Trng H K thut Cng nghip Thuyt minh n tt nghip
TRNG I HC K THUT CNG NGHIPKHOA C
KH__________________________
THUYT MINH N TT NGHIP K S C KH
Chuyn ngnh: C kh Ch to my
ti: Thit k quy trnh cng ngh gia cng chi tit trc then hoa.
Thit k: VNG CH DNG
Lp: K46CCM3
Hng dn khoa hc: Th.S : HONG VN QUYT
THI NGUYN - NM 2015TRNG I HC K THUT CNG NGHIPKHOA C
KH__________________________
TI TT NGHIP K S C KH
Chuyn ngnh: C kh Ch to my
ti: Thit k quy trnh cng ngh gia cng chi tit trc then hoa.
Yu cu:
1. Thuyt minh: .... trang.
2. Bn v: ........ bn A0
3.Chuyn :
Thit k: VNG CH DNG
Lp: K46CCM3
Ngy nhn ti: ....../10/2015
Ngy hon thnh: ......../...../2015
Thi Nguyn, ngy thng nm 2015
Hng dnTrng b mn
TRNG I HC K THUT CNG NGHIPKHOA C
KH__________________________
NI DUNG N TT NGHIP
Chuyn ngnh : C kh Ch to my
ti: Thit k quy trnh cng ngh gia cng chi tit trc then hoa.
Thuyt minh:
1. Phn I: Phn tch chi tit gia cng.
2. Phn II: Xc nh dng sn xut.
3. Phn III: Chn phi v phng php ch to phi.
4. Phn IV: Thit k qui trnh cng ngh
5. Phn V: Tra lng d cho cc b mt.
6. Phn VI: Tra ch ct cho cc nguyn cng.
Bn v:
1. Bn v chi tit lng phi: ... bn kh giy A0
2. S nguyn cng th hin dng kt cu: ... bn kh giy A0
Bn n tt nghip c thng qua ngy. thng. nm 2015
Hng dnTrng b mn
NHN XT CA GIO VIN HNG DN
.
LI NI UHin nay cc ngnh khoa hc k thut ni chung v ngnh k thut c
kh ni ring ang c mt mt bc pht trin ln. Hu ht cc sn phm ca c kh c mt
trong tt c cc hot ng i sng x hi, mang li nhng li ch to ln cho con
ngi c v vt cht ln tinh thn. Cc sn phm c kh c xem nh l xng sng ca
ngnh kinh t, phc v cc nhu cu sn xut v pht trin kinh t ca con ngi
trn th gii. thc hin mc tiu Cng nghip ha v hin i ha t nc ng ch trng
o to ngun nhn lc k thut ti cc trng k thut trong c nc. Vi sinh vin
ngnh ch to my, vic quan trng i hi sinh vin l phi hiu v lp c bn v
thit k v gia cng cc chi tit my. ng thi phi hiu c nguyn l lm vic ca
cc chi tit my a ra c phng n ch to hp l nht, m bo yu cu v kinh t k
thut.Thi Nguyn, ngy ... thng ...nm 2015
Sinh vin thc hinVng Ch Dng
n tt nghip Cng ngh ch to my c mc ch gip cho sinh vin lm quen vi
cc nhim v ngoi thc t yu cu sau khi ra trng. thc hin tt cng vic c
giao sinh vin phi tch cc tm hiu, tham kho cc ti liu cng ngh m thc t
sn xut ang s dng. Thng qua n ny sinh vin chng em c th cng c li tt c
cc kin thc c hc thit k, tnh ton ch to cc chi tit my. Vi ti: Thit k
quy trnh cng ngh gia cng chi tit trc then hoa.. Do kin thc cng hn
ch nn khng th trnh khi nhng sai st rt mong cc Thy c ch bo thm cho
em. Trong qu trnh lm n, em nhn c s gip ca Thy hng dn. Em xin chn
thnh cm n s hng dn tn tnh ca thy ThS. Hong Vn Quyt - B mn Ch to my,
Khoa c kh, trng i hc K thut Cng nghip gip em hon thnh n ny.MC LCLI
NI U5PHN I: PHN TCH CHI TIT GIA CNG81.1. Phn tch chc nng v iu kin
lm vic ca chi tit gia cng.81.2. Phn tch yu cu k thut v nh ra phng
php gia cng tinh ln cui.91.3. Bin php cng ngh t c cc YCKT quan
trng.101.4. Phn tch v nh gi tnh cng ngh trong kt cu chi tit Trc
rng10PHN II: XC NH DNG SN XUT112.1. ngha ca vic xc nh dng sn
xut.112.2. Xc nh dng sn xut.11PHN III: CHN PHI V PHNG PHP CH TO
PHI143.1. C s chn phi.143.2. Chn phng php to phi ti u nht.14PHN IV:
THIT K QUY TRNH CNG NGH174.1. Chn chun nh v.174.1.1. Vn chun nh v
khi gia cng.174.1.2. Chn chun tinh.174.1.3. Chn chun th.194.2. Thit
k quy trnh cng ngh.204.2.1. Lp trnh t cng ngh.204.2.2. Bn v s nguyn
cng.21PHN V: TRA LNG D CHO CC B MT395.1. Tra lng d cho cc b
mt.395.2. Phn b lng d.40PHN VI: TNH V TRA CH CT42 6.1. Nguyn cng I:
Ti ci thin42 6.2. Nguyn cng II: Phay mt u v khoan l tm42 6.3. Nguyn
cng III:Tin th mt tr 40, 45, 64, gc ln R543 6.4. Nguyn cng IV:Tin
th mt tr 20, 30, 40, 45, gc ln 46 6.5. Nguyn cng V: Tin th v tinh b
mt cn 20 3833( 30 - 24) 49 6.6. Nguyn cng VI : Tin tinh 20, 40 ,Vt
mp 20, 40, 64 v Xn rnh50 6.7. Nguyn cng VII: Tin tinh 40, 64. Vt mp
40, 6454 6.8. Nguyn cng VIII: Phay rng55 6.9. Nguyn cng IX: Phay
rnh then56 6.10. Nguyn cng X: Tin ren M20x1,557 6.11. Nguyn cng XI:
Nhit luyn.58 6.12. Nguyn cng XII: Mi c trc 4058 6.13. Nguyn cng
XIII: Mi c trc 40..59 6.14. Nguyn cng XIV: Mi th mt cn60 6.15.
