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Chanyoung Park Raphael T. Haftka Paper Helicopter Project

Chanyoung Park Raphael T. Haftka Paper Helicopter Project

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Chanyoung ParkRaphael T. HaftkaPaper Helicopter Project

1Problem1: Conservative estimate of the fall timeEstimating the 5th percentile of the fall time of one helicopterEstimating the 5th percentile to compensate the variability in the fall time(aleatory uncertainty)The sampling error (epistemic uncertainty)Estimating the sampling uncertaintyin the mean and the STDObtaining a distribution of the 5th percentileTaking the 5th percentile of the 5th percentile distribution to compensatethe sampling error

SamplingSamplingmt,Pst,PtPt0.05,P

Structural & Multidisciplinary Optimization Group#/252Estimating the 5th percentile of the fall time of first helicopter (mean 3.78, std 0.37)100,000 5th percentiles of fall timeHelicopter 1 of the dataset 3Height: 148.5 in2.88 (sec) is the 5th percentile of the histogram(a conservative estimate ofthe 5th percentile of the fall time for 95% confidence)

Problem1: Conservative estimate of the fall time

Structural & Multidisciplinary Optimization Group#/253Problem2: Predicted variability using priorCalculating predicted variability in the fall timeWe assume that the variability in the fall time is caused by the variability in the CDThe variability in the fall time is predicted using the computational model (quadratic model) and the distribution of the CD

The prior distribution represents our initial guess for the distribution of the CD

Height at time tSteady state speedwhere

Structural & Multidisciplinary Optimization Group#/25Problem2: Comparing predicted variability and observed variability using priorArea metric with the priorData set 3

0.290.340.49CD from the fall time dataHelicopter1Helicopter2Helicopter3Sample mean of CDs0.8960.8420.783Sample STD of CDs0.1900.1540.084PriorMean of CD = 1 / STD of CD = 0.28

Structural & Multidisciplinary Optimization Group#/25Problem3: Calibration: Posterior distribution of mean and standard deviationEstimating parameters of the CD distributionWe assume that CD of each helicopter follows the normal distribution

The parameters, CD and test are estimated using 10 dataPosterior distribution is obtained based on 10 fall time data

Non informative distribution is used for the standard deviation

After 1 updateAfter 5 updatesAfter 10 updates

Structural & Multidisciplinary Optimization Group#/25Problem3: Comparing predicted variability using posterior and observed variabilityComparing MLE and sampling statistics

MCMC sampling10,000 pairs of the CD and the STD of CD are generated using Metropolis-Hastings algorithmAn independent bivariate normal distribution is used as a proposal distributionMLE of the posterior distribution is used as a starting point

CD from the fall time dataHelicopter1Helicopter2Helicopter3Sample mean of CDs0.8960.8420.783Sample STD of CDs0.1900.1540.084MLE of the CD mean0.8960.8430.783MLE of the CD STD0.1820.1460.081

Structural & Multidisciplinary Optimization Group#/25MLE individual or both. MLE and mode?Problem3: Comparing predicted variability using posterior and observed variabilityHandling the epistemic uncertainty due to finite sampleHow to handle epistemic uncertainty in the CD and the test standard deviation estimates?Comparing the posterior predictive distribution of the fall time and the empirical CDF of tests (combining epistemic and aleatory uncertainties)Using p-box with 95% confidence interval of epistemic uncertainty (separating epistemic and alreatory uncertainties)

Structural & Multidisciplinary Optimization Group#/25Problem3: Comparing predicted variability using posterior and observed variabilityArea metric of the posterior predictive distribution of CD

0.150.110.07CD from the fall time dataHelicopter1Helicopter2Helicopter3148.5 in2 clips (ref)Sample mean of CDs0.8960.8420.783Sample STD of CDs0.1900.1540.084

Structural & Multidisciplinary Optimization Group#/25Problem3: Comparing predicted variability using posterior and observed variabilityArea metric of the posterior predictive distribution of CD

0.010.000.00

CD from the fall time dataHelicopter1Helicopter2Helicopter3148.5 in2 clips (ref)Sample mean of CDs0.8960.8420.783Sample STD of CDs0.1900.1540.084

Structural & Multidisciplinary Optimization Group#/25Problem4: Predictive validation for the same height and different weightArea metric of the posterior predictive distribution of CD

0.190.340.38

CD from the fall time dataHelicopter1Helicopter2Helicopter3148.5 in1 clipsSample mean of CDs0.9160.9920.968Sample STD of CDs0.1470.0690.049148.5 in2 clips (ref)Sample mean of CDs0.8960.8420.783Sample STD of CDs0.1900.1540.084

Structural & Multidisciplinary Optimization Group#/25Problem4: Predictive validation for the same height and different weightArea metric of the distribution of CD with p-box

0.010.110.22

CD from the fall time dataHelicopter1Helicopter2Helicopter3148.5 in1 clipsSample mean of CDs0.9160.9920.968Sample STD of CDs0.1470.0690.049148.5 in2 clips (ref)Sample mean of CDs0.8960.8420.783Sample STD of CDs0.1900.1540.084

