Bi tp anken1.Hon thnh dy chuyn ha sau . C2H2 -> C2H4 -> C2H5OH -> C2H4 -> C2H4(OH)2 2.C3H7OH -> C3H6 -> C3H8 -> C2H4 -> C2H5OH. 3.t chy hon ton 2,24 l kh ktc ri hp thu ton b vo dd cha 11,1 g Ca(OH)2 .Hi sau khi hp th khi lng dd tng hoc gim bao nhiu gam ? 4. Hn hp X gm ankan v anken c t l s mol 3:2 .t chy hon ton X , dn hi chy qua dd Ca(OH)2 bnh tng 7,08 g v c 8 g kt ta . Phn dd nc lc tc dng vi Ca(OH) 2 d xut hin thm 4 g kt ta na . Tm cng thc phn t mi cht . 5.A l ankan , B l anken u th kh t chy 0,1 mol hn hp ( cha a mol A v b mol B ) thu c khi lng CO2 ln hn nc l 7,6 g t chy 0,1 mol hn hp ( cha a mol A v b mol B ) thu c khi lng CO2 ln hn nc l 6,2 g Tm ctpt A, B .bit s nguyn t trong B ln hn A 6. Hn hp A gm hidro v 1 olefin c t l s mol 1:1 . un nng hn hp A vi niken xc tc thu c hn hp B c t khi so vi hidro l 12,5 . Hiu sut phn ng l h a. Lp biu thc tnh h theo n b.bit h > 70% xc nh cng thc phn t ca olefin v tnh h 7.Ly hai th tch bng nhau ca 1 anken th kh cho p ring r vi dd clo , brom . Khi lng ca hai sn phm cng khc nhau 44 ,5 g a. Tnh th tch anken dng 27,3 0 C v 1 at . Gi s hiu sut p u t 80 % b. Vit cng tha cu to c th c ca anken bit rng khi lng sn phm cng brom thu c l 108 g v nu cho p vi HCl ch thu c 1 sn phm duy nht 8.Hn hp kh A cha 1 ankan v 1 anken .Khi lng hn hp a l 9 g v th tch l 8,96 l . t chy hon ton A thu 13,44 l CO2 . Cc kh u o ktc . Xc nh cng thc v tnh % mi anken 10.cn bao nhiu ml etilen ktc iu ch 1 tn PE . Gi s hiu sut p trng hp t 80 % . 11. Hn hp A gm anken v hidro c t khi so vi hidro bng 9 ,dn hn hp i qua bt niken nung nng n khi p hon ton thu c kh B x t khi so vi H2 bng 15 . Tm ctpt ca X v tnh % th tch ca kh trong A v B . 12.Cho mt lng anken X tc dng vi nc c cht hu c Y , thy khi lng bnh ng nc ban u tng 4,2 g .nu cho lng X nh trn tc dng vi HBr thu c cht Z thy khi lng Y , Z khc nhau 9,45 g .Tm cng thc phn t v gi tn X , gi s cc p xy ra hon ton 13.t chy hon ton 2,24 l ktc mt hidrocacbon X mch h , sau dn sn phm chy ln lt i qua H2SO4 c v dd Ca(OH)2 d .Sau th nghim thy khi lng bnh ng axit tng 5,4 g v bnh Ca(OH) 2 c 30 g kt ta .Tm cng thc phn t ca X 14.Cho hn hp 2 anken qua bnh nc brom d . thy khi lng bnh brom tng 16 g . Tng s mol 2 anken l A. 0,1 B .0,2 C.0,05 D. 0,15 15.Hn hp A gm 1 ankan v 1 anken c cng s nguyn t C trong phn t v c cng s mol . Hn hp ny lm mt mu va 80 g dd brom 20 % . Cn t chy hn hp cho 13,44 l CO2 ktc.Ctpt l A.C4H6, C2H4 B.C4H10 ,C4H8 C.C3H8 , C3H6 D. KT QU KHC 16.Mt hn hp gm 3 anken C3H6,C4H8 , C5H10 . Nu t chy hn hp cho 6,72 l hi nc ktc . Nu cho hn hp p vi hidro d c xc tc ,t chy sn phm ri dn sn phm chy vo nc vi trng d , th khi lng kt ta sinh ra l A.30 g B .31g C. 32 g D . 