Nguyn cng XV: Mi tinh c trc 40.61 6.16. Nguyn cng XVI: Mi tinh c
trc 4061 6.17. Nguyn cng XVII: Tng kim tra, ng gi, bo qun61TI LIU
THAM KHO62
Phn I :PHN TCH CHI TIT GIA CNG.I.Nhim v nguyn l lm vic, c im ca
chi tit gia cng :Chi tit gia cng l trc then hoa c nhiu rnh vi
prphin hnh thang.Hai u trc c then hoa v s lng rnh then khc
nhau.Chiu di trc l 250(mm) ,c hai v tr lp bi tiu chun l v tr c ng
knh 30(mm) chiu di ngng trc 17 (mm) v v tr c ng knh 40 (mm). Trc c
vai trc ngn chn di chuyn dc trc.Hai u trc c cc rnh then vi s lng v
thng s khc nhau.Trc then hoa c th lp bnh rng di trt (u trc c chiu
di then ln hn). u trc cn li c chiu di then ngn hn c th lp vo vnh
trong ca moay- bnh rng.Trc then hoa c tc dng truyn mmen xon ,truyn
chuyn ng cho bnh rng. lp bnh rng di trt truyn m men xon v chuyn
ng.II.Yu cu k thut chi tit gia cng :Chi tit gia cng l trc then hoa
hnh thang dng truyn chuyn ng cho bnh rng nn chu tc ng ca mmen xon v
mmen un. V rnh then hay mn theo 2 mt bn ( b mt lm vic). V vy phi m
bo cc iu kin sau :- khng ng tm gia cc bc trc khng qu 0,02 (mm).-
khng song song gia ng rng v ng tm trc 0,025 (mm).- cng sau nhit
luyn t 38 HRC.- nhm v tr ngng trc lp ln (Ra = 2,5) t cp chnh xc
6.-B mt lm vic ca rnh then (Ra=4) t cp chnh xc 7.-B mt ihr then t
cp chnh xc 6.- song song ca rnh then hay then hoa so vi ng sinh
0,1mm/mm.- cong ca trc khng qu 0,02 mmPhn II:XC NH DNG SN XUT.I.
ngha :Dng sn xut l 1 khi nim c trng c tnh cht tng hp gip cho vic xc
nh hp l ng li bin php cng ngh v ra phng n sn xut to ra sn phm t ch
tiu kinh t v k thut. Mi dng sn xut c nhng c im ring ph thuc vo nhiu
yu t khc nhau . Tuy nhin y ta khng i nghin cu su vo phng php xc nh
chng theo tnh ton.II.Sn lng c kh hng nm :Sn lng c kh c tnh theo cng
thc :
(ct/nm).Theo bi ra ta c sn lng k hoch l 1000 chic/nm.Trong :- Ni
: Sn lng c kh ct/nm.- N : Sn lng k hoch ct/nm.- mi : S chi tit
trong mt loi sn phm .- : H s d phng k n ph phm .- : H s k n h hng
mt mt.Thng thng = = 2 3 ly = = 2 : mi = 1 => ta c :
(ct/nm).III.Tnh khi lng chi tit gia cng:c xc nh theo cng thcQ =
V.Trong :Q : khi lng ca chi tit gia cng (Kg).V : Th tch ca chi tit
gia cng (dm3).V = V1 + V2 +V3 +V4.ss
(dm3).
(dm3).
(dm3).
(dm3). V = 0,32542 (dm3). : Khi lng ring ca vt liu.i vi chi tit
gia cng vt liu thp C45 : = 7,852 kg/ dm3.= >Khi lng chi tit gia
cng l : Q = 0,32542 . 7,852 =2,56 (kg).Da vo Q v Ni Theo bng 2
(TKDACNCTM) :`Ta tra c dng sn xut l lot va.Phn III: PHNG PHP TO
PHI.I.C s chn phi :Vi chi tit dng trc lm vic chu ti trng mmen tt
nht l t chc kim loi nm cht. C th chn phng php gia cng l cn, rn, dp,
cVic xc nh phng php to phi hp l s m bo yu cu k thut ca chi tit kch
thc ca phi phi m bo phn b lng d cho qu trnh gia cng hnh dng ca phi
cng ging chi tit cng tt. Yu cu ny cho php gim s ln chy dao gim thi
gian gia cng gim sai s in dp dn n tng nng xut, h gi thnh sn phm.Cn
c vo bn v chi tit ta so snh cc phng php to phi sau:II. Phng php to
phi :Vic to phi phi ph hp vi vic ch to chi tit phi cn c vo cc yu t
sau :- Vt liu : C c tnh vt liu m chi tit gia cng.- Dng sn xut : Tnh
cht xn xut, trang thit b, dng c gia cng .- Kh nng t c chnh xc gia
cng chn phi hp l.1. Phng php chn cn:Ch dng vi cc loi phi n gin,
khng cn c thp cn c t chc kim loi cht, u trong sut chm di, phi th
kim loi lin tc c lp ng xut d.Thp cn c tiu chun ho nn khi chn phi
phi chn phi c ng knh ln hn ng knh ln nht ca chi tit gia cng s mt
nhiu thi gian ct gt mt nhiu kim loi gim nng xut dn n gi thnh cao.2.
