khoithuchanh 95.2.36 6840P W

Ph ti ng lc: Ta chn qut lp t cho phng l c qut trn v qut treo tng theo

kinh nghim ta ly gn ng l 30-50m2/1 qut trn v 11-18 m3/ 1qut treo tng .Chn

loi qut trn panasonic F-60MZ2 mi qut cng sut P=61W, qut treo tng 400E-

vinawind cng sut P=46 W

Da vo din tch ca phng ta c th lp t cho phng 10 qut treo trn v 10 qut treo

N 2A

49

tng.

t 2 _dl_khoithuchanh 610 460 1070P W


sau:

N3_tang 2_ 6840 1070 7910quatP W

-Ngoi ra do din tch phng qu ln nn ta trang b cho phng 2 cp loa Omaton SUB T-

3600 smaster tng cng sut P=4000W


_ 3_ tang 2 6840 7910 4000 18750tong NP W

*Tng 1 nhm 3:

-Phng hc b mn l,phng a phng tin, phng n cng, phng thc hnh ha,

phng hc b mn sinh, u c din tch ging nhau S=70,212m chiu di a=11,9m chiu

rng b=5,9m ta tin hnh tnh ton chiu sng cho mi phng nh sau:

Ly ri tiu chun l 300( )tcE lux , chn loi bng n loi bng hunh quang

mu trng ngy 6500k (standard 26mm) Ra=75p, P=36w, d =2500(lm), b n loi

profil paralume laque , cp b n : 0.58D, quang thng cc bng trn mt b :5000(lm) ,

2.7( )tth m , ch s a im:

( )tt

abK

h a b

11,9.5,91,4

2.7(11,9 5,9)

, 0.7tran , 0.5tuong , 0.2san ,

tra c du =0,78 , t s treo j=0, h s s dng 0,58.0,78 0,4524uK , h s b

d=1.25 , quang thng tng . . 300.70,21.1,25

581970,4524

tctong

u

E S d

K (lm),


/

5819711,6

5000

tong

boden

cacbong bo

N

N 2A

50


=> Vy ta c cng sut chiu sng ca phng : t1_cs_khoithuchanh 12.2.36 864P W

=>t1_cs_ 5phongkhoithuchanh 5.864 4320P W

-Ph ti ng lc: Ta chn qut lp t cho phng c qut trn v qut treo tng v theo

kinh nghim ta ly gn ng l 30-50m2/1 qut trn, 11-18 m2/ 1 qut treo tng .Chn loi

qut trn panasonic F-60MZ2 mi qut cng sut P=61W, qut treo tng 400E-


Ta lp t cho mi phng 2 qut treo trn v 2 qut treo tng :

Cng sut 1 phng P=2.61+2.46=214 W

=> t1_dl_ 5phongkhoithuchanh 5.214 1070P W

-Ring phng a phng tin c cng sut tng cc my tnh l P=14000 W, v c nhiu

my tnh nn ta lp t thm cho phng h thng my lnh m bo nhit phng n

nh. Theo kinh nghim th ta c 40-45m3/1HP . Ta chn loi m lnh Panasonic C45FFH

cng sut 5 HP lp cho phng. T th tch ca phng T=245 m3 ta c th lp t cho

phng 1 my lnh . Vy tng cng sut my lnh ca phng l P=3750 W.

- Mi phng hc c trang b lp t 2 cm in loi cm 2 chu 16A Sino S18AU3.

800ocamP W


nh sau:

_ 3_ 5 1tong N phongTP 4320+1070+14000+3750+4000=27140 W

-5 phng chun b kho v 1 phng kho chung c din tch ging nhau S=232m

,T=81m3, chiu di a=3,9m chiu rng b=5,9m ta tin hnh tnh ton chiu sng cho mi

phng nh sau:

ri yu cu v l nh kho nn khng cn nhiu nh sng nn ly ri tiu chun l


N 2A

51



( )tt

abK

h a b

5,9.3,90,87

2.7(5,9 3,9)



thng tng . . 100.23.1,25

84020,3422

tctong

u

E S d

K (lm),


/

84021,7

5000

tong

boden

cacbong bo

N


=> Vy ta c cng sut chiu sng ca phng : t1_cs_1nhakho 2.2.36 144P W

=>t1_cs_ 6nhakho 6.144 864P W



P=46 W

Ta lp t cho mi phng 2 qut treo tng =>cng sut qut mi phng l P=92 W

=>Ta c cng sut qut ca 6 phng l: t1_dl_ 6nhakho 6.92 552P W


300ocamP W


nh sau:

_ 3_ 6phong 1tong N TP 864+552+1800=3216 w

-Nh v sinh:di a=4,8 ,rng b=3,9 , din tch s=18,72 ,T=65,52m3 ,

N 2A

52




4,8.3,90.797

( ) 2,7.(4,8 3,9)tt

abK

h a b



thng tng . . 100.18,72.1,25

68380,3422

tctong

u

E S d

K (lm),


/

68381,36

5000

tong

boden

cacbong bo

N






Tg=T.X=65,52.10=655,2 (m3/h)


P=20W



-Hnh lang: c din tch S=130 2m chiu di a=52m chiu rng b=2,5m ta tin

hnh tnh ton chiu sng cho mi phng nh sau:

ri yu cu v l hnh lang nn khng cn nhiu nh sng nn ly ri tiu chun l

N 2A

53




( )tt

abK

h a b

52.2,50,88

2.7(52 2,5)

, 0.7tran , 0.5tuong , 0.2san , tra

c du =0,59, t s treo j=0, h s s dng 0,58.0,59 0,3422uK , h s b d=1.25 ,

quang thng tng . . 100.130.1,25

474890,3422

tctong

u

E S d

K (lm),


/

474899,4

5000

tong

boden

cacbong bo

N


=> Vy ta c cng sut chiu sng ca hnh lang : t1_cs_hanhlang 10.2.36 720P W

Tng cng sut tng 1 nhm 3:


*Tng trt nhm 3:

-2 phng gm: phng LAB v phng m nhc c din tch bng nhau S=69,622m

,T=244m3, chiu di a=11,8m chiu rng b=5,9m

. ri yu cu ,ly ri tiu chun l 300( )tcE lux , bng n loi bng hunh quang



2.7( )tth m , ch s a im: ( )tt

abK

h a b

11,8.5,91,45

2.7(11,8 5,9)

, 0.7tran ,

0.5tuong , 0.2san , tra c du =0,78, t s treo j=0, h s s dng

N 2A

54


. . 300.69,62.1,2557709

0,4524

tctong

u

E S d

K (lm),


/

5770911,5

5000

tong

boden

cacbong bo

N


=> Vy ta c cng sut chiu sng ca phng : ttret_cs1 12.2.36 864P W

=> ttret_ 2pcs1 2.864 1728P W



P=61W

Ta lp t cho mi phng 2 qut treo trn mi qut cng sut P=61W =>cng sut mi

phng P=122W

=>Cng sut qut ca 2 phng l P=244W

-Phng LAB c cng sut tng cc my tnh trong phng l P=14000 W . Do phng c

nhiu my tnh nn cn lp t thm cho phng h thng my lnh. Theo kinh nghim th ta

c 40-45m3/1HP . Ta chn loi m lnh Panasonic C45FFH cng sut 5 HP lp cho

phng. T th tch ca phng T=244 m3 ta c th lp t cho phng 1 my lnh . Vy tng

cng sut my lnh ca phng l P=3750 W.


600ocamP W


nh sau:

_ 3_ 2phongtrettong NP 1728+244+14000+3750+1200=20922 W

N 2A

55

-4 phng gm: 2 phng chun b, kho chung v phng gio vin c din tch bng

nhau S=232m chiu di a=3,9m chiu rng b=5,9m, T=81m3

ri yu cu ,ly ri tiu chun l 300( )tcE lux , bng n loi bng hunh quang




abK

h a b

3,9.5,90,86

2.7(3,9 5,9)

