Giao an Tu Chon Hoa Hoc 12 Cb

Ngy son 1/9/2008

T chn Ha 12

Ngy son: 04/8/2013 TC 2: LUYN TP V ESTE

I. MC TIU :

K nng :

- Vit c cng thc cu to ca este c ti a 4 nguyn t cacbon.

- Vit cc phng trnh ho hc minh ho tnh cht ho hc ca este no, n chc.

- Phn bit c este vi cc cht khc nh ancol, axit,... bng phng php ho hc.

II. PHNG PHP :

m thoi gi m, s dng bi tp ha hc.

III. T CHC HOT NG DY HC:

1. n nh t chc

2. Bi mi :

Hot ng ca gvhs

Cu hi v bi tp nh tnh:Cu 1: Chn cu tr li chnh xc nht:

A. Este l sn phm ca phn ng este ha gia cc cht hu c v ru.

B. Este l sn phm ca phn ng gia axit v c vi ru.

C. Este l sn phm ca phn ng cng gia axit hu c vi ru.

D. Este l sn phm ca phn ng este ha gia axit v c hoc hu c vi ru.

Cu 2: Cng thc tng qut ca este no n chc l:

A. CnH2nO2(n2). D. CnH2nO(n1).

B. CnH2n-2O2(n1). C. CnH2n+2O2(n1).

Cu 3: Mt hp cht A c cng thc C3H4O2. A tc dng c vi dung dch Br2, NaOH, AgNO3/NH3, nhng khng tc dng c vi Na. Cng thc cu to ca A phi l:

A. HCOOCH=CH2. B. CH3COOCH3.

C. CH2=CHCOOH. D. HCOOCH2CH3. Cu 4: Etilenglicol tc dng vi hn hp 2 axit CH3COOH v HCOOH th s thu c bao nhiu este ch cha chc este:

A. 1. B. 2. C. 3. D. 4.

Cu 5: Este metyl metacrylat c iu ch t:

A. Axit acrylic v ru metylic.

B. Axit acrylic v ru etylic.

C. Axit metacrylic v ru etylic.

D. Axit metacrylic v ru metylic.

Cu 6: Este metyl metacrylat c dng sn xut:

A. Thuc tr su. C. Cao su.

B. Thy tinh hu c. D. T tng hp.

Cu 7: tinh ch CH3COOH c ln C2H5OH ngi ta lm nh sau:

A. Cho hn hp tc dng vi NaOH d, c cn ly sn phm cho tc dng vi H2SO4 ta thu c axit axetic.

B. Cho hn hp tc dng vi Na d, c cn ly sn phm cho tc dng vi H2SO4 ta thu c axit axetic

C. Cho hn hp tc dng vi K2CO3 d, c cn ly sn phm cho tc dng vi H2SO4 ta thu c axit axetic

D. C A,C.

Cu 8: Trong phn ng este ha giu ru v axit hu c th cn bng s chuyn dch theo chiu to ra este khi ta:

A. Chng ct ngay tch este.

B. Cho ru d hay axit d.

C. Dng cht ht nc tch nc.

D. C ba bin php A ,B,C.

Cu 9: Dng ha cht g phn bit cc mu th mt nhn cha: Metyl fomiat v etyl axetat.

A. AgNO3/NH3. C. Na2CO3.

B. Cu(OH)2/NaOH. D. A v B.

Cu 10: Dng ha cht g phn bit vinyl fomiat v metyl fomiat?

A. AgNO3/NH3. B. Cu(OH)2/NaOH.

C. Dung dch Br2. D. A v C.

Cu 11: Este C4H8O2 c gc ru l metyl th cng thc cu to ca este l:

A. CH3COOC2H5. C. HCOOC3H7.

B. C2H5COOCH3. D. C2H3COOCH3.

Cu 12: Cho este c cng thc phn t l C4H6O2 c gc ru l metyl th tn gi ca axit tng ng ca n l:

A. Axit acrylic. D. Axit oxalic.

B. Axit axetic. C. Axit propionic.

Cu 13: Hp cht no sau y khng phi l este?

A. C2H5COOC2H5 C. HCOOCH3.

B. CH3CH2CH2COOCH3. D. C2H5COCH3.

Cu 14: Vinyl axetat phn ng c vi cht no trong s cc cht sau y:

A. Dung dch Br2. B. NaOH.

C. Na. D. C A v B ng.

Cu 15: Vinyl fomiat phn ng c vi cht no trong s cc cht sau y:

A. AgNO3/NH3. C. NaOH.

B. Cu(OH)2/NaOH. D. C 3 cu trn.

Cu 16: Mt hp cht B c cng thc C4H8O2. B tc dng c vi NaOH, AgNO3/NH3, nhng khng tc dng c vi Na. Cng thc cu to ca B phi l:

A. HCOOCH(CH3)2. C. C2H5COOCH3.

B.CH3 COOCH2CH3. D.CH3CH2 COOCH3.

Cu 17: Cho cc phn ng sau:

Askt

CH3COOH + Cl2 ClCH2COOH + HCl(1)HCOOH + 1/2O2 CO2 + H2O (2)

H2SO4 c

CH3COOH+C2H5OHCH3COOC2H5+H2O (3)

C2H5OH+HCl C2H5Cl + H2O (4)

Hy cho bit phn ng no l phn ng este ha?