Phng php c:- u im : c c loi phi phc tp c ng knh ln.- Nhc im : T chc
kim loi c km, lm khuyt tt, i hi k thut cao.3. Phng php rn : a. Rn t
do:Vi u t thp trang thit b n gin nhng chnh xc ph thuc vo tay ngh
ngi cng nhn thi gian gia cng lu, vic ch to rt nh chnh xc thp do vi
sn xut ln nh ch to, kh p ng.+ u im :- C tnh tng i tt.- T chc kim
loi bn cht.- Chu un chu xon tt.+ Nhc im : - Nng xut khng cao.- Tiu
hoa nhiu nng lng, vt liu.- Hiu qu thp.- iu kin lao ng cc nhc, hay b
bin cng b mt, lng d ln.b. Phi rn khun.Phi c chnh xc cao hn phi rn t
do, lng gia cng nh bng cao, hnh dng phi rn ging nh hnh dng chi tit
nh vy s t nng xut cao hn, gim ph phm v chnh xc phi cao ph hp vi sn
xut ln nhng phng php ny vt liu ch to khun phc tp thit b i hi vn
ln.+ Rn trong khun kn :Thng p dng cho vt rn c hnh dng phc tp v thit
b.+ Rn trong khun h :Sn phm thng rn t phi cn cho bng v chnh xc
cao.4. Dp nng : Theo phng php ny phi c tnh cht c tnh tt ch to phi c
hnh dng phc tp.+ u im : - C tnh vt liu cao.- Nng xut cao.- C th dp
phi t ng.=> Qua phn tch cc phng php to phi vi loi sn phm l trc
then hoa sn xut dng sn xut lot va, ta chn phi dp l ph hp v tit kim
thi gian v nguyn cng v cc nguyn vt liu.
Phn IV :
THIT K QUY TRNH CNG NGH GIA CNG CHI TITI.Phn tch vic chon
chun:nh ngha: Chun l mt tp hp ng, im, b mt ca chi tit c dng lm cn c
xc nh v tr ca mt tp hp ng, im, b mt khc ca chi tit hay ca cc chi
tit khc trong cng mt mi quan h lp rp nht nh.Vic phn tch chn chun nh
v c ngha quan trng n quyt nh ti cht lng chi tit gia cng do vy vic
chn chun phi tho mn 2 yu cu sau :- Phn b lng d trn ton chi tit
trong sut qu trnh gia cng ng u.- Nng sut v gi thnh h.Nguyn tc chn
chun :- Chn chun xut pht t nguyn tc 6 im khng ch tt bc t do, cn
trnh hin tng siu nh v.- Chn chun sao cho khng b lc ct, lc kp lm bin
dng chi tit qu nhiu- Chn chun sao cho thit k g n gin thch hp vi loi
hnh sn xut p ng c yu cu k thut t ra.1. Chn chun tinh :Yu cu :- Phn
b lng d cho cc b mt gia cng.- m bo chnh xc tng quan gia cc b mt.Li
khuyn :1.C gng chn chun tinh l chun tinh chnh. Thc hin li khuyn ny
s n gin ho qu trnh gia cng, lp gip v chi tit c v tr tng ng nh khi
lm vic chn nh vy phi gia cng thm chun tinh ph.2.Chn chun sao cho
tnh trng chun cng cao cng tt. (CKX CL CV CCD CCS).3.C gng chn chun
tinh l chun tinh thng nht .Trong qu trnh gia cng chn nh vy s gim c
chng loi g do gim c thi gian thit k v ch to g.* Phng n 1: Chun tinh
l 2 l tm.Chun tinh l hai mi tm dng truyn m men, s nh v nh di. Phng
n ny khng ch nm bc t do ch cn duy nht mt bc t do quay quanh ox.
u im:- Khng gian gia cng rng- L chun tinh thng nht dng gia cng
cc b mt ngng trc,then hoa.Nhc im:- cng vng thp.- Phi gia cng thm
chun tinh ph.* Phng n 2: Chun tinh l mt tr ngoi.
Chn chun tinh l hai mt tr ngoi s khng ch c 4 bc t do, bc t do th
5 cn khi khng ch mt bc ca chi tit. Bc th 6 khng cn khng ch.u im: -
C g t cao.- cng vng cao.Nhc im:- Phi ch to g nn phng n ny t tin. Ta
s dng phng n ny lm chun tinh khi phay rnh then.* Phng n 3: Chun
tinh l mt tr ngoi kt hp l tm.u im:- G t nhanh.- cng vng cao hn dng
hai mi tm.- Khng ch c sai s dc trc.Nhc im:Gim chnh xc tng quan gia
cc b mt.
