Tirgul_12

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  • 8/13/2019 Tirgul_12

    1/3

    (, F, )

    G F

    f L1(, F, )

    g L1(, G, )

    A

    f d=

    A

    g d

    A G E[f | G] g

    f

    G

    0 G 0 (, G)

    0(A) =(A) A G (, G)

    (A) =A

    f d0 A G 0

    g L1(, G, )

    A

    g d0= (A)

    A G

    A

    g d =

    A

    g d0= (A) =

    A

    f d0=

    A

    f d

    E[f | G]

    G

    A

    f d=A

    E[f | G]d

    A G

    E[f | G] E[f | G]

    E[f | G] f

    L1(, F, )

    G = {, } E[f | G] =

    f d := E[f] E[f]

    G

    A

    E[f] d= A

    f d

    A=

    A=

    G=F E[f | G] =f f G

    P F

    G=(P)

    E[f | G]() =h() :=

    CP

    1C() 1

    (C)

    C

    f d

  • 8/13/2019 Tirgul_12

    2/3

    h G A G

    (P) ={ CQC : Q P}

    A= CQ

    C Q P

    A

    h d=

    CQ

    C

    h d=

    CQ

    C

    ( 1

    (C)

    C

    f d) d=

    CQ

    C

    f d=

    A

    f d

    G F E[ | G]

    L1(, F, ) L1(, G, )

    E[ | G]

    E[ | G]

    g L(, G, ) E[g f | G] =g E[f | G] fL1(, F, )

    B G fL1(, F, )

    E[E[f | G]| B] =E[E[f | B]| G] =E[f | B]

    f, g L1(, F, ) , R E[f | G] + E[g | G]

    G

    A G

    A

    E[f | G] + E[g| G] d= A

    E[f | G] d + A

    E[g| G] d=

    =

    A

    f d +

    A

    g d=

    A

    f+ g d

    E[f+ g | G] =E[f | G] + E[g| G]

    fL1(, F, ) E[ | G] E[f | G]L1

    fL1 A = {E[f | G] 0} E[f | G] G

    A, Ac G

    E[f | G]L1 =

    A

    E[f | G] d +

    Ac

    E[f | G] d=

    =

    A

    f d +

    Ac

    f d

    A

    |f| d +

    Ac

    |f| d= fL1

    f L1(, F, ) A G 1A E[f | G] G

    B G

    B

    1A E[f | G] d=

    AB

    E[f | G] d=

    AB

    f d=

    B

    1A f d=

    B

    E[1A f | G] d

  • 8/13/2019 Tirgul_12

    3/3

    E[ | G]

    g L(, G, )

    g 0

    {sj}j=1

    L(, G, ) 0 s1 s2

    ... g sjj

    g B G

    B

    g E[f | G] d= limj

    B

    sj E[f | G] d= limj

    B

    sj f d=

    B

    g f d

    E[g f | G] = g E[f | G] g g = g+ g

    E[f | B]

    G

    E[E[f | B]| G] =E[f | B]

    E[E[f | G]| B] =E[f | B] B B

    B

    E[f | G] d=

    B

    f d=

    B

    E[f | B] d

    E[f | B] B E[E[f | G]| B] =E[f | B]