A. (1) v (4). C. (2) v (3).

B. (2) v (4). D. (3).

Cu 1: C

Cu 2: A

Cu 3: aCu 4: C

Cu 5: D

Cu 6: B

Cu 7: D

Cu 8: D

Cu 9: D

Cu 10: C

Cu 11: B

Cu 12: A

Cu 13: D

Cu 14: D

Cu 15: D

Cu 16: A

Cu 17: D

Hot ng 2.

GV giao bi tp HS lm

1/Vit cc CTCT cc este ng phn ca C4H8O2 v gi tn.Nhng este no c kh nng tham gia phn ng trng gng

2/ bi tp t tn gi vit CTCT

Metyl fomat,vinyl axetat

Etyl propionat ,metyl acrylat

Bi 1.

HCOOCH(CH3)2 isopropyl fomat

HCOOCH2CH2CH3 propyl fomat

CH3COOC2H5 etyl axetat

C2H5COOCH3 metyl propionate

Bi 2

HCOOCH3,CH3COOCH=CH2C2H5COOC2H5,CH2=CH-COOCH3Rt kinh nghim:

Ngy son 10/8/2013 TC 3: BI TP V ESTE-CHT BOA.Mc tiu:

1.Kin thc :

-n tp v cng c cc kin thc v este cht bo

2.K nng:

-Rn luyn k nng vit PTHH ,bi tp v cht bo

B.Phng php: m thoi bi tp

C.Chun b :

-Hc sinh n lai cc kin thc v este cht bo

D.T chc cc hot ng dy hc

Hot ng ca thy v tr

Hot ng 1

Gv giao bi tp hn hp 2 este

Bi 1. x phng ho hon ton 19,4g hn hp 2 este n chc A,B cn 200ml dung dch NaOH 1M .Sau khi phn ng xy ra hon ton ,c cn dung dch thu c hn hp 2 ancol l ng ng k tip nhau v 1 mui khan duy nht .Xc nh CTCT,gi tn ,% mi este

Bi 2 .Thu phn hon ton hn hp gm 2 este n chc X,Y l ng ng cu to ca nhau cn 100ml dung dch NaOH 1M ,thu c 7,85ghn hp 2 mui ca 2 axit l ng ng k tipv 4,95g 2 ancol bc 1.Xc nh CTCT ,% mi este trong hn hp

Hot ng 2 Gv giao bi tp v cht bo

Hs lm gv cha b xung

Bi 3un nng 4,45kg cht bo (tristearin)c cha 20% tp cht vi dung dch NaOH.

Tnh khi lng glixerol thu c ,bit h=85%

Bi 4. Tnh th tch H2 thu c ktc cn hirhoa 1 tn glixerol trioleat nh cht xc tc l Ni,gi s H =100%

Bi 5. Khi x phng ho hon ton 2,52g cht bo A cn 90ml dung dch KOH 0,1M.Mt khc ,khi x phng ho hon ton 5,04g cht bo A thu c 0,53g glixerol.Tnh ch s axit v ch ss x phng ho

Ni dung c bn

I.Bi tp hn hp este

Bi 1

Hai este c cng gc axit v cng to ra 1 mui sau khi x phng ho .t CT chung ca 2 este l RCOOR

RCOOR + NaOH ( RCOONa + ROH

Ta c MRCOOR =19,4/0,3=64,67g/mol

Hay MR+MR=20,67.Vy 2 ancol l CH3OH,C2H5OH

CTCT ca 2 este l HCOOCH3v HCOOC2H5%HCOOCH3=61,85%

%HCOOC2H5=38,15%

Bi 2 .Theo nh lut BTKL :meste=8,8g,neste=0,1mol,CTPT l C4H8O2RCOOR + NaOH (RCOONa +ROH

MRCOONa =78,5g/mol ,vy 2 axit l HCOOH,CH3COOH ,m 2 ancol l bc 1 nn CTCT ca 2 este l HCOOCH2CH2CH3v CH3COOC2H5II. Bi tp v cht bo

Bi 3(C17H35COO)3C3H5+ 3NaOH ( C3H5(OH)3 +C17H35COOH

Khi lng glixerol thu c l:3,56.92.85%/890=0,3128kg

Bi 4(C17H33COO)3C3H5+ 3H2 ((C17H35COO)3C3H5Th tch H2 cn : 1 tn .3.22,4/884=76018lit

Bi 5

nKOH =0,1.0,09=0,009mol

mKOH =0,009.56=0,504g=504mg

Ch s x phng ho : 504/2,52=200

Khi lng glixerol thu c khi xphng ho 2,52g cht bo l 0,53.2,52/5,04=0,265g

(RCOO)3C3H5+3KOH(C3H5(OH)3+3RCOOH

3.56(g) 92(g)

m (g) 0,265(g)

m=0,484g=484mg

ch s axit : 504-484/2,52=8

Hot ng 3: Cng c kin thc

Rt kinh nghim:

Ngy son : 8/9/2012 TC 4: GLUCOZOA.Mc tiu:

1.Kin thc:

-cng c v khc su kin thc v glucozo,tnh cht ho hc ca glucozo

2.k nng:

-lm bi tp v glucozo,saccarozo nhn bit.