nh v mt tr ngoi. Bng mm cp ba chu t nh tm v mt u chng tm. Phng n
ny b hn ch bi s chnh sc ca mm cp lm gim chnh xc tng quan gia cc b
mt =>Da vo cc li khuyn khi chn chun tinh v do sn xut dng lot va
nn ta chn chun tinh theo phng n 1.2.Chn chun th : Yu cu :1. m bo
chnh xc v v tr tng quan gia cc b mt khng gia cng vi cc b mt gia
cng.2. Phn phi lng d cho cc b mt s gia cng.Li khuyn : 1.Theo mt
phng kch thc nht nh, nu trn chi tit gia cng c mt b mt khng gia cng
th nn chn b mt lm chun th.2.Theo mt phng kch thc nht nh, nu trn chi
tit gia cng c hai hay nhiu b mt khng gia cng th nn chn b mt no yu
cu chnh xc v v tr tng quan so vi b mt gia cng l cao nht l chun
th.3.Theo mt phng kch thc nht nh, nu trn chi tit gia cng c tt c cc
b mt u gia cng th nn chn b mt no yu cu lng d nh v ng u nht lm chun
th.4.Nu c nhiu b mt tiu chun lm chun th th chn b mt bng phng trn
tru nht lm chun th.5.ng vi mt bc t do cn thit th chun th ch c chn v
s dng khng qu mt ln trong c qu trnh gia cng. Nu vi phm li khuyn ny
th gi l phm chun th, khi s lm cho sai s v v tr tng quan gia cc b mt
l rt ln.= > Chn chun th l b mt th ca hai ngng trc :
II- Lp quy trnh cng ngh :1.Trnh t cc nguyn cng : Thit k quy trnh
cng ngh gia cng chi tit ta phi xc nh hp l tin trnh cng ngh ng vi cc
b mt gia cng v cn c vo yu cu sau :- Xc nh v thc hin nguyn cng chn
chun th, tnh cn c vo nhn bng v chnh xc b mt m p dng bin php gia cng
ln cui cho thch hp.- m bo chn chun tinh thng nht.- Ch nhng nguyn
cng c th gy ph phm.- C gng gim s ln g t.Da vo cc phng n chn chun th
v chun tinh chn, cn c vo trng thi b mt cui cng ca chi tit gia cng ,
ta lp c th t gia cng cc b mt nh sau:
TT NCTn Nguyn CngMyDao
I
IIPhay mt uKhoan l tmMP76MT15K6P18
IIITin th mt tr 42 Tin th mt tr 37,5Tin th mt tr 30T616T15K6
IVTin th mt tr 49Tin th mt tr 40Tin th mt tr 39T616T15K6
VTin tinh mt tr 40Tin th mt tr 39Vt mp 1,5x45oT616T15K6
VITin tinh mt tr 42Tin th mt tr 30Vt mp 49Vt mp 42T616T15K6
VIIPhay then hoa 395K32P18
VIIIPhay then hoa 425K32P18
IXTi ton b chi tit t HRC=38
XMi th c trc 40312300x40x127 14A20K3
XIMi th c trc 30312300x40x127 14A20K3
XIITng kim tra v nh gi
2. Bn v s nguyn cng:
Phn V: PHN PHI LNG D CHO CC B MT5.1.Mc ch ca vic tra lng d
:Trong qu trnh ch to phi, t chnh xc cao v hp l phn ln ph thuc vo
vic xc nh lng d gia cng. Lng d gia cng c xc nh hp l v tr s v dung
sai c ngha rt ln trong vic h gi thnh sn phm, nng cao nng sut. Nu
lng d qu ln th tn nguyn vt liu, chi ph cho my, dao cng tng dn n vic
tng gi thnh. Nu lng d qu b th khng ht i lng d gia cng, khng m bo
chnh xc gia cng. iu ny c th c gii thch bng h s in dp K: sai lch ca
chi tit v phiNh vy sai lch s gim dn sau mi ln gia cng. V vy trong
quy trnh cng ngh phi chia thnh nhiu nguyn cng, nhiu bc ht dn i lng
d, do lng d phi thc hin cc nguyn cng. Khi lng d qu nh cn xy ra hin
tng trt gia dao v chi tit gia cng lm cho dao mn nh hng n cht lng b
mt gia cng.Trong ch to my thng tnh lng d theo hai phng php:+ Phng
php tnh ton phn tch + Phng php thng k kinh nghim (tra bng).Trong n
ny ta s dng phng php tra bng xc nh lng d cho cc nguyn cng. 5.2:Cc
phng php tnh lng d :a) Phng php thng k kinh nghim.Theo phng php ny
lng d gia cng c xc nh theo kinh nghim, c rt ra t thc t sn xut, chng
c thng k li v ghi trong cc s tay gip cho vic tra cu.u im: d tra cu,
s dng n gin.Nhc im: lng d gia cng thng khng tnh cho iu kin c th vi
chi tit c th.b) Phng php tnh ton phn tch.Phng php ny da trn l thuyt
bin dng n hi ca h thng cng ngh di tc ng ca ti trng thay i.u im:
Phng php ny cho php xc nh lng d gia cng cho chi tit c th v ti u nht
vi iu kin sn xut ca nh my. m bo tnh kinh t k thut ca sn phm ch