29 g 17.t chy anken X thu 2,24 l CO2 ktc , nu dn ton b sn phm chy vo nc vi trong d th khi lng bnh tng A.6,2 g B.5,2 C.4,2 D. 10 18.Cho 6,72 l hn hp gm 2 anken li qua dd brom d ,thy khi lng bnh tng 16,8 g . Tm cng thc pt ca anken , bit s C mi anken khng qu 5 . A. C2H4 B. C3H6 , C4H8 C . C4H8 , C5 H10 D. kt qu , C4H8 khc 19. Khi t chy mt HC A mch h cn 30 th tch khng kh , sinh ra 4 th tch CO 2 . A tc dng vi hidro c xc tc Ni to mt hidrocacbon no mch nhnh .Xc nh ctct ca A bit khng kh chim 20 % th tch 20.dn 3,584 l hn hp X gm 2 anken lin tip nhau trong dy ng ng vo nc brom d thy khi lng bnh ng nc brom tng 10,50 g a. Tm ctpt ca A , B . Bit th tochs kh o 00 C vaf 1,25 at

b. Tnh t khi ca hn hp so vi hidro Bi tp ankin Bi 1: t chy hon ton 0,25 mol hn hp kh gm ankin A v anken B thu c sn phm ln lt qua bnh 1 ng P2O5 d v bnh hai ng KOH d m c th thy bnh 1 khi lng tng 11,7 gam, bnh 2 khi lng tng 30,8 gam. Xc nh CTPT ca A, B bit rng A km hn B mt nguyn t C. Bi 2: a) Gii thch ti sao Al4C3 thu phn to CH4 cn CaC2 li thu phn to C2H2. b) Tch ri hn hp gm : metan, etilen v axetilen Butin-1, butin-2 v butan. c) iu ch PVC t than , vi, NaCl v H2O. Bi 3: Mt bnh kn dung tch 17,92 lit ng hn hp kh H2 v axetilen (00C v 1 atm) v mt t bt Ni. Nung nng bnh mt thi gian sau lm lnh n 00C . a) Nu cho lng kh trong bnh sau khi nung qua dung dch AgNO3 trong NH3 d s to 2,4 gam kt ta vng. Tnh khi lng axetilen cn li sau phn ng . b) Nu cho lng kh trong bnh sau khi nung qua dung dch nc brom ta thy khi lng dung dch tng ln 0,82 gam. Tnh khi lng etylen to thnh trong bnh c) Tnh th tch etan v th tch H2 cn li, bit rng hn hp kh ban u c t khi so vi H2 bng 4 . Bi 4: t chy hon ton 0,1 mol cht hu c A cn 12,8 gam O2. Sau phn ng thu c 16,8 lit hn hp hi (1360C ; 1atm) gm CO2 v hi nc. Hn hp ny c t khi so vi CH4 l 2,1. a) Xc nh CTPT ca A. Vit CTCT c th c ca A. b) Xc nh ng CTCT ca Av gi tn A bit rng A to kt ta vng khi cho tc dng vi dung dch AgNO3 trong NH3. Tnh lng kt ta khi cho 0,1 mol A phn ng vi hiu sut 90%. Bi 5: Mt hn hp gm axetilen , propilen, v metan. - t chy hon ton 11 gam hn hp th thu c 12,6 gam nc. - Mt khc 5,6 lit hn hp (ktc) phn ng va vi dung dch cha 50 gam brom. Xc nh thnh phn % th tch ca hn hp u. Bi 6: a) Hidrocacbon A, B u dng mch h. Trong phn t A c 5 lin kt s v 4 lin kt p. Trong phn t B c 7 lin kt s v 3 lin kt p. Xc nh CTCT ca A,B v gi tn. b) Hn hp A gm hai hidrocacbon mch h A, B (l nhng cht trong dy ng ng ankan, anken, ankin). - Dn 336 ml (ktc) A t t qua dung dch nc brom d thy c 4 gam brom tham gia phn ng v khng c kh thot ra. - Nu t chy hon ton 336 ml (ktc) A ri dn sn phm thu c qua nc vi trong c d th thu c 4 gam kt ta . 