B.Phng php : m thoi bi tp

C.Chun b : hc sinh n tp cc kin thc v glucozo

D.T chc cc hot ng dy hc

Hot ng ca thy v tr

Hot ng 1

Hc sinh n li khi nim cacbohirat,tnh cht ca glucozo

Hot ng 2

Gv yu cu hs lm bi tp v glucozo

Bi 1 .un nng dung dch cha 18g glucozo vi dung dch AgNO3/NH3 va ,bit rng cc phn ng xy ra hon ton .Tnh khi lng Ag v AgNO3-Hs ln bng lm

_Gv cha b xung

Bi 2 .Ln men m(g) glucozo thnh ancol etylic vi H=80%.Hp th hon ton kh sinh ra vo dung dch Ca(OH)2 d thu c 20g kt ta .Tnh m

Bi 3. Kh glucozo bng H2 to sobitol . to ra 1,82g sobitol vi H=80%.Tnh khi lng glucozo cn dng

Ni dung

I. Glucozo : C6H12O6(M=180g/mol)

CTCT: CH2OH-(CHOH)4-CHO

Fructozo CH2OH-(CHOH)3-CO-CH2OH

* T/c: tnh cht ca ancol a chc v t/c ca anehit

Trong mi trng bazo : G ( F

II Bi tp v glucozo

Bi 1

Ta c s mol Ag = s mol AgNO3=2 s mol glucozo=0,2 mol

Vy : mAg=0,2.108=21,6g,mAgNO3=0,2.170=34g

Bi 2

C6H12O6 (2 C2H5OH + 2CO2

CO2+ Ca(OH)2 (CaCO3 + H2O

S mol glucozo =1/2 s mol CaCO3=0,1mol.vy s g glucozo =0,1.180.100/80=22,5g

Bi 3

C6H12O6 +H2 (C6H12O6 180 182 x 1,82

khi lng glucozo l 1,82.180.100/182.80=2,24g

Hot ng 3 .Cng c HS tr li cc cu hi trc nghim sau

Cu1 .Trng hp no sau y c hm lng glucozo ln nht?

A.mu ngi B .Mt ong

C.dung dch huyt thanh D. qu nho chn

Cu2. Thuc th no sau y dng nhn bit cc dung dch : glixerol,fomanehit,glucozo,ancol etylic

A.AgNO3/NH3 B.Na C.nc brom D.Cu(OH)2/NaOH

Rt kinh nghim:

Ngy son 12/9/2012TC 5: BI TP V SACCAROZ-TINH BT-XENLULOZO

A.Mc tiu

1.kin thc: -Cng c v khc su kin thc v saccaroz tinh bt ,xenlulozo

2.k nng:

-k nng lm bi tp v tinh bt v xenlulozo


C.T chc cc hot ng dy hcHot ng ca thy v tr

Hot ng1

Gv giao bi tp v saccarozo

Hs lm gv cha b xung

Bi 1. Thu phn hon ton 1 kg saccarozo thu c m(g) glucozo.Tnh m

Bi 2. Nc ma cha khong 13% saccarozo.Bit H ca qu trnh tinh ch l 75%.Tnh khi lng saccarozo thu c khi tinh ch 1 tn nc ma trn.GV yu cu HS n tp cc kin thc v tinh bt v xenloluzo

HS trao i nhm thy r s ging v khc nhau v cu to v tnh cht ca tinh bt v xenloluzo

Hot ng 2

GV giao bi tp v tinh bt

Bi 1. Thu phn 1kg sn cha 20% tinh bt trong mi trng axit vi hiu sut 85%.Tnh khi lng glucozo thu c

_HS nhn bi tp v lm

-GV cha b xung

Bi 2. Cho m(g) tinhbt sn xut ancol etylic,ton b lng kh sinh ra uc dn vo dung dch Ca(OH)2 d thu c 500g kt ta .Bit hiu sut ca mi giai on l 75%.Tnh m

Hot ng 3 .GV giao bi tp v xenlulozo

-HS nhn bi tp v lm

Bi 1 .Dng 324kg xenlulozo v 420kg HNO3 nguyn ch c th thu c ? tn xenlulozo trinirat,bit s hao ht trong qu trnh sn sut l 20%

Bi 2. Khi lng phn t trung bnh ca xenlulozo trong si bng l 4860000.Tnh ss gc glucozo c trong si bng trn

Ni dung

IV.Bi tp v saccarozo

Bi 1

C12H22O11+H2O (C6H12O6+C6H12O6342 180(g)

1kg x(kg)

m =1.180/342=0,526kg

Bi 2

Lng saccarozo trong 1 tn nc ma l:1000.13/100=130g

Lng saccarozo thu c sau khi tinh ch l: 130.75/100=97,5g

I.So snh s ging v khc nhau v cu trc phn t ,tnh cht ca tinh bt v xenloluzo

II Bi tp v tinh bt

Bi 1

Khi lng tinh bt trong 1kg sn l: 1000.20/100=200g

(C6H10O5)n +n H2O (nC6H12O6 162n 180n

200g

Khi lng glucozo thu c l 180.200.85/162.100=188.89g

Bi 2 . S bin i cc cht

(C6H10O5)n(C6H12O6(2nCO2(2nCaCO3 162n 200g(h=100 )

