Vienkrie mehnismi SviraOksana imaneDaugavpils 10. vidusskola

SVIRAF1F1, F2 - darbojoie spkil1atbalsta punkts (rotcijas ass) F2l2l2 spka F2 plecs l1 spka F1 plecs Spka plecs - perpendikuls, kas vilkts no rotcijas ass ldz spka darbbas taisnei Svira - vienkrs mehnisms, kur ar statni kustgi savienots ciets ermenis, kas var pagriezties ap savienojuma eometrisko asi.

Noteikt sviras plecu garumus F1F2 2 cml1 = 5 . 2 cm = 10 cm l2 = 14 . 2 cm = 28 cm

Noteikt sviras plecu garumus F1F21)2)3)4)F2 5 cm 1 cmF1

Noteikt sviras plecu garumus F1F65) 0.5 cmF2F3F4F5

Noteikt sviras plecu garumusF1F2135o 1 cm Atkrtosim trigonometrisks funkcijas sin un cos

Noteikt sviras plecu garumusF1F2135oal1 = 9 . 1 cm = 9 cm l2 = 5 . cos45o = 1 cml1l2 cos a = l l2l l2 = l . cos a a = 180o - 135o = 5 . 3.5 cm

Noteikt sviras plecu garumusF1F2F3 10 cm

Noteikt sviras plecu garumusF1F2 10 cm150o120ok m

Sviras ldzsvara nosacjumiF1l1F2l2F2 . l2 = F2 . l 2 Svira atrodas ldzsvar, ja spka reizinjums ar sviras plecu abs atbalsta puss ir viends

Vai svira atrodas ldzsvar?F1F2 2 cml1 = 10 cm l2 = 28 cm 15 . 10 3 . 28 150 84F1 . l1 F2 . l2?F1 = 15 NF2 = 3 NN!F1 . l1 F2 . l2

Vai svira atrodas ldzsvar?F1F21)2)3)4)F2F1 5 cmF1 = 15 NF2 = 3 N

Vai svira atrodas ldzsvar?F1F6F2F3F5F4F1 = 3 NF2= 1 NF3 = 2 NF4 = 1,0 NF5 = 3,0 NF6 = 5,0 N

Vai svira atrodas ldzsvar?F1F2135oF1 = 14 NF2 = 3 N

Vai svira atrodas ldzsvar?F1150o120oF2

Aprint sviras masuaF1 = ? NF2= 600 NF3 = 500 NF4 = 600 N

AtbildeaF1F2F3F4l2l3l4l1l1 = 1,5 . cos30o = 1,3 ml2 = 1,5 . cos30o = 1,3 ml3 = 2,5 . cos30o = 2,2 ml4 = 3,0 . cos30o = 2,6 m F1 . l1 = F2 . l2 + F3 . l3 + F4 . l4F1 = ? NF2= 600 NF3 = 500 NF4 = 600 NF1 . 1,3 = 600 . 1,3 + 500 . 2,2+600 . 2,6==780+1100+1560=3440 (N) Akmens masa ir 344 kg

PALDIES PAR UZMANBU

AtbildesF1F21)2)3)4)F2F1l1 = 25 cml2 = 7,5 m l1 = 70 cml2 = 30 m l1 = 15 cml2 = 60 m l1 = 2 cml2 = 10 m

AtbildeF1F6l1 = 4,5 cm l2= 3,0 cml3 = 1,0 cml4 = 1,0 cml5 = 3,0 cml6 = 5,0 cm

5) 0.5 cmF2F3F4F5

aur lea kosinussPar aura lea kosinusu sauc piekatetes attiecbu pret hipotenzuCBbcjeb b = c . cos a

aur lea sinussPar aura lea sinusu sauc pretkatetes attiecbu pret hipotenzuACBjebac a = c . sin a

AtbildeF1F2F3 10 cm30o

30ol1 = 60 cml3l1l2cl2= 170 cm

l3 = c . sin a

l3 = 80 . sin 30o 69.28 cm

AtbildeF1F2l1 = 10 . sin60o = 5 cm l2 = 30 . sin30o = 25.5 cm l2 = m . sin a 150o120oa l1 l2 = 180o - 150o l1 = k . sin a = 180o - 120o sin a = k l1k m

AtbildeF1F21)2)3)4)F2F125 . 3 7,5 . 1575 112,5 N!N!2 . 15 = 10 . 330 = 30 J!15 . 15 60 . 3225 180 N!

AtbildeF1F2135ol1 = 9 cm l2 = 3,5 cml1l2F1 = 14 NF2 = 3 N 9 . 14 = 3,5 . 36126 = 126ldzsvara

AtbildeF1F6F2F3F5F4 4,5.3+3.1+1.2 1.1,5+3.3,5+5.1,5 18,5 19,5 N! l1 = 4,5 cm l2= 3,0 cml3 = 1,0 cml4 = 1,0 cml5 = 3,0 cml6 = 5,0 cm

F1 = 3 NF2= 1 NF3 = 2 NF4 = 1,0 cmF5 = 3,0 cmF6 = 5,0 cm

Atbildel1 = 5 cm l2 = 25.5 cmF1150o120oF2F1 = 90 NF2 = 20 N 5 . 110 25,5 . 20550 510N!