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Page 1: Sta Tika

HA

2 m 2 m

P1 = 9t

A

VA

4

P1 = 9t

RHA

PA sin α PA PA cos α

PA sin α PA PA cos α

RHA

P1

P

9 ton

Bidang Lintang

Bidang Momen

Bidang Normal

Reaksi Perletakan

r

Tinjau batang yang miring

Bidang MomenDaerah A-C MX1 = RA . XX1 = 0 � MA = 3,6 . 0 = 0 tonX1 = 2.5 � MC = 3,6 . 2,5 = 9 tonDaerah B-C MX2 = RB . XX2 = 0 � MA = 3,6 . 0 = 0 ton X2 = 2.5 � MC = 3,6 . 2,5 = 9 ton Bidang LintangDaerah A-C DX1 = RA X1 = 0 � DA = 3,6 tonX1 = 2.5 � DC = 3,6 tonDaerah B-C DX2 = RB X2 = 0 � DA = 3,6 tonX2 = 2.5 � DC = 3,6 ton Bidang NormalDaerah A-C NX1 = - HA X1 = 0 � NA = X1 = 2.5 � NC =

2 m 2 m

PB sin α PB PB cos α

= 9t

B

VB

3

= 9t

PB sin α PB PB cos α

P2

9 ton

Bidang Lintang

Momen

Normal

Reaksi Perletakan Soal 1

Tinjau batang yang miring Kontrol :

3,6+3,6−7,2 = 0

7,2−7,2 = 0 0 = 0

= 5,4 ton

Bidang Momen

= RA . X MA = 3,6 . 0 = 0 ton

MC = 3,6 . 2,5 = 9 ton

= RB . X MA = 3,6 . 0 = 0 ton

MC = 3,6 . 2,5 = 9 ton

Bidang Lintang

DA = 3,6 ton DC = 3,6 ton

A = 3,6 ton C = 3,6 ton

Bidang Normal

A = -5,4 ton C = -5,4 ton