V H =75% nn khi lng CaCO3 thc t thu c l 200.0,75.0,75.0,75=84,375g

thu c 500g CaCO3 th khi lng tinh bt cn dng l: 500.162/84,375=960g

III.Bi tp v xenlulozo

Bi 1 .[C6H7O2(OH)3]n3nHNO3([C6H7O2(ONO2)3]n +3nH2O

Theo PT khi lng HNO3 d ,nn khi lng sn phm tnh theo xenlulozo

324.297.80/162.100=475,2kg=0,4752tn

Bi 2. S gc glucozo l: 48600000/162=300000

Hot ng 4 .Cng cRt kinh nghim:

Ngy son 16/9/2012 TC 6: LUYN TP CHNG I-IIA.Mc tiu

1.kin thc :- cng c v khc su kin thc v este-lipit-cacbohirat

-tnh cht ho hc c trng ca cc hp cht trn

2.k nng : rn lun k nng lm bi tp t lun v trc nghim


C.T chc cc hot ng dy hc

Hot ng ca thy v trNi dung

Hot ng 1

GV yu cu HS trao i nhm cc kin thc v este,lipit,cacbohirat : CTCT,tnh cht ,iu ch

Hot ng 2

GV yu cu HS lm cc bi tp v este,lipit

-HS nhn bi tp v lm

-GV nhn xt v b xung

Bi 1.Khi x phng ha hon ton 6g mt este n chc cn 100ml dung dch KOH 1M ,c cn sn phm thu c 8,4g mui khan.Xc nh CTCT v gi tn

-Hs lm bi tp 2 gv cha b xung

Bi 2.

Thu phn hon ton 2,2g mt este n chc

bng 100ml NaOH 1M.Sau phi thm vo 75ml dung dch HCl1M trung ho NaOH d,sau cn cn thn thu c 6,43 75ghn hp 2 mui khan ,x c nh cng thc cu to,gi tn este trn

Bi 3

Cho glucozo ln men thnh ancol etylic,ton b lngkh sinh ra c hp th ht vo dung dch Ca(OH)2ly d thu c 40g kt ta.Tnh khi lng glucozo cn dng ,bit hiu sut phn ng t 70%

-Tnh th tch dung dch Ca(OH)21M dng

I.Kin thc

II. Bi tp

Bi 1.

RCOOR+NaOH(RCOONa+ROH

S mol RCOOK=s mol KOH=0,1mol.Vy MRCOOK=8,4/0,1=84,vy R l H

MRCOOR=6/0,1=60,R l CH3Este l: HCOOCH3 metyl axetat

Bi 2

RCOOR+NaOH(RCOONa+ROH

HCl + NaOH (NaCl + H2O

S mol NaOH d =s mol HCl=0,075mol,khi lng RCOONa=6,4375-0,075.58,5=2,05g

MRCOONa=2,05/0,025=82,vy R l CH3.

Ta c : MRCOOR=2,2/0,025=88,R l C2H5 .CTCT l CH3COOC2H5 etyl axetat.

Bi 3

C6H12O6(2CO2 + 2C2H5OH

CO2 + Ca(CO3)2(CaCO3+H2O

S mol glucozo=1/2 s mol CaCO3 =0,2 mol.Khi lng glucozo cn dng l: 0,2 .180.100/70=51,4g

Th tch dung dch Ca(OH)2=0,4/1=0,4lit

Hot ng 3: HS lm bi tp trc nghim

.

Cu 1: nhn bit glucozo v glierol dng thuc th no sau y:

A.Cu(OH)2 B.AgNO3(NH3,t0) C.Na D.H2SO4Cu 2: C3H6O2c bao nhiu CTCT cng tc dng vi dung dch NaOH?

A.2 B.3 C.4 D.5

Cu 3: Khi t chy hon ton 1este thu c s mol CO2bng s mol H2O th o l :

A.este n chc B.este no n chc C.este khng no D.trieste.

Cu 4: Khi thu phn vinyl axetat trong mi trng axit s thu c:

A.axit axetic v ancol ety lic B.axit axetic v ancol vinylic

C. axaxetic v andehit axetic D.axit foocmic v ancol etylic

Cu 5;Phn ng no sau y dng sn xut x phng:

A.un nng dung dch axit vi dung dch kim.

B.un nng cht bo vi dung dch kim

C.un nng glixerol vi axit

D.A,C u ng

Cu 6.un nng 9g axit axetic vi 9g ancol etylic (H2SO4 c) thu c m(g) este vi hiu sut phn ng t 80%.Gi tr ca m l:

A.13,2g B.16,5g C.10,56g D.21,53g.