1) Tnh thnh phn % v th tch X, Y trong A. 2) Xc nh CTPT ca X, Y. Bi 7: Mt hn hp kh X gm mt ankan, mt anken v mt ankin c th tch 1,792 lit ( ktc) c chia lm hai phn bng nhau: - Phn 1 cho qua dung dch AgNO3 trong NH3 d to ra 0,735 gam kt ta v th tch hn hp gim 12,5 %. - Phn 2 em t chy hon ton ri hp th ton b sn phm vo 9,2 lit dung dch Ca(OH)2 0,0125 M thy c 11 gam kt ta. Xc nh CTPT ca cc hidrocacbon. Bi 8: Cho 4,96 gam hn hp gm Ca, CaC2 tc dng ht vi H2O thu c 2,24 lit ( ktc) hn hp kh X. a) Tnh % khi lng CaC2 trong hn hp u b) un nng hn hp kh X c mt xc tc thch hp mt thi gian c hn hp kh Y. Chia Y lm hai phn bng nhau. - Ly phn 1 cho qua t t dung dch nc brom d thy cn li 0,448 lit (ktc) hn hp kh Z c t khi hi vi H2 bng 4,5. Hi khi lng bnh nc brom tng ln bao nhiu. - Phn hai trn vi 1,68 lit oxi ( ktc) vo bnh kn c th tch 4 lit. Sau khi bt tia la in t chy, gi nhit 109,20C. Tnh p sut bnh nhit ny. Bit rng dung tch bnh khng i Bi 9: t chy hon ton hn hp X gm hai hidrocacbon A, B thuc cng mt dy ng ng thu c 19,712 lit CO2 (ktc) v 10,08 gam nc. a) Xc nh ng ng ca A, B bit rng chng c th l anken, ankan, ankin. b) Xc nh CTPT, CTCT c th c ca A, B bit chng u th kh iu kin thng. c) Tnh th tch O2 cn thit t chy ht lng hn hp X bng hai phng php khc nhau.

d) Chn CT ng ca A, B bit rng khi cho lng hn hp X tc dng vi dung dch AgNO3 trong NH3 d th ta thu c 4,8 gam kt ta Bi 10: Mt hn hp X gm hai ankin v hidro c V = 35,84 lit (ktc). Chia X lm hai phn bng nhau. Phn 1 c un nng vi Ni xc tc thu c hn hp Y khng lm phai mu nc brom v c th tichs gim 50% so vi th tch ban u. t chy hon ton hn hp Y ri cho sn phm chy tc dng vi dung dch NaOH thu c hai mui ccbonat. Thm Ca(OH)2 d vo dung dch hai mui ny c 70 gam kt ta. Phn hai cho qua dung dch AgNO3 d trong NH3 thu c 14,7 gam kt ta . Cho bit hai an kin ny u th kh ktc v c th tch bng nhau. a) Xc nh CTCT ca hai ankin. b) Tnh t khi ca hn hp Y so vi khng kh. Bi 11: Mt hn hp X gm hai hidrocacbon cng mt dy ng ng (ankan, anken hoc ankin) u th kh ktc. Cn 20,16 lit O2 t chy ht X v phn ng to ra 7,2 gam nc. a) Xc nh dy ng ng ca A, B v vit CTPT c th c ca A, B. b) Xc nh CTCT ca A,B bit rng khi cho mt lng hn hp X nh trn tc dng vi dung dch