2. Chun dd baz yu a. dd baz yu n chc
BOH + HCl BCl + H2O* CV = 0 => F = 0 (cha chun )
Dd ( BOH) =>pHo=14- (pKb lgCo)* 0 < CV < CoVo => 0 < F < 1BOH + HCl BCl + H2O
Dd BOH:
BCl:Dd n baz yu
)1lg(14)lg(14 001 FF
CVCVVCpH ==
VVCVVCCb +
=
0
00
VVCVCm
+=
0
* CV = CoVo => F = 1
BOH + HCl BCl + H2ODd (BCl)
* CV > CoVo => F > 1 BOH + HCl BCl + H2O
Dd HCl: BCl
)lg(0
0021
VVVCpKpKpH bnt +=
VVVCCVpH
+
=
0
002 lg
VVCVVCCm +
=
=
0
00
VVVCCVCa +
=
0
00
ng cong chun :Td: Chun 10ml dd NH4OH 0,1 M (pKb= 4,8) bng dd HCl 0,1 M NH4OH + HCl NH4Cl + H2O CoVo CVF Cng thc tnh pH pH Ghi ch0,0 pHo= 14- (4,8-lg0,1) 11,1 Cha c.
0,5 pH0,5=14-(pKb-lgCa/Cm) 9,2
1,0 pHt = [14-4,8-lg(0,1)/2] 5,25 t
1,5 pH2= -lg[(15.0,1-10.0,1)/(10+15)] 1,6
Nhn xt
im tng ng ti min axit Cht ch th thch hp nht cho php chun ny l metyl da cam, metyl
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