Cu 7. trng 1 ci gng ht 5,4g Ag ,ngi ta dng mg glucozo .gi tr ca m l:

A.4,5g B.18g C..9g D.8,55g

Cu 8. phn ng thu phn tinh bt xy ra trong mi trng:

A.axit B.bazo C.trung tnh D.kim nh

Rt kinh nghim:

Ngy son 20/9/2012 TC 7: LUYN TP TP V AMIN

A.Mc tiu:

1.kin thc:

-cng c v khc su kin thc v amin,tnh cht ho hc ca amin

2.k nng :

-rn luyn k nng lm bi tpt lun v trc nghim

B.Phng php: m thoi-bi tp

C.T chc cc hot ng dy hc

Hoat ng ca thy v trNi dung

Hot ng 1

GV cho HS trao i nhm v CTCT,tnh cht ho hc ca amin

Hot ng 2

GV giao bi tp v amin ,HS lm

Bi 1.Trung ho 50ml dung dch metyl amin cn 30ml dung dch HCl 0,1M.Gi s th tch khng thay i,tnh nng mol/l ca metyl amin

-GV cha b sung

Bi 2.Cho nc brom d vo aniline thu c 16,5g kt ta.Tnh khi lng aniline trong dung dch.

-HS nhn bi tp v lm ,GV cha

Bi 3

.Cho 1,395g anilin tc dng hon ton vi 0,2l dung dch HCl 1M .Tnh khi lng mui thu c

I.Bi tp v amin

Bi 1

nHCl=0,1.0,03=0,003mol

CH3NH2 + HCl (CH3NH3Cl

0,003 0,003

CM=0,003/0,05=0,06M

Bi 2

C6H5NH2+Br2 (C6H2Br3NH2S mol 2,4,6-tribromanilin=16,5/330=0,05mol

Khi lng aniline thu c l: 93.0,05=4,65g

Bi 3

S mol anilin=1,395/93=0,015mol

S mol HCl=0,2mol

C6H5NH2+HCl (C6H5NH3Cl

0,015 0,015

Khi lng mui thu c l:0,015.129,5=1,9425g

Hot ng 3

HS lm bi tp trc nghim

Cu 1.Cht no sau y c lc bazo ln nht ?

A.NH3 B.C6H5NH2 C .(CH3)3N D,(CH3)2NH

Cu2.Dy cc amin c xp theo chiu tng dn lc bazo l:

A.C6H5NH2,CH3NH2,(CH3)2NH

B.CH3NH2,(CH3)2NH,C6H5NH2C.C6H5NH2,(CH3)2NH,CH3NH2D.CH3NH2,C6H5NH2,(CH3)2NH

Cu 3.Phn ng ca aniline vi dung dch brom chng t

A.nhm chc v gc hirocacbon c nh hng qua lai ln nhau

B.Nhm chc v gc hiroccbon khng c nh hng qua li ln nhau

C.nhm chc nh hng n t/c ca gc hirocacbon

D.gc hirocacbon nh hng n nhm chc

Cu4.Ho cht c th dng nhn bit phenol v aniline l:

A.dung dch brom. B .H2O C.Na D.dung dch HCl

Cu5 . Amin n chc c 19,178% nito v khi lng .CTPT ca amin l:

A.C4H5N B.C4H7N C.C4H11N D.C4H9N

Rt kinh nghim:

Ngy 22/9/2012TC 8 LUYN TP V AMINO AXIT

I.Mc tiu1.Kin thc :

- cng c v khc su kin thc v amino axit,tnh cht ca amino axit

2.K nng:

-rn luyn k nng lm bi tp

II.Phng php: m thoi-bi tp

III.Chun b: HS n tp li cc kin thc v amino axit

IV.T chc cc hot ng dy hc


Hot ng 1

GV yu cu HS trao i nhm v amin,tnh cht ca amin

Hot ng 2

GV giao bi tp v amin HS nhn bi tp v lm

Bi 1. Mt amino axit A c 40,4% C,7,9%H,15,7%N,36%O v khi lng v M=89g/mol.Xc nh CTPT ca A

-GV nhn xt v b sung

Bi 2.Cho 0,1molamino axit A phn ng va vi 100ml dung dch HCl 2M .Mt khc 18g A cng phn ng va vi 200ml dung dch HCl trn.Xc nh khi lng phn t ca A

Bi 3.X l 1 amino axit,khi cho 0,01mol X tc dng vi HCl th dng ht 80ml dung dch HCl 0,125M v thu c 1,835g mui khan,Khi cho 0,01mol X tc dng vi dung dch NaOH th cn dng 25g dung dch NaOH 3,2% .Xc nh CTPT v CTCT ca X

I. Kin thc c bn

II.Bi tp v amin

Bi 1

Gi CTG ca A l CxHyOzNt

Ta c x:y:z:t=40,4/12:7,9/1:36/16:15,7/14=3:7:2:1

Cng thc phn t ca A l ( C3H7O2N)n =89.Vy n=1

Cng thc phn t l C3H7O2N

Bi 2

Ta c 0,1 mol A phn ng va vi 0,2mol HCl.Mt khc 18g A cng phn ng va 0,4mol HCl trn.Vy A c khi lng phn t l; 18/0,2= 90g/mol