, 0.7tran ,



. . 300.23.1,2525205

0,3422

tctong

u

E S d

K (lm),


/

252055

5000

tong

boden

cacbong bo

N


=> Vy ta c cng sut chiu sng ca phng : ttret_cs2 5.2.36 360P W

=> ttret_ 4pcs2 4.360 1440P W

-Ph ti ng lc: Ta chn qut lp t cho phng l qut trn v qut treo tng v theo

kinh nghim ta ly gn ng l 30-50m2/1 qut trn v 11-18 m2/ qut treo tng .Chn loi

qut trn panasonic F-60MZ2 mi qut cng sut P=61W, qut treo tng 400E-


Phng gio vin lp 1 qut trn P=61 W, 3 phng kho cn li mi phng lp 2 qut treo

tng cng sut qut mi phng P=92 W ta c cng sut qut tng ca 4 phng l P=153 W


300ocamP W

N 2A

56


nh sau:

_ 3_ 4phong 2tong N TP 1440+153+1200=2793 W

-Kho chung: S=232m chiu di a=3,9m chiu rng b=5,9m, T=81m3





abK

h a b

3,9.5,90,86

2.7(3,9 5,9)

, 0.7tran ,



. . 100.23.1,258402

0,3422

tctong

u

E S d

K (lm),


/

84021,68

5000

tong

boden

cacbong bo

N


=> Vy ta c cng sut chiu sng ca phng : ttret_khochung 2.2.36 144P W



P=46 W

Ta lp cho phng 2 qut treo tng, vy tng cng sut qut ca phng P=92 W


sau:

_ 3_tong N khottretP 144+92=236 W

N 2A

57

-2 phng gm: phng b mn tin hc 1 v phng b mn tin hc 2 c din tch ging

nhau S=93,812m chiu rng a=15,9m chiu di b=5,9m,T=328m3





abK

h a b

15,9.5,91,59

2.7(15,9 5,9)

, 0.7tran ,



. . 300.93,81.1,2577760

0,4524

tctong

u

E S d

K (lm),


/

7776015,5

5000

tong

boden

cacbong bo

N


=> Vy ta c cng sut chiu sng ca phng : t 2 _cs3 16.2.36 1152P W

=> t 2 _ 2pcs3 2.1152 2304P W



P=61W

Vy ta lp cho phng 3 qut treo trn tng cng sut qut mi phng l P=183 W

=>cng sut qut ca 2 phng l P=366W

-2 phng tin hc c cng sut tng ca cc my tnh trong phng P=28000W. Do phng c

nhiu my tnh nn cn lp t thm h thng my lnh cho phng. Theo kinh nghim th ta

c 40-45m3/1HP . Ta chn loi my lnh LG C306HLA0 cng sut 3,5 HP lp cho

phng. T th tch ca phng T=328 m3 ta c th lp t cho mi phng 2 my lnh . Vy

N 2A

58

tng cng sut my lnh ca 2 phng l P=10500 W.

T cng sut chiu sng csP v cng sut ng lc dlP ta c cng sut tng ca 4 phng

nh sau:

_ 3_ 2phongttrettong NP 2304+366+28000+10500=41170 W

-i snh c din tch S=46,022m chiu di a=7,8 chiu rng b=5,9 v T=161m3





abK

h a b

7,8.5,91,2

2.7(7,8 5,9)

, 0.7tran ,



. . 150.46,02.1,2520380

0,4234

tctong

u

E S d

K (lm),


/

203804

5000

tong

boden

cacbong bo

N


=> Vy ta c cng sut chiu sng ca phng : t 2 _daisanh 4.2.36 288P W



P=61W

Vy ta lp cho phng 2 qut treo trn tng cng sut qut i snh l P=122 W

T cng sut chiu sng csP v cng sut ng lc dlP ta c cng sut tng ca 4 phng

nh sau:

N 2A

59

_ 3_tong N daisanhttretP 288+122=410 W

Tng cng sut tng trt nhm 3:


Tng cng sut nhm 3:

_ 3_ tang 2 18750tong NP W



=> 3_ 114637N tongP W

S mt bng chiu sng v qut nhm 3

N 2A

60

Tng trt nhm 3

RAM

P DOC CHO NGI KHUYET TAT

N 2A

61

Tng 1 nhm 3

1400

N 2A

62

Tng 2 nhm 3

1500

N 2A

63

4) Nhm IV: Trm s l nc thi v nh gi xe hc sinh.