to.Nhc im: tnh ton phc tp5.3:Tnh v tra lng d : Trong n ny ta s dng
phng php tra bng xc nh lng d cho cc nguyn cng. Vi phi c rn trn my
rn ngang ta s tra lng d trong bng 3.9(II) 5.3:. Tra lng d cho cc b
mt :Tra bng 3.9(II) vi G = 2,56 (kg) * B mt 40(mm) : 2Zb = 2,6(mm)-
Vi phi c rn trn my rn ngang nn ly thm 0,5(mm)- nhm b mt Ra 2,5(m)
ta ly thm 0,5(mm)Vy lng d tng cng cho mt tr 40 l: 2Zb = 3,6(mm)* B
mt 39 (mm) : 2Zb = 2,6(mm)- Vi phi c rn trn my rn ngang nn ly thm
0,5(mm)- nhm b mt Ra 2,5(m) ta ly thm 0,5(mm)Vy lng d tng cng cho
mt tr 39 l: 2Zb = 3,6(mm)* B mt 30(mm): 2Zb = 2,6(mm)- Vi phi c rn
trn my rn ngang nn ly thm 0,5(mm)- nhm b mt Ra 2,5(m) ta ly thm
0,5(mm)Vy lng d tng cng cho mt tr 30 l: 2Zb = 3,6(mm)* B mt 42(mm):
2Zb = 2,6(mm)- Vi phi c rn trn my rn ngang nn ly thm 0,5(mm)- nhm b
mt Ra 2,5 ta ly thm 0,5(mm)Vy lng d tng cng cho mt tr 42 l : 2Zb =
3,6(mm) * B mt 37,5 (mm): 2Zb = 2,6(mm)- Vi phi c rn trn my rn
ngang nn ly thm 0,5(mm)- nhm b mt Rz 20 (m), ta ly thm 0,3 (mm)Vy
lng d tng cng cho mt tr 37,5 l : 2Zb = 3,4(mm)* B mt 49(mm): 2Zb =
2,6(mm)- Vi phi c rn trn my rn ngang nn ly thm 0,5(mm)- nhm b mt Rz
20 (m), ta ly thm 0,3(mm)Vy lng d tng cng cho mt tr 49 l : 2Zb =
3,4(mm)* Mt u: 2Zb = 3,2(mm)- Vi phi c rn trn my rn ngang nn ly thm
0,5(mm)- nhm b mt Rz 40(m), ta ly thm 0,5(mm)Vy lng d tng cng cho
mt u l : 2Zb = 4,2(mm )5.3.2: Phn b lng d :* Mt tr 40 :- Tin th:
2,2 (mm) - Tin tinh: 1,0 (mm)- Mi : 0,4 (mm)* Mt tr 39 :- Tin th:
2,2 (mm) - Tin tinh: 1,0 (mm)- Mi : 0,4 (mm)* Mt tr 30 : - Tin th:
2,2 (mm) - Tin tinh: 1,0 (mm)- Mi : 0,4 (mm)* Mt tr 42 :- Tin th:
2,2 (mm) - Tin tinh: 1,0 (mm)- Mi : 0,4 (mm)* Mt tr 37,5 :- Tin th:
3,4 (mm) * Mt tr 49 :- Tin th: 3,4 (mm) * B mt then hoa 39 :- Phay
then: 1,5 (mm) * B mt then 42 :- Phay then : 1,75 (mm) * Mt u. -
Phay mt u: 2,1 (mm)
PHN VITNH V TRA CH CT
Ch ct ca qu trnh gia cng ct gt ph thuc vo nhiu yu t nh vt liu
gia cng, kt cu dng c ct, vt liu v thng s ca dng c ct, phng php g,
dung dch trn ngui v tnh trng ca h thng cng ngh.Vic xc nh ch ct hp l
l mt trong nhng bin php nng cao nng sut ct v tng cht lng b mt gia
cng.C nhiu phng php tnh ch ct nhng trong thc t sn xut ngi ta thng
dng phng php tra bng theo kinh nghim:Tham kho cc S tay cng ngh ch
to my, tnh ton v tra bng ta c thng s ca ch ct nh sau:6.1. Nguyn cng
I: Ti ci thin 6.2. Nguyn cng II: Phay mt u, Khoan tm* Bc 1: Kho mt
u t = 2,1 (mm)Tra bng 5.108[II]. Vi Thp 45C c sb = 80(KG/mm2); Nhn
hiu hp kim cng T15K6 Sb = 0,11 (mm/vg)Lng chy dao tnh ton Stt :Stt
= Sb.K1.K2K1,K2 : H s ph thuc g dao v gc nghing chnh+ Dao g cn. Tra
bng 5.109(II) c: K1 = 1+ j = 30oTra bng 5.110(II) c : K2 = 1,5 Stt
= 0,11.1.1,5 = 0,165 (mm/vg) Chn theo my c: Sm = 0,15 (mm/vg)Vn tc
ct. Tra bng 5.111(II) c: Vb = 249(mm/ph)Vn tc ct tnh ton Vtt =
VbK1.K2.K3.K4.K5K1: H s ph thuc c tnh ca thp. K1 = 1,26K2 H s ph
thuc nhn hiu HKC ca thp. K2= 1,0K3: H s ph thuc trng thi b mt gia
cng. K3 = 1,0K4: H s ph thuc chiu rng phay. K4 = 1,0K5: H s ph thuc
gc nghing chnh. K5 = 1,1Vtt = 249.1,26.1.1.1.1,1 = 345,1(mm/ph)- S
vng quay ca my: tra theo chui s vng quay ca my nm = 600(vg/ph) Vn
tc ct: vm = 528 (mm/ph) - Thi gian my chy: To = 0,1 (ph)* Bc 2:
Khoan tm- Dao khoan chuyn dng. Tra bng 5.55(II) ta c: S =
0,1(mm/vng)- S vng quay ca my: Tra theo chui s vng quay ca my nm =
1200 (vg/ph)- Thi gian my chy: ta c chiu di l khoan L = 7,5(mm)To =
0,2 (ph)BcMyDaot(mm)s(mm/v)s(mm/ph)n(vg/ph)To(ph)
1MP76MT15K62,1 5286000,1
2P181,50,1 12000,2
6.3: Nguyn cng III : Tin th mt tr 42 - 37,5 - 30 * Bc 1: Tin th