AgNO3 trong NH3 d thu c 62,7 gam kt ta. c) Mt hn hp Y gm A, B nh cu (b) v mt hidrocacbon D. T khi ca D so vi H2 bng 15,17. t chy hn hp Y thu c 57,2 gam CO2 v 23,4 gam nc. Chng minh rng D thuc dy ng ng ankan. Bit rng D c cng s nguyn t C vi A hoc vi B, nD = nA + nB . Xc nh CTPT ca D v thnh phn hn hp Y Bi 12: a) Khi t chy mt hidrocacbon A bng lng O2 d 20% so vi lng cn thit th thu dc t l CO2 v nc l 2 :1. Sau khi lm ngng t hi nc th th tch cn li bng 2,5 ln th tch ca A. Xc nh CTPT ca A bit cc kh o cng k. b) X l hn hp A ( trn) v B ( l ng ng ca A) c VX = 17,92 lit (ktc) v mX = 29,2 gam. Cho hn hp ny qua dung dch AgNO3 trong NH3 d thu c 120 gam kt ta. Tm CTPT, CTCT ca B v gi tn B theo theo hai cch c)Hn hp Y gm ton b lng X trn v H2 . Cho Y vo mt bnh dung tch 11,2 lit c cha mt t Ni th p sut P1 = 5,6 atm 00C. Nung bnh mt thi gian sau a v 00C th thu c hn hp Z c p sut gim 4/7 so vi p sut ban u. Phn ng cng H2 c hon ton hay khng? Tnh t khi ca Z so vi Y. Bi 13: t chy hon ton hn hp A gm hai hidrocacbon X, Y cng dy ng ng mch h. Hp th ton b sn phm chy vo 4,5 lt dung dch Ca(OH)2 0,02M, thu c kt ta v khi lng dung dch tng 3,78 gam. Cho dung dch Ba(OH)2 va vo dung dch thu c kt ta li tng thm, tng khi lng kt ta hai ln l 18,85 gam. T khi hi ca hn hp A so vi He < 10. Xc nh CTCT ca X, Y bit rng s mol ca X bng 60% tng s mol ca X v Y c trong hn hp A, cc phn ng xy ra hon ton. Bi 14: Trong mt bnh kn dung tch 20 lit cha 9,6 gam O2 v m gam hn hp ba hidrocacbon A, B, C. Nhit v p sut trong bnh l )0C v 0,448 atm. Bt tia la in t chy ht cc hidrocacbon v gi nhit 136,5 0C, p sut trong bnh lc ny l P. Cho hn hp kh trong bnh sau phn ng ln lt qua bnh 1 ng H2SO4 c v bnh hai ng KOH d thy khi lng bnh 1 tng 4,05 gam v bnh hai tng 6,16 gam. 1) Tnh P gi thit dung tch bnh khng i. 2) Xc nh CTPT ca cc hidrocacbon, bit B, C cng s nguyn t cacbon v s mol ca A gp 4 ln tng s mol ca B v C Bi 15: Cho a gam CaC2 cha b % tp cht tr, tc dng vi H2O thu c V lit kh C2H2 (ktc). 1) Lp biu thc tnh B theo A v V. 2) Nu cho V lt kh trn vo bnh kn c than hot tnh xc tc nung nng n t0C th p sut l P1. Sau phn ng thu c hn hp kh trong sn phm phn ng chim 60% th tch, nhit t0C, p sut l P2. Tnh hiu sut h ca phn ng. 3) Gi s dung tch bnh khng i, th tch cht rn khng ng k hy lp biu thc tnh P2 theo P1 v h l hiu sut ca phn ng . Tm khong xc nh ca P2 theo P1. Cu 1 - 1: Hn hp X gm propen v mt ng ng B theo t l th tch 1:1. t 1 th tch hn hp X cn 3,75 th tch oxi (cng k). CTPT B? Cu 2 - 4: Mt hn hp kh A ng mol gm 1 ankan, 1 