-Trm s l nc thi c cng sut t l 10tramsulynuocP KW

-Nh xe hai bnh c din tch S=19,22m chiu di a=12m chiu rng b=1,6m .


mu trng ngy 6500k (standard 26mm) Ra=75p, P=18w, d =1050(lm), b b n loi

profil paralume laque , cp b n : 0.59E, quang thng cc bng trn mt b :1050(lm) ,


abK

h a b

12.1,60.52

2.7(12 1,6)

, 0.7tran ,


0,59.0,43 0.2537uK , h s b d=1.25 , quang thng tng

. . 100.19,2.1,259459

0,2537

tctong

u

E S d

K (lm),


/

82757,8

1050

tong

boden

cacbong bo

N


=> Vy ta c cng sut chiu sng ca phng : sinh 8.18 144nhaxehocP W

=> 4 _10000 144 10144N tongP W

5) Nhm V: Trm s l nc cp-trm bm, nh gi xe gio vin.

- Chn bm nc bnh thng trong cng nghip th 4 yu t chnh l lu lng, ct p,

nht (khi bi ton cn s tnh ton chi tit) v kch thc ng ng

-Bm cp nc cho bn 30 khi, s dng ng dn nc loi ng thp DN25 c ng knh

bn trong ng l 25 mm, chiu di tng ng ng t trm bm n bn nc l 24m, chn

bn cn 1000 lt th bm=>bm 15000 lt/gi4,1666 lt/giy

-Ta s dng phn mm pipe flow wizard V1.12 tnh ct p tng trn ng ng 97,164

N 2A

64

mt nc =504245Pa (1Pa=41,02 10x mt nc)

- Cng sut in ca my bm Pbm(walt in) = p lc (Pa) x 10-3

x Lu Lng(lt/giy)/hiu

sut s dng (n=0,65 ~ 0,9)

=>T ta c th tnh c cng sut in ca bm :

Pbm(walt in) =

3952588 10 4,16664961

0,8

x xW

Nu mun mua bm ta nhn cho h s d tr 1,4 ln. Tc bng 4961 x 1,4 =6945 W ~ 10Hp

in cho bm.

-Vy trm s l nc cp, trm bm c cng sut t 7,5trambomP KW

-Nh xe hai bnh (nh xe dnh cho gio vin) c tng din tch S=4,82m chiu di a=8m

chiu rng b=1,2m


mu trng ngy 6500k (standard 26mm) Ra=75p, P=18w, d =1050(lm), b b n loi

profil paralume laque , cp b n : 0.59E, quang thng cc bng trn mt b :1050(lm) ,


abK

h a b

8.1,20,38

2.7(8 1,2)

, 0.7tran ,


0,59.0,43 0.2537uK , h s b d=1.25 , quang thng tng

. . 100.4,8.1,252364

0,2537

tctong

u

E S d

K (lm),


/

23642,25

1050

tong

boden

cacbong bo

N


=> Vy ta c cng sut chiu sng ca phng : 2.18 36nhaxegiaovienP W

N 2A

65

=> 5_7536 36 7572N tongP W

Tng Kt Cng Sut t Ca Cc Nhm Ph Ti:

_ hom1 48604tong nP W

_ 2 37189tong NP W

3_ 114637N tongP W

4 _ 10144N tongP W

5_ 7572N tongP W

N 2A

66

2.2.3 XC NH CNG SUT TNH TON CA TRNG HC

Ph ti tnh ton ca cc nhm trong trng hc.

Ta ly trung bnh h s cng sut ca ton trng hc l cos 0.8

Trng hc c h s nhu cu 0.8ncK

Ta tin hnh tnh ton cng sut tnh tin theo phng php cng sut t v h s nhu cu

Cng thc tnh:

Ptt= knc.