42. Vi t = 1,1 (mm)- Chiu di dch chuyn bn dao cng tc: Lbd = Lc + L1
+ L2Theo bng 5.3(I) c: j = 90o ly L1 = 2(mm); L2 = 0Theo s c Lc =
23 (mm); Vy Lbd = 25 (mm)+ Vi thp 45 C , sb = 80 (KG/mm2)Tra bng
5.11(III) c: Sb = 0,5 (mm/vg)+ vi my T616, lng chy dao ca my tra
theo chui lng chy dao c: So = 0,47 (mm/vg); Tra bng 5.29(II) c Vb =
105 (m/ph) (vi j = 90o)Tra bng 5.32(II), 5.37(II). C K1 = 0,9; K2 =
1,55K1 (H s iu chnh vn tc ct cho thp )K2 (H s cho tui bn ca dao T)
Vtt = Vb. K1. K2 = 105.0,9.1,55 = 146,475 (m/ph)
; nm = 1000 (vg/ph)
* Bc 2: Tin th 37,5 . Vi t = 1,7(mm)- Chiu di dch chuyn bn dao
cng tc: Lbd = Lc + L1 + L2Theo bng 5.3(I) c: j = 90o ly L1 = 2(mm);
L2 = 0Theo s c Lc = 26 (mm); Vy Lbd = 28 (mm)+ Vi thp 45 C, sb =
80(KG/mm2)Tra bng 5.11(III) c: Sb = 0,7 (mm/vg)+ vi my T616, lng
chy dao ca my tra theo chui lng chy dao c: So = 0,7 (mm/vg)Tra bng
5.29(II) c Vb = 93 (m/ph) (vi j = 90o)Tra bng 5.32(II), 5.37(II). C
K1 = 0,9; K2 = 1,55K1 (h s iu chnh vn tc ct cho thp )K2 (h s cho
tui bn ca dao T)
Vtt = Vb. K1. K2 = 93.0,9.1,55 = 129,735(m/ph) ; nm = 800
(vg/ph) vm =113,04 (m/ph) To = 0,05(ph)* Bc 3: Tin th 30 . Vi t =
1,1(mm)- Chiu di dch chuyn bn dao cng tc: Lbd = Lc + L1 + L2Theo
bng 5.3(I) c j = 90o ly L1 = 2(mm); L2 = 0Theo s c Lc = 52 (mm); Vy
Lbd = 54 (mm)+ Vi thp 45 C, sb = 80(KG/mm2)Tra bng 5.11(III) c: Sb
= 0,7 (mm/vg)+ vi my T616 lng chy dao ca my tra theo chui lng chy
dao c: So = 0,7 (mm/vg)Tra bng 5.29(II) c Vb = 93 (m/ph) ( vi s =
90o)Tra bng 5.32(II), 5.37(II). C K1 = 0,9, K2 = 1,55K1 (H s iu
chnh vn tc ct cho thp )K2 (H s cho tui bn ca dao T)
Vtt = Vb. K1. K2 = 93.0,9.1,55 = 129,735(m/ph) ; nm =630 (vg/ph)
vm =126,6 (m/ph) To = 0,122 (ph)Bng thng s ch ct cho nguyn cng
IIIBcMyDaot(mm)s(mm/v)v(m/ph)n(vg/ph)To(ph)
1T616T15K61,10,47125,610000,053
21,70,7113,048000,05
3
1,10,7126,66300,122
6.4: Nguyn cng IV: Tin th 49, 40, 39 :* Bc 1: Tin th 49. Vi t =
1,7 (mm)- Chiu di dch chuyn bn dao cng tc LbdLbd = Lc + L1 + L2Theo
bng 5.3(I) c: j = 90o ly L1 = 2(mm) Da vo s gia cng, ly L2 =
0(mm)Theo s c Lc = 25 (mm)Vy Lbd = 27 (mm)+ Vi thp 40C, sb =
80(KG/mm2); tra bng 5.11(III) c: Sb = 0,35 (mm/vg)+ vi my 1K62, lng
chy dao ca my tra theo chui lng chy dao c: So = 0,34 (mm/vg)Tra bng
5.29(II) c Vb = 115 (m/ph) ( vi j = 90o)Tra bng 5.32(II), 5.37(II).
C K1 =0,9; K2 = 1,55K1 (H s iu chnh vn tc ct cho thp )K2 (H s cho
tui bn ca dao T)
Vtt = Vb. K1. K2 = 115.0,9.1,55 = 160,425 (m/ph) ; nm = 1600
(vg/ph) vm = 125,6(m/ph); To = 0,04 (ph)* Bc 2: Tin th 40 . Vi t =
1,1 (mm)- Chiu di dch chuyn bn dao cng tc LbdLbd = Lc + L1 + L2Theo
bng 5.3(I) c: j = 90oly L1 = 2(mm); L2 = 0Theo s c Lc = 90 (mm); vy
Lbd = 92 (mm)+ Vi thp 45C, sb = 80(KG/mm2)Tra bng 5.11(III) c: Sb =
0,5 (mm/vg)+ vi my T616 lng chy dao ca my tra theo chui lng chy dao
c: So = 0,47 (mm/vg)Tra bng 5.29(II) c Vb = 105 (m/ph) ( vi j =
90o)Tra bng 5.32(II), 5.37(II). C K1 = 0,9, K2 = 1,55 K1 (H s iu
chnh vn tc ct cho thp )K2 (H s cho tui bn ca dao T)
Vtt = Vb. K1. K2 = 105.0,9.1,55 = 146,475 (m/ph) ; nm = 1250
(vg/ph) vm = 117,75 (m/ph); To = 0,156(ph)* Bc 3: Tin th 40. Vi t =
1,1 (mm)- Chiu di dch chuyn bn dao cng tc: Lbd = Lc + L1 + L2Theo
bng 5.3(I) c: j = 90o ly L1 = 2(mm); L2 = 0Theo s c Lc = 23 (mm);
Vy Lbd = 25(mm)+ Vi thp 45C; sb = 80(KG/mm2)Tra bng 5.11(III) c: Sb
= 0,5 (mm/vg)+ vi my 1K62, lng chy dao ca my tra theo chui lng chy
dao c: So = 0,47 (mm/vg)Tra bng 5.29(II) c Vb = 105 (m/ph) ( vi j =
90o)Tra bng 5.32(II), 5.37(II). C K1 = 0,9; K2 = 1,55K1 (H s iu
chnh vn tc ct cho thp )K2 (H s cho tui bn ca dao T) Vtt = Vb. K1.