anken c cng s carbon. Cho a (g) hn hp A phn ng va vi 120g dd Br2 20% trong CCl4. t a (g) hn hp trn thu c 20,16 lt CO2 (ktc). CTPT ca ankan & anken? Cu 3 - 5: t chy hon ton m (g) hn hp gm C3H6 ; C2H4 v C2H2 thu c 4,48 lt kh CO2 (ktc). Nu hidro ho hon ton m (g) hn hp trn, ri t chy ht hn hp thu c bao nhiu lt CO2 (ktc)? Cu 4 - 6: t chy hon ton m (g) etanol thu c 3,36 lt CO2 (ktc). Nu un m (g) etanol vi H2SO4 c; 180oC ri t chy ht sn phm thu c a (g) H2O. Tnh a

Cu 5 - 12: (ch bi c thay i): Anken X tc dng vi nc (xc tc acid) to ra hn hp 2 ancol ng phn ca nhau c t khi hi so vi N2 l 2,64. CTCT X? MT S BI TP V HYDROCACBON NO & KHNG NO-1 Cu 1: Tng s ng phn cu to ca C4H9Cl l: a. 3 b. 4 c. 5 d. Kt qu khc Cu 2: Tng s ng phn khng lm mt mu dd Brm ca C5H10 l: a. 3 b. 4 c. 5 d. 6 Cu 3: t chy hon ton 0,5 mol hh X gm 1 ankan A (CnH2n + 2 n1) v 1 anken B (CmH2m m 2). Thu c 26,88 lt CO2 (kc) v 25,2g H2O. Cng thc phn t ca A, B l: a. C2H6 v C3H6 b. C3H8 v C2 H4 c. CH4 v C4H6 d. Kt qu khc Cu 4: Oxy ho hon ton hh X gm 2 hydrocacbon thuc cng dy ng ng thu c 6,6g CO2 v 4,5g H2O. Cng thc phn t 2 hydrocacbon trong X l: a. CH4 & C2H6 b. CH4 & C3H8 c. CH4 & C4H10 d. C a, b, c Cu 5: Ho hi hon ton 30g cht hu c X (cha C, H, O) 1370C, 1atm th X chim th tch 16,81 lt. Cng thc phn t ca X l: a. C3H8O b. C2H4O2 c. C A & B d. Khng th xc nh c Cu 6: Oxy ho hon ton hh kh X gm 2 hydrocacbon thuc cng dy ng ng thu c CO2 v H2O vi t l khi lng mCO 2 : mH2O = 11: 6. Cng thc phn t ca 2 hydrocacbon trong X l: a. CH4 & C4H10 hoc C2H6 & C4H10 b. C2H6 & C4H10 hoc C3H8 & C4H10 c. CH4 & C3H8 hoc C2H6 & C3H8 d. Khng th xc nh c Cu 7: Hp cht hu c A c 8 nguyn t ca 2 nguyn t v c MA < 32. Cng thc phn t ca A l: a. C4H4 b. C3H5 c. C2H6 d. Kt qu khc Cu 8: t chy hon ton mt hydrocacbon X. Sn phm chy thu c cho hp th ht vo 200ml dd Ca(OH)2 1M thy c 10g kt ta xut hin v khi lng bnh ng dd Ca(OH)2 tng 16,8g. Lc b kt ta, cho nc lc tc dng vi dd Ba(OH)2 d li thu c kt ta, tng khi lng hai ln kt ta l 39,7g. Cng thc phn t ca X l: a. C3H8 b. C3H6 c. C3H4 d. Kt qu khc Cu 9: Mt hydrocacbon X phn ng c vi clo to dn xut Y. Th tch hi ca Y bng 1/3,3 th tch hi ca etan c cng khi lng. Bit th tch c o trong cng iu kin v nhit v p sut, X l: a. C2H4 b. C2H6 c. C3H6 d. a hay b Cu 10: Trn 400ml hh X (gm hydrocacbon A v N2) vi 900ml O2 d ri t chy hon ton. Th tch hh kh sau phn ng l 1,4 lt. Sau khi ngng t hi nc th cn li 800ml, tip tc cho qua dd KOH th cn li 400ml kh thot ra. Cng thc phn t ca X l: a. C2H4 b. C2H6 c. C3H6 d. C3H8