Qtt=Ptt.tg

Stt=

= ttP

cos

3.U

tt tttt

phaday

S SI

U

Nhm 1:

Nhm 1 bao gm tng cng sut cc phng hc v phn chiu sng ngoi :

_ hom1 48604tong nP W

T cng sut t ca nhm v h s nhu cu 0.8sK ta c th tnh c cng sut tnh

ton:

_ 1 . 39304.0,8 38883tt N dat ncP P K W

T h s cng sut cos 0.8 ta c th suy ra c cng sut phn khng Q theo cng

thc nh sau:

_ 1 _ 1. 38883.0,75 29162tt N tt NQ P tg VAr

T cng sut tc dng tnh ton v cng sut phn khng tnh ton ta c th tnh c cng

sut ton phn ca nhm:

N 2A

67

2 2 2 2

_ 1 _ 1 _ 1 38883 29162 48604tt N tt N tt NS P Q VA

Ph ti tnh ton cho tng tng:


=>_N1_tangtret _ tang _ 1. 14501.0,8 11601tt tong tret N NCP P K W

. 11601.0,75 8701tt ttQ P tg VAr

2 2 2 211601 8701 14501tt tt ttS P Q VA


=>_N1_tang1 _ tang1_ 1. 20827.0,8 16662tt tong N NCP P K W

. 16662.0,75 12496tt ttQ P tg VAr

16662

20827cos 0.8

tttt

PS VA

_ tang 2 _nhom1 10276tongP W

=>_N1_tang1 _ tang 2 _ 1. 10276.0,8 8221tt tong N NCP P K W

. 8221.0,75 6166tt ttQ P tg VAr

8221

10276cos 0.8

tttt

PS VA

_30000 30000.0,4 12000chieusangngoai tt chieusangngoaiP W P W

. 12000.0,75 9000tt ttQ P tg VAr

1200015000

cos 0.8

tttt

PS VA

Nhm 2:

_ 2 37189tong NP W


ton:

N 2A

68

_ 2 . 37189.0,8 29751tt N dat ncP P K W


thc nh sau:

_ 2 _ 1. 29751.0,75 22313tt N tt NQ P tg VAr


sut ton phn ca nhm:

2 2 2 2

_ 2 _ 2 _ 2 29751 22313 37189tt N tt N tt NS P Q VA



_N 2 _tangtret 2 _ _tangtret . 11408.0,8 9126tt N tong NCP P K W

. 9126.0,75 6845tt ttQ P tg VAr

912611408

cos 0.8

tttt

PS VA


_N 2 _tang1 2 _ _tang1. 13451.0,8 10761tt N tong NCP P K W

. 10761.0,75 8071tt ttQ P tg VAr

1067113451

cos 0.8

tttt

PS VA

2 _ _ tang 2 12330N tongP W

_N 2 _tang 2 2 _ _tang 2. 12330.0,8 9864tt N tong NCP P K W

. 9864.0,75 7398tt ttQ P tg VAr

739812330

cos 0.8

tttt

PS VA

Nhm 3:

3_ 114637N tongP W

N 2A

69


ton:

_ 3 . 114637.0,8 91710tt N dat sP P K W


thc nh sau:

_ 3 _ 3. 91710.0,75 68782tt N tt NQ P tg VAR


sut ton phn ca nhm:

2 2 2 2

_ 3 _ 3 _ 3 91710 68782 114637tt N tt N tt NS P Q VA



_N3_tangtret _ 3_tangtret . 65531.0,8 52425tt tong N NCP P K W

. 52425.0,75 39319tt ttQ P tg VAr

5242565531

cos 0.8

tttt

PS VA


_N3_tang1 _ 3_tang1. 30356.0,8 24285tt tong N NCP P K W

. 24285.0,75 18214tt ttQ P tg VAr

2428530356

cos 0.8

tttt

PS VA

_ 3_ tang 2 18750tong NP W

_N3_tang 2 _ 3_tang 2. 18705.0,8 15000tt tong N NCP P K W

. 15000.0,75 11250tt ttQ P tg VAr

N 2A

70

1500018750

cos 0.8

tttt

PS VA

Nhm 4:

4 _ 10144N tongP W


ton:

_ 4 . 10144.0,8 8115tt N dat sP P K W


thc nh sau:

_ 4 _ 4. 8115.0,75 6086tt N tt NQ P tg VAR


sut ton phn ca nhm:

2 2 2 2

_ 4 _ 4 _ 4 8115 6086 10144tt N tt N tt NS P Q VA

Nhm 5:

5_ 7572N tongP W


ton:

_ 5 . 7572.0,8 6058tt N dat sP P K W


thc nh sau:

_ 5 _ 5. 6058.0,75 4546tt N tt NQ P tg VAR


sut ton phn ca nhm:

2 2 2 2

_ 5 _ 5 _ 5 6058 4546 7574tt N tt N tt NS P Q VA

N 2A

71

CHNG 3: CHN PHNG N CUNG CP IN CHO TRNG HC

3.1 CC PHNG N CUNG CP IN.

Mng in h p y c hiu l mng ng lc hoc chiu sng vi cp in p thng

l 380/220 V.