Bi 3

S mol HCl=s mol X=0,01mol.X c 1 nhm NH2RNH2 + HCl (RNH3Cl

0,01 0,01

m X=m m-m HCl=1,835-36,5.0,02=1,47g

MX=147g/mol

n NaOH=2nX=0,01mol,vy X c 2 nhm COOH v X c dng R(NH2)(COOH)2,do R l C3H5

Hot ng 3

HS lm bi tp trc nghim

Cu1. chng minh amino axit l hp cht lng tnh,ta c th dng phn ng ca cht ny vi

A.dung dch KOH v CuO

B.dung dch KOH v HCl

C.dung dch NaOH v NH3D.dung dch HCl v Na2SO4

Cu 2.Phn bit 3 dung dch : H2N-CH2-COOH,CH3COOH v C2H5NH2, ch cn dng thuc th l:

A.dung dch HCl B.Na C.qu tm C.dung dch NaOH Cau Cu 3.Pht biu no sau y l ng

A.Amino axit l hp cht a chc c 2 nhm chc

B.Amino axit l hp cht tp chc c 1nhom COOH v 1 nhm NH2 C.Amino axit l hp cht tp chc c 2nhm COOH v 1 nhm NH2D.Amino axit l hp cht tp chc cha ng thi 2 nhm chc NH2v COOH

Cu 4.Cho m (g) anilin tc dung vi dung dch HCl d .C cn dung dch sau phn ng thu c 15,54g mui khan .Hiu sut phn ng 80% th gi tr ca m l

A.11,16g B.12,5g C.8,928g D.13,95g

Cu 5. tch ring hn hp benzene,phenol,aniline ta dng cc ho cht no (cc dng c y )

A.dung dch bom,NaOH,kh CO2B.dung dch NaOH,NaCl,kh CO2C.dung dch brom,HCl,kh CO2D.dung dch NaOH,HCl,kh CO2 Rt kinh nghim:

Ngy son 26/9/2012 TC 9: BI TP V PEPTIT-PROTEIN

I.Mc tiu

1.Kin thc:Cng c v khc su kin thc v peptit-protein,tnh cht ca chng

2.K nng: Rn luyn k nng lm bi tp v peptit-protein

II.Phng php: m thoi-bi tp

III.Chun b : HS n tp cc kin thc v peptit-protein

IV.T chc cc hot ng dy hc


Hot ng 1

GV yu cu HS trao i nhm v cu to ,tnh cht ca peptit-protein

Hot ng 2

GV giao bi tp v peptit-HS lm

Bi 1.Thc hin phn ng trng ngng 2 amino axit glyxin v alanin thu c ti a ? i peptit.Vit CTCT v gi tn

-HS lm bi tp 2

Bi 2. Vit cc CTCT v gi tn cc tripeptit c th hnh thnh t glyxin,alanin,phenylalanine(C6H5CH2-CH(NH2)-COOH)

Bi 3.Thu phn 1kg protein X thu c 286,5g glyxin.Nu phn t khi ca X l 50 000 th s mt xch glyxin trong phn t X l?I.Kin thc

II.Bi tp v peptit

Bi 1

H2N-CH2-CO-NH-CH(CH3)-COOH

H2N-CH2-CO-NH-CH2-COOH

H2N-CH(CH3)-CO-NH-CH(CH3)-COOH Ala-Ala

H2N-CH(CH3)-CO-NH-CH2-COOH

Ala-Gly

Bi 2

H2N-CH2-CO-NH-CH(CH3)-CO-NH-CH(C6H5CH2)-COOH Gly-Ala-Phe

Gly-Phe-Ala,Ala-Gly-Phe,Ala-Phe-Gly

Phe-Ala-Gly,Phe-Gly-Ala

Ala-Ala-Ala

Bi 3

n X1000:50 000=0,02mol

n Gly=286,5:75=3,82mol;s mt xch l 3,82:0,02=191

Hot ng 3 HS tr li cu hi trc nghim

Cu 1.Chn cu sai trong cc cu sau

A.phn t cc protit gm cc mch di polipeptit to nn

B.protit rt t tan trong nc v d tan khi un nng

C.khi cho Cu(OH)2 vo lng trng trng thy xut hin mu tm

D.khi nh axit HNO3 vo lng trng trng thy xut hin mu vng

Cu 3.Thu phn hpn ton protit s thu c sn phm

A. amin B.aminoaxit C.axit D.polipeptit

Cu 4 phn bit glixerol,glucozo,lng trng trng ta ch dng

A.Cu(OH)2 BAgNO3 C.dung dch brom D.tt c u sai

Cu 5.mi tanh ca c l hn hp cc amin v 1 s tp cht khc, kh mi tanh ca c trc khi nu nn:

A.ngm c tht lu trong nc cc amin tan i

B.ra c bng dung dch thuc tm c tnh st trng

C.ra c bng dung dch Na2CO3D.ra c bng gim n

Cu 6.S ng phn cu to ca peptit c 4 mt xch c to thnh t 4 amino axit khc nhau l

A.4 B .16 C.24 D.12

Cu 7. Chn pht biu ng trong cc pht biu sau

A.enzim l nhng cht hu ht c bn cht protein,c kh nng xc tc cho cc qu trnh ho hc,c bit l trong c th sinh vt

B.enzim l nhng protein c kh nng xc tc cho cc qu trnh ho hc,c bit l trong c th sinh vt

C.enzim l nhng cht khng c bn cht protein, c kh nng xc tc cho cc qu trnh ho hc,c bit l trong c th sinh vt

D.enzim l nhng cht hu ht khng c bn cht protein.