K2 = 105.0,9.1,55 = 146,475 (m/ph)
; nm = 1000 (vg/ph)
Bng thng s ch ct cho nguyn cng
IVBcMyDaot(mm)s(mm/v)v(m/ph)n(vg/ph)To(ph)
1T616T15K61,70,34125,616000,04
21,10, 47117,7512500,156
31,10,47125,610000,053
6.5 :Nguyn cng V : Tin tinh 40, 39, Vt mp 1,5x45o :* Bc 1: Tin
tinh 40 . Vi t = 0,5(mm)-Chiu di dch chuyn bn dao cng tc Lbd = 27
(mm)-Lng chy dao: Vi Rz = 20, r = 1,6+ Tra bng 5.14(III). C stt= sb
= 0,49(mm/vg)+ vi my T616, lng chy dao ca my tra theo chui lng chy
dao c: So = 0,43 (mm/vg)- Vn tc ctTra bng 5.29(II) c Vb = 130
(m/ph) ( vi j = 90o)Tra bng 5.32(II), 5.37(II). C K1 = 0,9; K2 =
1,55K1 (H s iu chnh vn tc ct cho thp )K2 (H s cho tui bn ca dao
T)
Vtt = Vb. K1. K2 = 130.0,9.1,55 = 181,35 (m/ph) Tra chui vng
quay ca my T616: nm = 630 (vg/ph) vm =39,564(m/ph) To = 0,1(ph)
* Bc 2: Tin tinh 39 . Vi t = 0,5(mm)-Chiu di dch chuyn bn dao
cng tc Lbd = 25 (mm)-Lng chy dao. Vi Rz = 20, r = 1,6+ Tra bng
5.14(III). C stt= sb = 0,49(mm/vg)+ vi my T616, lng chy dao ca my
tra theo chui lng chy dao c: So = 0,43 (mm/vg)- Vn tc ctTra bng
5.29(II) c Vb = 130 (m/ph) ( vi j = 90o)Tra bng 5.32(II), 5.37(II).
C K1 = 0,9; K2 = 1,55K1 (H s iu chnh vn tc ct cho thp )K2 (H s cho
tui bn ca dao T)
Vtt = Vb. K1. K2 = 130.0,9.1,55 = 181,35 (m/ph) Tra chui vng
quay ca my T616 c: nm =1250 (vg/ph) vm =157(m/ph) To = 0,046 (ph)*
Bc 3: Vp mp 1,5x450 b mt 40 . Vi t = 2(mm)- Chiu di dch chuyn bn
dao cng tc Lbd Lbd = Lc + L1 Lbd = 2 + 2 = 4+ Vi thp 40X, sb =
80(KG/mm2)Tra bng 5.15(III) c: Sb = 0,06 0,08 (mm/vg).Chn Sb=0,08
(mm/vg)+ vi my 1K62, lng chy dao ca my tra theo chui lng chy dao c:
So = 0,074 (mm/vg)Tra bng 5.31 (II) c Vb = 110 (m/ph) ( vi j =
90o)Tra bng 5.32(II), 5.37(II). C K1 = 0,9; K2 = 1,55K1 (H s iu
chnh vn tc ct cho thp )K2 (H s cho tui bn ca dao T)
Vtt = Vb. K1. K2 = 110.0,9.1,55 = 153,45 (m/ph) nm = 1600(vg/ph)
vm =125,6 (m/ph) To = 0,027(ph)
BcMyDaot(mm)s(mm/v)v(m/ph)n(vg/ph)To(ph)
1T616T15K6
0,50,4339,5646300,1
20,50,4315712500,046
31,50,074125,616000,027
6.6 : Nguyn cng VI : Tin tinh 42, 30 , Vt mp 49 , Vt mp 42 : *
Bc 1: Tin tinh 42. Vi t = 0,5(mm)-Chiu di dch chuyn bn dao cng tc
Lbd = 25 (mm)-Lng chy dao. Vi Rz = 20, r = 1,6+ Tra bng 5.14(III).
C stt= sb = 0,49(mm/vg)+ vi myT616, lng chy dao ca my tra theo chui
lng chy dao c: So = 0,43 (mm/vg)- Vn tc ctTra bng 5.29(II) c Vb =
130 (m/ph) ( vi j = 90o)Tra bng 5.32(II), 5.37(II). C K1 = 0,9, K2
= 1,55K1 (H s iu chnh vn tc ct cho thp )K2 (H s cho tui bn ca dao
T)
Vtt = Vb. K1. K2 = 130.0,9.1,55 = 181,35 (m/ph) Tra chui vng
quay ca my T616 c: nm =1250 (vg/ph) vm =157(m/ph) To = 0,046 (ph) *
Bc 2: Tin tinh 30 . Vi t = 0,5(mm)-Chiu di dch chuyn bn dao cng tc
Lbd = 56 (mm)-Lng chy dao. Vi Rz = 20, r = 1,6+ Tra bng 5.14(III).
