PODVLAKA Beton (Seminarski)

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  • 7/23/2019 PODVLAKA Beton (Seminarski)

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    1. ANALIZA POTEREENJA ZA SREDNJU PODVLAKU

    (*) Podvlaka je ko!. "#eda $a !#% &olja !j. 'aea#e je !%aj k#!e ve+e$#edj%, $!-ova o-+%#o a j%,ov +a!o aj k#!o$! odo$ a

    k#!o$! &odvlake.

    So&$!vea !e/%a &odvlake

    (020 3 040 3 54) 6 "$7 284 KN95

    Te/%a +%da %+ad &odvlake

    (054 3 5:4 3 124)6 "+7 ;

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    ", 7 B88 3 10 7 B88 KN9

    &, 7 20 3 10 7 200 KN9

    **) P#o#aC$ko ("#a%Co) o&!e#e?eje

    $7 1< 3 (122< 1

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    1+' Mb 2+/ Mc $ 32,+0

    2+/ Mb 1+' Mc $ 10&+&0

    S%4-I5

    Mb $ 1'+0/ KNm Mc $ 1/+0 KNm

    *) Me!oda6ni moment nad osloncima

    2.2) Momenti 7 oljima

    olje I)

    A=

    158+

    43,095,31

    25,3

    2+13,365,3/2

    5,3=62,687KN

    T#) $/ $8 &2+&0' 3 1,+,& * 9 3 ,+/(2+& * 9 * 9(2 $ /

    $8 3 0+1, 92: 1,+,& 9 &2+&0' $ /

    x=bb24ac

    2a$8 9 $ 2+/' m

    ma# M1$ &2+&0' 31,+,& * 2+/'2(2 : ,+/0(2+& * 2+/' * 1(2 * 1(, * 2+/'

    ma# M1$ &2+&0' 3 20+&2 3 11+&1$ 22+' KNm

    olje II)

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    ;Mc $ / $8B

    d=

    158+158+(3,75+3,0)2,052

    2

    2

    4

    M< ,/ $8 bf $ 2/+/ MPa $ 2+/ KN(cm2

    RA //(// $8 v $ // MPa $ / KN(cm2

    MA //(&/ $8 v $ // MPa $ / KN(cm2

    ,.1) PR4S4K U PO%>IMA 1 I ,

    M7 $ 22+' KN m

    do$ %(12 5 %(2/)

    do$ ,/(12 $ +1&'

    7s6ojeno5 do$ / cm

    d$ do(1/ $ cm ? d$ 1 cm

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    d @ { bo+20dp=330cm

    bo+0,25Lo=130cm

    =175cm

    $8 b$ 1,/ cm

    a!et$ cm

    $ do: $ & cm

    )599,7(612,7

    3005,2

    10457,22

    46

    2===

    x

    x

    xbf

    M

    hk

    b

    osl

    b

    7 18