Rt kinh nghim:

Ngy son : 28/9/2012 TC 10: BI TP TNG HP CHNG III I . Mc tiu :

1. Kin thc : Cng c v khc su kin thc v amin, amino axit, peptit, polime

2. K nng : Rn luyn k nng lm bi tp , k nng lm bi tp nhn bit

II. Phng php : m thoi trao i nhm

III. Chun b : HS n tp cc kin thc v amin,amino axit, polime

IV. T chc cc hot ng dy v hcHot ng ca thy v trNi dung

Hot ng 1

HS trao i nhm cc kin thc v amin, amino axit, peptit, polime

Hot ng 2

GV yu cu HS lm bi tp v amin

- HS lm vic theo nhm v theo yu cu ca GV

Bi 1 . Cho 1,395g anilin tc dng hon ton vi 0,2 lit HCl 1M.Tnh khi lng mui thu c

Hot ng 3

Bi 2 .Cho 0,02mol amino axit A tc dng va vi 80ml dung dch HCl 0,25 M.C cn hn hp sau phn ng thu c 3,67g mui khan.Xc nh phn t khi ca A

Bi 3.

Este A c iu ch t aminoaxit Y v ancol etylic. T khi hi ca X so vi H2 bng 51,5. t chy hon ton 10,3g X thu c 17,6 g CO2 , 8,1 g H2O , 1,12lit N2 (ktc) .Xc nh CTCT thu gn ca A

Hot ng 4GV yu cu HS lm bi tp v polime

HS lm theo yu cu

Bi 4.

Tin hnh trng hp 41,6g stiren vi nhit xc tc thch hp . Hn hp sau phn ng tc dng va vi dung dch cha 16g brom.Khi lng polime thu c l ?

I. Kin thc

II. Bi tp

Bi tp v amin

Bi 1 S mol C6H5NH2= 1,395: 93=0,15mol

S mol HCl=0,2mol

C6H5NH2 + HCl (C6H5NH3Cl

Khi lng mui thu c l : 0,15.129,5=1,9425g

Bi tp v amino axit

Bi 2

S mol HCl = 0,08.0,25=0,02mol

S mol A= s mol HCl nn A c 1 nhm NH2H2NR(COOH)n + HCl (H3NClR(COOH)nM (mui ) =3.67:0,02=147g/mol

Bi 3

M X =51,5.2=103

Cng thc ca este c dng :

NH2-R-COOC2H5 m M =103, vy R l CH2. CTCT l: H2N-CH2-COOC2H5 Bi tp v polimmeBi 4S mol stiren : 41,6:104=0,4mol

S mol brom: 16:160=0,1mol.

Hn hp sau phn ng tc dng vi dung dch brom , vy stiren cn d

C6H5CH=CH2 + Br2 (C6H5CHBr-CH2Br

0,1 0,1

S mol stiren trng hp =0,4-0,1=0,3

Khi lng polime=0,3.104=31,2g

Hot ng 5: Cng c kin thc hcRt kinh nghim:

Ngy son 1/10/2012 TC 11: LUYN TP V POLIME-VT LIU POLIME1.Kin thc

I.Mc tiu:

- cng c v khc su kin thc v polime, cc phng php iu ch polime

2.K nng -rn luyn k nng lm bi tp v polimeII.Phng php : m thoi- trao i nhm

III.Chun b : HS n tp cc kin thc v polime

IV. T chc cc hot ng dy hc


Hot ng 1

GV yu cu HS trao i nhm v cu to ,tnh cht ,cch iu ch polime

-HS lm vic theo nhm

-i din cc nhm bo co GV nhn xt v b sung

Hot ng 2

-GV giao bi tp v polime

Bi 1. T 13kg axetilen c th iu ch c ? kg PVC(h=100%)

Bi 2.H s trng hp ca polietilen M=984g/mol v ca polisaccarit M=162000g/mol l ?

Bi 3. Tin hnh trng hp 5,2g stiren. Hn hp sau phn ng cho tc dng vi 100ml dung dch brom 0,15M, cho tip dung dch KI d vo th c 0,635g iot.Tnh khi lng polime to thnh

I.Kin thc c bn

II.Bi tp

Bi 1.

nC2H2 (nCH2=CHCl((- CH2-CHCl -)n

26n 62,5n

13kg 31,25 kg

Bi 2.ta c (-CH2-CH2-)n =984, n=178

(C6H10O5) =162n=162000, n=1000

Bi 3.PTP

:nC6H5CH=CH2((-CH2-CH(C6H5)-)