S ni dy ca mng ng lc c hai dng c bn l mng hnh tia v mng phn nhnh

v u khuyt im ca chng nh sau :

-S hnh tia c u im l ni dy r rng , mi h dng in c cp t mt ng

dy, do chng t nh hng ln nhau tin cy cung cp in tng i cao d thc hin

cc bin php bo v v t ng ng ha cao d vn hnh bo qun .

Khuyt im ca n l vn u t ln . v vy s ni dy hnh tia c dng cung cp

in cho cc h tiu th loi 1 v loi 2.

-S phn nhnh c u khuyt im ngc li so vi s hnh tia v vy loi s ny

c dng khi cung cp in cho cc h tiu th loi 2 v 3.

Trong thc t ngi ta thng kt hp hai dng s c bn thnh nhng s hn hp

nng cao tin cy v linh hot ca s ngi ta thng t cc mch d phng chung

hoc ring .

Cc dng s :

N 2A

72

-S hnh tia c cung cp cho cc ph ti phn tn .t thanh ci ca trm bin p c cc

ng dy dn n cc t phn phi ng lc .t cc t phn phi ng lc c cc ng

dy dn n ph ti.

Loi s ny c tin cy tng i cao,n thng dng trong cc phn xng c cc

thit b phn tn trn din rng nh xng gia cng c kh lp rp ,dt ,si..

-S hnh tia dng cung cp cho cc ph ti tp trung c cng sut tng i ln nh cc

trm bm: l nung trm kh nn ..trong s ny t thanh ci ca trm bin p c cc ng

dy cung cp thng cho cc ph ti

N 2A

73

-S phn nhnh thng c dng trong cc phn xng c ph ti khng quan trng

N 2A

74

-S ny thng c dng trong cc phn xng c ph ti tng i ln v phn b

iu trn din tch rng . nh c cc thanh ci chy dc theo phn xng mng c th ti

c cng sut ln gim c cc tn tht v cng sut v in p

-S my bin p ng trc . loi s ny thng c dng cung cp cho cc ph

ti phn b ri theo chiu di .

N 2A

75

3.2 LA CHN PHNG N CP IN CHO TRNG HC

=>Vi u nhc im ca cc loi s nh trn ta nhn thy vi nhng c im trng

hc v m bo tnh kinh t k thut ta la chn phng n cung cp in bng s

hnh tia kt hp vi s ng trc cp in cho trng hc.

S Tng Qut Ca Trng Hc.

MBA

N 2A

76

S Mt Bng i Dy Tng Th

N 2A

77

S mt bng i dy khi thc hnh:

N 2A

78

Tng trt khi thc hnh

RAM

P DOC CHO NGI KHUYET TAT

N 2A

79

Tng 1 khi thc hnh

1400

N 2A

80

Tng 2 khi thc hnh

1500

N 2A

81

S Mt Bng i Dy Khi Phng Hc:

Tng trt khu phng hc

RA

MP

D

OC

C

HO

N

G

I K

HU

YE

T TA

T

i=1

0%

RA

MP

D

OC

C

HO

N

G

I K

HU

YE

T TA

T

i=1

0%

RAMP DOC CHO NGI KHUYET TAT RAMP DOC CHO NGI KHUYET TAT

VACH NGAN

NHOM KNH

VACH NGAN

NHOM KNH

VACH NGAN

NHOM KNH

N 2A

82

Tng 1 khu phng hc

LAM

CHE NANG BTCT

LAM

CHE NANG BTCT

220

VACH NGAN

NHOM KNH

N 2A

83

Tng 2 khu phng hc

220

i=2%

i=2%

i=2%

i=2%

i=2%

i=2%

3

7

8

8

8

SL1 SL1

CT1

N 2A

84

CHNG 4: CHN THIT B CHO MNG IN

4.1 CHN DY DN

4.1.1 PHNG PHP LC CHN TIT DIN DY DN.

1) Chn tit din dy dn theo tn hao in p cho php

Trc ht xc nh thnh phn phn khng ca tn hao in p cho php:

Ux=

Xc nh thnh phn tc dng ca tn hao in p cho php:

Ur = Ucp- U

Tit din dy dn c xc nh nh sau:

F=

Trong :

x0 thng c gi tr t 0,35-0,4

Pi- cng sut tc dng trn on dy th i,kW

li- chiu di on dy th i, m

U- in p nh mc ca ng dy, kV

Ur- thnh phn tc dng, V

- in dn ca vt liu .m/mm2

Cn c vo gi tr F la chn dy dn ng vi thang tit din gn nht v pha trn,

sau kim tra li tn hao in p thct ca dy dn va chn.

2) Xc nh tit din dy dn theo chi ph kim loi cc tiu

ng dy khng phn nhnh

Tit din ca ng dy khng phn nhnh gm nhiu on c xc nh trc ht t on

dy cui cng (on th n ):

F=

N 2A

85

Tit din ca cc on dy khc theo biu thc:

Fi=Fn

Pn- cng sut tc dng trn on dy th n

Ur- c xc nh bng cng thc phng php 1

i vi ng dy phn nhnh

Trc ht xc nh thnh phn tc dng ca tn hao in p cho php trn ng dy

chung theo biu thc:

Ur0 =

Tit din dy dn trn on u c xc nh:

F0 =

P0 v l0 l cng sut tc dng chy trn on dy chung v chiu di

Chn dy dn c tit din gn F0 nht v pha trn xc nh thnh phn tc dng ca tn hao

in p thc t trn on dy u:

UR0tt =

Thnh phn tc dng ca tn hao in p cho php trn cc on dy phn nhnh

UR1 = UR- UR0tt

N 2A

86

Tit din dy dn ca cc on dy phn nhnh c xc nh:

F1 =

v F2 =

Trong :

Pi, li - cng sut tc dng v chiu di ca on dy phn nhnh th i

3) Xc nh tit din dy dn theo mt dng in khng i

Phng php ny c p dng khi thi gian s dng cng sut cc i TM nh

Cc bc xc nh Ur tng t nh cc phng php khc, sau xc nh mt dng

in khng i theo biu thc:

j =

trong :

- h s cng sut tng ng on dy th i.

Vi mt dng in J, ta xc nh c tit din dy dn trn cc on:

F1 =

, F2 =

,. Fn =

4) Xc nh tit din dy dn theo mt dng in cho php ca dy dn

Theo phng php ny tit din dy dn c chn theo iu kin

Ilv Icp

Icp- dng in cho php ng vi tng loi dy dn,ph thuc vo nhit

t nng cho php ca chng.

5) Phng php chn tit din dy dn theo iu kin pht nng

Khi c dng in chy qua dy dn v dy cp th vt dn b nng, nu nhit dy dn qu

cao c th lm cho chng b h hng hoc gim tui th.Mc khc, bn c hc ca kim

loi dn in cng b gim xung. do vy nh ch to quy nh nhit cho php i vi

mi loi dy dn v dy cp.

iu kin chn dy dn

N 2A

87

1 2

1 2

* *

*

cp tt

ttcp

K K I I

II

K K

Trong :

1K :l h s hiu chnh nhit ng vi mi trng t dy cp

2K :l h s hiu chnh nhit k n s lng dy hoc cp i chung mt rnh

cpI : dng in lu di cho php ng vi tit din dy hoc cp nh la chn

Dng in cho php l dng in ln nht c th chy qua dy dn trong thi gian khng

hn ch m khng lm cho nhit ca n vt qu tr s cho php.

6) Chn tit din dy dn ca mng in chiu sng

F =

Trong :

- tng momen quy i ca tt c cc nhnh, c xc nh:

=

Trong :

- momen ti ca cc nhnh c cng s lng dy dn vi ng

trc chnh

- momen ti ca cc nhnh c cng s lng dy dn khc vi

nhm trn

Pl momem ti

- hao tn in p cho php,

C = h s ph thuc vo cu trc mng in, tra bng

4.pl.BT

h s quy i, ph thuc vo kt cu

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