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HA
2 m 2 m
P1 = 9t
A
VA
4
P1 = 9t
RHA
PA sin α PA PA cos α
PA sin α PA PA cos α
RHA
P1
P
9 ton
Bidang Lintang
Bidang Momen
Bidang Normal
Reaksi Perletakan
r
Tinjau batang yang miring
Bidang MomenDaerah A-C MX1 = RA . XX1 = 0 � MA = 3,6 . 0 = 0 tonX1 = 2.5 � MC = 3,6 . 2,5 = 9 tonDaerah B-C MX2 = RB . XX2 = 0 � MA = 3,6 . 0 = 0 ton X2 = 2.5 � MC = 3,6 . 2,5 = 9 ton Bidang LintangDaerah A-C DX1 = RA X1 = 0 � DA = 3,6 tonX1 = 2.5 � DC = 3,6 tonDaerah B-C DX2 = RB X2 = 0 � DA = 3,6 tonX2 = 2.5 � DC = 3,6 ton Bidang NormalDaerah A-C NX1 = - HA X1 = 0 � NA = X1 = 2.5 � NC =
2 m 2 m
PB sin α PB PB cos α
= 9t
B
VB
3
= 9t
PB sin α PB PB cos α
P2
9 ton
Bidang Lintang
Momen
Normal
Reaksi Perletakan Soal 1
Tinjau batang yang miring Kontrol :
3,6+3,6−7,2 = 0
7,2−7,2 = 0 0 = 0
= 5,4 ton
Bidang Momen
= RA . X MA = 3,6 . 0 = 0 ton
MC = 3,6 . 2,5 = 9 ton
= RB . X MA = 3,6 . 0 = 0 ton
MC = 3,6 . 2,5 = 9 ton
Bidang Lintang
DA = 3,6 ton DC = 3,6 ton
A = 3,6 ton C = 3,6 ton
Bidang Normal
A = -5,4 ton C = -5,4 ton