C6H5CH=CH2 + Br2 (C6H5CHBrCH2Br

Br2 + 2KI ( I2 +2KBr

S mol I2=0,635:254=0,0025mol

S mol brom cn d sau khi phn ng vi stiren d = 0,0025mol

S mol brom phn ng vi stiten d =0,015-0,0025=0,0125mol

Khi lng stiren d =1,3g

Khi lng stiren trng hp = khi lng polime=5,2-1,3=3.9g

Hot ng 3 HS lm bi tp trc nghim

Cu 1.Cht khng c kh nng tham gia phn ng trng hp l

A.stiren B.toluen C.propen D.isopren

Cu 2. Trong cc nhn xt di y ,nhn xt no khng ngA.cc polime khng bay hi

B.a s cc polime kh ha tan trong dung mi thng thng

C.cc polime khng c nhit nng chy xc nh

D.cc polime u bn vng di tc dng ca axit

Cu 3.T nilon-6,6 thuc loi

A.t nhn to B .t bn tng hp

C.t thin nhin D.t tng hp

Cu 4. iu ch polime ngi ta thc hin

A.phn ng cng

B.phn ng trng hp

C.phn ng trng ngng

D.phn ng trng hp hoc trng ngng

Cu 5.c im ca cc monome tham gia phn ng trng hp l

A.phn t phi c lin kt i mch nhnh

B.phn t phi c lin kt i mch chnh

C.phn t phi c cu to mch khng nhnh

D.phn t phi c cu to mch nhnh

Hot ng 4: Cng c kin thc hcRt kinh nghim:

Ngy son : 15/10/2012 TC 12: N TP CHNG III IV I . Mc tiu :

1. Kin thc : Cng c v khc su kin thc v amin, amino axit, peptit, polime

2. K nng : Rn luyn k nng lm bi tp , k nng lm bi tp nhn bit

II. Phng php : m thoi trao i nhm

III. Chun b : HS n tp cc kin thc v amin,amino axit, polime

IV. T chc cc hot ng dy v hcHot ng ca thy v trNi dung

Hot ng 1

HS trao i nhm cc kin thc v amin, amino axit, peptit, polime

Hot ng 2

GV yu cu HS lm bi tp v amin

- HS lm vic theo nhm v theo yu cu ca GV

Bi 1 t chy hon ton 6,2 g amin

no , n chc mch h cn 10,08 lit oxi (ktc) . CTCT ca amin l?Hot ng 3

GV giao bi tp v amino axit- HS lm vic theo nhm

Bi 2 . Cho 15,1 g amino axit n chc tc dng vi HCl d thu c 18,75 g mui . Xc nh CTCT ca amin trn

Hot ng 4GV yu cu HS lm bi tp v polime

HS lm theo yu cu

Bi 3.

Polime X c phn t khi M=280000 g/mol v h s trng hp l 10000

I. Kin thc

II. Bi tp

Bi tp v amin

Bi 1 .4n CnH2n+3 N + (6n +3) O2(4n

4 (14n + 17) 6n +3

6,2g 0,45

CO2 + 2(2n +3) H2O

Gii ra ta c n=1. CTCT : CH3NH2 Bi tp v amino axit

Bi 2.

NH2RCOOH + HCl (NH3ClRCOOH

Khi lng HCl = 18,75-15,1=3,65g , s mol HCl = 0,01mol

Phn t khi ca amino axit=151

M R=151-45-16= 80. Vy R l :C6H5CH-

CTCT : C6H5 CH(NH2) COOH

Bi tp v polimmeBi 3M monome:280000:10000=28

Vy M=28 l C2H4

Hot ng 5 HS lm bi tp trc nghim

1.Anilin khng tc dng vi cht no ?

a. C2H5OH b.H2SO4 c.HNO2 d.NaCl

2. tch ring tng cht trong hn hp gm benzen , nilin, phenol, ta ch cn dng ho cht (dng c , k th nghim y )

a.Br2, NaOH ,kh CO2 b.NaOH, NaCl, kh CO2

c. Br2, HCl, kh CO2 d . NaOH, HCl, kh CO2 3. Amin n chc c 19,178% nit v khi lng .CTPT ca amin l

a. C4H5N b.C4H7N c.C4H11N d.C4H9N

4. Cho lng d anilin tc dng hon ton vi dung dch cha 0,1mol H2SO4 long .Lng mui thu c l:

a.19,1g b.18,7g c. 27,6g d. 28,4g

5. Cho m (g) anilin tc dng vi dung dch HCl d .C cn dung dch sau phn ng thu c 15,54g mui khan .Hiu sut ca phn ng l 80% th gi tr ca m l:

a.11,16g b. 12,5g c.8,928g d.13,95g

6. Phn bit 3 dung dch : H2NCH2COOH, CH3COOH, C2H5NH2 ch cn dng 1 thuc th no ?

a. HCl b.Na c. qu tm d. NaOH

7. Cho 0,01mol amino axit X phn ng va vi 0,02mol HCl hoc 0,01mol NaOH .Cng thc ca X c dng

a. H2NRCOOH b. H2N R (COOH)2 c. (H2N)2R COOH d.(H2N)2R (COOH)28. Nha phenol fomanehit c iu ch t phenol v fomanehit bng loi phn ng no ?

a. trao i b. axit-bazo c. trng hp d. trng ngng

9. Khi cho H2N(CH2)6NH2 tc dng vi axit no sau y th to ra nilon-6,6.

a. axit oxalic b. axit aipic c. axit malonic d.axit glutamic

10. Poli(vinyl clorua) c iu ch theo s :

X (Y ( Z (PVC

X l cht no trong cc cht sau?

a. metan b .etan c. butan d. propan

Hot ng 6: Cng c kin thc ton biRt kinh nghim:

2

_1164045374.unknown

_1164045391.unknown

_1154109437.unknown

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