C stt= sb = 0,49(mm/vg)+ vi my T616, lng chy dao ca my tra theo
chui lng chy dao c: So = 0,43 (mm/vg)- Vn tc ctTra bng 5.29(II) c
Vb = 130 (m/ph) ( vi j = 90o)Tra bng 5.32(II), 5.37(II). C K1 =
0,9; K2 = 1,55K1 (H s iu chnh vn tc ct cho thp )K2 (H s cho tui bn
ca dao T)
Vtt = Vb. K1. K2 = 130.0,9.1,55 = 181,35 (m/ph) Tra chui vng
quay ca my T616 c: nm =800 (vg/ph) vm =160,768(m/ph) To = 0,163
(ph)Cc bc vt mp 40, 64 ging nguyn cng V.Bng thng s ch ct cho nguyn
cng VIIBcMyDaot(mm)s(mm/v)v(m/ph)n(vg/ph)To(ph)
1T616T15K60,50,4315712500,046
20,50,43160,7688000,163
30,074125,610000,054
40,074146,77300,074
6.7 : Nguyn cng VII : Phay then hoa :c tnh :- S rng: Z = 22-
Then hoa bin dng hnh thang cn.- Chn dao: Tra bng 4.106(III), chn
dao phay ln rng loi II- Vt liu dao: Thp gi P18- Thng s ca dao: mn=
2, dao=63, d=27, d1=40, L*=80, Z0=12(rnh)- Chiu su ct t = 1,5(mm)-
Chiu di dch chuyn bn dao cng tc: Lbd = Lc + L1 + L2 Ta c:+ L1 =
[t(dao d)]1/2 + (0,530) =[5(63 - 27)]1/2 + (0,530)= 13,943,4 (mm)
Chn L1 = 15 (mm)+ L2 = (2-5) mm. Chn L2 = 3(mm)+ Chiu di ct: Lc =
52 (mm) Vy Lbd =52 + 15 + 3 = 70 (mm)- Lng chy dao. Tra bng
5.191(III). C so = 1,2(mm/vg)-Vn tc ct. Tra bng 5.192(III). C v =
48(m/p)-S vng quay tnh ton ca my:
Tra chui vng quay ca my 5K32 c: nm = 200 (vg/ph)- Tc ct thc vm =
39,564 (m/ph) - Thi gian my chy: To = 3,6 (ph)
Bng thng s ch ct cho nguyn cng
VIIIBcMyDaot(mm)s(mm/vg)nf(vg/ph)nd(vg/ph)v(m/ph)To(ph)
15K32P181,51,22020039,5643,6
6.8 : Nguyn cng VIII : Phay then hoa :c tnh :- S rng: Z = 26-
Then hoa bin dng hnh thang cn.- Chn dao: Tra bng 4.106(III), chn
dao phay ln rng loi II- Vt liu dao: Thp gi P18- Thng s ca dao: mn=
2, dao=63, d=27, d1=40, L*=80, Z0=12(rnh)- Chiu su ct t = 1,5(mm)-
Chiu di dch chuyn bn dao cng tc: Lbd = Lc + L1 + L2 Ta c:+ L1 =
[t(dao d)]1/2 + (0,530) =[5(63 - 27)]1/2 + (0,530)= 13,943,4 (mm)
Chn L1 = 15 (mm)+ L2 = (2-5) mm. Chn L2 = 3(mm)+ Chiu di ct: Lc =
52 (mm) Vy Lbd =52 + 15 + 3 = 70 (mm)- Lng chy dao. Tra bng
5.191(III). C so = 1,2(mm/vg)-Vn tc ct. Tra bng 5.192(III). C v =
48(m/p)-S vng quay tnh ton ca my:
Tra chui vng quay ca my 5K32 c: nm = 200 (vg/ph)- Tc ct thc vm =
39,564 (m/ph) - Thi gian my chy: To = 3,6 (ph)Bng thng s ch ct cho
nguyn cng
VIIIBcMyDaot(mm)s(mm/vg)nf(vg/ph)nd(vg/ph)v(m/ph)To(ph)
15K32P181,751,22020039,5643,6
6.9 : Nguyn cng IX : Nhit luyn :6.10 : Nguyn cng X : Mi th b mt
40 (L = 35) :- My312- : 300x40x127 14A20K3 (Bng 4.170-(III) - Lng d
khi mi: h = 0,2(mm)- Chiu su khi mi: Tra bng X.92(VI), chn t =
0,02(mm). Vn tc ct. Tra bng X.92(VI). + Ca : v = 30(m/s)+ Ca phi:
vph = 25(m/ph) S vng quay:Chn theo chui s vng quay ca my. n = 2200
(vg/ph)+ Ca chi tit: chn theo my c nct = 175 (vg/ph)- Tc ct thc: V
= 973,4 (m/ph) Vct = 14,13 (m/ph) - Thi gian my chy: K: H s k n vic
quay dao thm my ln cui cng tng nhn bng. K = 1,5 , vy: To = 0,16
(pht)
Bng thng s ch ct cho nguyn cng
XIIBcMyDaoT(mm)Sn(mm/vg)nct(vg/ph)nd(vg/ph)To(ph)
312300x40x127 14A20K30,020,002517522000,16
6.11 : Nguyn cng XI : Mi th b mt 30 (L = 17 ) :- My312- :
300x40x127 14A20K3 (Bng 4.170-(III) - Lng d khi mi: h = 0,2(mm)-
Chiu su khi mi: Tra bng X.92(VI), chn t = 0,02(mm). Vn tc ct. Tra
bng X.92(VI). + Ca : v = 30(m/s)+ Ca phi: vph = 25(m/ph) S vng
quay:Chn theo chui s vng quay ca my. n = 2200 (vg/ph)+ Ca chi tit:
chn theo my c nct = 175 (vg/ph)- Tc ct thc: V = 973,4 (m/ph) Vct =
14,13 (m/ph) - Thi gian my chy: K: H s k n vic quay dao thm my ln
cui cng tng nhn bng. K = 1,5 , vy: To = 0,16 (pht)
Bng thng s ch ct cho nguyn cng
XIIBcMyDaoT(mm)Sn(mm/vg)nct(vg/ph)nd(vg/ph)To(ph)
312300x40x127 14A20K30,020,002517522000,16
12: Nguyn cng XVII : Tng kim tra, ng gi, bo qun.
TI LIU THAM KHO
[1]- Hng dn thit k n cng ngh ch to my- GS, TS. Nguyn c Lc (Ch
bin)- Lu Vn Nhang- Nh xut bn khoa hc v k thut H Ni- 2009.[2]- S tay
cng ngh ch to my- ch bin Trn Vn ch- Nh xut bn H Ni- 2000.[3]- S tay
cng ngh ch to my tp 1,2,3- GS. TS. Nguyn c Lc, PGS. TS. L Vn Tin,
PGS. TS. Ninh c Tn, PGS. TS. Trn Xun Vit- Nh xut bn khoa hc k
thut.[4]- Atlas g- GS. TS. Trn Vn ch- Nh xut bn khoa hc v k Thut H
Ni- 2010.[5]- Dung sai v lp ghp- PGS.TS. Ninh c Tn- NXB gio dc.[6]-
Cng ngh ch to my- Ch bin GS.TS Trn Vn ch- Nh xut bn khoa hc k thut
H Ni- 2003.[7]- Bi ging hc phn Cng ngh ch to my 1- Trng i hc K thut
Cng nghip- 2011.
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