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7/23/2019 PODVLAKA Beton (Seminarski)
1/5
1. ANALIZA POTEREENJA ZA SREDNJU PODVLAKU
(*) Podvlaka je ko!. "#eda $a !#% &olja !j. 'aea#e je !%aj k#!e ve+e$#edj%, $!-ova o-+%#o a j%,ov +a!o aj k#!o$! odo$ a
k#!o$! &odvlake.
So&$!vea !e/%a &odvlake
(020 3 040 3 54) 6 "$7 284 KN95
Te/%a +%da %+ad &odvlake
(054 3 5:4 3 124)6 "+7 ;
7/23/2019 PODVLAKA Beton (Seminarski)
2/5
", 7 B88 3 10 7 B88 KN9
&, 7 20 3 10 7 200 KN9
**) P#o#aC$ko ("#a%Co) o&!e#e?eje
$7 1< 3 (122< 1
7/23/2019 PODVLAKA Beton (Seminarski)
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1+' Mb 2+/ Mc $ 32,+0
2+/ Mb 1+' Mc $ 10&+&0
S%4-I5
Mb $ 1'+0/ KNm Mc $ 1/+0 KNm
*) Me!oda6ni moment nad osloncima
2.2) Momenti 7 oljima
olje I)
A=
158+
43,095,31
25,3
2+13,365,3/2
5,3=62,687KN
T#) $/ $8 &2+&0' 3 1,+,& * 9 3 ,+/(2+& * 9 * 9(2 $ /
$8 3 0+1, 92: 1,+,& 9 &2+&0' $ /
x=bb24ac
2a$8 9 $ 2+/' m
ma# M1$ &2+&0' 31,+,& * 2+/'2(2 : ,+/0(2+& * 2+/' * 1(2 * 1(, * 2+/'
ma# M1$ &2+&0' 3 20+&2 3 11+&1$ 22+' KNm
olje II)
7/23/2019 PODVLAKA Beton (Seminarski)
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;Mc $ / $8B
d=
158+158+(3,75+3,0)2,052
2
2
4
M< ,/ $8 bf $ 2/+/ MPa $ 2+/ KN(cm2
RA //(// $8 v $ // MPa $ / KN(cm2
MA //(&/ $8 v $ // MPa $ / KN(cm2
,.1) PR4S4K U PO%>IMA 1 I ,
M7 $ 22+' KN m
do$ %(12 5 %(2/)
do$ ,/(12 $ +1&'
7s6ojeno5 do$ / cm
d$ do(1/ $ cm ? d$ 1 cm
7/23/2019 PODVLAKA Beton (Seminarski)
5/5
d @ { bo+20dp=330cm
bo+0,25Lo=130cm
=175cm
$8 b$ 1,/ cm
a!et$ cm
$ do: $ & cm
)599,7(612,7
3005,2
10457,22
46
2===
x
x
xbf
M
hk
b
osl
b
7 18
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