Structural & Multidisciplinary Optimization Group#/25Problem6: Predictive validation for different height and the same weightArea metric of the posterior predictive distribution of CD

0.340.190.09

CD from the fall time dataHelicopter1Helicopter2Helicopter3181.25 in2 clipsSample mean of CDs0.8860.8660.816Sample STD of CDs0.0790.1190.066148.5 in2 clips (ref)Sample mean of CDs0.8960.8420.783Sample STD of CDs0.1900.1540.084

Structural & Multidisciplinary Optimization Group#/25Problem6: Predictive validation for different height and the same weightArea metric of the distribution of CD with p-box

0.050.000.01

CD from the fall time dataHelicopter1Helicopter2Helicopter3181.25 in2 clipsSample mean of CDs0.8860.8660.816Sample STD of CDs0.0790.1190.066148.5 in2 clips (ref)Sample mean of CDs0.8960.8420.783Sample STD of CDs0.1900.1540.084

Structural & Multidisciplinary Optimization Group#/25Problem5: Linear modelArea metric with the priorData set 30.650.680.81CD from the fall time dataHelicopter1Helicopter2Helicopter3Sample mean of CDs0.9780.9490.916Sample STD of CDs0.1020.0910.050PriorMean of CD = 1 / STD of CD = 0.28

Structural & Multidisciplinary Optimization Group#/25Comparison to predictive validationArea metric of the posterior predictive distribution of CDThe predictive validation with the linear model is not as successful as that with the quadratic model

Area metric with p-boxArea metric with p-box tries to capture the extreme discrepancy between the predicted variability and the observed variabilityHelicopter1Helicopter2Helicopter3148.5 in / 1 clips0.130.060.02148.5 in / 2 clips (ref)0.010.000.00Helicopter1Helicopter2Helicopter3148.5 in / 1 clips0.440.300.14148.5 in / 2 clips (ref)0.130.110.07

Structural & Multidisciplinary Optimization Group#/25Problem5: Linear modelArea metric of the posterior predictive distribution of CD

0.130.110.07CD from the fall time dataHelicopter1Helicopter2Helicopter3148.5 in2 clips (ref)Sample mean of CDs0.9780.9490.916Sample STD of CDs0.1020.0910.050

Structural & Multidisciplinary Optimization Group#/25Problem5: Linear modelArea metric of the distribution of CD with p-box

0.010.000.00CD from the fall time dataHelicopter1Helicopter2Helicopter3148.5 in2 clips (ref)Sample mean of CDs0.9780.9490.916Sample STD of CDs0.1020.0910.050

Structural & Multidisciplinary Optimization Group#/25Problem5: Linear model with one clipArea metric of the posterior predictive distribution of CD

0.440.300.14CD from the fall time dataHelicopter1Helicopter2Helicopter3148.5 in1 clipsSample mean of CDs0.8820.9230.911Sample STD of CDs0.0780.0330.025148.5 in2 clips (ref)Sample mean of CDs0.9780.9490.916Sample STD of CDs0.1020.0910.050

Structural & Multidisciplinary Optimization Group#/25Problem5: Linear model with one clipArea metric of the distribution of CD with p-box

0.130.060.02CD from the fall time dataHelicopter1Helicopter2Helicopter3148.5 in1 clipsSample mean of CDs0.8820.9230.911Sample STD of CDs0.0780.0330.025148.5 in2 clips (ref)Sample mean of CDs0.9780.9490.916Sample STD of CDs0.1020.0910.050

Structural & Multidisciplinary Optimization Group#/25Comparison between quadratic and linear modelsArea metric of the posterior predictive distribution of CD

Area metric of the distribution of CD with p-box

Helicopter1Helicopter2Helicopter3148.5 in / 1 clipLinear0.190.340.38Quadratic0.440.300.14148.5 in / 2 clips (ref)Linear0.130.110.07Quadratic0.150.110.07Helicopter1Helicopter2Helicopter3148.5 in / 1 clipLinear0.130.060.02Quadratic0.010.110.22148.5 in / 2 clips (ref)Linear0.010.000.00Quadratic0.010.000.00

Structural & Multidisciplinary Optimization Group#/25Concluding remarks Predictive validation for both quadratic and linear modelsThe predictive validation for different mass is a partially successThe predictive validation for different height is a success but the assumption of constant CD is not clearly proven Comparison between modelsCannot conclude OverallReason for the differences in the area metric is not clearThe effect of the manufacturing uncertainty is significant (i.e. very different area metrics for the same test condition)

Structural & Multidisciplinary Optimization Group#/25Many designs have multiple failure modes. Probabilistic design approach has clear advantages over deterministic design in providing tradeoff between improving performance and protecting failure modes. Dr. Acar studied the effect of allocating risks for aircraft design with wings and a horizontal tail. Instead of applying the same design margins, allocating risks by moving a small amount of material from the wing to horizontal tail provides safer and lighter design. Dr. Qu investigated probabilistic design approach for cryogenic tank design, which has two failure modes, thermal and mechanical failure modes. To apply probabilistic design, system reliability has be to determined. Applying independence assumption for failure modes can simplify evaluating system reliability. However, in many cases, failure modes are correlated, ignoring dependence results error in system reliability. The effect of ignoring dependence with respect to important factors will be presented. 22First overall comment is not clear

Paper ClipsHeightCalibrated?ModelArea MetricSet 1 Model 1Set 1 Model 2Set 1 Model 3Set 3 Model 1Set 3 Model 2Set 3 Model 321noquadratic0.53760.83970.57170.30040.37060.529921yesquadratic0.1430.4420.190.3050.2670.094612yesquadratic0.62720.8330.65030.39270.5930.544221nolinear0.96391.02021.00620.63850.57370.738821yeslinear0.10730.50030.25870.35710.31040.139811yeslinear1.32161.53981.34570.2130.2070.16822yesquadratic0.1690.2140.2840.4610.4240.269

Kaitlin Harris, VVUQ Fall 2013Comments:Chose to maintain uniform distribution for calibration parameter based on histogram results (vs normal)Conclusions: Best models: calibrated quadratic at both heights and calibrated linear with 2 paper clips Worst models: un-calibrated linear with 2 paper clips and un-calibrated linear with 1 clip for data set 1

Validation of analytical model used to predict fall time for Paper HelicopterBy Nikhil Londhe *Calibrated Analytical Model is validated to represent experimental data *Quadratic dependence is valid assumption between drag force and speed *For given difference in fall height, Cd can be assumed to be constant Comparison of Analytical Cdf and Empirical CdfData Set 5, H=18.832, No. of Pins=2Helicopter 1Helicopter 2Helicopter 3Validation Area MetricBefore Calibration0.73090.69320.6169After Calibration0.28090.09060.142Calibration ResultsHelicopter 1Helicopter 2Helicopter 3Maximum Likelihood Estimate of Cd0.78890.89650.9111Standard deviation in Posterior pdf of Cd0.0460.01910.0238Predictive Validation for Data Set 5, No. of Pins =1H=18.832ft.Helicopter 1Helicopter 2Helicopter 3Validation Area Metric0.18690.24530.192Validation Area Metric for Linear Dependence ModelData Set 5Helicopter 1Helicopter 2Helicopter 3Validation Area Metric0.44350.26060.3506

Validation of Cd is constant at different height, h=11.482ftData Set 5, Pins = 2Helicopter 1Helicopter 2Helicopter 3Validation Area Metric0.41860.15920.1513Quadratic Dependence 2 clipsDifferent height.Quadratic Dependence 1 clipPredictive Validation.Linear Dependence 2 clips & 1clipPrior VS. Posterior Dist.Quadratic Dependence 2 clipsPrior VS. Posterior Dist.Course Project: Validation of Drag Coefficient -Yiming ZhangValidation based on 1 set of data:Validation based on 3 set of data:Summary: (1) Quadratic dependence seems accurate using one set; Quadratic and linear dependence both dont match well using 3 sets;

Prior Area Metric:0.4042

Post Area Metric:0.1695

Prior Area Metric:0.4920

Post Area Metric:0.2

Validation Area Metric:0.1923

Validation Area Metric:0.1267

2 clips:

1 clip:

Posterior Area Metric:0.1729

Validation Area Metric:0.1960 Summary:

Two confi. interval of Cd dont coincide. Linear dependence seems inaccurate.2 clips:

Posterior Area Metric:0.19871 clip:

Validation Area Metric: 0.1253 Summary:

Seems reasonable, but not accurate

Validation Area Metric:0.0970

Validation Area Metric:0.1394

(2) SRQ is required to be fall time. If use Cd as SRQ, comparison could be more consistent and clear;(3) 0.8 seems a reasonable estimation of Cd. This estimation would be more accurate while introducing more sets of data. Backup SlidesProblemsProblem1: Conservative estimate of the fall timeProblem2: Comparing predicted variability and observed variability using priorProblem3: Comparing predicted variability and observed variability using posteriorProblem4: Predictive validation for the same height and different weightProblem5: Comparing the quadratic and linear modelsProblem6: Predictive validation for different height and the same weight (proving the assumption of constant CD)

Structural & Multidisciplinary Optimization Group#/2527Problem1: Conservative estimate of the fall timeEstimating the 5th percentile of the fall time of one helicopterSince fall time follows a normal distribution, estimating the 5th percentile is based on estimating the mean and standard deviation (STD) of the fall time distributionThe mean and STD are estimated based on 10 samples There is epistemic uncertainty in the estimated mean and STD due to a finite number of samplesTo compensate the epistemic uncertainty, a conservative measure to compensate the epistemic uncertainty is requiredEstimating the 5th percentile with 95% confidence levelStructural & Multidisciplinary Optimization Group#/2528